Tracking the World's Great Unsolved Math Mysteries
coondoggie writes "Some math problems are as old as the wind, experts say, and many remain truly unsolved. But a new open source-based site from the American Institute of Mathematics looks to help track work done and solve long-standing and difficult math problems. The Institute, along with the National Science Foundation, has opened the AIM Problem Lists site to offer an organized and annotated collection of unsolved problems, and previously unsolved problems, in a specialized area of mathematics research. The problem list provides a snapshot of the current state of research in a particular research area, letting experts track new developments, and newcomers gain a perspective on the subject."
How can math problems exist before people start using mathematics? Last I checked, math was nothing more than a representation of the hypothetical that as closely models our universe as possible.
Why is it that after taking some, the day after I always get a splitting headache?
Oh wait, math mysteries.
http://en.wikipedia.org/wiki/Collatz_conjecture Speaking of unsolved math mysteries, the 3n+1 problem is a fabulous way to spend days and days of your life. It's particularly fun if you think about it in binary. Whatever the answer is, it's either simple and elegant or complex beyond imagination.
-- IANAL, this isn't legal advice, and definitely isn't legal advice for you. Also, Squee!
I have this wonderful proof for this conjecture, but unfortunately the 80 char limit for sig in slashdot is too small for it.
sed -e 's/Chuck Norris/Rajnikant/g' joke > fact
Julius Shaneson and Sylvain Cappell claimed to have solve a famous problem about counting the lattice points in a circle. It's been out for years, even earlier than this arxiv paper:
http://arxiv.org/abs/math/0702613
Thing is, even though it is a famous problem, no one cares enough to check. So this notion of "famous" is shaky.
So they finally discovered the Merits Of The Bug Tracker.
But i hope they don't switch to math 2.0 anytime soon, that'll just introduce a bunch of regressions and won't do anyone any good. They've already spent some thousands of years just to get their project management straight, it's about time they delivered.
They can probably add the remaining unsolved millennium prize problems to the list.
For very large values of 1
their servers will explode when they take a stab at Navier-Stokes. I asked Wolfram-Alpha, but it simply returned the exact solution of a degenerate case, the solution being 'Fuck you.'
'We are trying to prove ourselves wrong as quickly as possible, because only in that way can we find progress.' RPF
See http://rjlipton.wordpress.com/2009/11/12/more-on-mathematical-diseases/ for unsolved problems which are all really simple and also really addicting to think about. For many of these, the best way to stop thinking about one of them is to start thinking about another.
I'm actually a bit puzzled as to why this is a Slashdot article. If I wanted to point to something new in the way people are doing math I'd point to Math Overflow http://mathoverflow.net/ where many professional mathematicians, grad students and others are active. It is essentially a centralized system for people to post math questions and get math answers from people who know. It is very cool. It also is highly addictive to read.
As of about a year ago, a new kind of collaborative math project known as "polymath" is emerging. These research projects are completely open for any interested scholar to drop in and make contributions to the problem at hand. The technical infrastructure is based on well-known tools such as wikis and forum discussions
The very first such project successfully explored a new approach to the density Hales-Jewett thorem--a significant problem in combinatorics--in about six weeks of effort, with a fully preserved record of about a thousand contributions from dozens of participants.
See Polymath Wiki for the details. This new contribution from the AIM will provide a focus point for such efforts and encourage similar massively collaborative projects.
And of course, the emerging field of computer-verified mathematics is also dependent on massive collaboration, in order to translate existing results into a fully-formalized form that computes will understand and verify as correct. A wiki-based project could be a great help there as well.
why not hide them in video games so we can get more people to look at them.
Only (very) loosely related but deserving mention is the Encyclopedia of Integer Sequences.
This encyclopedia has proven very useful for me in that I have avoided 'solving' many problems with it.
"His name was James Damore."
maybe (AIM) should ask Smarterchild for the answers.
Mathematically modelling the brain would seem to be a very trivial problem. The problem is that there's a lot of brain to model. I've posted (admittedly non-rigorous) mathematical models of the brain on Slashdot before, but narry a grant check from it. Bah.
