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Is There a Limit To a Laser's Energy?

StartsWithABang (3485481) writes "For normal matter — things like protons, neutrons and electrons — there's a fundamental limit to the number of particles you can fit into a given region of space thanks to the Pauli exclusion principle. But photons aren't subject to that limit; in theory, you could cram an infinite number of them into the same exact state. In principle, then, couldn't you create a laser (or lasing cavity) with an infinite amount of energy inside? Perhaps, but there are some big challenges to be overcome!"

135 comments

  1. Photons aren't the problem by Anonymous Coward · · Score: 4, Funny

    It's the number of sharks you can fit into a given region of space.

    1. Re:Photons aren't the problem by Anonymous Coward · · Score: 0

      what about 'angels on a pinhead'? isn't this the old problem?

    2. Re:Photons aren't the problem by flyneye · · Score: 1

      It may be the number of D cells you can fit into the units on the sharks.

      --
      *Repent!Quit Your Job!Slack Off!The World Ends Tomorrow and You May Die!
    3. Re:Photons aren't the problem by davester666 · · Score: 1

      No. photons actually exist. you can literally see them.

      --
      Sleep your way to a whiter smile...date a dentist!
  2. No by Anonymous Coward · · Score: 0

    Except nex time. Later. Before then.

  3. You keep using that word by Anonymous Coward · · Score: 0

    Infinity doesn't mean what you think it means.

    1. Re:You keep using that word by Mitchell314 · · Score: 3, Insightful

      We can outright throw it out, as there isn't an infinite amount of energy in the visible universe.

      --
      I read TFA and all I got was this lousy cookie
    2. Re:You keep using that word by superwiz · · Score: 1

      Not having a finite limit means infinite. At least it does so in math. The summary got it right.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    3. Re:You keep using that word by Anonymous Coward · · Score: 2, Insightful

      No, it doesn't. In maths, we use the phrase, "finite but unbounded". This describes the natural numbers, for example: each specific integer is strictly finite, but there's no finite upper limit.

    4. Re: You keep using that word by Anonymous Coward · · Score: 0

      Where is dark energy coming from? What is the limit of energy in the universe?

    5. Re:You keep using that word by Anonymous Coward · · Score: 0

      You should probably send that back to whoever posted it to you.

    6. Re:You keep using that word by Anonymous Coward · · Score: 0

      That we may have an unbounded number of photons in the same state is not the same that we can have infinitely many photons there. The theory may say that we could have n photons there for any natural number n, but that is still a finite number of them in each case.

      So the way I read it, the summary might be wrong (unless the theory really says we can have infinitely many photons in the same state). I don't know if the universe can contain infinitely many photons at all.

    7. Re:You keep using that word by Anonymous Coward · · Score: 0

      Oh, and there is no such thing as "maths". ... And I have a PhD in math.

      How many years did you study math without ever encountering British English and "maths"?

    8. Re:You keep using that word by superwiz · · Score: 1

      I resist as incorrect every time I have a chance. It only became the British short form fairly recently. And, to anyone who uses the singular short form "math", it makes a suggestion that mathematical conclusions are open to being overturned the way scientific conclusions are. Since mathematical conclusions are final, there is only one math.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    9. Re:You keep using that word by superwiz · · Score: 1

      Infinity is not a number. It only exists as a formal notion to indicate lack of bound. One can talk about a "point at infinity", but to do so, one must adjoin to the set of numbers an object that is not numeric, but which only exists as a formal notion. Therefore, any set which contains a point at infinity is not a set of numbers. Yes, this is a "no true Scotsman" argument, but it has to be so because it is an argument about definitions.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    10. Re:You keep using that word by Anonymous Coward · · Score: 0

      What I'm talking about here is cardinality. Maybe there can be a bounded number of photons at one place, perhaps unbounded but finite (what is what I was talking about in the post you replied to), could also be countably infinitely many (has the same cardinality as the set of natural numbers, which is already infinite), or even uncountably many.

    11. Re:You keep using that word by superwiz · · Score: 1
      This:

      unbounded but finite

      makes no sense from a mathematical perspective. Does an infinite number of photons exist? Probably not (I am not a physicist). But the question is not that. The question is whether an infinite number of photons can fit into a space occupied by a laser. If that number has no bound, then infinitely many photons can fit there.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    12. Re:You keep using that word by Anonymous Coward · · Score: 0

      "Unbounded but finite" makes perfect sense as a restriction - it is the same as "any finite number".

      For that reason this is wrong:

      The question is whether an infinite number of photons can fit into a space occupied by a laser. If that number has no bound, then infinitely many photons can fit there.

      I suggest you to search "unbounded but finite" in your favorite search engine to find many examples of use in mathematics and other disciplines. I am not the same person who originally used the term "finite but unbounded" in this thread, btw.

    13. Re:You keep using that word by Anonymous Coward · · Score: 0

      there is only one math.

      As there is only one maths. It is a singular noun, just an abbreviation for mathematics.

    14. Re:You keep using that word by superwiz · · Score: 1

      It's a misnomer. Finite at every point does not mean finite. Heck, y=x is would fit this criterion of "finite" if it did. Finite function means globally bounded.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    15. Re:You keep using that word by superwiz · · Score: 1

      Ok, maybe I should put it this way. You may be able to draw a formal distinction between "countably many" and "any number of", but you cannot draw that distinction logically; certainly not in the context of counting.

      --
      Any guest worker system is indistinguishable from indentured servitude.
    16. Re:You keep using that word by Anonymous Coward · · Score: 0

      "Ford.. There's an infinite number of photons out here that want to talk to us about this script for Hamlet they've worked up".

    17. Re:You keep using that word by Anonymous Coward · · Score: 0

      "Integers, as a whole"

      I see what you did there ...

    18. Re:You keep using that word by Anonymous Coward · · Score: 0

      "Maths" is not a plural, it's just a contraction of "mathematics" that happens to also contain the *last* letter as well as the first four.

    19. Re:You keep using that word by omnichad · · Score: 1

      It's probably a hypercorrection because the original term is mathematics, and therefore its short form should be plural. No, if I want to make it short - I'll leave off as many letters as I want to. From this point on, a capital M refers to the field of mathematics.

