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Proving 0.999... Is Equal To 1

eldavojohn writes "Some of the juiciest parts of mathematics are the really simple statements that cause one to immediately pause and exclaim 'that can't be right!' But a recent 28 page paper in The Montana Mathematics Enthusiast (PDF) spends a great deal of time fielding questions by researchers who have explored this in depth and this seemingly impossibility is further explored in a brief history by Dev Gualtieri who presents the digit manipulation proof: Let a = 0.999... then we can multiply both sides by ten yielding 10a = 9.999... then subtracting a (which is 0.999...) from both sides we get 10a — a = 9.999... — 0.999... which reduces to 9a = 9 and thus a = 1. Mathematicians as far back as Euler have used various means to prove 0.999... = 1."

56 of 1,260 comments (clear)

  1. (0.999...)st Post! by Anonymous Coward · · Score: 5, Funny

    (0.999...)st Post!

    1. Re:(0.999...)st Post! by arivanov · · Score: 3, Funny

      2+2=5 for sufficiently big values of 2.

      --
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    2. Re:(0.999...)st Post! by Dan+East · · Score: 4, Funny

      Geez these first posters. Like spammers, always looking for a new attack vector. I'm sure he's been sitting on this particular exploit for a long time, just waiting for his opportunity to strike. You've won today, but we're all onto your trick when you try to (0.999...)st post the next story...

      --
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    3. Re:(0.999...)st Post! by derrida · · Score: 5, Funny

      2+2=5 for sufficiently big values of 2.

      or for sufficiently small values of 5.

      --
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    4. Re:(0.999...)st Post! by Vintermann · · Score: 4, Funny

      But, if you choose the rounding method known as "floor", then 0.999... is 0, right? So for sufficiently bad rounding methods, 1 = 0.

      --
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    5. Re:(0.999...)st Post! by acedotcom · · Score: 3, Funny

      geek humor...ruining it for everybody.

      --
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    6. Re:(0.999...)st Post! by LastDawnOfMan · · Score: 3, Funny

      Which is why it's a good idea to forego buying food that advertises itself as having "0% trans fats."

    7. Re:(0.999...)st Post! by ByOhTek · · Score: 3, Interesting

      What I'm saying, is I don't think anyone would accept such a proof, because while recognized, floor and ceiling are rarely considered useful due to inclusion of error, and most people don't even think of ceiling (only floor).

      So, sorry, 2+2=6 is a stretch compared to 2+2=5. You might as well say 2+2=1000000, ceiling-rounded to the nearest million

      --
      Self proclaimed typo king, and inventor of the bear destroying coffee table (patent not pending).
    8. Re:(0.999...)st Post! by interkin3tic · · Score: 4, Funny

      Shoot, I just spent my last 0.999... mod points.

  2. I went one further by MyLongNickName · · Score: 4, Funny

    I was able to prove that with even one less "9" after the decimal point, it STILL equaled 1. I plan on doing this for a few more iteration until I can prove that . = 1

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    1. Re:I went one further by MyLongNickName · · Score: 3, Insightful

      And seriously... is this really front page material? The simplest proof is to say "express 1/9" as a decimal. Now multiply both sides by 9. I remember this in elementary school algebra.

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    2. Re:I went one further by betterunixthanunix · · Score: 4, Insightful

      Small numbers usually win; express 1/3 as a decimal, and multiply by 3. The problem with that, though, is that people have trouble accepting that there was nothing wrong with what they did -- a lot of people have this implicit assumption that if a few simple steps bring them to a result that doesn't look like it makes sense, then they did something wrong. If you get them a more complicated proof (assuming they can follow it), they are more willing to accept the result.

      --
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    3. Re:I went one further by cgenman · · Score: 3, Insightful

      Conceptually, 0.999... keeps getting closer and closer to 1, as you add more decimal places. It approaches 1. This limit is how all calculus works. Any series that approaches another number as you flesh out the series further and further, will be that number once you have taken the series to infinity.

    4. Re:I went one further by MozeeToby · · Score: 4, Insightful

      a lot of people have this implicit assumption that if a few simple steps bring them to a result that doesn't look like it makes sense, then they did something wrong.

