Slashdot Mirror


Goldbach Conjecture: Closer To Solved?

mikejuk writes "The Goldbach conjecture is not the sort of thing that relates to practical applications, but they used to say the same thing about electricity. The Goldbach conjecture is reasonably well known: every integer can be expressed as the sum of two primes. Very easy to state, but it seems very difficult to prove. Terence Tao, a Fields medalist, has published a paper that proves that every odd number greater than 1 is the sum of at most five primes. This may not sound like much of an advance, but notice that there is no stipulation for the integer to be greater than some bound. This is a complete proof of a slightly lesser conjecture, and might point the way to getting the number of primes needed down from at most five to at most 2. Notice that no computers were involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search."

170 comments

  1. and here is the proof for every even number by Anonymous Coward · · Score: 4, Funny

    I hereby prove that every even number is a sum of no more than six primes, one of those is 1.

    1. Re:and here is the proof for every even number by santiago · · Score: 5, Informative

      I hereby prove that every even number is a sum of no more than six primes, one of those is 1.

      Psst, 1 isn't prime. Or composite. It's neither.

    2. Re:and here is the proof for every even number by Smurf · · Score: 4, Insightful

      I hereby prove that every even number is a sum of no more than six primes, one of those is 1.

      Psst, 1 isn't prime. Or composite. It's neither.

      True, but you can change the GP's proof to "every even number n (where n > 4) is a sum of no more than six primes, because m = n - 3 is an odd number".

    3. Re:and here is the proof for every even number by Geoffrey.landis · · Score: 2

      Every even number greater than 1 is the sum of no more than six primes, one of which is three.

      --
      http://www.geoffreylandis.com
    4. Re:and here is the proof for every even number by Anonymous Coward · · Score: 1

      2 = 3 + ?

    5. Re:and here is the proof for every even number by Anonymous Coward · · Score: 1

      an imaginary number squared, obviously

    6. Re:and here is the proof for every even number by Sussurros · · Score: 2

      Given that 1 is divisible only by itself and 1 I hearby nominate it to be an honorary prime.

      --
      I said - don't look Ethel!..., but it was too late..., she'd already looked.
    7. Re:and here is the proof for every even number by tixxit · · Score: 1

      Unfortunately (for Ramare), this was already proven before Terrence Tao's result:

      We prove that every odd number N greater than 1 can be expressed as the sum of at most ve primes, improving the result of Ramare that every even natural number can be expressed as the sum of at most six primes.

    8. Re:and here is the proof for every even number by JoshuaZ · · Score: 1

      Minor note: While that's true, in Goldbach's day it was actually common to include 1 as a prime. So the original conjectures allowed 1.

    9. Re:and here is the proof for every even number by Anonymous Coward · · Score: 1

      1 was a prime when the Goldbach conjecture was first stated. Read some older mathematical papers. Mathematicians now tend to exclude it from the list of primes because that way is more useful, but the definition is not absolute.

    10. Re:and here is the proof for every even number by theshibboleth · · Score: 1

      I'm not sure what your point regarding m is, but if you just take out the 'one of these is 1' predicate it's still true since 5 primes is in the domain of 'no more than 6'.

    11. Re:and here is the proof for every even number by Anonymous Coward · · Score: 0

      You missed "even" and "odd".

    12. Re:and here is the proof for every even number by Arancaytar · · Score: 1

      No need to make up fake primes. With 3, every even number n>4 is 3 plus an odd number n>1; 4 and 2 are, obviously, trivial.

    13. Re:and here is the proof for every even number by silentcoder · · Score: 2

      What about 2 ? It's even, and it's greater than 1, but it's less than your 3.

      --
      Unicode killed the ASCII-art *
    14. Re:and here is the proof for every even number by Garridan · · Score: 3, Funny

      All y'all are confusing "theorem" with "proof". Stop it, it hurts.

    15. Re:and here is the proof for every even number by Joce640k · · Score: 1

      Major fail in summary - subby can't even get the conjecture right.

      --
      No sig today...
    16. Re:and here is the proof for every even number by Anonymous Coward · · Score: 0

      If you study math history, you know considering 1 as prime was very common.

    17. Re:and here is the proof for every even number by fatphil · · Score: 2

      Major failure in submitting at all. TT's proof was published on Febrauary 1st - this isn't news at all, this is olds.

      --
      Also FatPhil on SoylentNews, id 863
    18. Re:and here is the proof for every even number by Anonymous Coward · · Score: 0

      All y'all are confusing "theorem" with "proof". Stop it, it hurts.

      Of course the GP is not offering a formal theorem with a formal proof. But in one sentence he is providing enough material for the enunciation of a theorem (more like a corollary, but still) and its proof by anyone with basic knowledge in Mathematics. If that was so hard for you that it hurt you... your'e in the wrong field.

    19. Re:and here is the proof for every even number by Garridan · · Score: 1

      Yeah, I facepalmed once I re-read the OP, no fewer than 3 seconds after I hit 'submit'. Amazing what one can learn from reading an entire sentence!

  2. Terry Tao by bgeezus · · Score: 4, Interesting

    Terry Tao always amazes me with the scope of his knowledge. Contributions in mathematical areas as diverse as random matrix theory, harmonic analysis, and number theory. I look forward to what comes next!

    1. Re:Terry Tao by EuclideanSilence · · Score: 2

      I've also heard Tao say in lecture that he doesn't even like using computer assistance when he's working out theory. I found some of his lectures to be great for getting the scope of ideas, but unless you really know the subject of number theory he can be hard to follow.

    2. Re:Terry Tao by Anonymous Coward · · Score: 0

      Yeah, nice work for a boy from Adelaide, South Australia. I went to high school with his younger brother Trevor, who is a maths/chess/music virtuoso in his own right. Congratulations Terry!

    3. Re:Terry Tao by Anonymous Coward · · Score: 1

      you think those areas are diverse? All I see is analysis, analysis, and analytic number theory.

    4. Re:Terry Tao by Anonymous Coward · · Score: 0

      I know, right? I instantly recognized his name, and that's quite unusual for a field like math.

  3. Every Integer? by Anonymous Coward · · Score: 0

    Really.

    1. Re:Every Integer? by Anonymous Coward · · Score: 1

      Dude... what's 2 + 7?

    2. Re:Every Integer? by jejones · · Score: 5, Insightful

      7 + 2 = 9

    3. Re:Every Integer? by Anonymous Coward · · Score: 0

      For example, 9 can't be expressed as the sum of 2 primes.

      7 + 2. I've done the impossible!

    4. Re:Every Integer? by Anonymous Coward · · Score: 0

      Parent probably isn't a troll. The summary should say every even integer greater than 2. For example, 9 can't be expressed as the sum of 2 primes.

