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Remote RSA Timing Attacks Practical

David Brumley and Dan Boneh writes "Timing attacks are usually used to attack weak computing devices such as smartcards. We show that timing attacks apply to general software systems. Specifically, we devise a timing attack against OpenSSL. Our experiments show that we can extract private keys from a OpenSSL-based server such as Apache with mod_SSL and stunnel running on a machine in the local network. Our results demonstrate that timing attacks against widely deployed network servers are practical. Subsequently, software should implement defenses against timing attacks. Our paper can be found at Stanford's Applied Crypto Group."

34 of 223 comments (clear)

  1. Personal crypto? by pro-mpd · · Score: 5, Interesting

    OK, so we know now that SSL servers may be vulerable. Can this sort of an attack be used against personal encryption, a la pgp?

    1. Re:Personal crypto? by Anonymous Coward · · Score: 4, Funny

      Only if you type really, really fast.

    2. Re:Personal crypto? by tjohns · · Score: 5, Informative

      No. According to the article, "Timing attacks enable an attacker to extract secrets maintained in a security system by observing the time it takes the system to respond to various queries." Once you choose to encrypt and send a message with GPG/PGP, it is done, and that is that. Aide from the conversation your computer makes with the SMTP server, there is no further communication between hosts, so there is no way somebody could try to measure the time it takes to generate an encrypted reply to something.

      Therefore, as long as your computer isn't comprimised, you're fine. However, if your computer is comprimised, well, you've got bigger things to worry about than somebody trying to time how long it takes to encrypt a message. ;-)

    3. Re:Personal crypto? by SgtPepper · · Score: 4, Informative

      I should clarify though that it would only be possible if someone was on your system WHILE you were encrypting something or decrypting something that was encrypted with your key. It isn't /possible/ to execute this attack AFTER something is encrypted, only during the encrypting process.

      Someone tell me if I'm wrong...I might be, but I don't think I am...

  2. Oh Shiiiiiiit! by The+Mainframe · · Score: 4, Funny

    Great, and this after I've been bragging about my 'not-breakable for a billion years' 2048-bit key.
    $mouth . $foot

    --
    --Bennett Prescott
    Former Lord Of Packets
  3. How could OpenSSL be vulnerable to security attack by MisterFancypants · · Score: 4, Funny
    Microsoft didn't write OpenSSL..How could this be possible????

  4. Dan Boneh by blackmail · · Score: 3, Funny

    Is one smart cookie. He's also the only prof I wouldn't take a class from because it wasn't webcast. In other words you can't pause and rewind his live lectures. He talks real fast. And tilts his head at a 30 degree angle to his left.

    1. Re:Dan Boneh by ChadN · · Score: 3, Interesting

      I took a couple classes from him, and found him to be a very good lecturer. VERY knowledgeable about his subject, and very well organized with his presentation.

      Even reading all the course books intently, I got a great deal of helpful information from the lectures.

      --
      "It's overkill, of course. But you can never have too much overkill." - Anonymous Slashdot Coward
  5. Umm... by Anonymous Coward · · Score: 5, Funny

    That summary is so buzzword-rich I feel compelled to purchase a product, if one were offered.

  6. Not cracking crypto by Phishpin · · Score: 3, Insightful

    The article says that they "can extract private keys from an OpenSSL-based web server". That doesn't sound like a compromise to the RSA algorithm. They just got the private key.