      It should be noted that this is not a bad thing. Indeed, it is one of the first things that a good math teacher will teach to the class - all answers should go through a 'does this make sense?' filter before you consider the problem done. It is only very rarely that it causes problems, and it is exceedingly common that it prevents them.

    5. Re:I went one further by radtea · · Score: 5, Insightful

      The problem with that, though, is that people have trouble accepting that there was nothing wrong with what they did -- a lot of people have this implicit assumption that if a few simple steps bring them to a result that doesn't look like it makes sense, then they did something wrong.

      Nope, the problem is that the people who discuss this question are lousy teachers. They set it up deliberately to create a block in other people's minds that makes it unnecessarily difficult for them to understand what is being claimed and why it is true.

      If instead they said, "It is possible to represent numbers in different ways. We all know this, and it's completely uninteresting, but I'm going to bore you with it anyway. You know you can represent 1/3 as 0.3333... right? No big deal. Now curiously that also means you can represent 1/1 = (3*1/3) as 3*0.3333... or 0.99999... It's just a different representation of exactly the same value. You can of course also represent 1 as 5*1/5 1/2+1/2 and all kinds of other awkward and unintersting ways, too."

      I'm not sure why people insist on presenting this result in the most counter-intuitive way possible and then wasting vast amounts of time trying to undo the damage they've inflicted with their incompetent introduction of the problem. My guess is that they are simply not very smart, as anyone who isn't fairly dumb would see that there is an obvious pedagogical problem at play here, and correct their presentation accordingly, rather than blindly and stupidly repeating the rote "0.9999... = 1" introduction to the remarkably dull fact that you can represent the same value in different ways.

      Of course, in an insanely strictly typed language with infinite precision 0.999... would not quite be the same as 1, as the former is a real and the latter is an integer, so despite having the same value their different types would mean they could not be used identically in all circumstances.

      --
      Blasphemy is a human right. Blasphemophobia kills.
    6. Re:I went one further by mea37 · · Score: 3, Informative

      People assuming they did something wrong when the result "doesn't make sense" isn't the problem.

      People failing to distinguish between a notation and a number, creating the belief that "0.99(9)=1" doesn't make sense, is the problem.

      Consider this proof, which follows simple steps to reach a conclusion that doesn't make sense:

      i^2 = -1 (definition of i)
      i^2 * i^2 = -1 * -1
      i^4 = 1
      sqrt(i^4) = sqrt(1)
      i^2 = 1
      -1 = 1

      Then if you want you can add 1 to both sides and divide by 2, to find 0 = 1.

      Now, do you know why this proof is bogus? When I was in high school, we were introduced to imaginary numbers, and I drew up a slightly more obfuscated version of the above; it had a lot of people (including a couple relatively sharp teachers) in "I know you did something wrong because the result doesn't make sense" mode for a long time.

      The fault, of course, lies with the sqrt() step. For a=a to imply sqrt(a)=sqrt(a), we have to interpret sqrt(a) as the pricple square root function, so sqrt(x^y) = x^(y/2) doesn't necessary work when x isn't a real number.

      Without the motivation of "this result cannot be right", I wouldn't have puzzled this out. More than that, the solution comes from understanding that rules we take for granted only apply to certain types of number. Applying that to 0.99(9), it's easy for people to convince themselves that repeating decimals are a special class of number subject to "some rule I just don't know".

      But in this instance, that reasoning is flawed, because .99(9) really is just a regular real number in a weird notation.

    7. Re:I went one further by MobileTatsu-NJG · · Score: 4, Funny

      And seriously... is this really front page material?

      You'd rather argue about smartphones?

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    8. Re:I went one further by Eunuchswear · · Score: 3, Funny

      Absolutely.

      Did I tell you that the N899.999... is the the bee's knees?

      --
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    9. Re:I went one further by Evo · · Score: 5, Informative

      Surely the problem is that you're assuming sqrt(1) = 1 when actually it is +- 1? You're throwing away the sign change in that step :)

    10. Re:I went one further by Apatharch · · Score: 3, Informative

      Yes it is. Insofar as using infinity as an arithmetical value is valid, 10/infinity = 9/infinity = 1/infinity = 0.

