IMHO the main advantage of a VM system is that a program doesn't need to care where its memory is located. It can always act as if it just owned all the memory up to some maximum address. The VM takes care of mapping that to the right place.
You will have to flush dirty cache lines to main memory
Since cache is just SRAM, if SRAM is replaced by memristors, you don't even need to do that. Just save the registers into memory (probably the processor would have a special register storage on chip for that, so you don't even need to access memory).
What you'll still need to do is to properly shut down/reinitialize your peripherals (e.g. you don't want data from your USB memory stick in the cache when powering off, because the stick might get removed after power down, or even removed, modified on another computer, and then reinserted before the next power up).
Yes, they do have momentum. But that doesn't imply they have mass.
The relativistic energy-momentum-relation is E^2=(mc^2)^2+(pc)^2. For photons, m=0 and therefore E=pc. This is consistent with the results for radiation pressure and field energy from classical electrodynamics.
Raw natural milk might be good for you, but the sterile pasturized milk most of us grew up drinking is NOT good for you.
Any evidence for your claim?
I for one will not be getting a flu shot. I consider getting over the flu naturally to be exercising my immune system.
A flu shot is exercising the immune system. That's how it works. Your strategy is like not training soldiers because it's better training for them if another army actually invades the country and they then beat it than if you can beat that army directly at the border because of your well-trained soldiers.
The neutrinos are quite magnetically neutral, and thus not affected by the Earth's magnetic field.
To put it in a car analogy, as is the custom here: They are not passengers in this car.
The Earth moved in space while the neutrino was thrusting forwards. Even if the absolute momentum stayed within the constraint given by the 'speed of light'-- the Earth still moved its target closer to it's absolute origin, thus the neutrino traveled less than 720km. This way your calculations match and speed of light remains unbroken.
Have a nice day, -j
All you've proven is that you don't understand relativity.
Well, if you formulate relativity properly in 4 dimensions, nowhere does a "relativistic mass", a "longitudinal mass" or a "transversal mass" show up. Indeed, the relation between 4-velocity and 4-momentum is p=mu, where p is the 4-momentum, u is the 4-velocity and m is the Lorentz-invariant "rest" mass.
this is good, but you will absolutely need to get the developers to a point where they won't be over-protective of their (sometimes terrible) UI decisions. Same goes for the end-users, they need to be able to say something better than "It sucks"... e.g. "it sucks because I have to click through these three levels of context menus to get to the 'write my own SQL query' option"...
This is fixed in the next version. Now you'll just click for the context menu, scroll two screens down to the "more" menu item, which will give you a dialog window with a dropdown box. The fifth item in the dropdown list is then "write my own SQL query". Select that and press OK to get there.
Santa Claus is completely imaginary, and therefore also has a completely imaginary mass. It is well known that objects with imaginary mass are tachyonic. Being tachyonic, Santa Claus can even be at two places at the same time!
OMG. I just had to join slashdot to ask, 'WTF are most of you talking about!?'.
About Physics.
Did you not even do basic physics?
I don't know about most, but you obviously didn't, judging on your comment. Disclosure: I not only did do basic physics, but am actually a physicist.
If a particle has no mass its speed equals C???
Yes.
As far as I know anything divided by zero equals inf.
Then you have to relearn your math. Anything divided by zero is undefined. Something going to zero in the denominator makes the term go to infinity if the numerator doesn't also go to zero (or does, but slower). But that's irrelevant anyway. The energy-momentum relation of a particle in special relativity is E^2 = (mc^2)^2 + (pc)^2. For a particle at rest (p=0), this gives the well-known E=mc^2. For photons, we have m=0, and E=pc (as it must be, or the laws of classical electrodynamics would be wrong). No division by zero in sight.
They haven't even managed to measure particles with no mass because of the obvious problems.
They indeed haven't measures particles with no mass, but not because of the "problems" you claimed, but because, as we know today, the neutrinos do have mass. This is known due to the neutrino oscillations which have been found, and which were the solution to the solar neutrino problem. There are no theoretical problems with massless neutrinos (at least from the theories we know today; maybe some future unified field theory will not allow massless neutrinos). Indeed, for most of the time neutrinos have been thought to be massless.
Slashdot Mirror
The first thing they will make with this is SSDs (replacing Flash, remember?)
So the question of "how is this better than SSDs" doesn't make sense.
SSD is nonvolatile. However DRAM, which they want to replace next, is volatile.
One could define secured memory areas to be encrypted or cleared when shutting down.
