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Furthest Gamma-Ray Burst Ever Observed

jd writes "The SWIFT team have announced the furthest-ever observed super-massive gamma-ray burst (from 13 billion light years away). The burst was observed on the 6th of September and lasted for 3 minutes - long enough for a number of other telescopes to home in on the gigantic explosion. The distance is only barely within the reaches of the observable universe. The idea of the SWIFT telescope and follow-up observations is that they will discover both the cause of the bursts and the consequences to the star."

25 of 273 comments (clear)

  1. NOVA ran a program on gamma ray bursts... by Propagandhi · · Score: 5, Informative

    Imagine there are a few people rather lost at the headline (we're not all astronomers/cosmologists/whatever :) ). Anyway, NOVA ran an excellent show on this a couple years ago, and as usual there was an excellent companion website.

    If that doesn't answer your questions, well... there's always Wikipedia. /I feel like a Karma whore linking to wikipedia, mod me as you see fit..

    1. Re:NOVA ran a program on gamma ray bursts... by Propagandhi · · Score: 4, Informative

      The observable universe is the total volume of the universe from which light could have reached us since the beginning of said universe (the big bang or whatever).

      In other words, as you get farther away from our point of observation (Earth and the area immediately around it) you eventually reach a point in space which is so far from us that light could not have reached us. Assuming that nothing can move faster than the speed of light, this sphere would include everything that could have possibly affected us since the beginning of the universe. Ugh. I hope that makes sense, and I hope I didn't screw that up.

      As usual Wikipedia has more information: Cosmic Light Horizon and Obxervable Universe

    2. Re:NOVA ran a program on gamma ray bursts... by Propagandhi · · Score: 3, Informative

      So, the universe (according to our understanding) is a constantly growing sphere with earth in the center?

      No, no. That's the key difference between the observable universe and the actual universe itself. The observable universe is just the part of the universe we can actually see/be directly affected* by.

      Sorry, I think I left a few "observables" out of my original reply. You're absolutely right, there's still a universe beyond the observable universe. Problem is, by the time you get to that part of the universe it will have become part of the observable universe (because you can't go faster than the speed of light).

      Important note: as you move your theoretically observable universe changes. So the observable universe for your hypothetical Enterprise would be different from ours, as it would be able to see light which had not reached Earth.

    3. Re:NOVA ran a program on gamma ray bursts... by Michael+Woodhams · · Score: 5, Informative

      Here's the simple answer:

      About 13.5 billion light years ago, the universe changed from being opaque to photons to being transparent (an event inappropriately called "recombination"). No photon emitted earlier than this time could reach us, so we cannot observe further than about 13.5 billion light years away. (The photons emitted at that time are the cosmic microwave background.) So the observable universe is 13.5 billion light years in radius. A billion years from now, it will be 14.5 billion light years in radius.

      However, it gets more complicated: the universe is expanding, so the space that photon travelled through has got bigger in the meantime.

      Imagine two points in the universe. Because the universe is expanding, the distance between them is increasing with time. The rate at which the distance increases is a velocity (which you can think of as causing the red shift of distant galaxies.) Hubble's law says this velocity is proportional to the distance between them. If they are sufficiently distant, the relative velocity is greater than the speed of light.

      So (for example) imagine this is twice the speed of light. A photon emitted from one point travels towards the other. After one year, it has travelled one light-year, but the points have got two light-years further apart - clearly it will never arrive. These two points are not in each other's observable universes. The edge of our observable universe are the points which have a recession velocity equal to the speed of light.

      The discussion above assumes no acceleration. Of course, astronomers from Hubble onwards knew there would be acceleration, but it wasn't until the mid 1990s that we could measure it.

      It turns out, contrary to general expectation, that the expansion of the universe is now accelerating. This means that as time goes on, points don't have to be so far apart before their recession velocity exceeds the speed of light, so in a sense the observable universe is getting smaller. (In the sense that points that were within our observable universe in the past are no longer so. But remember that the points are always getting further apart - the radius of the obserable universe is increasing linearly with time.)