  3. This is second place by betterunixthanunix · · Score: 4, Insightful

    0.999... = 1 is second place to the Monty Hall Problem on the list of things that people have difficulty understanding and accepting the proof of. It is second place because the only department where I do not see graduate students giving me a confused look is the math department; with the Monty Hall problem, I will sometimes get a confused look even from people in the math department.

    The other reason I put it in second place is that most people have difficult understanding the problem at all, whereas very few people have trouble understand what the Monty Hall problem is asking.

    --
    Palm trees and 8
    1. Re:This is second place by MyLongNickName · · Score: 4, Informative

      It is easy to explain.

      1. 1/9 = 0.111111111111111111111111111111.....
      2. Multiply each side by 9
      3. 9/9 = 0.999999999999999999999999999999......
      4. Simplify fraction
      5. 1 = 0.999999999999999999999999999999......

      Monty Hall trips up even serious math enthusiasts.

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    2. Re:This is second place by ObsessiveMathsFreak · · Score: 4, Insightful

      The Monty Hall problem and its delinquent cousin the Tuesday Boy problem are genuinely difficult because the answer is highly dependent on the way that the question is posed.

      0.9999...=1 is not genuinely difficult because at the end of the day it's a very informal statement about adding an infinite number of decimals, and the only real controversy about the statement exists among 4chan trolls and Wikipedia users. Most who don't understand don't care and most who do understand also don't care.

      The only people with a problem are the people who don't understand but still care, but then that's the problem with most topics these days.

      --
      May the Maths Be with you!
    3. Re:This is second place by kannibul · · Score: 4, Interesting

      This could be done with any fraction represented as a repeating decimal.
      The trip-up is that it's repeating...since we have no concept for infinity, and, that there's no method of resolving a fraction w/ repeating decimal...it's not an accurate representation of the fraction - that's the flaw.
      Therefore, Fractions are Good. Decimals are Evil!
      Good thing our banks, credit card companies, and governments don't use repeating fractions.

    4. Re:This is second place by Colonel+Korn · · Score: 5, Informative

      Unfortunatelly, your proof is not valid. You are trying to prove something which you postulate in your first step.
      How do you know 1/9 equals 0.1111111.... ?

      He begged the question! For anyone confused about the term "beg the question," this is exactly what it means: assuming the proposition to be proved in the premise.

      But that begs the question: is the classical meaning already dead, replaced with the much more easily understood modern usage demonstrated here?

      --
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    5. Re:This is second place by Missing.Matter · · Score: 5, Insightful

      I remember being told this in highschool. There was much objection, but the teacher shut us up by simply saying "give me a number in between them."

    6. Re:This is second place by metamechanical · · Score: 4, Insightful

      The Monty Hall problem and its delinquent cousin the Tuesday Boy problem are genuinely difficult because the answer is highly dependent on the way that the question is posed.

      I would argue that the Monty Hall problem is difficult because people don't take into account the fact that the result is NOT path independent.

      It would be much easier (I think) to understand intuitively if people realized that it was highly likely that they picked the wrong door to start. A more intuitive way of explaining the problem to somebody would be to increase the number of doors - to say, infinity. If there are infinity minus one closed doors with goats behind them, and a single door with a car behind it, the odds are obviously very high that you picked a goat. The probability that you picked the car is vanishingly small. Therefore, when the host opens every door except yours and one other, and they all reveal goats, the odds are very, very high that the other door hides a car, and yours hides a goat.

      Now, reduce that to 3 doors. The same logic applies.

      --
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    7. Re:This is second place by Johnny+Mnemonic · · Score: 4, Funny

      Typical engineer. Here's the operations perspective:
      a reliability of 1.0 equates to never fail.
      a reliability of .999... means "sometime fail".

      The sales guy will sell 1.0, and when failure happens, explain that what was really meant was .999...

      Good luck with that.

      --

      --
      $tar -xvf .sig.tar
    8. Re:This is second place by Chapter80 · · Score: 5, Funny

      I remember being told this in highschool. There was much objection, but the teacher shut us up by simply saying "give me a number in between them."

      Duh. 0.9999... and a half!

