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Ask Slashdot: How Do You Read Code?

New submitter Gornkleschnitzer writes: The majority of humans read silently by rendering a simulation of the printed words as if they were being spoken. By reading that sentence, chances are you're now stuck being conscious of this, too. You're welcome.

As a programmer (and a reader of fanfiction), plenty of things I read are not valid English syntax. When I find myself reviewing class definitions, for loops, and #define macros, I rely on some interesting if inconsistent mental pronunciation rules. For instance, int i = 0; comes out as "int i equals zero," but if(i == 0) sometimes comes out as either "if i is zero" or "if i equals equals zero." The loop for(size_t i = 0; i < itemList.size(); ++i) generally translates to "for size T i equals zero, i less than item list dot size, plus-plus i." I seem to drop C++ insertion/extraction operators entirely in favor of a brief comma-like pause, with cout << str << endl; sounding like "kowt, stur, endel."

What are your code-reading quirks?

2 of 337 comments (clear)

  1. Re:Wrong! by Anonymous Coward · · Score: 4, Informative

    Actually, only people who read poorly do that. People who read well decode printed words directly into mental concepts, rather than sounding them all out, only sounding out a word when it is unfamiliar in print. (see jokes about people whose lips move when they read)

    Exactly. Imagine trying to make sense of a web page by sub-vocalizing the HTML as it is printed out.

  2. Re:Maybe by viperidaenz · · Score: 5, Informative

    It's "c out" for those who understand what the statement does and "kowt" for those who don't bother to think about what it means.