      I am an ex-astronomer, not a cosmologist. There may be subtle errors in the above, but I hope not.

      --
      Quattuor res in hoc mundo sanctae sunt: libri, liberi, libertas et liberalitas.
  2. Re:An honest question... by Peyna · · Score: 5, Informative

    How do we know the universe is 13.7 billion years old? It was recently discovered that the universe's expansion is accelerating as time goes by. Assuming this change in acceleration has been the case all along, doesn't that really fudge with the numbers we used to estimate the universe's age?

    There are many ways to estimate the age of the universe, not all of which involve calculating the expansion of the universe.

    http://www.astro.ucla.edu/~wright/age.html

    --
    What?
  3. Re:light instead of gamma by Tablizer · · Score: 3, Informative

    When supernovae occur you can see them. Are they the brightest visible object?

    Galaxies are the brightest visable objects. Well, actually quasars are, but are thought to be galaxies or at least closely related to them. But the total energy put out by gamma bursts is far larger than the energy put out by supernova. It is just that they do it over a wider area of the spectrum such that their visible light component is roughly comparable to supernova but beat them by far in higher-energy radiation.

  4. Re:light instead of gamma by mbrother · · Score: 4, Informative

    Well, the leading idea about (this type of) gamma ray burst says that they're associated with supernovas. So, they look like supernovas.

    Quasars are the most luminous long-lived light sources. Gamma ray bursts can release more energy for short periods of time, but there are arguments about to what extent the energy is beamed in a preferred direction (complicating efforts to calculate total energy released).

    I'm not sure what you mean by "alpha and beta?" Are you talking about alpha and beta radiation? Apples and oranges, although all are called "radiation". Gamma rays are a form of light (very high energy photons), while alpha and beta radiation isn't electromagnetic radiation at all, but rather particles (He nuclei and electrons).

    --
    Professor of Astronomy, Author of Spider Star & Star Dragon (Tor)
  5. Re:light instead of gamma by UnrefinedLayman · · Score: 5, Informative

    For being so feisty, are you quite sure there's no such thing as alpha and beta radiation?

    http://www.orau.gov/reacts/alpha.htm

    http://www.orau.gov/reacts/beta.htm

    Both are particle radiation and both plentifully originate in stars. You can read more about them in Wikipedia also.

    http://en.wikipedia.org/wiki/Particle_radiation

  6. Grammar Whore by Anonymous Coward · · Score: 4, Informative

    ahem. Farthest Gamma-Ray... Farthest . 'Further' is a definition of degree. 'Farther' is a measure of distance.

    1. Re:Grammar Whore by Anonymous Coward · · Score: 2, Informative

      There are certainly many people, especially in the US, who observe that distinction. However, there are also many people who do not make a strict distinction between 'farthest' and 'furthest'. I challenge you to find a dictionary that doesn't accept the usage of 'furthest' for distance comparison.

  7. Re:Blackhole Question... by erichill · · Score: 4, Informative
    If this massive gamma-ray burst resulted in a black hole, then how did the light escape enough to reach us here on earth, 13 billion light years away?

    Someone or another asks something like this everytime anything related to black holes comes up on Slashdot.

    The radiation emitted from black hole related events, such as quasars, gamma ray bursts, and Hawking radiation, for that matter, comes from processes near-sometimes very near, but still OUTSIDE, the event horizon. As long as you're outside the horizon, there are trajectories that escape.

    As for,

    Also, if a black hole was created at explosion, was this even more massive then we can see, yet the black hole swallowed up a majority of the explosion and what we see, is just a small glimpse of it?

    According to the literature on very massive stars, there as mass ranges that results in the star collapsing completely into a black hole such that no significant amount of matter or radiation gets away at all.

    Check out How Massive Single Stars End their Life. Figure 1 is particularly enlightening. It's a pretty math-free article, so I think anyone who's generally interested in this stuff can follow it, maybe with a bit of help from Wikipedia and Science World.

