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The Moon's Gravitational Pull Can Trigger Major Earthquakes, Says Study (nature.com)

schwit1 writes: A careful statistical analysis of when major earthquakes occur has suggested they are more likely to be more powerful if they occur around the full and new moons when tidal forces are at their peak. Nature.com reports: "Satoshi Ide, a seismologist at the University of Tokyo, and his colleagues investigated three separate earthquake records covering Japan, California and the entire globe. For the 15 days leading up to each quake, the scientists assigned a number representing the relative tidal stress on that day, with 15 representing the highest. They found that large quakes such as those that hit Chile and Tohoku-Oki occurred near the time of maximum tidal strain -- or during new and full moons when the Sun, Moon and Earth align. For more than 10,000 earthquakes of around magnitude 5.5, the researchers found, an earthquake that began during a time of high tidal stress was more likely to grow to magnitude 8 or above." As these results are based entirely on statistical evidence, not on any direct link between tidal forces and actual quakes, they are quite uncertain and unproven.

130 comments

  1. Nuke the Moon? by Anonymous Coward · · Score: 0

    Well fuck the moon then, nuke the shit out of that rock.

    1. Re:Nuke the Moon? by Calydor · · Score: 2

      Video blocked in Germany for copyright reasons. Yay free world.

      --
      -=This sig has nothing to do with my comment. Move along now=-
    2. Re:Nuke the Moon? by Tablizer · · Score: 1

      Trump: "I'll blow the damned moon out of the water! The moon doesn't respect USA, it keeps mooning Obama."

  2. Article is garbage by Anonymous Coward · · Score: 0

    The article doesn't say how much more likely major earthquakes are. For a large sample, even small differences are statistically significant and will result in very low p-values. For that reason, statistical significance doesn't necessarily indicate that the result is actually meaningful.

  3. fucking BS headlines by Anonymous Coward · · Score: 1

    "The Moon's Gravitational Pull Can Trigger Major Earthquakes, Says Study".
    No the fucking study does not say that at all, it says their is some correlation between the tidal stress and the size of earthquakes.

    1. Re:fucking BS headlines by doccus · · Score: 1

      Perhaps.. but it's hardly "breaking news" either. In fact it HAS been shown years ago now that the moon can *trigger* earthquakes during full and new moons. Land tides are hardly a newly discovered phenomenom . So a study that says the moon has an impact on the size of quakes is simply another stiudy to bolster evidence of the moons influence. But..... :yawn: When we have that nasty EQ here in the pacific NW maybe I'll look up at the moon..while the tsunami wipes out everything lower than 300 feet... :-(

  4. It's the Sun, actually by czert · · Score: 5, Interesting

    Well, it's actually the added stress from the Sun's alignment with Earth and Moon that's likely to play the major role here. The Moon itself doesn't do anything special during the full and new moons.

    1. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      Also, why would the moon's gravitational pull be at a peak at full moon?

    2. Re:It's the Sun, actually by Anonymous Coward · · Score: 0

      Maybe this is also the reason people go loony during a full moon.

    3. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      Sun of a bitch!

      But we all agree 'New Moon' was awful, right?

    4. Re:It's the Sun, actually by Anonymous Coward · · Score: 0

      Nope. The moon makes the tides. Moving that much water changes the stresses on the plates... Try again.

    5. Re: It's the Sun, actually by bytesex · · Score: 2

      The moon is heavier when it shinest brightest, didn't you know that? Those photons don't weigh nothing, you know...

      No, actually, it has something to do with the position of the moon and the sun, and how that both creates the optimal conditions for gravitational pull, and gives it the most exposure to the earth. Think, young Anakin, think!

      --
      Religion is what happens when nature strikes and groupthink goes wrong.
    6. Re: It's the Sun, actually by therealkevinkretz · · Score: 5, Informative

      During full and new moons, Sun - Earth - moon ( or Sun - moon - Earth ) are aligned in a line. That's when their combined tidal forces are at a maximum

    7. Re: It's the Sun, actually by silentcoder · · Score: 1

      Just to pick a minor nit. Photons really don't weigh nothing. They lack mass. But they do have weight. Weight is the force of gravity on something - gravity affects light (hence we get things like gravitational lensing) ergo - light has weight.

      --
      Unicode killed the ASCII-art *
    8. Re:It's the Sun, actually by silentcoder · · Score: 1

      Nah, that's PMS. There are more than enough people in the world, with cycles that are the same average length as the lunar cycle, that a significant number will end up correlating with it. Hence - crazy people at full moon.

      Okay, so I just made that up but it's actually entirely possible. Much like the high incidence of autism diagnosis immediately after vaccination can be entirely explained by the high number of people getting vaccinated every day and the fact that autism first becomes diagnosible at around the same age - which means every day there is going to be a signficant number of people with as-yet-undiagnosed autism getting their vaccinations. Thousands actually.

      --
      Unicode killed the ASCII-art *
    9. Re: It's the Sun, actually by michelcolman · · Score: 5, Informative

      It has nothing to do with the total amount of gravitational pull.

      Tidal stress is the difference between the amounts of gravitational pull at different distances. If you are floating in space near a massive object (planet, star, moon), with your feet pointing towards it, your feet will be closer to it and will therefore experience more attraction, while your head will be further away from it and therefore experience less attraction. This will tend to stretch your body a little bit (or a whole lot if you happen to fall into a black hole). If the gravitational gradient is strong enough, it will make your hair stand up. Your entire body is actually accelerating towards the object, but your feet are being pulled harder while your hair gets left behind. Relative to the pull on your gravitational center, it feels like there are two forces pulling at you from opposite sides trying to tear you apart.

      On earth, that means there's a high tide on the side of the moon (closer to the moon, therefore attracted more to it) but also on the other side (further from the moon, therefore attracted less and bulging the other way). The effect is the same on both sides because it's not the amount of attraction that matters, but only the difference with the attraction experienced by the earth's center.

      The sun also creates a similar effect, though smaller.

      When the sun and the moon are either on the same side (new moon) or on opposite sides (full moon), the two effects are added together and you get spring tide. And, apparently, possibly more or stronger earthquakes.

    10. Re:It's the Sun, actually by Anonymous Coward · · Score: 0

      I think you need to understand a bit more about the difference between lunacy and hysteria.

    11. Re: It's the Sun, actually by mysidia · · Score: 1

      During Full moon, the maximal area of alien death rays from the sun are reflected off the moon towards earth, and during new moon, the moon is not in place to absorb any of them, so they hit earth directly.

    12. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      During full and new moons, Sun - Earth - moon ( or Sun - moon - Earth ) are aligned in a line. That's when their combined tidal forces are at a maximum

      Are you sure you're not thinking of eclipses?

    13. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      Bill O'reilly would like to have a word with you about God. His miracles cannot be explained by simple science.

    14. Re: It's the Sun, actually by tomhath · · Score: 3, Informative

      They're usually not quite lined up due to the inclination of the Moon's orbital plane relative to the plane of the ecliptic, but they're close enough. An eclipse happens occasionally when the Moon lines up exactly with the Earth and the Sun.

    15. Re: It's the Sun, actually by Anonymous Coward · · Score: 2, Informative

      Just to pick a minor nit. Photons really don't weigh nothing. They lack mass. But they do have weight. Weight is the force of gravity on something - gravity affects light (hence we get things like gravitational lensing) ergo - light has weight.

