Grok Goldbach, Grab Gold
Caseman writes, "Are you a closet mathematician who wants to come out? British publisher Tony Faber is offering a cool million bucks to the first would-be math head to prove the infamous Goldbach conjecture. Yeah, the one about every even number being the sum of two primes. Impossible, you say? Remember Fermat's Last Theorem? It stood unproven for 350 years until a recent effort yielded a proof. Read The London Times article about the challenge. "
Unfortunately, the slashdot comment submission box is too small to post the whole proof. I shall leave the proof to the reader.
"Pinky, you've left the lens cap of your mind on again." - P&TB
"I can see my house from here!" - ST:
Yes, it is possible that the Goldbach conjecture may be proved or disproved by a lay person but it's far more likely to be solved by someone with a sound grasp of lots of number theory who is already studying the properties of numbers for a living.
BTW I have a truly marvellous proof of the Goldbach conjecture but there is no margin on the submit form to write it in :)
--- Hot Shot City is particularly good.
Disclaimer: long boring math stuff with a conclusion that may be interesting for some at the end ...
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An interesting question is: assuming prime numbers are "randomly" distributed, what is the probability that an even number won't be the sum of two odd numbers?
If the probability is rather high, yet we did not find any such even number, it can be an indication there may be some "meat" in goldbach theorem. On the other hand, if such probability is exremely low, than the verification of goldbach's theorem up to 4e+15 means nothing
Well, according to Gauss' estimate for prime number density around sufficiently large n, the density is 1/log(n). To find pi(n), which is the number of prime numbers up to n, we need to integrate this, but pi(n)=n/log(n), so we can make life simpler and over-estimate the probability by taking the smaller number.
Now, given the number of prime numbers up to n, pi(n), if we choose x to be a prime number smaller than n, than the probability its pair: (n-x) is a prime number is: 2*pi(n)/n. (I multiplied by 2 since itcannot be possibly an even number, so no need to consider them).
The probability that it is not a prime number is therefore (1-2*pi(n)/n).
Since there are pi(n) different prime numbers to choose from, the probability that an even number is not the sum of two prime numbers is:
(1-2*pi(n)/n)^pi(n).
So what is the probability for numbers around 1e+15? If we use the estimate for pi(n), we get:
pi(n)=2e+13
(1-2*pi(n)/n) = 0.959
Taking the last number by the power of pi(n), the result is that the probability is around:
10^-(4e11)
That is - an extremely small probability!!!
Conclusion:
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If Goldbach's theorem is false, the probability that an even number won't be the sum of two prime numbers is so small that we may need to check around 10^(10^11) numbers to find a counter example. This number is so big no computer could possibly handle it now or any time soon
In other words: Don't bother to find a counter-example.
Sela
It's stunning how many people want to approach this as a programming problem; i.e. a fast way of checking lots of numbers. We're talking about a *proof*. Guessing and checking is missing the point.