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Intel Doubles Capacity of Likely Flash Successor

Intel has announced a new technique that allows them to effectively double the storage capacity of a single phase-change memory cell without adding cost to the current fabrication process. "Phase-change memory differs from other solid-state memory technologies such as flash and random-access memory because it doesn't use electrons to store data. Instead, it relies on the material's own arrangement of atoms, known as its physical state. Previously, phase-change memory was designed to take advantage of only two states: one in which atoms are loosely organized (amorphous), and another where they are rigidly structured (crystalline). But in a paper presented at the International Solid State Circuits Conference in San Francisco, researchers illustrated that there are two more distinct states that fall between amorphous and crystalline, and that these states can be used to store data."

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  1. Re:Only Double? by wizardforce · · Score: 5, Informative

    Now, if you are using binary storage, and each bit stores 1 of 2 values, then you have the possibilities of: 00,01,10,11. Which is 4 different values. Now if you have 4 states for each bit (which I guess wouldn't, by definition, be a bit anymore), then you have 00,01,02,03,10,11,12,13,20,21,22,23,30,31,32,33. So, you have have squared the amount of information you can store.
    simply put, no. 1 bit can either be 0 or 1 *not* 00, 01, 10, 11, that would be TWO bits. doubling the number of combos for one "bit" would likely be stored as 00,01,10,11 although what you're actually doing here is storing 0001 and 1011 together hence two "bits" of info can be stored per unit in a 4 state system.
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    Sigs are too short to say anything truly profound so read the above post instead.