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Relativistic Navigation Needed For Solar Sails

KentuckyFC writes "Last year, physicists calculated that a solar sail about a kilometer across with a mass of 300 kg (including 150 kg of payload) would have a peak acceleration of roughly 0.6g if released about 0.1AU from the Sun, where the radiation pressure is highest. That kind of acceleration could take it to the heliopause — the boundary between the Solar System and interstellar space — in only 2.5 years; a distance of 200 AU. In 30 years, it could travel 2500AU, far enough to explore the Oort Cloud. But the team has discovered a problem. Ordinary Newtonian physics just doesn't cut it for the kind of navigational calculations needed for this journey. Because the sail has to be released so close to the Sun, it becomes subject to the effects of general relativity. And although the errors these introduce are small, they become magnified over the course of a long journey, sending the sail roughly 1 million kilometers off course by the time it reaches the Oort Cloud. What these guys are saying is that if ever such a sail is launched (and the earliest estimate is 2040), the navigators will have to be proficient in a new discipline of relativistic navigation."

185 comments

  1. One word: by Anonymous Coward · · Score: 1, Insightful

    one word: computers.

    hurrrr.

    1. Re:One word: by Anonymous Coward · · Score: 0

      hurrrr.

      Brains?

    2. Re:One word: by Whalou · · Score: 1

      One word: Pilgrims.

      --
      English is not this .sig mother tongue...
    3. Re:One word: by spazdor · · Score: 1

      This was my first and second thought too. (The researchers will have to be proficient at running simulations, adjusting inputs, and running them again?)

      Hurrrr.

      --
      DRM: Terminator crops for your mind!
    4. Re:One word: by Kagura · · Score: 1

      Hmm, what is a 1km x 1km 2d-surface and weighs 150kg, with enough strength to withstand solar wind and the space environment?

      Probably just magical fabric...

  2. Computers? by Extremus · · Score: 4, Insightful

    the navigators will have to be proficient in a new discipline of relativistic navigation.

    Probably you are trying to say that the computers will have to be proficient in this new discipline.

    1. Re:Computers? by FooAtWFU · · Score: 4, Insightful

      Probably you are trying to say that the computers will have to be proficient in this new discipline.

      It's not that hard, either. Just math. We have the equations. They're well-understood. Some physics grad students could probably write the basic engine for such an endeavour. I'd worry more about $UNKNOWN_EXOTIC_EFFECT pushing something off-course.

      --
      The World Wide Web is dying. Soon, we shall have only the Internet.
    2. Re:Computers? by drseuk · · Score: 1, Funny

      Tough choice for NASA: Use MS Excel 2040 and end up a million km off course or use Linux and have the sail get where it's supposed to be for 1st January 1972. Simples!

    3. Re:Computers? by TooMuchToDo · · Score: 4, Insightful

      Even if you get pushed off course, you get to discover $UNKNOWN_EXOTIC_EFFECT =)

    4. Re:Computers? by sabt-pestnu · · Score: 3, Insightful

      I'd be more worried about simple things like...

      Kilometers-to-AU translation errors (nobody would be using "miles" in their calculations, now would they?)
      cumulative floating point rounding errors
      antenna positioning failure

      There are more than enough problems that could re-occur, before you start looking for new ones.

    5. Re:Computers? by maxwell+demon · · Score: 3, Informative

      Probably you are trying to say that the computers will have to be proficient in this new discipline.

      It's not that hard, either. Just math. We have the equations. They're well-understood. Some physics grad students could probably write the basic engine for such an endeavour. I'd worry more about $UNKNOWN_EXOTIC_EFFECT pushing something off-course.

      You mean, something like the Pioneer anomaly?

      --
      The Tao of math: The numbers you can count are not the real numbers.
    6. Re:Computers? by OwnedByTwoCats · · Score: 1

      The article sounds like it's extrapolating the peak 0.6g acceleration for the entire length of the flight. Seems to me that acceleration is proportional to the light flux trapped and/or reflected by the sail, which will fall off with the square of the distance from the sun. So you can't get to the Oort cloud in just a couple of years.

      What am I missing?

    7. Re:Computers? by OwnedByTwoCats · · Score: 2, Informative

      That's what I get for posting before whipping out the calculator. The acceleration needed to go 200 AUs in 2.5 years is only 9.5 E-3 meters/second. Or around .001g. I don't trust my calculus any more, but integrating the acceleration over that time is in the ballpark.

    8. Re:Computers? by Anonymous Coward · · Score: 0

      First, let me preface this by saying it has been 5-10 years since I've done any kind of serious study into solar sail tech... Because of the frictionless vacuum, the initial acceleration does not dissipate. I believe that what they're referring to as a peak 0.6g acceleration is the accumulated acceleration from the initial, tiny acceleration added together with the ever decreasing, but still positive acceleration as the sail moves farther away. The eventual acceleration for the entire trip would reach a peak of 0.6g, but would start at only a fraction thereof.

    9. Re:Computers? by Anonymous Coward · · Score: 0

      And who's going to stop you once you've got to 0.6g ? last time I've check there was no friction in vacuum.

    10. Re:Computers? by Pentium100 · · Score: 1

      a = F/m

      F = (the force with which sunlight pushes the sail) - (the force with which the sun pulls the sail back)

    11. Re:Computers? by tinkerton · · Score: 1

      A "new discipline" that is 100 years old.

    12. Re:Computers? by DerekLyons · · Score: 1

      Probably you are trying to say that the computers will have to be proficient in this new discipline.

      Computers can't do anything they haven't been programmed to to.

    13. Re:Computers? by interploy · · Score: 1

      If the navigators know how far the sail be off course by, why can't they adjust where they launch the sail to account for the drift?

    14. Re:Computers? by HTH+NE1 · · Score: 1

      Kilometers-to-AU translation errors

      How about just g to c translation errors?

      --
      Oh, say does that Star-Spangled Banner entwine / The myrtle of Venus with Bacchus's vine?
    15. Re:Computers? by HTH+NE1 · · Score: 2, Insightful

      And who's going to stop you once you've got to 0.6g ? last time I've check there was no friction in vacuum.

      "Once you've got to 0.6g"?

      g is acceleration! c is velocity!

      1g is the rate of acceleration due to gravity on Earth 9.8 m/s^2. 1c is the speed of light, 299,792,458 m/s.

      If you don't put in more energy, you're gonna stop accelerating, friction or no friction!

      --
      Oh, say does that Star-Spangled Banner entwine / The myrtle of Venus with Bacchus's vine?
    16. Re:Computers? by spazdor · · Score: 2, Insightful

      The ideal time to make that discovery is not when you're kissing the Sun from 0.1 AU away.

      Let's start with unmanned probes, hey?

      --
      DRM: Terminator crops for your mind!
    17. Re:Computers? by HTH+NE1 · · Score: 2, Informative

      (Damn summary.) G is acceleration. g is grams.

      1G is acceleration due to gravity at the surface of the Earth, 9.8 m/s^2.

      An object in motion will stay in motion unless acted on by an outside force.
      An object in acceleration will cease to be in acceleration when the outside force is removed. As the force reduces, the acceleration reduces.

      0.6G means if you stand with your head in the direction of acceleration, you'll weigh 3/5ths your weight on Earth.
      0.6c means you're moving 3/5ths the speed of light.

      --
      Oh, say does that Star-Spangled Banner entwine / The myrtle of Venus with Bacchus's vine?
    18. Re:Computers? by Antique+Geekmeister · · Score: 3, Informative

      It's a solar sail. Without significant solar thrust, it _will_ drag against the interstellar gas, and it's likely to gain mass as it does so.

    19. Re:Computers? by ByTor-2112 · · Score: 3, Interesting

      Pfft, and give up the chance to have an unknown exotic effect named after you? Small price to pay my friend! Did you think all those crazy radiations and particles from Star Trek were named after unmanned probes???

    20. Re:Computers? by Kagura · · Score: 1

      Thanks for the post. I was curious about that myself, without whipping out the calculator.

    21. Re:Computers? by bronney · · Score: 1

      Wesley! Quick!! The Picard Maneuver :)

      I wonder what happens when our sun no longer acts on it.

    22. Re:Computers? by rve · · Score: 1

      I'm a bit confused by the article too. What is so remarkable about this? All space travel, including satelites, has to take relativistic effects into account. Your GPS would be off by many miles if it didn't.

    23. Re:Computers? by Anonymous Coward · · Score: 0

      [Citation Needed]

    24. Re:Computers? by Anonymous Coward · · Score: 0

      I'd be more worried about simple things like...

      Kilometers-to-AU translation errors (nobody would be using "miles" in their calculations, now would they?)

      or kellicams..

    25. Re:Computers? by Anonymous Coward · · Score: 0

      Computers? I get that slashdot is a community of (mostly) IT folks.. but there seems to be a mistaken assumption that the whole world revolves around computers and s/w.
      some "expert" codes and everyone else just uses the code blindly? The real world is more than just "coding", and software is the last piece of the puzzle not the puzzle itself.

      wonder what the majority of slashdotters would do if they were stranded in a jungle..code their way out??

  3. You knew what this mission was when you signed up by Ryvar · · Score: 1, Offtopic

    The navigators? Correct me if I'm wrong, but isn't this a guaranteed one-way trip? For what possible reason would we use human pilots?

