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Northrop Grumman Markets Weaponized Laser System
stephencrane writes "Northrop Grumman is making available for sale the FIRESTRIKE weaponized laser system. The solid-state laser unit weighs over 400lbs, sends/receives instructions and data via an RJ-45 jack and can be synchronized with additional units to emit a 100 kW beam. It looks like some piece of stereophonic amplification equipment out of the '50s. Or Fallout 3. The press release suggests that FIRESTRIKE 'will form the backbone of future laser weapon systems.'"
from here: http://www.fas.org/man/dod-101/sys/land/m998.htm
Sounds like the Hummer can carry quite a FEW 400 pound laser packs. In fact, a light and fast platform like the HMMWV is IDEAL for a weapons system like this. I expect we'll see this deployed within 10 years.
Official Heretic from the "Church of Global Warming". Proven right thanks to whistle blowers. AGW = Flat Earth Theory
it's not a weight issue. it's a power issue. the Humvee can't just run one of these off it's alternator like it can with the air conditioning. It's a high power laser system, which needs a lot of back end support (cooling, etc). Probably not made for a HMMWV. Maybe one of the larger vehicles. Notice from the release that operation is "Continuous, as long as power and coolant are provided". So power's not internal, it has to be hooked to some sort of converter. That will likely be another box almost as big as the laser itself. Cooling will be a third box (that must be powered too) also about the same size. These are big.
Not quite... a reflecting surface has to absorb all the energy and then re-emit it when it is reflected. With a regular mirror, it's a piece of glass with a silvered back. This would rapidly heat up and destroy the glass, and the silvering. With a highly reflective metal surface, it would still heat it up and destroy its reflective properties with hasty abandon. Do a google search for anti-missile lasers to read how a laser weapon actually works.
Unless it is a pencil-thin or smaller beam, 15kW is just plain not very much. I mean, it's a lot of energy, I wouldn't want it pointed at my couch... but it is only about as much as you would get out of 150 light bulbs. Maybe even less, considering the conversion factor.
I guess it is on the verge of being practical. But not much more, yet.
Well, lessee...a 100mW (20dBm or 0.1W) collimated burning laser will pop ballons and burn dark objects such as electrical tape. This one is 15KW (~72dBm) so that's ~72-20=52dB times the power, or about 15KW/0.1W=150,000 "burning lasers", assuming Northrop-Grumman can collimate a laser as well as some guy on Instructables.
I guess you haven't worked with lasers much. A 3 Watt CO2 laser will burn paper in less than a second or so. Light bulbs put out a lot of power. If you hold on to a light bulb that's on, your hand won't last very long. Nevertheless, the destructive power is small compared to conventional weapons. The advantage here is accuracy.
You don't weigh any less in water, but someone "picking you up" or "carrying" you while in water is aided by the fact that people are buoyant. I can guarantee that a 400lb metal box is not buoyant in the slightest.
Check your quantum physics. In fact, there are only a couple of ways that photons interact with matter... if there's no interaction at all, the photons pass right through. That's "transparency". There's also the photoelectric effect, where photons interact with electrons, which rise to higher energy states, absorbing the photons. The new configurations aren't stable, so the electrons rapidly fall back to their original state, which emits a new photon. On a reflective surface, the atoms are aligned in such a way that the new photons are lined up very precisely, such that they match the photons that were absorbed. Otherwise, you might get a spectral reflection (i.e. shiny), but not coherent. In non-reflective surfaces, the photons are absorbed and the electrons either remain in their excited state, or photons are emitted that are different than the photons that were absorbed (for example, when you shine a black light on a white surface, the emitted photons are at a different wavelength than the absorbed photons). Either way, the entropy of the material is increased (i.e. it is heated), though the entropy is obviously greater when no new photon is re-emitted. There are other quantum interactions possible at higher energies, but the idea is the same.
There's a good layman's explanation here, and a more comprehensive look in Dick Feynman's book.