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The End of Encryption?

An anonymous reader writes "The encryption algorithms that make virtually all electronic commerce possible work only because certain mathematical problems are very, very hard to solve. But some mathematicians are trying to prove that there's really no difference between 'hard' and 'not hard' problems--known in the math biz as P and NP. In an article on TechnologyReview.com, Simson Garfinkel spells out the real-world consequences of this mathematical conundrum."

4 of 633 comments (clear)

  1. Re:Quantum Computers / Shor's Algorithm by wwest4 · · Score: 5, Informative

    > Or a quantum computer is made that can break all these passwords.

    No. To put in plain language: there are forms of encryption more advanced than those that employ difficult math problems. Quantum computing does not pose a threat to a OTP system that employs quantum key exchange. Sorry.

  2. Re:It's not "the end of encryption" at all by Control+Group · · Score: 5, Informative
    True, but OTPs aren't reusable, and the key needs to have as much information as the message, so they're not an answer to digital signatures or secure transactions online. Or at least, not an answer that's easy enough for me to comprehend.

    Since those are the areas in which most people encounter encryption, that's what the author was focusing on.

    On the other hand, the author also didn't give any reason to think that P?=NP is even coming closer to being resolved, and certainly no reason to think that it will end up being P=NP...so I don't see how PKE is threatened, either.

    It's a non-story, if you ask me. Not that anyone did.

    --

    Reality has a conservative bias: it conserves mass, energy, momentum...
  3. Re:As I thought I understood it... by RWerp · · Score: 5, Informative

    by having a plaintext and cyphertext, a quantum computer can make it very trivial to find the key using certain iterative attacks on the algorithm. I mean, isn't the quantum computer "instantly" backtracking up until the substitution step of each round, as the operations would be reversible up until that point? I would think the complexity to crack is only dependant on the number of rounds.

    There is no possibility to use a quantum computer to make simultaneous dictionary attack (guessing the key by trying all possible keys at the same time), because, contrary to what most people think, you can do only one usable computation at the same time on a quantum computer. The difference between classical and quantum computer is that you can 'tune' the quantum computer into doing this one computation which is important -- like the one needed to break the key. If you can do that, you've cracked the cipher. But it requires an algorithm specific to the cipher in question. A good defense before such attack would be to change the cipher in such a way as to make the corresponding quantum algorithm useless, and make attacker think really hard before coming up with another one. A bit more challenging than just increasing the key length.

    IANAQCE (I Am Not A Quantum Computing Expert), but that's what I gathered from listening to seminars delivered by people from the field.

    --
    "Long run is a misleading guide to current affairs. In the long run we are all dead." (John Maynard Keynes)
  4. Re:Quantum Computers / Shor's Algorithm by swillden · · Score: 5, Informative

    I thought that all the public key (etc) systems relied on a "hard math problem" to produce the public-key secret-key pair.

    Sort of. Actually, they rely on the hard math problem to make it so someone who knows the secret key can do something that someone who knows the public key cannot, and, potentially, vice versa. Generation of keys is simpler.

    When I generate my DES and AES keys I go through that "mostly prime" exercise.

    Umm, no. DES and AES don't care about primes, or factoring, etc., at all. The DES and AES keyspaces are (nearly) flat. To pick a DES/AES key, you just choose a random 56-bit/128-bit number. (I said nearly because DES does have some weak keys, so some people choose to avoid those).

    So quantum computing should be able to do the "large nubmer factoring" exercise necessary to crack the key...

    For public-key algorithsm like RSA, DSA, Diffie-Hellman, ECC (well, you don't use factoring to attack ECC, but same notion), etc., yes. For secret-key algorithms like DES, AES, IDEA, RC-4, Twofish, etc., no, there is no number factoring exercise or similar that will help. So probably not, which was my point.

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