    9. Re:This is second place by AllieA · · Score: 3, Interesting

      I am not a mathematician, but I have always considered the Monty Hall trick to be more of a word trick than any basis in mathematics. Look at it this way:

      If you pick one door out of a million and Monty Hall opens 999,998 others and it's between yours and the other door, there's a good chance Monty Hall knew where the car was since the chances of him doing that at random are so small, so of course your chance is better if you switch to the other door since there is a strong probability he didn't miss that one door just by chance.

      On the other hand, if Monty opens 999,998 doors at random and still hasn't revealed the car, despite the unliklihood of that happening, then the odds are still 50/50 that you have the right door. The odds at first might have been 1 in a million, but now they are 1 in 2 since the other 999,998 have been eliminated without a biased factor (Monty's choice).

      It's the human element that always seems to get lost here. The real question is whether the other 999,998 doors are eliminated by someone who knows where the car is (Monty) or by chance.

  4. Time to Update my SLA by Anonymous Coward · · Score: 5, Funny

    Now I can replace my SLA with 100% uptime.

  5. Or by Anonymous Coward · · Score: 3, Insightful

    1/3 = 0.3333...
    2/3 = 0.6666...

    0.3333.... + 0.6666.... = 0.9999....

    1/3 + 2/3 = 1 = 0.9999.....

    1. Re:Or by Culture20 · · Score: 3, Funny

      As a mathematician, I have always hated people who claim that 0.999... = 1 can't be true.

      As a nerd, I have always hated people that hate others for trivial reasons. You're just a math bully.

  6. Re:I'm Surprised by Anonymous Coward · · Score: 3, Funny

    They damn well better, how else will I measure out all this dental floss.

  7. This is so old... by DiSKiLLeR · · Score: 3, Interesting

    This is so old...

    Even Blizzard issues a press release about it years ago because people kept arguing about it on the Blizzard forums.

    http://www.mbdguild.com/index.php?topic=14915.0

    --
    You can tell how powerful someone is by the magnitude of the crime they can commit and be able to get away with.
  8. Re:Finally by Vectormatic · · Score: 5, Funny

    just as long as no-one proves 0 = 1 we computerpeople are safe...

    --
    People, what a bunch of bastards
  9. Cribbed, Since My Memory for Jokes Sucks by Anne_Nonymous · · Score: 5, Funny

    In the high school gym, all the girls in the class were lined up against one wall, and all the boys against the opposite wall. Then, every ten seconds, they walked toward each other until they were half the previous distance apart. A mathematician, a physicist, and an engineer were asked, "When will the girls and boys meet?"

    The mathematician said: "Never."
    The physicist said: "In an infinite amount of time."
    The engineer said: "Well... in about two minutes, they'll be close enough for all practical purposes."

    1. Re:Cribbed, Since My Memory for Jokes Sucks by Daniel_Staal · · Score: 4, Informative

      Actually, a good physicist should have been able to give an answer (or something close to it) as well...

      Eventually, they will come to a point where they would be required to move less than 1.616252(81)×1035 meters closer together. From the uncertainty principle, we know we cannot measure position more accurately than that. So either they will not move at all, or they will superimpose at that point.

      --
      'Sensible' is a curse word.
  10. And if by Dunbal · · Score: 3, Funny

    0.99999... is equal to 1, then 0.999999...8 is equal to 0.99999... and 0.9999999...7 is equal to 0.999999...6 etc etc etc until 1 = 0! Holy shit!

    Or we could just admit that using a tool incorrectly produces idiotic results.

    --
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  11. Re:Oh yeah? Well... by MyLongNickName · · Score: 3, Informative

    this probably isn't necessary for most of the Slashdot crowd, but...

    (a+b)(a-b) = b(a-b) --> a + b = b

    Required division by (a-b) on both sides. Since a = b, this is division by zero.

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  12. Re:This is just faulty math by Sockatume · · Score: 5, Insightful

    Actually, if you define 0.999... as having an infinite number of decimal points, then it is true. And that's how that ellipsis is defined! It means exactly infinite repeating decimals.

    You've demonstrated the first hurdle that this problem raises in people's brains: they start thinking about adding "one more" decimal point to the expression, meaning they're thinking of a large but finite number of decimal points. And the second hurdle: people find it hard to believe that you can do mathematics with "infinity" as a meaningful quantity.