      I can't tell if you're joking, so I'll assume that others may not be able to tell either. Light doesn't have mass, but it does have momentum. It does not "weigh" anything. Gravity bends spacetime, and the path light takes can also be bent.

      If you were joking, well played. Carry on.

    16. Re:It's the Sun, actually by gtall · · Score: 1

      i thought autism diagnoses spiked when some blond bimbo got significant TV airtime...I guess you learn something new every day.

    17. Re:It's the Sun, actually by Applehu+Akbar · · Score: 2

      A 'land tide' of about one meter corresponding to the ocean tides has been noted for years, and so has been the effect on earthquakes.

    18. Re:It's the Sun, actually by silentcoder · · Score: 1

      Correction: I did the math based on the working days in a year, but the actual period of overlap is only six months - so you have to cut the divisor in half, which means that, in fact all the coincidences become twice as common, so it's 36000 exact coincidences per year - and the others change the same way.

      --
      Unicode killed the ASCII-art *
    19. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      It would also depend on the angle of the fault line, and the actual configuration of whatever was causing the stress build up. Whether it's one plate of solid granite or basalt sitting on top of another or sliding past each other.

    20. Re: It's the Sun, actually by tinkerton · · Score: 2

      i think he means it the other way round. If you have a sphere filled with light, the light will add to the gravity of the sphere. For calculating the mass of the sphere you need the amount of energy inside and you don't need the details about what kind of energy it is.

    21. Re:It's the Sun, actually by Anonymous Coward · · Score: 0

      This.

      Saw the headline and thought "but we've known this for years".

    22. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      The fuck is this +5 Informative? It's plain wrong.

    23. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      #blackenergymatters.

    24. Re: It's the Sun, actually by Aristos+Mazer · · Score: 1

      Actually, it is exactly right. When moon is opposite side of Earth from sun (full moon) it pulls opposite the sun, stretching Earth. When it is on the same side as the sun (new moon), it adds maximally to the sun's own pull.

    25. Re:It's the Sun, actually by angel'o'sphere · · Score: 1

      That is probably the dumbest comment ever.
      And it even got modded up by even dumber moderators?

      Well, it's actually the added stress from the Sun's alignment with Earth and Moon
      The sun is always there. The sun does not add anything.

      The moon is adding its weight to the pull of the sun, either by _adding_ and pulling in the same direction like the sun if the moon is between earth and sun, or by _pulling opposite_ of the sun when the moon is on the opposite side.

      The Moon itself doesn't do anything special during the full and new moons.
      Yeah, dumb ass. I'm lucky you are not a sailor and have to sail in the northern sea, for example. You would not get very far with such moronic lack of basic understanding of physics.

      Why did you actually post? To make a fool of your self or to show that there are bigger fools that even would mod you up?

      --
      Cost free eBook I read (by iBook/Kobo/Amazon/ObookO/Gutenberg etc.): "The Green Odyssey" by Philip Jose Farmer.
    26. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > The effect is the same on both sides because

      FYI you are disseminating incorrect information and need to re-read your tidal theory.

    27. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      AC who asked the seemingly naive question here. Since i was in transit, i couldn't really look it up earlier. My questions slightly implied, whether the moon would be closest to earth during full moon, which apparently it is not. Here's a chart from 2014

      Also the ellipsis rotates around earth with almost 9 years for a full rotation

      So the full/new moon idea appears not to give, to quote you, optimal conditions for gravitational pull

      This was a valuable lesson, master. The source turned out once again to be a great ally ;)

    28. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > On earth, that means there's a high tide on the side of the moon (closer to the moon, therefore attracted more to it)

      That is actually complete nonsense (even though you may have been told that in school). The Moon does _NOT_ 'suck the tide up'*. The first thing to understand is that the Moon does not obit the Earth. They both orbit their common centre of gravity which is a point away from the centre of the Earth (but still inside the Earth). This means that there is a centrifugal force which is greater on the side of the Earth away from the moon than it is on the side towards the moon.

      The gravity of the moon acts on every cubic mile of the earth with a difference that is completely insignificant (c/f inverse square law). By resolving the centrifugal effects of the earth-moon rotation and the gravitational effects at the earth's surface the result is that there is a maximum effect at the sides of the earth (ie the moon around the horizon) with a roughly horizontal pull. The tides move _horizontally_.

      Whether the high tide coincides with the moon being overhead or not is dependent _entirely_ on where you are. New Zealand is roughly north-south and yet at any tide there is one point where the tide is high, and another where it is low. The tide circulates around the country and joins 3 large 'wheels' that lie across the south pacific, the high tides are spokes of these 'wheels' which engage like gears.

      * if the moon did 'suck up the tide' then a pressure gauge at the bottom of a swimming pool would vary depending on the position of the moon - it doesn't.

    29. Re:It's the Sun, actually by Anonymous Coward · · Score: 0

      Note that one of the bigger Fools was Galileo. He attributed the Tides to Earths rotation while orbiting the Sun, and that the Moon had little or no effect. This was part of his proof for the Copernican System in the "Dialogue" that got him in so much trouble with the Church; that and ridiculing the Pope.
      Note that Galileo's arguments were logical and well thought out. But they were still wrong.

    30. Re: It's the Sun, actually by michelcolman · · Score: 1

      No, I'm sorry, but your theory with centrifugal forces is completely wrong.

      First of all, you need to realise that centrifugal forces are not real forces but pseudo-forces that only show up when you are using an accelerating reference frame. If, for example, you take a turn with your car, the tires are making the car turn (providing centripetal force towards the center of the turn) while your body does not receive that force and wants to go straight ahead. This feels like a force that pushes you to the outside of the turn, but that's only because you are using the car as your reference frame. If you take the road as the reference, your body is merely continuing its straight trajectory until it hits the inside wall of the car which is taking a different, curving trajectory.

      Now, if the turn is not caused by the friction of the tires but by some sort of gravitational force (like, for example, the ISS orbiting the earth with a centripetal force of almost 1g), you will not feel any centrifugal force. The bodies of the astronauts receive the same gravitational acceleration as the space station so they feel weightless relative to the ISS. If you would spin the ISS at the same distance with a rope instead of the force of gravity, the astronauts would be pinned to the outer side with a centrifugal acceleration of almost 1g.

      The earth is indeed orbting the common center of gravity of the moon-earth system (which is inside the earth). If it were orbiting that point because it was attached to it by some fourth-dimensional pin that forcibly made it orbit that point, then yes, you would get centrifugal forces if you took the earth as your reference frame. But this is not the case: it is not orbiting that point because it is attached to it, but rather because the moon is pulling it towards it.

      Now here's the contradiction in your theory: IF it were true that the moon was exerting "the same amount of gravity on every cubic mile of the earth with a difference that is completely insignificant", then that would result in no centrifugal force whatsoever. Just like the astronauts feel no centrifugal force in the ISS.

      In reality, there IS a significant difference between the moon's attraction on both sides of the earth. A quick back-of-the-envelope calculation, using the moon's average distance of 384400 km, its radius of 1737.1 km, its surface gravity of 1.62 m/s^2 and the earth's radius of 6371 km, gives me about 33 micron/s^2 at the center of the earth, 32 micron/s^2 on the far side of the moon, and 34 micron/s^2 on the near side. That may not seem like much, but since it's a steady force continuously revolving around, it's enough to keep a mass of water moving around the planet.

