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The Deepest Photo Ever Taken

Astroturtle writes "Astronomers using the Hubble Space Telescope's powerful new Advanced Camera for Surveys (ACS) have taken the deepest visible-light image ever made of the sky. The 3.5-day (84-hour) exposure captures stars as faint as 31st magnitude, according to Tom M. Brown (Space Telescope Science Institute), who headed the eight-person team that took the picture."

17 of 218 comments (clear)

  1. 3.5 Day Exposure? by Anonymous+Canard · · Score: 5, Interesting

    Imagine a Beowulf... um. Seriously, how do you cope with reciprocity failure in a 3.5 day exposure. I would have thought that stray heat or electron flow would turn the whole image to static with such a long exposure. HST must consist of unfathomably cool (literally and figuratively) electronics.

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    1. Re:3.5 Day Exposure? by Biogenesis · · Score: 5, Insightful

      ...and it is, hubble has some type of cryogenic cooler onboard. At least according to an article in Sky and Space magazine (it's an australian one AFAIK) a while back that talked about all the extra stuff that was put on hubble last time a shuttle stopped by to maintain it.

    2. Re:3.5 Day Exposure? by deathcow · · Score: 5, Informative

      Astrophotos are commonly made by combining many shorter exposures. Each additional exposure improves the signal to noise ratio yielding progressively greater detail.

      As far as color and reciprocity, Hubble color shots are not always as the eye sees them. The famous "pillars of creation" shot for example, presented the light from oxygen ionization in one color, the light from sulfur ionization in another color, the light from hydogren ionization in another color.

    3. Re:3.5 Day Exposure? by Liquid+Tip · · Score: 5, Informative

      CCDs do not suffer from Reciprocity failure like film does. However there are other problems that will turn long exposures into junk (such as cosmic rays as HST is not sheltered by the earths atmosphere!). So many shorter exposures are taken and then coadded to make a 3.5 day exposure.

  2. Re:Details on the exposure techniques? by deathcow · · Score: 5, Informative

    Many spacecraft have small jets that push them into different positions in space. Hubble has no jets because the exhaust gas from jets could damage its delicate mirrors. Instead, Hubble uses momentum to move.

    When Hubble needs to move to a new target, engineers on Earth radio a signal to the HST flight computer. The flight computer then activates the Reaction Wheels.

    Reaction wheels are heavy fly wheels that spin. As they spin, the momentum from their motion causes the telescope to move. There are four Reaction Wheels. By spinning each one at a certain speed and in a certain direction, engineers can point the telescop e anywhere they want.

  3. hubblesite.org by zaneIO · · Score: 5, Informative

    Here is a link to a higher resolution image.
    Hubblesite.org

  4. exposure time misleading by jeffrey1681 · · Score: 5, Informative

    The image is not actually a single exposure of 3.5 days in duration, but is actually made from 250 separate exposures taken from Dec. 2 to Jan. 11, 2003. The total exposure time was 3.5 days.

    For those who are interested, the original hubble press release is located here.

    The site includes the image in a variety of different formats, including a 123 MB tiff file.

  5. Re:Shameless karma whoring: by Biogenesis · · Score: 5, Funny

    Thanks for the links, i've got it downloading in a new tab ri Segmentation Fault

  6. This has to be the most expensive by jkauzlar · · Score: 5, Funny

    desktop background ever created :) Its sure worth the effort, however!

  7. It's due to the way telescopes are built. by Anonymous Coward · · Score: 5, Informative

    Modern optical/IR/UV telescopes typically have a large primary mirror, which reflects light back to a smaller secondary, which reflects the light through a small hole in the primary to the detectors. The secondary is supported by little rods. It is diffraction of light by those supports which cause stars to have distorted shapes.

    (Astronomers understand the diffraction issues very well... it's usually not a problem; it just looks weird.)

