NASA's Kepler Spots Its First Rocky Exoplanet
coondoggie writes "NASA today said its star-gazing satellite Kepler has identified its first rocky planet orbiting a sun similar to our own — 560 light years from our solar system. While not in an area of space considered habitable, the rocky planet known as Kepler-10b is never-the-less significant because it showcases the ability of Kepler to find and track such small exoplanetary movements. 'Kepler's ultra-precise photometer measures the tiny decrease in a star's brightness that occurs when a planet crosses in front of it. The size of the planet can be derived from these periodic dips in brightness. The distance between the planet and the star is calculated by measuring the time between successive dips as the planet orbits the star. Kepler is the first NASA mission capable of finding Earth-size planets in or near the habitable zone, the region in a planetary system where liquid water can exist on the planet's surface. However, since it orbits once every 0.84 days, Kepler-10b is more than 20 times closer to its star than Mercury is to our sun and not in the habitable zone.'"
The headline isn't flashy enough.
Should read:
NASA's Kepler Spots Hell 560 light years from earth and closing.
That's less than 2 million miles, or .05 AU from the sun.
Quite toasty.
So this means if a planet orbits a sun in any other plane than the one that happens to line up directly with us, it wont spot anything? Wouldn't that be...most of space?
Seeing as Kepler uses transits to find these planets, I wonder what the expected timeframe is for when they start really pumping out the data. I mean, if it looking at the right place for a year solid, it would expect to see one dimming of our sun from us (if it was pointed at our system from elsewhere). And that is only to find a single transit. Then add another year to get the orbit, probably another year at least to confirm.
To me it seems that it is going to be a very slow start (apart from these totally hotrock type planets with insanely quick orbit) but then the taps will be turned on and they will start finding exponentially more and more?
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The Roche limit is defined as:
d = R ( 2 rhoM/rhom) ^ (1/3).
d is the orbital distance.
R is the primary (star in this case) radius.
rhoM is the primary's density.
rhom is the satellite's density.
If rhom > 2 rhoM, d is inside the radius of the primary.
The star in question is similar to ours, so I'll use our sun's density: 1.4 g/cm^3
The planet's density is 8.8 g/cm^3.
Therefore, the roche limit is within the star's radius and the planet will not be ripped apart.
This presumes a nearly circular orbit, which is good enough for this case.
So to find a truly earthlike planet, won't they have to focus on a single star for more than a year in order to detect the planet passing the star more than once?
Yep. And for Jupiter-like planet we'd need to be watching it for hundreds, if not thousands of years if we were to use this method.
What if the planet's orbit never aligns to eclipse the sun?
Then we would never detect it via this method.
What if there are two or three planets in very similar orbits?
It depends on how well they are aligned. Even if they're perfectly aligned, we're liable to see the first one before the second or third one as it passes in front of the star. If they are even slightly out of phase, they will eventually be in an orbit in which we see all three distinctly. In any case, the radius and shape of the occlusion in front of the star is determined by the shape of the light intensity vs. time graph. Circular disks have a very specific light occlusion shape, while abberant occlusions have different shapes.