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New Camera Sensor Filter Allows Twice As Much Light

bugnuts writes "Nearly all modern DSLRs use a Bayer filter to determine colors, which filters red, two greens, and a blue for each block of 4 pixels. As a result of the filtering, the pixels don't receive all the light and the pixel values must be multiplied by predetermined values (which also multiplies the noise) to normalize the differences. Panasonic developed a novel method of 'filtering' which splits the light so the photons are not absorbed, but redirected to the appropriate pixel. As a result, about twice the light reaches the sensor and almost no light is lost. Instead of RGGB, each block of 4 pixels receives Cyan, White + Red, White + Blue, and Yellow, and the RGB values can be interpolated."

37 of 170 comments (clear)

  1. Wow! Computational Electromagnetics rock! by 140Mandak262Jamuna · · Score: 5, Interesting

    "We've developed a completely new analysis method, called Babinet-BPM. Compared with the usual FDTD method, the computation speed is 325 times higher, but it only consumes 1/16 of the memory. This is the result of a three-hour calculation by the FDTD method. We achieved the same result in just 36.9 seconds."

    What I don't get is calling the FDTD (finite difference time domain) analysis as the "usual" method. It is the usual method in fluid mechanics. But in computational electromagnetics finite element methods have been in use for a long time, and they beat FDTD methods hollow. The basic problem in FDTD method is that, to get more accurate results you need a finer grids. But finer grids also force you to use finer time steps. Thus if you halve the grid spacing, the computational load goes up by a factor of 16. It is known as the tyranny of the CFL condition. The finite element method in frequency domain does not have this limitation and it scales as O(N^1.5) or so. (FDTD scales by O(N^4)). It is still a beast to solve, rank deficient matrix, low condition numbers, needs a full L-U decomposition, but still, FEM wins over FDTD because of the better scaling.

    The technique mentioned here seems to be a variant of boundary integral method, usually used in open domains, and multiwavelength long solution domains. I wonder if FEM can crack this problem.

    --
    sed -e 's/Chuck Norris/Rajnikant/g' joke > fact
    1. Re:Wow! Computational Electromagnetics rock! by Anonymous Coward · · Score: 5, Interesting

      I'm not sure any of the comparison of FDTD and FEM-FD in this post is right. FDTD suffers from the CFL limitation only in its explicit form. Implicit methods allow time steps much greater than the CFL limit. The implicit version requires matrix inversions at each time step, whereas the explicit version does not. Comparing FEM-FD and FDTD methods is silly. One is time domain, one is frequency domain, they are solving different problems. There is no problem doing FEM-TD (time domain), in which case the scaling is worse for FEM, when compared to explicit FDTD since the FDTD method pushes a vector, not a matrix, requires only nearest neighbor communication, whereas FEM requires a sparse-matrix solve, which is the bane of computer scientists as the strong scaling curve rolls over as N increases. FDTD does not have this problem, requires less memory and is more friendly toward GPU based compute hardware that is starting to dominate todays supercomputers.

    2. Re:Wow! Computational Electromagnetics rock! by loufoque · · Score: 2

      A GPU is actually pretty good at sparse matrix computations, unlike CPUs.

    3. Re:Wow! Computational Electromagnetics rock! by 140Mandak262Jamuna · · Score: 2
      I too come fram CFD side and gone to the wrong side of the (electromagnetic) force ;-). CFD formulation is inherently parallel, all grid points can be update for the next step simultaneously, and each grid point has a very limited domain of dependency, update computation is relatively simple just mass, momentum and energy conservation, and the unknowns are simply two scalars (density, pressure) and one real vector (momentum). But the CFL condition and turbulence takes away all these benefits and makes life extremely hard for the CFD people.

      CEM (computational electro magnetics) is linear, the biggest advantage. But the users want broad spectrum response, so you need to solve it in frequency domain. Each degree of freedom consists of two complex vectors. Formulation is a bitch, almost always a Galerkin. Matrix becomes rank deficient after you remove the null space of the curl vector from the equation. That means the memory hogging L-U decomp.

      If I come across as a guy with a chip on the shoulder it is because of the sneering by CFD specialists laughing at our million tet meshes. A million tet mesh in CFD would get about 200K finite volumes after the median dual, get you about 1million scalar unknowns (x,y,z momentum, pressure and density). A million tet CEM mesh would get 20 million complex vectors as unknowns (H1 curl formulation), or 120 million components (x,y,z real & imaginary). And we have to do it L-U decomp, while CFD runs along in time marching on GPUs.

