New, Faster Attack against SHA-1 Revealed
VxSote writes "According to Bruce Schneier's
blog, a team of Chinese cryptographers has announced new results against SHA-1 that speed up the time required to find collisions compared to their previously published attack. Schneier says that a SHA-1 collision search is now 'squarely in the realm of feasibility,' and that further improvements are expected."
I wonder how this will effect RFC 4109 in that it depreciates MD5 in favor of SHA1. Does this mean that SHA1, at 2^63 is less secure than MD5 at a brute-force 2^64? I'm not a crypto expert or anything, just asking the question; will this effect the proposed standard for the HASH algorithm used in IPsec?
While this finding definitely shows a weakness in the SHA algorithm, it isn't a weakness that makes most applications that use SHA any more vulnerable. They found a way to generate two texts that produce the same hash using an algorithm with a time complexity of 2^63 instead of 2^80 as would be required for a brute force attack. However, being able to generate two texts that produce the same hash won't help you exploit most systems that rely on SHA. If someone finds a way to generate text that produces a SPECIFIED hash in 2^63 time, then there's reason to be concerned. However, since these findings show that SHA-1 has some weaknesses, it's probably time to start looking for a better hashing algorithm before a more serious vulnerability is found.
What no one seems to mention is that their attack finds "freeform" collisions. I mean, they go and find two plaintexts with the same hash. I wouldn't worry about it until they find 2^63 attack against given plaintext/hash.
You can read about the distinction in Birthday Paradox article on Wikipedia. In short, when the difficulty of finding collision against a given message is 2^n, the difficulty of finding any two colliding plaintexts is 2^(n/2).
So, while they may have found 2^63 attack against SHA-1, it is still a "birthday attack", and to find collision against my message signed with sha-1 the attack would still be 2^126.
Or did I miss something?
Robert
Bastard Operator From 193.219.28.162