  4. One part in 37 million... by argent · · Score: 5, Insightful

    One million kilometers sounds like a big number, until you realize that 2,500 AU is 3.7 * 10^11 kilometers. So that error is one part in thirty seven million. I suspect that accumulated errors from variations in light intensity due to sunspots and flares will be a bigger problem.

    1. Re:One part in 37 million... by Anonymous Coward · · Score: 3, Informative

      You mean one part in 370,000, but on the whole you're right. The unfolding speed of the solar sail, or its random deformation during travel will have a higher impact. What a stupid article.

    2. Re:One part in 37 million... by Volante3192 · · Score: 1

      So, basically, we shouldn't expect Cassini style precision with this?

    3. Re:One part in 37 million... by mcvos · · Score: 1

      My thought exactly. Of course if we want this new probe to end up near a neighbouring star in 30,000 years, it really starts to add up. But over that time, chances are we'll have lots of other unknown and unexpected effects to correct for as well, so we're going to need to ability to adjust course during flight anyway.

      On the other hand, I don't think keeping track of relativistic effects is really going to be that big of an issue. It's not as intuitive as Newtonian physics, but we've got all the necessary math, right?

    4. Re:One part in 37 million... by CrimsonAvenger · · Score: 3, Insightful

      Unless we have some specific target in the Oort Cloud that we aim for at the beginning of the trip, with no course-corrections, this is pretty much meaningless.

      And with essentially unlimited ability to maneuver, course-corrections aren't going to be an issue, really.

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    5. Re:One part in 37 million... by argent · · Score: 1

      That's why you have in-flight course corrections. I think Cassini made several burns on the way to Saturn, as well as the circularizing burn once it got to the system.

    6. Re:One part in 37 million... by argent · · Score: 1

      You mean one part in 370,000

      Doh.

    7. Re:One part in 37 million... by Anonymous Coward · · Score: 1, Insightful

      I definitely agree. This article makes it look like relativity is some sort of thing that has just been discovered. This does not qualify as news and is a waste of my time. Seriously, I'm sure that the course will be set and run by computers, if it runs, and those will take into consideration something like that. Furthermore, if it were ever built, there would be control of it from earth. So if there are small corrections that need to be made or adjustments, I'm sure we can compensate...

    8. Re:One part in 37 million... by R2.0 · · Score: 4, Funny

      I would think that the Oort cloud itself would be the destination. Theoretically, the distribution of rocks is pretty even, so we should be able to get data no matter where in the cloud the probe goes. If it gets to that random point and finds either nothing, or a whole lot, we need to change the theory, don't we?

      Remember, Columbus set out to sail to the Indies, not land in Mumbai harbor. Of course, if we follow that example the probe will crash into Neptune and we'll declare it a new comet, but the general principle is the same.

      --
      "As God is my witness, I thought turkeys could fly." A. Carlson
    9. Re:One part in 37 million... by Idarubicin · · Score: 2, Informative

      And with essentially unlimited ability to maneuver, course-corrections aren't going to be an issue, really.

      I agree with the posts which note that the relative magnitude of the navigational error is trivial (a million kilometers in 2500 AU is the same relative error as one kilometer on a trip to the Moon). I also fully agree that any expedition to the Oort would be a random crapshoot anyway.

      I do have to quibble with the notion of 'essentially unlimited ability to maneuver', however. The amount of thrust available decreases with increasing distance from the sun. (Indeed, it falls off as the inverse square of the distance.) If our hypothetical sail starts off at 0.1 AU from the sun for maximum thrust, its acceleration will be down to 1% of its original value as it crosses the Earth's orbit, and less than 0.04% when it crosses Jupiter's orbit. At Pluto's orbit, the probe will be able to call on less than a hundred-thousandth the amount of sunlight it saw when it started. In other words, errors in course selection which take place early will accumulate for the longest, and will be most apparent when the least thrust is available for correction.

      --
      ~Idarubicin
    10. Re:One part in 37 million... by HiThere · · Score: 1

      Well, you could use a moon-based laser system to deliver the power for a mid-course correction. And laser power while also falling off as the square of the distance, can still fall off a lot more slowly. You'd need a hefty laser beyond appreciable atmosphere, which is why I said moon based (to allow for cooling). Asteroid based might be even better, but harder to build.

      Besides, if you build it on the far side of the moon no rogue faction can use it to threaten it's home country. But it could still shoot down incoming asteroids. (Shoot down is a bit imprecise. Ablate is better. Possibly changing the orbit so even if it isn't rendered too small to be dangerous, it's still no longer a threat.)

      --

      I think we've pushed this "anyone can grow up to be president" thing too far.
    11. Re:One part in 37 million... by Smoke2Joints · · Score: 1

      great idea. now if only we could fix the moon in place, so that the dark side is always pointing towards the probe...

    12. Re:One part in 37 million... by spazdor · · Score: 1

      If we built two ground-based lasers on the Moon's equator, each within a few degrees of longitude of the Earth border (but far enough to keep the Earth firmly in their blind spot) then we could have nearly month-round coverage, interrupted only while the probe is occupying that same blind spot.

       

      And then, of course, the terrorists and/or James Bond villains will hatch a plot to hijack a laser, build some hidden thrusters and change the angular momentum of the moon!

      --
      DRM: Terminator crops for your mind!
    13. Re:One part in 37 million... by CrimsonAvenger · · Score: 1

      great idea. now if only we could fix the moon in place, so that the dark side is always pointing towards the probe...

      Even if we could, why bother? One laser at any point on the Moon can fire at the lightsail half the time. At the low accelerations possible out in the deep dark, it'll take considerably more than a month in all likelihood, so the "burn" will take place in two or more parts over several months (or years).

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    14. Re:One part in 37 million... by CrimsonAvenger · · Score: 1

      I do have to quibble with the notion of 'essentially unlimited ability to maneuver', however. The amount of thrust available decreases with increasing distance from the sun. (Indeed, it falls off as the inverse square of the distance.) If our hypothetical sail starts off at 0.1 AU from the sun for maximum thrust, its acceleration will be down to 1% of its original value as it crosses the Earth's orbit, and less than 0.04% when it crosses Jupiter's orbit. At Pluto's orbit, the probe will be able to call on less than a hundred-thousandth the amount of sunlight it saw when it started. In other words, errors in course selection which take place early will accumulate for the longest, and will be most apparent when the least thrust is available for correction.

      Thirty year trip. The relativistic elements of the orbit will be non-issues by the time the lightsail is one AU from the sun.

      Assume we take another year after that time to decide on a course-change. We have twenty-nine more years to change the orbit.

      Assume further that the orbit really is off course by 1 Gm at a distance of 2500 AU. That means deltaV required to get back into design groove is about 1 m/sec. At one millionth of a gravity acceleration, that "burn" will take around two weeks.

      In other words, the problem is trivial.

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    15. Re:One part in 37 million... by khallow · · Score: 2, Informative

      Unless we have some specific target in the Oort Cloud that we aim for at the beginning of the trip, with no course-corrections, this is pretty much meaningless.

      Why call it the "Oort Cloud" if there's nothing in it? My view is that such solar sails would be first used for Kuiper Belt targets and the heliopause (the latter not needing trajectory accuracy aside from making sure the probe heads away from the Sun). Later as we discover targets in the Oort cloud to investigate, probes could be sent out in this way. It's also good for interstellar missions. These velocities provide a good first stage boost. Accurate trajectories might greatly reduce the propellant consumed to correct the trajectory to another star.

    16. Re:One part in 37 million... by Anonymous Coward · · Score: 0

      I don't understand the problem, every other spacecraft has had to do mid-course corrections in order to arrive at the right place at the right time. Why is this any different?

    17. Re:One part in 37 million... by TheTurtlesMoves · · Score: 1

      You don't have unlimited ability to maneuver unfortunately. Thrust goes down with 1/r2 from the sun. So once you are out past Jupiter you have almost all of your momentum vector fixed, and no thrust left to change it (thrust is down by a factor of 2500). Gravity maneuver would be about the only thing that would work after that. Even then, you are moving really fast and that on its own reduces the ability to maneuver.

      --
      The Grey Goo disaster happened 3 billion years ago. This rock is covered in self replicating machines!
    18. Re:One part in 37 million... by CrimsonAvenger · · Score: 1

      You don't have unlimited ability to maneuver unfortunately. Thrust goes down with 1/r2 from the sun. So once you are out past Jupiter you have almost all of your momentum vector fixed, and no thrust left to change it (thrust is down by a factor of 2500). Gravity maneuver would be about the only thing that would work after that. Even then, you are moving really fast and that on its own reduces the ability to maneuver.

      Let's see. No reaction mass required for acceleration. Sounds unlimited to me. Yah, the acceleration is piss-poor out there in the deep dark, but the acceleration isn't going away until and unless the sail is shredded.

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    19. Re:One part in 37 million... by CrimsonAvenger · · Score: 1

      Why call it the "Oort Cloud" if there's nothing in it? My view is that such solar sails would be first used for Kuiper Belt targets and the heliopause (the latter not needing trajectory accuracy aside from making sure the probe heads away from the Sun). Later as we discover targets in the Oort cloud to investigate, probes could be sent out in this way. It's also good for interstellar missions. These velocities provide a good first stage boost. Accurate trajectories might greatly reduce the propellant consumed to correct the trajectory to another star.

