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Long-Term Performance Analysis of Intel SSDs

Vigile writes "When the Intel X25-M series of solid state drives hit the market last year, there was little debate that they were easily the best performing MLC (multi-level cell) offerings to date. The one area in which they blew away the competition was with write speeds — initial reviews showed consistent 80MB/s results. However, a new article over at PC Perspective that looks at Intel X25-M performance over a period of time shows that write speeds are dramatically reduced from everyday usage patterns. Average write speeds are shown to drop to half (40MB/s) or less in the worst cases, though the author does describe ways that users can recover some of the original drive speed using standard HDD testing tools." Reader MojoKid contributes related SSD news that researchers from the University of Tokyo have developed a new power supply system which will significantly reduce power consumption for NAND Flash memory.

10 of 95 comments (clear)

  1. Re:Why? by SpazmodeusG · · Score: 5, Informative

    The Intel SSD (and all SSDs) are made up of big addressable blocks. On the Intel SSD these are 64KiB in length. When you read or write to the drive the internal controller actually reads or writes an entire 64KiB block.
    A simple change to 1 byte means a read of the entire 64KiB block that byte is in, a change of the data and then a write of 64KiB.
    If the filesystem isn't flash-aware you can suffer a theoretical performance hit of being 65536 times slower because of this.

    So what you really need is a filesystem that stores files in 64KiB blocks and groups reads and writes to the same blocks together as 1 operation.

  2. Re:Damn by Viper+Daimao · · Score: 4, Insightful

    Exactly. BSG and Joss Whedon's new show are on.

    --
    "In the game of life, someone always has to lose. To me, if life were fair, that someone would always be Oklahoma." -DKR
  3. Re:Why? by Rockoon · · Score: 5, Informative

    It happens because flash drives write on very large (512KB) "blocks", but they still pretend like they have average sized (4KB) "sectors".

    Essentialy what the intel write-combining technology is doing is combining multiple small (4KB) writes into a single block, and letting the old block become fragmented (having a bunch of 4KB holes in it.)

    The scenario in the nutshell:

    You have a 1MB file and a program which modifies a single 4KB chunk of it. Intels technology marks the original 4KB chunk within its original "block" as erased, and then allocates a new block (using the wear leveling algorithm) to hold the new version of the 4KB chunk and additionally combines it with any other small writer operations that may have recently occured or will recently occur. Up to 128 such 4KB writes can be combined into a single block write.

    After this is done many hundreds of thousands of times, however, the drive begins to be in a state where nearly every "block" is only partialy used. The write combiner itself is stuck with whatever the wear leveling algorithm handed it, which is now a partialy used block instead of a fully virgin block. It can no longer combine 128 small 4KB writes together, but maybe only has space to combine 10 of them, or in the worst case scenario.. 1 of them.

    --
    "His name was James Damore."
  4. Re:Why? by Dr.+Ion · · Score: 5, Informative

    Um... no.

    When cells age, they take longer to erase. This happens over 5,000, 10,000 cycles or longer. It's not dramatic, and eventually the cells fail in a way more severe than can be corrected by the ECC.

    Because there is a (software) process to bring full speed back to the drive, we can safely conclude that none of the slowdown is related to cell aging or other cell-level issues. It's more of an organization and fragmentation issue.

  5. Re:Why? by tlhIngan · · Score: 5, Informative

    The Intel SSD (and all SSDs) are made up of big addressable blocks. On the Intel SSD these are 64KiB in length. When you read or write to the drive the internal controller actually reads or writes an entire 64KiB block.
    A simple change to 1 byte means a read of the entire 64KiB block that byte is in, a change of the data and then a write of 64KiB.
    If the filesystem isn't flash-aware you can suffer a theoretical performance hit of being 65536 times slower because of this.

    So what you really need is a filesystem that stores files in 64KiB blocks and groups reads and writes to the same blocks together as 1 operation.

    Actually, NAND flash comes in 2 block sizes - small block (16kiB/block, 512bytes/page, 32 pages/block), and large block (128kiB/block, 2048bytes/pages, 64 pages/block).

