Slashdot Mirror


Scientists Discover Teeny Tiny Black Hole

AbsoluteXyro writes "According to a Space.com article, NASA scientists have discovered the smallest known black hole to date. The object is known as 'XTE J1650-500'. Weighing in at a scant 3.8 solar masses and measuring only 15 miles across, this finding sheds new light on the lower limit of black hole sizes and the critical threshold at which a star will become a black hole upon its death, rather than a neutron star. XTE J1650-500 beats out the previous record holder, GRO 1655-40, by about 2.5 solar masses."

37 of 277 comments (clear)

  1. That's nothing... by Anonymous Coward · · Score: 5, Funny

    They say LHC-001 will be even smaller!

    (But who will be there to measure...?)

    1. Re:That's nothing... by Enoxice · · Score: 5, Informative

      LHC = Large Hadron Collider: http://en.wikipedia.org/wiki/Large_Hadron_Collider

      001 = First black hole created by LHC

      Some people are afraid the LHC-001 is going to destroy the Earth.

      --
      Anyone else think the comments just weren't rendering right before they turned off ABP and saw ads?
    2. Re:That's nothing... by B3ryllium · · Score: 4, Funny

      He's talking out of his hardon-collider.

    3. Re:That's nothing... by sayfawa · · Score: 5, Funny

      There may already be microscopic (more like picoscopic) black holes all around us. The thing with black holes is they are only dangerous if you get close to them. If they are small they can whiz right through us without hitting anything, much like many other particles that pass through us all the time. I'm not saying that creating one would be a good idea, but if, on the off-chance, one were created by the LHC it will probably be innocuous. I wish I could make those sound less like famous last words.

      --
      Free the Quark 3 from asymptotic confinement! Bring your charm! Don't get down! All colours and flavours welcome!
    4. Re:That's nothing... by ShadowBlasko · · Score: 4, Funny

      So thats where all my socks keep going!

      --
      There are 4 boxes to use in the defense of liberty: soap, ballot, jury, ammo. Use in that order- Ed Howdershelt Via Tass
    5. Re:That's nothing... by c6gunner · · Score: 4, Funny

      He's talking out of his hardon-collider.
      How exactly did we get from talking about black holes, to talking about gay porn?

      ....

      Actually, nm, don't say it, it's too obvious....
    6. Re:That's nothing... by inode_buddha · · Score: 5, Funny

      Nope. Umatched socks are simply the larval stage of coat hangers.

      --
      C|N>K
    7. Re:That's nothing... by Kingrames · · Score: 3, Funny

      So what you're saying is that the odds of getting sucked into a black hole are proportional to its size. That sounds like something you could write a couple hundred to a couple thousand pages on and get a doctorate out of.

      But... it needs more string theory.

      --
      If you can read this, I forgot to post anonymously.
    8. Re:That's nothing... by phirst · · Score: 4, Funny

      001 = First black hole created by LHC. Some people are afraid the LHC-001 is going to destroy the Earth. Presumably you're not one of them, what with your three digit black hole serial numbers...
  2. Black-hole... sheds new light... by Anonymous Coward · · Score: 5, Funny

    HILARITY!

  3. We weren't the first by cryptoluddite · · Score: 4, Funny

    I see we weren't the first to build a large hadron collider.

    1. Re:We weren't the first by Oktober+Sunset · · Score: 3, Funny

      Wikipedia says Goatse.cx was launched in 1999, but Hello.jpg was on IRC before then, so the black hole much have been created quite a while ago quite a while ago.

    2. Re:We weren't the first by treeves · · Score: 3, Funny

      Yuck. I hate those artificial ones. They're full of preservatives. Give me a good old-fashioned, all natural, non-GMO, organic black hole any day.

      --
      ...the future crusty old bastards are already drinking the Kool-Aid.
  4. Awwww, little baby one by Anonymous Coward · · Score: 5, Funny

    It may look cute now. But they grow up.

  5. Size vs Age by __aapbzv4610 · · Score: 5, Interesting

    While it may be possible that this black hole was formed from a relatively small (to form a black hole) star, couldn't it also be the case that it just a really old black hole? Hawkings told of how black holes can 'evaporate' over time with lack of surrounding matter, perhaps that could be the case here.