      What about 7+2?

    5. Re:Every Integer? by Old+Wolf · · Score: 5, Funny

      Wow, what has slashdot come to when posts are getting modded up for posting basic arithmetic :)

    6. Re:Every Integer? by ChrisMaple · · Score: 2

      29-2

      --
      Contribute to civilization: ari.aynrand.org/donate
    7. Re:Every Integer? by EuclideanSilence · · Score: 1

      Sorry I mean 11 can't be, because one of the terms would have to be 9 which isn't prime.

    8. Re:Every Integer? by Anonymous Coward · · Score: 0

      7 + 2 + 2

    9. Re:Every Integer? by Anonymous Coward · · Score: 0

      2 is prime. 7 is prime. So, no, you haven't found a counter-example. Look again what the conjecture claims.

    10. Re:Every Integer? by Anonymous Coward · · Score: 0

      Yes, yes it can. 7+2. 27 can't, though.

      We can do it with 3 primes tho ;) 7+7+13

    11. Re:Every Integer? by Burpmaster · · Score: 3, Funny

      7 + 2 = 9

      Damn, that's the most intelligent post I've seen on Slashdot all day, and I mis-clicked and chose 'redundant' when moderating...

    12. Re:Every Integer? by sexconker · · Score: 3, Funny

      7 + 2 + 2

      Ah, Mexican Math, we meet again. That's not two primes. That's three primes, two of which are 2.

    13. Re:Every Integer? by jd · · Score: 3, Informative

      Looked the conjecture up on Wikipedia. It's actually a little more specific still - every even number is a Goldbach Number, where a Goldbach number is a number that can be written as the sum of two odd primes.

      That means that every odd number can always be written as the sum of three primes or less. Numbers like 9 are the sum of two primes but are NOT Goldbach numbers since one of the primes is 2 and the requirement is that both primes be odd.

      Errors in this post are due to Wikipedia, blame them if there are any.

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    14. Re:Every Integer? by Anonymous Coward · · Score: 0

      13 - 2

    15. Re:Every Integer? by konohitowa · · Score: 0

      The story passed by the editor(s) (granted, it's timothy) with a summary that was quite excited to point out that computation isn't the same as proof. Perhaps it's time to relegate this site to r/slashdot and replace it with a nice stream of cats and ponies.

    16. Re:Every Integer? by Raenex · · Score: 2

      a summary that was quite excited to point out that computation isn't the same as proof

      It doesn't say that. It says, "Notice that no computers were involved in the proof -- this is classical mathematical proof involving logical deductions rather than exhaustive search."

      If you're going to bitch, at least complain about the incorrect statement of the theorem.

    17. Re:Every Integer? by Lando · · Score: 1

      Brief note of course is that you cannot do an exhaustive search on numbers since by definition they are infinite. This is no finite set therefore could not be exhaustively searched, why would anyone think it could is beyond me.

      --
      /* TODO: Spawn child process, interest child in technology, have child write a new sig */
    18. Re:Every Integer? by Raenex · · Score: 2

      The continuous plane is infinite too, yet the seminal math proof using computers was the four-color map theorem, which sparked a controversy that continues to this day:

      "Appel and Haken's approach started by showing that there is a particular set of 1,936 maps, each of which cannot be part of a smallest-sized counterexample to the four color theorem. Appel and Haken used a special-purpose computer program to confirm that each of these maps had this property."

    19. Re:Every Integer? by konohitowa · · Score: 1

      I think he gets it; just won't admit it. At least you understood my point.

    20. Re:Every Integer? by Anonymous Coward · · Score: 0

      Errors in this post are due to Wikipedia, blame them if there are any.

      No. I'll blame you for quoting the summary instead of going to the actual source material.

    21. Re:Every Integer? by Anonymous Coward · · Score: 0

      13 - 2

      Wrong- a prime number is always greater than 1, so you don't get to "add a negative".

    22. Re:Every Integer? by Anonymous Coward · · Score: 0

      ...

      11 = 11, which is prime. One is less than five.

    23. Re:Every Integer? by Anonymous Coward · · Score: 0

      "At most 5 primes": 11 = 11

    24. Re:Every Integer? by A+Pressbutton · · Score: 1

      3+3+3 = 9

    25. Re:Every Integer? by jd · · Score: 1

      True, and that would meet the sum of three odd primes requirement. If you include 2, then 7+2=9, making it the sum of two primes where one prime is NOT a Goldbach Number.

      ObTrivia: Found this page, it looks like it has some interesting information: http://homepage.mac.com/billtomlinson/primes.html

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    26. Re:Every Integer? by jd · · Score: 1

      http://mathworld.wolfram.com/GoldbachNumber.html

      Wolfram says the same thing. So Nyah! Pttttthhhhhpt!

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
  4. It's every *even* number by MrKevvy · · Score: 5, Informative

    "...every integer can be expressed as the sum of two primes."

    It should be every even integer. Note TFA has sums for 52, 54, 56, 58 and 60.

    --
    -- Insert witty one-liner here. --
    1. Re:It's every *even* number by Derekloffin · · Score: 1

      Ah, yes, I knew something was missing or I disproved it inside of a couple seconds :P. Yeah, it would have to be even as all primes are odd save 2, and the sum of any 2 primes is even, so you'd be forced to use 2 as one of those primes all the time for all even number and that very quickly breaks.

    2. Re:It's every *even* number by Derekloffin · · Score: 1

      Bah, that should be "For all odd numbers". That will treat me to reed my messages before posting.

    3. Re:It's every *even* number by Hentes · · Score: 1

      Or three primes.

    4. Re:It's every *even* number by cupantae · · Score: 2

      Another way to say it, which just occurred to me now, is:
      "Every natural number is halfway between two primes."

      --
      --
    5. Re:It's every *even* number by su5so10 · · Score: 3, Informative

      Actually... every even integer GREATER THAN TWO. See http://mathworld.wolfram.com/GoldbachConjecture.html

    6. Re:It's every *even* number by FrootLoops · · Score: 5, Informative

      Indeed, it should actually say, "every even integer greater than 2 can be expressed as the sum of two primes". 2 is degenerate. For the purposes of the conjecture calling 0 prime (this is non-standard) gets rid of that little wrinkle, though the cost of a more involved statement of the fundamental theorem of arithmetic is not worth it (which is incidentally a good reason why 1 isn't prime).

      For anyone interested, an actual theorem that's similar to the Goldbach conjecture is Lagrange's four-square theorem. It states that any non-negative whole number is the sum of the squares of four whole numbers. There are numerous proofs, though I wouldn't recommend trying to find one yourself if you don't have a background in algebra or number theory.