    Also, in NAND flash, a "write" operation can turn a "1" bit to a "0" bit. An "erase" operation turns a "0" bit into a "1" bit. Writes can work at the bit level, erases at the block level. (Though, large block NAND can NOT be partial-page programmed, so you must write 2048 bytes at once, but you can read all 2048 bytes, flip one bit, then write it all back). This characteristic is used by the flash management routines in order to manage the flash block. Marking pages as "discard" or "ready for erase" is done by flipping a 1 bit to 0 since that's easy. You can write a block partially, so you don't have to incur a huge 128kiB write always.

    Given this, it's a block device, so you can't write 1 byte anyhow - you must write the sector size, which is emulated as 512 bytes. What normally happens is that the SSD will mark a page as "dirty" to indicate it's not to be used, and remap that page's contents onto a new page elsewhere, thus only performing a 2048 byte write (plus 64 out of band bytes).

    Now, what happens when all the blocks are used? The flash routines have to erase a block, but before erasing a block, it has to make sure all the pages within it are "dirty". If there are non-dirty pages, they're copied to another block, and when all non-dirty pages are copied, that block is erased. If your access pattern is such that all the blocks have non-dirty pages, it takes a little while to actually move all the data around to get blocks that can be erased. Do enough random I/O, and this can happen quite easily.

  6. Closer, but.. no. by Dr.+Ion · · Score: 4, Informative

    NAND blocks are *erased* in large blocks, probably 128KB or larger in this case.

    However, the read and write operations occur at a *page* level, not block. NAND pages today are typically 2K or 4KB in size.

    So you can read and write in smaller units than 128KB.

    However, to erase any byte of the NAND, you have to relocate the preserved data and erase a whole block.

    Because these drives operate on huge aggregate arrays of NAND, their block structure may be much larger, or they may have very complicated and smart algorithms to re-map write new data while waiting to perform erases much later.

  7. Re:There's got to be some writable space here... by Dr.+Ion · · Score: 4, Insightful

    That's so oversimplified as to be completely wrong.

    The number of write/erase cycles on NAND is significantly less than a hard drive. Typical devices are rated for 10,000 cycles. Bleeding-edge MLC parts can be as low as 5,000 or 7,000 erase cycles.

    But.. a well-designed device will perform accurate wear-levelling across all the available blocks, so it doesn't matter what kind of access the user performs -- the whole device will wear evenly.

    There are indeed reserve blocks to mitigate premature death of some parts.

    But, the most important part is the ECC mechanism. The parts don't just wear out and die, they get an increasing bit error rate. By overdesigning the ECC logic, you can squeeze longer life out of the parts.

    It does not play guess and check.. well-recognized error correction algorithms like Reed-Solomon or BCH are used with really high detect/correct rates.

    Once you have accurate wear levelling, excellent ECC, and some manner of failure prediction, then it doesn't make so much sense to keep all your flash "in reserve" ready to swap out other parts wholesale. You might as well involve all the parts in the mix, so you get longer wear throughout.

  8. Re:SLC vs MLC by Kjella · · Score: 4, Insightful

    To me, MLC has a conceptual problem of going against the fine tradition of binary computing, which is all about data integrity. Why don't we go back to analog computers for even higher densities, while we're at it.

    Says someone that obviously has never seen the raw output of a HDD read head, or the optical laser in a DVD reader. The real world was always very ugly and analog, there's a helluva lot going on to give you a 0 or 1 answer.

    --
    Live today, because you never know what tomorrow brings
  9. Re:SLC vs MLC by cnettel · · Score: 4, Informative

    Do you detest Gigabit Ethernet and disk-based drives as well? Pure binary protocols for signals on media tend to be inefficient. The technology is still digital. Whether data integrity is a priority or not is really a matter of proper error correction, to rely on avoiding on single-bit errors is a flawed strategy.

  10. Re:TL:DR by TheRaven64 · · Score: 4, Interesting

    Not sure about the Linux world, but LFS on NetBSD counts as mature. It's been sitting in the BSD tree since 4.4BSD (1990, a year before the first Linux release) and is well supported by NetBSD, although the other BSDs dropped it from their trees in the intervening decades because it didn't provide major benefits on rotating mechanical disks. With flash becoming cheap, suddenly it's seeing a lot more interest...

    --
    I am TheRaven on Soylent News