      Nobody ever said there was nothing in the Oort Cloud. But we're not going to be sending a lightsail out to the Oort Cloud to do more than fly past an Oort Cloud object really fast. Like 500+ km/sec fast.

      And no, it's not particularly useful for interstellar missions. We're still talking about 2000+ years to make an interstellar jump. Note that the deltaV we're talking about for this lightsail is higher (but not much higher) than a similar amount of reaction mass being pushed out of a VASIMR or ion drive that we can build right now. In other words, by the time we get ready for interstellar trips at any reasonable speed (~10% c), this particular technology will be essentially useless.

      Also, let us consider that hypothetical interstellar trip, and the inaccuracy of this proposed system. We have an expected error of 1 Gm in 2500 AU. Alphacent is about 270000 AU away. So this vehicle would be about 110 Gm off course by the time it reached Alphacent, absent relativistic corrections to its course. 110 Gm is rather less than one AU (150 Gm), so I doubt seriously we'll be really hard put to call that a trajectory requiring massive course corrections.

      Again, remember that the relativistic effects only apply during the first very small part of the acceleration of the lightsail. By the time the lightsail reaches one AU from Sol, we'll be back to flat enough space that Newtonian approximations will suffice. And that leaves us (hypothetically) 2499 AU to make a 1 m/s course correction to get back in the groove.

      Note that if we had a conventional rocket onboard to make such corrections, it would require about 100 grams of reaction mass to make the required correction. And that's the worst possible case - letting the lightsail do the work is a trivial two-week correction done anywhere out to 100 AU....

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    20. Re:One part in 37 million... by khallow · · Score: 1

      Nobody ever said there was nothing in the Oort Cloud. But we're not going to be sending a lightsail out to the Oort Cloud to do more than fly past an Oort Cloud object really fast. Like 500+ km/sec fast.

      Right. But that does count as an example.

      And no, it's not particularly useful for interstellar missions. We're still talking about 2000+ years to make an interstellar jump. Note that the deltaV we're talking about for this lightsail is higher (but not much higher) than a similar amount of reaction mass being pushed out of a VASIMR or ion drive that we can build right now. In other words, by the time we get ready for interstellar trips at any reasonable speed (~10% c), this particular technology will be essentially useless.

      Supposedly, the upper limit for solar sails in this sort of trajectory is 0.01c which is 10% of your desired "reasonable" speed. And you can always illuminate the vehicle at a later time to increase the speed. Still I am a bit surprised to find that for this sort of trajectory solar sails play by the same rules (delta v versus mass fraction trade off) as propellant-based propulsion systems.

      Also, let us consider that hypothetical interstellar trip, and the inaccuracy of this proposed system. We have an expected error of 1 Gm in 2500 AU. Alphacent is about 270000 AU away. So this vehicle would be about 110 Gm off course by the time it reached Alphacent, absent relativistic corrections to its course. 110 Gm is rather less than one AU (150 Gm), so I doubt seriously we'll be really hard put to call that a trajectory requiring massive course corrections.

      Excellent point.

    21. Re:One part in 37 million... by TheTurtlesMoves · · Score: 1

      At Jupiter is 2500 time less than when you started. At neptune is 90000 time less. So at neptune an corrected that would take a day, now takes 90000 days or 246 years! You are already past the Ort cloud before your even though 2% of the maneuver, Oh and the sun is still getting dimmer! At the Ort cloud the force is 600 million times less.

      Turns out that Since you are traveling away from the sun, the *total* impulse that the sail can provide is *finite*. And its almost useless past Jupiter...

      This is published research. I'm not making this up.

      --
      The Grey Goo disaster happened 3 billion years ago. This rock is covered in self replicating machines!
    22. Re:One part in 37 million... by CrimsonAvenger · · Score: 1

      So at neptune an corrected that would take a day, now takes 90000 days or 246 years! You are already past the Ort cloud before your even though 2% of the maneuver, Oh and the sun is still getting dimmer! At the Ort cloud the force is 600 million times less.

      The error specified in TFA was 1,000,000 km at 2500 AU. Course correction required to recover from that error is about 1 m/sec. Which can be corrected quite nicely at about the orbit of Neptune by a "burn" that takes about four hours, based on your 90000x smaller acceleration. So if we started the "burn as we reached Neptune's orbit, we'd cover about five times the distance from Earth to Luna during the "burn".

      I fail to see the issue. Yes, the acceleration continues to decrease. But it never decreases to zero, so your deltaV is still essentially infinite.

      I think you are so dazzled by the tiny numbers involved in measuring acceleration of a lightsail in the deep dark that you're overlooking completely that the numbers attached to the hypothetical course correction are also very tiny numbers.

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    23. Re:One part in 37 million... by Anonymous Coward · · Score: 0

      And laser power while also falling off as the square of the distance, can still fall off a lot more slowly

      There's nothing magical about coherent light with respect to the inverse square law for area. However, the inverse square law only applies to point source ominidirectional radiators (i.e. that emit the same power in all directions) in free space in flat spacetime. A non-omnidirectional radiator in the same environment only obeys a constant wattage per solid angle (W/Sr^2, Sr being steradian). (The omnidirectional radiator *also* obeys a constant W/Sr^2, but the area of a solid angle increases as the radial distance from the source increases).

      High collimation means that the solid angle (Sr) subtended by the beam is very small, and so the area (in m^2) remains small even as the radial distance (in m) becomes large. So, W/m^2 remains high at high distances. This is a useful feature for communication, and also for avoiding energy loss.

      The problem with a laser source is that most manufactured lasers will use relatively low energy (that is, low frequency, or long wavelength) photons. As the momentum carried by a photon follows the Einsteinean equation E^2 = p^2c^2 + m^2c^4 (so p, momentum, is p = E/c), and the Energy of a photon relates to its wavelength lambda as E = hbar c / lambda, lasers in the micrometre wavelengths transfer very little momentum per photon. One could use a large flux, or one could try to design a useful lower-frequency laser, for the moon installation, of course.

      We can assume that interplanetary space is relatively free in the sense of having relatively little gas, dust, and other objects to absorb, scatter, Beer-shift or reflect the laser light.

      We cannot assume that interplanetary space has flat spacetime. Indeed, we can prove a small (5 millisecond) gravitational time dilation for all photons leaving the surface of the moon for interplanetary space; this is seen as a redshift by observers at the higher gravitational potential (away from the moon). The redshift -- an increase in frequency -- represents a per-photon decrease in energy, and consequently momentum. Likewise, the gravitational potential here, close to the sun, is much lower than at high radiuses from the sun, towards the Oort cloud. This again means that photons reaching the probe will have lost significant momentum.

      Likewise, there is a Lorentz contraction as the probe accelerates with respect to the surface of the moon, that will also be seen by the probe as a per-photon loss of substantial energy as the probe accelerates outwards.

      Naturally one can add more photons or use lower frequency photons or both as the probe is in flight, but understanding this requires understanding general relativity.

      You'd need a hefty laser beyond appreciable atmosphere

      Hefty laser, not necessarily, since you may want only small (but constant, subject to relativistic effects) acceleration felt by the probe.

      Atmosphere? Depends on the wavelength of the laser; the Earth's atmosphere is highly transparent at some wavelengths (that is, after all, how we see!).

      Besides, if you build it on the far side of the moon no rogue faction can use it to threaten it's home country

      You complicate power delivery and maintenance putting it there.

      You also dramatically constrain the times at which you have a line-of-sight to the probe, which may be a problem.

      Any "rogue faction" capable of taking over a lunar installation has better weapons available than a laser that might be a few kW or maybe even a few MW. Not to mention that the *main* advantage for being on the moon is using photon frequencies that are highly absorbed by Earth's atmosphere, which would work shooting "down" at terrestrial targets, just like shooting "up" at the probe.

      But it could still shoot down incoming asteroids. (Shoot down is a bit imprecise. Ablate is b

    24. Re:One part in 37 million... by Anonymous Coward · · Score: 0

      Doh, both W/Sr^2 is W/Sr.

  5. Wont the accleration decrease with distance by Anonymous Coward · · Score: 0

    I may be being daft here but wont that acceleration slow with distance from the sun? Does the math stack up?

    1. Re:Wont the accleration decrease with distance by UnHolier+than+ever · · Score: 3, Insightful

      The acceleration, yes, but not the speed. That is why the sail has to start so close ot the sun, it needs it to accumulate most of its speed.

      The reall question will be: how does it stops? I doubt it can use the gravitational slingshot trick at these speeds using only comets.

    2. Re:Wont the accleration decrease with distance by HoboCop · · Score: 1

      Maybe it won't stop.. after it passes whatever it was aimed at it will just keep sending data and traveling until it dies. Power problem? I guess those mars rovers are doing ok with solar.

    3. Re:Wont the accleration decrease with distance by mcvos · · Score: 1

      Power problem? I guess those mars rovers are doing ok with solar.

      Except solar isn't going to help you much at 2500 AU.

    4. Re:Wont the accleration decrease with distance by jeffb+(2.718) · · Score: 1

      Unless you can arrange for that 1km^2 solar sail to also be a solar cell, in which case you'd still be intercepting around a hundred watts. Good luck making a 1km^2 solar cell that masses less than 100kg, though.

