Why does your browser use a crappy font for monospaced text? There's a setting for that. Mine uses Consolas. It's readable. And it differentiates between O and 0, and other characters that look similar (if not identical) in most other fonts.
The reason for DRM's existence is to limit web content to those users who have the money (resources) to pay for it.
No, no... the reason for DRM's existence is to enable users who have the money to obtain content. Otherwise, the creators could keep it to themselves and nobody would benefit from it! Repeat after me: war is peace. freedom is slavery. ignorance is strength. DRM is good.
I joke, but I think there are must be people who actually believe this. It's the only logical explanation for some people's behavior. The W3C is just the latest example...
Yeah, unfortunately on mine the device was removed entirely. I tried to find an older driver that had it, but it always said that it wasn't the right driver.
Did you read the whole article? One photon will be re-emitted in identical form to the original, but two photons will likely be re-emitted as a single, molecule-like unit.
Niagara^AX is a software framework and development environment that solves the challenges associated with building Internet-enabled products, device-to-enterprise applications and distributed Internet-enabled automation systems.
By default, the Tridium Niagara AX software is not configured to deny access to restricted parent directories... An attacker could exploit this vulnerability by sending a specially crafted request to the Web server running on Port 80/TCP
"The system insecurely stores user authentication credentials, which are susceptible to interception and retrieval. User authentication credentials are stored in the Niagara station configuration file, config.bog, which is located in the root of the station folder"
In other words, it's about as simple as GET/../config.bog HTTP/1.1
Also, forgot to mention, isn't the implication of some cracked / some non cracked that whoever originally got their hands on the data only has the hashes, not the full passwords?
Of course, it's also possible that some scavenger started cracking the SHA-1 hashes in a file that someone else released...
I checked the tail end of the SHA-1 hash of my LinkedIn password; it wasn't in the list, neither zeroed or in full. I'd already signed into LinkedIn and changed it, so it's moot, but yeah, my password wasn't in the dump.
"'jQuery', he mumbled". Well stop mumbling, either make with the argument (and the CODE), or shut the fuck up already. Show me the code that hooks the flag up to an action... it's just not there.
That pixel-sized image is just a server-side script that logs some metrics based on the request the browser sent. It could send back a 404 error instead of a 1x1 transparent gif - it wouldn't matter. And it doesn't have to be an image; it could just as easily be a script or style tag, and the server sends back a 0-byte file after logging the request.
If somebody can impersonate your peer at that exchange, you are owned.
It would get them nowhere, on its own. They would also need to intercept the entangled photon, without detection - which can't be done (in theory); that photon would simply be ignored, not used for the encryption.
It's basically like you're doing XOR encryption with a random one-time pad, known only to you and your target. The quantum encryption is basically the part that ensures that only you and your target can possibly know what the one-time pad contains (according to present interpretation of the laws of physics). Because any time your eavesdropper intercepts a single bit of the one-time pad, both of you are able to sense this and simply not use that bit.
Not the exact same thing - quoting from the paper,
Most recently, following a modified scheme, quantum teleportation over 16 km free-space links was demonstrated with a single pair of entangled photons. However, in this experiment, the unknown quantum state must be prepared on one of the resource entangled qubits and therefore cannot be presented independently. In our experiment, we demonstrate quantum teleportation of an independent unknown state...
It's not really known whether or not Bob's photon actually changes, or whether it's simply been in the same state as Alice's photon all along. If it changes that would imply that the information moved faster than the speed of light, which poses problems under current models. If it's been that way all along, the only thing that changes is that Alice now knows what state it's in.
In either case, Alice can tell Bob which quantum operation to perform on the entangled photon to determine the state of Alice's original photon. Intercepting this would tell you nothing unless you have one of the entangled photons, since the state of Alice's entangled photon is assumed to be random when she measures it. Bob's entangled photon has the same quantum state as Alice's does, and when he performs the correct operation, he finds the state of the original qubit.
I assume there must be some way to determine whether both Alice and Bob have an entangled pair of photons before Alice transmits which transformation Bob should use. Otherwise, it seems like someone could intercept an entangled photon intended for Bob and also intercept the transmission where Alice reveals which transformation will yield the encoded qubit.
Well, I went ahead and downloaded the PDF (surprisingly not paywalled).
It describes it as (paraphrasing slightly):
Alice has a photon of unknown quantum state and wishes to transfer it to Bob, who is at a distant location. Charlie first distributes an entangled photon pair to Alice and Bob, respectively. Alice now has two photons, and performs a joint Bell-state measurement (BSM) on them. The state of Bob's entangled photon is instantaneously altered by Alice's measurement. Alice then transmits the BSM result (meaningless on its own) to Bob via a classical channel. Based on this result, Bob can apply the appropriate unitary transformation which will convert the state of his entangled photon into the original state of the unknown photon.
So it sounds like the information is not teleported until Bob and Alice have successfully received a pair of entangled photons. Losses simply interfere with Bob's ability to receive entangled photons (Charlie and Alice are in the same physical location).
