The paper seemed to deal with polygonal data, with algorithms to determine how many dots to use for a polygon etc... Dealing with ct data (which is volumetric, like a 3d analogue of a bitmap) would be simpler.
1. how big a footprint does this voxel project to on the screen? 2. what intensity is the voxel? (0 - empty space, 255 -solid matter) 3. Draw n points randomly within a circle of radius footprint, centered about the voxels projected centre point, where n is something like (((footprint radius^2)*intensity)/255)*desired pointilism density.
It's a reasonable, simple technique. I remember thinking that when I hacked a similar thing together as an effect in a previous job. Took about an hour. If I'd known something that obvious could get you paper of the year, I'd have written it up.;-)
Re:Doesn't the earth receive more?
on
Lunar Power
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· Score: 1
But you still have to get through the atmosphere. I suspect any e.m. frequency will interact with the atmosphere to an extent, so you're going to lose a fraction. As someone else has mentioned, the reciever would have to be a very large one, to handle that level of energy throughput. I wonder what the effect of having a large, superheated column of air stretching all the way to space would be on the atmosphere as a whole? HAARP anybody?
Slashdot Mirror
The paper seemed to deal with polygonal data, with algorithms to determine how many dots to use for a polygon etc... Dealing with ct data (which is volumetric, like a 3d analogue of a bitmap) would be simpler.
;-)
1. how big a footprint does this voxel project to on the screen?
2. what intensity is the voxel? (0 - empty space, 255 -solid matter)
3. Draw n points randomly within a circle of radius footprint, centered about the voxels projected centre point, where n is something like (((footprint radius^2)*intensity)/255)*desired pointilism density.
It's a reasonable, simple technique. I remember thinking that when I hacked a similar thing together as an effect in a previous job. Took about an hour. If I'd known something that obvious could get you paper of the year, I'd have written it up.
But you still have to get through the atmosphere. I suspect any e.m. frequency will interact with the atmosphere to an extent, so you're going to lose a fraction.
As someone else has mentioned, the reciever would have to be a very large one, to handle that level of energy throughput. I wonder what the effect of having a large, superheated column of air stretching all the way to space would be on the atmosphere as a whole? HAARP anybody?
Matt "not sure I want to find out" Taylor
I always understood that the QWERTY keyboard was invented by the eccentric Professor Qwertyuiop, so he could sign his letters with a real flourish.