    --
    Credo sim. - I think I am.
  8. Re:I think Wyoming tried... by mbrother · · Score: 2, Informative

    What's your problem? Most observatories post public schedules with the times observers will be there, what instruments they're using, etc. When the papers are published, the dates and locations of the observations are recorded, and often the observers are noted (e.g., with footnotes about who was the visiting astronomer at Kitt Peak). There was already a circular that went out last week about these observations with her name on it, specifying exactly when and where she and another observer obtained the data. She was THRILLED to have her name on this.

    I don't think you have a good idea about how this stuff works. If you're some sort of weird astronomer stalker local to Wyoming, let us know. We've never had a problem at our observatory other than the occasional minor accident or mountain lion, and no one is ever up there alone. The people here are few and far between, usually friendly, and usually armed.

    Where are you from, because you're being weirdly paranoid?

    --
    Professor of Astronomy, Author of Spider Star & Star Dragon (Tor)
  9. Re:light instead of gamma by mbrother · · Score: 2, Informative

    No. The effects of a black hole's gravity, even a supermassive one, are rather limited. We'd need to be within a few light years to have a problem with our sun being tidally disrupted. The radiation would destroy all life on Earth long before we got close enough to have problems associated with the supermassive black hole. We'd likely be fine with a weak quasar in the Milky Way as the gas and dust in the plane would block the vast majority of its radiative output in our direction.

    --
    Professor of Astronomy, Author of Spider Star & Star Dragon (Tor)
  10. Re:light instead of gamma by Vellmont · · Score: 3, Informative

    Light is usually defined as visible light. If you start using the term light to refer to radio waves, you'll only sound very confused.

    As someone else already pointed out there is such a thing as alpha and beta radiation. I'd suggest some remedial physics classes before you discuss physics with anyone again.

    --
    AccountKiller
  11. Re:rast reaction, but how? by jd · · Score: 3, Informative
    SWIFT is a space-based telescope designed specifically to chase gamma-ray bursts. It has amazing thrusters, capable of spinning the telescope faster than anything else we have in space.


    My understanding is there's a low-res, very wide angle gamma-ray detector that they can use to scan vast sections of the sky. If the computers see anything interesting, they spin the probe to get a better look. If it's still a strong candidate, it then notifies anything and everything on Earth that is interested in such events.


    The problem used to be that, precisely because they had to book telescopes and because telescopes are rather unwieldy, even if they saw something, it was too late to get an accurate enough fix to see what the cause was.


    SWIFT was designed to solve this problem. In fact, it has discovered far more bursts than the astronomers were expecting and it started detecting them far sooner. (They got half-drowned in notifications, during the test and burn-in phase.)


    So far, it has been an outstanding success - second only to Hubble, in the sense that Hubble generates better pics for the press and the average space geek. As far as I know, SWIFT was not designed to really record much in the way of actual hard data (other than location), it was more an early-warning system for giant space explosions. That is partly how it works so fast, but with the pitfall that it means that you HAVE to have additional telescopes available, if it does detect something.

    --
    It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
  12. Re:Old news by Guppy06 · · Score: 3, Informative

    You're thinking "hand grenade in a vacuum." There was no space-time before the Big Bang, that's what it created. We're not racing away from everything, the space-time between us is spreading out. The two-dimensional analogy used in Sphereland is that of the universe being the surface of a balloon that's being inflated.

    This is why the cosmic background radiation, which is a relic from the Big Bang, is visible in all directions with the same intensity.

  13. Extremely over-simplified explanation by jd · · Score: 3, Informative
    Assume two objects to be stationary on the surface of an expanding object - say, a balloon. The angle between the two objects, relative to some point of origin, will be constant. However, when you measure the distance between the points along the surface, they move apart at a rate that is a function of the rate of expansion and their original distance.


    Any object at the edge of the observable Universe would appear to be travelling away from us at the speed of light. Which basically means, we'd never see it. (The red-shift would be infinite, amongst other things.) That's not quite the definition of the observable Universe, but it'll do.


    Anything marginally closer will be visible, but because there is an ever-increasing gap, the closer it is to the edge, the longer it'll take to see. (This is because although light travels at a fixed velocity, it is space that is expanding and therefore there is more distance to travel through.)