    - A friendly neighborhood astrophysicist

  8. Re:It would be interesting to know... by Liquid+Tip · · Score: 5, Informative

    The best way is to download the processed HST images and see what the count rate is for a faint star. Then multiply by the gain (in the header of the image) which will give you the number of photons detected. A way to guestimate the number of photons is to compare the flux of the faintest star with the Sun. At the Earth's distance the Sun has a flux of 1.36x10^6 erg s-1 cm-2 and the apparent mag of the sun is V=-26.8. If we assume that we have a star with V=31 mag (the 50% completeness level is V=30.7 mag) then the flux recieved from the star is given by: F2/F1 = 100^((m1-m2)/5) where F1 and m1 are the flux and magnitude of the sun and F2 and m1 refer to the star. This gives 1.03x10^-17 erg s-1 cm-2. Convert the ergs into photons by the de Broglie frequency (E=hv) where we assume that a V-band photon has a wavelength of 550nm or a frequency of 5*10^14 s-1. Thus, each photon carries 3.61x10^-12 ergs which gives a rate of 2.85x10^-6 photons s-1 cm-2. So a 3.5 day exposure is 302400 secs and HST has an aperature of 240 cm so we get about 50000 photons at the entrance of the telescope. Remember.. detection of these sources means having a low background so that these photons are not lost in noise! I should also point out that HST does not leave the shutter open continuously for 3.5Hs, instead it takes a series of short exposures that are co-added. I hope this helps (and doesn't freak people out!)

  9. Damn, by fireman+sam · · Score: 5, Funny

    I'd hate to have to hold my finger on the button for that long without shaking the camera.

    *This is a lame joke*

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  10. Re:Streaks by Liquid+Tip · · Score: 5, Informative

    The "streaks" centering on stars are diffration spikes from the secondary mirror support. The colour alternates as different wavelenghts cause different diffration spacings.

    The big bright cluster is actually a member of Andromedae (M31). Very impressive! The appearance of fuzziness is because the CCD oversamples the resolution of the telescope - which is necessary for good photometry - if you want it "sharp" then just bin the pixels by 2x2 or 3x3 or whatever looks best!

  11. Mirror of full JPG by idiot900 · · Score: 5, Informative


    http://wuarchive.wustl.edu/users/tom/mirrors/hub bl e/full_jpg.jpg

    is a mirror of the full JPEG - about 5M. Enjoy.

  12. Not all scopes exhibit diffraction spikes. by fmaxwell · · Score: 5, Informative

    Something I've wondered for a while... what's up with the points coming off the stars?

    As was mentioned in another post, those are diffraction spikes from the supports for the secondary mirror.

    Newtonian reflectors and classical Cassegrain telescopes support their secondary mirror with "spiders" that produce diffraction spikes. There have been various efforts over the years to eliminate these from that type of telescope. One method is to seal the tube with an optical flat (a flat piece of optical glass) which supports the mirror. The trade-offs include longer times for the scopes to reach temperature equilibrium, distortion from imperfections in the optical figure of the flat, and slight light loss. Other attempts have included the use of spiders with curved support arms, which reduce or eliminates spikes at the cost of slightly degraded overall image contrast.

    Other telescope types, such as refractors, Maksutovs, Schmidt-Cassegrains, and Yolo reflectors have no diffraction spikes, but they are all more optically complex (Yolos, for instance, require toroidal mirrors) and are more difficult to produce as a result. Refractors have the added problem of chromatic abberation, which is the fringing of color on the edge of bright objects. Various complex, multi-element objectives have been developed to reduce, or even practically eliminate, this problem. The problems are optical complexity, cost, and light loss. Figuring a 3-element objective lens for a refractor means grinding six optical surfaces with precise curves. Compare that to a Newtonian which has a single parabolic primary mirror and a flat optical secondary.

    There are many other telescope types than the few popular types I mentioned here and each have their proponents. Most designs that have survived the test of time can be made to perform well, but each has trade-offs.

  13. Big Picture... by HobbitGod42 · · Score: 5, Interesting

    Does anyone know if there is a BitTorrent file out for the 128mb TIFF? the nasa servers are a bit slow and I feel my hardware cycles and bandwidth could be of use...

  14. Re:Very impressed... by LMCBoy · · Score: 5, Interesting

    Actually, the really unique thing about this image is the stellar populations. The stars you see in the image are almost all in the Andromeda galaxy (aka M 31), seen here.

    M 31 is 2.2 million light-years away. This is the galaxy that Hubble originally resolved into stars, thereby settling the Shapley-Curtis debate on the true scale of the Universe. However, the stars Hubble saw were the very brightest supergiants in M 31. In this HST image, we see stars 2 magnitudes fainter than the ancient main-sequence turn-off; i.e., stars which are intrinsically fainter than our Sun! This lets us learn a lot about the ages and chemical composition of M 31's halo stars, which turn out to be quite different from the stars in our halo (our halo is entirely composed of ancient, metal-poor stars; M 31's halo contains stars that are only 6 Gyr old, and much more metal-rich than our halo).

    I heard Tom Brown give a talk on this work last week; very cool stuff.

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