    7. Re:It's every *even* number by Anonymous Coward · · Score: 0

      Actually 2 is a sum of _at most_ two integers. Namely one integer 2=2.

    8. Re:It's every *even* number by Anonymous Coward · · Score: 2, Funny

      That will treat me to reed my messages before posting.

      Alas, it did not treat you.

    9. Re:It's every *even* number by Anonymous Coward · · Score: 0

      Sorta obviously, since the only even prime is 2, it means any ODD number resulting from the sum of two primes would have to be prime+2, which is defintely not true.

    10. Re:It's every *even* number by silentcoder · · Score: 1

      > For the purposes of the conjecture calling 0 prime (this is non-standard)

      Calling 1 a prime is non-standard. Calling 0 a prime is er... stupid. Why ? Because it's not divisible by itself. Nothing is divisible by 0 remember.

      --
      Unicode killed the ASCII-art *
    11. Re:It's every *even* number by cowboy76Spain · · Score: 0

      2 = 1 + 1

      :-P

      In case that you are wondering, no, I didn't follow your link :-).

      --
      Why can't /. have a rich-text editor? Editing your own HTML is so XXth century.
    12. Re:It's every *even* number by Odin's+Raven · · Score: 1

      2 is degenerate.

      That's rather harsh, isn't it? My understanding was that 2's relationship with the goat was entirely consensual, and at worst should be deemed indecent. (Particularly the time when 2 and the goat were in front of town hall on the 4th of July with that 128 ounce jar of mayonnaise, and ... ah, but I digress.) Heck, this story talks about groups of as many as five primes getting their groove on together, but nobody's calling them degenerate. Sheesh, have a little fling with a caprid and suddenly everyone's on your case.

      --
      A marriage is always made up of two people who are prepared to swear that only the other one snores.
    13. Re:It's every *even* number by Anonymous Coward · · Score: 0

      The Berners-Lee Foursquare Conjecture is that the foursquare count at any location can be expressed as the sum of hipsters plus douchebags minus hipster-douchebags currently on site.

    14. Re:It's every *even* number by gr8_phk · · Score: 1

      Unless you consider 1 to be prime, in which case 2 = 1+1. Didn't someone say Goldbach considered 1 prime for this?

    15. Re:It's every *even* number by su5so10 · · Score: 1

      The number 1 is not prime. If it were, the Fundamental Theorem of Arithmetic (every integer can be written as a unique ordered product of primes) would be false because you could represent, say, 4 as 2x2, 1x2x2, 1x1x2x2, 1x1x1x2x2, etc.

    16. Re:It's every *even* number by FrootLoops · · Score: 1

      I did say that the cost of calling 0 prime is not worthwhile in general. Still, "nothing is divisible by 0" is a little disingenious. Compactifying the real numbers with one or two points at infinity, defining 1/0 as (positive) infinity makes some sense. Similarly defining 0/0 = 1 also makes some sense, but the usual rules of arithmetic are broken rather badly with these definitions so to avoid confusing people they're not typically made. Still, if you told a mathematician "Formula (1) is true when we interpret 1/0 as positive infinity, 0/0 as 1", they'd be completely fine with it.

      Actually, I'm reminded of a similar convention that occurs in practice. Many people leave 0^0 undefined, calling it an indeterminate form to make calculus students just meeting L'Hopital's Rule for the first time more comfortable. However, if you've ever seen a power series, it uses the convention 0^0 = 1 (eg. sum_n a_n x^n at x=0 is a_0 0^0 + a_1 0^1 + ... = a_0 * 1 = a_0). Most of the time this is done without comment.

    17. Re:It's every *even* number by silentcoder · · Score: 1

      Well I find that quite a fascinating proposal. X/0 is an unknown infinite (there is no such number as infinity though - we're about 200 years past that idea) but X/X = 1

      So which of the two rules should actually apply to X=0 ?

      Seems from your post that mathematicians pretty much interchangeably swap...

      --
      Unicode killed the ASCII-art *
    18. Re:It's every *even* number by FrootLoops · · Score: 3, Insightful

      Actually "infinity" is an honest number in several modern, rigorous senses.

      In the extended real numbers, one adds two symbols to the usual real numbers (which won't render here), "+inf" and "-inf". No mystical qualities are needed; one could just as well use symbols "@" and "#". The extended real numbers are useful in formulating elementary measure theory, where some basic arithmetic with them is defined (+inf - -inf = +inf, for instance; +inf + -inf is left undefined).

      In the real projective line, one adds a single "point at infinity" which is imagined to "wrap around" from "negative infinity" to "positive infinity". I'm sorry for all the scare quotes; the actual construction is rigorous. Suppose you have a plane and a horizontal line passing through y=1. Given a point on the horizontal line, there is another line passing through that point and the origin; this line is taken to be a "point" on the real projective line. The additional point at infinity is taken to be the horizontal line passing through the origin, which is the limiting value of the other real projective line-points as they go to positive or negative infinity.

      As for X/X = 1 vs. X/0 = infinity when X=0, one could simply say X/0 = infinity when X is not 0 and then there is no conflict. But again, the usual rules of arithmetic don't work well in this situation, so you need a good reason to extend arithmetic to work with infinities. The only case I've encountered where that is true is with the extended real numbers in measure theory mentioned above.

      As for mathematicians, yes, we change conventions whenever needed without real difficulty. The phrase "ring" is a great example--it can have a huge variety of meanings depending on context. Careful authors will specify, but otherwise you'll have to figure out from context what precisely is meant. Once in a while this can be confusing, but for something as simple as whether primes can be negative or not it's a complete non-issue.

    19. Re:It's every *even* number by Anonymous Coward · · Score: 0

      Giving zero a multiplicative inverse is not just confusing, it breaks uniqueness. since 1*0=2*0, now we have 1=2. Not a structure you can play with that much :(

      x/0 can surely be defined as some new object (which is sometimes done as the grandparent says), but then the new object usually does not follow the usual rules we define. However, in that case zero does not have a multiplicative inverse. Uh, see http://en.wikipedia.org/wiki/Extended_real_number_line

      Mathematicians do pretty much interchangeably swap... but it should always be clear from context in what number system you work at the moment. If it isn't, always remember to define it properly.

    20. Re:It's every *even* number by Anynomous+Coward · · Score: 2

      Nicely stated, but not correct unless you consider 1 to be prime, which is as much blasphemy as stating that Pluto is a planet.

      Try "Every natural number above three is halfway between two primes."

      Your sig is confusingly appropriate ;-)

      --
      I'm not a coward by any name.
  5. Exhaustive search... by Anonymous Coward · · Score: 2, Interesting

    Notice that no computers where involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search.