Conventional lasers use a beam consisting of millions of photons, and some percentage of them have to reach the destination. In the quantum version, individual photons are transmitted, and all must reach the destination, or both transmitter and receiver will know that the secure link has been broken. Additionally, it's theoretically impossible to eavesdrop without either breaking the quantum entanglement, or blocking the photon (or both). Either way, both parties will detect it.
The photons must remain in quantum entanglement while one photon is transmitted to the destination. A photon traveling through a glass fiber loses its quantum entanglement fairly rapidly.
Note that it's still limited by the speed of light. The key feature, however, is that it is secure: someone intercepting the photon can't copy or read its qbit state without breaking the quantum entanglement, or preventing it from reaching the destination. In either case, the receiver will immediately know that the channel has been broken. It then stops transmitting a response to the sender, and the sender perceives this as also a break in secure communications and stops transmitting. Both the sender and the receiver would then go into failure mode and send query/response polls periodically. When secure communications are re-established, they can resume transmitting data.
The information contained in the qbit is transported from one entangled photon to another, but you first must get that entangled photon to the destination via more conventional means. They're doing that with a laser.
Slashdot Mirror
According to the description on figure 4, the battery provides 0.5 volts:
EFCs are powered by 500âmM methanol, 7.2% wt/v glucose or 15% wt/v maltodextrin or dehydrated fuels at a voltage of 0.5âV.
Additionally, supplementary table S3 (PDF, page 11 of 14 or PNG) also lists the voltage at 0.5 volts.
No, first you increment and then you shift left twice*. Increment is a unary operation, so you avoid an unnecessary operand.
Why does your browser use a crappy font for monospaced text? There's a setting for that. Mine uses Consolas. It's readable. And it differentiates between O and 0, and other characters that look similar (if not identical) in most other fonts.
42
The reason for DRM's existence is to limit web content to those users who have the money (resources) to pay for it.
No, no... the reason for DRM's existence is to enable users who have the money to obtain content. Otherwise, the creators could keep it to themselves and nobody would benefit from it! Repeat after me: war is peace. freedom is slavery. ignorance is strength. DRM is good.
I joke, but I think there are must be people who actually believe this. It's the only logical explanation for some people's behavior. The W3C is just the latest example...
Yeah, unfortunately on mine the device was removed entirely. I tried to find an older driver that had it, but it always said that it wasn't the right driver.
Same reason as the newer RealTek sound drivers have disabled/removed the Stereo Mix recording device: DRM.
Did you read the whole article? One photon will be re-emitted in identical form to the original, but two photons will likely be re-emitted as a single, molecule-like unit.
Actually, it's designed to be web-facing.
Niagara^AX is a software framework and development environment that solves the challenges associated with building Internet-enabled products, device-to-enterprise applications and distributed Internet-enabled automation systems.
Worse, this is a laughably simple exploit of the web-facing interface:
By default, the Tridium Niagara AX software is not configured to deny access to restricted parent directories... An attacker could exploit this vulnerability by sending a specially crafted request to the Web server running on Port 80/TCP
"The system insecurely stores user authentication credentials, which are susceptible to interception and retrieval. User authentication credentials are stored in the Niagara station configuration file, config.bog, which is located in the root of the station folder"
In other words, it's about as simple as GET /../config.bog HTTP/1.1
Also, forgot to mention, isn't the implication of some cracked / some non cracked that whoever originally got their hands on the data only has the hashes, not the full passwords?
Of course, it's also possible that some scavenger started cracking the SHA-1 hashes in a file that someone else released...
Thanks for that info.
I checked the tail end of the SHA-1 hash of my LinkedIn password; it wasn't in the list, neither zeroed or in full. I'd already signed into LinkedIn and changed it, so it's moot, but yeah, my password wasn't in the dump.
I tested it in Opera before I posted my comment. Same effect as you: nothing happens.
Probably this bug.
Only it isn't. ...
"'jQuery', he mumbled". Well stop mumbling, either make with the argument (and the CODE), or shut the fuck up already. Show me the code that hooks the flag up to an action ... it's just not there.
Yes it is. Right here in the script.
jQuery(document).ready( .ui-icon.flag').live('click', .t").live('keyup', .s").removeAttr("disabled"); .s").attr("disabled","disabled");
function(){
$('.commentSub
function(fe){
if($('#flag_comment').length>0){
$('#flag_comment').remove();
}
$(this).parent().append('<form id="flag_comment"><input type="hidden" name="comment" value="'+this.id+'"><input type="button" class="s" value="Report" disabled="disabled" onclick="reportCommentAbuse();"><input type="text" name="reason" class="t" placeholder="Specify reason" ></form>').parent().parent().addClass('flag-in');
$('input[name=reason]').focus();
}
);
$(".comment").hover(function(){},
function(){
if($(this).hasClass('flag-in')){
$('#flag_comment').remove();
$(this).removeClass('flag-in');
}
}
);
$("input[name=reason]").live('keypress',
function(kp){
var code=(kp.keyCode?kp.keyCode:kp.which);
if(code==13){
$(this).prev().trigger('click');
kp.preventDefault();
}
}
);
$("#flag_comment
function(data){
if($(this).val()!=""){
$("#flag_comment
}else{
$("#flag_comment
}
}
);
}
);
function reportCommentAbuse(){
ajax_update(
{
op:'reportCommentAbuse',
comment:$("#flag_comment input[name=comment]").val(),
reason:$("#flag_comment input[name=reason]").val()
},
'',
{
onComplete:function(){
Slash.busy('modal-fetch',false);
$("#flag_comment").hide();
}
}
);
return false;
}
No, that's also because of issues with color dithering.