    5. Re:Wont the accleration decrease with distance by jeffb+(2.718) · · Score: 2, Informative
    6. Re:Wont the accleration decrease with distance by GlobalEcho · · Score: 1

      The reall question will be: how does it stops? I doubt it can use the gravitational slingshot trick at these speeds using only comets.

      It's a solar sail, right? It can just luff up.

      (kidding)

    7. Re:Wont the accleration decrease with distance by Anonymous Coward · · Score: 1, Interesting

      No, the real question is HOW ARE WE GOING TO GET THE SOLAR SAIL THERE. .1 AU from the sun? How hot is that? And dragging the solar sail all the way there will take a fair amount of energy, no?

      Something I've always wondered about solar sails is, can they go towards the sun or what?

    8. Re:Wont the accleration decrease with distance by UnHolier+than+ever · · Score: 1

      Ok, but it will go very fast by then. If we're going to send a probe to the Oort cloud, I'd like it to be able to observe anything it finds for more than 10 minutes.

  6. Re:You knew what this mission was when you signed by SBrach · · Score: 2, Funny

    They are relatively better at the calculations??

  7. Sailing in Space by ZanzibarZero · · Score: 1

    Maybe NASA should start recruiting some America's Cup skippers...

    1. Re:Sailing in Space by Anonymous Coward · · Score: 0

      I'm not talkin' about pleasure boatin' or daily sailin'. I'm talkin' about workin' for a livin'. I'm talkin' about probin'!

  8. Shouldn't this be irrelavent... by Churla · · Score: 2, Funny

    Wouldn't this be completely besides the point as long as we keep enough spice in their tanks? They can always just think their way back on course.

    --
    I'm a fiscal conservative, it's a pity we don't have a political party anymore
    1. Re:Shouldn't this be irrelavent... by el_tedward · · Score: 1

      What if the terrorists decide to poison all of our sandworms with water of life? We'll run out of spice and be totally fucked. Nothing against using spice, but I think we should develop the navigational computers just in case.

    2. Re:Shouldn't this be irrelavent... by Duradin · · Score: 1

      Until we find out that someone has parked No-ships in the cloud...

    3. Re:Shouldn't this be irrelavent... by jamstar7 · · Score: 1

      What if the terrorists decide to poison all of our sandworms with water of life? We'll run out of spice and be totally fucked. Nothing against using spice, but I think we should develop the navigational computers just in case.

      Should be some sandtrout around someplace we can genetically modify a bit to live in oceans...

      --
      Understanding the scope of the problem is the first step on the path to true panic.
  9. What else is new? by jarocho · · Score: 5, Interesting

    Pioneer 10 has been off-course for a while now. Maybe the trick for reaching the Oort Cloud is to aim for 1 million kilometers to the left.

    1. Re:What else is new? by Anonymous Coward · · Score: 0

      Or throw the probe at the sun ... and miss.

    2. Re:What else is new? by drseuk · · Score: 1

      Oblig:

      Commander Pavel Chekov: Course heading, Captain?

      Captain James T. Kirk: Second star to the right and straight on 'til morning.

      http://www.imdb.com/title/tt0102975/quotes

    3. Re:What else is new? by jtownatpunk.net · · Score: 1

      Should have taken that left turn at Albuquerque.

    4. Re:What else is new? by Anonymous Coward · · Score: 0

      Followed shortly by, the shields can't take this kind of heat cap'n you'll have to go 'round the freakin' ball of gas...

  10. Is this that important? by MiniMike · · Score: 5, Insightful

    sending the sail roughly 1 million kilometers off course by the time it reaches the Oort Cloud.

    Is there a specific part of the Oort Cloud they want to go to?
    If this ability is needed to travel to other planets accurately, then it seems important. For the Oort cloud, not as much.

    .

    Will this solar sail be going at a speed that will allow it to do any useful observations, or are we just going to watch for the flash when it 'finds' something at that speed?

    1. Re:Is this that important? by physburn · · Score: 1
      I doubt it will be easy to get the solar sail within 0.1 AU of the Sun, that is very close, and will need a lot of energy to begin will. Apart from the relativistic course correction need to nagivate (which isn't that numerically difficult), the sail will have to deal with variation in the amount of Sun light and Solar wind, coming towards the Sail, which may vary at random, and be much more difficult to nagivate with. Good luck to Solar Sailors.

      ---

      Space Craft Feed @ Feed Distiller

    2. Re:Is this that important? by 4D6963 · · Score: 1

      Well, if it's a sail, maybe it can just slow itself down from an Earth-level Sun orbit until it gets lower, then flip 90Â to face the Sun and then get pushed away?

      --
      You just got troll'd!
    3. Re:Is this that important? by Rich0 · · Score: 1, Interesting

      The only force acting on a solar sail is outwards from the sun. If the sail is angled the force would be reduced (less cross-sectional area), but the direction of the force would remain the same. A sailboat can only turn because it has a keel that exerts force against the relatively-motionless water normal to its direction of motion. There is nothing to push against in space.

      The only way to move in a direction other than away from the sun is to employ alternate propulsion, or to somehow find another source of light (such as the concept of getting sunward force by detaching a reflector that bounces sunlight back at the far side of the sail). Keeping everything aligned would be very tricky.

    4. Re:Is this that important? by Ungrounded+Lightning · · Score: 2, Informative

      Wrong.

      The solar wind force is essentially outward (in the solar wind direction) only. (The particles initially stick to the sail and then are released, if at all, by a different mechanism such as electrostatic repulsion.) And the portion of the light that is absorbed by the sail also produces an outward force.

      But for a mirror-finished solar sail the portion of the light that is reflected (most of it) gives the vector sum of the momenta of its arrival and the recoil of its departure. So tilting the sail to reflect sunlight forward along the direction of orbit gives a strong deceleration and lowers the orbit.

      --
      Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
    5. Re:Is this that important? by Ungrounded+Lightning · · Score: 1

      The solar wind force is essentially outward (in the solar wind direction) only. (The particles initially stick to the sail and then are released, if at all, by a different mechanism such as electrostatic repulsion.)

      Or penetrate it and deposit momentum from drag averaging out to be along their incoming direction of travel.

      --
      Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
    6. Re:Is this that important? by 4D6963 · · Score: 1

      No I'm not sure you get what I was proposing. The idea was to orient the sail so it offers virtually no cross section to the solar wind, and let the atmospheric drag do the job of slowing down its orbit so that it can descend.

      --
      You just got troll'd!
    7. Re:Is this that important? by videoBuff · · Score: 1

      sending the sail roughly 1 million kilometers off course by the time it reaches the Oort Cloud.

      Is there a specific part of the Oort Cloud they want to go to?

      May be they are worried aiming antenna on spaceship properly? Some signal or other should reaches earth from that antenna for an expedition to have some value (at least for earth bound folks).

    8. Re:Is this that important? by jamstar7 · · Score: 1

      I doubt it will be easy to get the solar sail within 0.1 AU of the Sun, that is very close, and will need a lot of energy to begin will.

      Takes just as much energy as a solid capsual, actually. Just don't deploy the sail til you get there...

      --
      Understanding the scope of the problem is the first step on the path to true panic.
    9. Re:Is this that important? by nahdude812 · · Score: 1

      Wouldn't the propulsion surface of the sail be black to absorb the energy of the light rather than reflect it away having received none of its energy? Photons do not have mass, merely causing the photon to collide and bounce off of the mirror surface should not transfer any energy (the speed of the photon has not been altered as it's still traveling at 1c, thus no transfer of energy).

      If the surface is black, the energy of the photon is absorbed, and as that surface heats up, it will radiate this energy in the opposite direction producing thrust. You can still steer, because the thrust vector will be along the normal of the surface of the sail.

    10. Re:Is this that important? by nahdude812 · · Score: 1

      It's my understanding that the thrust in a solar sail is not from the collision of photons against the sail (in ocean sailing, thrust is the transfer of momentum from the air molecules to the sail, mast, and ultimately body of the ship). Although photons have momentum, they do not have mass, so no meaningful acceleration can be acquired in this way.

      Instead, in solar sailing thrust is produced by absorbing the energy of the photons (not the momentum), and radiating it in the opposite direction (eg in the form of thermal energy).

      As such, the thrust vector would be along the normal of the surface of the sail. The direction of the sail is thus the direction of the thrust. But (like ocean sailing) the more you angle your sail away from the energy source, the smaller the effective cross-sectional area, and thus the less energy is absorbed. Unlike ocean sailing, you would not be able to meaningfully tack into the wind because it is this which relies on using water to convert the angle of momentum. In space, you can orient your thrust, but you cannot orient it opposite to your energy source.

    11. Re:Is this that important? by Rich0 · · Score: 1

      Hadn't even thought about this. Sure, that would work, although I can't imagine the solar atmospheric density at 0.1-1 AU is all that large. You'd also need to start breaking out of the dive well before 0.1AU since you don't have much thrust, but that wouldn't be a problem with the idea at all.

      You'd just need lots of patience...

    12. Re:Is this that important? by Ungrounded+Lightning · · Score: 1

      Photons have inertia and momentum. (Though they have no rest mass their energy is equivalent to mass and they cause recoil when they interact with other matter.)

      You're not trying to "absorb energy" with a solar sail (which would just heat it - and melt it if you get too close to the sun). You're trying to collect momentum. You get just as much momentum from the recoil when a photon leaves as you get from capturing it when it lands.