  4. E=MC^2 by Anonymous Coward · · Score: 2, Interesting

    Eventually the laser energy will create a black hole, provided some other exotic effect doesn't occur first. Realisitcally though it's not possible to attain those kinds of photon densities (nothing can reflect anywhere close to well enough for starters).

    1. Re:E=MC^2 by Anonymous Coward · · Score: 0

      E = mc^2 doesn't mean that the photons will get mass at high energies.

    2. Re: E=MC^2 by Anonymous Coward · · Score: 0

      They have zero rest mass, this does not mean zero mass when its not at rest. Good luck finding a photon at rest

    3. Re:E=MC^2 by K.+S.+Kyosuke · · Score: 1

      Actually, it means precisely that. (Unless they lied to me in high school!)

      --
      Ezekiel 23:20
    4. Re:E=MC^2 by Anonymous Coward · · Score: 4, Informative

      They did. Photons will gain an increasing energy density, and a corresponding increasing pressure, which both have an impact on the gravitational field and, if high enough in a concentrated area, could indeed cause the appearance of a black hole. That does not mean they have "mass". The photon energy is basically E=hbar*omega or E=pc, depending how you want to write it. Here omega is the angular frequency, p the momentum, while hbar and c are Planck's constant and the speed of light respectively.

    5. Re:E=MC^2 by Mitchell314 · · Score: 1

      It's been a long time since I last studied physics, but an extremely strong EM field can have mass.

      --
      I read TFA and all I got was this lousy cookie
    6. Re: E=mc^2 by Anonymous Coward · · Score: 0

      And you'll get a Big Bang?

    7. Re:E=MC^2 by sillybilly · · Score: 1

      It does not mean they have "rest mass", but they do actually have "mass", m=E/c2, that should create gravity around the photon ( if gravity is such as thing that gets created and is present around an object, and it's not just a straight "instantaneous action at a distance" between two objects. now my head is starting to hurt)

    8. Re:E=MC^2 by MillionthMonkey · · Score: 4, Informative

      E = mc^2 specifically applies only to objects that have nonzero mass and are at rest with respect to the observer. Photons are massless and move at the speed of light.

      The general equation is E = sqrt((mc^2)^2 + (pc)^2) for rest mass m and momentum p. If a particle has mass and is at rest, then p=0 so E=mc^2. If a particle is massless, then m=0 so E=pc.

      (The "m" here refers to rest mass m0, not the "relativistic mass" m* which is defined as m* = m0 / sqrt(1-(vc)^2)). Relativistic mass is best thought of as a fake concept to hide the ugly sqrt denominator. People can imagine things getting heavier when they're moving, and can keep saying "Einstein discovered E=mc^2". But it still has division-by-zero problems with massless particles, and things don't really "get heavier" when they move, so if you try to avoid thinking in terms of m* you won't get as confused. Neither m nor m* makes E=mc^2 work with photons.

      Imagine if a bundle of photons could gather and form a "black hole". The hole and its event horizon would be constrained to move at the speed of light, which you can't, since you have mass. so you might easily escape its event horizon- you wouldn't have time to fall in before the thing was gone. Real black holes have mass and don't move at the speed of light relative to anybody.

    9. Re:E=MC^2 by Anonymous Coward · · Score: 0

      So Ronald Mallett was right, he just cant yet afford the power bill in his time machine? I Knew It!

    10. Re:E=MC^2 by Anonymous Coward · · Score: 0

      Imagine if a bundle of photons could gather and form a "black hole". The hole and its event horizon would be constrained to move at the speed of light, which you can't, since you have mass. so you might easily escape its event horizon- you wouldn't have time to fall in before the thing was gone. Real black holes have mass and don't move at the speed of light relative to anybody.

      Except for the whole stress-energy tensor in GR depending on the energy density in terms of E/c^2, which means that even photons have a gravitational effect similar to as if you did apply E=mc^2 to get an effective mass. GR allows for a high enough photon density to form a black hole. The fact the light is traveling at c doesn't stop this, just like it is capable of forming sublight speed particles from pair production (with a little care when handling the momentum via a extra particle). The pedagogical handling of rest and relativistic mass is a mess, but you still have to be careful of over-correcting and resulting in a reasoning that doesn't actually work under GR.

    11. Re:E=MC^2 by Anonymous Coward · · Score: 0

      Hey bigmouth: You're being called out (why're you running "forrest"?) http://slashdot.org/comments.p...

    12. Re: E=mc^2 by ILongForDarkness · · Score: 1

      Not sure. There is weirdness in particle physics where you are able to break the rules as long as the duration is short enough that you never could measure it. Sometimes those "broken rules" states are simplify calculations. If you pumped in enough energy I'd guess you could get a big bang. Another option would be that the expansion of the edge of the high energy region combined with the reduction of the speed of light in this new material would be such that you stop increasing the energy density of the center of your target.

    13. Re:E=MC^2 by Anonymous Coward · · Score: 0

      Gravitational effects become important as the total "box of light" (Einstein's Box, using French's treatment in light of the unphysicality of perfectly rigid boxes) energy-momentum increases.

      However, pair-production effects also become important as the individual light quanta increase in energy-momentum.

      It is exactly solving a collapsing "box of light" system that tests semiclassical gravity, which is an EFT only until the point where spacetime curvature becomes proportional to the length of the box, and falls apart at the point where spacetime curvature becomes proportional to the wavelength of the excitations in the EM field. QED also starts looking shaky if there are even slight magnetic effects in the strong field limit of semiclassical gravity.

      Stacking up enough photons of any energy will create an analogy of a collapsar, and you get there faster with higher frequency photons. Pair productions as the light's self-gravitation becomes significant is a plus, since the pairs will be thermal; however, whether that carries away energy from the self-gravitating photons or makes a collapse more likely depends a lot on the details of Hawking radiation, for which there is no full theory yet. Additionally, as self-gravitation increases, the effects on the "clocks" of each photon increases, and that may break up the function of the laser, depending on the precise details of the gravitational redshift on each photon.

      On the other hand, with sufficiently high-frequency photons, pair production will happen starting at the cavity mirrors and then throughout the cavity with increasing photon energy. The resulting matter will still be thermal, but are likely to scatter the photons in ways which break up phase coherence, as well as introducing other EM effects which will wreck the function of the laser, dissipating its energy, and possibly producing gravitational waves, undoing the self-gravitation of the light.