    Exhaustive search for a result that holds for every integer? Good luck with that one.

    1. Re:Exhaustive search... by sexconker · · Score: 4, Funny

      Notice that no computers where involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search.

      Exhaustive search for a result that holds for every integer? Good luck with that one.

      Everyone knows integers only go from 0 to 4294967295!

    2. Re:Exhaustive search... by thoughtspace · · Score: 1

      You may write that in jest. You can use a theorem if it is not proven for the general case - only need it to 32 bits.

    3. Re:Exhaustive search... by Anonymous Coward · · Score: 2, Funny

      They recently discovered a few more: 4294967296 through 18446744073709551615. Just in time too--we were starting to run out in some computations. Unfortunately it'll take a bit longer to verify the conjecture for these newly discovered specimens. At least there's only a finite number of primes...

    4. Re:Exhaustive search... by Kjella · · Score: 1

      Everyone knows integers only go from 0 to 4294967295!

      Hey, on my computer INT_MAX is only 2137483647. Damn store must have cheated me, giving me crippled integers. I'm going to down there right now and demand one where integers go all the way up to 0x11..11..11..11.

      --
      Live today, because you never know what tomorrow brings
    5. Re:Exhaustive search... by Anonymous Coward · · Score: 0

      Damn, you are right. Are there any practically useful theorems that would be valid for 32-bit integers only?

    6. Re:Exhaustive search... by shentino · · Score: 1

      Sounds like it might be the perfect thing for quantum computers to handle.

    7. Re:Exhaustive search... by silentcoder · · Score: 4, Funny

      You youngsters... I remember telling that joke with 32768.

      --
      Unicode killed the ASCII-art *
    8. Re:Exhaustive search... by Anonymous Coward · · Score: 0

      Ah, but 32768 is negative. Curiously, so is its additive inverse.

    9. Re:Exhaustive search... by ignavus · · Score: 1

      Notice that no computers where involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search.

      Exhaustive search for a result that holds for every integer? Good luck with that one.

      Everyone knows integers only go from 0 to 4294967295!

      Can't afford a 64bit PC, huh?

      --
      I am anarch of all I survey.
    10. Re:Exhaustive search... by doru · · Score: 2

      Notice that no computers where involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search.

      Computers were involved to some extent. From Tao's blog:

      The first refinement, which is only available in the five primes case, is to take advantage of the numerical verification of the even Goldbach conjecture up to some large {N_0} (we take {N_0=4\times 10^{14}}, using a verification of Richstein [...])

      . See the paper by Richstein: http://www.ams.org/journals/mcom/2001-70-236/S0025-5718-00-01290-4/S0025-5718-00-01290-4.pdf

    11. Re:Exhaustive search... by martas · · Score: 2

      You do know that there are an infinite number of planar graphs, yes? You do also know that the (first) proof of the 4-coloring problem involved exhaustive search over a finite number of sub-problems, yes? So what's your point? (If it was just a joke, then my apologies)

    12. Re:Exhaustive search... by gringer · · Score: 1

      Everyone knows integers only go from 0 to 4294967295!

      That's quite large.

      --
      Ask me about repetitive DNA
  6. This way more useful than electricity by Anonymous Coward · · Score: 0

    Think of all of the applications this can be used for...

    Ok ... while I'm having difficulty at the moment coming up with one that's probably because of the electrodes they attached to my head to make me happy.

  7. Exhaustive by lurker1997 · · Score: 2

    every odd number greater than 1 is the sum of at most five primes

    Notice that no computers where involved in the proof — this is classical mathematical proof involving logical deductions rather than exhaustive search."

    That would have been a pretty long "exhaustive search".

    1. Re:Exhaustive by Beetle+B. · · Score: 0

      I'm not sure if you meant it as a joke, but exhaustive search can still be used for problems like these. An example would be to categorize all the integers into, say, 10000 groups and then write a program to prove each of those groups...

      --
      Beetle B.
  8. and yet another plagiarized slashdot summary by bcrowell · · Score: 0

    Why can't submitters get it through their head that when you quote someone, you need to put the quote in quotation marks and give credit to the source?

    1. Re:and yet another plagiarized slashdot summary by cupantae · · Score: 1

      What?
      The entire summary is quoted (error and all) from the only linked article. How is that not giving credit?

      --
      --
    2. Re:and yet another plagiarized slashdot summary by Anonymous Coward · · Score: 0, Flamebait

      "The parent is a faggot." --AC

    3. Re:and yet another plagiarized slashdot summary by bcrowell · · Score: 2

      What?
      The entire summary is quoted (error and all) from the only linked article. How is that not giving credit?

      It's not giving credit because it says: 'mikejuk writes "...",' where ... is a collection of sentences grabbed from various places in the article, and none of those sentences were written by mikejuk.

      Similarly --

      bcrowell writes:

      O Romeo, Romeo! wherefore art thou Romeo? Deny thy father and refuse thy name. Parting is such sweet sorrow, that I shall say good night till it be morrow. Courage, man; the hurt cannot be much.

    4. Re:and yet another plagiarized slashdot summary by bill_mcgonigle · · Score: 1

      Why can't submitters get it through their head that when you quote someone, you need to put the quote in quotation marks and give credit to the source?

      That's quite a leap of faith that the submitter got it wrong...

      --
      My God, it's Full of Source!
      OUTSIDE_IP=$(dig +short my.ip @outsideip.net)
  9. This is part of a very long trend by JoshuaZ · · Score: 5, Informative

    Work on this problem has been ongoing for about a hundred years now. First, Schnirelmann proved that there was some k such that every even integer could be expressed as a sum of at most k primes. The value for k had then been reduced over time. Vinogradov's proved that the Odd Golbach Conjecture (that every odd integer greater than 7 is the sum of three primes) was true for sufficiently large n. How large sufficiently large is has been slowly reduced. Later in the 1970s, Chen proved that every sufficiently large even integer is the sum of a number that is prime and another number that is either prime or a product of two primes. At this point, Chen's result is the strongest result known.

    In general, there are two general methods of attack on this problem, one which uses Schinerlmann's method and variants thereof, and the other which uses sieve theoretic approaches with the Hardy-Littlewood circle method http://en.wikipedia.org/wiki/Hardy-Littlewood_circle_method (Chen used a version of this for his result and Tao's work uses a similar approach). Unfortunately, there's not much work on actually connecting the two methods. There's an excellent piece of Tao at his blog where he discusses his work on the problem and is understandable without much background. http://terrytao.wordpress.com/2012/02/01/every-odd-integer-larger-than-1-is-the-sum-of-at-most-five-primes/. Note that TFA is a little out of date since he announced this result with a preprint a few months ago, and it is only that now the result is being published.