      So if you reflect the incoming sunlight you get twice as much momentum from it. And while the direction of the momentum from the incoming light is fixed, you get to pick the direction of the outgoing light - and thus the direction of its recoil thrust.

      --
      Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
    13. Re:Is this that important? by 4D6963 · · Score: 1

      Yeah, it might take forever to go that far down, I mean even if you could stop dead from your 1 AU orbit it'd still take about two months to fall down to 0.1 AU, but well I guess it depends a lot on the sail. But yeah, that surely wouldn't be anywhere practical. Plus I wonder, doesn't solar wind/atmosphere "rotate" too? Probably follows the Sun's 25 day rotation to a certain degree?

      --
      You just got troll'd!
    14. Re:Is this that important? by nahdude812 · · Score: 1

      I'll be the first to admit that I'm a big amateur at this stuff, but what you're saying differs from my understanding of the principles involved, including Carnot's law and Newton's laws of thermodynamics. What you're suggesting would result in a closed system which has a higher energy state as it progresses through time (thus be grounds for a perpetual motion machine).

      If the photon leaves the surface of the mirror with the same energy as it had when it collided with it, then how can the sail be in a higher energy state after the fact?

      This article was extremely useful to me, talking deeply about the actual physics involved, and covering the common misconceptions regarding solar sails: http://arxiv.org/html/physics/0306050.

      In order to accelerate a body, you need thrust. Thrust requires energy. Radiation or particles of any sort which leave a surface at the same energy level as they arrived have not imparted any energy, thus no thrust, and therefore no acceleration. So yes, you are trying to absorb energy in a very real sense.

      Radiative momentum is not like Newtonian momentum. It is a scalar defined as E/c (E being scalar and c being a constant) and not a vector.

      From the article I linked above: "If the body is a perfect mirror or reflector of all incident energy, instead of a black body, then the energy absorbed is zero and so the radiation pressure is zero also. The same is true for any body, when it has reached temperature equilibrium with the radiation to which it is exposed."

      The energy of a closed system is fixed. If you consider the closed system to be the light over a certain time period plus the solar craft, then it's clear that this system by itself cannot produce thrust on the craft except that you have converted energy from the light into thrust in some way. If there is thrust, and the solar energy which interacted with the craft has not changed in energy state, then the system was not closed, and the thrust came from somewhere else.

  11. Re:You knew what this mission was when you signed by Anonymous Coward · · Score: 0

    It's called ground control, major Tom.

  12. Manuvering system for a sail..... by jameskojiro · · Score: 3, Interesting

    Would that be an RTG powered ion thruster? or do you make holes in the sail that are opened and closed by tiny articulated motors?

    --
    Tsukasa: All I really want, is to be left alone...
    1. Re:Manuvering system for a sail..... by TooMuchToDo · · Score: 1

      No need for holes in the sail, you just articulate the sail itself.

    2. Re:Manuvering system for a sail..... by Anonymous Coward · · Score: 0

      Yep - shorten the cables holding the sail on one side, and it's now asymmetric, and changing your course. Similar solutions have existed since early sailing vessels.

  13. Time to get out the spice... by haggishunk · · Score: 1

    can't let these danged computers do everything for us!

    1. Re:Time to get out the spice... by Anonymous Coward · · Score: 0

      I think that only works when you fold space... but since we'd be sailing through space, maybe spice rum would be more appropriate?

  14. Mid-course corrections? by vrmlguy · · Score: 4, Insightful

    No space craft has ever been aimed accurately. At various times during the mission, you look at where you are and where you're supposed to be, and make a correction to your trajectory. Is there some reason why this won't work with a solar sail?

    --
    Nothing for 6-digit uids?
    1. Re:Mid-course corrections? by clintp · · Score: 2, Informative

      And isn't starting at the Sun and aiming for a point in the Oort cloud complicated by the N-body problem anyway? Course corrections will have to be done for the entire trip because of all of those large chunks of rock and gas floating around. Gravity's a bitch, man.

      --
      Get off my lawn.
    2. Re:Mid-course corrections? by autocracy · · Score: 2, Interesting

      It can't work like a sailboat does... steering partly into the wind, or changing the sail angle to alter the thrust exerted. There's no resistive force to work against, so it just kind of goes where it is taken.

      --
      SIG: HUP
    3. Re:Mid-course corrections? by Volante3192 · · Score: 1

      With most probes they're pretty compact, small thruster bursts will do a lot.

      How do you tack a solar sail though?

    4. Re:Mid-course corrections? by mcvos · · Score: 1

      And isn't starting at the Sun and aiming for a point in the Oort cloud complicated by the N-body problem anyway?

      Not really. The Oort cloud isn't exactly small. Just keep flying away from the sun and you'll get there eventually.

    5. Re:Mid-course corrections? by fenring · · Score: 1

      And how do you know where you are if your compass isn't working properly?

    6. Re:Mid-course corrections? by SBrach · · Score: 1

      You can call a U-turn a mid-course correction but it is still best to start off pointed in the correct direction.

    7. Re:Mid-course corrections? by onkelonkel · · Score: 2, Interesting

      Why not? Reel in the shrouds on one side and lengthen them on the other and the whole sail is tilted with respect to the capsule, and you start to change course. You can't tack (I think) but a broad reach should work.

      --
      None of them can see the clouds; The polished wings don't care.
    8. Re:Mid-course corrections? by WhiteDragon · · Score: 3, Informative

      It can't work like a sailboat does... steering partly into the wind, or changing the sail angle to alter the thrust exerted. There's no resistive force to work against, so it just kind of goes where it is taken.

      However, tacking with the solar sail is still possible.

      --
      Did you mount a military-grade, variable-focus MASER on an unlicensed artificial intelligence?
    9. Re:Mid-course corrections? by jpmorgan · · Score: 3, Insightful

      Of course there's resistive force. It's called gravity and most people, when they think about space travel, vastly underestimate it's strength.

      Do not forget for one instant that your solar-sailship is in orbit around something. You aren't using your solar sail to overcome the sun's gravity and drift off into the outer reaches of the solar system... there's a term what happens when a star is generating enough radiation pressure to overcome its own gravity: a supernova. Travel by solar sail (and any other modern propulsion system) is based on giving a gentle nudge to your orbit so that eventually you swing by where you want to be.

    10. Re:Mid-course corrections? by clintp · · Score: 1

      And isn't starting at the Sun and aiming for a point in the Oort cloud

      Not really.

      You missed the point. Hitting any part of the Oort cloud is easy. Trying to hit any particular point in space without course corrections is unbelievably hard, unless it's a really deep and small gravity well....

      --
      Get off my lawn.
    11. Re:Mid-course corrections? by vrmlguy · · Score: 1

      With most probes they're pretty compact, small thruster bursts will do a lot.

      How do you tack a solar sail though?

      http://www.ugcs.caltech.edu/~diedrich/solarsails/intro/tacking.html

      --
      Nothing for 6-digit uids?
    12. Re:Mid-course corrections? by khallow · · Score: 2, Informative

      Of course there's resistive force. It's called gravity and most people, when they think about space travel, vastly underestimate it's strength.

      Gravity is not a resistive force. A resistive force is a force that acts opposite the motion of a moving object. Gravity is an attractive force between masses independent (in the Newtonian model in which it exists) of the motion of the masses. I think GR has an extremely weak resistive force in that gravity waves carry away some energy from masses moving near one another.

    13. Re:Mid-course corrections? by TheTurtlesMoves · · Score: 1

      As i just stated previously. Once you are as far out as Jupiter the you have 2500 times less thrust but have 99% (or even 100%) of you max velocity. You need to get it right close to the sun where you have less momentum and more thrust.

      --
      The Grey Goo disaster happened 3 billion years ago. This rock is covered in self replicating machines!
    14. Re:Mid-course corrections? by mcvos · · Score: 1

      You missed the point. Hitting any part of the Oort cloud is easy. Trying to hit any particular point in space without course corrections is unbelievably hard, unless it's a really deep and small gravity well....

      Of course, but the Oort cloud is really big, and we have no idea what different parts of it look like. We have (as far as I know) no idea which parts of the Oort cloud are more interesting than other parts. So what does it matter which part of the Oort cloud we're going to hit?

    15. Re:Mid-course corrections? by autocracy · · Score: 1

      With respect to the capsule, yes. Without a resistive force to hold the capsule relatively in place, though, I think the expected result is that the capsule would be pulled relative to the sail. The fin of a sailboat in the water is a key part of being able to turn the boat. The water resists lateral motion. Nothing like that is available in space.

      --
      SIG: HUP
    16. Re:Mid-course corrections? by Anonymous Coward · · Score: 0

      You're kind of missing the point. It's not about the solar sail, it's about the speed. Questions like "where you are and where you're supposed to be" are not so simple once Einstein takes the wheel from Newton.

  15. Just how big is the Oort Cloud? by Eevee · · Score: 4, Funny

    From Wikipedia, "The Oort cloud is a hypothetical spherical cloud of comets which may lie roughly 50,000 AU, or nearly a light-year, from the Sun." So...um...how do you miss it? You go straight out in any direction. When you see a lot of icy chunks floating around, you're there.

    1. Re:Just how big is the Oort Cloud? by Minwee · · Score: 3, Informative

      So...um...how do you miss it? You go straight out in any direction. When you see a lot of icy chunks floating around, you're there.