    --
    -phish
  7. is this easy to implement? by circletimessquare · · Score: 4, Interesting

    just randomize the timing in every reply... a few NOOPs?

    or am i missing something?

    it would seem to me that the encryption/ decryption process has no self-awareness of what is a short and long time to reply. therefore, maybe you need another process to watch the time it takes to reply. it could average it over time and provide some sort of super-lengthening of the time it takes to reply so that long replies can be made to look shorter than an artifically lengthened short reply?

    because if you just lengthen the short replies, doesn't that still reveal something since a really long reply will still show a spike?

    if replies happen on the order of 5-50 nanoseconds naturally (hypothetically speaking), and you lengthen the short replies so that the range becomes something like 35-50 nanoseconds, then that could still reveal something.

    so what is needed is maybe a superlengthening of replies so that 5-50 nanoseconds becomes 100-200 nanoseconds? only that way could you hide the difference between a 5 nanosecond and a 50 nanosecond reply completely, no?

    doesn't this have implications though on overall speed? or are the times still so tiny it really doesn't matter?

    --
    intellectual property law is philosophically incoherent. it is your moral duty to ignore it or sabotage it
    1. Re:is this easy to implement? by selectspec · · Score: 4, Informative

      It's called RSA Blinding which pads the computation by some random timings. Implementations vary but typical performance overhead is 2-10%.

      --

      Someone you trust is one of us.

    2. Re:is this easy to implement? by rew · · Score: 4, Informative

      The idea is that bad code will do something like:

      if (bit[i] != key[i]) return FALSE;

      By timing this accurately, you'll know what (approximately) bit failed. Once fixed, and everyone agrees the fix is trivial, your code will look something like:

      if (bit[i] != key[i]) bad_bit = 1;
      else good_bit = 1;
      [...]
      if (bad_bit) return FALSE;

      As you can see the computer has to do exactly the same work for a good or a bad bit. Thus the timing should be identical.

      It's VERY VERY hard to mask these timing issues by "random" delays. Worst case, the attacker guesses your random numbers. Best case, the attacker will have to run his attack a couple more times to get the same results through the noise.

      Cryptographers have known about this for years. In fact, this (kind of) attack was posted on slashdot no more than a week ago.

      Roger.

  8. In a nutshell... by Dr.+Bareback · · Score: 5, Informative
    The paper was admittedly somewhat difficult reading for those of us who are not frequently subjected to academic research texts. However, I would like to take some time to shed some light on the topic for those of you who do not have an Master's degree from Harvard as I do. :)

    These timing attacks are very different from those executed against an embedded device, such as a smart chip, in that the attack against the smart chip aims to disrupt the device and cause it to skip one or more instructions in order to breach the security. These attacks instead use timing attacks as an oracle which allows the malicious hacker to make thousands of guesses against the insecure server, knowing that the timing of the response will eventually give away the key. For instance, by sending a specially crafted packet to one of these vulnerable SSL servers, one will be able to deduce from the timing whether a given bit in the private key is a 0 or a 1, simply by looking at how much time it takes to respond (on the average, for that particular crafted input). You can see how this could be a bad thing.

    Although this could be a very nasty threat today for machines within a small, predictable network distance from the attacker, there is hope. In the 2.5 kernel, developers have begun adding features that randomize round trip latency for packet reponses. This means that these systems will not serve as good oracles for an active attacker because the timings generated by the randomization feature will not approximate an even (normal) distribution. This means that even by averaging them out, it will not be possible to determine from the timing of a cryptographic response whether (say) the bit is a zero or a one.

    This vulnerablility has actually been discussed as a possiblility for the past few years (mostly within the CERT "members only" club) but it was not until recently that a practical exploit was published. So if your keys were compromised before this went public, perhaps one of the blackhats figured the trick out first. :(

    1. Re:In a nutshell... by Lux · · Score: 4, Insightful

      I'm pretty sure you're trolling, but I'll bite...

      Your elitism has been commented on thoroughly, so I'll skip to the meat. :)

      It takes 1.5 million queries to break an SSL key using this technique if you have an account on the same machine. That's for a local attack.

      They go on to give evidence that a remote attack is possible, but don't actually give parameters that would indicate the complexity of the attack. 1.5 million queries is already kind of pushing it though, and I would imagine taking the attack to the remote setting, even with a small round trip, will explode the complexity significantly. So the attack may not be feasible at all.

