Slashdot Mirror


Chinese Mathematicians Prove Poincare Conjecture

Joe Lau writes to mention a story running on the Xinhua News Agency site, reporting a proof for the Poincare Conjecture in an upcoming edition of the Asian Journal of Mathematics. From the article: "A Columbia professor Richard Hamilton and a Russian mathematician Grigori Perelman have laid foundation on the latest endeavors made by the two Chinese. Prof. Hamilton completed the majority of the program and the geometrization conjecture. Yang, member of the Chinese Academy of Sciences, said in an interview with Xinhua, 'All the American, Russian and Chinese mathematicians have made indispensable contribution to the complete proof.'"

58 of 288 comments (clear)

  1. It's all a conjecture by The+Bungi · · Score: 5, Funny
    I looked at TFA, and I was kind of lost after reading this:

    In its original form, the Poincaré conjecture states that every simply connected closed three-manifold is homeomorphic to the three-sphere (in a topologist's sense) S^3, where a three-sphere is simply a generalization of the usual sphere to one dimension higher.

    Homeomorphic. Thank god, they dumb it down a bit later:

    More colloquially, the conjecture says that the three-sphere is the only type of bounded three-dimensional space possible that contains no holes. This conjecture was first proposed in 1904 by H. Poincaré Eric Weisstein's World of Biography (Poincaré 1953, pp. 486 and 498), and subsequently generalized to the conjecture that every compact n-manifold is homotopy-equivalent to the n-sphere if it is homeomorphic to the n-sphere. The generalized statement reduces to the original conjecture for n==3.

    More colloquially, it's homotopy-equivalent to the n-sphere! Of course!

    Slow news day?

    1. Re:It's all a conjecture by joe+155 · · Score: 4, Informative

      Slow news day?

      this is actually quite a discovery; it's one of these things which has been hanging around for over a hundred years and it's good to finally have a proof... it's a little like proving P=NP... but a little less grand

      --
      *''I can't believe it's not a hyperlink.''
    2. Re:It's all a conjecture by Umbral+Blot · · Score: 4, Funny

      You might think that this is useless to you. However simply memorize those quotes and you can be prepared for any situation. Boss unexpectedly wants a status report? Sure boss, currently my I'm developong a compact n-manifold that is homotopy-equivalent to the n-sphere if it is homeomorphic to the n-sphere. We'll be done in a couple of weeks. Wife bothering you to take out the trash? Sure honey right after I demonstrate that every simply connected closed three-manifold is homeomorphic to the three-sphere (in a topologist's sense) S^3, where a three-sphere is simply a generalization of the usual sphere to one dimension higher. Never be at a loss for words again!

    3. Re:It's all a conjecture by Barraketh · · Score: 5, Insightful

      Technically, it's more like proving P != NP, since that's the current accepted belief. Proving P=NP would be huge - this would give polynomial time algorithms for Travelling Salesman Problem, Boolean Satisiability Problem, and a slew of others (that all reduce to each other in polynomial time). Proving P != NP pretty much confirms what everyone believes to be true, similar to how the Poincaire conjecture was generally accepted to be true. Still, this is a major result, and clearly falls under the "News for nerds, stuff that matters" heading.

    4. Re:It's all a conjecture by Anonymous Coward · · Score: 4, Insightful

      Proving that P==NP wouldn't automatically give us polynomial time algorithms for any NP problem. The proof need not be constructive, and if it's not, it doesn't give algorithms. Granted, it seems easier to prove that P==NP by accidentally finding a polynomial time algorithm for an NP problem than otherwise, but don't assume that the prove would sove anything practical.

    5. Re:It's all a conjecture by S3D · · Score: 2, Funny
      echnically, it's more like proving P != NP, since that's the current accepted belief. Proving P=NP would be huge - this would give polynomial time algorithms for Travelling Salesman Problem, Boolean Satisiability Problem, and a slew of others (that all reduce to each other in polynomial time).
      Proving P=NP would cause doors to the Cthulhu dimention opened, as was shown by Charlse Stross in The Atrocity Archives
    6. Re:It's all a conjecture by ZenSkin · · Score: 2, Interesting

      Though proving P != NP does not necessarily give any insight to heuristics for NP problems. The fact, in and of itself, has no value in engineering. But it would be a significant proof and highly newsworthy. Since both the P vs NP problem and the Poincare conjecture are pesky and hard problems that have received attention in the popular press, I would imagine, like you, it is worthy of mentioning on slashdot -- indeed if it wasn't mentioned here, slashdot would be suspect.

