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Solar System in a Can May Reveal Hidden Dimensions

dylanduck writes "A model solar system, made of tungsten and placed in space, could reveal hidden spatial dimensions and test alternative theories of gravity. If the system's 'planets' moved slightly differently to the way predicted by standard gravity, it would signal the presence of new physical phenomena." From the article: "Once at the Lagrange point, the artificial solar system would be set in motion inside the spacecraft. An 8-centimetre-wide sphere of tungsten would act as an artificial sun, while a smaller test sphere would be launched 10 cm away into an oval-shaped orbit. The miniscule planet would orbit its tungsten sun 3,000 times per year."

14 of 251 comments (clear)

  1. What if by Raindance · · Score: 5, Funny

    I wonder if our universe is just a hidden spacial dimension test for a super-advanced alien civilization... still trying to figure out string theory.

    1. Re:What if by stunt_penguin · · Score: 4, Funny

      Tom Cruise seems to think so.

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  2. Re:Gotchas, we got em by pilgrim23 · · Score: 5, Funny

    the old L5 Society wanted to place a module they called a High Orbital Mini-Earth there... sort of a H.O.M.E. on LaGrannge.....

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  3. Re:Gotchas, we got em by ceoyoyo · · Score: 4, Insightful

    They mentioned that would have to be taken into account. Scientists measure the gravitation attraction between human scaled objects on Earth all the time, yet that's dwarfed by Earth's gravity.

  4. Re:Why L2? by addie · · Score: 4, Interesting
    Well actually the article did say:
    A spacecraft placed there would stay fixed in space, relative to Earth, making it easier to monitor. The Earth would also shield it from the Sun's radiation, which pushes gently on any objects it shines on. Any such push could change the spacecraft's position relative to the tiny "planets" held inside it.

    So they've got that much of it thought out. But in regards to the mass of the spacecraft carrying this jar:
    And the spacecraft components themselves would exert gravitational forces on the spheres. These forces could be minimised by making the spacecraft as symmetrical as possible and putting its heaviest components as far from the artificial solar system as possible.

    "Such an experiment would be quite challenging to set up, but I don't think it is technologically impossible," says MOND expert Stacy McGaugh of the University of Maryland, US.


    So while they're full aware of the problems the mass of the craft can cause, they seem to think it's possible to minimize the effects to a reasonable level.

    My question is, aren't Lagrangian points going to start to get a bit crowded? There are only five to work with in our neighbourhood and who gets to say who uses which and for how long?
  5. Re:Suspect this is rubbish - NS has been had? by erice · · Score: 4, Informative

    A tungsten sphere 10cm in diameter would have such a tiny gravitational field that I suspect even a hydrogen atom at the ambient temperature of local space would possess escape velocity.


    No doubt. The only reason there is any hydrogen on *Earth* is because it binds readily with more massive elements. Helium does not and, as a consequence, any helium released into the atmosphere will ultimately escape. My understanding is that the only reason we have any helium at all is due to radioactive decay from heavier elements

  6. Re:Suspect this is rubbish - NS has been had? by Cecil · · Score: 4, Informative

    Actually, an 8cm tungsten sphere would exert the same gravitational pull on any object 10cm away, regardless of the other object's mass. It would have an escape velocity of 0.013 cm/s or 1.3 microns per second -- which, while very slow, is certainly within the realm of feasability. Your hard drive heads move accurately with tolerances significantly smaller than that.

    I calculated the escape velocity using the formula sqrt(2Gm/r):

    sqrt((2)(6.6742x10^-11)(5.16)/0.4) = 0.00013m/s or 0.013cm/s

  7. Re:What's tungsten? by JourneyExpertApe · · Score: 4, Funny

    Read more about bots here.

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  8. Gauss's Law by amightywind · · Score: 4, Informative

    Gauss's Law says that the gravitational acceleration of a body anywhere in an enclosed sphere is 0. At L4, L5 Earth and Sun graviational forces are balanced. The only accelerations that don't cancel out are the two body accelerations of interest. It is surprising to me that the bodies orbit as fast as 10 times per day. I wonder why they don't use heavier Uranium as the mass. It is an interesting side note that a body can stably orbit one of these points. They orbit with no body (!) at the focus. The Genesis Probe and WMAP missions have already taken advantage of this.