    1. Re:Size vs Age by smolloy · · Score: 5, Informative
      It is true that black holes will evaporate over time, but they will also gain mass from infalling matter.

      But!

      The temperature of a black hole can be defined by the rate at which Hawking photons are streaming away from it. In the case of a black hole of a few solar masses, this temperature will be in the nano-Kelvin (I think -- don't hurt me if I'm wrong by a few orders of magnitude). Now remember everything in the Universe is sitting in a bath of cold photons from the Big Bang (i.e. the microwave background). These photons have a temperature of ~4 Kelvin.

      Therefore, black holes whose Hawking temperature is above the microwave background will be net *gaining* mass.

      Which is all a long way of saying, no, this isn't a normal size black hole that has decayed over time. It must have been created at this mass (or smaller).

    2. Re:Size vs Age by tardyon · · Score: 3, Interesting

      Perhaps you can answer a question for me. If I understand the concept correctly (and stop me where I go wrong), the event horizon can be defined as the point where any light that were to be ejected (I know, I know not possible) from the singularity perpendicular to the tangent (straight "up") would stop and return. This is the Newtonian description of a black hole. The relativistic description is considerably more complicated. First of all, you must always start any relativistic description by stating your reference frame - i.e. who is making the observations? The Schwarzschild metric (which is the standard non-rotating black hole) takes the observer to be someone infinitely far away and not moving relative to the black hole. According to that observer, there is a singularity at the event horizon. Anything inside the horizon is effectively in a different universe. Anything outside of it takes an infinite amount of time to fall all the way to the horizon. As stuff gets closer to the horizon, its time rate slows down and the radiation it emits gets red-shifted. There's no point in saying what the distance from the horizon to the singularity is in this frame of reference because the horizon IS the singularity. Equally, the space inside had no volume; in fact, the "space" inside isn't even space-like, whatever that means.

      Given the relativistic time stretching effects that this implies, as I understand it, anybody falling in would experience "the end of the universe" as time around him speeds up infinitely. Now we're in a new frame of reference, that of the person falling in. In this frame of reference, the event horizon is nothing special. In fact, for the huge black holes theoretically at the centers of galaxies, someone falling through the event horizon doesn't notice much at all, even the tidal forces are fairly tame. As far as they are concerned, time keeps marching on happily and they keep falling, and their only discomfort is the increasing tidal forces they experience. Also, the rest of the universe slows down. They categorically do not see the end of the universe. They also never see the singularity. If they fall feet first, they don't even feel their feet hit the singularity as their brain hits the singularity before light can travel from the space-time event of "foot hits singularity" to the brain. I can do the proof, but I'm not entirely sure I understand this concept. :) This is irrelevant however since tidal forces will rip them up before they hit the singularity.

      My question is, assuming that I am not simply mistaken about the relativistic effects of the event horizon, is; what happens to that item falling into the black hole when the black hole evaporates? That's a very good question. In principle, the answer is that anything that falls into the black hole hits the singularity and gets utterly destroyed. There's a lot of concern about what really happens to the "information" about what went in, but it's probably irrelevant to your question. Whatever comes out, it's not what you or I would consider to be recognizable based on what went in. If you fall in, you won't reappear after the black hole evaporates. Instead, a slew of random (or possibly not so random) elementary particles with the same total mass that you had will be emitted over the course of trillions of years. It's a brilliant paper shredder.
  6. Goldilocks by Dopamine,+Redacted · · Score: 5, Funny

    So, we've now discovered the biggest and smallest black holes known to exist within about a week of each other.

    When we find the most average, space bears will come and blast us into porridge.

    Astronomy kicks ass.

  7. Re:Probably Something Stupid by Ecuador · · Score: 4, Informative

    While black holes is not my area, I can tell you that when someone talks about the size of the black hole, they refer to the event horizon, since you can't really measure anything going on inside it.
    The mass of the black hole is the most defining characteristic.