Computational fluid dynamics for foams, liquid crystals, et al, isn't any harder than for anything else. The equations are chaotic by nature, but chaotic systems can be well-behaved on aggregate under certain conditions. CFD as generally done relies on some specifically hand-picked special case or cases being universally true. They never are, which is why most CFD differs from how systems actually behave in practice.
If you were to treat CFD as a problem in chaos theory, rather than as isolated collections of imperfect examples of special cases, there would be no problem. It is always when engineers try to take shortcuts and oversimplify the maths to make it easy on themselves that they run into problems. They should be locked up for their own safety. If you want to really annoy them, lock them up with some airgel foam.
The problem with chaotic systems is that the system is sensitive to initial conditions, which means the only way to get "correct" results is to use infinite precision and zero step sizes. This isn't useful, but is a good way to annoy experts in CFD.
This leaves two options - use very very big, very very fast computers (the option used by F1 teams), or find an equivalent problem you CAN solve (the idea behind transforms).
Ok, does chaos look like a good place to use transforms? If you could identify and classify the Strange Attractors in the system, can you do anything useful? Probably not, at least not in the "solving the problem" sense. Chaos is fully deterministic, but it is utterly unpredictable. The only solution is the whole solution.
What knowing the Strange Attractors might tell you is how to vary the precision and step-size to get the best results for a given level of compute power. But it's going to be all raw horsepower from thereon out.
The best way to invest money on such work is to design a co-processor that performs a handful of fairly high-level maths functions directly (optimized purely for speed, not physical or logical space) so that you can do Navier-Stokes almost at the level of raw hardware rather than through clunky software. Then cluster the living daylights out of the co-processor.
It's necessary to optimize commodity hardware for space, because chip real-estate is expensive. However, if you're building what is basically a SOP (single-operation processor) for a dedicated market that can afford things like Earth Simulator, the only time you care about space is when it impacts speed.
Ideally, if the speed of light wasn't an issue, you'd want each bit in the output to be produced by wholly independent logic, duplicating the input bits as necessary to accomplish this. In practice, you'd probably want to start with that conceptually but in reality have something that was somewhere between that and a highly compressed form. Too parallel and the delays in communication exceed the benefits from the parallelization.
But this is all obvious. Anyone here who has done multi-threading or any other form of parallelization knows about synchronization issues and communication overheads. It's even one of the biggest chunks of any course on the subject of parallel design. There's nothing new there, certainly nothing "unsolved".
But, yeah, a well-designed Navier-Stokes co-processor would likely give you greater accuracy and greater performance than the modern pure software solutions. Especially those using ugly protocols to do the communications.
If Intel can conceptulalize 80 Pentium 4 cores on a wafer, it would seem reasonable enough to imagine modern fabrication methods being able to put at least a couple of hundred dedicated Navier-Stokes processors into the same space. Since the input for an iteration would be based on output from that and other processors, there's no
It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
So when a promising idea comes along, the "expert" can follow up and hopefully get credit for the solution. I see this is the workplace and on the net in various places. Technical discussion forums are lurked by "experts" in industry who look for ideas without contributing anything to the discussion. Some people don't mind, others don't realize, and others are bothered by it.
I am pretty sure that some of the problems at least will be Hilbert Problems that do not currently have a solution. http://en.wikipedia.org/wiki/Hilbert_problems
Did Glenn Beck rape and kill a girl in 1990? gb1990.com
This is a great idea. It whould promote more interest in the specific problems and unsolved math problems in general. Besides, more collaboration should result in better research.
Loban Amaan Rahman ==> Anagram of ==> Aha! An Abnormal Man!
There exist no empty sets in the Universe! We can construct all of Mathematics beginning only with the Empty set. So, all of mathematics can be constructed from something that does not exist in the real world. Hmm? Makes you think.
Over-the-top Response Guy! Giving "Over-the-Top Responses" since 1970.
Those things which we use mathematics to describe (relationships of every variety) are discovered (by observation and experience)
The language with which we describe them (symbols, axioms, and rules of transformation) is invented (and refined over time, as a quick review of the history of mathematics will promptly reveal)
Additional products of this language (logical consequences of the axioms we have invented) are subsequently discovered.