    14. Re:E=MC^2 by RockDoctor · · Score: 1

      (nothing can reflect anywhere close to well enough for starters).

      ... nothing that we have technological access to at the moment. You might manage to reflect light with a high-enough magnetic field, but getting it flat enough to form a lasing cavity isn't going to be easy.

      --
      Birds are not dinosaur descendants;birds are dinosaurs, for all useful meanings of "birds", "are" and "dinosaurs"
    15. Re:E=MC^2 by Anonymous Coward · · Score: 0

      Although classical physics does not allow for magnetic fields to interact with light, QED gives higher order interactions that allow photons to scatter off of magnetic fields. But it is a scattering process, so won't help you make mirrors for any sort of cavity (not to mention requiring fields like that around a magnetar, that have the same energy density as the mass energy of lead, and still only working on high energy gamma rays as it has a strong wavelength dependence).

    16. Re:E=MC^2 by omnichad · · Score: 1

      That's a theoretical conversion if turning energy into mass. Not a superstate of being both mass and energy.

  5. ExactoMundo by maseo126 · · Score: 2

    Napoleon, like anyone can even know that.

  6. There are some... er, limits: by theNAM666 · · Score: 4, Informative
  7. Spoiler at the end. Answer is "No" by Tablizer · · Score: 5, Informative

    "Update: After a conversation with Chad Orzel, it looks like although there's no limit to the photon energy you can produce, you will at some point--above about 1 MeV in photon energy--start spontaneously producing matter-antimatter pairs of particles whenever your photon interacts with a reflective surface. So at extremely high photon energies, your laser light begins to resemble a matter-antimatter thermal bath rather than merely coherent light."

    So it would act like more Star Wars weapons?

    1. Re: Spoiler at the end. Answer is "No" by Anonymous Coward · · Score: 0

      Exactly. May the Fourth be with you.

    2. Re:Spoiler at the end. Answer is "No" by Zorpheus · · Score: 1

      This is not only a problem for high photon energies on mirrors, but also for high energy densities in free space. If I remember correctly this starts at about 10^20 W/cm^2

    3. Re:Spoiler at the end. Answer is "No" by jovius · · Score: 1

      So it wouldn't be possible to construct a reflective surface that's not solid in the traditional sense but a reactive field of energy, which would guide the process at the point of interaction - to bypass the limit?

    4. Re:Spoiler at the end. Answer is "No" by ixtapa · · Score: 1

      Some sort of force field?

    5. Re:Spoiler at the end. Answer is "No" by Zorpheus · · Score: 4, Informative

      I just searched for an answer to this question. Seems that pair generation by irradiation of matter (e.g. a mirror) is shown experimentally and can reach quite high intensities:
      http://journals.aps.org/prl/ab...
      Generation in vacuum though seems to be shown only in models until now:
      http://iopscience.iop.org/0295...
      http://journals.aps.org/pra/ab...
      Seems that the reaction rate is much lower, so maybe this is not a limiting factor for building a laser.
      Normally high intensities are achieved by building a pulsed laser. This produces a beam of laser pulses, which is then focussed into a tiny spot. Intensities in this spot can be alot higher than inside the laser cavity. You could achieve higher laser intensities just by building a larger laser (like http://en.wikipedia.org/wiki/N... ).
      Inside the laser cavity intensities are normally limited by the effects of nonlinear optics ( http://en.wikipedia.org/wiki/N... ), which occur in all kinds of matter.

    6. Re:Spoiler at the end. Answer is "No" by Anonymous Coward · · Score: 0

      That is energy per photon....you could just keep your photon energies below 1 MeV (which is gamma ray or at least hard X-ray, by the way), and just pile more low energy photons into the same space to increase the energy density...say visible light photons of ~1 eV.

    7. Re:Spoiler at the end. Answer is "No" by Anonymous Coward · · Score: 0

      At least until they start recombining or scattering off each other....

    8. Re:Spoiler at the end. Answer is "No" by Anonymous Coward · · Score: 0

      So, an array of laser produces photons of more than 1 MeV. Use magnetic field for separating and focus into electon and positron beams. Focus and direct and no more Alderaan. Princess Leia cries and curses Grand Moff Tarkin. There some engineering problems here.

    9. Re:Spoiler at the end. Answer is "No" by tpjunkie · · Score: 1

      Chad Orzel was my college physics professor. Cool dude.

    10. Re:Spoiler at the end. Answer is "No" by Anonymous Coward · · Score: 0

      lol," Don't, I repeat, Don't use this laser to fill my house with popcorn! OK???? Funny guy!

    11. Re:Spoiler at the end. Answer is "No" by Tablizer · · Score: 1

      Correction, the answer is "yes" in terms of "is there a limit?".

  8. Finally! by Anonymous Coward · · Score: 0

    Something worth reading.

    1. Re:Finally! by Anonymous Coward · · Score: 0

      Gotta use the cache for now.

  9. Not even for "normal" matter by DMiax · · Score: 1

    For normal matter — things like protons, neutrons and electrons — there's a fundamental limit to the number of particles you can fit into a given region of space thanks to the Pauli exclusion principle.

    Wrong, unless you assume space is discretized, which might happen around Planck's length, but has never been proven theoretically nor experimentally.

  10. Bosons vs Fermions. by Anonymous Coward · · Score: 0

    If you did physics like me then it's not that mysterious. There are some problems. The particles would burn through the cavity long before 'it' got 'infinite,' not that that sentence makes any sense whatsoever. Also where the !@#k are you going to get infinite power to pump the stupid thing?(!)

    1. Re:Bosons vs Fermions. by Anonymous Coward · · Score: 1
      1. 1.Put up a site
      2. 2.Link to slashdot
      3. 3.Use energy of the burning servers.
      4. 4.Profit!
    2. Re:Bosons vs Fermions. by ledow · · Score: 2

      The power generation isn't one billionth as hard as - how the hell do you get that energy (presumably electrical) to the device in the first place in a usable format? You can alway just build a nuclear fusion plant, then another, then another, then another, then another, in close proximity.

      But somewhere, somehow, you have to transport or convert that amount of energy in a non-light way, which is going to involve some humungously gigantic amount of heat on a physical component, or some monstrously huge device to attempt to dissipate the heat.

      The problems of generation are solveable - we just need a way to harness something like a Sun (e.g. Dyson spheres). The problem you really have is how do you concentrate that energy onto a point such that it generates a laser?

