This is a development board made by the DINI Group. It looks like it's the DN8000K10PCI, and it's typically used for logic emulation.
Here is a web-link to the manufacturer's website:
http://www.dinigroup.com/index.php?product=DN8000k 10pci
I'm Assuming that we want to guarantee a 100% accurate 875Mbyte image of your DNA. A bit-error-rate better than 1 bit in 3.5 * 10^9.. What is the typical bit error rate for any file stored on a disk using the forward-error-correction and data redundancy that's built into a standard disk? A disk can handle being scratched by utilizing error correcting codes.. Error correction, in part, makes the fundamental trade-off between the amount of data redundancy you need to store to guarantee a bit error rate. It's all a matter of Gaussian probability.. The number I remember hearing about is 1 part in 2^31; so a standard disk should be able to recover your DNA even with scratches, but I'm not sure.
In college, I only went briefly into the theory of data-storage, error-correcting codes; etc, other than knowing that Reed-Solomon is the one that is used to encode your data on standard disks.
It would still be interesting to know how much more space you would need using a standard Reed-Solomon encoding to store an 875MByte image of your DNA.. I wonder how the file size would increase with decreasing bit-error rate?
What can we assume about how writable DVD disks age and lose data over time, assuming that you keep them in a humidity and temperature controlled, dark environment?
The Human genome is about 3.5 billion bases, and you need 2 bits to encode 2 bases, which corresponds to 7Gigiabits of data. 1 byte is 8 bits. So you would need at least 875Megabytes to store your DNA. This, I'm sure, would be bloated somewhat with the extra encoding and CRC checking to ensure that a disk with your DNA isn't missing any bases..
Does anyone know how much more space would be required to ensure that the DNA is copied accurately? I've heard that disks use Reed-Solomon codes as a way of minimizing bit errors, while also minimizing the amount of extra data you'd need to store.. It would be interesting to find out how much more space, in addition to the 875MBytes you would need, the probability of a bit-error, etc..
http://www.4i2i.com/reed_solomon_codes.htm
I work at a company that makes DNA sequencers, and feel excited to be in this business..
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This is a development board made by the DINI Group. It looks like it's the DN8000K10PCI, and it's typically used for logic emulation.k 10pci
Here is a web-link to the manufacturer's website:
http://www.dinigroup.com/index.php?product=DN8000
I'm Assuming that we want to guarantee a 100% accurate 875Mbyte image of your DNA. A bit-error-rate better than 1 bit in 3.5 * 10^9.. What is the typical bit error rate for any file stored on a disk using the forward-error-correction and data redundancy that's built into a standard disk? A disk can handle being scratched by utilizing error correcting codes.. Error correction, in part, makes the fundamental trade-off between the amount of data redundancy you need to store to guarantee a bit error rate. It's all a matter of Gaussian probability.. The number I remember hearing about is 1 part in 2^31; so a standard disk should be able to recover your DNA even with scratches, but I'm not sure. In college, I only went briefly into the theory of data-storage, error-correcting codes; etc, other than knowing that Reed-Solomon is the one that is used to encode your data on standard disks. It would still be interesting to know how much more space you would need using a standard Reed-Solomon encoding to store an 875MByte image of your DNA.. I wonder how the file size would increase with decreasing bit-error rate? What can we assume about how writable DVD disks age and lose data over time, assuming that you keep them in a humidity and temperature controlled, dark environment?
The Human genome is about 3.5 billion bases, and you need 2 bits to encode 2 bases, which corresponds to 7Gigiabits of data. 1 byte is 8 bits. So you would need at least 875Megabytes to store your DNA. This, I'm sure, would be bloated somewhat with the extra encoding and CRC checking to ensure that a disk with your DNA isn't missing any bases.. Does anyone know how much more space would be required to ensure that the DNA is copied accurately? I've heard that disks use Reed-Solomon codes as a way of minimizing bit errors, while also minimizing the amount of extra data you'd need to store.. It would be interesting to find out how much more space, in addition to the 875MBytes you would need, the probability of a bit-error, etc.. http://www.4i2i.com/reed_solomon_codes.htm I work at a company that makes DNA sequencers, and feel excited to be in this business..