Newly Discovered Asteroid To Pass Within Geostationary Orbit Sunday
theshowmecanuck writes: A newly found asteroid the size of a house will give earth a close flyby this weekend. It will pass just below satellites in geostationary orbit, and above New Zealand around 14:18 EDT / 18:18 GMT / 06:18 NZST this coming Sunday (Monday morning in NZ). "Asteroid 2014 RC was initially discovered on the night of August 31 by the Catalina Sky Survey near Tucson, Arizona, and independently detected the next night by the Pan-STARRS 1 telescope, located on the summit of Haleakal on Maui, Hawaii," NASA officials said in a statement.
Not the 34,000 km above earth part, but the "we discovered it a week ago" part.
Will it be visible by the naked eye?
What I find cool about this asteroid is that it's in a 1.5 year orbit. That means it's in a 3:2 resonance with Earth. So it'll come by again if you miss it this time, every 3 years.
Normally you'd expect asteroids that makes this close an approach to Earth to have a bit of a change in orbital parameters after the flyby, but that 3:2 orbital ratio is unlikely to be a coincidence-- it looks like a resonant orbit, in which the Earth's gravitational perturbation has already modified the orbit until it reached that stable resonance.
The small-body page allows you to propagate the orbit into the future, if you're interested. (Not a good tool to use if you're calculating missions, though-- you'll want a more accurate simulator! The V_infinity is a bit large for a rendezvous, though.)
http://www.geoffreylandis.com
All other source I've seen mention 0.0002664... AU or approx. 40'000 km. That would be above geosynchronous orbit altitude, not below.
For example, from JPL:
http://ssd.jpl.nasa.gov/sbdb.c...
Geostationary Orbit Sunday
I've only just recovered from Near Equatorial Tuesday!
systemd is Roko's Basilisk.
"It will pass just below satellites in geostationary orbit, and above New Zealand "
Geostationary orbit is around the equator, NZ is 40 to 45 degrees south or so.
Space.com says it's a 60-footer. http://www.space.com/27026-ast...
For "really close"
Chas - The one, the only.
THANK GOD!!!
All our hopes and dreams revolving around deflecting asteroids and comets all hinge on being able to detect them far enough out to make an intercept. Makes me think we should really reconsider the priority we put on manned space missions, particularly generational missions. Otherwise we stand a good chance of getting snuffed out as a species if we hang around here long enough. Asteroids and comets are not even the most dangerous threats we face.
That's our life, the big wheel of shit. - The Fat Man, Blue Tango Salvage
to answer GP (who I assume is an AC): geostationary is by no means arbitrary.
A geostationary orbit is one in which the orbiting body does not move relative to a point on the surface of its parent (in the context case, specifically Earth). This requires a specific orbital distance (22,236 miles*) at a specific inclination (0 to the equator), to maintain a sidereal orbital period of 23 hours 56 minutes 4 seconds (approximately). which is equal to the sidereal rotation period of Earth - how about that? In a two-body problem this would be simple, but we have this thing called the Moon, and this thing called the Sun, and to a lesser extent every other body with mass in the Universe, to deal with in maintaining a geostationary orbit. NBody physics introduces a certain degree of chaos to orbital predictions.
*this number is known by calculation using: cube root mu over omega squared. Refer to the Wikipedia.
Political debates have me rolling my eyes so much I think I got optical whiplash. I should sue. - Foamy The Squirrel