    3. Re:Bosons vs Fermions. by Hognoxious · · Score: 3, Funny

      Also where the !@#k are you going to get infinite power to pump the stupid thing?(!)

      Two or three of Elon Musk's batteries of sheer awesomeness should do it.

      Make it four, in case one catches fire.

      --
      Confucius say, "Find worm in apple - bad. Find half a worm - worse."
    4. Re:Bosons vs Fermions. by Anonymous Coward · · Score: 0

      The problem you really have is how do you concentrate that energy onto a point such that it generates a laser?

      In theory you can put a beam in orbit around a black hole. That way you can accumulate energy over a long time.

      I guess it should be possible to "slingshot" the beam between two black holes too if you want the energy to be accessible.

    5. Re:Bosons vs Fermions. by ultranova · · Score: 1

      But somewhere, somehow, you have to transport or convert that amount of energy in a non-light way, which is going to involve some humungously gigantic amount of heat on a physical component, or some monstrously huge device to attempt to dissipate the heat.

      Why? If raw power is all you're concerned with, just use gamma rays and/or neutrons from an exploding nuclear bomb to pump your lasing media. Sure, you'll only get a single pulse, but that's all you'll need.

      Heck, you could surround the bomb with primary converters to capture as much energy as possible, and focus them on a secondary converter to get a single beam, Death Star style.

      --

      Forget magic. Any technology distinguishable from divine power is insufficiently advanced.

    6. Re:Bosons vs Fermions. by Kjella · · Score: 1

      The problems of generation are solveable - we just need a way to harness something like a Sun (e.g. Dyson spheres). The problem you really have is how do you concentrate that energy onto a point such that it generates a laser?

      Well, if you have a Dyson sphere you can shoot a laser from every point on the surface facing the target, they won't be perfectly aligned but they will pass through the same volume of space, like a magnifying glass effect with lasers. That should make a rather nice bug zapper.

      --
      Live today, because you never know what tomorrow brings
    7. Re:Bosons vs Fermions. by Anonymous Coward · · Score: 0

      The problem you really have is how do you concentrate that energy onto a point such that it generates a laser?

      You don, you build a very physically large laser that would then need a low energy and power density. Or use one that has a broadband amplifier to you can split a short pulse into its constituent frequencies, amplify them separately, then recombine to get a short pulse, as is currently done for ultra-fast lasers.

    8. Re:Bosons vs Fermions. by Anonymous Coward · · Score: 0

      Photons orbiting a black hole would be in unstable orbits and would not stay there long, assuming you could even get them into anything close to an orbit in the first place.

  11. History.... by beheaderaswp · · Score: 4, Informative

    Billions and billions of years ago, even before lord Xenu, there was a scientist who pulled this off.

    Blext Telfrawd, an A type Hixoid, did get an infinite number of protons into a finite space. Then the containment field faltered, obliterating the iteration of his universe..

    Most historians agree this was tragic for it ended his universe, and created one with Justin Bieber. Sentients who were able to achieve trans-dimensional universital access, send a message to you from the past: It's just too risky to repeat the so called "Bieber Event",

    You've been warned.

    --
    Another consultant who stuck it out.

    "We are the Priests, of the Temples of Syrinx..."
    1. Re:History.... by Anonymous Coward · · Score: 0

      Hey mods, this should be modded funny not informative. This is Slashdot after all, not digg.

  12. Putting the cart before the horse? by Chas · · Score: 3, Interesting

    Okay. Interesting on a theoretical level.

    The main problem with testing this is "how does one generate infinite or near-infinite energy" to power something like this?

    Of course, if we've answered that, we're ALREADY in a place where we've either wiped ourselves out (accidentally or otherwise), or we've basically solved the greatest real-world problem in the history of humanity.

    --


    Chas - The one, the only.
    THANK GOD!!!
    1. Re:Putting the cart before the horse? by wisnoskij · · Score: 2

      I think the idea if that you could create a stable laser, that exists in some reflective box. And you would keep adding power to it forever.
      Or at least until it exploded.

      --
      Troll is not a replacement for I disagree.
    2. Re:Putting the cart before the horse? by Anonymous Coward · · Score: 0

      Black holes are the answer to everything. The light..wait a minute, or a year. Put that a millennium.

    3. Re:Putting the cart before the horse? by penguinoid · · Score: 1

      The main problem with testing this is "how does one generate infinite or near-infinite energy" to power something like this?

      Use your local power plant. It produces near-infinite energy as far as lasers are concerned.

      --
      Don't waste your vote! Vote for whoever you want, unless you live in a swing state it won't matter anyways
    4. Re:Putting the cart before the horse? by Chas · · Score: 1

      You're not acquainted with what "infinite" actually means are you?

      --


      Chas - The one, the only.
      THANK GOD!!!
    5. Re:Putting the cart before the horse? by penguinoid · · Score: 1

      You're not acquainted with what "near-infinite" actually means are you? Talk to me again when you have a laser that uses 100-1000 megawatts continuously.

      --
      Don't waste your vote! Vote for whoever you want, unless you live in a swing state it won't matter anyways
  13. Oblig. XKCD by Anonymous Coward · · Score: 0

    I got nothing.

    But what a great what-if question you could forge from it.

    1. Re:Oblig. XKCD by FatLittleMonkey · · Score: 4, Interesting

      Yes.

      --
      Science is all about firing a drunk pig out of a cannon just to see what happens.
  14. Wrong interpretation of energy by AchilleTalon · · Score: 4, Informative

    The energy of a photon is characterized by its wavelength. In a laser, the wavelength is constant. You have a large amount of photons which are coherent but at an almost single wavelength. When the article is talking about 1 MeV, it falsely interprets this as if the laser is emitting a single photon at 1 MeV. That is not what happen. It emits many photons in coherence which the sum of energy of all the individual photons will reach 1 MeV or more. Each photon cannot create an electron-positron pair and all photons collectively cannot create an electron-positron pair.

    A 1 MeV photon would be a gamma ray photon and it is not true at all, your laser doesn't change its wavelenght as more more "energy" is emitted. In fact, we should instead talk about the power of the laser rather than its energy. The power being the amount of energy emitted by unit of time.