Most people expect their black and white printer to be able to print shades of gray. It doesn't have gray ink. It can't make gray ink. So it dithers.
That pixel-sized image is just a server-side script that logs some metrics based on the request the browser sent. It could send back a 404 error instead of a 1x1 transparent gif - it wouldn't matter. And it doesn't have to be an image; it could just as easily be a script or style tag, and the server sends back a 0-byte file after logging the request.
Thank you for your insightful explanation of why this would never work - if you were designing it.
If somebody can impersonate your peer at that exchange, you are owned.
It would get them nowhere, on its own. They would also need to intercept the entangled photon, without detection - which can't be done (in theory); that photon would simply be ignored, not used for the encryption.
It's basically like you're doing XOR encryption with a random one-time pad, known only to you and your target. The quantum encryption is basically the part that ensures that only you and your target can possibly know what the one-time pad contains (according to present interpretation of the laws of physics). Because any time your eavesdropper intercepts a single bit of the one-time pad, both of you are able to sense this and simply not use that bit.
Not the exact same thing - quoting from the paper,
Most recently, following a modified scheme, quantum teleportation over 16 km free-space links was demonstrated with a single pair of entangled photons. However, in this experiment, the unknown quantum state must be prepared on one of the resource entangled qubits and therefore cannot be presented independently. In our experiment, we demonstrate quantum teleportation of an independent unknown state...
It's not really known whether or not Bob's photon actually changes, or whether it's simply been in the same state as Alice's photon all along. If it changes that would imply that the information moved faster than the speed of light, which poses problems under current models. If it's been that way all along, the only thing that changes is that Alice now knows what state it's in.
In either case, Alice can tell Bob which quantum operation to perform on the entangled photon to determine the state of Alice's original photon. Intercepting this would tell you nothing unless you have one of the entangled photons, since the state of Alice's entangled photon is assumed to be random when she measures it. Bob's entangled photon has the same quantum state as Alice's does, and when he performs the correct operation, he finds the state of the original qubit.
I assume there must be some way to determine whether both Alice and Bob have an entangled pair of photons before Alice transmits which transformation Bob should use. Otherwise, it seems like someone could intercept an entangled photon intended for Bob and also intercept the transmission where Alice reveals which transformation will yield the encoded qubit.
Well, I went ahead and downloaded the PDF (surprisingly not paywalled).
It describes it as (paraphrasing slightly):
Alice has a photon of unknown quantum state and wishes to transfer it to Bob, who is at a distant location. Charlie first distributes an entangled photon pair to Alice and Bob, respectively. Alice now has two photons, and performs a joint Bell-state measurement (BSM) on them. The state of Bob's entangled photon is instantaneously altered by Alice's measurement. Alice then transmits the BSM result (meaningless on its own) to Bob via a classical channel. Based on this result, Bob can apply the appropriate unitary transformation which will convert the state of his entangled photon into the original state of the unknown photon.
So it sounds like the information is not teleported until Bob and Alice have successfully received a pair of entangled photons. Losses simply interfere with Bob's ability to receive entangled photons (Charlie and Alice are in the same physical location).
Conventional lasers use a beam consisting of millions of photons, and some percentage of them have to reach the destination. In the quantum version, individual photons are transmitted, and all must reach the destination, or both transmitter and receiver will know that the secure link has been broken. Additionally, it's theoretically impossible to eavesdrop without either breaking the quantum entanglement, or blocking the photon (or both). Either way, both parties will detect it.
Bill Cosby
The photons must remain in quantum entanglement while one photon is transmitted to the destination. A photon traveling through a glass fiber loses its quantum entanglement fairly rapidly.
Note that it's still limited by the speed of light. The key feature, however, is that it is secure: someone intercepting the photon can't copy or read its qbit state without breaking the quantum entanglement, or preventing it from reaching the destination. In either case, the receiver will immediately know that the channel has been broken. It then stops transmitting a response to the sender, and the sender perceives this as also a break in secure communications and stops transmitting. Both the sender and the receiver would then go into failure mode and send query/response polls periodically. When secure communications are re-established, they can resume transmitting data.
The information contained in the qbit is transported from one entangled photon to another, but you first must get that entangled photon to the destination via more conventional means. They're doing that with a laser.