    7. Re:It's all a conjecture by IWannaBeAnAC · · Score: 3, Insightful
      That isn't quite true: you only need a polynomial time algorithm for a single NP-complete problem, and you can transform that into a polynomial time for all NP-complete problems.

      True, that if there was a non-constructive proof that P==NP, it might not be obvious what the polynomial time algorithm actually is. But since such a scenario would be probably the most astounding open problem in the history of mathematics, I don't think it would be an open problem for long ;)

  2. This is... by mlow82 · · Score: 5, Interesting

    This is one of the Millennium Prize problems! One down, seven more to go!

    1. Re:This is... by nacturation · · Score: 5, Funny

      One down, seven more to go!

      Given that there are seven questions total, maybe you know the mystery surrounding the elusive eighth question: "What is seven minus one?"

      --
      Want to improve your Karma? Instead of "Post Anonymously", try the "Post Humously" option.
    2. Re:This is... by mlow82 · · Score: 4, Funny

      There are actually 8 problems now. I added the Twin Prime Conjecture via one mighty edit to the Wikipedia article!

      Just kidding, of course. ;)

    3. Re:This is... by ozbird · · Score: 2, Funny

      Given that there are seven questions total, maybe you know the mystery surrounding the elusive eighth question: "What is seven minus one?"

      Forty-two?

  3. Ok, in plain english by AuMatar · · Score: 2, Interesting

    Can someone boil down what the Poincare Conjecture is for us? I've had up to linear algebra in college, but I don't understand what itsa saying.

    Bonus points if you can explain some consequences of it being proven true.

    --
    I still have more fans than freaks. WTF is wrong with you people?
    1. Re:Ok, in plain english by binarybum · · Score: 4, Funny

      I think it basically has something to do with:

          If poincare conjecture = proved , my homepage switches to harsh new look. QED.

      --
      ôó
    2. Re:Ok, in plain english by Stalyn · · Score: 5, Informative

      In topology spheres are identical to cubes and pyramids. However spheres are not identical to doughnuts. What PC says is that spheres are the only class of objects that are not doughnut-like (has holes). This seems trivial and obvious to most of us however to prove it is really hard. What it shows is that there is something fundamental and important about the sphere-like class of objects. It also says something important about space itself.

      --
      The best education consists in immunizing people against systematic attempts at education. - Paul Feyerabend
    3. Re:Ok, in plain english by Auxbuss · · Score: 3, Informative
      From Millennium Prize Problems

      In topology, a sphere with a two-dimensional surface is essentially characterized by the fact that it is simply connected. The Poincaré conjecture is that this is also true for spheres with three-dimensional surfaces. The question has been solved for all dimensions above three. Solving it for three is central to the problem of classifying 3-manifolds.
      --
      Marc
    4. Re:Ok, in plain english by mozu · · Score: 4, Funny

      Seems like whats been proven is that a doughnut != sphere.

    5. Re:Ok, in plain english by david.given · · Score: 4, Funny
      In topology spheres are identical to cubes and pyramids.

      A topologist is someone who doesn't know whether to dip their doughnut into their coffee mug, or vice versa...

    6. Re:Ok, in plain english by Pendersempai · · Score: 2, Insightful

      Unfortunately this is wrong. A three-manifold is LIKE a sphere but in four dimensions. A sphere is a three-dimensional object with a two dimensional surface. A three-manifold is a four-dimensional object with a three dimensional surface. I suppose one way to visualize it is by taking our (three-dimensional) universe and imagining that if you traveled far enough in any direction you'd eventually end up back where you started, just like if an ant started walking in a straight line on the (two-dimensional) surface of a sphere he'd eventually end up back where he started.