    --
    Achille Talon
    Hop!
    1. Re:Wrong interpretation of energy by Anonymous Coward · · Score: 0

      I thought he was talking about the energy density at the focal point, not the energy of a single photon.

    2. Re:Wrong interpretation of energy by poodlediagram · · Score: 5, Informative

      Exactly.

      This is the usual muddle up between energy and intensity.

      There is no apparent upper limit to the energy of a photon. The galaxy Markarian 501 emits photons in the teraelectronvolt (TeV) range.

      The question here is about intensity. The relativistic energy-moment dispersion, E^2=(mc^2)^2+(pc)^2, which applies to all on-shell particles, has a gap when m>0. This gap, which is about 1 MeV for electrons and positrons, can be overcome when the electric field (generated by a sufficient number of photons, irrespective of their energy) approaches the Schwinger limit of about 1.3 x 10^18 V/m. At this point, virtual electron-positron pairs can be created in abundance because the mass gap has been overcome, and electromagnetism then becomes non-linear. Pumping in more photons after this simply creates more virtual e-p pairs.

      Hope that helps.

      (IAAP working on this topic).

    3. Re:Wrong interpretation of energy by Anonymous Coward · · Score: 0

      > I thought he was talking about the energy density [...]

      Then he chose the wrong units. Energy density would be in MeV per cubic furlong or whatever.

      Overall, a very sloppy article (including the point where he cites Pauli's exclusion principle ("no two fermions ... in the same *state*") and moves nonchalantly to "no two fermions may occupy the same *volume of space*". Is state the same as space? How are they related?

      Of course I wouldn't expect a rigorous explanation (most of us wouldn't understand that anyway), but at least a mention in-passing.

    4. Re:Wrong interpretation of energy by Attila+the+Bun · · Score: 1

      When the article is talking about 1 MeV, it falsely interprets this as if the laser is emitting a single photon at 1 MeV. That is not what happen

      He is indeed talking about 1 MeV per photon. He's discussing the theoretical limits of photon power density in a hypothetical gamma-ray laser with an adjustable wavelength. An ordinary laser pointer stores more than 1 MeV of energy in its lasing cavity, although a physicist would not typically use eV to describe the combined energy of a light beam.

    5. Re:Wrong interpretation of energy by Anonymous Coward · · Score: 0

      At one level that the EM field is quantised into discrete excitations we call photons. (frequency more characteristic of energy than wavelength, E = hbar*omega, wavelength varies under various conditions) Interactions/resonances with other systems occur in these quantised amounts. However there is uncertainty in the energy contained within small volumes of the field, particularly over short time/length scales in a dE*dt > hbar/2 Heisenberg sense and at some point you have enough energy density such that 2 * 0.51 MeV/c^2 positron/electron pairs are likely to be created & destroyed (pair production). Dirac predicted these troubling particle creations & destructions when merging special relativity into the QM wave equations. Once the energy in a volume c*dt across is high enough the system behaves relativistically & particle number is not conserved. Energy can even be "borrowed" from uncertainty momentarily so this occurs with some probability at any energy. Photons aren't little billiard balls they're just a representation of the quantisation of modes of the field and not the only picture of what's going on. Quantum field theory / Quantum Electrodynamics are better descriptions of what goes on at his level.

      A more troubling question that brings up for me is why other energies of photon aren't produced. Perhaps that's where power broadening comes in. I think the resonant cavity would be one factor that would strongly suppress other modes.

    6. Re:Wrong interpretation of energy by grimJester · · Score: 1

      (IAAP working on this topic).

      I demand proof in the form of a youtube video of your laser!

    7. Re:Wrong interpretation of energy by Anonymous Coward · · Score: 0

      The energy of a photon is characterized by its wavelength. In a laser, the wavelength is constant. You have a large amount of photons which are coherent but at an almost single wavelength.

      While I agree with the first statements, the last one is not necessarily true. Due to Heisenberg's Uncertainty Principle a particle's position (x) and momentum (p) cannot be known beyond a certain limit: delta_x*delta*p >= h/(4*pi)

      In the case of light this uncertainty, also called the Fourier limit, expresses itself in terms of frequency (f) and time (t): delta_f*delta_t >=1/(4*pi)

      So for a continuous wave laser delta_t tends to infinity and the frequency variation goes to zero but in the case of pulsed lasers, an ultrashort pulse with a duration of 10E-14 seconds (10 fs) corresponds to a frequency variation of about 8 THz, so if your pulse is centered around 700 nm in wavelength that means that your pulse width is about 190 nm or ~80 nm if you take the full-width at half-maximum and assume a Gaussian emission spectrum.

    8. Re:Wrong interpretation of energy by Too+Much+Noise · · Score: 2

      He is indeed talking about 1 MeV per photon.

      he is jumbling together a lot of nonsense, imnsho.

      He starts with the idea of an ordinary laser. Those are not even in the X-ray range, nevermind the MeV gamma-ray range. Then he wants to 'compress' the lasing cavity to *ahem* reach black-hole level of energy densities. While you can transfer energy to the radiation field (thus shifting up photon energies from the visible/UV range) you'll need a HECK of a fast compression to reach the electron-positron generation threshold. So that's nonsense.

      Second, lasing does not happen in effing vacuum. Your first problem if you increase photon density, assuming your mirrors do not start to degrade before that, is nonlinear effects. Both in the lasing medium and in the mirrors. You start losing photons via multiple photon absorption that will give you back a higher energy photon that most likely escapes your cavity (goes in the wrong direction most of the time, and when it goes in the right direction the decreased mirror reflectivity and absorption/reemission x-section will not keep that energy contained for long). He never even sees that one coming.

      Third, his armchair laser building scenario conveniently ignores all the losses that a real laser system has to contend with. The most obvious part being heat dissipation. Your pretty 99.999% reflective mirror will start to degrade rather quickly if you increase too much the incident radiation density without keeping it adequately cooled (this goes back to several things - normal absorption coefficient in that 0.001% that does not get reflected, having a lasing medium inside the cavity that loses energy to walls, nonlinear absorption effects in the mirror, etc.). Once that happens, you start to say goodbye to the containment properties of your lasing cavity, and thus to your 'bajillion increase in laser field energy density' plans for taking over the world. Try again tomorrow night, Brain.

      Fourth ... bah, why bother. This is pretty much a jumbled collection of ideas that you'd expect from someone taking a first course in a given field and imagining things without an effective reality check. Perfect /. front page material.