      All I am saying is, yes, CFD's life is a bitch. But our life is bitchier.

      --
      sed -e 's/Chuck Norris/Rajnikant/g' joke > fact
    4. Re:Wow! Computational Electromagnetics rock! by loufoque · · Score: 2

      Sparse reads and writes are not vectorizable and are not cache-friendly. A GPU has fast memory without cache and is not limited by traditional vectorization

  2. Re:I call bullpucky by bugnuts · · Score: 4, Informative

    Foveon has 3 photodiodes per pixel, and theoretically should have the most accurate colors and sharpness by avoiding moire and interpolation issues with bayer filters. In practice, though, a lot of light is lost by the time it reaches the 3rd photodiode.

    There is indeed white light because not every pixel has a filter over it. Many pixels pass the light through a hole to the pixel, while a neighbor pixel funnels red light (e.g.) to it. Thus, you get white + 1/2 the neighbor's red. You also get half the neighbor's red on the other side, resulting in white + red for the three pixels in a line.

    Cyan is part of the color spectrum as a "subtractive color". What remains under each neighbor pixel when you strip away the red, is the cyan.

    From what I can tell, this will not get rid of the need for the anti-aliasing.

  3. So essentially... by rusty0101 · · Score: 2

    ...we've switched from calculating rggb values based on attenuated rggb values sensed, to calculating rgb values from sensing cyan (usually a color of reflected light with red subtracted, white+blue ?, white+red ?, and yellow (again reflected white light minus the blue spectral light.)

    I can see the resulting files having better print characteristics, if the detectors sense to the levels close to the characteristics of ink used for prints, but I don't think that's going to help at the display the photographer will be using to manipulate the images.

    And of course neither variety of photo image capture is comparable to the qualities of light that our rods and cones respond to in our eyes.

    --
    You never know...
    1. Re:So essentially... by Lehk228 · · Score: 2

      it means for any given sized sensor, a higher percentage of the incoming photons are captured for analysis

      how this advantage is used it up to the engineers.

      it could be used to make sensors that are smaller and just as good as current sensors, or better quality out of the same sensors. because this improvement is in the signal/noise domain it will also allow for better high speed image capture.

      --
      Snowden and Manning are heroes.
    2. Re:So essentially... by PhrostyMcByte · · Score: 2

      I can see the resulting files having better print characteristics, if the detectors sense to the levels close to the characteristics of ink used for prints, but I don't think that's going to help at the display the photographer will be using to manipulate the images.

      You can losslessly, mathematically translate between this and RGB (certainly not sRGB) and CMYK. But that's just math. Printing is difficult due to the physical variables of the subtractive color model. The more money you throw at it -- that is to say, the better and more inks and quality of paper you use -- the better it gets. No new physical or mathematical colorspace will improve color reproduction.

    3. Re:So essentially... by Solandri · · Score: 5, Informative

      ...we've switched from calculating rggb values based on attenuated rggb values sensed, to calculating rgb values from sensing cyan (usually a color of reflected light with red subtracted, white+blue ?, white+red ?, and yellow (again reflected white light minus the blue spectral light.)

      Your eyes actually aren't sensitive to red, green, and blue. Here are the spectral sensitivities of the red, green, and blue cones in your eye. The red cones are actually most sensitive to orange, green most sensitive to yellow-green, and blue most sensitive to green-blue. There's also a wide range of colors that each type of cone is sensitive to, not a single frequency. When your brain decodes this into color, it uses the combined signal it's getting from all three types of cones to figure out which color you're seeing. e.g. Green isn't just the stimulation of your green-yellow cones. It's that plus the low stimulation of your orange cones and blue-green cones in the correct ratio.

      RGB being the holy trinity of color is a display phenomenon, not a sensing one. In order to be able to stimulate the entire range of colors you can perceive, it's easiest if you pick three colors which stimulate the orange cones most and the other two least (red), the green-blue cones most and the others least (blue), and the green-yellow cones most but the other two least (green). (I won't get into purple/violet - that's a long story which you can probably guess if you look at the left end of the orange cones' response curve.) You could actually pick 3 different colors as your primaries, e.g. orange, yellow, and blue. They'd just be more limited in the range of colors you can reproduce because their inability to stimulate the three types of comes semi-independently. Even if you pick non-optimal colors, it's possible to replicate the full range if you add a 4th or 5th display primary. It's just more complex and usually not economical (Panasonic I think made a TV with extra yellow primary to help bolster that portion of the spectrum).

