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Most Detailed Photos of an Atom Yet

BuzzSkyline writes "Ukrainian researchers have managed to take pictures of atoms that reveal structure of the electron clouds surrounding carbon nuclei in unprecedented detail. Although the images offer no surprises (they look much like the sketches of electron orbitals included in high school science texts), this is the first time that anyone has directly imaged atoms at this level, rather than inferring the structure of the orbitals from indirect measurements such as electron or X-ray interferometry."

56 of 229 comments (clear)

  1. really? by timmarhy · · Score: 3, Funny

    looks like it was done in MS paint to me...

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    1. Re:really? by ModernGeek · · Score: 5, Funny

      The shadows are all wrong.

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    2. Re:really? by Canazza · · Score: 4, Funny

      Physicists are not photographers! They obviously had the shutter speed too low - Look how blurry the picture is!

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    3. Re:really? by miro+f · · Score: 4, Funny

      can't really call it a photograph if it was taken with electrons rather than light.
      I wonder how they can tell the electron is blue?

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    4. Re:really? by Stenchwarrior · · Score: 2, Funny

      Looks like the magic 8-ball to me.

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    5. Re:really? by tsa · · Score: 2, Funny

      Duh. It's in a vacuum! Of course it's blue.

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    6. Re:really? by nacturation · · Score: 5, Funny

      Looks like a smurf sat on the photocopier.

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    7. Re:really? by easyTree · · Score: 2, Informative

      Did someone post the wrong image? Isn't this the winner of last year's "Least detailed photo of anything" contest? I'm pretty sure it is.

  2. Speaking as a chemist by PatrickThomson · · Score: 5, Interesting

    This is amazing. We'd theorised orbitals to exist, and they worked very well. We could calculate the shapes of molecules and make detailed predictions that came true to 10 decimal places. Quantum mechanics as applied to electrons in atoms is the most successful and the most rigorously tested theory ever developed.

    And yet, to finally see a real orbital, not a simulation. Looks like a 1s and a 2p, right there for the looking!

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    1. Re:Speaking as a chemist by PatrickThomson · · Score: 4, Insightful

      We can only "approximate" orbitals in atoms with more than one electron, true. That's the same as saying that numerical methods won't "exactly" solve a function. We can still get really accurate results, even if it's computationally expensive. FT-IR of heteronuclear diatomics, anyone?. Orbitals still retain the basic shapes in multiple-electron atoms.

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    2. Re:Speaking as a chemist by L4t3r4lu5 · · Score: 2, Interesting

      Speaking as a chemist, could you explain what exactly this means? Up until this very moment I have been under the misguided notion that the nucleus of an atom was orbited by electrons within groups called "shells", and these worked very similarly to satellites around a planet. I've looked up and read (for around 5 minutes, so give me a little time to properly read up on it) that this is not the case, and that the "shells" model given to 16 year olds is (understandably) over-simplified.

      So, could you in any way explain how we get from "think of it as a planet with many moons" to this or more importantly, what gives orbitals this shape?

      Maybe I'm opening Pandora's Box here, but I'm intruiged.

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    3. Re:Speaking as a chemist by anarchyboy · · Score: 3, Interesting

      Depends what you mean by real, certainly splitting your many electron wave function into orbitals works well and allows an accurate approximation of the system as a whole. The orbitals do form a basis of functions for the system (with some acceptable approximations) so while your quantum state is the whole thing you can think of it as being built of oribitals. This is true in a mathematical sense its an expansion of the quantum function as a set of orbital functions. This is as valid as any other expansion like a taylor or powerseries expansion. So orbitals are real enough in that sense. You can then calculate observables for the individual electrons since your operators will act only on the single electron and your oribtals are normalised the rest of the electrons essentialy go away and you can calculate things like the average radial ditance etc and build up pictures of what that electron "looks like". Since the orbital functions are calculated (numerically) as a multi electron system even though the end product allows you to look at individual electrons as orbitals the overall wave function (all the orbitals combined) is still a very accurate picture of the system

      In fact the experimental evidence showing a physical picture of these orbitals just goes to show that this is in fact a very sensible and useful way of picturing your atom.