    9. Re:Wrong interpretation of energy by epine · · Score: 1

      Then he wants to 'compress' the lasing cavity to *ahem* reach black-hole level of energy densities.

      It seems pretty clear to me—I took that same first course—that a neutrino is just a white hole (moving at the speed of light) made up of photons which such a strong self-interaction they can't escape from themselves and thus refuse to interact with much of anything else.

      This all seemed to fit with the gravitational contribution of the EM Stress Energy Tensor until I saw a post from Lubos on Stackexchange about the non-zero photon pressure and their Tii spatial components in GR, so I'm now back to looking for a different way to pretend I have a clue.

    10. Re:Wrong interpretation of energy by Anonymous Coward · · Score: 0

      Thermodynamics states that energy can neither be created nor destroyed so If you do figure out a solution to the power problem, you might want to christen the "Laser" with this song, because it is what you would be doing...

      http://www.youtube.com/watch?v=xNnAvTTaJjM&feature=kp

  15. Kugelblitz by Guppy · · Score: 4, Informative

    Eventually the laser energy will create a black
    hole

    There is a specific term in astrophysics for such a theoretical object:

    http://en.m.wikipedia.org/wiki...

  16. Mmmm, spam by Anonymous Coward · · Score: 0

    Is it more or less than the times you can spam your own blog on Slashdot? Coz that's all I really care about.

  17. Even if there is no limit by Vinegar+Joe · · Score: 1

    Would it be effective against a Dikironium cloud creature?

    --
    "The average reporter we talk to is 27 years old......They literally know nothing." - Ben Rhodes
  18. Re:There are some... er, limits: by Anonymous Coward · · Score: 0

    I found this a better analysis
     
      Are Black Hole Starships Possible?

  19. Re:There are some... er, limits: by drolli · · Score: 4, Interesting

    But long before that happens the question is if the laser can remain a laser.

    A laser needs some kind of nonlinearity in the medium. Any nonlinearity introduces a scale. So the real question is: At which power does of-resonant driving cause transitions (e.g. Landau-Zener) or of-resonant shifts (Stark shift) and can you actually theoretically contruct a medium which fulfills the criteria to serve as a lasing medium for an arbitrary large scale of power?

    As a starting point for an examination of such questions i recomment the Quantum Optics Toolbox for Matlab by Sze Tan.

  20. How much energy would you need... by Anonymous Coward · · Score: 0

    How much energy would one need in order to fire a laser so powerful the atmosphere would just instantly ignite.
    I just need to know for, hmm, educational purposes. I am not an evil-doer, honest. That guy over there is, get him.

    Really though, the amount of power to come out of these lasers to be SUSTAINED beams would be immense.
    We are talking fusion-power generations here. And we are trying to ignite a fusion reactor WITH a powerful laser! The madness!
    Hopefully one day. Fusion has the ability to change everything about our society once we get around the initial hurdle of making the damn thing work and getting it smaller and more optimized.

  21. bomb-pumped X-Ray lasers by dltaylor · · Score: 1

    If you can channel the energy of a fusion explosion into many lasing-while-ionizing rods (think "Real Genius"s death ray laser, but MUCH larger) you could pack so many X-Ray photons into a burst that the impact (momentum transfer) alone destroys the target's armor, at least according to David Weber.

  22. Yes by Anonymous Coward · · Score: 0

    42

  23. Old news? by KClaisse · · Score: 4, Interesting

    There was an article from 2010 that talked about the theoretical limit to laser beam energy. From the article:

    "At high laser intensities interaction of the created electron and positron with the laser field can lead to production of multiple new particles and thus to formation of an avalanche-like electromagnetic cascade"

    Here's the link to the article in question: http://physicsbuzz.physicscent...

    That article was ultimately using this article as a source.

  24. Please by Anonymous Coward · · Score: 0

    Stop creating these stupid web layouts. With the full screen opening page and the rest below.

    1. Re:Please by drewm1980 · · Score: 1

      I have to agree there. If this trend continues, I foresee browser plugins for nerds that just extract the damn text and render it as a static page. Maybe they already exist...

  25. Photons Under Pressure by Anonymous Coward · · Score: 0

    Theoretically there is a definable limit to the number of photons of a given energy that can be constrained within a specific region. It comes from the fact that photon interactions with normal matter transfer energy see https://en.wikipedia.org/wiki/Radiation_pressure. So that containing photons by reflection in present laser equipment does exert an infinitesimal force outwards on the mirrors.

    So as I see it the limit is one of how well made the laser containment equipment is manufactured, but there is a limit where no material could resist the tendency for the device to tare itself apart, I leave it to the reader to do the actual engineering math to work out what that is.

  26. Silly article by Anonymous Coward · · Score: 0

    The article outlines how lasers work but it's basically this: If we could build powerful lasers, which we do not know how to do due to technical issues, we had powerful lasers! Awesome!

    Car analogy: There is no theoretical limit how far you can drive with your car! If we could build cars that drive further, we could drive further with our cars! Even an infinite mileage seems possible! Awesome!

  27. Overcoming the "black hole" problem by MobyDisk · · Score: 1

    It is well-known that once you exceed a certain energy density you create a black hole. This is why the Death Star superlaser consists of multiple small lasers that combine.

  28. Of course there are limits. by Anonymous Coward · · Score: 0

    That's why ZPMs eventually go flat.

    1. Re:Of course there are limits. by Anonymous Coward · · Score: 0

      In theory you can recharge them with zero point energy drawn in from parallel universes.

  29. File this under "smart people are stupid" by NemoinSpace · · Score: 1

    IANAP. Which means, i probably have a better understanding of the subject than they do. Theoretically.

  30. Eddington Limit by mbone · · Score: 2

    As a certain energy density, the radiation pressure from the photons will be stronger than the tensile strength of the optical cavity, and the laser will blow apart. In astronomy, a similar limit is called the Eddington limit, so this is really the Eddington limit for a laser.

    The radiation pressure is (ignoring all factors of 2 or cos(incidence)) E / c. A tensile limit, T, of 500 mega pascals (reasonable for steel) thus would imply an energy intensity of c T, or 1.5 x 10^17 Watts/m^2. If the total cavity had an area of 1 m^2, then that's ~ 10^17 Watts.