      But like your eyes, for the purposes of recording colors, you don't have to actually record red, green, and blue. You can replicate the same frequency response spectrum using photoreceptors sensitive to any 3 different colors. All that matters is that their range of sensitivity covers the full visible spectrum, and their combined response curves allow you to uniquely distinguish any single frequency of light within that range. It may involve a lot of math, but hey computational power is cheap nowadays.

      It's also worth noting that real-world objects don't give off a single frequency of light. They give off a wide spectrum, which your eyes combine into the 3 signal strengths from the 3 types of cones. This is part of the reason why some objects can appear to shift relative colors as you put them under different lighting. A blue quilt with orange patches can appear to be a blue quilt with red patches under lighting with a stronger red component. The "orange" patches are actually reflecting both orange and red light. So the actual color you see is the frequency spectrum of the light source, times the frequency emission response (color reflection spectrum) of the object, convolved with the frequency response of the cones in your eyes. And when you display a picture of that object, your monitor is simply doing its best using three narrow-band frequencies to stimulate your cones in the same ratio as they were with the wide-band color of the object. So a photo can never truly replicate the appearance of an object; it can only replicate its appearance under a specific lighting condition.

    4. Re:So essentially... by EdZ · · Score: 2

      it could be used to make sensors that are smaller and just as good as current sensors

      I'm not sure if it could. Pixel sizes for really tiny cameraphone sensors (1.1 microns, or 1100 nm) are getting close to the wavelength of visible red photons (750 nm). If you shrink them anymore, Quantum Stuff starts to happen which you may not really want to happen.

    5. Re:So essentially... by Anonymous Coward · · Score: 2, Informative

      Then the material is phosphorous.
      The photons from the light source are able to put electrons in the material in a higher orbit (skipping at least one orbit level), then when the electron drops its orbit it doesn't go all the way back to the original orbit. Since the distance of the electron going up, is not the same as going down, the photon produces is of a different frequency (color) than the photon from the light source.

      The second drop of the electron to the original orbit will also cause another photon to be released which would be a third colour.

    6. Re:So essentially... by Rockoon · · Score: 3, Interesting

      If you shrink them anymore, Quantum Stuff starts to happen which you may not really want to happen.

      ..unless you embrace the Quantum Stuff and deal with the consequences. One of the nice things about Quantum Interference is that its well defined, unlike other forms of noise.

      --
      "His name was James Damore."
    7. Re:So essentially... by Rockoon · · Score: 2

      No new physical or mathematical colorspace will improve color reproduction.

      'cept we arent dealing with 'preproduction' - we are dealing with 'capture' - while the RGB color space can indeed encode "yellow" it cannot encode how it got to be yellow (is it a single light wave with a wavelength of 570 nm, is it a combination of 510 nm and 650 nm waves, or is it something else?)

      (hint: Your monitor reproduces yellow by combining 510 nm and 650 nm waves, but most things in nature that appear yellow do so because the waves are 570 nm)

      --
      "His name was James Damore."
    8. Re:So essentially... by Rich0 · · Score: 4, Informative

      Yup - this is fluorescence.

      It is worth nothing that a related term is phosphorescence, which is what most people think of when they thing of phosphors. For the benefit of those reading, the two are basically the same phenomena on different timescales.

      When light hits an object that is fluorescent it absorbs the light and re-emits it. The re-emitted light has a different spectrum than the absorbed light. The re-emitted light is also emitted AFTER the light is absorbed. In most cases it is emitted almost instantaneously and this is called fluorescence. However, some materials take much longer to emit the absorbed energy as light and this is called phosphorescence.

      So, that T-shirt that lights up under a blacklight is exhibiting fluorescence. The watch hands that continue to glow 30 seconds after going from daylight to darkness is exhibiting phosphorescence. They're the exact same thing, but with different dynamics. They both involve electrons absorbing energy and releasing it, but with phosphorescence they get stuck in metastable states (read wikipedia for a decent explanation, but a full one requires a bit more quantum physics than I've mastered).

  4. I agree with point, but the Foveon works... by SuperKendall · · Score: 4, Informative

    In other words, technological superiority doesn't always win in digital photography.

    This is very true, although the Foveon was superior in resolution and lack of color moire only - it terms of higher ISO support it has not been as good as the top performers of the day.