      I think that watching The Empire Strikes Back may have given you the wrong idea about just how densely packed objects like asteroids and comets are in our solar system.

      Consider this. Get your own envelope and pencil if you want to follow along at home. The inner boundary of the Oort cloud is at about 5,000 AU, or 750 billion km from the Sun. The outer boundary is expected to be somewhere around 100,000 AU or 1500 billion km. Inside that volume are an estimated twelve billion objects. Nobody has been able to count them, but Jan Oort guessed that there would be that many and no astronomer has been able to contradict him yet.

      That gives us a total volume on the order of 10^28 km^3, with just 12,000,000,000 objects in it. That's 10^18 km^3 for each object, giving you an average distance between objects of at least a million kilometers. A million km is three times the distance from the Earth to the Moon, and the size of a cometary nucleus is on the order of ten km. You'd be lucky just to see a 10 km object at that distance, let alone see it well enough to justify the trip out there.

      That means that if you're aiming for an object in the Oort cloud but miss by up to a million km, you're going to sail right through empty space. You won't narrowly dodge between densely packed cometary bodies, rolling and weaving to avoid laser blasts, and then have to hide inside the belly of a giant space worm while the Empire searches for you. You'll just pass on by and miss everything.

      Real astronomy isn't nearly as exciting as Star Wars, but that's probably good news for everyone who lives in our galaxy.

    2. Re:Just how big is the Oort Cloud? by Anonymous Coward · · Score: 2, Interesting

      Actually, if they're roughly a million km apart, and you miss one by a million km... you're in the vicinity of another one.

      Now missing by *half* a million km... that'd suck.

    3. Re:Just how big is the Oort Cloud? by fuzzyfuzzyfungus · · Score: 2, Funny

      Asteroids do not concern me, Minwee. I want that ship, not excuses.

    4. Re:Just how big is the Oort Cloud? by larry+bagina · · Score: 3, Insightful

      No one has contradicted him? More like no one has any evidence whatsoever that there is an oort cloud, much less that his guess is right or wrong.

      --
      Do you even lift?

      These aren't the 'roids you're looking for.

    5. Re:Just how big is the Oort Cloud? by Anonymous Coward · · Score: 0

      But our telescopes can't see the Oort cloud objects anyway and hence it is hypothetical. So we don't have anything to aim at.

    6. Re:Just how big is the Oort Cloud? by maxume · · Score: 1

      My envelope says the volume is on the order of 10^40 km^3. Copy this into Google:

      (4/3 * pi * (100000 astronomical units)^3) - (4/3*pi*(5000 astronomical units)^3) -> cubic kilometers

      Or should I not be modeling the volumes as spheres and subtracting the smaller from the larger? If the 100,000 in your post is a typo and supposed to be 10,000, using spheres still gives 10^37 km^3. Either of those does interesting things to your estimate of the distances between objects.

      So I'm curious how the volume is actually modeled on your envelope there.

      --
      Nerd rage is the funniest rage.
    7. Re:Just how big is the Oort Cloud? by Quarters · · Score: 1

      "Rel astronomy isn't nearly as exciting as Star Wars..." Star Wars was about astronomy? Man, I *really* missed the point of those movies.

    8. Re:Just how big is the Oort Cloud? by mldi · · Score: 1

      No one has contradicted him? More like no one has any evidence whatsoever that there is an oort cloud, much less that his guess is right or wrong.

      Not only that, but if there is an Oort cloud, according to the Wikipedia entry, it "may lie roughly 50,000 AU, or nearly a light-year, from the Sun."

      2,500AU != 50,000AU? Someone put a decimal point in the wrong place or what?

      --
      If you aren't suspicious of your government's actions, you aren't doing your job as a responsible citizen.
    9. Re:Just how big is the Oort Cloud? by Anonymous Coward · · Score: 0

      That means that if you're aiming for an object in the Oort cloud but miss by up to a million km, you're going to sail right through empty space.

      The problem being that we don't even know if the Oort Cloud even exists, much less where any individual object in it is (or will be when the sail passes it). One would have to design the ship to survey as large a volume as possible, i.e. not travel radially out of the solar system, but instead pass through the Oort Cloud for as long as possible.

  16. Re:You knew what this mission was when you signed by MaerD · · Score: 1

    Colonization?

    --
    I put on my robe and wizard hat..
  17. Much ado about nothing by djcinsb · · Score: 2, Informative

    It's more likely that the flight engineers would just add course corrections in (i.e. change the sail orientation to redirect the force) if they had a specific target in the Oort cloud in mind.

    Just as small errors due to GR get magnified over the long trajectory, so do small corrections get magnified if made early enough. And, as one earlier commenter noted, a million km isn't much of anything at these distances.

    --
    A signature always reveals a man's character - and sometimes even his name. -- Evan Esar
  18. How are you making your course corrections? by JSBiff · · Score: 2, Insightful

    2 thoughts come to mind:

    1) If the solar sail is your means of propulsion, do you include some sort of 'conventional' rockets to make your course adjustments? Can course adjustments somehow be made with the sail itself? It's not like a ship with a solar sail has a rudder. If not with the sail, how are you making those corrections.

    2) Efficiency - getting the correct path to start with means you'll get there sooner. Perhaps a LOT sooner, because making course corrections might have the effect of slowing down spacecraft some, and even if you don't have to slow down the craft, making course corrections implies you are not taking the most optimal route. But, hey, what's a few extra AU between friends? Oh yeah, that's right, it's the difference between getting the craft to the correct place, and having it shoot by a few hundred million kilometers off to the side. I'm sure no one will mind if that multi-billion dollar space mission gets lost in space having missed it's objective.

    1. Re:How are you making your course corrections? by djcinsb · · Score: 2, Informative

      On a "good" sail the surface is very reflective. The force that propels the spacecraft is the sum of two vectors; one pointing from the sun to the spacecraft, and a second for the reflected radiation leaving the sail. So you can steer the spacecraft by shortening one side and lengthening the other side of the says attaching the sail to the spacecraft, redirecting the outgoing vector. Or do something similar (e.g. reorient segments rather than the whole sail).

      --
      A signature always reveals a man's character - and sometimes even his name. -- Evan Esar
    2. Re:How are you making your course corrections? by CrimsonAvenger · · Score: 1

      2) Efficiency - getting the correct path to start with means you'll get there sooner. Perhaps a LOT sooner, because making course corrections might have the effect of slowing down spacecraft some, and even if you don't have to slow down the craft, making course corrections implies you are not taking the most optimal route. But, hey, what's a few extra AU between friends? Oh yeah, that's right, it's the difference between getting the craft to the correct place, and having it shoot by a few hundred million kilometers off to the side. I'm sure no one will mind if that multi-billion dollar space mission gets lost in space having missed it's objective.

      Umm, no. Getting the correct path doesn't actually make you more likely to get there sooner, much less a lot sooner. You're just as likely to be going too fast as too slow, so you may get there sooner with a bad course than with a good course.

      What's a few extra AU between friends? At the distances that obtain in the Oort Cloud, it's rounding error. Even if we were talking a few extra AU (remember, the number mentioned in the article was 1/150th of an AU.

      --

      "I do not agree with what you say, but I will defend to the death your right to say it"
    3. Re:How are you making your course corrections? by speedtux · · Score: 1

      If the solar sail is your means of propulsion, do you include some sort of 'conventional' rockets to make your course adjustments?

      Just like you do on a sailing ship: you turn the sail.

  19. My pet peeve about big numbers by line-bundle · · Score: 1

    TFS says that it will set the sail 1 million kilometers off course. I have no idea if that's a lot or a little. Don't switch units (from AU to km) mid paragraph (it's a smelly hint of wool coming over eyes).

    I beg you please don't just put big numbers without context or feel for what they mean.

    \begin{rant}
    I especially hate it when the government publishes such big numbers. Is a pork barrel item of $1,000,000 big or small.
    \end{rant}

    1. Re:My pet peeve about big numbers by Anonymous Coward · · Score: 0

      Think you forgot to
      \usepackage{rant}

    2. Re:My pet peeve about big numbers by brock+bitumen · · Score: 1

      wth is that? are you guys annotating your comments in RTF?

  20. Ping... pong by autocracy · · Score: 1

    Passing the orbit of Pluto will give a round-trip time of over 12 hours for the speed of light.

    After 2.5 years, it will be a 2 day affair.

    We might need something that can think on its own to have any useful input.

    --
    SIG: HUP
  21. one more stat by ILuvRamen · · Score: 2, Interesting

    The probability of it getting all the way there without one single part of the 1 KM sail getting hit by any single piece of space rock or other debris: 0%
    Dream on, space sailors. It's an idiotic idea and always will be.

    --
    Google's Super Secret Search Algorithm: SELECT @search_results FROM internet WHERE @search_results = 'good'
    1. Re:one more stat by jeffb+(2.718) · · Score: 1

      The probability of it getting all the way there without one single part of the 1 KM sail getting hit by any single piece of space rock or other debris: 0%

      And the consequence of a blowing a few 1cm^2 holes in a 1km^2 sail is...? It's not like a perforation will let all the sun leak out.

    2. Re:one more stat by R2.0 · · Score: 1

      "The probability of it getting all the way there without one single part of the 1 KM sail getting hit by any single piece of space rock or other debris: 0% "

      Math or GTFO.