      Of course the water moves horizontally. The water in the tital bulges comes from the sides, where else would it come from? I agree with you on that bit.

      And yes, there are local scenarios where particular coastlines and ocean depths change the tides so they happen a bit earlier or later. But that does not change the fact that the major force driving the tides is simply the gradient of the moon's gravitational field.

      By the way, gravitational gradients are enough to tear apart asteroids passing too close by Jupiter. You would think that, on an asteroid only a few km across, the difference in attraction to Jupiter on both sides would be completely insignificant. But apparently it's enough to tear rocks apart.

    31. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > IF it were true that the moon was exerting "the same amount of gravity on every cubic mile of the earth with a difference that is completely insignificant", then that would result in no centrifugal force whatsoever.

      You are confused. The fact that the 'pull' of the moon is almost equal on every cubic mile of earth is a direct result of the inverse cubelaw where the gravitational 'pull' is related to the distance from the mass. The difference between the distance from the moon to the near side and to the far side is very small relative to the distance from the moon, thus the gravitational effect of the moon on each part of the earth is almost the same.

      There is a centrifugal force caused by the earth spinning on its axis. If you spin a rock on a string then the string gets taught as you pull the rock into a circle. The same happens to the surface of the earth as gravity pulls each piece of the earth into a circle. As the magnitude of this force depends on the distance from the axis, this force pulls the earth into an oblate spheroid where the equator is about 7 miles 'higher' than it would be if the earth was a non-rotating sphere.

      http://earth.rice.edu/mtpe/geo/geosphere.html

      The earth is also rotating about a point approx 5000km from its main axis every 28 days or so due to the earth-moon rotation. If one were to replace gravity by a string between the centre of the earth and the moon then from that rotation point the tension in the string would be equal each side. In other words the mass of the earth would exert a 'centrifugal' force by being rotated about that common centre of gravity which is 500km from the centre of the earth. Each part of the earth would have a different amount of this 'force' depending on the distance from that rotation point, some would be acting towards the moon, most of it away. At that

      > And yes, there are local scenarios where particular coastlines and ocean depths change the tides so they happen a bit earlier or later. But that does not change the fact that the major force driving the tides is simply the gradient of the moon's gravitational field.

      Just because they taught you a simplistic view just not mean that is all there is (unless you are a flat-earther). There is almost zero 'gradient' to the moon's gravitational field over the tiny difference that is the diameter of the earth relative to the earth-moon distance - do the maths. There is a significant difference in the 'centifugal' force caused by the earth-moon rotation due to the _large_ difference between the distance from the centre of that rotation to the surface on one side, close to the moon, and that away from the moon. When these two sets of forces are added up over the surface the result is that the strongest force is almost horizontal at the 'sides' of the earth. This pulls the tides sideways, there is _NO_ lifting.

      This sideways pull results in the water sloshing back and forth. In most places of the oceans there is _NO_ tide at all, the surface height does not change. Tides rising and falling is solely a result of the water bumping against a coastline.

      If the Moon 'pulled up' the water then there would be tides mid-ocean. These do not exist (for the most part)*.

      *There are 'tides' in the circulatory systems in the south pacific. As these rotate there is no direct correlation with the position of the moon across the seas, some will be high, some low for any particular position.

    32. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > In reality, there IS a significant difference between the moon's attraction on both sides of the earth. A quick back-of-the-envelope calculation, using the moon's average distance of 384400 km, its radius of 1737.1 km, its surface gravity of 1.62 m/s^2 and the earth's radius of 6371 km, gives me about 33 micron/s^2 at the center of the earth, 32 micron/s^2 on the far side of the moon, and 34 micron/s^2 on the near side.

      Your calculation are wrong byl orders of magnitude. The gravitational pull decreases by the inverse square law. The difference in distance is 60 times. the inverse square law gives a difference of 1/3600 between the near side and far side. Your claim is a difference of 1/7 which is complete nonsense.

      > That may not seem like much, but since it's a steady force continuously revolving around, it's enough to keep a mass of water moving around the planet.

      The tidal 'mass of water' does _NOT_ 'move around the planet'. In the north pacific it sloshes back and forth (mostly without raising the level) and only 'lumps up' as a tide when it reaches a coast. In the south pacific there a 3 'wheels' engaging like gears that rotate. The one nearest new zealand engages with the (single) tide that travels up the west coast and down the east coast.

      You have an overly simplistic and wrong viewpoint of tides that are akin to flat-earth.

    33. Re: It's the Sun, actually by michelcolman · · Score: 1

      Look, I don't have time for this right now. I've got a book about gravity here ("Gravity from the ground up" by Bernard Schutz), which starts from the basics and works up to General Relativity and cosmology in a very scientific, not-dumbed-down way with actual math, and it explains tides exactly like I did. So does the Wikipedia article on tides.

      I hate to use authoritative arguments, but I really do have better things to do, sorry. I'm not being paid for this.

      Spinning around an axis creates a centrifugal (pseudo-)force, but orbiting by gravity (translation rather than rotation) does not. Otherwise the occupants of the ISS would not feel weightless inside the station but would stick to one side of it like I already explained. The motion of the earth around the center of gravity of the earth-moon system is caused by the attraction of the moon which acts on all of the earth, the only difference between different points being the gravitational gradient. I calculated that tidal gravitational gradient for you in my previous post (about 6% between the two sides, hardly negligible). There's not much more I can do, it really does work that way.

    34. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > there are local scenarios where particular coastlines and ocean depths change the tides so they happen a bit earlier or later.

      There are some places where the high tide coincides with the moon overhead, and some where it occurs when the moon is on the horizon, and others in-between. In my country every variation exists in equal proportion*. This is not unique. Around Great Britain the tides circulate and some places get more than two tides per day as the water sloshes back and forth. Get a tide chart for many locations along a coast and see that there is no 'bump' that stays under the moon.

      Yes, generally, the time between tides is related to the orbit of the moon. But this does not mean that high tide is when the moon is above.

      * There is one place where one harbour on one coast and another harbour on the other coast are separated by only a few km and the tides are 3 hours different, and neither are high with the moon overhead.

    35. Re: It's the Sun, actually by michelcolman · · Score: 1

      Your calculation are wrong byl orders of magnitude. The gravitational pull decreases by the inverse square law. The difference in distance is 60 times. the inverse square law gives a difference of 1/3600 between the near side and far side

      Come on, this is basic physics.

      Gravity at the surface of the moon (1737.1 km from the center) is 1.62 m/s^2
      Gravity at 384400 km from the center of the moon is 1.62 * 1737.1^2 / 384400^2 = 33.08 micron per second squared.
      Gravity at 390771 km from the center of the moon is 1.62 * 1737.1^2 / 390771^2 = 32.01 micron per second squared.
      Gravity at 378029 km from the center of the moon is 1.62 * 1737.1^2 / 378029^2 = 34.21 micron per second squared.

      A difference of 1/60 in the distance does not result in a difference of only 1/3600. Derivatives don't work that way, you are squaring the wrong thing.

    36. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > the difference in attraction to Jupiter on both sides would be completely insignificant. But apparently it's enough to tear rocks apart.

      It will 'tear rocks apart' because there is almost nothing holding them together. Asteroids are not like a boulder, they are more like a handful of sand and pebbles that is only held together by their mutual gravitational attraction (which is almost insignificant).