We equivocate the term "Mathematics" to mean all three of these things (that described, the language of description, and logical consequences of the axioms of that language). When the word means all three of these things at once, it seems that we have both discovered and invented it, and lively (though misguided) debate ensues.
When we establish clarity about our topic of discussion (through disambiguation of our terms), then whether it was invented or discovered becomes clear, as I have just demonstrated.
42
can we get the good will hunting guy to work on them or rainman. may even Kazan?
Why is the alternative to halving, 3n+1? Why 3? I'm curious. If it were just n+1 it seems like it would converge to 1 pretty quickly (since most non-even numbers become even if you add 1).
10 gives you:
10 5 6 3 4 2 1
100 gives you:
100 50 25 26 13 14 7 8 4 2 1
What if it were 4n+1? Then 10 gives you:
10 5 21 85 341 1365 5461 21845 uh oh
What if it were 5n+1? Then 10 gives you:
10 5 26 13 76 38 19 96 48 24 12 6 3 16 8 4 2 1
Build a man a fire, he's warm for one night. Set him on fire, and he's warm for the rest of his life.
I think the more interesting question is why people would ever think that 1 is not equal to 0.999...?
I mean, what do they expect to find in between?
(Disclaimer: I am one of them Math "teachers", I suppose)
-- open source? sounds like the real book --
That is not entirely correct.
First strange attractor is usually embedded into lower-dimension manifold. Reducing dimensionality can make problem a lot more tractable, especially if original system was infinitely-dimensional (like Navier-Stocks). Estimation of dimensionality of that manifold or any other information about it can help a lot in numerical simulation.
Second strange attractors have non-trivial statistical properties and specific geometry. Exact solutions is not always the target of calculation, statistical properties or averages of solutions, or its geometrical properties could be target of calculations too.
That is probably more potential that practice for now. While I've read paper (long ago) about statistical (ergodic theory) and algebraic-geometrical approach to Lorentz attractor I don't know if there are any works on dimensionality or statistical properties on attractors of other "real world" systems.
1^0 = 1
1^1 = 1
hence 1^0 = 1^1
taking log to the base 1 from both sides,
0 = 1
by extending to 1^2, 1^3 etc...
0 = 1 = 2 = 3 .....
Let's try this...
Start with:
a = 0.999...
Multiply both sides by 10 to get:
10a = 9.999...
Subtract the first equation from the second:
10a - a = 9.999... - 0.999...
9a = 9
a = 1
Substituting back into the original equation:
a = 0.999...
1 = 0.999...
Who's the retard?
I void warranties.
P = NP?
I so want it to be true. Quantum computing is our best hope right now of shedding light on this problem.
And it's not on their list...
I void warranties.
Ok, I would agree with all that. (I can't mod you informative for obvious and non-chaotic reasons.)
It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
galois theory can be used to show that some constructions do not exist. for example, it is impossible to trisect an angle in general by using a straight edge and compass in a finite number of operations (although 180degrees can be trisected by constructing three 60deg divisions). it can also be used to show that there are fifth order polynomials that have root that cannot be expressed using a finite number of the operations addition, subtraction, division, multiplication and taking powers/radicals. these roots are real (or complex numbers) that cannot be constructed using the conventional mathematical operators a finite number of times.
similarly you cannot construct a 7 sided polygon. its quite interesting to think about the nature of these truths. that you can show that something is impossible, is not constructive. when you have a constructive proof it is easy to see when the answer is correct. but to verify these proofs is more subtle and requires considerable thought and time. you could expect to look at galois theory towards the end of a degree in mathematics, but how many people can dedicate the time and effort required. how can they trust that these assertions are correct. how we enable trust in such non obvious truths.
My immediate response to that would be that 9.999... != 10 x 0.999... . I'm not sure exactly how to explain it though, other than "you just added 9, you didn't really multiply by 10 because it is "impossible" to do so due to 0.999... having an infinite amount of decimals."
I'm not a math teacher though, so what do I know.
Let x = sum(n=1..inf) 1/10^n = 1/10 + 1/100 + 1/1000 + ... = 0.111... ... = 0.999... ... = 1 + (1/10 + 1/100 + 1/1000 + ...) = 1.111... = 1 + x.