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    1. Re:Gauss's Law by bbaskin · · Score: 5, Informative

      If I had a nickel for everytime I heard someone suggest replacing a tungsten weight with uranium, I'd have a buck or so. Uranium (238 anyway) isn't denser than tungsten. Tungsten is the densist material for semi-practical applications. It's more available than iridium or osmium, and far less expensive than platinum, three more dense elements. For a few reasonably obvious reasons, neptunium and plutonium aren't really good alternatives to tungsten if you just want a dense lump of metal.

    2. Re:Gauss's Law by Quantum+Fizz · · Score: 4, Informative
      Gauss's Law says that the gravitational acceleration of a body anywhere in an enclosed sphere is 0.

      No it doesn't, re=read the law you linked to. It says the "surface integral of gravitational acceleration" will be zero over any arbitrarily-shaped closed surface, as long as that surface encloses zero mass. You cannot work backwards from this statement to assume that the local gravitational acceleration will be zero.

      Simple example. Imagine a closed surface (say a small sphere) 20 feet above the ground (and also assume there's no air inside) such that the surface is closed. Since it encloses no mass, the net acceleration will be zero as summed over the whole sphere. However, any object placed within this hypothetical spherical surface (eg a brick) will fall to the ground.

  9. interesting but by rucs_hack · · Score: 5, Insightful

    Since we're not able currently even to build a spaceship capable of making it to the moon (having mothballed all the relevent tech and gone for the technical nightmare that is the shuttle, and the hidiously expensive disaster that is the ISS), why bother with these types of experiments?

    Such experiments, while useful, aren't practical when we have a real and current need to figure out how to get construction workers and ordinary people into space, so we can build a realistic presence there.
    Once we're there, we could perform experiments like this at a fraction of the cost.

    Ok, perhaps I'm thinking too fancifully, but it's real concern. Let's face it, every environment we've moved into only becomes liveable when the ordinary people who know how to build stuff and make things arrive. The larger the number of people, the faster things progress.

    So long as it's only scientists and the 'elite' going into space and performing experiments progress will be very slow. That can't be good.

    What we need is people going 'prospecting' for interesting asteroids/orbiting 'junk' that can be exploited, building commercial stations, setting up routine flights into space. In short, we need economic forces active in space.

  10. Too many uncertainties by mcguiver · · Score: 4, Interesting

    It seems to me, after reading the article, that there are just too many influential factors to be able to conclude anything by such a test. From the article If gravity is leaking into extra dimensions, the slight change in its force should cause the planet's oval-shaped orbit to rotate, or precess, slowly... the orbit would precess by 1/3600 per year - "a reasonable quantity to try and measure," they say.
    I wonder how they could conclude that a change of this magnitude would come from gravity leaking into other dimension and not from any of the other myriad of possible effects. It is a good idea, I just don't see how it could work.

  11. High School Physics by Soong · · Score: 4, Informative

    Ok, some orbital mechanics.

    Going with a circular orbit because they didn't specify the ellipse:
    365.24*24*3600 = 31556736.00 seconds per year
    ./3000 = 10518.912 seconds per orbit
    1/. = .00009506686623103225 orbits per second
    .*.14*3.1415926*2 meters per orbit =
    .0000836 meters per second
    .*1000 = .0836 millimeters per second

    Pretty slow orbit. About that tungsten, 19250 kg/m3
    3.1415926*(4/3)*.04*.04*.04 = .000268 m^3
    .*19250 = 5.16 kg
    And let's say the planet is 8 mm in diameter, .004 m in radius
    3.1415926*(4/3)*.004*.004*.004 = .000000268 m^3
    .*19250 = .00516 kg

    F = G m1 m2 / r^2 =
    gravitational constant = 6.67300 × 10-11 m3 kg-1 s-2
    .00000000006673000000 * 5.16 * .00516 / (.1*.1)
    = .00000000017767262800 Newtons of force, resulting acceleration on the smaller body of
    ./.00516 = .00000003443267984496 m/s = .00003443267984496 mm/s

    Sounds reasonable to me. Assuming they can get a clean launch at exactly .0836 millimeters per second everything should be fine!

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