    37. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > Otherwise the occupants of the ISS would not feel weightless inside the station but would stick to one side of it like I already explained.

      If ISIS was spinning around on a string then the occupants would be 'stuck to one side' by 'centrifugal force'. If it were stationary but still held at that altitude then the occupants would be 'stuck to' the other side by gravity of Earth. They are 'weightless' because the 'centrifugal' force is exactly equal and opposite to the force of gravity (otherwise they would fly off into space or fall to earth). There is no gradient across the craft so there is no force felt by the occupants.

      > The motion of the earth around the center of gravity of the earth-moon system is caused by the attraction of the moon which acts on all of the earth, the only difference between different points being the gravitational gradient.

      No. WRONG. You make the same mistake as you did with ISIS. The point furthest away from the CoG of earth-moon will feel more centrifugal force away from the moon because it is further away. The point closest to the moon will feel a smaller centrifugal force towards the moon. The total centrifugal force is equal and opposite to the gravitational attraction of the moon (otherwise we would move away or closer). Because the centrifugal forces are acting in different directions (away from the earth-moon CoG which is 5000km from earth's centre) the difference (gradient) between the side away from the moon and the side towards the moon is much greater than the gravity gradient caused by the moon..

      These forces are completely insignificant compared to earth's gravity so they are not detectable, they are even small compared to variations in gravity over small distance on earth's surface due to hills and valleys.

      > I calculated that tidal gravitational gradient for you in my previous post (about 6% between the two sides, hardly negligible).

      OK, it is about 6% of almost nothing, spread over several thousand miles. It is still not enough to 'lift' anything, and in fact cannot do so (it can, however, make water slosh back and forth). The difference between a 'low' weather patten and a 'high' (approx 1 tonne per sq.metre difference) is several orders of magnitude greater than all of the moon's gravitational 'pull', let alone the tiny gradient.

    38. Re: It's the Sun, actually by michelcolman · · Score: 1

      Where did you even get this theory? Did somebody explain it to you like that? Did you get it from a book or a website or something? Or did you come up with it yourself? I'm just curious, because it really is completely wrong.

      I'm going to stop arguing now. It's not worth my time.

    39. Re: It's the Sun, actually by Anonymous Coward · · Score: 0

      > Where did you even get this theory? Did somebody explain it to you like that? Did you get it from a book or a website or something? Or did you come up with it yourself? I'm just curious, because it really is completely wrong.

      The flat-earther asks "where did you get the theory about the earth moving?".

      This one explains it.

      https://www.lhup.edu/~dsimanek/scenario/tides.htm

    40. Re: It's the Sun, actually by michelcolman · · Score: 1

      Thank you very much for providing an article that proves my point. Too bad you apparently didn't read it yourself, or you would have realised you were wrong and I was right all along.

      From that very website:
      "The distortion of water and earth that we call "tidal bulges" is the result of deformation of earth and water materials at different places on earth in response to the combined gravitational effects of moon and sun. It is not simply the size of the force of attraction of these bodies at a certain point on earth that determines this. It is the variation of force over the volumes of materials (water and earth) of which the earth is composed."

      You know, that variation that you claimed was completely insignificant and could never be strong enough to cause tides? Yes, that very variation turns out to be the cause of the tides after all, just like I wrote it was.

      The article goes into more detail than I did: it turns out these differential gravitational forces don't just mean more gravity one one side and less on the other, but also have sideways components due to the change in the direction of gravity. At the poles the resulting force is even towards the surface of the earth. That's something I didn't even know, I would have thought those would be insignificant.

      Anyway, the part about "A closer look at centrifugal forces" goes on to debunk your very theory about tides being caused by centrifugal forces.

      "So the bottom line is that centrifugal forces on the earth due to the presence of the moon are not tide-raising forces at all. They cannot be invoked as an "explanation" for any tide, on either side of the earth or anywhere else."

      Seriously, do me a favor and read the article. All of it. I couldn't explain it better than it does.

  5. Unnecessary cushioning by The+Evil+Atheist · · Score: 5, Insightful

    As these results are based entirely on statistical evidence, not on any direct link between tidal forces and actual quakes, they are quite uncertain and unproven.

    Given that the article does not say tidal forces CAUSE quakes, this cushioning is completely unnecessary. They're only noting a suggestion of a link between tidal forces and the magnitude of the quake - not the occurrence/non-occurrence of a quake.

    And something being "based entirely on statistical evidence" does not invalidate or weaken anything. It is the quality of the statistical evidence, not the mere use of statistical evidence, that would invalidate or weaken a claim.

    --
    Those who do not learn from commit history are doomed to regress it.
    1. Re:Unnecessary cushioning by ilguido · · Score: 2

      To say the truth, this is a very old theory. A guy spent his life searching for connections between tides and earthquakes.

    2. Re:Unnecessary cushioning by Plus1Entropy · · Score: 1

      *hypothesis

      --
      Only crack the nuts that crack. You don't put the ones that don't crack in the sack.
    3. Re:Unnecessary cushioning by Anonymous Coward · · Score: 0

      And another guy:
      https://en.wikipedia.org/wiki/Ken_Ring_(writer)

      Specifically:
      http://www.predictweather.co.nz/ArticleShow.aspx?ID=577&type=home

    4. Re:Unnecessary cushioning by jheath314 · · Score: 5, Funny

      Earthquakes cause full moons!

      --
      Procrastination Man strikes again!
    5. Re:Unnecessary cushioning by silentcoder · · Score: 2

      >And something being "based entirely on statistical evidence" does not invalidate or weaken anything. It is the quality of the statistical evidence, not the mere use of statistical evidence, that would invalidate or weaken a claim.

      Well, in this case, that evidence is purely of correlation. Correlation does not imply causation. Now as it happens - they aren't even claiming causation and there is no reason to suspect it. The suggestion is that tidal forces can make quakes worse - and there are conceivable mechanisms that might cause that effect, this does not however prove any of those mechanisms actually happen. They could all cancel out for all we know.
      What this does say is -there is reason to study more, there's something here worth further study.

      Some of that study may be statistical - in which case it's important to remember the golden rule of these things: rule out all the data so far. Basically, the statistical clump you noticed, is not a valid sample in determining whether that clump matters or represents a real thing. This is where the scientific method kicks in. Based on the clump we can now predict that, in future, quakes that that coincide with new or full moons will also be more severe than quakes which do not. If that prediction holds- then we learn that there must, indeed, be some causal mechanism at play. If it does not -it means we picked an interesting but meaningless data set either deliberately or unintentionally because human brains are programmed to look for interesting patterns whether or not they exist.

      --
      Unicode killed the ASCII-art *
    6. Re:Unnecessary cushioning by jrumney · · Score: 2

      And something being "based entirely on statistical evidence" does not invalidate or weaken anything.

      It depends if you consider correlation to be weaker than causation. Statistical evidence is correlation. You now need to come up with a theory to explain the cause of that correlation, and test the theory to see if it can be proven. With only a correlation, there is still a possibility, however remote, that the relationship you have noticed has appeared in the data purely by chance.

