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ESA Selects Targets for Asteroid Deflection Test

Vandil X writes "The European Space Agency has announced that it has selected two candidate asteroid targets for a planned mission to impact an asteroid in an attempt to deflect the asteroid off course by a measurable amount. The mission, dubbed "Don Quijote," will send two spacecraft to their final choice asteroid. One craft will impact the asteroid while the other will observe the asteroid before and after the collision. The mission craft and target selection are expected to be finalized sometime in 2007."

9 of 284 comments (clear)

  1. The public will get to view the event by Anonymous Coward · · Score: 5, Funny

    ... but can only watch it in black and white vector graphics, and have to pay $0.25 to view it.

  2. Dateline 27 September 2159 by DavidRawling · · Score: 5, Funny

    In other news, the asteroid deflected in 2008 by the European Space Agency has been confirmed as hitting Earth in December this year, with an expected impact point near Switzerland.

    It's been nice knowing you folks.

  3. Re:Something wrong with p? by Zaak · · Score: 5, Insightful

    What's wrong with the good old p=mv (momentum)?

    "In theory there is no difference between theory and practice. In practice there is."
    -- Yogi Berra

    TTFN

  4. Re:Crash? by republican+gourd · · Score: 5, Insightful

    Yes, the possible deflection of an object of a given mass and velocity when struck with another object can be calculated. But you miss lots of other important information if you ignore real world tests. Just off the top of my head:

    1) You assume that the target object is solid enough to resist being broken into multiple pieces. It does no good to deflect a small chunk of the object while the main mass continues on its normal course.

    2) If you are planning on hitting an object enough to deflect it, you need... a bit of practice. The targetting, propulsion and all other such systems are just as big a part of this test as anything else. All the mathematics in the world won't help you play pool with a bad cue.

    3) Is a collision with an asteroid likely to be elastic? Will the striking object bounce off of the target or embed itself within it? These are very different models as far as where the force goes.

    4) As a side effect, you get more information along the lines of the previous Deep Impact probe.

  5. Re:Sweet mercy by raider_red · · Score: 5, Funny

    Good call, but let's leave Ben Affleck on the asteroid this time.

    --
    It's good to use your head, but not as a battering ram.
  6. Re:Crash? by MyLongNickName · · Score: 5, Funny

    ir, I wish you good luck in finding a circus capable of handling your freakishness.

    I have. It is called "Slashdot".

    --
    See my journal for slashdot ID's by year. Mine created in 2005. http://slashdot.org/journal/289875/slashdot-ids-by-year
  7. OOPS by Brad1138 · · Score: 5, Funny

    What we don't want to hear after a successful deflection....

    --
    If you could reason with religious people, there would be no religious people
  8. Re:Liv Tyler? by servognome · · Score: 5, Insightful

    It is funny what we never think of- every night while we sleep there are so many people keeping us safe- Call me a geek, but astronomers are unsung heroes.

    Yeah, like the guy at the water treatment facility - who keeps us from plague, or the fed-ex guy- who transports vital medical supplies, or the building inspector- who ensures our structures don't collapse on us, or the guy who draws those warning pictures - so we don't accidently eat our Shuffles, or telephone sanitizers.

    Astronomers do an important job, but calling them unsung heroes is a little much. If they volunteer to be stuffed in a cannon and shot at the asteroid to deflect its path, then i'd call them heroes.

    --
    D6 63 0D 70 89 81 BB 8E 7B 7C 5F 5D 54 EA AB 73
  9. Re:Something wrong with p? SIMPLE by amdotaku · · Score: 5, Informative

    (p1 + p2)[)[initial]=(p1 + p2)[final]

    Uh, we know the first two p(momentum, vector) values(and that's if we know the mass of the asteroid, which isn't necessarily true), but not the second two. In my math classes, we learned that was 1 equation (vector valued) and two unknown vectors. I don't think anyone can solve that, and no, conservation of kinetic energy won't work because the internal energy changes big time in most non-particle scale collisions. In Mechanics, many of our college educated comrades learned of a way to resolve this textbook documented issue with the simple aide of a constant e, which details the elasticity of the interaction. Unfortunately, e is not easy to determine through theory, and is also just a model (and a bad one at that), and therefore an experiment is usually called for (and usually a lot of them). 'Nuff said.

    http://scienceworld.wolfram.com/physics/Collision. html