    Note that it is common in pulsed lasers to have a lot of energy in a very short pulse (so the actual power during the pulse is very high). If your pulses were a microsecond in length, then the Eddington limit per pulse would be about 10^11 Joules, equivalent to 24 tons of TNT.

    1. Re:Eddington Limit by Anonymous Coward · · Score: 0

      You can get around that by just making the laser bigger, keeping density down, then focusing the beam down at the end. Or like ultrafast lasers, take the frequency spread and use that to spread a pulse out in space or time with a diffraction grating, then recombine after amplifying. High power lasers using amplifiers, or even oscillator stages that are single pass, don't require any reflections to work too.

    2. Re:Eddington Limit by mbone · · Score: 1

      The first part is irrelevant, as he asked the limit for "a cavity" (i.e., inside a specific sized object), and not on the target, but the second is not. You can, in fact, make your laser from a bomb and evade such limits. This was basically Edward Tellers idea for gamma ray lasers for anti-missile defense.

  31. Multi-photon interaction by Anonymous Coward · · Score: 0

    all photons collectively cannot create an electron-positron pair.

    This is false. Multiple photons can participate in an interaction and work with their combined energy. The probability of this happening is rather low compared to a single photon (and for pair production, it is rather in-efficient until you get above a couple MeV anyway), but typically the effect is also quite non-linear in terms of intensity. This is seen with laser induced breakdown of material. No individual photon has the ionization energy, and the particular material does not have a transition level that matches the photon, so it is not a matter of exciting the atoms first. Instead, there is a small chance that two photons (or more) will interact at the same time to combine energy and ionize the atom.

    This effect is important and useful because of the non-linear response to intensity, so that if you focus down a beam you can get a very small region of activity, instead of a gradual increase in activity as you approach the focus point.

  32. Already covered by Anonymous Coward · · Score: 0

    They've already ran into this issue with fusion power generation via lasers. When they increase the laser output too much, the laser light decreases. Turns out the photons are spontaneously turning into matter at high energy densities. This issue has been known about for years.

    1. Re:Already covered by Anonymous Coward · · Score: 0

      The lasers used in inertial confinement research are many orders of magnitude lower in peak power than ultrafast lasers, and don't have a problem with pair-production, especially within the laser. There is not much to be gained (in fact, it would be worse) by having shorter pulses in such a set up, but even though the total energy is large in something like NIF, the pulse times of ultra-fast lasers is millions of times faster. That gives much more intense power available for non-linear and exotic effects, and even then they don't have pair production in the laser itself, only when hitting special targets after the beam has been focused.

  33. E=mc^2 by ILongForDarkness · · Score: 3, Interesting

    At high enough energies particles are spontaneously created. They in turn will obey Pauli Exclusion (at least if they have spin I think). So enough photons and you make matter that will prevent you from making more particles ie pumping more energy into the space.

  34. Compton Scattering by Roger+W+Moore · · Score: 2

    This effect will not only kill at high energies but at high intensity too. With a high enough intensity you can have multi-photon interactions to achieve the same total energy. However pair production is not the only process you have to worry about compton scattering will occur as well. This will impose an intensity limit well below pair production energies.

    Essentially reflected photons will have less energy than incident photons and as the energy increases so too does this energy difference. It is caused by relativistic effects when a photon is reflected from an electron. At visible wavelengths the effect still occurs but is not noticeable but crank the energy up to several keV and your photon has an energy more comparable to the electron rest mass energy and the effect kicks in.

  35. That's a limit on energy DENSITY by Ungrounded+Lightning · · Score: 3, Insightful

    Eventually the laser energy will create a black hole, provided some other exotic effect doesn't occur first.

    That's a limit on energy density, not total energy in the laser. In principle you could use a very WIDE laser opterating below the black-hole thrshold and focus the beam externally (which, if it's powerful enough, it might do eventually, by self-gravitation, after leaving the cavity, even if the cavity geometry made it emit a colimated, rather than a converging, beam.) Thus, making a kugelblitz with a (very wide) laser might be theoretically possible (if "some other exotic effect" didn't make the required laser cavity to wide to be physically realizable).

    I'd imagine "Some other exotic effects" might include the electric field component of the coherent light becoming strong enough to polarize the vacuum and create particle-antiparticle pairs from multiple photons, dissipating their energy, somewhere WAY below the threshold of gravitic-collapse effects. So you'd need a REALLY WIDE laser and REALLY GOOD optics to make your external-to-the-laser black hole.

    Of course the question, being phrased in terms of Bose-Einstein vs. Fermi-Dirac statistics and "infinite" energy was really about energy density in the cavity - just poorly phrased. So you answered the question that was REALLY being asked.

    --
    Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
  36. "physics" is multidisciplinary by Goldsmith · · Score: 2

    "Physics" is not just one thing anymore. The guy writing TFA, Ethan Siegel, is a bonified professional physicist. Reading the comments, you can see he just didn't know this one thing as well as he thought. How does that happen?

    I don't know that there's any physicist going through training today or in the last 20 years who really understands "all" of physics.

    Physics PhDs learn most of physics up to about 1910 (even that is a stretch, but at least the complete fields up to that point are introduced and sketched out), and the next 100 years are based on your specialty. The limits of energy density for photons are usually in this realm of "introduced only if directly important to your specialty."

    It's up to the individual to fill in the gaps after formal classes, and it can be very hard to figure out what you don't know. It's particularly hard because of the oversimplified way physics is generally taught in undergrad, even to physics majors. Your old reference books may not actually be correct. I'm sure I've got a physics textbook around which claims almost exactly what Ethan said in his blog; the "why" of pair generation is just too distracting.

    1. Re:"physics" is multidisciplinary by Anonymous Coward · · Score: 0

      "bonified "???? I think you mean "bona fide".

  37. On a tangent note... by Twinbee · · Score: 1

    On a related note, I asked this quessie at a laser pointer forum a while back. Would still be interested in hearing a real answer: http://laserpointerforums.com/...

    --
    Why OpalCalc is the best Windows calc
  38. Please stop posting medium.com urls. by Anonymous Coward · · Score: 0

    They're unreadable without a tablet.