    7. Re:Unnecessary cushioning by tinkerton · · Score: 1

      I think it would be interesting knowledge when creating models of earthquakes. If you have models of earthquakes that predict the distribution of quakes for all the values of the richter scale. It acts as a power law, a bit like the old sandpile avalanche model. Then what happens if you add a disturbance, does this affect the distribution or not? For instance, intuition might say it decreases the chance of the largest quakes, triggering them early so they are smaller. This would affect the distribution. So if you collect some good data of the impact of a disturbance that could lead to changes in the models. Chances are of course that the collected data is just not definitive enough to say much.

      The old sandpile model: You have a constant small stream of sand onto a pile of grains of sand, and measure the size of the avalanches sliding down from the sides. The sizes of the avalanches have a certain distribution, a power law, and the frequency of very large avalanches does not really go to zero as scale goes up.

    8. Re:Unnecessary cushioning by Alomex · · Score: 4, Insightful

      Correlation does not imply causation.

      This has become a /. meme. What is your suggestion here, that there is a third agent responsible both for earthquakes and full/new moons?

      In real life, science correlation is often converted into causation using Occam's razor or logical physical principles. E.g. while there is nothing in theoretical physics forbidding the interpretation that the light about to start shining made you turn the switch, we choose for a variety of other reasons, the interpretation that the causation is the other way around, we turn on the switch, then the light goes on.

    9. Re:Unnecessary cushioning by Anonymous Coward · · Score: 0

      I see no reason to stick to one interpretation or the other. If the light wasn't about to start shining then why would you have hit the switch? Remember, we're talking about a case where the correlation exists, so it's not like the light would have failed to come on. There's no difference.

    10. Re:Unnecessary cushioning by silentcoder · · Score: 1

      >What is your suggestion here, that there is a third agent responsible both for earthquakes and full/new moons?

      Fallacy. There isn't only ONE alternative.
      A correlation ONLY proves that things happened to at the same times. Nothing more. Where you have a correlation between X and Y any of the following could be true.
      1) The correlation could be because X causes Y - this is the one everybody assumes
      2) The correlation could *actually* be because Y causes X
      3) The correlation could be because an unknown, Z, causes both X and Y
      4) Unknown A and B causes X and Y respectively and but unknown Z can cause both A and B
      5) Nothing. X and Y are caused by A and B respectively but there is no causal link anywhere whatsoever and the correlation is simply coincidence.

      Most human intuition is that 1 is the most likely, in fact 5 is far more likely. Humans underestimate just how incredibly common coincidence actually is. See my post above about how often people get diagnosed with austism and vaccinated on the same day. 18000 times a year just in the US (and that's just the lowest number of exact ones - what people perceive as the same thing goes into the hundreds of thousands). - and it's pure coincidence. I actually show the math that proves it is coincidence. That's what the statistics actually predicts the coincidence would be if there was NO causal link.

      --
      Unicode killed the ASCII-art *
    11. Re:Unnecessary cushioning by dcw3 · · Score: 1

      While the correlation doesn't imply causation, correlation might be helpful in prediction. If events A and B often occur together, and the frequency of that correlation (X), and you know when A happens, couldn't you reasonably say there's an X% chance of B occurring.

      --
      Just another day in Paradise
    12. Re:Unnecessary cushioning by Anne+Thwacks · · Score: 1
      a third agent responsible both for earthquakes and full/new moons

      Yes - its agent Gibbs - don't you watch NCIS?

      --
      Sent from my ASR33 using ASCII
    13. Re:Unnecessary cushioning by Alomex · · Score: 1

      What you say is true in the abstract, though to be accurate 4 is a special case of 3 if you think about it.

      After each experiment, one must consider all five alternatives before reaching a conclusion. However in this specific case the only reasonable conclusions are 1 and 5, which is why bringing up the "correlation does not imply causation" is just a meme.

      A valid comment would have been "wait, how big is the earthquake sample? how large is the increase in intensity?, could it be just random variation?". There is no way to answer those questions, so those will remain a mystery (unless we read the TFA that is, but who does that?).

    14. Re:Unnecessary cushioning by hcs_$reboot · · Score: 1

      Interesting to note that a week from the big Tohoku earthquake in Japan (2011), it was one of the biggest Super Moon of the decade.

      --
      Slashdot, fix the reply notifications... You won't get away with it...
    15. Re:Unnecessary cushioning by lars_stefan_axelsson · · Score: 1

      This has become a /. meme. What is your suggestion here, that there is a third agent responsible both for earthquakes and full/new moons?

      God?

      Sorry, sorry. I'll see myself out... ;-)

      --
      Stefan Axelsson
    16. Re: Unnecessary cushioning by Anonymous Coward · · Score: 0

      It's strange but now we have deep mining techniques working on Terabytes of data looking for hidden correlations.

      Sometimes human intuition comes up with things like "the bus is always late when you are early and early when you are late". Which is basically a 2Ã--2 true-positive/false negative statistics analysis.

    17. Re:Unnecessary cushioning by Anonymous Coward · · Score: 0

      Tides can't melt steel earthquakes.

    18. Re:Unnecessary cushioning by RockDoctor · · Score: 1
      Many people have been trying to find correlations between the occurrence of earthquakes and the occurrence of other phenomena which might possibly give predictive ability for earthquakes, and they've been trying (scientifically and less scientifically) for somewhat more than a century.

      No-one has had significant success up to this date - this result barely makes it to significance with a corpus of relevant earthquakes of only a dozen or so. And the (putative) discovery of this weak signal is likely to mean that any other signals in the data set (several million earthquakes) are even weaker and of even lower significance.

      --
      Birds are not dinosaur descendants;birds are dinosaurs, for all useful meanings of "birds", "are" and "dinosaurs"
    19. Re:Unnecessary cushioning by RockDoctor · · Score: 1

      A valid comment would have been "wait, how big is the earthquake sample? how large is the increase in intensity?, could it be just random variation?". There is no way to answer those questions,

      The sample of earthquakes (note : "sample", not "population") showing this effect is of "great earthquakes", not all earthquakes. But when they extend their analysis to M5.5 quakes the correlation disappears. There have been a dozen "great earthquakes" in instrumental history.

      Our catalogues of quakes of M5.5+ are essentially complete for the last half century. Chalk that one up to the global test-ban treaty - a nuclear blast of Hiroshima or smaller size will produce a quake of M3 or higher.

      If you want the paper, try this link.

      --
      Birds are not dinosaur descendants;birds are dinosaurs, for all useful meanings of "birds", "are" and "dinosaurs"
  6. Is the reverse true? by bazmail · · Score: 2, Interesting

    Do moonquakes occur during these periods?

    1. Re: Is the reverse true? by Anonymous Coward · · Score: 1

      Only during a full earth or new earth...

    2. Re:Is the reverse true? by quenda · · Score: 1

      Do moonquakes occur during these periods?

      Are you serious? The moon is in gravitational lock, so experiences no tidal stress.
      Have you not noticed that the same side of the moon always faces the earth?

      OK, there is some tidal force from the sun, but the moon is also kind of small, and solid. No molten core, no ocean, no thin crust, no plate tectonics.

    3. Re:Is the reverse true? by Plus1Entropy · · Score: 1

      TIL there are moonquakes.

