Ivy Bridge Running Hotter Than Intel's Last-gen CPU
crookedvulture writes "The launch of Intel's Ivy Bridge CPUs made headlines earlier this week, but the next-gen processor's story is still being told. When overclocked, Ivy Bridge runs as much as 20C hotter than its Sandy Bridge predecessor at the same speed, despite the fact that the two chips have comparable power consumption. There are several reasons for these toasty tendencies. The new 22-nm process used to fabricate the CPU produces a smaller die with less surface area to dissipate heat. Intel has changed the thermal interface material between the CPU die and its heat spreader. Ivy also requires a much bigger step up in voltage to hit the same speeds as Sandy Bridge."
It's clear in the article, but the headline here sort of implies that the chips run hotter in general, whereas this test is only saying the new chips run hotter when overclocked. From what I can find, when run at the rated voltages/speeds, Ivy Bridge CPUs run at about the same temperature as last gen's CPUs.
10 PRINT CHR$(205.5+RND(1)); : GOTO 10
Read the Anandtech review, that's total system power consumption. If you compare just the CPU power consumption it's ~33% more power efficient (66W increase from idle to load for Ivy Bridge vs 98W increase for SB). And if you look at the GPU intensive comparisons, IB is ~20% more power efficient, but that's including a ~33% increase in GPU cores and an increase in GPU clock, for an ~40% increase in performance while using 20% less power. For the first generation chips on a brand new production process, those are very good results. I expect to see them improve as their 22nm tri-gate process matures.
make imaginary.friends COUNT=100 VISIBLE=false
After switching all my lights to LED bulbs, its a bit cold in my office. A new, hotter CPU could be just what I need.
You're confusing temperature and heat. A candle burns hotter than a person, but a person puts out more heat (100W) than a candle (80W). Likewise, Ivy Bridge puts out less heat than Sandy Bridge, even though it's hotter.
(T>t && O(n)--) == sqrt(666)