    4. Re:Speaking as a chemist by PatrickThomson · · Score: 5, Insightful

      Basically, a chemistry education is very much like fast-forwarding through 300+ years of science history. Some dead-ends are skipped, but by and large, the simpler and more self-contained a theory was, the older it is and the earlier it's taught in school. The university-taught molecular orbital theory is (debatably) too rich and complex to be taught any earlier.

      The moons-orbiting theory fit with all the available evidence at the time it was developed. Think of orbitals as clouds of probability where, if you tried to pin down the electron, it might be. A moons-orbiting theory would give this probability cloud as a thin donut around the atomic waist. The shapes of orbitals as depicted in wikipedia etc. are consequences of the maths of quantum mechanics. It's annoyingly non-intuitive.

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    5. Re:Speaking as a chemist by PvtVoid · · Score: 5, Informative

      Speaking as a chemist, could you explain what exactly this means? Up until this very moment I have been under the misguided notion that the nucleus of an atom was orbited by electrons within groups called "shells", and these worked very similarly to satellites around a planet.

      You're thinking of the Bohr model.

      So, could you in any way explain how we get from "think of it as a planet with many moons" to this or more importantly, what gives orbitals this shape?

      It's because the Schrodinger equation is a Laplacian, and the hydrogen atom is a spherically symmetric problem. The natural basis for the Laplacian in spherical coordinates is spherical harmonics. The shape you are seeing is the characteristic shape of different spherical harmonics, corresponding to the angular momentum of the electron.

    6. Re:Speaking as a chemist by S3D · · Score: 2, Informative

      Up until this very moment I have been under the misguided notion that the nucleus of an atom was orbited by electrons within groups called "shells", and these worked very similarly to satellites around a planet.

      Think of a satellite randomly teleporting around the planet, leaving ghostly afterglow behind. The "glow" would have the shape of those shells. Or the "brightness" of the shell is the probability of existence of "satellite" in the point of space. What gives orbitals their shape is the Schrodinger equation.

    7. Re:Speaking as a chemist by The_Duck271 · · Score: 5, Informative
      At atomic scales electrons cannot be thought of as points; instead they are smeared out probability distributions. They don't exist at any given point, there's a chance for a given electron to be found throughout a whole region of space, and the probability of finding it at any given point is given by a probability distribution. These probability distributions are called wave functions, and given an electron's wave function you can calculate the likelihood of getting different results when you take a measurement of the electron. It is a strange aspect of quantum mechanics that you can't calculate exactly what you will measure, you can only establish the probabilities of each possible outcome.

      Another aspect of quantum mechanics is that if you measure, say, the energy of an electron in an atom, you can only get one of a certain set of discrete values, and never any energy in between those values. The energy of the electron is quantized. In general, if you measure an electron's energy you have a certain probability to get a result corresponding to the first energy level, a probability to find it in the second energy level, and so on. This is also the case for some other things you can measure, like angular momentum.

      However, there are certain wave functions that correspond to exactly one value of energy; that is, if you have an electron with this wave function, you are guaranteed to get a certain energy value when you measure it. In fact, there is a special set of wave functions with the following three properties:
      • They each have a definite energy level.
      • They each have a definite total angular momentum around the nucleus.
      • They each have a definite angular momentum around the z axis.

      These wave functions are the atomic orbitals that are so important in chemistry. If you calculate the shapes of the wave functions that satisfy these properties, you get the shapes shown on the Wikipedia page. They are listed in a table indexed by the variables n, l, and m. n corresponds to the energy level, l corresponds to the total angular momentum, and m corresponds to the angular momentum around the z axis. For example, you can see that orbitals with high m (angular momentum around the z axis), like the ones on the very right of the Wikipedia table, are sort of flattened out by the centrifugal force from spinning fast around a vertical axis.