      Furthermore, adding random variance to latency data doesn't theoretically help much. Get enough samples, and that noise drops out. It raises the number of queries, yes, but doesn't stop the latency from forming a statistically usable distribution.

      -Lux

  9. Xbox by Anonymous Coward · · Score: 5, Interesting

    Wouldn't this type of attack be feasible on the Xbox instead of trying to factor the key? You even have access to the hardware so very precise timing could be done.

    Just a thought.

  10. After reading the article.... by myst564 · · Score: 5, Informative

    It seems that this is severe when the attacker is very "close" in network terms to the server. It relies on the time difference when multiplying numbers in OpenSSL.

    So, if you are "far" away from the SSL server, I suppose this attack isn't as "good".

    All this talk about closeness and goodness really just means we're using smoke and mirrors.

    OpenSSL needs to figure out how to be completely mundane with any input string from the client.

  11. Followup or what? by Stavr0 · · Score: 4, Informative
    Swiss Researchers Find A Hole In SSL

    This sounds a lot like the weakness discovered last month by the LASEC folks in Switzerland ...

    1. Re:Followup or what? by SiliconEntity · · Score: 4, Informative

      No, the recent OpenSSL attack was different. That relied on distinguishing messages which failed due to a bad MAC versus bad padding. The timing was slightly different in the two cases. It allowed you to get some portions of a sample message decrypted.

      The new attack just looks at how long the RSA decryption takes for carefully chosen values, and determines from that what the RSA secret exponent is, which means the RSA secret key. So this leaks the server's secret key and the server operator loses all of his cryptographic security. It's a much worse break.

      However the timing precision needed for the new attack is much tighter thatn for the pad-vs-mac one, so at this point it can only be mounted across a LAN or on a shared-user system.

  12. Where's the DMCA lawsuit by Anonymous Coward · · Score: 5, Funny

    Why don't all the OpenSSL folks sue these guys under the DMCA? It's good enough for Adobe, it should be good enough for Open Source folks, right?

  13. Define Remote.... by SgtPepper · · Score: 4, Informative

    According to the conclusion at the end of the article:

    "We devised and implemented a timing attack against OpenSSL { a library commonly used in web
    servers. Our experiments show that, counter to current belief, the timing attack is eective when
    carried out between two machines in a local network. Similarly, the timing attack is eective
    between two processes on the same machine and two Virtual Machines on the same computer. We
    hope these results will convince designers of crypto libraries to implement defenses against timing
    attacks as described in the previous section.
    "

    So it looks like it is only useful against machines on the local network, which means you would have to have a comprimised machine on the network to launch the attack from. Possible yes, but it's not has simple has querying a remote system over the internet (I would assume that the unknown latency would render a timing attack useless, but couldn't use you use a traceroute to determine the latency and compinsate? Just a thought..) Anyway, I don't expect there to be 1,000s of comprimised servers by tommorow...

  14. Chill please, It's not that bad by Tailhook · · Score: 3, Interesting

    IANACE (crypo expert)

    The attack works by measuring the time it takes for an SSL server to encrypt things. By causing the SSL server to do lots of encrypting of known things, you can derive a private key. Apparently, this must be repeated many times and is highly dependent on timing. Thus, it's not fast and network latency, high server load, etc. will reduce the effectiveness of the attack. Further, subtle environment differences prevent an obvious "script kiddy" level implementation of this attack. A relevant quote from the paper:

    As we will see, the performance of our attack varies with the exact environment in which it is applied. Even the exact compiler optimizations used to compile OpenSSL can make a big difference.

    A solution to this might be to implement a small random delay before the server returns cyphertext to the client, no? A few extra milliseconds here and there would probably be sufficient.