    --
    Violence is the last refuge of the incompetent. Polar Scope Align for iOS
  8. untrue statement by ILuvRamen · · Score: 5, Interesting

    They can't figure out the "critical threshold" because there isn't one. It all depends on too many variables to set a universal limit (hehehe get it...universal :-P) It depends on how much nuclear activity there is still going on when it start collapsing and what the amount of heavier atoms is and the amount of other things orbiting the star and any other forces affecting the star at that time and how fast it's moving and spinning. Mass is a smaller part of the calculation than they're making it sound like. If they're going to factor everything in just to find some minimum mass, well duh, two particles and a hell of a lot of force. Haven't they suggested that in that big particle accelerator aka donut of doom. So yeah, a critical mass threshold doesn't exist.

    --
    Google's Super Secret Search Algorithm: SELECT @search_results FROM internet WHERE @search_results = 'good'
  9. Re:Probably Something Stupid by Geoffrey.landis · · Score: 5, Informative

    I thought that Black Holes had no dimensions, but this one is several miles across. Where have I gone wrong?

    A black hole, conventionally, consists of an event horizon surrounding a region of space from which you can't send information to the external world. This region of space is not a point, it has a well-defined circumference. (Because of the non-euclidean nature of general relativity, it doesn't actually have a well-defined radius (since you can't measure across the middle!) but people usually just consider the radius as if it were defined as the circumference divided by 2 pi, and don't worry about the fact that you can't actually measure it.)

    At the center of the black hole is, according to general relativity, a point singularity, which indeed has no dimensions.

    --
    http://www.geoffreylandis.com
  10. Re:As someone who skimmed A Brief History of Time by BoChen456 · · Score: 3, Informative

    I believe they are referring to the diameter of the event horizon

  11. "this finding sheds new light" by nick_davison · · Score: 4, Funny

    "this finding sheds new light" I'm pretty sure it doesn't.
  12. Re:Probably Something Stupid by The+Only+Druid · · Score: 4, Informative

    Actually, that's only true of a non-rotating (or Kerr) singularity. All natural black holes will be rotating (the black hole maintains the rotational momentum of the pre-collapse mass). In a rotating black hole, the singularity is actually a ring (or torus). Inside that ring/torus, there is a tear in space.

    It was this tear that lead, if I recall, to the original conjectures of a white hole, and the Einstein-Rosen bridge.

    --
    "Stumble before you crawl"
  13. Re:The Earth in danger from microscopic black hole by Anonymous Coward · · Score: 4, Interesting

    ok, I am ripping most of the info from here: http://www.physicsforums.com/showthread.php?t=122375&page=6

            "If they were able to make a small blackhole, and it got "loose" and fell to the center of the Earth, the pressures at the Earths core would force material into it so fast that even a very small one would gobble us up very fast. I am not sure what the exact pressure is at the Earths core but it could force material through even a very small "hole" very quickly. I do agree that once it gobbled up the Earth, it would just continue to orbit the Sun, and the Moon would still orbit the blackhole as if it were the Earth..."

    No, you should read this thread.

    First of all, a black hole that falls to the center of the earth, wouldn't stop there, but would continue falling up on the other side, just to plunge in again, and on and on, because there's no "friction" on the black hole.

    Second, there have been posted in this thread a lot of calculations of the speed at which it would gobble up matter.
    Don't forget that the black hole we're talking about here IS MUCH MUCH SMALLER THAN A PROTON. As such, pressures on *atomic* level (such as in the center of the earth) matter little: the black hole travels most of the time in the empty space between nucleae.
    A way to calculate the probability of hitting a nucleus (and somehow imagining that it would gobble up the entire nucleus, which is MUCH MUCH bigger than the black hole itself - which is a worst-case scenario) is done by calculating the "cross section" of the black hole and its probability to cross a nucleus on its voyages through the earth. We know its speed (just falling), and knowing the cross section and the density of nucleae, we can estimate how many nucleae it could eat per unit of time.

    For a classical black hole, the calculation is done in the link provided by Pervect in this post:
    http://www.physicsforums.com/showpos...4&postcount=12

    for a MUCH LARGER black hole, about the size of a proton, weighting a billion tons (figure that! A black hole *the size of a proton* weights a billion tonnes ; we're talking here about black holes that weight 10 TeV or 10^(-24) kg - go figure how small it is !)