      --
      Only crack the nuts that crack. You don't put the ones that don't crack in the sack.
    4. Re:Is the reverse true? by silentcoder · · Score: 1

      To be fair, our knowledge of these things is pretty much in it's infancy. When New Horizons sent us the first close-up pictures of Jupiter recently - the single biggest shock was how varied the land is. Mountains. Valleys. All the signs of a geologically active body - and no known mechanism for what could possibly let this relatively tiny little thing far from the sun's energy be geologically active. What could power it ? Is it still active or did it merely used to be, once, long ago ?
      Mars was considered geologically dead until recently - but now some evidence suggests there is still some geological activity going on. Everything we know about geology is based on Earth and almost all of it are inferred from indirect observations (mostly from seismographs and studying the layers in rocks). We have seen the magma at the plate boundaries in the oceans - but that's about the extent of direct observation of geological forces we have.
      Most of the planets have magnetic fields - we have no real idea how that's possible. We actually have a fairly complete theory about Earth's magnetic field (which is very much something geologists figured out) but hardly any of the components of that is present in most other planets and some have none -yet still have magnetic fields.
      Just today there is a headline about studies of moon rocks from the 1970's done with modern day spectrometers and finding things that suggests our model of the moon's formation is radically wrong and it was a much bigger impact than we previously thought.
      Astrgeophysics as a science is still just beginning to explore - and we can expect major and groundbreaking discoveries that rewrite every textbook to be coming frequently for quite some time yet, simply because what we are studying is still so incredibly unknown and we're just beginning to develop the technology to study it better -a process that is likely to accelerate rapidly.

      --
      Unicode killed the ASCII-art *
    5. Re:Is the reverse true? by Black.Shuck · · Score: 4, Informative

      And yet.

    6. Re:Is the reverse true? by Anonymous Coward · · Score: 2, Funny

      "When New Horizons sent us the first close-up pictures of Jupiter recently - the single biggest shock was how varied the land is."

      Actually, the biggest shock would have been that it was Jupiter, not Pluto, like it was supposed to be...

    7. Re:Is the reverse true? by Plus1Entropy · · Score: 1

      All the signs of a geologically active body - and no known mechanism for what could possibly let this relatively tiny little thing far from the sun's energy be geologically active.

      I assume you're talking about Pluto, not Jupiter. I'm not sure I agree that there is "no known mechanism". Charon and is a huge moon, relatively speaking. The two are tidally locked to each other and the barycenter exists outside of Pluto. The tidal forces between them probably don't tell the whole story, but I'd imagine they're at least partially responsible for any geological activity.

      --
      Only crack the nuts that crack. You don't put the ones that don't crack in the sack.
  7. Old news to some by reboot246 · · Score: 1

    There used to be a geologist on Coast to Coast AM (Art Bell's radio show) who always claimed that there was a relationship between the moon and earthquakes. He predicted the 1989 World Series quake and lost his government job. His name was Jim Berkland.

    1. Re:Old news to some by Anonymous Coward · · Score: 1

      I also remember reading about this theory ~10 years ago; i.e. that if the tidal forces from the sun and moon are strong enough to move the oceans around, they should also be strong enough to move the Earths crust a bit around, and then you've got yourself an earthquake. So it's not exactly news, more like new evidence in support of an existing theory.

  8. look up flat earth on youtube by Anonymous Coward · · Score: 0

    look up flat earth on youtube. trumps any tv show

  9. that's no moon... by Anonymous Coward · · Score: 0

    Now witness the paawer of diss fully armed and operational battle station! Good, geuwd, you can now hear my voice, my young AppRenTist!

  10. Sellings eyeballs to the ad company by DrYak · · Score: 4, Insightful

    Yeah, but
    "Study shows statistical correlation that might suggest that tidal stress could be among the dozens of other factors that each contribute slightly in favor of stronger earthquakes", though much more accurate, doesn't have the same "oomph" and thus doesn't manage to sell the same amount of eyeballs to the ad-company paying for this fucking article.
    "The moon will kill with its earthquake power! Cower in terror!! Panic!!! Buy products to feel better!!!!" works so much better...

    --
    "Sufficiently advanced satire is indistinguishable from reality." - [Tips: 1DrYakQDKCQ6y52z6QbnkxHXAocMZJE61o ]
    1. Re:Sellings eyeballs to the ad company by gtall · · Score: 1

      It is more likely "Ignore those extra quakes in Oklahoma, it is the moon, you see?!?"

    2. Re:Sellings eyeballs to the ad company by Anonymous Coward · · Score: 1

      Well, getting people to stop trying to pin Earthquakes on fracking is a good thing, right up there with re-educating creationists. Since the earthquake happens because of tectonic stress, the fracking helps to release that stress early in a much smaller-than-it-would-have-been quake. The anti-oil folks should probably find a different row to hoe.

    3. Re:Sellings eyeballs to the ad company by Anonymous Coward · · Score: 0

      so they have quakes and also tornados?

      New movie confirmed, QUAKENADO, staring Tara Reid "woooo i felt the like the earth move and then i got blown away it was amazing"

    4. Re:Sellings eyeballs to the ad company by MillionthMonkey · · Score: 0

      the fracking helps to release that stress early in a much smaller-than-it-would-have-been quake. The anti-oil folks should probably find a different row to hoe.

      Yes, instead of a single huge quake happening several millenia from now, we're much better off having medium-sized quakes destroying houses every week.

    5. Re:Sellings eyeballs to the ad company by RockDoctor · · Score: 1

      I see the traditional Slashdot disease of not reading the fucking article before commenting stupidly hasn't cured in the last week.

      --
      Birds are not dinosaur descendants;birds are dinosaurs, for all useful meanings of "birds", "are" and "dinosaurs"
  11. Much less by DrYak · · Score: 1

    There's a lot less likeliness of Moonquales happening:

    - The Moon, as mentioned by others is tidally locked with Earth.
    i.e.: It's always the same side facing Earth
    that means that Earth tidal stress is always "pulling" the exact same part.
    thus no change in this "pull" and therefore no directly-earth-caused tides on the moon.

    - The Moon is a huge solid rock, it doesn't move much, whereas the Earth is pieces of solid crust all covering a molten mantle on which they more or less float (the "more of less" part being when they bump into each other, rub against each other, or one dives under another).
    Thus Earth has a tectonic seismology (the tectonic plate doing their above mentioned shit instead of peacefully floating next to each other), on which a whole bunch of factors (including in parts the tidal stress exerted by the Moon as maybe suggested by this study) can act as trigger to release to stored shear stress (causing Earthquakes).
    Whereas the Moon, by being a solid block of rocks can't do that.

    - On the other hand, the Moon has no atmosphere :
    Any falling rock will smash straigh on the surface. Such meteorite contribute heavily on the moonquakes.
    The part of the moon that face the Sun will be backed in light, while the other side will cool off a lot, and as the moon is tidally locked with Earth, such "Moon's days" take a whole full-moon cycle (2 weeks day, 2 weeks night). Such huge difference in "cooking" temperature can cause stress and also contribute to moonquakes.
    (in both case the Earth is more or less innocent - except indirectly by tidal lock and/or "benefiting" from the moon as a giant meteor shield)

    NOTE: I am a Doctor, not an Astrophysicist (in McCoy's voice).
    So I might be wrong. ...or I might be lying and covering moonquakes actually caused by nuclear tests done by the Nazis hidden on the dark side of the moon.

    --
    "Sufficiently advanced satire is indistinguishable from reality." - [Tips: 1DrYakQDKCQ6y52z6QbnkxHXAocMZJE61o ]
  12. Problem Solved by Anonymous Coward · · Score: 0

    Solution: Destroy the moon!