    It does not seem that this result really does put us much closer to proving the full Golbach Conjecture. At most this could be used to prove some version of the odd Goldbach Conjecture. The methods used would have a large amount of trouble dropping from 5 to 3. There's some bit of leeway, and if anyone is going to do it, it is going to to be Tao, but right now, I'm not optimistic.

    1. Re:This is part of a very long trend by gnasher719 · · Score: 2

      It is astonishing how weak the result is, and how hard it is to prove.

      The "ordinary" Goldbach conjecture is: Every even number N >= 4 is the sum of two primes. For example, 100 = 3 + 97 = 11 + 89 = 17 + 83 = 29 + 71 = 41 + 59 = 47 + 53, so we see that sum numbers can be written as the sum of two primes in many different ways. We call a number that is the sum of two primes a "Goldbach number", then the conjecture says that every even integer N >= 4 is a Goldbach number.

      The "weak" Goldbach conjecture is: Every odd number N >= 7 is the sum of three primes. At least one of these primes nust be odd, so we can express the weak conjecture as: For every odd N >= 7, there is an odd prime p = N - 4 such that N - p is a Goldbach number. Since there are many odd primes p = N - 4, only one out of a huge list of numbers of the form N - p need to be a Goldbach number.

    2. Re:This is part of a very long trend by FrootLoops · · Score: 4, Informative

      and if anyone is going to do it, it is going to to be Tao, but right now, I'm not optimistic.

      Agreed. I imagine Terry Tao isn't well-known outside of mathematics, but for those who don't know, he's certainly one of the most famous and skilled living mathematicians. He's originally Australian and is currently at UCLA. His list of high profile awards is ridiculously long, but aside from top-notch research, he's also an excellent teacher. His blog is mainly pitched at math grad students and higher, but some of it is very accessible. There's of course more biographical details at his Wikipedia page. The statement of the Green-Tao theorem is also accessible and interesting.

      I totally have a researcher-crush on him, or more specifically his math skills.

    3. Re:This is part of a very long trend by Anonymous Coward · · Score: 0

      I totally have a researcher-crush on him, or more specifically his math skills.

      It's OK of if you have real crush on him. Like a man-to-man crush. We understand.

    4. Re:This is part of a very long trend by FrootLoops · · Score: 1

      Hah. I actually am gay, but nope, I don't have a man-to-man crush on him, just his math. I can't imagine how exhausting it would be to try keeping up with him mentally, which makes me curious about his wife.

  10. And the two primes are? by Anonymous Coward · · Score: 1

    Optimus and Giedi?

    1. Re:And the two primes are? by sexconker · · Score: 1

      Optimus and Giedi?

      Optimus and Rodimus. Deal with it.

    2. Re:And the two primes are? by Anonymous Coward · · Score: 0

      Never! The Prime Must Flow!

  11. ZERO? by Anonymous Coward · · Score: 0

    What about the integer of ZERO? What two primes represent that, noting that primes are >1 (ie. not ZERO and not negative). I'm no mathematician and this occurred to me in about 5 seconds, so I'm sure it's flawed thought from me.

    AC

    1. Re:ZERO? by Spodi · · Score: 3, Informative

      Goldbach's conjecture: "Every even integer greater than 2 can be expressed as the sum of two primes." (source)

    2. Re:ZERO? by sexconker · · Score: 0

      8561290356012956901265912656135612056135460123560912356102650932604 disproves it, actually.

    3. Re:ZERO? by WalksOnDirt · · Score: 4, Funny

      Not so, 8561290356012956901265912656135612056135460123560912356102650931951 and 653 are prime. They sum to your number.

      --
      a,e,i,o,u and sometimes w and y (at be if of up cwm by)
    4. Re:ZERO? by martas · · Score: 1

      It actually checks out... How the hell did you do that?

    5. Re:ZERO? by Anonymous Coward · · Score: 0

      Try combinations until it checks out.

    6. Re:ZERO? by chocapix · · Score: 1

      If you have Maple handy, this one-liner does the trick:

      a := whatever; b := 2; while not(isprime(a-b)) do b := nextprime(b) end do; a-b, b;

      Of course the interesting part is the code for isprime(). You can start here if you want to know how it's done.

    7. Re:ZERO? by WalksOnDirt · · Score: 1

      I used the GMP. It includes an isprime() function. I've been meaning to install it on my computer, and the assertion by sexconker gave me the motivation to actually do it. It just took a simple decrement by two and test for primality loop.

      --
      a,e,i,o,u and sometimes w and y (at be if of up cwm by)
  12. The numbers less than 3 by gringer · · Score: 3, Insightful

    If you're talking about integers (which this conjecture refers to), then that's easy:

    2 = 5 + -3

    0 is trivial:

    0 = p + -p for all prime numbers p

    1 is also fairly easy:

    1 = 3 + -2

    And just to complete this, here's 3:

    3 = 5 + -2

    [multiplication by a unit, in this case -1, does not change the "primeness" of a number]

    --
    Ask me about repetitive DNA
    1. Re:The numbers less than 3 by gringer · · Score: 2

      of course, Goldbach was a bit before Ring theory, so may not have been referring strictly to "todays" integers, or prime elements in the set of integers (i.e. including negative numbers).

      --
      Ask me about repetitive DNA
    2. Re:The numbers less than 3 by mark-t · · Score: 3, Informative

      fwiw, it's my understanding that negative numbers are not considered primes, since allowing primes to be negative would allow composite numbers to have non-unique prime factorization.

    3. Re:The numbers less than 3 by sexconker · · Score: 1

      Correct.
      Negative numbers are not prime.
      1 is not prime (though it never fucking matters since it's always the trivial/base case when you're doing anything useful).

    4. Re:The numbers less than 3 by 2.7182 · · Score: 1

      It depends on the situation. (Ring.) Or author.

    5. Re:The numbers less than 3 by Pseudonym · · Score: 1

      As others have noted, it depends. It's sometimes convenient to consider -1 as being prime, for example, because it allows you to extend the notion of squarefree numbers to negative integers.

      --
      sub f{($f)=@_;print"$f(q{$f});";}f(q{sub f{($f)=@_;print"$f(q{$f});";}f});
    6. Re:The numbers less than 3 by Anonymous Coward · · Score: 0

      1 is not always the trivial/base case! 0 often is.

    7. Re:The numbers less than 3 by Anonymous Coward · · Score: 0

      Correct.
      Negative numbers are not prime.
      1 is not prime (though it never fucking matters since it's always the trivial/base case when you're doing anything useful).

      If you are doing something where it for some reason is important to note that 1 isn't a prime my first guess would be that the hardest part will be finding an actual real world application for it.

