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'Mouse-Tronaughts' to Test Low-Gravity in Space

RandBlade writes "The Telegraph has an article about plans to launch mice into space with simulated low-gravity for five weeks, to test the effects of low-gravity on their bodies. This "will be the first time mammals of any kind have lived in partial gravity for an extended period." Hopes are that this will provide information useful for plans to launch men to Mars, which has one-third of the gravity of Earth."

15 of 276 comments (clear)

  1. First time for mammals by baryon351 · · Score: 5, Funny

    > This "will be the first time mammals of any kind have lived in > partial gravity for an extended period."

    As opposed to those reptilian astronauts.

    1. Re:First time for mammals by hokanomono · · Score: 4, Informative

      The point is: there is no documented experiment of humans living in partial gravity for an extended period.

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  2. Re:Pardon? by worst_name_ever · · Score: 5, Informative

    RTFA... partial gravity != microgravity.

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  3. Mouse-Tronaughts? by Tirel · · Score: 5, Funny

    so people in space are what? Homo-tronaughts?

  4. Reproduction in space by tjstork · · Score: 5, Interesting


    Can people reproduce on other planets? Can any earth creature? We can conceivably provide a breathable habitat, running water, etc. But, it is becoming clear that gravity plays a fairly strong role in the development of living things from fertilized egg to adulthood. Perhaps it might be impossible to reproduce on the moon or mars, because there is not enough gravity. Or, maybe you can but there will be a statistical risk of some undiscovered birth defect.

    It may turn out that the only viable planet to really colonize is Venus, then, it becomes a question of, what do we do with 10^20 tons of carbon dioxide!

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  5. Animal Cruelty by queen+of+everything · · Score: 4, Insightful

    I'm sure we'll have lots of posts about "animal cruelty". Is it better to test on mice or humans? Which life is worth more? Would it be fair to send humans to Mars and just watch their bodies essentially turn to jello from the lack of gravity? Those that spent time on the ISS are dealing with the consequences of little or no gravity for an extended period of time.

    I'm not saying that it is necessarily "right" to test on animals, but from a scientific point of view, it will bring us much closer to knowing the effect of the conditions on Mars and will bring us closer to having manned missions and even maybe a space station there one day.

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  6. You mean astromouse ? by theefer · · Score: 4, Interesting

    The word astronauts come from the greek : astro (stars), nautike (navigation). So astronaut litteraly means star navigator, and mouse-tronaut would mean mouse navigator, which lacks some sense here.

    I'd rather have said astro-mouse (star mouse) instead. Or if anyone has the greek word for mouse ...

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    1. Re:You mean astromouse ? by NonSequor · · Score: 4, Informative

      Actually astrum (star), is Latin. And nauta is Latin for sailor. So you need the Latin word for mouse which is mus (pronounced like the English word moose).

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  7. Re:Pardon? by Gojira+Shipi-Taro · · Score: 4, Insightful

    I think you missed the bit about "simulated low gravity." They're not going to be in "zero-g" or microgravity.

    The point of the experiment, if I understand it correctly, is to determine to what degree a low gravity (as opposed to micro-gravity, which is what the space stations experience) environment differs in effect on mammals from Full Gravity and Micro-gravity environments.

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  8. Enhanced Gravity by vontrotsky · · Score: 4, Interesting

    In high school I did a project which involved growing plants in simulated hypergravity (produced by centripetal acceleration), then tried to extrapolated into the low gravity regime.

    Up to 140% of normal, the plants grew faster with increasing "gravity". From this I reasoned that lower gravity conditions (moon, mars) would be healthy for plants.

    Of course, NASA's results may vary. Especially when using mice.

    Jeff

  9. isn't this pointless? by bob_jenkins · · Score: 4, Interesting

    I would have thought the effects of gravity scale with weight. Mice are so small, they're nearly surface-oriented instead of gravity-oriented anyhow. They've got almost no gravity-induced features in the first place.

  10. Re:They contradict themselves in the article by Mwongozi · · Score: 4, Informative

    Or you could try reading the article. Partial gravity is not the same as a weightless environment.

  11. Mice in space? by FrostedWheat · · Score: 4, Funny

    They're Pinky and the Brain?

    Pinky: What are we gonna to tommorow night Brain?
    Brain: Same thing we do every night Pinky. Try to take over the space capsule!

  12. i think there's been a misunderstanding by real_smiff · · Score: 5, Funny
    People in space *are* Astronauts (from the greek astron, meaning star, and naut, meaning sailor).

    Unfortunately this means 'Mousetronauts' are people who sail into mice. Right, perhaps someone should call the paper.

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  13. Re:They contradict themselves in the article by NeoThermic · · Score: 4, Insightful

    >> If you have a calculator, determine the force from gravity applied to a human on earth. Then, calculate again from 1,000 km away. It's a small difference.

    Sure! I'm Game!


    Now, if a body of mass m is a distance r from the center of the earth, you know that the weight of the body is F given by the formula F=GmM/r^2 The gravitaional field strength is g = F/m = (GmM/r^2)/m = GM/r^2

    (With me sofar?)

    g=GM/r^2
    = 6.7 * 10^-11 N m^2 kg^-2 * 6.0 * 10^24 kg/(6.4 * 10^6)^2
    = 9.814 N kg^-1


    Notice! We get a value which is gravity at earths surface...

    Ok, so with the poster above... lets add on our 1,000 km ...

    g=GM/r^2
    = 6.7 * 10^-11 N m^2 kg^-2 * 6.0 * 10^24 kg/(6.401 * 10^6)^2
    = 9.811 N kg^-1

    Yes, we lost all of 0.001 N kg^-1... our poster above is right.

    So, how can they make this worth while? Easy. Make them do a larger orbit, so that they are twice the distance r from the earth (notice above, you have to measure from the center of the earth...)

    So, lets see how much N kg-1 our mice would have if they were twice as far out...

    g=GM/r^2
    = 6.7 * 10^-11 N m^2 kg^-2 * 6.0 * 10^24 kg/(12.8 * 10^6)^2
    = 2.453 N kg^-1


    Anyway, enough maths...
    NeoThermic

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