    --
    Maw! Fire up the karma burner!
  15. Re:I'm sorry by Tailhook · · Score: 4, Funny

    A SQL varient of this is far more effective:

    insert into mouth values ('foot')

    --
    Maw! Fire up the karma burner!
  16. ROT-13+ by silvakow · · Score: 3, Funny

    Is there even a reason to be concerned with this when ROT-13+ is perfectly secure? It was recently expanded from regular ROT-13 so it doesn't only encrypt letters, so it should be good enough for any application.

    --
    In the long run, we're all dead.
  17. Actualyl it IS that bad by Anonymous Coward · · Score: 5, Interesting


    Being further from the server will add noise, but they already compensate for noise by averaging 7 samples (5 would have been sufficient for local use). Over a remote network, you take more samples. (perhaps quite a few)

    It currently takes 2 hours to crack a server.
    If you have a week or so of time on your hands, a realtively unused server (not mail.bigisp.com but admin.bigisp.com), and the asministrator doesn't notice the traffic spike, quite a few sites could be vulnerable.

    Remember, people get upset when crypto can be cracked in terms of *years* and *dollars*. This can crack things in HOURS on a fast pc.

  18. Idiot... by andfarm · · Score: 3, Informative
    Buffer overflows are a result of sloppy code missing length checks.

    Timing attacks are completely unrelated -- they are a result of code running predictably enough that the timing of a response leaks information. They are not a general security breach -- this is an isolated case where a large number of requests to a modSSL server could leak the server's private key -- but nothing else.

    --

    TANSTAAFI: There Ain't No Such Thing As A Free iPod.

  19. An explanation of this attack by Myria · · Score: 5, Informative

    The exploit behind this is actually not that complicated, if you know RSA. In RSA, you have these formulas:

    C=M^e mod n (encryption/signature verification)
    M=C^d mod n (decryption/signing)

    When OpenSSL wants to sign a message C, it needs to produce the signature M using the "M=C^d mod n" formula above. Calculating this is simple in idea: calculate C to the d'th power modulo n. However, d is a very big number; on average, it is n/2. There is no way you can calculate C^d mod n by multiplying C with itself many times.

    The answer to this is to use a "repeated squaring" algorithm. Let's say that d=17, and you want to calculate C^d. Multiplying C 17 times works, but is very slow. It is possible to calculate C^17 using the following formula:

    C^17 = C * C^16
    C^17 = C * (((C^2)^2)^2)^2

    Now, there are only 5 multiplies: 4 squares and one multiply with C. There is a pattern to when you square and when you multiply. The number 17 is 10001 in binary. The binary digits tell you when to square and when to multiply.

    You start with the number 1, and go through the bits in 10001 from left to right. For each bit, either 0 or 1, you square. But if a bit is a 1, you also multiply. This means that the first step (a 1 bit), you square, then multiply by C. Since you started out with 1, you get C here. For the next 3 bits, all 0's, you square, getting C^8 as your result. The last bit is a 1. You square, getting C^16, then multiply by C again, since it's a 1 bit. This gets you C^17.

    The problem here is that "1" bits require a different amount of work than "0" bits. When you have a "1" bit, you have to perform an additional multiply than for a "0" bit. If you can somehow time each multiplication/square step, you can determine whether the bit of "d" was a 0 or 1. If you can do this 2048 times, you can calculate all the bits of the private key, which is "d". That is what this attack does, minus all the complicated details.

    This RSA hole can only possibly be exploited when the attacker has physical access to the device (as in a smart card attack), or the owner of the private key automatically signs/decrypts messages sent from a client (as in OpenSSL). Manual encryption systems, such as those used for email, can't be exploited this way realistically.

    Myria ^-^ *hugs*

    --
    "Screw Sun, cross-platform will never work. Let's move on and steal the Java language." - Visual J++ Product Manager
  20. Why hasn't the simple fix reached OpenSSL? by dido · · Score: 5, Interesting

    I believe Paul Kocher first proposed (this is PDF) this attack way, way back in 1995, and as I recall, he even applied it to networked systems. RSA Labs' BSAFE, since version 3.0 has included a "blinding factor" in its RSA implementation that renders this attack ineffective. Reading the original RSA Labs bulletin (also PDF) on this attack shows a very simple fix, and I'm surprised that this hasn't made its way into OpenSSL! Ron Rivest proposed this back in early 1996. What's up?