Thus 9x = 9 * sum(n=1..inf) 1/10^n = sum(n=1..inf) 9/10^n = 9/10 + 9/100 + 9/1000 +
and 10x = 10 * sum(n=1..inf) 1/10^n = 10/10 + 10/100 + 10/1000 + 10/10000 +
In other words: what's 10x - x? Answer: (1 + x) - x = 1. Therefore 9x = 1, so x = 1/9, and 9 * (1/9) = 0.999... = 1.
Alternately, 10x = 10x = 9x + x = 0.999... + x, yet above we see that 10x = 1 + x, so 9x = 0.999... = 1, also.
is why there never is enough money in my account... --- Shawn Way...
This is a common misconception. 0.9999... is EXACTLY the same as 1, they're two representations for the same number. This can be proved in a lot of ways, the most basic being that if 1/3 = 0.33333..., then 3 * 1/3 = 1 = 0.999... Another way is, if these two numbers are not equal, what's the distance (difference) between them? Can you find it?
More info here
The problem is your failure to understand infinity.
You can easily see that 0.123 * 10 is 1.23, right?
Well, just because I multiplied by 10 and brought one of the 9's over to the left side of the decimal, there's still an infinite number of nines on the right side.
Even though I "borrowed" a 9, infinity - 1 is still infinity.
I void warranties.
Semantics != Mathematics
.999 if your frame of reference is 1 second and the value you are measuring is the speed of light.
.999 inches might as well be the same thing.
.999 is irrelevant then there for all practical purposes is no difference. However if your scale is wrong then those repeating decimals make a big difference.
There is a lot between 1 and
If you are measuring the length of a shoelace in inches then 1 inch and
Really if you just change the frame of reference and name your units something so that
The problem is you can't add and sting of infinitely long #'s.
.333 repaint for ever does not = 1/3. You can't ever convert 1/3 into decimal form. We pretned we can and then then we make 1/3 EQUAL to .333 with a line over it. Well, of course if you add 3 of those representations you get 1. 1/3 + 1/3 + 1/3 =equals one.
.999... equals one falls apart is EVERY OTHER # system.
.3 and in 9s .3 + .3 + .3 = 1!
.999 in HEX and guess what .999.. does not equal 1, but you can do you magic on .fff... which looks like it equals one.
.999.. equals one, which is 9/10th +90/100 = 900/1000th.
.fff... which is 15/16th + ......
.555... = 1
.666... = 1
.777... = 1
.888... = 1
.999... = 1
.aaa... = 1
.555... really equal one because that little trick works in BINARY!?!
.888... (i.e. 8/9) perfectly in binary.
.999... go to a # system with more precision like the 11s, 12,s etc and you can then represent .999...
.3 with a remainder of !!!! 1/3!!! You're back were you started.
.333r1/3 . That r1/3 is there wherever you stop.
.333r1/3 + .333r1/3 + .333r1/3 = .999r9/9 which of course is 1..
.333... and do math to it. It's impossible. If you pretend it is .333r1/3 then you can and .333... +.333.. repeating is really .333r1/3 +.333r1/3 = .666r2/3.
.3333333.... of a pie. You can't because they are not the same thing.
Where your little
If you go to the 9s number system 1/3 =
Try doing you LITTLE MAGIC show of
But you said
But in hex you have
Where it really starts to fall apart is in # systems that have less room/precision.
Start doing your "fancy math" in BINARY.
Does
Hell, no, it means you plain CAN'T represent
So same with
Other wise you are just doing divison from 3rd grad. 3 goes in to 1.0000 , you get
So 1/3 in decimal is really
The fact that you can't realize just putting a line over it means r1/3 is sad. Of course the real representation of 9 repeating after the . litteraly just means keep moving (adding) 9/10th closer than the last power of ten.
You can't take an infinitly long # like
Try it. In decimal take 2 and divide by three. You always will have 2/3 left. You can't magically get rid of it by a line.
Try to cut a 1/3 of a pie. Now try to cut
I always respected my engineering friends in college who were busy solving complicated problems. I was a humanities major, so I was far more interested in solving this math problem with the hot chicks in my social sciences classes: let's add ourselves together, subtract our clothes, divide our legs and multiply.