    But the Foveon chip does persist in cameras, currently Sigma (who bought Foveon) still selling a DSLR with the Foveon sensor, and now a range of really high quality compact cameras with a DSLR sized Foveon chip in it. (the Sigma DP-1M, DP-2M and DP-3M each with fixed prime lenses of different focal lengths)

    I think though that we are entering a period where resolution has plateaued, that is most people do not need more resolution than cameras are delivering - so there is more room for alternative sensors to capture some of the market because they are delivering other benefits that people enjoy. Now that Sigma has carried Foveon forward into a newer age of sensors they are having better luck selling a high-resolution very sharp small compact that has as much detail as a Nikon D800 and no color moire...

    Another interesting alternative sensor is Fuji with the X-Trans sensor - randomized RGB filters to eliminate color moire. The Panasonic approach seems like it might have some real gains in higher ISO support though.

    --
    "There is more worth loving than we have strength to love." - Brian Jay Stanley
  5. Re:I call bullpucky by ceoyoyo · · Score: 3, Insightful

    "From what I can tell, this will not get rid of the need for the anti-aliasing."

    You ALWAYS need antialiasing when you discretize.

  6. I just wish they would... by FlyingGuy · · Score: 4, Interesting

    Simply use three sensors and a prism. The color separation camera has been around for along time and the color prints from it are just breath taking. Just use three really great sensors then we can have digital color that rivals film.

    Check out the work of Harry Warnecke and you will see what I mean.

    --
    Hey KID! Yeah you, get the fuck off my lawn!
    1. Re:I just wish they would... by D1G1T · · Score: 3, Insightful

      Er, you mean like in the 3 chip cameras Panasonic has been making for decades?

    2. Re:I just wish they would... by gagol · · Score: 4, Informative

      You mean like those 3CCD cameras used to shoot pro broadcast? They have been around for years, if not decades. Consumer goods are another story.

      --
      Tomorrow is another day...
    3. Re:I just wish they would... by Anonymous Coward · · Score: 2, Interesting

      Pro video 3CCD cameras do this. Interestingly those cameras can make use of a trick so that the lens becomes cheaper.
      Normally a lens needs to focus all three colours on the same plane, this is difficult due to the prism effects of a lens, therefor normal lenses need to use glass from two different materials with different refractive indices to compensate for this.

      Since the colour for a 3CCD video camera is split, you can simply place each sensor on the focus plane of each colour for a non-compensating lens.

  7. Re:Just say no to Gizmodo by tloh · · Score: 3, Interesting

    Ironically, the last paragraph at Gizmodo somewhat answers your question:

    What's particularly neat about this new approach is that it can be used with any kind of sensor without modification; CMOS, CCD, or BSI. And the filters can be produced using the same materials and manufacturing processes in place today. Which means we'll probably be seeing this technology implemented on cameras sooner rather than later.

    --
    Stay sentient. Don't drink bad milk.
  8. Re:I call bullpucky by Jafafa+Hots · · Score: 5, Funny

    "You ALWAYS need antialiasing when you discretize."

    That's my motto!

    --
    This space available.
  9. The real question is... by XiaoMing · · Score: 5, Funny

    Interesting comments from both, but I believe you both missed the point. The real question is, which one of these methods, FDTD or FEM-FD, will allow optimal reprocessing in the frequency domain that makes my dinner look prettier with an Instagram vintage filter?

  10. Re:yeay four sensors by ceoyoyo · · Score: 3, Informative

    So when you print to your eight colour inkjet, what file format is your image stored in that has eight colour channels? What software are you using that supports it?

    Note that in CMYK, which is the most by far the most popular "four colour" system (and is the one all those "four colour" printers use), black is one of the colours. That makes up for a shortcoming in the colour inks (which is not shared by camera sensors or displays) in which you can't make a decent black by mixing the colours. I suspect the eight colour printer is doing something very similar - mixing colours to give you a better (they say anyway) representation of the three colour additive system that your computer, camera and monitor use.

    Besides, the vast, vast majority of people don't colour calibrate their monitors OR printers. Unless you do that regularly all the extra colour channels in the world aren't going to help you.

  11. Re:I call bullpucky by Opportunist · · Score: 3, Funny

    Is that one of those colors only women can see? Like mauve?

    --
    We used to have a Bill of Rights. Now, with the rights gone, all we have left is the bill.
  12. Re:I call bullpucky by ThePeices · · Score: 2

    "From what I can tell, this will not get rid of the need for the anti-aliasing."

    You ALWAYS need antialiasing when you discretize.

