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A Quantum Linear Equation Solver

joe writes "Aram Harrow and colleagues have just published on the arXiv a quantum algorithm for solving systems of linear equations (paper, PDF). Until now, the only quantum algorithms of practical consequence have been Shor's algorithm for prime factoring, and Feynman-inspired quantum simulation algorithms. All other algorithms either solve problems with no known practical applications, or produce only a polynomial speedup versus classical algorithms. Harrow et. al.'s algorithm provides an exponential speedup over the best-known classical algorithms. Since solving linear equations is such a common task in computational science and engineering, this algorithm makes many more important problems that currently use thousands of hours of CPU time on supercomputers amenable to significant quantum speedup. Now we just need a large-scale quantum computer. Hurry up, guys!"

14 of 171 comments (clear)

  1. Re:Seems bogus by Anonymous Coward · · Score: 4, Insightful

    Maybe you should READ the damn thing and notice how that's addressed in the first half-page.

  2. Re:Hm by FrozenFOXX · · Score: 5, Funny

    Is this algorithm in Haskell or somethin'?

    I'll wait until I can program in VB. Will it take long?

    It may or may not.

    --
    "Just a fox, a whisper."
  3. Re:not able to be used == not useful by Andr+T. · · Score: 4, Insightful
    Maybe it's just a story, but I've read something about Faraday that made me think about what you've written.

    When the Prime Minister asked him about a new discovery, "What good is it?", Faraday replied, "What good is a newborn baby?"

    --

    Any life is made up of a single moment, the moment in which a man finds out, once and for all, who he is.

  4. Re:not able to be used == not useful by norton_I · · Score: 4, Insightful

    You think that quantum computers are not able to justify grants or PhDs? What world are you living in?

    until these quantum computers exist and are cheap enough to fill datacentres

    Yeah, because classical computers were never useful to anyone (or anyone important) until datacenters existed.

    No, to be really useful, quantum computing has to be as easy to afford and deploy as current computing technology.

    And until then, developments that bring us closer are irrelevant? Applications that could give us more reason to develop the technology are pointless?

    What exactly is your point here?

  5. Re:not able to be used == not useful by Ambitwistor · · Score: 4, Interesting

    It's not a 'new toy' for computer science. Computer science has pretty much nothing to do with it. Mostly, it's a toy, or rather, academic persuit for theoretical physicists.

    No, it's of real interest to theoretical computer science. Quantum computing defines a new class of algorithmic complexity: there are, for instance, sub-exponential quantum algorithms for problems which have only exponential-time classical solutions. There is a whole subindustry of algorithmic complexity theory devoted to exploring the differences between algorithms that can be executed on quantum computers and those which are executed on classical computers. Scott Aaronson's lecture notes are a good introduction to this subject.

  6. Re:Hm by AdmiralXyz · · Score: 5, Funny

    Quantum computing is nondeterministic and probability-based: when you put in a certain input, you have a finite probability of getting the right answer out, it could just as easily be anything else. So in other words, coming from VB, you'll be at a major advantage.

    --
    Dislike the Electoral College? Lobby your state to join the National Popular Vote Interstate Compact.
  7. Looks like a big deal to me. by jonniesmokes · · Score: 4, Informative

    Finally a cool article on /. This is extremely cool! There are a lot of problems in the real world that have extremely large sparse matrices that need to be inverted. Fluid dynamics and solutions to Maxwells equations come to mind. But I am sure there are other applications in relativity and plasma physics. Estimating a solution to a linear dynamic system of say 2^128 degrees of freedom in only 128 cycles would change a lot of things.

    And... Yes, we are working very hard on building the computers.

  8. Re:Implications by Anonymous Coward · · Score: 5, Funny

    Does this mean they can solve P=NP?

    Yes: N=1.

  9. Avinatan Hassidim and Seth Lloyd by aram.harrow · · Score: 5, Informative
    are my coauthors, and the ordering of author names was alphabetical, and doesn't reflect our level of contributions (which were more or less equal).

    So please cite this as "Harrow, Hassidim and Lloyd" and not "Harrow and coauthors."

    That said, we're pleased about that attention. :)

    In response to one question: the matrix inversion problem for the parameters we consider is (almost certainly) not NP-complete, but instead is BQP-complete, meaning that it is as difficult as any other problem that quantum computers can solve. We plan to update our arXiv paper shortly with an explanation of this point.

  10. Re:Polynomial Speedup by blueg3 · · Score: 4, Informative

    To rephrase the other response, log vs. polynomial is the same as polynomial vs. exponential. Moving from polynomial time to logarithmic time is an exponential speedup (just as is moving from exponential time to polynomial time is).

    O(n^3) vs. O(log n)
    ->
    O(exp(n^3)) vs. O(n)

  11. Re:arXiv articles - question by fph+il+quozientatore · · Score: 4, Funny

    Are arXiv articles peer-reviewed?

    No, they aren't.

    --
    My first program:

    Hell Segmentation fault

  12. Re:Seems bogus by Bitch-Face+Jones · · Score: 4, Funny

    In O(log n) time he can't read the entire article.

  13. Re:Implications by lenester · · Score: 5, Funny

    Oh come on, this deserves +P Funny.

  14. Re:Comparing Apples to Apples by aram.harrow · · Score: 4, Informative

    This is a great question. Here's how I like to think about it: If A is a stochastic matrix and b is a probability distribution that we can sample from, then given a few assumptions, we can sample from Ab efficiently. This is more or less the idea behind so-called Monte Carlo simulations, which are a tremendously useful tool in classical computing. However, we don't know how to get sampling access to A^{-1} b. Our algorithm gives us something like sampling access to A^{-1} b. Not exactly, because we're talking about quantum amplitudes, rather than probabilities. But more importantly, taking the inverse can make a sparse matrix dense, and (as we often see for problems admitting quantum speedups) sampling-based approaches to computing it fail because the samples have alternating signs.