    For more exotic calculations which are more severe, orion made some, and arrived at a time to eat the earth ~ 10^46 years.

    All this in the following rather un-natural hypotheses:
    - no Hawking radiation (which would make the black hole evaporate almost immediately)
    - production of black hole EXACTLY IN THE CENTER OF GRAVITY of the collision (no remnant particles)
    - very high production rate, producing billions of black holes per second.

    I am not a physicist, but from what little physics I have had, and from reading threw the thread/flamewar, I dont think we have to worry about the LHC

  14. Re:Probably Something Stupid by dmartin · · Score: 3, Interesting

    Actually, the Schwarzchild solution does have a well-defined radius. In fact, the problem is that it has many well-defined radii, depending on what you mean by the term (as you point out, this comes about because of the non-Euclidean nature of the geometry). The commonly quoted "Schwarzschild radius" r = 2GM/c^2 is obtained by taking the area of the horizon and figuring out which "r" you would have to plug into A = 4 pi r^2 [true for a flat space sphere] to get the right result. Taking the circumference and dividing by 2 pi would achieve the same result. However, it is quite possible to figure out the proper distance between the horizon and the singularity by measuring the distance an infalling observer would travel. This distance is finite.

    A problem can occur if you try and use constant time slices, using the "natural" time coordinate as defined by an observer far from the black hole. This gives silly results, but that is only because of badly behaved coordinates.

  15. Oh shit... by neokushan · · Score: 5, Funny

    If that happens, what are we going to do!? Capitan Picard hasn't been born yet! Hell, even Kirk isn't around yet....

    --
    +1 IDisagreeSoHeMustBeATrollOrAnAstroturferOrAShill
    1. Re:Oh shit... by evilviper · · Score: 4, Funny

      If that happens, what are we going to do!? Capitan Picard hasn't been born yet! Hell, even Kirk isn't around yet....

      Not to worry, the Enterprise is speeding around the Sun as we speak... Space-whales told them to.

      --
      Slashdot gets worse every day... Pipedot: News for nerds, without the corporate slant
  16. What the article fails to pont out is ... by celtic_hackr · · Score: 5, Funny

    This newly discovered Black Hole is the final result of a Large Hadron Collider, that caused a microsopic black hole on the third planet formerly circling the former star now known as 'XTE J1650-500'. So, this is not a naturally occuring black hole, but an alien-created one. Sadly this alien species is now extinct so they can't tell us how to avoid their mistake.

  17. Re:Probably Something Stupid by Geoffrey.landis · · Score: 3, Interesting

    Actually, the Schwarzchild solution does have a well-defined radius.

    No, actually it doesn't. What is usually called the Schwartzschild "radius" is not actually a radius by the definition of the word, "distance to the center".

    In fact, the problem is that it has many well-defined radii, depending on what you mean by the term (as you point out, this comes about because of the non-Euclidean nature of the geometry). The commonly quoted "Schwarzschild radius" r = 2GM/c^2 is obtained by taking the area of the horizon and figuring out which "r" you would have to plug into A = 4 pi r^2 [true for a flat space sphere] to get the right result.

    Exactly. You can calculate the area (which is well defined) and divide it by 4 pi, and you are free to call that the radius if you like. Or, equivalently, divide the circumference by two pi. But you can't measure the distance to the center.

    Taking the circumference and dividing by 2 pi would achieve the same result. However, it is quite possible to figure out the proper distance between the horizon and the singularity by measuring the distance an infalling observer would travel. This distance is finite.

    Finite... and timelike. It would be a little like trying to define the radius of a circle if you're standing on the circumference, and the center is next Tuesday at noon.

    A problem can occur if you try and use constant time slices, using the "natural" time coordinate as defined by an observer far from the black hole. This gives silly results, but that is only because of badly behaved coordinates.

    Within the event horizon, any choice of coordinates is rather badly behaved, because there is no well-behaved stationary coordinate system.

