LHC Hits an Energy of 3.5TeV

Inovaovao writes "As announced on Twitter by the CMS experiment, the LHC has finally accelerated both beams to 3.5 TeV for the first time. It thus broke the previous energy record of 1.18 TeV it had set last fall, about a month since operations started again this year. It'll be a while yet before we see stable beams and collisions at 3.5 TeV. You won't get much of a clue to the timetable by reading the General Manager's pompous announcements. If you want to follow what's going on, look at the Status Ops."

Comments

The press release is one week old

[Bananenrepublik]

The press release you called 'pompous' is one week old -- when the record energy hadn't yet been reached. Apparently going to CERN's front page is too much effort for slashdot's editors. Anyway, here's the current press release

Re:The press release is one week old

[bucky0]

Also, IIRC the general director's first language isn't english, so I think the "pompous" the submitter saw was just stemming from that. From what I've heard, he's a nice guy.

Re:Energetically Equivalent to...

[ceoyoyo]

Per particle.

The designed nominal total beam energy of the LHC is in the range of the kinetic energy of an aircraft carrier travelling at a significant speed.

Re:If both beams are 3.5 TeV

[Werthless5]

LHC physicist checking in - yes, that will make the collisions 7 TeV. Note that there are no collisions yet, we're still doing work to make sure that the beams are stable and focused properly. Once we have collisions, we'll run at this energy for about a year and a half before shutting down for a year to perform maintenance.

The LHC never produced 14 TeV collisions, the highest collision it will perform this year is 7 TeV. It is designed to produce 14 TeV collisions, and it will hopefully do that after we finish taking data at 7 TeV. It is true, however, that cosmic ray collisions completely kill the "LHC will destroy the world" bullshit.

Re:How many Libraries of Congress

[maxwell demon]

Of course the correct way to do it would be to multiply the information of the LoC with k*T ln 2 where k = Boltzmann constant, T = temperature of the Library, ln 2 to change from base 2 logarithm (information entropy) to natural logarithm (thermodynamic entropy).

Let's take the 20 million volumes * 200 pages from your calculation, and assume 250 words per page, 4.5 letters per word and 1.4 bits per letter (see directly above table 1, the value for longer text; I've taken the middle, rounded up). With this data, we get a total information content of the LoC of 6.3*10^12 bits. Let's further assume the temperature of LoC is about 290K, then we get the energy equivalent of the LoC as about 0.11 TeV.

Therefore 3.5 TeV is about 32 LoC.