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Your Pay Is About To Go Up (gawker.com)

The Department of Labor's overtime rule is expected to be updated some time later this summer, and when it does, you will soon be entitled to overtime pay if you make less than $50,000 per year. According to Gawker, "It now appears that even if you are a salaried employee or some sort of 'manager,' you will still be entitled to time-and-a-half pay for working more than 40 hours per week, as long as your total salary falls under the threshold." How did they come to this conclusion? Gawker points out that the Department of Labor promotes a Wall Street Journal story which says that "The threshold would be increased to $970, or $50,440 annually. That level is about the 40th percentile of weekly earnings for salaried workers." Hamilton Nolan writes, "This rule has been a matter of political contention for years. But now that it is actually approaching, its import is becoming clear: overtime pay, which has long been isolated to a minority of workers, is about to be extended to almost the entire middle class."

2 of 271 comments (clear)

  1. Re:Great, drive prices up some more by crunchygranola · · Score: 4, Informative

    Get ready for things to get more expensive. You didn't actually think companies were going to give that money away freely, did you? People will lose jobs, too, because businesses won't be able to afford this.

    Because, you know, without any sort of employment regulation we always get the best of all possible worlds with absolutely the best economy and wages that there is possible to be. Because right wing ideology says so!

    It's the same reasons economists agree that minimum wage hurts the economy.

    Economists "agree" on no such thing.

    --
    Second class citizen of the New Gilded Age
  2. Re:Whose pay? by Pseudonym · · Score: 4, Informative

    Isn't everyone here a tech worker? Does anyone here actually make under 50k?

    And not everyone here lives in the US, you insensitive clod.

    --
    sub f{($f)=@_;print"$f(q{$f});";}f(q{sub f{($f)=@_;print"$f(q{$f});";}f});