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Siemens Reaches 107 Gbps Data Transfer Record

prostoalex writes "Reuters is reporting on Siemens engineers reaching 107 Gbps data transmission record over a fiberoptic cable, and expects the technology to be on the market within a few years: "The test, 2.5 times faster than a previous maximum transmission performance per channel, was done in cooperation with Germany's Micram Microelectronic, the Fraunhofer Institute for Telecommunications and Eindhoven Technical University of the Netherlands.""

3 of 161 comments (clear)

  1. Re:How viable is it over longer distances? by MrJynxx · · Score: 4, Insightful

    Telecom companies dont' usually have fiber that long because of the risk of breaks and really costly repair processes, it's not because of degradation. Also the distance doesn't really matter(remember, how do you think the contients are connected? single link fiber), because if it's a good cable the data should travel at the speed of light. It depends on the recieving ends how fast your can process it.

    Also the infrastructure for telecom is quite large, you'd be surprised how much stuff is running underground.

  2. Re:How viable is it over longer distances? by 3.14159265 · · Score: 3, Insightful

    sigh... of course they usually have fiber, that's the only way you've got to carry those kind of bitrates! What do you think Verizon and AT&T are getting? CAT5e?
    sigh... of course the distance matters, the higher the span length the higher the attenuation and dispersion!
    sigh... if they say they can do 107Gb/s that's because they can fire up the laser on one side and get it with an acceptable bit error rate at the other side. These tests are not based on sending something to /dev/null!

  3. Re:107Gb/s = 13,696 MB/s = 13.375 GB/s by Hes+Nikke · · Score: 4, Insightful
    The byte is the amount of data you could store on a single coin if you had a code worked out placing it either heads up or heads down. Ones and zero's.

    almost

    The bit is the amount of data you could store on a single coin if you had a code worked out placing it either heads up or heads down. Ones and zero's. A byte would therefore need 8 coins.
    --
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