    8. Re:The numbers less than 3 by Anonymous Coward · · Score: 0

      Wrong. Prime factorization is unique only while disregarding unit factors (a unit is a number having an inverse, so in the integers, both 1 and -1 are units). The definition of a prime is that a prime p is a non-unit number with the property p|ab => p|a or p|b, meaning that if p is a factor of a product of given numbers, it is a factor of at least one of the product's constituing factors. In contrast, an irreducible is a non-unit number that can't be expressed as a product of two non-units.

      In the integers, those conditions are equivalent. There are other rings where they aren't, and those often have non-unique prime factorization.

    9. Re:The numbers less than 3 by mark-t · · Score: 1

      The problem with considering -1 as prime is the same problem as considering 1 prime: you end up with nonunique prime factorization for composite numbers, since the only limit on the number of times a factor may appear in its factorization is the highest power of that prime which is a factor of the composite number. -1 to the power of 2 is 1. -1 to the power of 3 is -1. -1 to the power of 4 is 1... And so on.

    10. Re:The numbers less than 3 by Pseudonym · · Score: 1

      You may have missed the word "squarefree" in my comment.

      --
      sub f{($f)=@_;print"$f(q{$f});";}f(q{sub f{($f)=@_;print"$f(q{$f});";}f});
  13. What about negative numbers by rossdee · · Score: 1

    When I went to school, integers included negative numbers. Of course that may have changed.

    1. Re:What about negative numbers by FrootLoops · · Score: 2

      Integers do still include negatives. Actually, the "prime numbers" used in abstract algebra also include negatives, so for instance -5 is prime. This genuinely useful convention results in the following statement of the fundamental theorem of algebra: "Every non-zero integer can be factored as the product of prime numbers. The factorization is unique up to order and signs." (Example: -12 = 2*(-2)*3 = (-2)*(-3)*(-2).) This directly generalizes to a corresponding statement in so-called unique factorization domains, of which the integers are a particular case. Still, fiddling with negatives might confuse students, and people don't often factor negative numbers anyway, so the definition is often restricted to positive numbers, even though it's artificial.

    2. Re:What about negative numbers by Anonymous Coward · · Score: 0

      Prime number are positive. There is no way to get a negative number from the sum of positive numbers.

    3. Re:What about negative numbers by Anonymous Coward · · Score: 0

      Okay, one is an empty product, but how do you factor -1? You can't add -1 to the list of primes without breaking your statement regarding uniqueness.

    4. Re:What about negative numbers by Anonymous Coward · · Score: 0

      Actually, the "prime numbers" used in abstract algebra also include negatives

      Uh, no. Primes are always greater than 1.
      Allowing negatives would violate the fundamental theorem of arithmetic. What you're working with are not true primes, and calling them such does nothing but create confusion.

    5. Re:What about negative numbers by Anonymous Coward · · Score: 0

      Math is a language, and in the language of math we have defined the word "Prime" to NOT include negative numbers. I understand what you're saying, and you are correct insofar as what we call a "Prime" number can indeed be negative, but it's not correct to use the word "Prime" to refer to them.

    6. Re:What about negative numbers by Anonymous Coward · · Score: 0

      Math is a language

      Interesting statement. You have something to back it up with?

    7. Re:What about negative numbers by FrootLoops · · Score: 1

      Thank you, that is a good point. I neglected the overall sign on the factorization. -1 would then be -{empty product}.

    8. Re:What about negative numbers by FrootLoops · · Score: 1

      I'm sorry, but you have no idea what you're talking about. I suspect you're trolling, but if not see this definition of prime element:

      In abstract algebra, an element p of a commutative ring R is said to be prime if it is not zero, not a unit and whenever p divides ab for some a and b in R, then p divides a or p divides b

      -2 is prime by this definition since it's not zero, it has no multiplicative inverse in the integers, and whenever ab is divisible by -2, either a or b is divisible by -2.

      This definition can be used in the defining property of unique factorization domains (see my original link) to generalize the fundamental theorem of arithmetic to other rings. Strictly speaking irreducibles are used instead of primes, but they coincide for the integers.

    9. Re:What about negative numbers by FrootLoops · · Score: 1

      Words can have multiple definitions, even in math. The common definition of "prime" refers to positives, but the definition I'm referring to (as made more explicit here) allows negatives. I was explicit about which definition I was referring to ("the 'prime numbers' used in abstract algebra"), so my usage was correct.

  14. Re:Should be every even integer by FrootLoops · · Score: 1

    I suspect it would have been disproved a long time ago.

    Long, long ago. If the conjecture really was as written, it would require every odd integer to be prime, which is patently ridiculous (eg. 3^k would be prime). Suppose the number n is odd. n+2 is odd too and, if the misstated conjecture were true, n+2 = p+q for primes p and q. Since all primes except 2 are odd, to get the sum to be odd, one of p or q must be 2, say q=2. But then n+2 = p+2, so n = q, and n is prime since q was.

  15. Is this progress? by spaceyhackerlady · · Score: 4, Insightful

    Sorry, but I can't accept this being progress toward a proof.

    Consider Fermat's Last Theorem. Proving it for any particular exponent is doable. Mathematicians had proved it for various sets of exponents (Sophie Germain, Wieferich, etc.). But the proof for all exponents was based on completely different mathematics (Elliptic curves/modular forms, Taniyama-Shimura, Wiles) and didn't look like anything that had come before.

    ...laura

    1. Re:Is this progress? by JoshuaZ · · Score: 4, Interesting

      That's not completely true. Wiles's proof only proves it for an exponent that is a prime p>=7. So one needs the classical results of n=3,4,5,7 also. This is to some extent a minor criticism. Your essential point is correct that sometimes a proof of a theorem comes out of a completely different direction. But, very often, it does come from a straightforward way of refining the same techniques more and more. For example, Catalan's Conjecture http://en.wikipedia.org/wiki/Catalan's_conjecture (the claim that that the only consecutive positive perfect powers are 8 and 9) was proven by what in many ways amounted to slow and steady progress.

    2. Re:Is this progress? by phantomfive · · Score: 2

      Even in the worst case, and the ultimate proof doesn't look anything like this, he's still eliminated one path that someone else might try (or forged along that path to show what it could do).

      --
      "First they came for the slanderers and i said nothing."
    3. Re:Is this progress? by Anonymous Coward · · Score: 0

      More to the point, Tao's blog post about this says

      though many more ideas would still be needed to tackle the three primes problem, and as is well known the circle method is very unlikely to be the route to make progress on the two primes problem

    4. Re:Is this progress? by Anonymous Coward · · Score: 0

      You make it sound like there is only one possible proof for every problem. Just because *a* proof was found based on entirely different mathematics, does not mean that there does not exist a proof with the same mathematics.

