Tracking Possible Earth-impacting Asteroids
EccentricAnomaly writes "NASA's Near-Earth Object program has announced the Sentry automatic impact monitoring program. Check out this impact risks page showing current asteroids that might impact the Earth. The current highest risk object is 2002 CU11 which has a 0.001% impact probability in 2049... an impact that would be 58,000 megatons."
...to say "58,000 Megatons" vs "58 Gigatons".
I mean hey, a Gigaton is big, but a 1000 Megatons? Whoa, you're talking some serious tonnage there!
Personally I'd go for the max fear-factor and say 58,000,000 tons...
Alright! For the last two years, I have been looking for a reason to keep the bomb shelter in good repair. Before I was born, it was there in case of nuclear war. Then, the cold war ended, and there was a time when the shelter served no purpose. Thank the gods for y2k, there was once again a reason to keep it clean. But the computers continued to work, damn it! I damn well want to us my bomb shelter! Now, I have 47 years of anticipation. Well, its better than nothing, I suppose.
Rhapsody in Numbers
Sentry automatic impact monitoring system... Damn thing better monitor the impacts automaticly. It's not like there will me any people to care after an impact with an energy equil to the detonation of 52,727,272,727,272,727 grams of trinitrotoluol!!!
If voting were effective, it would be illegal by now.
But it would take much less TNT to wound a Gorn.
If voting were effective, it would be illegal by now.
So in 47 years we might die.
Tahts scary. Not the dying bit, the fact its 47 years - by far the most common number in the universe.
I'm sure these guys have the metric/standard thing fixed for these trajectory calculations. I mean it is NASA and they would never make a silly mistake like that right? um.. right?
How many times has your computer spit out the wrong answer but you accept it as true, just to find out later that you fed it the wrong data? I would sort of like to see them put at least as much effort into tracking earth crossing asteroids as say... modeling nuclear explosions.
I mean the JPL's computer is number 374 on the top 500 list not number 1, with number 5 acting as a glorified graphics card.
ASCI Blue, a 32,524,800,000-transistor graphics card: 50 million dollars
GeForce 4, 63,000,000-transistor graphics card: 450 dollars.
Time for ASCI blue's power to be available at retail following Moore's law: 14 years
Amateur computer enthusiasts and astronomers saving the world: priceless.
If voting were effective, it would be illegal by now.
Bruce Willis will be 94 in 2049! How will we get someone that old into space to blow up the asteroid?
I doubt a 40-meter meteor would burn much, relative to its size, on the way down.
I hate to say it, but an impact from one of these "small" rocks might be a good thing. Get a nuke-size detonation (I'm guessing a 40-meter rock would be a Hiroshima-equivalent?), preferably but not necessarily in an unpopulated area, and the world's governments might wake the fuck up to how serious the danger is, and the fact that an active space program that doesn't have to plan its launches months in advance is our best defense.
The correlation between ignorance of statistics and using "correlation is not causation" as an argument is close to 1.
Assuming the submitter did his/her math correctly...
I know 0.001% isn't *that* great a probability (1 in 100,000), but it's a little daunting to think that the probability of Earth being smacked by a huge asteroid during my lifetime is about 1000 times better than my chances of winning the lottery.
(And yeah, that's just that one asteroid, so the real chance would be even a bit higher.)
Gives new meaning to "live for today", eh?
The probability for an impact in 2049 is 1e-5 which is 0.001%. If you take range of years you can get a higher probabilty, but I thought the probabilty of impact in a given year was more interesting than over an arbitrary range of years.
There are 10 types of people in this world, those who can count in binary and those who can't.
With the annoying inverse square law for radars, you're be pretty much reduced to optics
... and the major problem with "eyballing it" (well.... CCD'ing it anyway) is that a lot of Kuiper belt objects have an albedo of ~0.03-0.05. That's about the same as printer toner. Hmmm.... let's look for the black rock 10km across that's 2x10^9 km away.
Asteroids are a little brighter, but it still takes a LOT of patience, comparing multiple shots of the same piece of sky to look for the movers and THEN try to calculate a trajectory
MAB