      The Poincare Conjecture says that every three-manifold that meets some conditions (no holes cut from its surface, it's all one object, etc.) can be smoothly distorted (through a process called homeomorphism) into any other three-manifold.

      This is NOT true of two-manifolds: while you can smoothly distort (homeomorph) a sphere into a cube, for example, you cannot smoothly distort a sphere into a donut. This is because of the way we define a smooth distortion: at some point in the transformation you'd need to open up a hole in the sphere to make it into a donut, which disrupts the smoothness of the distortion. It's like if the cube were made of flexible rubber, you could bend it into a sphere, but you couldn't turn it into a donut without a pair of scissors and some glue. (This is all very hand-wavy, I know, but it's the best I can do without getting all technical.)

    7. Re:Ok, in plain english by edew · · Score: 2, Informative

      Let's look at 2-dimensional objects. There is a classification of 2-dim objects (done mostly by Euler in the late 1700s). Assume they're bounded (that is, doesn't go to infinity). There are the boundaried ones, like a sheet of paper: there's an edge to it. Then there are those without boundaries, like a sphere, or the surface of a donut, or the surface of a pretzel (three-holed). There are also orientable and non-orientable surfaces. A regular sphere is orientable: there's an outside and inside direction (if you're on the surface of the earth looking at the stars, no matter how your walk and travel, you can get back to where you were and look at the stars by looking in the same direction). A non-orientable surface would be a mobius strip. If you walk once around the strip, then looking at the stars in one direction will get to looking at a different direction. There is a non-orientable version of a sphere. The non-orientable version of a torus (the donut's surface) is called a Klein-bottle. In any case, the classification of 2-dim surfaces, orientable, compact, connected, no boundaries are basically the number of holes. Zero holes is the sphere. One hole is the torus, 2 holes is the two-torus (take two pairs of pants, sew the waists together. Then, sew the two leg holes of each pant together), 3-torus, 4-torus, etc. They're it, topologically. They're all equivalent (and equivalent here means homomorphic to each other; homeomorphic requires some additional geometric structure to stay the same). The genus of the surface is the number of holes. The main point for 2-dim is that any zero-genus surface is homomorphic to the sphere. The generalized conjecture is that any simply connected compact orientable n-dim manifold (fancy word for higher dimensional geometric object) is homomorphic to the n-sphere. Apparently, it wasn't very hard to prove it for very high dimensions. Supposedly, the constraints on the higher dimensions forced the case. The lower dimensions were rather difficult and the fifth and fourth dimension cases were solved only rather recently (in the late 80s?). The poincare conjecture was left to the 3-dimensional case, which apparently is now solved, if correct.

  4. more info by airbie · · Score: 3, Interesting
    --
    They couldn't fix my brakes, so they made my horn louder.
  5. Chinese == Good at Math by hyeh · · Score: 3, Funny

    Wow, Chinese people solved a math problem?

    This is news?

    (j/k... I am Chinese).

    1. Re:Chinese == Good at Math by dartarrow · · Score: 2, Funny

      NO the news is that the lest of the wold undestan wen thee Chinese peopre EXPRAIN the sorusion to the plobrem.

      *ducks*

      --
      I love humanity, it is people I hate
    2. Re:Chinese == Good at Math by 808140 · · Score: 4, Interesting

      As someone who has lived in China for a long time and was formerly a mathematician, I think that your statement is sort of ridiculous. For one thing, as others have pointed out, saying "some race is good at math" as if being good at math were something in your blood is silly. Having said that, the Chinese (as in, those from China) are, unfortunately, overwelmingly bad at Math. In ancient times the Chinese innovated quite competitively but this hasn't been true for a long time. Since I just took issue with your equating mathematical ability with racial characteristics, you can probably guess that there's another reason, and as it happens, I am prepared to qualify my statements.

      The Chinese school system (and in ancient times, the scholar system, which stratified society into a "scholar class" and the "masses") is completely and utterly innovation stifling. It emphasises testing and memorization above all else, and curiosity and individuality are systematically beaten out of students. No snide comments about communism, please, it has nothing to do with that (any mathematician will tell you that the Soviet Union produced a metric tonne of talented mathematicians, my advisor was one). Chinese students memorize everything. Because I speak Chinese and love math, I have tutored quite a number of high school and university undergraduate students in math and the simple reason that they suck at it is they basically cannot wrap their head around proofs.