  39. 3 words: Bose-Einstein Condensate. by vanzilar8378 · · Score: 2

    Bose-Einstein Condensate! In more detail, fermions cannot be crammed together but in certain conditions, Bosons can. Photons are a type of Boson but not the only one. The Pauli exclusion principle does not apply to Bosons! Looks like a non-specialist needs to read some books on this concept. I won't even go into deeper details without this point being crystal clear!

  40. There are a few things that might get in the way by Anonymous Coward · · Score: 0

    The inability to focus light to a small enough region of space. At a high enough intensity it will start pair production of electron and positron and that will dissipate the energy. If you can get pass the pair production problem then there is the mini black hole problem.

  41. Uh, yeah... by Anonymous Coward · · Score: 0

    The author is a crank.

  42. What if photons stopped being so mixed up by Anonymous Coward · · Score: 0

    Compressed light has been an area study for me for a while.

    What if photons stopped generally not interacting with each other and instead reacted strongly. Suddenly.

    Imagine what would happen if an area was filled relatively speaking with intense laser light and suddenly converted to an interactive state. It would either explode violently if the particles repelled, or form a singularity if they attract. The former is more likely. Thus all you need to make a bomb is a nice light source, perhaps even a star would work.

    How do you get photons to react like that? Aren't they moving too fast and without mass? The way you do this is by imposing the influence from an exterior dimension upon a small area of normal space, in this case one where photons are not massless or infinitely fast. Basically, you'd cancel both of those things at once and the pile of photons would 1, hit a brick wall with enormous force, and 2, do it with effectively infinite mass. C condensed turns into an awful lot of E, in a hurry.

    So you need a cavity with a suitable photo source, a cargo container would work. Attach photon source, power source, and scatter photon converters as needed around the container. Turn it on, fill it with nice tasty photons, and then condense them. Bang. Hope you weren't close.

    If this sort of large effect is not desired, you can still play with it by condensing single photons at a time. The explosive effect is smaller, more useful and the components needed are easier to get.

    Causing other dimensions to exert influence here is a huge area of potential. Not only do we have the physics we think we know, you also get physics from another universe where the laws are different. Combining parts of them together yields effects that border on magic, and it doesn't violate our laws of physics because our laws don't apply. The basic problems with it are that it's hard to obtain and use these influences because our technology is not there yet. At all. And secondly, we don't understand all the effects. Hell, we understand none of it. It's like trying to understand an entire physics model unlike anything you think you know. Nothing is the same. And oh by the way, there;s not just one of these but dozens and they're all different. Nobody can understand all of it, not even Einstein if he was alive. He managed one about as well as anyone can. This is several orders of magnitude above that.

    Most of it is also lethal to humans. Lots of loose radiation from any/all of this stuff. It's very unhealthy. Nothing like taking the smartest people you have, or anyone has, and have them try to work it it, only to have it manifest in an unexpected way and kill everybody. To make it worse, it's hard to tell if we've failed to understand it or if the influence is being manipulated to cause failures. It is not in anyone's interest for anyone of us to achieve success. Much better to have it all fail via "accidents" and be perceived as too dangerous to even try.

  43. Medium but ugly by Crass+Spektakel · · Score: 1

    man this medium page is but guly.

    giant fonts, no use of the screen.

    bleark.

    --
    "Life is short and in most cases it ends with death." Sir Sinclair
  44. More importantly by TuxWithoutPants · · Score: 1

    How many balloons can you pop with that?

  45. Yes. by cyn1c77 · · Score: 1

    The article reads as somewhat naive to me.

    Every material has an energy density limit, at which point it will breakdown or ionize.

    And given that no material is completely transparent to any wavelength, once you produce enough energy density, every material will ionize and place an upper limit on laser propagation.

  46. its stargate by Anonymous Coward · · Score: 0

    and a zero point module

  47. Photon Torpedoes by PortHaven · · Score: 1

    Now you know how Photon Torpedoes work....

  48. Pauli exclusion limit by dywolf · · Score: 1

    Is that when a sweaty guy in a Vneck, chest hair puffed out, gold chain on his neck, wont let you into "da club" ?

    --
    The guy who said the election was rigged won the presidency with the second-most votes.
  49. Re:There are some... er, limits: by Anonymous Coward · · Score: 0

    I think the real question is, at what point does the resonance cascade occur and open up a portal to Xen?

  50. Spacetime. by Anonymous Coward · · Score: 0

    If space-time would not exist as we know it these days, as in Einstein's theories, light could be two dimensional. A line.
    A photon then could be a field, extending in front of it, and trailing it, basically generalized as a photonic particle [the average photon].
    Such a field, for instance measured as velocity, but call it energy, since distance doesn't really exist, neither does place, has a maximum value.
    The amount of energy within this universe you can put from A to B has a limit.
    Einstein would have been very mad if you would ask him how many photons there would somewhere -at the same time at the same place-.

    Anyway, simply put, if you put too much energy in one spot we call it matter.
    [since this universe allows for the crystallization of energy into matter]

    I'm probably wrong though, because I am not a theoretical physicist.
    Einstein is still right, so it doesn't matter.

    I think we should call space-time Ether, as that follows the human reasoning about a medium.

  51. Ionization Limit by Anonymous Coward · · Score: 0

    Finally an intelligent comment, as counterpoint to all the mental masturbation. :p The word "theoretical" here is meaningless, since one discipline's theory is another discipline's practice. Practical limits rule ALL engineering systems, and eventually it becomes impossibly expensive to surmount the next more difficult one.

    I propose an even lower limit than light pressure - ionization potential. There are two cases: gas laser and solid state.

    In the case of a gas laser, the electric field strength at the cavity wall must stay below the ionization potential of the wall material, or else the cavity wall erodes. Even if you postulate a device where the active medium is cavity wall plasma, and there is no reason to suppose such a combination of materials can ever exist, erosion will still cause the cavity to change size, ruining the optical tuning. Even movable end mirrors can't compensate indefinitely, and the cavity simply burns out.

    The solid state case is even easier. The maximum tolerable E-field is the ionization potential of the active medium, which again burns out the cavity, but this time volumetrically, not from the surface.

    Most respondents have interpreted the question as "What is the maximum E-field that free space can support." This is a different question, which has nothing to do with lasers. Slashdot's computer geniuses clearly understand not plasma physics, material science nor lasers. :(

  52. Re:There are some... er, limits: by Anonymous Coward · · Score: 0

    I used to think I'd never see a resonance cascade. Then I took an arrow to the knee.