      --
      "As God is my witness, I thought turkeys could fly." A. Carlson
    3. Re:one more stat by julesh · · Score: 1

      The probability of it getting all the way there without one single part of the 1 KM sail getting hit by any single piece of space rock or other debris: 0%
      Dream on, space sailors. It's an idiotic idea and always will be.

      That, plus the fact that they're talking about in 30 years being able to have the technology to make the trip take only 30 years.

      Great.

      Here's an alternative mission profile for you: we use a VASIMR drive, with an estimated specific impulse of around 30,000s. We have one large enough to produce an acceleration of around 0.0001m/s^2, and enough propellant for a delta-v of 200km/s. This is a lot of propellant, but it would be possible. The required thrust is around 100N if we assume the engine will mass around 1000kg (this will require the current designs, which produce around 5N, to be scaled up somewhat, and the resulting design to be more efficient than the current design, but such efficiency improvements seem likely with a larger model).

      We're travelling 2500AU, or ~375,000,000,000,000 metres.

      The probe will accelerate for 2,000,000,000 seconds (~63 years). In this time it will cover 200,000,000,000 metres, or just over half the distance. It will cover the remaining half of the distance in around 1,000,000,000 seconds or about 30 years.

      This mission has taken approximately 50% longer than the estimated time to complete the above-mentioned mission. It can almost be achieved with today's technology. It would cost, I suspect, about a tenth as much. The technologies developed for it (a large, high thrust, high specific-impulse thruster) would be very useful for orbital work (whereas space sails aren't really useful in an orbital situation as they only work when they're on the daylight side of the planet). And above all else, it's much more likely to work, because its failure modes are much better understood.

      Of course, neither mission will ever happen because no government is going to invest in something that won't pay off for such a long time, whether it's 30, 60 or 90 years.

    4. Re:one more stat by Anonymous Coward · · Score: 0

      Hold on, we can 'almost' do it with today's technology that provides 1/20th of the thrust you claim is necessary? Not only that, but I believe your thrust calculations are missing something very important... ... The mass of the *fuel* needed to provide the thrust, which in turn increases the thrust needed to get that mass up to speed.

      Congratulations, your costs 'about a tenth as much' has already gone about 2000% over budget just to get the fuel you need into space so that you can use your 20x more powerful, and more efficient than today's technology 'today's technology'.

      Here's a clue for you. A solar sail is *actually* today's technology, the version discussed is much closer to being today's technology than your hypothetical rocket engine, and it doesn't require several launches to get into space.

      Not only that, but by your own calculations, your suggested probe will take more than 3 times as long to make the journey. I know, I know. That's because you think they can simply scale up an existing design in a couple weeks, and have it be more efficient and 20x more powerful. Sadly, it doesn't work that way. A more powerful rocket produces more vibration. More vibration requires more reinforcement and damping. Increased reinforcement and damping adds up to more mass. More mass reduces the efficiency of the rocket. There's a reason rocket engines start small. That's where they're (relatively) easy.

    5. Re:one more stat by maxume · · Score: 1

      They might invest in something that takes 30 or more years to pay off, especially if it is a big dam that starts making electricity right after it is finished.

      --
      Nerd rage is the funniest rage.
    6. Re:one more stat by ILuvRamen · · Score: 1

      what are the consequences if it doesn't break through the sail? (duh) What happens if a 50 pound seagull flies into a sailboat's sail?

      --
      Google's Super Secret Search Algorithm: SELECT @search_results FROM internet WHERE @search_results = 'good'
    7. Re:one more stat by jeffb+(2.718) · · Score: 2, Informative

      <deep sigh/>

      What happens if you shoot a bullet at a sailboat's sail? You get a tiny hole in the sail. Now imagine the bullet is a million times less massive, and traveling a thousand times as fast. Same kinetic energy, but it's going to punch a much smaller and neater hole.

      Any space debris at the relative velocity of a solar sail will punch right through any imaginable sail material, vaporizing the tiny bit that it contacts. The surrounding material won't even feel a tug.

  22. Solar at that distance? by JSBiff · · Score: 1

    I wonder, how practical is Solar power past pluto?

    I seem to recall from one of my physics classes, a discussion about point sources of light and other EM fields, that as your distance from an object doubles, the 'density' of the field becomes 1/4. My point is, that outside the Solar System, you're so far from the Sun, that wouldn't the density of light at that distance (and thus, the amount of light/power that is hitting your solar cells) be very very very small?

    1. Re:Solar at that distance? by John_Booty · · Score: 3, Informative

      Right. There's (almost) no friction in space, so your craft isn't going to slow down just because it's no longer receiving enough power from the sun to accelerate. But after a certain point it won't receive enough solar power to power onboard navigation and communications systems. Those would likely be powered by a wee bit o' radioactive power like today's deep space probes.

      --

      OtakuBooty.com: Smart, funny, sexy nerds.
    2. Re:Solar at that distance? by HoboCop · · Score: 1

      Certainly from our sun.. might pass close enough to other stars to get power periodically (for very large values of period).

  23. Already done for GPS by Anonymous Coward · · Score: 0

    Read the wikipedia article on GPS - relativity is already taken into account for general navigation on Earth. If it wasn't, nobody would get anywhere.

    1. Re:Already done for GPS by Anonymous Coward · · Score: 0

      Well done AC, problem solved on Earth years ago, just scale it up to the SSPS (Solar System Positioning System) and we'll be all set. We have till 2040 so no real rush.

  24. Pardon the pun, but the scale tilts both ways. by Tsar · · Score: 1

    Yes, the vast scale of the distances involved does mean that the relatively small influence of relativistic effects will be magnified over the course of the mission, but they also dictate that large variances will have a commensurately smaller effect.

    From Earth's vantage point, an error of a million miles at 2500 A.U. would amount to a pointing error of about .55 arcseconds, not significant enough to bother correcting where we (or the probe) point our antennas.

    As for the environment at the Oort cloud, it will probably be just as interesting as the one a million kilometers to the left or right. This would be analogous to a shift of 18 meters left or right in low Earth orbit.

    Finally, a correction can be easily applied if pinpoint accuracy becomes important. A delta vee of only 1.6 m/sec applied as late as 10 years after launch would do the trick.

    1. Re:Pardon the pun, but the scale tilts both ways. by Anonymous Coward · · Score: 0

      You're looking at those numbers the wrong way. If you have a navigation error (or collection of them) that adds up to being *only* .55 arc seconds off course, you're going to arrive at a point roughly a *million miles* from your intended destination.

      From a telemetry stand point, you're correct that thats a pretty minor effect. From the stand point of what the telemetry would be used for, it's the difference between taking a picture of the one of the lunar rovers we left on the moon, and wasting a roll of film because you forgot to take off the lens cap.

  25. Newsflash by Anonymous Coward · · Score: 0

    Space really is rather empty, the chances are not all that bad. Not like you need that sail anyways after initial acceleration. And it might be possible to turn the sail in such a position, that minimizes the risk of debris impact.

    By the way, it's 1 km (kilometer), not 1 megakelvin (K = kelvin, M = mega), get your units right. Physics is not about guessing.

  26. Why single stage? by NYFreddie · · Score: 1

    Why only use the solar sail? Use the sail to get up to speed, then disengage it and switch over to using a Bussard ramjet. Use of the ramjet should provide ample power for guidance corrections using a vectored thrust system.

    Of course, the article may be leaving out a point like using gravity boosts for the sail on its way out, in which case a thousand kilometers would be a very drastic course deviance.

    --
    Barbie of Borg - She doesn't just Assimilate, She Accessorizes too!
  27. That sucks! by cowdung · · Score: 1

    Damn, now I'll have to put my solar sail project on hold till I can find a relitivistic navigator! I wish they'd said something before!

  28. Need to think relatively by Lev13than · · Score: 5, Funny

    Course correcting a small ship is easy - I'm more worried about everything else. In a relativistic navigation model, the ship is going to be in exactly the right place. However, the energy required to course correct the entire universe by one million km will be prohibitive.

    --
    When you have nothing left to burn you must set yourself on fire
  29. Move along. Nothing to see here. by mbone · · Score: 3, Informative

    The JPL ODP (Orbit Determination Program) has incorporated relativity since the 1960's and uses the proper Einstein Infeld Hoffmann (EIH) equations of motion for the harmonic gauge.

     

    1. Re:Move along. Nothing to see here. by TheRocketMan · · Score: 1

      The JPL ODP (Orbit Determination Program) has incorporated relativity since the 1960's and uses the proper Einstein Infeld Hoffmann (EIH) equations of motion for the harmonic gauge.

      Glad I read through to here before posting what you already did re relativity in the ODP (and it's replacement). Where are mod points when you need them...

    2. Re:Move along. Nothing to see here. by dbIII · · Score: 1

      That's a good point considering a few probes have taken a loop not far from the sun already to get a bit of extra acceleration from gravity. Getting to Jupiter via the Sun from Earth is a pretty tricky snooker shot.

  30. 0.1 AU? by TheSHAD0W · · Score: 2, Interesting

    I can understand why it would be nice to start off a solar-sail-based craft at one-tenth AU from the Sun; more light pressure = more acceleration. Thing is, it will almost certainly be starting out from Earth. You'd need to accelerate it just to drop it down to 0.1 AU. Wouldn't it be more efficient to use that acceleration to throw it outward instead of inward? Anyone care to calculate this?