  16. Exhaustive search? by Anonymous Coward · · Score: 0

    "this is classical mathematical proof involving logical deductions rather than exhaustive search"

    I would be very impressed with an exhaustive search covering every even integer.

  17. Not Quite! by Anonymous Coward · · Score: 1

    The proof is missing a crucial part at the end...

      Q . E . D .

    There!

  18. Slashdot editors by Anonymous Coward · · Score: 0

    "no computers where involved in the proof"
    should be
    "no computers were involved in the proof"

  19. There WERE computers involved, indirectly. by kevinatilusa · · Score: 1

    From the abstract of Tao's paper: Our argument relies on some previous numerical work, namely the verification of Richstein of the even Goldbach conjecture up to $4 \times 10^{14}$, and the verification of van de Lune and (independently) of Wedeniwski of the Riemann hypothesis up to height $3.29 \times 10^9$.

    Richstein's work (available at http://www.ams.org/journals/mcom/2001-70-236/S0025-5718-00-01290-4/S0025-5718-00-01290-4.pdf ) definitely involves a computer, and I assume the Riemann hypothesis verification does as well.

    1. Re:There WERE computers involved, indirectly. by Anonymous Coward · · Score: 0

      Yes, the Riemann hypothesis verification also involved computers, in fact Wedeniwski's work was a distributed computation requiring some 700 years of Pentium IV @ 2GHz equivalant effort. See http://numbers.computation.free.fr/Constants/Miscellaneous/zetazeros1e13-1e24.pdf

    2. Re:There WERE computers involved, indirectly. by ogrizzo · · Score: 1
      Indeed, even a rough reading of Tao's blog post shows that previous computer computations are an essential part of the proof:

      The first refinement, which is only available in the five primes case, is to take advantage of the numerical verification of the even Goldbach conjecture up to some large (we take , using a verification of Richstein, although there are now much larger values of – as high as – for which the conjecture has been verified). As such, instead of trying to represent an odd number as the sum of five primes, we can represent it as the sum of three odd primes and a natural number between and . This effectively brings us back to the three primes problem, but with the significant additional boost that one can essentially restrict the frequency variable to be of size . In practice, this eliminates all of the major arcs except for the principal arc around . This is a significant simplification, in particular avoiding the need to deal with the prime number theorem in arithmetic progressions (and all the attendant theory of L-functions, Siegel zeroes, etc.). In a similar spirit, by taking advantage of the numerical verification of the Riemann hypothesis up to some height , and using the explicit formula relating the von Mangoldt function with the zeroes of the zeta function, one can safely deal with the principal major arc . For our specific application, we use the value , arising from the verification of the Riemann hypothesis of the first zeroes by van de Lune (unpublished) and Wedeniswki. (Such verifications have since been extended further, the latest being that the first zeroes lie on the line.)

  20. Rodimus? I can dig it. by Anonymous Coward · · Score: 0

    Still better than Sentinel Prime.

  21. Computers were used! (but/and this is still great) by Anonymous Coward · · Score: 0

    Computers were used in the proof! An exhaustive search was done over some small cases; and there have been previous proofs for the integers that are "large enough". Tao managed to make large enough small enough so that it falls into the rang covered by the computerized exhaustive search,

  22. Dis-proof of Goldbach as stated? by Roger+W+Moore · · Score: 1
    That was my understanding too - I'm a physicist not a mathematician though. However the article states that the Goldbach conjecture is:

    every integer can be expressed as the sum of two primes

    but this seems trivially easy to disprove. There is only one even prime, 2, so if I take an odd integer I have to construct it from the sum of an even and an odd number hence if N-2 is not a prime number Goldbach (as stated) cannot be correct. Now consider '11': since 9 is not a prime number and '2' is the only even prime this cannot hold true for all integers, only even integers which are constructed from the sum of two odd numbers.

    So is the article wrong? Should Goldbach actually be limited to 'every even integer' or does the mistake lie somewhere else?

    1. Re:Dis-proof of Goldbach as stated? by rpresser · · Score: 5, Informative

      http://mathworld.wolfram.com/GoldbachConjecture.html

      Goldbach's original conjecture (sometimes called the "ternary" Goldbach conjecture), written in a June 7, 1742 letter to Euler, states "at least it seems that every number that is greater than 2 is the sum of three primes" (Goldbach 1742; Dickson 2005, p. 421). Note that here Goldbach considered the number 1 to be a prime, a convention that is no longer followed. As re-expressed by Euler, an equivalent form of this conjecture (called the "strong" or "binary" Goldbach conjecture) asserts that all positive even integers >=4 can be expressed as the sum of two primes.

    2. Re:Dis-proof of Goldbach as stated? by ewanm89 · · Score: 1

      91, 93 and 95 are all non prime, so even if we take negative primes as a stretch (so we could negate 2 instead) as to get an odd integer we would need to sum an even and an odd and 93±2 is not prime. Therefore disproven that all odd integers can be expressed as the sun of two primes or their negatives.

  23. Goldbach's Conjecture was already solved by Anonymous Coward · · Score: 0

    Watch the movie "Fermat's Room", which is a great movie.

  24. Slashdot Summaries Again by TaoPhoenix · · Score: 5, Informative

    Dammit, Slashdot you have some of the best commenters here but you're wasting our time making us get about 30 comments in before someone posts the correction to the flawed summaries.

    From what I can see in a quick glance, the summary is at least partially wrong. The "regular" Goldbach conjecture seems to apply to every *even* integer greater than 2. So your odd number question disappears into another heading, which is apparently called variously the odd-number or three-primes version of the Goldbach.
    http://primes.utm.edu/glossary/page.php?sort=goldbachconjecture
    http://primes.utm.edu/glossary/xpage/OddGoldbachConjecture.html

    (Rant)

    So for a community that is expert on Forks, why can't we just Fork Slashdot? *We* are the "value". The only value they offer is the "summaries" and *every single one is wrong*. We lost our leader anyway, and we've all seen what the successors are up to, and Slashcode is sorta/mostly open source right? (Dunno if they bolted on something.)

    So why can't we Fork Slashdot? Are we so exhausted and burnt out from the days when fighting IE6 and Vista mattered, that we just don't care anymore? Oh and by the way, every new user would start at the *bottom* of the thread so those new breeds of shills with names like SunriseVista and BoldBraveBalmer don't hijack the top real estate of the conversation. P.S. Sorry, AC's, the top 10 memes of 2003 Slashdot have to go to now. Basically no other forum on the entire net has the First Post thing, and while I get the low level "test against censorship thing", we need a *user option* to flip the entire first post thread and any matching titles to the *bottom* of the post set. Then the *second thread in* which tries to deal with the article can do some work.