    8. Re:Speaking as a chemist by locofungus · · Score: 4, Insightful

      It's wrong to think of the electron as a particle when it's "orbiting" in an atom. Instead you should think of it as a probability density. This is Schroedinger's cat all over again, the electron is "smeared out" all over its "orbit" but instead of being "half dead, half alive" it's x% here, y% there.

      This is also like the two slit experiment. The electron doesn't go through one slit or the other, it goes through both slits (not 50% dead and 50% alive; 50% went through that slit and 50% went through this slit) but when it hits the phosphor screen it's a particle as its "where is it" probability function collapses to a point.

      The "wavefunction" is (as far as we can tell) a mathematical curiosity that when squared gives us the observed probability function. The probability distribution is real, the wavefunction gives us a convenient handle to calculate probabilities and how they evolve.

      But now that I've said that the wavefunction is an imaginary curiosity, imagine a sine wave on a string and then join the two ends of the string together. There will only be a few discrete lengths of string where the sine wave will "join up" correctly (ok there's an infinite number but the length of the string is limited). It turns out that, with rather a lot of unpleasant maths (see the wikipedia page for spherical harmonics), our wavefunction works like that sine wave and we find that there are only certain orbitals where the wavefunction is well behaved.

      Tim.

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    9. Re:Speaking as a chemist by master_p · · Score: 3, Insightful

      Could it be that we can't pinpoint the exact position and velocity of an electron at the same time because they are interlinked with all the surrounding particles? i.e. the act of measurement affects the outcome.

    10. Re:Speaking as a chemist by radtea · · Score: 2, Informative

      Depends what you mean by real

      By "real" I mean things that obey the laws of non-contradiction and causality, which wavefunctions don't (which is why we see experimental violations of Bell's Inequalities.)

      So I see this argument over whether or not spherical harmonics are "real" kind of beside the point: they are a mathematically useful decomposition of a conceptual artefact that is already ontologically problematic.

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    11. Re:Speaking as a chemist by __aamnbm3774 · · Score: 2, Funny

      damn, the UK is so great. I wish more people actually wanted to move into your country and got the hell out of mine.

    12. Re:Speaking as a chemist by Anonymous Coward · · Score: 3, Insightful

      Based on your previous posts, your lack of education was never in doubt.

    13. Re:Speaking as a chemist by emjay88 · · Score: 2, Interesting

      Yep and if you do an even more elaborate experiment, where you put detectors at each slit, but then wire the detectors up to the same output (ie, the electron is detected, but you don't know which one detected it), the wave function doesn't collapse until it hits the screen!

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    14. Re:Speaking as a chemist by Barterer · · Score: 3, Insightful

      Very informative, thanks. When you say the electrons have a definite momentum about the Z-axis, do you mean just one chosen axis (depending on your perspective and axes you assign) or does it have something to do with which way is "up" or gravity?

    15. Re:Speaking as a chemist by locofungus · · Score: 2, Informative

      No it doesn't because my post explicitly says that the wave function is a mathematical curiosity.

      My post does constantly confuse an electron with the probability function of finding it. But that's because that's the way electrons behave. If anything the probability function is more fundamental so it should be "You constantly confuse the probability function with a hypothetical billiard ball model of the electron"

      The wave function is a mathematical trick that just happens to allow us to calculate the probability distributions we observe. It has no known physical significance whatsoever.

      Tim.

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    16. Re:Speaking as a chemist by brian0918 · · Score: 4, Informative

      You can turn down the beam current in the two slit experiment until you're talking about orders of magnitude less than one electron in the apparatus at any one time on average and you still get the diffraction pattern.

      That's not correct. See experiment and photos here (Figure 2). Single electrons produce single dots. It's only after you dump many electrons through that you get a pattern - that's simply because the electrons follow wave trajectories rather than the standard trajectory visualized from classical motion. In reality everything follows these same wave trajectories, it's just that for macroscopic objects, the individual oscillations of the individual particles cancel out.

