Another question, the CDs were probably 74 minute CDs, so wouldn't a simple 90 minute tape hold more data than a CD? No, it wouldn't. CDs have almost perfect channel separation, so you could put one side of the tape on the left channel, and the other one on the right.
The current passing through that thing is at MOST 0.02 mA (0.2 J = 0.02 mA x 20 kV). That's weak =) No, not quite. 0.02 mA x 20 kV = 0.2 W, not J. So, if the duration of the pulse is only one millisecond, then the current would be 20 mA, IF the voltage would really be 20 kV. But the 20 kV is only the open circuit voltage. As soon as there is some resistance between the terminals, the voltage decreases (and the current increases). I don't know how much current will actually flow, but it will be a LOT more than your faulty calculation indicates.
The U.S. didn't sign the Kyoto treaty because parts of it would violate our Constitution (specifically, the 4th Ammendment). The government CAN'T sign a treaty that violates our Constitution.
How does
The right of the people to be secure in their persons, houses, papers, and effects, against unreasonable searches and seizures, shall not be violated, and no Warrants shall issue, but upon probable cause, supported by Oath or affirmation, and particularly describing the place to be searched, and the persons or things to be seized.
(the text of the fourth amendment) interfere with the Kyoto treaty?
It should be easy enough to get around this. The statistical telltale is only due to the fact that El-Khalil consistently uses the same type of instruction to encode a certain bit value. Have Hydan XOR the hidden message with a secret key that produces the right distribution of ones and zeros prior to encoding the message and the problem disappears.
I'm afraid this will not work. Problem is: 'normal' programs will do 'sub 50' instead of 'add -50'. If you don't want to be visible that a message is contained, you cannot change that. But if you don't change that (in about 50% of the cases), you can't hide the information! The only key that would work here would be as long as the message itself!
The technique you propose will work to get a more even distribution of ones and zeros, but not the 'all zeros' (sub 50) distribution that is present in 'standard' programs.
The english article mentions temperature control, but I can't imagine how a washing machine could do the type of temperature control needed for making beer. During the mash (early stage) you need to keep a high temperature (around 150F) for at least 4 or 5 hours. But the water can't change. Its part of what will become beer! European washing machines as I know them are filled with cold water only, and have a heating element in the tub that is thermostatically controlled. I can set mine to anywhere from 30C to 95C, and it will hold that temperature during the whole washing cycle. No need to change the water to keep it hot!
No, that's an urban legend.... The only way it will cause people to go blind is if there are impurities (read: poisons) in it Yes, but methanol (very poisonous) is created when fermenting pectin, which gives hard fruit (like apples, pears etc) their firmness. Methanol has a lower boiling point than ethanol, so if you distill apple wine, and don't throw away the first fraction, your first bottles will contain almost pure poison. (no urban legend, I've done some distilling myself)
In the reactions to the first post on Slashdot all emphasis was put on the (im)possibility of applications for remote surgery, and I don't find this back in the original website.
No mention at all was made on the application for musical purposes, and this seems to be what the research is targeted to.
On the other hand, the second posting on Slashdot only concentrates on the dupe...:-(
The article mentions that you could use this technique to monitor if the line is OK just before a critical operation. But will testing the quality of the line now give enough assurance that this quality will still be met in the middle of the operation, when there is no turning back? I think that for these critical applications any simple test like this will never suffice, and you will need some way of guaranteeing that a minimal level of signal quality will be there, regardless of changing circumstances.
Does this mean that the speed varies based on temperature?
Initially this idea bugs me a bit because it means that a computer would have 'moods' based on the temperature.
What is the problem in that? Actually, this speed difference based on temperature is there in present-day computers. The further you cool them, the higher you can (over)clock. But to avoid stability problems, you should keep a safety-margin.
You could see asynchronous computing as automatic maximum overclocking without stability issues: the system will run as fast as temperature will allow!
Most people here talk about multiple copies being possible.
They overlook that, using this 'quantum entanglement', each particle on the input side is directly linked to exactly one particle on the output side, with the speed of light.
There is no state that is stored, so no possibility for creating another copy!
While im sure all of these participents are very good programmers and incredible mathmeticians, I'm fairly sure a lot of them wouldn't be able to tell you how to take two files on a Unix OS, and list only lines that appear in both in a single commandline.
sort file1 file2 | uniq -d
So, whats my prize;)
Hm. Doesn't this also show lines that appear twice in just one of the files?
Re:so, you people want to build a gun eh?
on
Homemade Gauss Gun
·
· Score: 1
You are just silly as the person you are insulting.
> 2000ms over a 3m barrel is not "hundreds of thousands of G's" its about 66G. Might want to read a 1st year phyics book.