IMHO the main advantage of a VM system is that a program doesn't need to care where its memory is located. It can always act as if it just owned all the memory up to some maximum address. The VM takes care of mapping that to the right place.
Maybe they wanted the stock to go down in order to buy more of it ...
Since cache is just SRAM, if SRAM is replaced by memristors, you don't even need to do that. Just save the registers into memory (probably the processor would have a special register storage on chip for that, so you don't even need to access memory).
What you'll still need to do is to properly shut down/reinitialize your peripherals (e.g. you don't want data from your USB memory stick in the cache when powering off, because the stick might get removed after power down, or even removed, modified on another computer, and then reinserted before the next power up).
My laptop still drains its battery while suspended. It drains much slower, but it still drains.
Even if suspended to disk?
That's completely irrelevant to the question whether drinking pasteurized milk is good for you or not.
I would have thought that basic tech knowledge would be a prerequisite to being an editor on a site like Slashdot.
Not everyone replaces the TV every five years. When I bought my current TV, flat screen TVs didn't yet exist.
Well, I knew about k=1000 and k=1024. But k=720 never before occurred to me.
Well, if something is affecting the electronics in the drive, it can cause data corruption even if the physical writing process is unaffected.
Yes, they do have momentum. But that doesn't imply they have mass.
The relativistic energy-momentum-relation is E^2=(mc^2)^2+(pc)^2. For photons, m=0 and therefore E=pc. This is consistent with the results for radiation pressure and field energy from classical electrodynamics.
Seems you also got fooled by comment reparenting. Hint: He was not replying to the first post of the thread.
http://ars.userfriendly.org/cartoons/?id=20020428
Any evidence for your claim?
A flu shot is exercising the immune system. That's how it works. Your strategy is like not training soldiers because it's better training for them if another army actually invades the country and they then beat it than if you can beat that army directly at the border because of your well-trained soldiers.
Woosh. It's a Futurama joke.
The comment he replied to was definitely no Futurama quote. Beware of the reparenting!
The neutrinos are quite magnetically neutral, and thus not affected by the Earth's magnetic field.
To put it in a car analogy, as is the custom here: They are not passengers in this car.
The Earth moved in space while the neutrino was thrusting forwards. Even if the absolute momentum stayed within the constraint given by the 'speed of light'-- the Earth still moved its target closer to it's absolute origin, thus the neutrino traveled less than 720km. This way your calculations match and speed of light remains unbroken.
Have a nice day,
-j
All you've proven is that you don't understand relativity.
Well, if you formulate relativity properly in 4 dimensions, nowhere does a "relativistic mass", a "longitudinal mass" or a "transversal mass" show up. Indeed, the relation between 4-velocity and 4-momentum is p=mu, where p is the 4-momentum, u is the 4-velocity and m is the Lorentz-invariant "rest" mass.
The problem with this approach is that before you've finished your product, you'll have finished your liver.
This is fixed in the next version. Now you'll just click for the context menu, scroll two screens down to the "more" menu item, which will give you a dialog window with a dropdown box. The fifth item in the dropdown list is then "write my own SQL query". Select that and press OK to get there.
Santa Claus is completely imaginary, and therefore also has a completely imaginary mass. It is well known that objects with imaginary mass are tachyonic. Being tachyonic, Santa Claus can even be at two places at the same time!
More importantly, there doesn't yet exist a single experiment which is inconsistent with zero photon mass.
Wouldn't help. Imaginary mass, however, would.
Your knowledge is outdated. Today we know that neutrinos do have mass.
About Physics.
I don't know about most, but you obviously didn't, judging on your comment. Disclosure: I not only did do basic physics, but am actually a physicist.
Yes.
Then you have to relearn your math. Anything divided by zero is undefined. Something going to zero in the denominator makes the term go to infinity if the numerator doesn't also go to zero (or does, but slower). But that's irrelevant anyway. The energy-momentum relation of a particle in special relativity is E^2 = (mc^2)^2 + (pc)^2. For a particle at rest (p=0), this gives the well-known E=mc^2. For photons, we have m=0, and E=pc (as it must be, or the laws of classical electrodynamics would be wrong). No division by zero in sight.
They indeed haven't measures particles with no mass, but not because of the "problems" you claimed, but because, as we know today, the neutrinos do have mass. This is known due to the neutrino oscillations which have been found, and which were the solution to the solar neutrino problem. There are no theoretical problems with massless neutrinos (at least from the theories we know today; maybe some future unified field theory will not allow massless neutrinos). Indeed, for most of the time neutrinos have been thought to be massless.