      Proofs are difficult for most people at first, but you have to understand that the way a typical mainland Chinese kid approaches math is by memorizing every formula in his math textbook and then trying as best he can to choose the one that "works" with the problem he is presented. He does not do this because he stupid: he does this because the Chinese standardized testing system reinforces the behaviour. The exam problems are expressly designed so that various formulas are the "keys" to the problem, that is, answering the (usually multiple choice) question correctly relies on your ability to quickly recall one formula (perhaps two) and plug the numbers in effectively. So many problems are presented and so little time is given that no time for derivation or logic is really provided. Because of this, essentially every Chinese kid can recite from memory a whole host of trigonometric identities without having the faintest idea why they work or how to derive them, even when the derivation is relatively simple.

      Because there's so much anti-Chinese sentiment in the west these days and on Slashdot in particular, I want to reiterate for a moment and say that this is not an inherent failure in the Chinese kids themselves -- they are not stupid -- but they are completely crippled by their education system. From day one they memorize everything. They memorize entire passages written in old Chinese and are asked to reproduced them from memory at exam time -- I've been told by several kids here in Beijing that writing even one character wrong is essentially equivalent to forfeiting the entire problem. These are not 3 line passages folks: we're talking two or three pages of old Chinese. Imagine being told at 17 to memorize 3 pages of Beowulf. That's what we're talking about.

      The thing is (as any drama major will tell you) memorization, like all things, gets easier with practice. And from day one (when I first arrived in China I moonlighted as a Kindergarten teacher, so I have some first hand experience here) kids are memorizing stuff, from poems to proverbs to Chinese characters. It becomes easy for them, and over the years they depend on it more and more. The worst part is, high school and lower division level mathematics (if it can be called that) presents problems (like doing integrals or calculating derivatives) that lend themselves well to the "memorize a formula" method. And so Chinese kids tend to do exceptionally well in these courses, and then mistakenly assume they are good at math. This is in fact not

    3. Re:Chinese == Good at Math by Pinback · · Score: 2, Insightful

      If it follows the recent pattern, there will be a follow up story about this pair of Chinese mathematicians hiring other Chinese mathematicians to pretend the proof is real.

  6. Should share credit with Perelman by Stalyn · · Score: 5, Informative

    I thought the general consesus was that Perelman had proved Thurston's geometrization conjecture. If this proof by Zhu Xiping and Cao Huaidong is correct it must be a rephrasing of Perelman's work. Perelman is credited with making the major theoretical advances in order for any such proof. Basically he did most of the heavy lifting while these Chinese mathematicians basically dotted the i's and crossed the t's.

    The proof is 300 pages but I would guess the majority of it is an overview of Perelman's extension of Hamiltion's Ricci Flow.

    --
    The best education consists in immunizing people against systematic attempts at education. - Paul Feyerabend
    1. Re:Should share credit with Perelman by gowen · · Score: 2, Insightful

      I can't see why Perelman would share the credit. If his results are right, he proved it first. A second proof is impressive (moreso if it contains anything particularly new), but until shown otherwise, Perelman was the first, so he gets all the marbles.

      --
      Athletic Scholarships to universities make as much sense as academic scholarships to sports teams.
    2. Re:Should share credit with Perelman by m874t232 · · Score: 2, Informative

      I can't see why Perelman would share the credit. If his results are right, he proved it first.

      You haven't "proved" something until you have written it down in a form in which it convinces at least other specialists in your field. The fact that nobody knows for certain "if his results are right" is tantamount to the statement that he hasn't proven it yet.

      So, I suggest a simple rule: whichever of the two proof attempts will be verified first by at least a dozen other mathematicians or by a mechanical device, its author(s) should get recognized as the people to prove the conjecture.

    3. Re:Should share credit with Perelman by gowen · · Score: 2, Insightful
      You haven't "proved" something until you have written it down in a form in which it convinces at least other specialists in your field.
      That assertion is simply untrue.

