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User: Brittany+$paniel

Brittany+$paniel's activity in the archive.

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  1. Re:Episode 2 - Martial Arts Jedi? on Episode II Rumours · · Score: 1

    How about casting Jackie Chan as a Jedi Knight.
    You'd get some kick ass action, AND he could supply the comic relief negating the need for a return of the dreaded Jar-Jar.

    -=[doug]=-

  2. Re:All Part of the Master Plan on Web site identifies anonymous spammers · · Score: 1

    > Same goes for websites that ask for my address

    Whenever I am asked for an address, I use root@ the domain name of the web site in the remote hope that someone in charge will get as pissed at the spam as we do.

    -=[doug]=-

  3. Re:SETI announcement? on SETI@home & RC5 · · Score: 1
    There is a slightly longer announcement in the techical news section:
    The work unit pipeline is now fully operational again. Users will be seeing data recorded on a variety of dates over the last few months.
  4. Hacker FAQ on How to Manage Geeks? · · Score: 0

    Here's a link to Peter Seebach's Hacker FAQ which may be what Taco was looking for

  5. Re:Hubble constant == 1/age-of-universe !! on Age of Universe Derived · · Score: 1

    No, it is not a coincidence that the age of the universe is 1/H (H=Hubble
    Constant). The Hubble Law can be written as:

    v = Hd where v=velocity of galaxy, and d=distance of galaxy. this is
    also where the funky units for the Hubble Constant come from.
    Astronomers like to measure distances in Mpc, so simply multiplying H
    by the distance in Mpc gives the velocity in km/s. In actuality it is
    much easier to measure the velocity, so astronomers usually divide H by
    the velocity to get an idea of the distance.


    Here is a quick estimate for the age of the universe: Consider a huge
    explosion of galaxies at time t=0. After a while when we look out at the
    galaxies, the faster ones will have moved further. A specific galaxy
    will have moved:

    d = v t where d is the distance, v is the velocity, and t is the time
    since the explosion.

    This can be rewritten as v = d / t. Now compare this equation to the
    Hubble law -- H must equal 1/t, or t (time since explosion) must equal
    1/H.

    This is the Astro 101 explaination. The correct derivation requires
    differential equations and a many assumptions about the flatness and
    density of the universe. The correct values for the age of the universe
    are:


    0 t
    t = 2/3H^-1 for a just dense enough universe

    2/3H^-1

    What always got my goat is that H is called the Hubble constant, but it
    changes with time.

    -=[doug]=- who has never even pretended to be a cosmologist