      I don't know why it's any more conceptually obvious that a "variable" should be smeared out than an "electron" should be smeared out.

      The phrase "smeared out" conveys nothing, so it should be no surprise that it can be used for situations that are completely different.

    17. Re:Speaking as a chemist by The_Duck271 · · Score: 2, Informative

      The z-axis is arbitrary; you just pick some direction and call it the z direction.

    18. Re:Speaking as a chemist by gribbly · · Score: 2, Informative

      It *is* correct. GP said "less than one electron in the apparatus at any one time on average and you still get the diffraction pattern" which is right. Even if you only ever send one electron through it will be detected in a location consistent with the fringe pattern.

      From the link you included in your reply:

      "Although electrons were sent one by one, interference fringes could be observed."

      You say "Single electrons produce single dots. It's only after you dump many electrons through that you get a pattern" which I think is misleading at best. It suggests that the first electron could be found in a location consistent with classical mechanics. The reality is that from the very first dot you'll be seeing interference effects (this is the heart of the double slit experiment), although it's true it won't *look* like there's a pattern until you've accumulated many dots.

      Anyway, my point is that GP had it right.

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  3. Similar Pictures From Switzerland by Maddog+Batty · · Score: 3, Interesting

    "Leo Gross and his colleagues at IBM in Zurich, Switzerland, modified the AFM technique to make the most detailed image yet of pentacene, an organic molecule consisting of five benzene rings"

    http://www.newscientist.com/article/dn17699-microscopes-zoom-in-on-molecules-at-last.html

     

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    1. Re:Similar Pictures From Switzerland by L4t3r4lu5 · · Score: 3, Interesting

      Your article is much more impressive, IMHO. All I see in the original story is three blue blobs. You could have told me it was false-colour cellular mitosis, and I'd have believed you. I understand that the detail in the story is much higher (imaging one atom instead of a whole molecule) but seeing hexagonal Benzene rings with my own eyes just excites me more.

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    2. Re:Similar Pictures From Switzerland by junglee_iitk · · Score: 3, Informative

      It is anything but similar.
      * That article was about taking picture of big but fragile molecules, even though atoms have been pictures before with ease.
      * This article is about even detailed picture of atoms.

    3. Re:Similar Pictures From Switzerland by Schiphol · · Score: 2, Informative

      Hey, individual orbitals are several orders of magnitude smaller than pentacene molecules.

  4. Why is this significant? by romit_icarus · · Score: 2, Interesting

    The ability to directly measure electron density is quite an old technique. STMs and AFMs have been doing this since the very beginning.. I agree with the researcher's quote in the article that it's good to develop a complementary technique(FEEM) abd at best that's its contribution. I'd be happy to hear what else it contributes. though I don't quite agree with his or the editors spelling! ;) "it's always good to have complimentary approaches,"

    1. Re:Why is this significant? by Genda · · Score: 3, Insightful

      The ability to directly measure electron density is quite an old technique. STMs and AFMs have been doing this since the very beginning.. I agree with the researcher's quote in the article that it's good to develop a complementary technique(FEEM) abd at best that's its contribution. I'd be happy to hear what else it contributes. though I don't quite agree with his or the editors spelling! ;) "it's always good to have complimentary approaches,"

      In this particular application, its simply a very cool thing to be able to prove theory with direct measurement. In the future I can imagine viewing electron orbitals for test samples of high temperature superconductors or producing high resolution images of the electron cloud density for a protein (get a better idea of the quantum component for protein folding) might prove extremely useful and interesting.

      In my experience, no sooner does someone come up with a better device for viewing, then someone comes up with a exquisite need for that device.

  5. Unscaled photo link by UPi · · Score: 5, Informative
    1. Re:Unscaled photo link by PGC · · Score: 5, Funny

      Unscaled, wow. That is one HUGE atom.... no wonder they were capable of photographing it.