    (/Rant)

    --
    My first Journal Entry ever, in 8 years! http://slashdot.org/journal/365947/aphelion-scifi-fantasy-horror-poetry-webzine
    1. Re:Slashdot Summaries Again by Anonymous Coward · · Score: 0

      Fork it. I'd switch if it didn't suck.

    2. Re:Slashdot Summaries Again by Raenex · · Score: 1

      Dammit, Slashdot you have some of the best commenters here but you're wasting our time making us get about 30 comments in before someone posts the correction to the flawed summaries.

      By the time I read it, using my Slashdot settings it was the second post I read. The moderation system mostly works.

      So for a community that is expert on Forks, why can't we just Fork Slashdot?

      Wasn't that essentionally what Technocrat was?

      The only value they offer is the "summaries" and *every single one is wrong*.

      Oh really?

      We lost our leader anyway

      Speak for yourself.

    3. Re:Slashdot Summaries Again by DarkIye · · Score: 2

      I have a feeling you're basically describing Reddit. I have no doubt that there's an /r/maths, and it's probably quite good...

      Ugh. Fine, /r/math, no 's'. Yeah, it doesn't look bad.

    4. Re:Slashdot Summaries Again by TuringTest · · Score: 1

      So why can't we Fork Slashdot?

      I think the Slashdot effect might have something to do. I don't know how bad it is lately, though; maybe a small farm of modern servers may stand the load - but who would pay for it?

      --
      Singularity: a belief in the "God" idea with the "demiurge" relation inverted.
    5. Re:Slashdot Summaries Again by Sulphur · · Score: 1

      By the time I read it, using my Slashdot settings it was the second post I read. The moderation system mostly works.

      Say something nice about the mod system and get the old additive identity mod.

      So for a community that is expert on Forks, why can't we just Fork Slashdot?

      You could call it \. and aid confusion about slashes.

      We lost our leader anyway

      Maybe he got tired of a certain comment.

      Speak for yourself.

      Are you sure that's ok?

  25. Re:Should be every even integer by shentino · · Score: 1

    All primes except 2 are odd.

    Otherwise 2 itself would be a factor which would make it not so prime anymore.

  26. what sort of number would prove it false? by bzipitidoo · · Score: 1

    Assuming Goldbach's conjecture is not true, what kind of numbers would the "anti-Goldbach" numbers be? Huge, for one. Maybe a primorial +/- 1 or +/- 9? That number at least could not be the sum of two primes in which one of the primes is a factor of the primorial. Same idea could work for a "seriously" isolated prime +/- 1, if there is such a thing. I imagine people have tried to come up with numbers that disprove the conjecture.

    I'm thinking of a density and probabilistic kind of argument for Goldbach's conjecture. There are approximately x/ln(x) primes less than x. The chance that any two random numbers less than x is prime is (1/ln(x))^2. The probability that none of the pairs of odd numbers that sum to the even number in question are prime is (1-(1/ln(x))^2)^(x/4). As x gets larger, this quantity shrinks. In other words, the likelihood that an even number will have 2 primes that sum to it goes up as the number gets larger.

    Has anyone counted how many ways there are to satisfy the conjecture for particular numbers? Are there more pairs of primes that sum to a particular even number, when that number is larger? There any big even numbers for which there is only one pair of primes that sum to them?

    I also thought of trying for an even stronger conjecture. How could Goldbach's be made stronger? How about requiring that every even number x be the sum of not just 1 pair of primes, but the sum of ln(ln(x)) or sqrt(ln(x)) distinct pairs of primes? I'm just tossing those formulas out there, no idea if they're reasonable.

    --
    Intellectual Property is a monopolistic, selfish, and defective concept. It is "tyranny over the mind of man"
  27. Seven. by Anonymous Coward · · Score: 0

    Oops. Sum of 3 (prime) and 4 (NOT prime). Maybe in the summary he meant "sum of primes" not "sum of TWO primes" (emphasis added to enhance flavor). But I just disproved the conjecture right there, if the conjecture actually is that every integer is the sum of TWO primes. (That, again, is unless you mean sum of any multiple of two different primes, in which case 2 (prime) plus 2 (prime) plus 3 (prime) IS seven... I would go ahead and chalk this up to "bad summary".

    1. Re:Seven. by Roujo · · Score: 2

      How about, say, 2 + 5?

      Mind you, you'll run into a problem when you get to 11. As stated elsewhere in the comments, though, the Conjecture actually says "Every even integer greater than 2 can be expressed as the sum of two primes.", so I agree the summary isn't accurate. =)

  28. What two prime numbers add together to equal 17? by iambarry · · Score: 1

    Perhaps I didn't have my coffee this morning, or I am missing something. What two primes add together to form 17?

  29. Re:What two prime numbers add together to equal 17 by iambarry · · Score: 1

    Aha - I think the summary is perhaps misleading. Wikipedia explains its only even integers: http://en.wikipedia.org/wiki/Goldbach's_conjecture

  30. In related news... by Anonymous Coward · · Score: 2, Funny

    I'm going to eat 5 donuts a day while masturbating to pictures of Angela Merkel. It's not the sort of thing that relates to practical applications, but they used to say the same thing about electricity.

  31. Tao's proof does rely on computer-verified results by HuguesT · · Score: 1

    Contrary to what the Fine Announcement says, and although Tao's proof itself does not require any long or involved computer calculation, it relies on previously computed results. More precisely, the proof uses a numerical bound under which the Riemann Hypothesis is known to be true. This is theorem 1.5 in his paper.

    Theorem 1.5 (Numerical verification of Riemann hypothesis). Let T0 := 3.29 × 10^9.
    Then all the zeroes of the Riemann zeta function in the strip {s : 0 \leq (s) \leq 1; 0 \leq
    (s) \leq T0} lie on the line (s) = 1/2. Furthermore, there are at most 10^10 zeroes in
    this strip.

  32. The summary needs editing. If this by walter_f · · Score: 1

    'every integer can be expressed as the sum of two primes'

    were correct, Goldbach's conjecture would be a very simple way to find a huge number of primes.

    If so, any given odd integer would be the sum of an even prime (with a very limited choice, namely the number 2) and another prime, one of the odd ones.
    If so, any given odd integer would lead to a prime, the ultra-easy way.

    But it doesn't. You don't necessarily get a prime as a result by just taking an arbitrary odd integer and subtracting 2 from it. In most cases, you'll get another odd integer and that's it.

    So 'every even integer can be expressed as the sum of two primes' is a more precise way to put Goldbach's conjecture.