Please, show me your calculation (from that 1st year physics book) When I do the calculation, it goes:
a*t = 2000 m/s 1/2*a*t2 = 3m = 1/2 * (a*t) * t = 1/2 * 2000m/s * t ==> t=3 ms. a=2000 m/s / t ==> a=666666 m/s2 = 67957 g.
OK, this is a factor 9.81 lower than Dyolf Knip found, because he omitted that 1g = 9.81 m/s2, but still a factor 1000 greater than you stated.
Please don't call people silly when your own math is not perfect, and, moderators, please do not mod posts up as informative when a little checking proves them more wrong than the post they are criticizing!
In the article, Tom has concentrated on go/no-go tests.
In a product that can influence picture quality tremendously, I would have liked to see something more than "It... produced a good picture " (with no mention of the resolution tested) in case of the CS-USB21H , or no mention of picture quality at all in case of the GCS124U KVM .
It would have been really helpful to see characteristics like 'amount of reflections' or 'actual measured bandwidth'
This would have helped me more on deciding which unit is right for my purposes than describing the computer systems that were used in detail. What is the use of specifying the brand of CD-writer or the amount and brand of RAM that were used? I cannot imagine that these have any influence on the performance of the KVM switch.
Why does the RIAA need an exception to a TERRORIST law? It seems to me that (illegal, without a warrant) searching for copyright infringement has nothing to do with terrorism. If the law they want to amend sees this as terrorism, then we don't need an amendment for just the copyright-related breakins, but for all breakins that are obviously not terrorism-related. Let this law be restricted to terrorism, instead of calling all computer-crime terrorism.
It'll be done by a computer program - hence the standard console interface.
I realized that.
But, let's say we get 1000 contestants.
Also, they specify 6-12 different games for each, let's say 10 on average.
This will mean 10*1000 * 999 / 2 matches (when A has played against B, B has played against A) of many thousand moves (let's say just 2000) each.
A program is required to process at least 10 moves per second. Worst case, this will lead to roughly 1000 million seconds, or 30 years, of computer time.
When you get more than 1000 contestants, the time required for the match will rise quadratically.
I realize that the average program will be faster than 10 moves/second, and that you can use several computers to speed things up (from the height of the prize, I gather that their budget is not unlimited, so I think more than 10 computers will be out of the question), but still, if you get a significant number of contestants, letting every contestant play agains very other may be prohibitive.
From the detailed information on their web-site:
A round-robin tournament will be held to select the winner of the Learning Machine Challenge. All combinations of players will take part in all games, of which there will be between six and twelve.
As I see it, they plan to let every contestant play against every other, on 6-12 games, several thousand moves each.
Where will they find the time to do this if they get more than just a few dozens of entries?
There are almost half a million/. accounts - imagine if just 20% of them read/. in a 1 hour window and clicked that link
I think your estimate of just 20% of slashdot readers at any time is a bit high. The average slashdot reader would have to be on slashdot almost 5 hours a day to reach this. This maybe normal for you and me, but on average?
From what I understand your X-mhz box does not run at precisely X-mhz. The clock actually oscillates slightly around the stated frequency. This is of course to prevent a huge spike of RF emissions at the clock frequency, which makes it way easier to get FCC certification.
This is an option in most modern bioses (spread spectrum) that is switched OFF by default
Yes, and no. Bluetooth will do most things better than IRDA, except for one: directionality (if that is a word). I have a Palm, and to exchange info with another Palm user, you point both Palms at each other, and you go. I would not like my Palm to react to a broadcast of every other Palm in a range of 10 meters! Sometimes a disadvantage (you must aim for IRDA) can be an advantage.
The 68000 address registers were 32bit long, but only the lower 24 bit were used for addressing. Externally the chip had 23 pins, because it addressed words instead of bytes, and had 16 data pins. It could access 2^24 = 16MB
Correct for the 68000, but the original poster complained about the 68008, not the 68000.
The 68008 has only 20 or 22 address pins, and 8 data pins.
My comment on the 68000 series was only that it did not have a multiplexed data/address bus, as the original poster claimed.
The ancient Sinclair QL used a 68008, which could handle 32 bit addresses, and thus 4GB of memory, but only had an 8-bit combined address and data bus. It'd take 4 bus clocks to select an address, and another four to read/write a 32 bit value from/to the location.
I'm sorry to correct you, but the 68000 series of microprocessors does not have a combined address / data bus. The 68008 had a separate address bus of 20 or 22 pins, so it could directly address 1 or 4 MB of memory (depending on package)
Although inductance is an impedance, i.e. it will limit the current that is transmitted at a specific voltage, it does so without loss.
The only loss through inductance is indirect. Power delivered is V*I*cos(phi), and thus diminishes when voltage and current are out of phase. Power lost is I*I*R, and thus independent of cos(phi). For the same power delivered, lowering cos(phi) will diminish efficiency, _as_long_as_there_is_R_! Without resistance, the cos(phi) will not matter!