      Suppose (and this a deliberately perverse example), Fermat had secretly developed all the machinery for Wiles' proof of his Last Theorem, and gone on to prove it. None of his contemporaries could possibly understand it. But the theorem would've been proved, even if no-one knew it.
      --
      Athletic Scholarships to universities make as much sense as academic scholarships to sports teams.
  7. Re:The proof is due to Perleman by mlow82 · · Score: 4, Informative
    From the Wikipedia article:
    In June 2006, the Asian Journal of Mathematics published a paper by Cao Huaidong of Lehigh University in Pennsylvania and Zhu Xiping of Zhongshan University in China, which has filled in the details of Perelman's work, thus "putting the finishing touches to the complete proof of the Poincare Conjecture", according to the Fields medalist Shing-Tung Yau.
    Huaidong and Xiping "filled in the details", meaning that some important details must have been missing from Perelman's work which they were able to provide.
  8. Two very good reasons by Silver+Sloth · · Score: 4, Interesting
    1. Firstly you never know when a mathematical oddity will turn out, years later, to be an essential part of something else. Both the sqare root of minus one and matraces had no posible application when they were firts investigated. Now both are essential tools for engineers.
    2. Secondly for the same reason that we flew to the moon, because if we lose our inate curiosity then we lose our humanity. There's far more to being alive than materialism
    --
    init 11 - for when you need that edge.
    1. Re:Two very good reasons by pedantic+bore · · Score: 2, Informative
      Two words: Fourier Analysis.

      --
      Am I part of the core demographic for Swedish Fish?
    2. Re:Two very good reasons by mprinkey · · Score: 2, Informative

      The key word for the airfoil problem is "conformal mapping." It is a technique used to map 2D space into the complex domain and in the process manipulated its shape. So what was a sphere or straight line segment is now an airfoil. It is used to make the solution of "potential flow" possible, so called because the velocity field of the flow is generated by the gradient of a single scalar potential.

  9. Math isn't dead by colin353 · · Score: 5, Interesting

    This is another reason why math isn't dead. The world's problems aren't solved, and they aren't impossible, either.

    I was just having a conversation about this yesterday with my math teacher.

    Lots of people think that high level math is just advanced adding and subtracting.

    This is good stuff. Props to Zhu Xiping and Cao Huaidong- this shows people that a career in studying mathematics is actually an interesting and rewarding career.

    --
    -- If unsure, say "Why?"
  10. Re:WDWC query by jopet · · Score: 2, Insightful

    Why do you care about the arts, a clean apartment, love? Well, judging from your question, you probably don't but a lot of people do.
    Not everything worthwile doing needs to result in amazing products.

    Apart from this, mathematical insights, sometimes of the more dry and abstract sort *have* already resulted in amazing products (take public key encryption, the application of insights gained from number theory).

  11. Re:WDWC query by Lord+Crc · · Score: 4, Informative

    This leads us to the answer to another pressing problem in mathematics - Why Do We Care?

    Really, what does this have to do with how we deal with reality? Will we be buying amazing products that are based on this? Breaking encryption? Making pigs fly?


    In the the 18th and 19th century, the foundations were laid for something called finite fields, which had little to no impact on reality then. Fast forward to 1960, when a couple of guys figured out a way to use finite fields in a way that enables you to still play a scratched cd, or ensuring your raid-5 is working properly when a disk fails.

    So do you still think the mathematicians back in the 18th and 19th century should have done something else, something with direct applications in their time?

  12. Chinese == Good at Math? Wrong! by Anonymous Coward · · Score: 2, Insightful

    There are so many Chinese, some of them are bound to be good at math.

  13. Math geeks are in their own L-Space by Yetihehe · · Score: 2, Informative

    If it doesn't contain holes like donut, it can be inflated until it's sphere.