    1. Re:0.1 AU? by mbone · · Score: 1

      Presumably you would unpack the sail at 0.1 AU. Before you deploy it, the light pressure acceleration would be much, much, smaller. To conserve even more fuel, you could do a Jupiter gravity assist or multiple Venus gravity assists to help you get there.

    2. Re:0.1 AU? by TheTurtlesMoves · · Score: 1

      The H-reversal sun flyby trajectory(down the page a bit) deals with this problem.

      --
      The Grey Goo disaster happened 3 billion years ago. This rock is covered in self replicating machines!
    3. Re:0.1 AU? by Anonymous Coward · · Score: 0

      Using the limited acceleration provided by a rocket to launch to launch a craft powered by a solar sail straight out has two problems:
      1. Limited thrust is pitted against solar gravity.
      2. Solar wind provides less thrust when rocket stops, increasing total travel time.
      Launching inward takes advantage of both solar gravity and gives the solar sail more bang for the buck (think slingshot)
      Sorry for the AC don't have an account.

  31. GPS must correct for special & general realtiv by peter303 · · Score: 2, Informative

    There is slowing of the clock onboard GPS satellites both due to the orbital speed (special relativity) and lower gravity (general relativity). This paper says special relativity errors accumlate about 7 microseconds a day and general relativity 46 microseconds. Radio signals move a thousand feet per microsecond, so the effect significant.

  32. I already use relativistic navigation by 140Mandak262Jamuna · · Score: 2, Funny

    I don't know what the big fuss is about relativistic navigation. Almost every day my close relative sits on the passenger seat tells me where to go. Some times my other close relative sits in the back seat and tells me where to go. Being used to that kind of relativistic navigation, I wonder why NASA is so puzzled.

    --
    sed -e 's/Chuck Norris/Rajnikant/g' joke > fact
  33. What is the top speed? by AttillaTheNun · · Score: 1

    How close to C does this probe reach during the journey?

    1. Re:What is the top speed? by careysub · · Score: 1

      It reaches 0.13% of the speed of light. It will reach the nearest star in 3300 years or so.

      --
      Starships were meant to fly, Hands up and touch the sky - Nicky Minaj
  34. I don't get it... Why don't they just drop it, &am by DRAGONWEEZEL · · Score: 1

    wait until when it gets about say 8 Light minutes away 8') send it new coordinates, giving it an "update" to it's trajectory. This should be able to be done w/ small rockets & such, and it's way earlier, the speed will be high, but not it's peak speed. We should be able to give it a Garmin (tm)navigational update.
    but how is it going to navigate around ojects in it's path? My guess is that any "Solar Sail" application will be torn to shreds by space dust at those high speeds by the time it get's between Venus and Jupiter.

    --
    How much is your data worth? Back it up now.
  35. Re:GPS must correct for special & general real by radtea · · Score: 1

    There is slowing of the clock onboard GPS satellites both due to the orbital speed (special relativity) and lower gravity (general relativity).

    A colleague who used to teach a "Modern Physics for Engineers" course took great delight in detailing the history of the GPS system, and how they had to bring in some hard-core theoretical physicists to work out the GR corrections.

    Engineers have a tendency to think theory is irrelevant and stupid, and this is a nice example of how the GPS system would have either failed or been full of inelegant hacks if we didn't have an esoteric but exact theory of gravity on large scales.

    --
    Blasphemy is a human right. Blasphemophobia kills.
  36. I'm Confused by Kozar_The_Malignant · · Score: 2, Insightful

    > it could travel 2500AU, far enough to explore the Oort Cloud... sending the sail roughly 1 million kilometers off course by the time it reaches the Oort Cloud

    How could you possibly miss the Oort Cloud, a spherical region, when you start inside it. Considering that we don't know jack, or even 10% of jack, about the Oort Cloud, what the hell are we aiming at? Fling the sucker out there at random and see what we find. The unaimed arrow never misses.

    --
    Some mornings it's hardly worth chewing through the restraints to get out of bed.
    1. Re:I'm Confused by jjohnson · · Score: 1

      I think the issue with knowing the course accurately has to do with being able to communicate with it. Knowing its course means knowing how it should be oriented to keep an antenna pointed at the Earth.

      --
      Anyone who loves or hates any language, platform, or manufacturer, doesn't know what they're talking about.
  37. The math does not look promising by Ancient_Hacker · · Score: 1

    When I do the math, a square kilometer sail weighing 150 kilograms can only weigh 0.15 grams per square meter. If the material is only 0.0025 cm thick, it would have to have a density of 0.006. It's hard to find anything solid that is that light.

    And that's ignoring the non-negligible weight of whatever lashes the 150Kg payload to the square kilometer of sail.

    And if this thing is going to pull 0.6G, you need some kind of structure that can transfer the force to the payload without collapsing the sail. Quite a trick.

    Also at 0.1 AU from the Sun, the thing is going to get mighty hot.

    1. Re:The math does not look promising by Anonymous Coward · · Score: 0

      Don't forget it has to be able to survive micrometeorites and god knows what else impacting the sail and/or body of the vessel as it travels that far. And for as empty as space is said to be, I'm sure given that much time there's plenty of interstellar matter that might impact it. All potentially moving at speeds catastrophic for the integrity of the probe in the event of collision.

    2. Re:The math does not look promising by Carnildo · · Score: 1

      0.025mm? Why use something that thick? McMaster sells 0.0125mm PET film for $0.25 per square foot.

      --
      "They redundantly repeated themselves over and over again incessantly without end ad infinitum" -- ibid.
    3. Re:The math does not look promising by Ancient_Hacker · · Score: 1

      oookay, so the stuff can be as dense as 0.012.

      PET's density is 1.35 so it's still a bit over 100 times too heavy. And I doubt if PET can stand being 0.1 AU from the Sun for very long.

  38. Re:GPS must correct for special & general real by Anonymous Coward · · Score: 0

    My physici friend says that early GPS devices came with a relativity switch, so you could disable the corrections just in case the theory was wrong.

    Seems totally legit -- it's the kind of anecdote you'd hear in our intro-to-relativity subjects.

  39. The Spice must flow by Gothmolly · · Score: 1

    Its easy, just take a massive overdose of Spice, float in your tank, and visualize the spaceship getting there. Presto! There it is.

    --
    I want to delete my account but Slashdot doesn't allow it.
  40. neat by jjeffries · · Score: 1

    I hope I live to see this, and that it looks exactly like the one in Tron. C'mon reality, don't let me down again!

  41. The Infinite Improbability Drive by Anonymous Coward · · Score: 0

    The Infinite Improbability Drive is a fictional faster-than-light drive. The most prominent usage of the drive is in the starship Heart of Gold. It is based on a particular perception of quantum theory: a subatomic particle is most likely to be in a particular place, such as near the nucleus of an atom, but there is also a small probability of it being found very far from its point of origin (for example close to a distant star). Thus, a body could travel from place to place without passing through the intervening space (or hyperspace, for that matter), if you had sufficient control of probability.[1]

  42. Something Missing Here by Nom+du+Keyboard · · Score: 1

    sending the sail roughly 1 million kilometers off course by the time it reaches the Oort Cloud.

    Haven't these guys ever heard of the mid-course correction? I mean, really...

    --
    "It's the height of ridiculousness to say for those 9 lines you get hundreds of millions."
  43. As always.... by sconeu · · Score: 1

    xkcd to the rescue...

    http://xkcd.com/265/

    --
    General Relativity: Space-time tells matter where to go; Matter tells space-time what shape to be.
  44. Maths required for space navigation? by Crookdotter · · Score: 3, Informative

    Why is this a suprise at all? GPS satellites have to include relativistic calculations. This isn't difficult for anyone involved. It's hardly rocket science.....

  45. 250 posts in by Johnny+Mnemonic · · Score: 0

    and no Dune reference, at least not at +5?

    THE SPICE MUST FLOW

    --

    --
    $tar -xvf .sig.tar
  46. And Magellan had to weigh the threads in his sails by Antique+Geekmeister · · Score: 1

    What truly amazing twaddle. The concept of a solar sail that cannot _steer_ to correct any errors in its original launch is simply amazing. This would be a very expensive spacecraft, not an arrow. It's going to need some control in order to keep its sail aligned for maximum effective thrust, lest it twist very slightly and get pushed slightly wrong for days or years. Even the slightest control of the sails, very slightly pulling in one corner or even two, could be used over a voyage to avvect its course.

  47. Re:And Magellan had to weigh the threads in his sa by Anonymous Coward · · Score: 0

    it's not about steering, it's about navigating, which is about knowing where you are, and relativity is a tricky thing to compensate for (how do you compensate for phenomena you don't completely understand?). It's like the difference btw your steering wheel and your tomtom. I can see how you might get those confused, they do have some overlapping goals, but really, they perform very different functions when you get right down to it.

  48. Except the farther you get away from the sun. . . by JSBiff · · Score: 1

    I've been trying to think about this problem over the past couple days, and your response about turning the sail. The problem which keeps occurring to me, and which doesn't seem like your 'solution' addresses, is that when you are no longer close to the sun, the force from the sun will be very small, and may not be sufficient to make course corrections? I'm not really sure about that, but it really seems like, with a Solar Sail, you gotta get it right early, because the closer you get to the 'destination', the less power there is available to make course corrections (with the sail, at least).