10a - a = 9.999... - 0.999...
There's your problem. What makes you think you can take an infinitely long number and ADD or SUBTRACT it to another infinitely long number?
Please work out the whole addition sequence for me till you reach the end.
Thanks,
Reality
P = NP
P/P = NP/P
1 = N
Is 1563649 a prime number?
You claim that 0.555... = 1?
Let's do my "fancy math" and see what it equals...
a = 0.555...
10a = 5.555...
10a - a = 5.555... - 0.555...
9a = 5
a = 5/9
Convert 5/9 to a decimal and you get 0.555...
So your arguement that 0.555... = 1 is wrong.
Once again, you fail to understand the nature of infinity.
I void warranties.
10a - a = 9.999... - 0.999...
There's your problem. What makes you think you can take an infinitely long number and ADD or SUBTRACT it to another infinitely long number?
http://en.wikipedia.org/wiki/0.999
http://www.straightdope.com/columns/read/2459/an-infinite-question-why-doesnt-999-1
Algebra
Calculus
et alii ad infinitum...
I void warranties.
2nd did you RTFA you posted from Wikipedia!?! It shows all the "Mystical" ways people try to show
Since you didn't read it I'll quote it for you,
Breaking subtraction
Another manner in which the proofs undermined is if 1 - 0.999... simply does not exist, because subtraction is not always possible. Mathematical structures with an addition operation but not a subtraction operation include commutative semigroups, commutative monoids and semirings. Richman considers two such systems, designed so that 0.999... < 1.
And look at the second article, it states the same false crap, 1/3 = .333~ no, 1/3 does not equal .333~
.333~
.333~ You never make a cut, because you you move 3/10 or the way around the pie from where you start, then you start to slice, OH WAIT, you need to move 3/100 further, now you get ready to cut again, OOOPS wait, you need to move 3/1000 closer now, get ready to cut, HOLY CRAP you need to move again.
.3 In the nines number system I can cut .3 or 1/3 of a pie. But gues what!?! There is no way to represent 1/4 in the 9s number system. 1/4 in 9s is .2222~ You can't represent 1/4 in 9s number system. It would be absurd to try. Just like it is absurd to try to represent 1/3 in Decimal. 3 WILL NEVER divided 10 or any power of 10, ever. Then just putting a line over it and going well, .333~ is "close enough" lets multiply by 3 and get 1.
You can "say" it does and then add three together and say 1!!!
That's like saying, I'll let 1/3 = 4. So, 4 + 4 + 4 = 1 1/3 should not be represented by 4 anymore than it should be represented by
Cut a pie. You can cut 1/3 of the pie slice. Now cut a pie in
This is like using the 9s number system. 1/3 =
In said convertered to BINARY ! .5 = 5/10th = 1/2 .1
.111~
.111~ = 1
.999~ = 1 then in binary .111~ equals one.
.fff~ will equal one with your flawed math.
.333333~ There is no way to represent 1/3 in Decimal. If you go to the 9s number system, 1/3 is represented very well, .3
.999~ is really tricking yourself. Look again at 1/3. Dived 1.000 by 3. You always have a remainder 1/3. That is one third of the last value you stopped at.
.3 with a remainder of 1/3 of a tenth. Now instead of just saying it's 1/3 of a tenth left over we stick a bar over the 3. Problem is when we add .3 with a bar over it we are in essence adding the 1/3. Hench .3 with the 1/3 of a thenth remainder. So you when you add .333~ plus .333~ what you are doing is getting .666~ r2/3
Now the bar = r2/3
.1111 r1/9
2/9 you get .2222 r2/9
.3 r1/3 + .3 r1/3 + .3 r1/3 = .9 r3/3 , that's 3/3 of a tenth which is one whole tenth so it's .9 + r.1 so =1
.9 r9/9 .9 r9/9 === all you are doing is taking 10-1.
.999999 to infinity. You are literaly saying keeping going closer, but NEVER touch one. Then to say it touched one contradicts what you meant it to mean.
.999~ is being molested into rounding your fraction off.