    --
    Extreme Programming - Redundant Array of Inexpensive Developers
  14. ... not yet. But it may die soon. by Anonymous Coward · · Score: 4, Interesting

    The problem is rather that the complexity of current math problems has approached the limit of what humans are able to handle. Any 8th grader can verify Pythagoras, but verifying a proof like the one at hand can only be done by a handful of the world's best mathematicians and may take weeks to complete (remember what happened when Wiles proved Fermat's Last Theorem). A proof is meant to demonstrate that a given conjecture is true by splitting it up into many small steps which are considered self-evident. However, today even verifying a proof is very hard and the time may be near when no one on earth will be able to handle the complexity of this task anymore, so that even if a proof is given it may be impossible to say with certainty whether it is valid. Computers may help here, but other problems arise in that context.

    1. Re:... not yet. But it may die soon. by Ithika · · Score: 2, Insightful

      And you apparently have no ability to read what the GP said. Specifically, he suggested that most of Wiles' effort was directed at proving the Taniyama-Shimura conjecture. From that point on, it was a simple step to prove Fermat's Last Theorem (for some extremely esoteric value of 'simple').

      Note this line here:

      Actually, Wiles proof of FLT is a simplification of the Taniyama-Shimura conjecture which he proved I believe.

      Whether the grandparent poster's assertion about this method is accurate or not is neither here nor there. You managed to quote him grossly out of context and completely twisted the original message.

    2. Re:... not yet. But it may die soon. by RackinFrackin · · Score: 3, Informative

      However, today even verifying a proof is very hard

      While that's true of some proofs, it's certainly not true of all of them, or even most of them. Every year, hundreds of mathematics journals collectively publish thousands of new proofs. Some are more difficult to verify than others, but they are all verifiable (or falsifiable in the case of published errors).

      the time may be near when no one on earth will be able to handle the complexity of this task anymore

      I doubt we'll ever see that happen. Of course as a mathematical field matures, the number of accessible problems will approach zero and we're left with only the very difficult problems. However, new fields arise and give us a host of new problems to explore.

  15. Re:plain english? Maybe... by The+Mathinator · · Score: 2, Insightful

    Not quite. The fact that the n-sphere is simply connected is pretty easy to prove. Poincare asked whether every closed simply connected 3-manifold is a 3-sphere. A surface is a 2-manifold. The sphere, plane, Mobius strip, Klein bottle, and so on are all 2-manifolds. A 3-manifold is just a natural extension of that idea, except instead of a surface, you have a 3-dimensional object. They're a bit hard to visualize, since most of them don't "fit into" our notion of space, in the same way that a sphere doesn't fit into a plane. Anyway, Poincare's original question In English: if you have a 3-manifold with no holes and no border, is it necessarily the 3-sphere? Translating the more general version into English is a bit more difficult, and I'll leave it to those who actually have experience with the problem. I just read the Wikipedia article. Just a bit more information from there that might be interesting: The problem is actually easier for higher dimensions. It was first shown for dimensions 7 and above, and then worked down to the lower dimensions.

  16. A translation... by FhnuZoag · · Score: 5, Informative

    First, think in Four Dimensions. Not in terms of time, or something, but as a fourth spacial dimension - like in terms of up down, left right, in out, and foo bar. A 3 sphere is a sphere in that sort of space. For example, in three dimensions, a 2-sphere is just a normal sphere - a group of points that are all the same distance from a certain centre point. A 3-sphere in 4 dimensions is just the set of points in four dimensional space that are the same 'distance' from a point in 4D. (We define distance using the pythagorus formula sqrt(x^2 + y^2 + z^2 + k^2).)

    A 3-manifold is another four dimensional object - in fact, a class of objects. They are the analogies of surfaces in 3D space, only again we have it in 4D space. The 3-sphere, for example is an example of a 3-manifold. Simple, connected and closed are two topological properties describing what a surface is like. In layman's terms, simple connected and close means that the surface is well... just an obvious surface. The simple-connected-closed-3-manifold taken together essentially rule out the bizzare sorts of objects that mathematicians come up with. There won't be any 'holes' in the object, and there won't be any non-solid boundaries, the object can't go through itself, and you can't take two seperate objects and pretend the pair is a single one.

    So what does the conjecture say? It says that if we have any 3-manifold satisfying certain properties, there is way of distorting it (that's basically what homeomorphism means. Like you take the object as a piece of putty and stretch and pull it, or fold it, or whatever without cutting or gluing bits together) to make it into a 3-sphere.