Slashdot Mirror
Another question, the CDs were probably 74 minute CDs, so wouldn't a simple 90 minute tape hold more data than a CD?
No, it wouldn't. CDs have almost perfect channel separation, so you could put one side of the tape on the left channel, and the other one on the right.
The current passing through that thing is at MOST 0.02 mA (0.2 J = 0.02 mA x 20 kV). That's weak =)
No, not quite. 0.02 mA x 20 kV = 0.2 W, not J.
So, if the duration of the pulse is only one millisecond, then the current would be 20 mA, IF the voltage would really be 20 kV.
But the 20 kV is only the open circuit voltage. As soon as there is some resistance between the terminals, the voltage decreases (and the current increases). I don't know how much current will actually flow, but it will be a LOT more than your faulty calculation indicates.
How does
(the text of the fourth amendment) interfere with the Kyoto treaty?
It should be easy enough to get around this. The statistical telltale is only due to the fact that El-Khalil consistently uses the same type of instruction to encode a certain bit value. Have Hydan XOR the hidden message with a secret key that produces the right distribution of ones and zeros prior to encoding the message and the problem disappears.
I'm afraid this will not work.
Problem is: 'normal' programs will do 'sub 50' instead of 'add -50'. If you don't want to be visible that a message is contained, you cannot change that. But if you don't change that (in about 50% of the cases), you can't hide the information! The only key that would work here would be as long as the message itself!
The technique you propose will work to get a more even distribution of ones and zeros, but not the 'all zeros' (sub 50) distribution that is present in 'standard' programs.
The english article mentions temperature control, but I can't imagine how a washing machine could do the type of temperature control needed for making beer. During the mash (early stage) you need to keep a high temperature (around 150F) for at least 4 or 5 hours. But the water can't change. Its part of what will become beer!
European washing machines as I know them are filled with cold water only, and have a heating element in the tub that is thermostatically controlled. I can set mine to anywhere from 30C to 95C, and it will hold that temperature during the whole washing cycle. No need to change the water to keep it hot!
No, that's an urban legend. ... The only way it will cause people to go blind is if there are impurities (read: poisons) in it
Yes, but methanol (very poisonous) is created when fermenting pectin, which gives hard fruit (like apples, pears etc) their firmness.
Methanol has a lower boiling point than ethanol, so if you distill apple wine, and don't throw away the first fraction, your first bottles will contain almost pure poison. (no urban legend, I've done some distilling myself)
I'm currently compiling OpenOffice on a 466 MHz Celeron. Takes about 30 hours...
XScale is just the ARM compatible processor of Intel. GCC supports it.
Agree!
:-(
In the reactions to the first post on Slashdot all emphasis was put on the (im)possibility of applications for remote surgery, and I don't find this back in the original website.
No mention at all was made on the application for musical purposes, and this seems to be what the research is targeted to.
On the other hand, the second posting on Slashdot only concentrates on the dupe...
The article mentions that you could use this technique to monitor if the line is OK just before a critical operation. But will testing the quality of the line now give enough assurance that this quality will still be met in the middle of the operation, when there is no turning back?
I think that for these critical applications any simple test like this will never suffice, and you will need some way of guaranteeing that a minimal level of signal quality will be there, regardless of changing circumstances.
No, you meant phase velocity, of course.
Group velocity is what carries the information, phase velocity can be higher than c.
Does this mean that the speed varies based on temperature?
Initially this idea bugs me a bit because it means that a computer would have 'moods' based on the temperature.
What is the problem in that? Actually, this speed difference based on temperature is there in present-day computers. The further you cool them, the higher you can (over)clock. But to avoid stability problems, you should keep a safety-margin.
You could see asynchronous computing as automatic maximum overclocking without stability issues: the system will run as fast as temperature will allow!
Most people here talk about multiple copies being possible.
They overlook that, using this 'quantum entanglement', each particle on the input side is directly linked to exactly one particle on the output side, with the speed of light.
There is no state that is stored, so no possibility for creating another copy!
While im sure all of these participents are very good programmers and incredible mathmeticians, I'm fairly sure a lot of them wouldn't be able to tell you how to take two files on a Unix OS, and list only lines that appear in both in a single commandline.
;)
sort file1 file2 | uniq -d
So, whats my prize
Hm. Doesn't this also show lines that appear twice in just one of the files?
You are just silly as the person you are insulting.
> 2000ms over a 3m barrel is not "hundreds of thousands of G's" its about 66G. Might want to read a 1st year phyics book.
Please, show me your calculation (from that 1st year physics book)
When I do the calculation, it goes:
a*t = 2000 m/s
1/2*a*t2 = 3m = 1/2 * (a*t) * t = 1/2 * 2000m/s * t
==> t=3 ms.
a=2000 m/s / t ==> a=666666 m/s2 = 67957 g.