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    2. Re:Unscaled photo link by fastest+fascist · · Score: 3, Insightful

      Not to pick nits, but is a picture that is the result of electrons striking a surface actually a photograph?

    3. Re:Unscaled photo link by miro+f · · Score: 4, Funny

      I have embedded the unscaled photos in this post.

      Millions of them

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    4. Re:Unscaled photo link by pclminion · · Score: 2, Informative

      or, we could simply call it a photograph and not worry about what detection and imaging techniques were used.

      I would kind of prefer that we limit the use of the word "photograph" to include images produced by illumination by photons. There's a reason that the imagery produced by electron microscopes are called "micrographs," not photographs. The images are produced by the irradiation of the specimen with electron waves, not photons.

  6. There are other ones by houghi · · Score: 2, Funny

    There are other ones like this one or even the inside of one like here

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  7. Magnification by Butterspoon · · Score: 2, Interesting

    On my monitor, the unzoomed images are about 3cm across. This corresponds to a magnification factor of around 100 million! Awesome!

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  8. It makes me very suspicious indeed. by Kupfernigk · · Score: 4, Informative

    Why? Because the "orbitals" are actually solutions of the Schroedinger Wave Equation. They are images or a probability distribution in abstract space. Electrons are not clouds or points, they are things we don't really understand but describe by means of quantum mechanics. So I am deeply suspicious of the picture, because there is no physical object of that shape to image.

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    1. Re:It makes me very suspicious indeed. by vikhyat · · Score: 3, Insightful

      It's probably like one of those long exposure photographs.

    2. Re:It makes me very suspicious indeed. by Anonymous Coward · · Score: 5, Informative

      The article was extremely superficial when describing the actual experiment, but essentially a current was passed through a small chain of carbon atoms by applying a voltage across the chain. The current caused the the carbon atom at the tip to give off electrons to a phosphor screen. I would suppose that these "given off" electrons were integrated (summed) over time and this formed a pattern that reflected the shape of the probability distribution, i.e. orbital. Each electron that was "given off" constituted a sampling experiment regarding electron position, and the sum total of the samples would, over time, give rise to the orbital shape. In the case of an s orbital, electrons were given off in all radial directions. For the p orbital, certain angles gave off no electrons. This behavior corresponds to the quantum equations.

    3. Re:It makes me very suspicious indeed. by MiniMike · · Score: 2, Funny

      Wait until you've read the paper in Phys Rev B then, it's possible the reporter just put their own spin on it...

  9. mirror by Anonymous Coward · · Score: 4, Funny

    .
    (not actual size)

  10. Re:Picture of story from two weeks ago by PeterBrett · · Score: 2, Insightful

    Here's a picture of a dupe, complete with comments.

    It's not a dupe -- that was a different story, as you would know if you had compared TFA from each story.

  11. Wow by Anonymous Coward · · Score: 4, Funny

    So this is what's powering my netbook!

  12. (do not mod) by aepervius · · Score: 4, Funny

    ignore. Reply done to undo bad moderation

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    1. Re:(do not mod) by machine321 · · Score: 5, Funny

      MOD PARENT UP!

  13. Not quite a of an electron in an orbital by Richard+Kirk · · Score: 5, Informative

    They do look like the classical orbitals, don't they?

    However, there are some problems with interpreting the image as a photograph of an orbital. What the FEEM does is to charge up a very sharp point. The actual voltage may not be very big, but the local field strength depends on screening and curvature, so you can get very large electrostatic fields around sharp features, and if you get the balance right, electrons will leave the sharp points, zoom down the field lines, and get imaged. I remember seeing a sharp tungsten needle in a FEEM back in the seventies, and seeing the individual atoms. This sort of thing provided the first real evidence of a screw dislocation. You got a strange projection of the tip of the needle, as the electrostatic field tended to map the roughly spherical tip onto a flat plane.