    It's a sort of bubblegum theorem. You can chew up the manifold and blow it into a bubble. (Okay, it's not really like that, topologists.... But it's close enough)

    1. Re:A translation... by sammy+baby · · Score: 5, Informative

      so you should be able to distort a shape in 4D to a 4D sphere! and it looks like it ought to apply to any number of dimensions as well - was proof required?

      There are some things which "seem" obvious to us which aren't necessarily so. In math classes that discuss Cantor's theorem, there are always a few holdouts that refuse to believe that one infinite set can be bigger than another infinite set. After all, they're both infinite. How could one be bigger than the other? And yet it's true, and Cantor demonstrated it in a way that's so cool that you can literally explain it on the back of a napkin.

      Likewise, there are certain things that are accepted as a given, until someone discovers/proves something that causes the known world to fall around your ears, mathematically speaking. Kurt Godel pulled the rug out from a whole slew of logicians by demonstrating that not everything that's true can be proven. Up until that time, the "completeness" of mathematics had been considered a given by some people.

      So yeah - on a naive level, it may seem like "making things all bendy" is obvious, but that doesn't mean it wasn't in need of a proof.

    2. Re:A translation... by Anonymous Coward · · Score: 4, Funny

      It proves that topologically there is no difference between you yesterday, and you now with your head up your ass.

    3. Re:A translation... by OldManAndTheC++ · · Score: 3, Funny

      You lost me after 'First,'

      --
      Soylent Green is peoplicious!
    4. Re:A translation... by AxelBoldt · · Score: 4, Informative
      This is a really nice description of the theorem. I have just two small additions:

      simple connected and close means that the surface is well... just an obvious surface
      Simply connected means "no holes that you could capture with a loop". For instance, an ordinary sphere (what mathematicians call a 2-sphere, the surface of a ball) is simply connected: if you have any closed loop on the sphere, you can shrink it to a single point without leaving the sphere. The same is true for the 3-sphere. With a torus (surface of a donut) you can't always do that: there are certain loops that you can never shrink to a point without leaving the donut's surface. So the torus is not simply connected.

      A closed surface is one that does not allow points to go off to infinity (technical term: compact) and has no boundary. So for instance all of three-space is a nice simply connected 3-dimensional manifold, but it is not closed because points can run off to infinity. It also doesn't have a boundary. How could something without a boundary keep points from moving to infinity? Well, consider the 2-sphere, torus, or 3-sphere. No points in these spaces can shoot to infinity, but yet they don't have a boundary (a boundary point is a point where the surface abruptly stops). Closed manifolds somehow have to fold back on themselves.

      that's basically what homeomorphism means. Like you take the object as a piece of putty and stretch and pull it, or fold it, or whatever without cutting or gluing bits together
      Not quite: in additions to stretching and pulling, a homeomorphism also allows cutting and gluing, as long as you first cut, then move and stretch, and then glue together in exactly the same way that you cut earlier. So for example, take a little cylinder made from paper (without its top and bottom, just the side). Now cut it open along a straight line from top to bottom: if you unwrap it, you'll have a rectangle. Now create a double twist in that rectangle and glue it together along the same line again. The result is a terribly twisted "cylinder", and it is homeomorphic to the cylinder you started out with. (Had you made only a single twist rather than a double twist, then you wouldn't have glued points together that were earlier cut apart, and the result wouldn't have been homeomorphic to the cylinder--it would have been a Moebius strip.)
  17. Re:Dear God by grolschie · · Score: 2, Funny

    Does He read /. ?

  18. What does it all mean? by distantbody · · Score: 3, Funny

    What are the useful applications of this? Can I get a quantum computer next week!?

  19. Here is a conjecture by 2Bits · · Score: 4, Funny

    I assert that there is a torrent of the proof somewhere on the net. Now can someone prove that, please?

  20. Great. Still waiting for peer review.. by Anonymous Coward · · Score: 4, Insightful

    I'll accept the proof when it's been properly reviewed by peers. Just publishing a proof in a journal doesn't equate to a correct proof, now does it?