  13. Tidal forces and moonquakes by sjbe · · Score: 4, Informative

    Are you serious? The moon is in gravitational lock, so experiences no tidal stress.

    Not actually true. Because Earth is not tidal locked to the moon, the rotation of the Earth will cause tidal stresses on the Moon because the Earth is not a uniform body, nor is the moon. Tidal locking does not equal no tidal stresses.

    Have you not noticed that the same side of the moon always faces the earth?

    Again not completely true. See lunar libration. The orbit of the moon is not circular, the Earth itself rotates and their respective axis of rotation are not identical. So we don't always see precisely the same face of the moon. We actually see about 59% of the moon's surface though not all at the same time.

    OK, there is some tidal force from the sun, but the moon is also kind of small, and solid. No molten core, no ocean, no thin crust, no plate tectonics.

    There also are some tidal forces from the Earth on the moon. The effect appears to be quite minor. Moonquakes are apparently a thing and apparently ARE caused at least in part by tidal interactions between the Earth and the Moon.

    1. Re:Tidal forces and moonquakes by Anonymous Coward · · Score: 0

      IIRC the tidal effects of the Earth's upon on the Moon are stronger than the Moon's effects on the Earth, due to Earth being more massive (the IIRC part: the impact of that is greater than the impact of the fact that the moons diameter is smaller than the Earth's). The effects upon the Moon may be less noticeable since there are no oceans on the Moon, but nonetheless the tidal forces are greater. The crust of each body actually stretches due to the tidal forces caused by the other body.

    2. Re:Tidal forces and moonquakes by angel'o'sphere · · Score: 1

      the Earth itself rotates and their respective axis of rotation are not identical.
      Which is completely irrelevant for the question if another object is tidal locked or not.

      --
      Cost free eBook I read (by iBook/Kobo/Amazon/ObookO/Gutenberg etc.): "The Green Odyssey" by Philip Jose Farmer.
  14. Tides on the moon by sjbe · · Score: 1

    - The Moon, as mentioned by others is tidally locked with Earth.
    i.e.: It's always the same side facing Earth that means that Earth tidal stress is always "pulling" the exact same part. thus no change in this "pull" and therefore no directly-earth-caused tides on the moon.

    Incorrect. The Earth is not a uniform sphere and it is not (yet) tide locked to the Moon. The Earth does exert tidal stresses on the Moon because the gravitational pull on the moon is not uniform.

    - The Moon is a huge solid rock, it doesn't move much, whereas the Earth is pieces of solid crust all covering a molten mantle on which they more or less float (the "more of less" part being when they bump into each other, rub against each other, or one dives under another).

    That very malleability of the Earth is a big part of what causes tidal stresses on the Moon. Remember that tidal forces are simply the results of unequal gravity between two bodies. If the bodies aren't uniform the tidal forces by definition cannot be zero. Tidal lock does not mean no tidal stresses. In fact I'm pretty sure it is tidal stresses that create and maintain the tidal lock.

  15. Re:It's the Sun, actually. NOT! by Anonymous Coward · · Score: 0

    Since this was rated "interesting" instead of "funny", I can only assume that the people here actually believe this crock of s***. If someone actually bothered to compute the gravitational force on the Earth by both the sun and moon, you would find the force of the moon is about 1E6 times larger than that of the sun. I'm not going to do the computation here as I already did it about 30 years ago when we were quoting a highly accurate motion platform. I'll let someone else do the math and post the numbers here.

  16. Why does the phase of the moon matter? by acoustix · · Score: 1

    Can anyone explain to me why the phase of the moon would have anything to do with its gravitational pull?

    --
    "A plan fiendishly clever in its intricacies"- Homer Simpson
    1. Re: Why does the phase of the moon matter? by Anonymous Coward · · Score: 0

      Alignment within orbits. Imagine earth, sun, moon in a roughly straight line. Now imagine moon at 90 degrees from earth sun....or 60. Magnitude of gravitational forces change.

    2. Re:Why does the phase of the moon matter? by 93+Escort+Wagon · · Score: 2

      It's about tidal forces - the relative angles at which the sun and the moon are acting on the earth as the phases of the moon change. The overall strength of the moon's gravitational pull does not change, since its mass is constant.

      --
      #DeleteChrome
    3. Re:Why does the phase of the moon matter? by 93+Escort+Wagon · · Score: 1

      (Okay, the moon's orbit is not perfectly circular - but that's not related to the moon's phase)

      --
      #DeleteChrome
    4. Re:Why does the phase of the moon matter? by Anonymous Coward · · Score: 0

      Full moon = sun and moon 180 degrees opposite to each other
      New moon = sun and moon in alignment
      Both the Sun and Moon have an influence on ocean tides in terms of amplitude. When these reinforce each other we get extra high tides.
      But the Earth is spinning once on its axis every 24 hours. That allows for low and high tides around every 24, 12 and 6 hours depending
      on the location.

    5. Re:Why does the phase of the moon matter? by acoustix · · Score: 1

      Thank you to everyone who answered. I forgot about the alignment with the Sun. It makes perfect sense.

      --
      "A plan fiendishly clever in its intricacies"- Homer Simpson
  17. Finally, they admit it by Anonymous Coward · · Score: 1

    It's about time scientists started admitting that bad things DO happen at full moon.

  18. Time to call Gru by Anonymous Coward · · Score: 0

    and tell him to try to steal the moon again. :)

  19. Phase is a function of orbit by sjbe · · Score: 1

    Can anyone explain to me why the phase of the moon would have anything to do with its gravitational pull?

    The phase itself doesn't have any meaningful effect that I am aware of but the factors that cause the moon phase DO cause real changes in tides. Primarily orbit of the moon in relation to other bodies including the Earth. It isn't the phase per-se that causes the differences but the fact that phase and lunar orbit are closely related.

    Some examples:

    1) Tidal forces don't just come from the Moon. The Sun exerts significant tidal forces as well. The sum of these forces is dependent on the position (and by extension phase) of the Moon in its orbit. So you will tend to see the strongest tides during Full and New moons because the Sun and moon are (approximately) directly lined up.

    2) Also the lunar orbit isn't circular so the moon will exert different amounts of tidal force on the Earth depending on its proximity. You will see different phases of the moon depending on its orbital position. Stronger tides occur when the moon is closest in its orbit to the Earth.

  20. This just in ... by Qbertino · · Score: 2

    Forces of nature can trigger forces of nature.
    Film at eleven.

    --
    We suffer more in our imagination than in reality. - Seneca
  21. Re:It's the Sun, actually. NOT! by khallow · · Score: 2

    If someone actually bothered to compute the gravitational force on the Earth by both the sun and moon, you would find the force of the moon is about 1E6 times larger than that of the sun.

    The Sun is roughly 400 times further way than the Moon. The Sun masses roughly 30 million times more than the Moon, We have that gravitational force is proportional (using the pretty accurate point mass Newtonian model of gravity) to the mass of the object and inversely proportional to the square of its distance. Hence, the Sun's gravitational force is crudely 200 times stronger than that of the Moon.

    By a similar calculation one would get that the tidal force of the Sun is roughly half that of the Moon since tidal force under the above model is proportional to mass and inversely proportional to the cube of the distance.

    So maybe there was a reason your highly accurate motion platform wasn't.