    I think the word you are looking for is "quantize"

  13. Screen Printing by Tenebrousedge · · Score: 2

    When working with designs meant for screen printing, the original artwork was done in RGB, then a team would separate the color channels (in Photoshop), one channel per ink to be used. They could technically do CMYK directly, but it didn't look good for a wide variety of purposes -- you can imagine a flat-filled cartoon character would be pretty much impossible. It would look a bit like comic book halftoning, probably. The shop would use that when they wanted to print Thomas Kincaide-esque sweatshirts for grannies. They would also use additional channels for things that weren't colors, like adhesive (for foil, usually) and clear inks.

    I don't imagine that having more than three or four color channels is a new thing, or difficult to deal with. I would imagine even the prosumer technology would allow you to choose between various rendering intents. Probably the color separation is handled at the driver or device level, but TIFF, PDF, and DCS 2.0 (??) should handle extra channels natively.

    A few more details on screen printing for those who might care: The actual screen printing process was not computer-controlled as a rule. The smaller shops I worked at printed a transparency which was transferred onto the screen by a photographic process, but the large one had a computer-controlled airjet "printer" that would knock out the design. Usually they would do a few samples by hand, to work out what ink and screen combination to use (different mesh sizes and ink thicknesses produce slightly different effects), and adjust finer details like when you would "flash" the shirt. That is, hitting it with a very high powered xenon lamp for a few seconds to dry the ink, before applying a new layer. You could do some interesting painterly effects with wet-on-wet ink; you can also make a hell of a mess that way. Flashing also tends to affect the color somewhat, especially for temperature-sensitive inks. After you get a few good samples, you send them off to the client as a proof. Then you would set up your automatic press for a run of a couple hundred. Color balance was something that the press operator kept an eye on after that point. After printing, the shirts are sent through a 400 degree open oven on a conveyor belt, for perhaps 10-20 seconds, to cure the ink.

    Very fun job, the ink is messy as hell. I would still be doing it, but working with computers pays better.

    --
    Those who advocate genocide deserve every protection afforded by law, and none afforded by common human decency.
  14. Re:yeay four sensors by AK+Marc · · Score: 2

    I gave an example of a printer with 7 colors+black, and yet you quibble over printer capabilities. Since reality is unrelated to your complaint, I'm curious what it is you are really complaining about. "There's no printer with 4 colours." "Here's one with 7+black" then you go off on some tangent about file support. I don't care. You are wrong. Everything you've said is wrong. I posted a link that proves you 100% wrong, and yet you keep insisting that reality is wrong and you are right. Yeah, I don't know where to go. If I answered your question about software, I'm sure you'd make up some other crap about paper quality or something.

  15. Re:I call bullpucky by EdZ · · Score: 2

    Discretising is just quantising in the spacial domain!

  16. Re:I call bullpucky by thegarbz · · Score: 3, Informative

    Magenta is a combination of colours just like white isn't "in the colour spectrum".

    Indigo/violet however is in the spectrum but as it's outside of the range of values which can be created with red green and blue we approximate it using magenta which is a mixture of blue and red.

  17. Re:yeay four sensors by thegarbz · · Score: 3, Informative

    So when you print to your eight colour inkjet, what file format is your image stored in that has eight colour channels?

    You don't seem to understand the purpose of the colours or how colour is managed in a workflow. A file stored in your computer will have a certain gamut, if not specified this gamut is sRGB. Your printer also has a certain gamut. This is a function of the ink, colours it can print and the paper printed on. Colour management will take care of ensuring what you see on your screen will be reproduced on the printer providing the printer is physically capable of printing the colours in the gamut.

    This is a quite common problem for instance with a CMYK printer which is unable to print any of the primary colours shown as red green and blue on the monitor. The result is a printer that prints a subset of the available colours a screen can display, but at the same time can print outside the gamut of your monitor too.

    You don't need a file that has 8 primary colours to take advantage of the really wide gamuts 8 colour printers can print, you just need maths on your side. The ProPhotoRGB colour space works around this by defining the primary for green and blue as imaginary negative values which don't exist in reality. As such using red, green and blue primaries you can create for instance a colour that *almost* represents a pure cyan.

    This is something that many photographers who print images already do. I think even the latest Photoshop comes setup out of the box to import raw camera files using ProPhotoRGB as the working colour space.

    Besides, the vast, vast majority of people don't colour calibrate their monitors OR printers. Unless you do that regularly all the extra colour channels in the world aren't going to help you.

    You don't know photographers very well do you? The vast majority of amateur and all professional photographers I've ever met calibrate their screens. Printer calibration is often not needed as the vast majority of photographers I know outsource their printing to someone else, and that someone else will typically provide them with the colour profile of their printer's last calibration to ensure accurate results can be obtained. Pretty much every printing company will do this for you, even cheap mass production ones like Snapfish.