    1. Re:Great. Still waiting for peer review.. by Metasquares · · Score: 2, Informative

      The Clay prize isn't given out until 2 (IIRC) years after publication, so there will be plenty of time for it to be reviewed.

  21. Joe Public goes by advocate_one · · Score: 4, Funny

    "isn't that like the Da Vinci Code???"

    I think it makes a good thriller title... "The Poincare Conjecture"

    --
    Donald 'Duck' Dunn: We had a band powerful enough to turn goat piss into gasoline.
    1. Re:Joe Public goes by dido · · Score: 2, Interesting

      There's a whole slew of mathematical theorems, conjectures, hypotheses, et. al. that sound like Robert Ludlum novels:

      1. The Riemann Hypothesis
      2. The Eisenstein Criterion
      3. The Fredholm Alternative
      4. The Poincare Conjecture
      5. The Fourier Transform
      --
      Qu'on me donne six lignes écrites de la main du plus honnête homme, j'y trouverai de quoi le faire pendre.
  22. not necessarily by m874t232 · · Score: 4, Insightful

    The purpose of a proof is to communicate a sequence of statements such that each and every individual step is easily derivable from axioms or well-known theorems. Let me emphasize this again: a proof is about communication, not merely about making true statements.

    Perelman apparently failed to do this: he may have produced a sequence of true statements that could somehow form a subsequence of a complete proof, but he has apparently not supplied enough detail to demonstrate his point to even specialists in his area. The fact that he may have done "the heavy lifting" or that he may have provided the key ideas doesn't change that.

    I think it is valid to give all three mathematicians equal credit. And, strictly speaking, the people who actually have done the proof are the ones who "dotted the i's" because that's what ultimately constitutes a proof.

  23. Re:wouldn't trust it yet by Yrd · · Score: 3, Interesting

    This is something I'm peripherally involved in - automated proof tools are becoming more capable all the time, and I was at a keynote address by Tom Hales (University of Pittsburgh) who has been using such tools to formalise one of the proofs he's known for. There's some resistance (a lot, perhaps) to using such things in the mathematical community, but as a mathematician who's decided to use them rather than a computer scientist who's trying to prove that they're useful, he's hoping to change some minds and it's also nice for those of us in AR research to hear that there are mathematicians out there using them!

    Unfortunately, automated proof tools are not sophisticated enough to handle the kind of maths seen in solving the Really Big Problems. Not yet, anyway.

    --
    Miri it is whil Linux ilast...
  24. Re: They are the kind of people ... by 140Mandak262Jamuna · · Score: 4, Funny
    ... who would pour their coffee into their doughnuts and dunk their cups in the soggy mess and look surprised. They are topologists. They cant tell a cup from a doughnut. When they need a ball in a hurry they will break off the handle of their coffee cup and try to bounce it on the court. These topologists are the most confused/confusing mathematicians around. ;-) They could make their math easier for us lesser mortals to understand. But they would rather knot.

    --
    sed -e 's/Chuck Norris/Rajnikant/g' joke > fact
  25. Re:Is there a math geek in the house? by Wooster_UK · · Score: 3, Insightful
    I'm not too sure what you mean by "broken down into a circular-shaped plane", and I'd much sooner you lost the word "probably". I'll explain the conjecture by means of the two-dimensional version. Before I get there, I've got to explain what I mean by a "sphere", because the mathematical definition is quite specific. A "sphere" is the skin of a ball, okay, so it's all the points lying at a distance r, say, from the origin. Having been so specific about all that, I'm now going to be dreadfully, appallingly loose in the rest of my language. Here we go.

    Now, suppose you've got a surface, let's call it S, which is bounded (so it's finite in any direction), closed (so it's not got an edge), and simply-connected (so it's got no holes). Then by twisting, stretching, moving and generally deforming S in any way you like, but without taking scissors to it, you can turn it into a sphere. That's the Generalised Poincaré Conjecture, reduced to 2 dimensions, and it was proved, oh, ages ago. To understand the higher dimension versions, just imagine doing that for an n-sphere, which is the set of all points lying at a distance r from the origin in n-dimensional space.