    So what is happening here? Our field stripping an electron from the orbital. We are getting a map of the electron flows as focused by the electrostatic field. We calculate the trajectory back through the electrostatic field and guess some sort of map of emission. They must have stripped hundreds or thousands of orbital electrons from the same atom, and replaced them to get each image. However, if an orbital 'pokes out' of the atom, or forms a 'sharp feature' (inverted commas because they are wave functions, so these concepts are a bit hard to define) then we get a bright spot. The really cool bit is getting the atom to go back to the same hybridization state hundreds of times, so we got the two-lobed picture.

    It's dead clever. However, for my money, the atomic force probes are cooler as they can measure the fields without stripping the electrons. But, as the reviewer said, it takes all sorts...

  14. Re:How would this look animated and slowed down? by mattr · · Score: 2, Informative

    Electrons act like both particles and waves, following the laws of quantum mechanics. They are not really like moons traveling around planets in a neat circle.

    I'm not a physicist but my understanding is that each element has a different number of electrons balancing the positive charge of the protons in the nucleus. These electrons form electron shells which are at different energy levels, and the shells are composed of a combination of atomic orbitals.

    Quantum physics says that one cannot know where an electron is until you measure it. The three-dimensional geometric shape of an orbital indicates where the probability is highest that the electron will be found, but it could be just about anywhere. Some orbitals are spherical but others are very different shapes.

    Here are some wikipedia links:

    Atomic Orbitals
    Electron Configuration
    Electron Shells

  15. If you squint... by Drakkenmensch · · Score: 2, Funny

    ... you can see Bigfoot in the background!

  16. Cool by Elwar123 · · Score: 2, Funny

    Atoms are blue. I guess that explains why the sky is blue...it's full of atoms.

  17. Everything is an approximation by rlseaman · · Score: 2, Interesting

    Orbitals are not real ! They are mathematical constructs and they are not observables. People think that just because you can calculate something it is real, that is not the case.

    That a derived quantity is "just" a calculated approximate model of some part of the universe doesn't mean it isn't real. Forget about orbitals and quantum mechanics, consider planetary orbits and classical mechanics. There is no such thing as a closed elliptical orbit as depicted in the textbooks. All orbits are unclosed.

    Physics IS building models. Models are real even if they are incomplete:

    http://www.revell.com/catalog/products/buzz_aldrin_rocket_hero.html

    It may not be Buzz, but it shares the quality of physical existence with him. (And Buzz is himself not the man he was on the Moon.) The absurdity of Moon-landing deniers lies in the fact that each and every one of us spends our entire life embedded in outer space. Where else would be be? The evolving Earth is far more special a place than just another desiccated Moon.

  18. Pity this is AC by Kupfernigk · · Score: 5, Informative

    Thanks for responding. This could do with some mod points but I can't mod and post...so I'll respond. It's interesting to think about what is happening here. It's possibly unhelpful to refer in the same sentence to "current" and "electrons" but I know what you mean, though I would rephrase it a little to help my own understanding. The "current" did not cause the carbon atom to give off electrons; rather, the potential difference enabled some electrons to pass along the carbon chain until they left the tip, and the path of the emerging electrons was probabilitistically interfered with in a way that reflected the solution of the Schroedinger wave equation for the outer electrons of the end atom. That's a very interesting experiment. The benefit of using carbon atoms in a molecule is that the bond angle presumably locks the orientation of the P orbitals sufficiently to enable the experiment. So for many atoms it simply wouldn't work, and what we are seeing here is not an image per se but something more like the result of the Rutherford/Geiger/Marsden experiment. It looks like a significant experiment, but the summary is quite wrong as to what is being shown.

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    1. Re:Pity this is AC by chill · · Score: 2, Funny

      It looks like a significant experiment, but the summary is quite wrong as to what is being shown.

      Dude, this is Slashdot and the discussion is on elementary particle physics. What exactly did you expect?

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