    In fact, your question works rather better in reverse. Given the speed implied by the red-shift, can you calculate the fantastic distances that must be involved? The answer is yes, provided you can eliminate (or allow for) any unknowns.


    For objects that have a well-defined spectral output and luminosity, it's easy. You simply compare what you see with what you should see. The shift in frequency and the reduction in output observed can both be used to guesstimate a distance.


    For objects of an intermediate distance, it's harder. There are gravitational lenses, which can make objects appear further away. They're often not close enough to other objects to be able to measure an unknown against a known. Those tend to be tougher.


    The further an object is, the less important lensing is, as you'd have to bend light more to add enough distance to be significant. By the time you get to 13 billion light-years, the lens would be so bloody obvious in its own right, you'd have probably spotted it first and allowed for it.


    However, you can't verify calculations at all easily. At those sorts of distances, you're talking about phenomena that astronomers don't fully comprehend and cannot, therefore, tell what the profile would normally look like.


    That is one reason it is important to get a good look with as many types of telescope as possible, so that we can see what created the gamma-bursts, or whatever. That way, we can verify our calculations.


    (This is actually important - strange things can happen when you don't verify data. Superluminal motion, stars older than the Universe - all have been observed, but usually because of incorrect calculations or incorrect assumptions.)

    --
    It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
  14. Re:I don't understand how this works.Can anyone he by Starker_Kull · · Score: 3, Informative

    The way we figure the distance to the furthest objects (in the 1 - 14 billion light-year range) is precisely by the rate of retreat of the astronomical objects we observe. It was noted empirically (back in the 1920's, I think) that the further away an object is from us, the faster it is retreating, in roughly linear proportion. The rate of retreat is figured out by how much the object's spectra shifts (due to the Doppler effect). So yes, some very far away objects are retreating at speeds damned near the speed of light.

    Originally, when Einstein came up with his field equations in General Relativity (1915?), they did not have a steady state solution; but an expanding universe WAS a possible solution. Apparently, this disturbed Einstein so much that he threw in a "fudge factor" called the cosmological constant, in just such a way that a steady state solution existed for the general configuration of the universe. Of course, as more and more observations poured in indicating that virtually ALL extra-galactic objects were retreating away from us, with higher speeds the further away, it became clear that the Universe was, in fact, expanding, despite the tastes of Einstein. He removed the mathematically ugly constant, and I think he later said that messing up his original equation with it was the "greatest mistake of my life."

    Of course, you may wonder how we figured out how far some objects were to begin with to USE our distance = (constant) x speed formula. This post is getting a bit long, but it turns out that supernova, explosions of very massive stars at the end of their lives, tend to have an absolute maximum brightness that has a simple relationship to the length of time they "explode". Thus, supernovae can serve as a yardstick if we can spot them in other galaxies; and fortunately, they are bright enough so that we can - I think they are the ONLY individual stars we can discern in other galaxies; all the others are just too dim from those distances....

    And how do we determine how far away the "first" supernova is? In other words, how did we calibrate that yardstick? Here I'm not sure; we haven't had a supernova go off close by (meaning, in our galaxy) in the last 500 years (and that's a GOOD thing - a supernova can shine as brightly as an entire galaxy at its peak! There was one in one of the Magellanic clouds (a pair of small, neighborhood galaxes) in 1987, I think); I know we have other yardsticks from direct parallax measurements (measuring the shift of nearer stars vs. their further cousins as the Earth shifts its position around the sun - good out to about 1000 light years now, I think), our knowledge of the absolute brightness to temperature as revealed by spectrum/color of stars on the main sequence, and some knowledge of the brightness patterns of ordinary novae...

    There is a really good book called Parallax, which goes into the whole history of how we figured out how far away stuff in the Universe is - it's a fascinating, wonderful read; here is the amazon URL:

    http://www.amazon.com/exec/obidos/tg/detail/-/0805 071334/ref=lpr_g_1/103-7798844-8308625?v=glance&s= books

    Hope this helps.

