Dear Gentlemen: Dr.Andrew Beal and High math Staff of AMS,
Now I would like to Show all of You My Secret Theorem for your Beal Conjucture...
First I will used My Secret ALIEN Theorem and from this we will Take this:
Agron (Theorem) for the Beal Conjucture:
My ALIEN Proof:
We will take : A^x + B^y = C^z
Now we take: A=x, x=n, B=y, y=n, C=z, z=n why we take: n because A, B, C it's Greater then 2 so now we have: x^n + y^n =z^n
For: n=2 we have this:
x^2 + y^2=z^2
For : x=m^2 - n^2 , y=2mn and z=m^2 + n^2 , when m= positive integer then =>
[(m^2)-(n^2)]^2 + (2mn)^2 = [(m^2)+(n^2)]^2 , =>
m^4+n^4-2(m^2)(n^2)+4(m^2)(n^2) =m^4+n^4+2(m^2)(n^2) , =>
2(m^2)(n^2)=2(m^2)(n^2).
Author: Agron Hoxha, (Ferizaj) Kosova
a.51@collector.org
me1@null.net
Original Date: 10.June.2013 (Copy Rights),
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Dear Gentlemen: Dr.Andrew Beal and High math Staff of AMS, Now I would like to Show all of You My Secret Theorem for your Beal Conjucture... First I will used My Secret ALIEN Theorem and from this we will Take this: Agron (Theorem) for the Beal Conjucture: My ALIEN Proof: We will take : A^x + B^y = C^z Now we take: A=x, x=n, B=y, y=n, C=z, z=n why we take: n because A, B, C it's Greater then 2 so now we have: x^n + y^n =z^n For: n=2 we have this: x^2 + y^2=z^2 For : x=m^2 - n^2 , y=2mn and z=m^2 + n^2 , when m= positive integer then => [(m^2)-(n^2)]^2 + (2mn)^2 = [(m^2)+(n^2)]^2 , => m^4+n^4-2(m^2)(n^2)+4(m^2)(n^2) =m^4+n^4+2(m^2)(n^2) , => 2(m^2)(n^2)=2(m^2)(n^2). Author: Agron Hoxha, (Ferizaj) Kosova a.51@collector.org me1@null.net Original Date: 10.June.2013 (Copy Rights),