    --
    Qu'on me donne six lignes écrites de la main du plus honnête homme, j'y trouverai de quoi le faire pendre.
    1. Re:Why hasn't the simple fix reached OpenSSL? by mh_cryptonomicon · · Score: 3, Informative

      Actually, if you look at the Cryptonomicon.Net article about this attack, you can see that, in fact, blinding has been added to the OpenSSL code. The issue is whether or not it is turned on by developers.

  21. Use this attack against X-Box by philthechill · · Score: 5, Interesting

    The paper mentions that things like palladium may also have this kind of problem (unless they implement timing protections of some sort), which leads me to believe the 2048-bit X-Box key could also be attacked this way, and probably much faster since you might be able to attack it right on the box without going over a network.

    But I could be wrong.

    Phil

    1. Re:Use this attack against X-Box by jareds · · Score: 3, Informative

      Microsoft's private key isn't on the X-box, but rather their public key is. This is because the public key is what the box needs to verify that a game is signed by Microsoft. It certainly does not need the private key. Hence, there is no private key on the box to extract.

      X-box security is actually extremely different from Palladium. For Palladium, it is inherently necessary to have a private key (that is, a private key inaccessible to the end user) with every computer, so that computers can authenticate the trusted kernel (aka Nexus) that they are running to third parties. If they use an RSA implementation vulnerable to a timing-based attack, a local user could easily perform such an attack, extract the key, and forge any desired authentication.

  22. From far away? Probably not... by j.e.hahn · · Score: 3, Informative
    (I would assume that the unknown latency would render a timing attack useless, but couldn't use you use a traceroute to determine the latency and compinsate? Just a thought..)

    You'd need to know something about how the latency varies. It's not constant. It's got a probability distribution over some range. (it's bounded below, and probably above too...)

    Problem is, if that probability distribution is random, or "near" random, you're going to have a bitch of a time extracting enough info to perform an attack of this sort. This is why you need to be close; it's not because there's low latency (that helps) but because the latency has low variation, which means you can assume a value for it and subtract that out. With a random distribution, your "signal" will be lost in the noise.

    It's another example of an attack being not quite as practical as advertised to the public. There's a real threat here, but it's not the "ultimate 'sploit".

    1. Re:From far away? Probably not... by bshuttleworth · · Score: 3, Insightful

      Hmmmm... Not as unlikely as that - lots of people host on virtual-machines (e.g. Verio) or with managed hosting companies (e.g. Rackspace, which is why I'm nervous ;) ). That means that latency is very low, and fairly consistent.

      Just a thought.

  23. Re:Crypto for Idiots by ManicGiraffe · · Score: 5, Informative

    Heh, everyone hold on, it's been a few years since the crypto class in college:

    RSA is based on modular arithmetic. This is nasty stuff: it's not unbreakable, but so difficult to reverse that it's not practical to do so. Basically, when my client sends a request to start a SSL session to a server, I send a number g. The server and client use that number to create a shared key that they use to encrypt their messages.

    Here's the fun part: the server can only unlock the shared messages using its private key. When I send it an encrypted message, it takes the server a certain amount of time to try and unlock it. If the number g I used to encrypt the message is close to the number that is the server's private key, it takes noticably less time for the server to respond with "good message" or "bad message". So by sending millions of queries, I can narrow in on the private key just by timing how long it takes the server to answer me.

    Note it doesn't help me read messages, only to get the private key. Of course, once I have that key, I can read anything the server receives - like credit card numbers, email addresses, etc.

    I've probably confused a few details - someone with more recent experience here feel free to correct me.