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Israeli Company Creates Nano-Armor

Izeickl writes "According to IsraCast, an Israeli company has created materials made of inorganic fullerene-like nanostructures (IFs) which have amazing shock absorbing properties. During preliminary tests, these materials, which are five times stronger than steel, have successfully resisted to steel projectiles generating pressures as high as 250 tons per square centimeter. These materials could be incorporated in "nanoarmors" able to protect soldiers or police forces within three years."

5 of 416 comments (clear)

  1. Good news by Anonymous Coward · · Score: 5, Funny

    This nanoarmor will vastly improve the protection available for nanosoldiers.

    Right now we cannot deploy nanosoldiers due to the high risk of being trodden upon. This brings us one step closer to a solution.

  2. Finally... by Anonymous Coward · · Score: 5, Funny

    I'll be able to keep my ipod scratch free.

  3. Re:The problem is... by Supurcell · · Score: 5, Funny
    The armor may survive, but will the wearer be, too?
    No. As soon as the wearer of such armor is struck, he will instantaneously be transformed into absolute nothingness*. Thus he will no longer be.

    *Whether "nothingness" is Void, Null, Cipher, Zero, Nothing, or Jersey is still under debate.
  4. Re:Getting your point across. by ls+-la · · Score: 5, Informative

    more muzzle velocity, yes. better armor piercing ability, not likely.

    As a physics major, let me explain my understanding of firearms:
    I believe the bullets would (all else being equal) receive the same kinetic energy (1/2*m*v^2), so if the bullet was half the mass, it would go sqrt(2) times as fast. At least at the end of the muzzle. After that (and to a lesser extent, before) air resistance affects the bullet proportional to v^2. Since v^2 is twice as large for the smaller bullett, the force would be twice as large, and due to the lower mass, the lighter bullet would decelerate much quicker (starting at 4x). This is a rather complex differential equation (because of the square), but what's likely to happen is that at any large distance, the lighter bullett will probably hit the target moving slower.

    Now, when the bullet impacts the target I believe it's the pressure that actually does the damage. Pressure is force per unit area, and the areas would be the same (although here the analysis could possibly fail, if the lighter bullet held a pointier shape for longer). At point-blank range (or ignoring air resistance) and treating the force the target exerts as spring-like (probably good approximation for armor), the force needed to stop the bullets would be the same on each bullet (because the energy is the same so they would deform the target the same amount). Factoring air resistance back in, the lighter bullet will reach the target with less energy, and so exert less pressure. If the lighter bullet doesn't deform, it's possible that the pressure would be greater, dealing more damage.

    Conclusions:
    1. A lighter bullet will hit the target at a slower velocity.
    2. Assuming the same deformation upon impact, the lighter bullet will deal less damage.
    3. If the heavy bullet deforms and the light doesn't, the light one *might* do more damage.

    This is my best guess, but it's possible I made a mistake somewhere.

  5. Re:Getting your point across. by Ringthane · · Score: 5, Informative

    "How about teflon-coated bullets?"

    FWIW:

          The teflon coating found on many armor-piercing rounds for small arms has no effect on the armor-piercing ability of the ammunition. The teflon coat is to protect the barrel from excess wear caused by the hard materials of the projectile. Armor-piercing properties come from the composition of the projectile or from a insert of a harder substance incorporated into the projectile.

    --
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