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Two Handfuls Of Handhelds

rgarcia writes: "CNET has this story: Panasonic announced on Monday its first handheld computer, the Toughbook 01, which is designed to complement its notebook line of the same name. The consumer electronics maker has been selling into a niche in the notebook market by focusing on durable laptops that can withstand the shock of a fall and can resist moisture, dust and scratches. I know Ive dropped a few in my day. Damn things are fragile. Cool design, though I dont know if its actually better." And an unnamed reader points out that DALinux now has hardware available: "They claim it is Palm compatible, but it won't run palm apps - so what 'Palm compatible' means is anyone's guess. But it is a cool gadget, it runs Linux, and, most importantly, it is affordable." "Palm compatible" better at least mean painless address-book import.

16 of 125 comments (clear)

  1. BREAKING NEWS! by Anonymous Coward · · Score: -1, Offtopic
  2. STO by Anonymous Coward · · Score: -1, Offtopic

    Strength Through Oi!

    Skinheads rule, OK.

  3. get a handful of this by Anonymous Coward · · Score: -1, Offtopic


    * g o a t s e x * g o a t s e x * g o a t s e x *
    g g
    o / \ \ / \ o
    a| | \ | | a
    t| `. | | : t
    s` | | \| | s
    e \ | / / \\\ -- \\ : e
    x \ \/ --~~ ~--| \ | x
    * \ \-~ ~-\ | *
    g \ \ .--------.__\| | g
    o \ \_// ((> \ | o
    a \ . C ) _ ((> | / a
    t /\ | C )/ \ (> |/ t
    s / /\| C) | (> / \ s
    e | ( C__)\__/ // / / \ e
    x | \ | \\__// (/ | x
    * | \ \) `---- --' | *
    g | \ \ / / | g
    o | / | | \ | o
    a | | / \ \ | a
    t | / / | | \ |t
    s | / / \/\/ | |s
    e | / / | | | |e
    x | | | | | |x
    * g o a t s e x * g o a t s e x * g o a t s e x *

    1. Re:get a handful of this by Anonymous Coward · · Score: -1, Offtopic

      I would like to get a fistful of kind buds, stick them in there, and then smoke them. Care to join me?

  4. and the answer is... by ArchieBunker · · Score: -1, Offtopic

    False

    although that is a very creative first post.

    --
    Only the State obtains its revenue by coercion. - Murray Rothbard
  5. Re:First Calculus Post by Anonymous Coward · · Score: -1, Offtopic

    This is a hell of a lot better than my Katy posts. I applaud you.

  6. Re:First Calculus Post by Wire+Tap · · Score: -1, Offtopic

    Actually, the derivative of that function is f'(x)=6x, so when you evaluate f'(x) at 1, you get 6. So, the slope at x=1 of that function is 6 y units per y unit. Simple, really. It is not false, and I am not graphing it for you on here. :) Good first post, though! Come on, moderators, don't mod me down.... and heck, mod him up! That was funny!

    --

    Man is born free; and everywhere he is in chains.

  7. Re:And it's about time! by Anonymous Coward · · Score: -1, Offtopic

    what's your karma, silort? did taco bitchslap you?

  8. Re:It's true. by Anonymous Coward · · Score: -1, Offtopic

    youre THAT flabby hmm?

  9. Re:First Calculus Post by maelstrom · · Score: 0, Offtopic

    For God's sake, please give it up. Fear it no less than the sensual passion, because it, too, may take up all your time and deprive you of your health, peace of mind and happiness in life.

    --
    The more you know, the less you understand.
  10. Re:And it's about time! by Anonymous Coward · · Score: -1, Offtopic

    -6. i'm not sure it was taco, but i lost 45 in a day. i suspect a gay wiccan conspiracy.

  11. Re:It's true. by Anonymous Coward · · Score: -1, Offtopic

    Just because nature cheated you, is no reason to be jealous.

  12. Cool by Anonymous Coward · · Score: -1, Offtopic

    It looks like the Northern Afghanistan Alliance uses Slashcode!

    1. Re:Cool by WildBeast · · Score: 0, Offtopic

      looks like MS was right, Linux is Anti-American :)

    2. Re:Cool by Anonymous Coward · · Score: -1, Offtopic

      Umm, php-Nuke is open source... dumbass

  13. Re:First Calculus Post by Anonymous Coward · · Score: -1, Offtopic

    f(x):=3x^2

    therefore:
    f(x+h):=3(x+h)^2
    :=3(x^2 +2xh +h^2)

    f'(x):=lim(h->0) [(f(x+h) -f(x))/h]
    :=lim(h->0) [(6xh +h^2)/h]
    :=lim(h->0) [6x +h]
    therefore:
    f'(x):=6x

    when x=1; f'(x)=6

    h is just some amount that is a fraction of x.
    your graph (sketch) should show the curve and a (straight) secant line passing through the points (x,y) and (x+h, 3(x+h)^2). any straight line that cuts the curve twice will do, but if you choose the two points too far apart it'll look like you don't know what you are doing and had to ask on Slashdot. Draw another line (points like before but smaller value for h, hence points will be closer)to show that as h tends to zero, the gradient of the secant line provides an increasing better approximation to the true gradient of the curve at point x.