.1111~ = 1 or in trinary .2222~ = 1
.ddd which approaches one much faster than .999 in decimal. However, in HEX at .fff~ you do the same thing if you are trying to add it you are really adding .fff rf/f .
.333~ is not 1/3.
In Binary that is
So in binary
If I do you magic math IN BINARY.
Binary, Trinary, etc this all happens. You can do it with any # system. Each one you get closer to 1. So if in decimal
This happens in every number system. Go to hex and
Again this is because you can't represent certain numbers in certain # systems. 1/3 !=
What you're doing by saying
So for example. 3 into 1.0, I get
Hence when you do this with: 1/9 you get
You are just treating the remainder as r3/3 or r9/9
So x =
10x = 9 r9/9
10x - 9x = 9 r9/9 -
So you are letting the line over it be a whole. This different then saying
This happens in every # system. Except it the amount of error is worse the small the # system. Like binary, where
The same thing happens when you use number systems with MORE precision than 10s, like HEX, you get
Basically just sticking a line over something that can't be converted is not logically. I can't write 1/3 in decimal.
High school students begin posting math homework problems there.
Have gnu, will travel.
I said I'd never reply to an AC on this topic, but this one is being particularly bad, so I have to do it.
Yes, .111~ in base 2 is 1. And .222~ in base 3 is 1. Incidentally, .111~ in base 2 = .222~ in base 3 = .999~ in base 10. There is no difference in precision, and it's silly to even suggest. It indicates that you are not thinking in infinity, and that you believe an infinitely repeating decimal has an end point.
First, note that .111~ in base 2 and .222~ in base 3 and .999~ in base 10 and all other similar cases share a similar sum: $\sum_{n=1}^\inf (r-1)(\frac{1}{r})^n$. This is a geometric sum starting with n=1, so we can quickly find the sum to be $\frac{(r-1)}{1-\frac{1}{r}} - (r-1) = \frac{(r-1)}{\frac{r-1}{r}} - (r-1) = r - (r-1) = 1$, so, yes, this "trick" does work in every base.
Your problem is that you are thinking of the number .999~ as a process, when it's really a set number with an infinite number of decimal places, just like every other decimal number (the fact that some numbers have most of their fractional digits be 0 doesn't mean they don't exist or that you can ignore those digits).
Of course, the multiply-by-10-and-subtract proof is just a quick and easy-to-understand proof. I much prefer using some concepts from real analysis, but they would clearly go over your head.
Remember, open source is free as in speech, not free as in bear.
2nd did you RTFA you posted from Wikipedia!?! It shows all the "Mystical" ways people try to show .999~ = 1 and then GOES ON to show IT DOESN'T!!
Actually, it shows that it is true, and then goes on to show constructions people specifically to make it not true. In fact, your "breaking subtraction" quote specifically states that it was part of a construction intended to make .999~
And look at the second article, it states the same false crap, 1/3 = .333~ no, 1/3 does not equal .333~
You can "say" it does and then add three together and say 1!!!
That's like saying, I'll let 1/3 = 4. So, 4 + 4 + 4 = 1 1/3 should not be represented by 4 anymore than it should be represented by .333~
Except that the equivalence 1/3 = .333~ is provable and 1/3 = 4 isn't (in our usual system). Other than that huge fact, yeah, they're exactly the same.
Cut a pie. You can cut 1/3 of the pie slice. Now cut a pie in .333~ You never make a cut, because you you move 3/10 or the way around the pie from where you start, then you start to slice, OH WAIT, you need to move 3/100 further, now you get ready to cut again, OOOPS wait, you need to move 3/1000 closer now, get ready to cut, HOLY CRAP you need to move again.
Except numbers don't work that way. The number .999~ is a specific number, one which we can define in terms of a process or sequence if we wish, but it is not that process or sequence itself. If I want to cut .333~ of a pie, I'll make my first cut and then move .333~ of the way around the pie and slice. Incidentally, if I start from the same 0 point, this slice will be identical to the one I'd make if I went 1/3 of the way around the pie.
Really, the only way I'd agree with you that 1/3 != .333~ in decimal is if you complained that 1/3 is integer division and that 1/3 is really 0, but then we're just being silly.
Remember, open source is free as in speech, not free as in bear.