  15. Re:I don't understand how this works.Can anyone he by D2Deek · · Score: 2, Informative

    Of course, you may wonder how we figured out how far some objects were to begin with to USE our distance = (constant) x speed formula. This post is getting a bit long, but it turns out that supernova, explosions of very massive stars at the end of their lives, tend to have an absolute maximum brightness that has a simple relationship to the length of time they "explode". Thus, supernovae can serve as a yardstick if we can spot them in other galaxies; and fortunately, they are bright enough so that we can - I think they are the ONLY individual stars we can discern in other galaxies; all the others are just too dim from those distances....

    Specifically, we talk about Type A supernovae, which always have the same intrinsic brightness.

    Type A supernovae are what happen when a neutron star is drawing matter from (feeding from) a companion normal star, usually in the main sequence. As it collects matter, it gets to a certain point and explodes. Usually, both of the stars survive, with the companion being somewhat less massive afterward. :)

    The reason Type A supernovae are always the same brightness is that it always takes the same amount of matter for the neutron star to reach critical mass.

    We can tell the distance for Type A supernovae by observing one occurring near a Cepheid variable star (and thus relatively nearby).

    Cepheids are stars whose variability (the rate at which it dims and brightens) is directly related to its luminosity. So by looking at a Cepheid's variability, we can calculate how intrinsically bright it is. If a Type A supernova occurs near a known Cepheid, we can use the supernova's brightness to refine our calculations of how far other Type As are. And so we have two linked "Standard Candles" for the universe, one for relatively short distances and one for the rest of the universe.

    Hope this helps. :)

  16. Re:light instead of gamma by -brazil- · · Score: 2, Informative

    Only some particle radiation (beta, I think), and high-energy E.M. radiation (UV and above), has a more than miniscule probability of doing that.

    All particle radiation has that effect, and it's actually weakest in beta radiation. Alpha radiation is a lot more destructive (four nucleons instead of one electron!) but can be shielded much easier, exactly because it interacts more readily with matter. I think Neutrons are the worst, because they can activate (make radioactive) atoms they hit.

    --

    The illegal we do immediately. The unconstitutional takes a little longer.
    --Henry Kissinger

  17. Re:rast reaction, but how? by Paul+Dirac · · Score: 2, Informative

    Swift (not an acronym, so don't capitalize all of the letters) does have a wide field of view gamma-ray telescope. The interesting thing is that it also has a narrow field of view x-ray telescope, as well as a narrow field of view UV/optical telescope on board. This allows the wide field of view instrument to find the burst, then have the telescope slew to position to observe it with the x-ray and UV/optical scopes.

  18. Re:It still doesn't make sense by rubycodez · · Score: 3, Informative

    you have the wrong idea of "the center of the Universe". that's a meaningless phrase. We are at the center of our observable universe, but the universe as a whole is expanding, and you could call any body you wish the "center", and if you were located there you would see the rest of the universe moving away from you.

  19. FYI by Retric · · Score: 2, Informative

    Neutrons are the worst type of radiation for several reasons.

    They are neutral in charge so they tend to pass though mater and magnetic fields easily, which makes them hard to shield.
    They tend to be sent out at high energy's so they tend to create lots of ions along their travel path before they slow down enough to be absorbed. These ions tend to do significant cellular damage.

    When they are finally absorbed they tend to create an unstable element which will decay and emit more radiation possibly some other type of radiation and possibly more Neutrons.

  20. Re:When do we get to see the big bang? by lgw · · Score: 2, Informative

    The cosmic microwave backgroud radiation is the closest to seeing the big bang as we can get. Up to a certain early point in the universe's history, the entire universe was effectively opaque, though glowing brightly with its own heat. At some point the universe expanded enough to become transparant, and the light of that moment is visible in every direction all the time, as weak microwave radiation.

    --
    Socialism: a lie told by totalitarians and believed by fools.
  21. Re:light instead of gamma by mbrother · · Score: 2, Informative

    That's probably the case for the short duration bursts (there was one like this identified in April -- there's probably a NASA press release you cna find about it). The long-duration bursts like this one at z=6.3 have been associated with a type of supernova.

    --
    Professor of Astronomy, Author of Spider Star & Star Dragon (Tor)