    --
    http://www.geoffreylandis.com
  18. Re:Probably Something Stupid by afaik_ianal · · Score: 3, Interesting

    Is there a theoretical way to revert a singularity? In theory, they radiate themselves out of existence over time through Hawking Radiation. They constantly release energy, which reduces their mass. If they lose more mass than they swallow, then their event horizon will shrink. Eventually, there'll be no mass left, and no black hole.
  19. Rotating black holes [Re:Probably Something S...] by Geoffrey.landis · · Score: 4, Interesting

    Actually, that's only true of a non-rotating (or Kerr) singularity. Yeah, I thought about mentioning that, and decided what I was writing was getting a bit complicated already

    All natural black holes will be rotating (the black hole maintains the rotational momentum of the pre-collapse mass).

    Well, maybe. Actually, rotating black holes radiate away angular momentum, and they also preferentially eat material that reduces their angular momentum, so it's an open question as to whether real black holes will be rotating. Probably, because the accretion disk is likely to be rotating, and it swallows up the accretion disk and gains the momentum from it, but I'm not sure you can necessarily say that all natural black holes will rotate.

    In a rotating black hole, the singularity is actually a ring (or torus). Inside that ring/torus, there is a tear in space.
    It was this tear that lead, if I recall, to the original conjectures of a white hole, and the Einstein-Rosen bridge.

    Actually, the Einstein-Rosen bridge comes from the maximum analytical extension of the Flamm embedding, way predating the Kerr solution. (It's a very trivial embedding, z = sqrt(r). The extension is z = plus or minus sqrt(r).) Turns out that the extended Flamm embedding is misleading, and a Schwartzschild black hole isn't a wormhole after all. But that wasn't obvious.

    --
    http://www.geoffreylandis.com
  20. Quantum Foam by jd · · Score: 3, Informative

    There are going to be a near-infinite number of quantum-scale black holes and wormholes in whatever volume of space you care to imagine. They evaporate almost instantly. As for stellar black holes, the Chandrasaker Limit is 2.5 solar masses, with a relatively small margin of error. Absolutely nothing of interest will be learned until we're within 2.75 solar masses, because then we can define sensible confidence limits on what the value actually is.

    --
    It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    1. Re:Quantum Foam by rasputin465 · · Score: 4, Insightful

      As for stellar black holes, the Chandrasaker [sic] Limit is 2.5 solar masses, with a relatively small margin of error.


      The value of the Chandrasekhar limit depends on how one performs the calculation, but typically it comes out to around 1.4 solar masses (not 2.5). But actually, this is not so much the interesting question, because the Chandrasekhar limit applies only to white dwarfs, whose mass is supported by electron degeneracy pressure. This is only one type of a much broader concept called fermion degeneracy pressure.

      For example, a neutron star is much denser than a white dwarf, and is supported by neutron degeneracy pressure instead of electron degeneracy pressure and hence the Chandrasekhar limit does not apply to neutron stars. The equivalent limit for neutron degenerate matter is called the Tolman-Oppenheimer-Volkoff limit. Like the Chandrasekhar limit, this calculation is very dependent on the behavior of the degenerate matter, but UNlike the Chandrasekhar limit, we know very little about the properties of neutron degenerate matter, and so the uncertainty of the T-O-V limit is quite large; it is usually placed (as you can see in the wikipedia article that I link to) between 1.5 and 3.0 solar masses. And there are even denser objects that have been proposed (though not observed) made of quark degenerate matter, and the limit on the mass of these things is even more uncertain.

      So the point is, there is still a good deal of physics that can come from the observation of a 3.8 solar mass black hole, as it can constrain various models of fermion degenerate matter.
  21. Relax by Orion+Blastar · · Score: 3, Funny

    as long as Stephen Hawking is still alive, I am sure he can handle it. After all Stephen Hawking beat all the other great scientists in poker with Commander Data in the far future, so he should be smarter than Picard or Kirk. If anyone knows how to reverse a black hole it would be Hawking.

    Besides never apply a Star Trek solution to a Babylon Five problem.

    --
    Remember, Slashdot does not have a -1 disagree moderation, and no, troll, flamebait, and overrated are not substitutes.
  22. I dunno, but... by OneoFamillion · · Score: 4, Funny

    for those wanting to find the article later, I strongly suggest Slashdot's own search instead of googling for the words "teeny", "tiny", "black" and "hole" :|