OK, this is a factor 9.81 lower than Dyolf Knip found, because he omitted that 1g = 9.81 m/s2, but still a factor 1000 greater than you stated.
Please don't call people silly when your own math is not perfect, and, moderators, please do not mod posts up as informative when a little checking proves them more wrong than the post they are criticizing!
In the article, Tom has concentrated on go/no-go tests. ... produced a good picture " (with no mention of the resolution tested) in case of the CS-USB21H , or no mention of picture quality at all in case of the GCS124U KVM .
In a product that can influence picture quality tremendously, I would have liked to see something more than "It
It would have been really helpful to see characteristics like 'amount of reflections' or 'actual measured bandwidth'
This would have helped me more on deciding which unit is right for my purposes than describing the computer systems that were used in detail. What is the use of specifying the brand of CD-writer or the amount and brand of RAM that were used? I cannot imagine that these have any influence on the performance of the KVM switch.
Why does the RIAA need an exception to a TERRORIST law? It seems to me that (illegal, without a warrant) searching for copyright infringement has nothing to do with terrorism. If the law they want to amend sees this as terrorism, then we don't need an amendment for just the copyright-related breakins, but for all breakins that are obviously not terrorism-related. Let this law be restricted to terrorism, instead of calling all computer-crime terrorism.
It'll be done by a computer program - hence the standard console interface.
I realized that.
But, let's say we get 1000 contestants.
Also, they specify 6-12 different games for each, let's say 10 on average.
This will mean 10*1000 * 999 / 2 matches (when A has played against B, B has played against A) of many thousand moves (let's say just 2000) each.
A program is required to process at least 10 moves per second. Worst case, this will lead to roughly 1000 million seconds, or 30 years, of computer time.
When you get more than 1000 contestants, the time required for the match will rise quadratically.
I realize that the average program will be faster than 10 moves/second, and that you can use several computers to speed things up (from the height of the prize, I gather that their budget is not unlimited, so I think more than 10 computers will be out of the question), but still, if you get a significant number of contestants, letting every contestant play agains very other may be prohibitive.
From the detailed information on their web-site:
A round-robin tournament will be held to select the winner of the Learning Machine Challenge. All combinations of players will take part in all games, of which there will be between six and twelve.
As I see it, they plan to let every contestant play against every other, on 6-12 games, several thousand moves each.
Where will they find the time to do this if they get more than just a few dozens of entries?
There are almost half a million /. accounts - imagine if just 20% of them read /. in a 1 hour window and clicked that link
I think your estimate of just 20% of slashdot readers at any time is a bit high. The average slashdot reader would have to be on slashdot almost 5 hours a day to reach this. This maybe normal for you and me, but on average?
From what I understand your X-mhz box does not run at precisely X-mhz. The clock actually oscillates slightly around the stated frequency. This is of course to prevent a huge spike of RF emissions at the clock frequency, which makes it way easier to get FCC certification.
This is an option in most modern bioses (spread spectrum) that is switched OFF by default
Bluetooth is what IRDA should have been.
Yes, and no. Bluetooth will do most things better than IRDA, except for one: directionality (if that is a word). I have a Palm, and to exchange info with another Palm user, you point both Palms at each other, and you go. I would not like my Palm to react to a broadcast of every other Palm in a range of 10 meters! Sometimes a disadvantage (you must aim for IRDA) can be an advantage.
The 68000 address registers were 32bit long, but only the lower 24 bit were used for addressing. Externally the chip had 23 pins, because it addressed words instead of bytes, and had 16 data pins. It could access 2^24 = 16MB
Correct for the 68000, but the original poster complained about the 68008, not the 68000.
The 68008 has only 20 or 22 address pins, and 8 data pins.
My comment on the 68000 series was only that it did not have a multiplexed data/address bus, as the original poster claimed.
The ancient Sinclair QL used a 68008, which could handle 32 bit addresses, and thus 4GB of memory, but only had an 8-bit combined address and data bus. It'd take 4 bus clocks to select an address, and another four to read/write a 32 bit value from/to the location.
I'm sorry to correct you, but the 68000 series of microprocessors does not have a combined address / data bus. The 68008 had a separate address bus of 20 or 22 pins, so it could directly address 1 or 4 MB of memory (depending on package)
> The majority of the loss is due to inductance
Although inductance is an impedance, i.e. it will limit the current that is transmitted at a specific voltage, it does so without loss.
The only loss through inductance is indirect. Power delivered is V*I*cos(phi), and thus diminishes when voltage and current are out of phase. Power lost is I*I*R, and thus independent of cos(phi). For the same power delivered, lowering cos(phi) will diminish efficiency, _as_long_as_there_is_R_! Without resistance, the cos(phi) will not matter!