  22. Jim Berkland (sp?) has been saying this for years. by Anonymous Coward · · Score: 1

    The moon causes ocean tides of several feet. It also causes land "tides" of several inches. This small flexing of the earth can set up conditions where a fault that is already under a lot of stress can release, resulting in an earthquake. Normal tectonic movements are the source of the stress that is slowly building up over time, but the flexing of the earth due to the sun and moon results in statistically higher releases of the stress around full and new moons. In other words, the fault was ready to rip and the gravitational forces just gave it the little extra bump that it needed.

  23. Fracking moon by kimgkimg · · Score: 1

    Well just think how we can magnify that by fracking on the moon...

  24. Re:It's the Sun, actually. NOT! by Anonymous Coward · · Score: 0

    Really? So there's a noticeable tidal change once every 24 hours from the sun? I don't see it. What you see is motion of the oceans and tectonic plates that match the period of the moon's position.

  25. Insufficient cushioning by pjt33 · · Score: 1

    Given that the article does not say tidal forces CAUSE quakes, this cushioning is completely unnecessary.

    Given that the title under which the article was posted to /. is "The moon's gravitational pull can trigger major earthquakes, says study", the cushioning was not only necessary but inadequate.

    1. Re:Insufficient cushioning by The+Evil+Atheist · · Score: 1

      Yeah? Well fuck the title. If you read only the title for you news, that's your problem.

      --
      Those who do not learn from commit history are doomed to regress it.
  26. Similarly, earthquakes alter Earths graviational by thinkwaitfast · · Score: 0

    pull on the moon (basic physics). And because global warming causes earthquakes, global warming affects the orbit of Earth's moon.

  27. Re:It's the Sun, actually. NOT! by khallow · · Score: 1

    So there's a noticeable tidal change once every 24 hours from the sun?

    Yes. There's even centuries old names for these effects, spring and neap tide.

    Just because you can't see it now doesn't mean that sailors centuries ago couldn't see it.

    What you see is motion of the oceans and tectonic plates that match the period of the moon's position.

    The Moon's position relative to the Sun.

  28. An earthquake is an accident waiting to happen by trenobus · · Score: 1

    An earthquakes occurs when the static force of friction at a point of geologic stress is overcome, or when the force on a geologic structure exceeds its breaking point. It is an extremely non-linear response, which can be triggered by small changes in these forces. Given that, it would be surprising if tidal effects were not correlated with earthquakes.

    As the polar ice melts and its weight is redistributed over the oceans, I expect this also will result in sufficient changes in tectonic forces to trigger more earthquakes, and perhaps volcanic activity as well. It wouldn't surprise me if even changes in atmospheric pressure are sometimes sufficient to trigger a quake.

    1. Re:An earthquake is an accident waiting to happen by spitzak · · Score: 1

      I don't know if you are trying to make a joke, but global warming is not going to do too much to the earthquakes. Greenland is already rising steadily due to the loss of the glaciers from the last ice age. It is really slow and will still happen for tens of thousands of years. Even if all the current ice cap disappeared tomorrow it would, at best, speed this up a tiny amount (the current ice cap is a fraction of the ice age ice cap so the amount of lost mass is only a small change). The weight of the new ice added to the ocean is insignificant (if it raised the ocean 30 feet that would still only be a tiny fraction of mass increase, think about how deep the ocean is).

    2. Re:An earthquake is an accident waiting to happen by trenobus · · Score: 1

      I'm talking about differentials in force with respect to a system capable of extremely non-linear responses. When polar ice melts, much of the weight that was on one plate moves to adjacent plate(s), so the force on the plate where the ice was decreases, and the force on the adjacent plate(s) increases. The change in the difference in force between the plates could exceed the weight of the ice. (And it could be a positive or negative change, depending on the relationship of the plates. A negative change could reduce the static friction enough to trigger a quake. A positive change could increase the stress enough to do it.) The changes in force may not amount to much in terms of magnitudes of the total forces in play, but it could easily be enough to trigger quakes which otherwise might not have happened for thousands of years.

    3. Re:An earthquake is an accident waiting to happen by Anonymous Coward · · Score: 0

      > As the polar ice melts and its weight is redistributed over the oceans,

      There are places in Scandinavia that are rising by a metre a century as a result of rebounding after the ice age finished and the weight of the ice reduced.

      > changes in atmospheric pressure are sometimes sufficient to trigger a quake.

      Average atmospheric pressure is equivalent to that of 33 feet depth of water. The air pressure changes by approx 10% from lows to highs. So a difference of approx 3 feet depth of water. That is roughly a tonne per sq.metre (or ton per sq.yard).

  29. Duh!!! by Anonymous Coward · · Score: 0

    Duh.
    Gravity pulls on matter.

  30. I thought we knew this ... by NoSalt · · Score: 2

    Didn't we already know this? The moon can cause tides, earthquakes, and other Earth-bound changes.

  31. Let's Answer the Real Question by Anonymous Coward · · Score: 0

    Let's answer the REAL question, shall we? The REAL question is, how can we blame this phenomenon on anthropocentric climate change?

  32. RAPTURE READY! by Thud457 · · Score: 1

    Craigslist killed syzygy job.
    How can you predict earthquakes if you can't monitor lost pet notices in the newspaper classifieds?

    Also makes it hard to hookup with timetravellers, for obvious reasons.

    --

    the preceding comment is my own and in no way reflects the opinion of the Joint Chiefs of Staff

  33. RAQIA by Anonymous Coward · · Score: 0

    If the moon's gravitational pull lifts stuff on earth, then shouldn't the earth's pull lift stuff on the moon? How is it then that the official shape of the moon looks like a lemon with the flat side facing earth?

    There is no outer space & the Van Allen belts are an euphemism for solid firmament.

    1. Re:RAQIA by Anonymous Coward · · Score: 0

      > If the moon's gravitational pull lifts stuff on earth,

      It doesn't.

      > like a lemon with the flat side

      I have a lemon tree, it has never grown a lemon with a flat side.

  34. Satoshi Ide? by Yvan256 · · Score: 1

    If the Bitcoin guy says the gravitational pull of the moon can trigger major Earthquakes, I believe him!

  35. Obl by thegameiam · · Score: 1

    That's no moon!

    --
    Need Geek Rock? Try The Franchise!
  36. Re:It's the Sun, actually. NOT! by Anonymous Coward · · Score: 0

    Have you ever lived on a coast? There is a roughly-daily cycle of tides, caused by the combination of the Moon's and the Sun's gravity. If it was only affected by the Moon, it would be just a simple cycle and the tides would always be the same height. The Sun throws off the peak times and causes higher tides near alignment and lower tides when the Moon is half full.

  37. hmm... by Anonymous Coward · · Score: 0

    I wonder whether the direction of the fault and the latitude make any difference?

  38. Its not the sun or the moon causing earthquakes... by Toxick · · Score: 1

    They're divine punishment to us all for allowing homosexuals and assorted heathens to run amok! It's true. It's all there black and white clear as crystal.

    --
    BRE
    "Dude check me out. I'm like a little otter. A SEXY little otter"
  39. Moonites - What are we going to do about it? by Anonymous Coward · · Score: 0

    Obviously it's a plan to wreck destruction upon the earth by the evil moonites. So what are we going to do about it? Lets show them our wrath and blow up the moon.