  18. Re:yeay four sensors by ceoyoyo · · Score: 3, Informative

    You don't seem to know what we're talking about. Let me quote the OP:

    "I've been hoping for 4-sensor cameras for ages. People only have three color sensors, but what those colors are vary a bit from person to person, and capturing 4 colors stands a better chance of getting images that look good for everyone."

    Yes, more inks in your printer help it reproduce the RGB values that you capture with your camera, save in your files, display on your screen, and send to the printer. Just like in the example I gave, the K channel in CMYK helps make up for deficiencies in the mixing properties of the C, M and Y that don't let you make a proper black by mixing. Extra ink won't do squat to match extra colour information from a theoretical extra colour sensor in the camera though, because everything in between is RGB.

    Yes, actually, I know lots of photographers. I calibrate my screen, and I use a printer I chose specifically because they do a good job of frequent calibration. Most professional photographers do. But if you haven't noticed, with the availability of digital cameras a LOT of people took up photography. Hardware screen calibrators are still a niche item, nowhere near as popular as cameras. In particular, Panasonic doesn't make any still cameras that are likely to be used extensively by professionals, so it's likely that even fewer people who shoot Panasonic would calibrate their equipment.

  19. Re:yeay four sensors by ceoyoyo · · Score: 4, Informative

    I'm not complaining about anything. I'm replying to your erroneous assertion (you DID read the whole thread before replying, right?) that the existence of printers with eight inks somehow means they'll be able to reproduce data from a hypothetical four colour channel camera sensor.

    I do like your fake quotes though. Please indicate where I said "there's no printer with 4 colours." What I DID say was "Too bad you're displaying them on a screen or printing them with a process that only uses three colours." If you bothered to understand what you're talking about, or even read my comments, you'd realize that the process is indeed three colour. Even if you imagine a four colour camera sensor, the file you store the data in is three colour channel, the software you use to edit it is three colour channel, the screen you show it on is three channel and the data you send to the printer driver is three channel. IF you could somehow send the four channel data to the printer you might be able to reproduce some extra colours (which the vast majority of humanity probably wouldn't be able to see anyway), but probably not very well since all those extra inks are formulated specifically to help reproduce RGB.

  20. Re:I call bullpucky by stenvar · · Score: 2

    That's wrong too. For example, if your image consists of widely spaced point light sources, it isn't low-pass filtered, but you still don't need or want an anti-aliasing filter to reconstruct the position of the point light sources. Not only don't you need an anti-aliasing filter, the image will look better without it. That's the case in astrophotography.

    Whether you need anti-aliasing filters depends on what kinds of pictures you take, what you know about the scene, and what you are trying to get out.

  21. Re:I call bullpucky by ceoyoyo · · Score: 2

    Nope, it's not. Quantization is the process of taking a continuous valued measurement and rounding, truncating or otherwise cramming it onto a discrete scale. For example, taking the value 5.382... and recording it as 5.

    I COULD have said "sampling." Sampling is measuring a signal at several points. The measured values are on the same scale the original was - if you're sampling sound with a microphone, for example, the samples are on a continuous scale. We almost always then quantize the samples, putting them on a discrete scale that's suitable to store in a computer. But sampling/discretization and quantization are two separate things.

    Discretization is a term used more in math and statistics, but I used it here because it specifically refers to going from a continuous representation to a discrete representation. Sampling can also be done on a signal that is already discrete. We usually call that "resampling." If you're sampling a discrete signal and your sampling rate is equal to or higher than the original you don't necessarily need to low pass filter.

    Discretization: http://en.wikipedia.org/wiki/Discretization
    Quantization: http://en.wikipedia.org/wiki/Quantization_(signal_processing)

  22. Re:I call bullpucky by x3CDA84B · · Score: 2

    You might want to open your eyes and look in the 490–520nm range on a representation of the visual range of the EM spectrum.

    To nitpick, that's actually not cyan. Cyan is a combination of green and blue light. The wavelength you're describing stimulates the green and blue receptors in our eyes in a way that looks (to us) identical to cyan, but it's not the same thing. Sort of like how violet (in the sense of being around 400nm) light stimulates the red and blue receptors in our eyes, similar to (but distinct from) certain shades of purple.

    This becomes important when discussing things like optical filters. A cyan filter passes green and blue light. In other words, it is a red-blocking filter. This is very different from a filter with a bandpass of 490-520nm, which would also block most green and blue light.