    --
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  13. Re:Finally by SoVeryTired · · Score: 3, Insightful

    If pressed, many logicians will admit that the modern foundation of mathematics (ZFC) is probably inconsistent.
    See this article:
    http://www.math.princeton.edu/~nelson/papers/warn.pdf

    The author discusses an informal survey he took among loogicians on page three.

    If someone ever discovers a paradox, we can simply scale back to some other system and keep most of what we know, but still...

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  14. Re:When you add/subtract/multiply/divide infinite by BlackPignouf · · Score: 5, Funny

    Wrong, wrong and wrong.

    First off, you're not talking about sets, but separate finite numbers.

    Then, infinity is neither rational nor irrational.

    Then, all numbers that have "infinite repeating decimals" are rational. See : http://en.wikipedia.org/wiki/Rational_number

    The decimal expansion of a rational number always either terminates after finitely many digits or begins to repeat the same finite sequence of digits over and over. Moreover, any repeating or terminating decimal represents a rational number. These statements hold true not just for base 10, but also for binary, hexadecimal, or any other integer base.

    So that means 0.999999..... is rational. Which rational you ask? Why! 9/9 :D

    Finally, if you say 0.99999999..... is less than 1 : what is the difference between both?
    We know it's less than any positive epsilon (0.1, 0.01, or 0.00000.....00001).
    Which means it's nil.
    There's no place for a single mosquito fart between 0.999999... and 1.

  15. People don't really know what numbers are by qmaqdk · · Score: 3, Interesting

    This just goes to show that people don't really know what numbers are, at least when they are infinite decimal numbers. A finite decimal number corresponds to a rational number, e.g. 9.99 corresponds to 9 + 9/10 + 9/100. The way you describe infinite decimal numbers of by denoting a sequence of finite decimal numbers that goes towards this infinite decimal, in our case: 0.9, 0.99, 0.999, etc. This, by the way, is how you construct the real numbers (pi is described in such a way).

    In doing so, however, there are multiply ways of describing the same number; the sequences 0.9, 0.99, 0.999, etc. and 1, 1, 1, etc. describe the same number, and this apparent non-uniqueness is probably what bugs people.

    --
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  16. Re:Finally by Jason+Levine · · Score: 3, Insightful

    Suppose you have 3 numbers, a, b and c such that c = b - a.

    Multiply each side by (b - a) to get:

    c(b - a) = (b - a)(b - a) => Or....
    cb - ca = b^2 - 2ba + a^2 => Now add (ab - a^2 - cb) to both sides
    ab - ca - a^2 = b^2 - cb - ba => Or....
    a(b - c - a) = b(b - c - a) => Divide both sides by (b - c - a) and.....
    a = b

    There you go! Proof that any two numbers (such as 0 and 1) are equal.

    (Yes, I know there's a flaw in there. Let's see who'll spot it first.)

    --
    My sci-fi novel, Ghost Thief, is now available from Amazon.com.
  17. Re:Finally by MyLongNickName · · Score: 4, Informative

    I am compelled to answer...
    Divide both sides by (b - c - a) is dividing by zero.

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  18. Re:Finally by drakaan · · Score: 3, Insightful

    Okay, but this isn't a problem with the foundation of math being inconsistent, this is a problem with people not knowing how to write the number normally known as "1" in a different way. Most people would grasp "3/3" as being the same as 1, but this *looks* different because they're unused to seeing it.

    The fact that the fractions 1/3 (known in decimal notation as .3...) and 2/3 (known in decimal as .6...) have a sum that can be written funny doesn't mean that they don't still add up to 1.

    A mathematical amusement causes people confusion and consternation. It's like asking someone why they appear reversed left-to-right in a mirror, but not top-to-bottom, and saying there's an inconsistency in the foundation of physics.

    The problem is that partial understanding of a subject and an associated problem in that subject makes things *appear* inconsistent when they are not.

    --
    "Murphy was an optimist" - O'Toole's commentary on Murphy's Law
  19. Corrected, Since My Memory for Jokes Sucks by Anne_Nonymous · · Score: 5, Funny

    In the high school gym, all the girls in the class were lined up against one wall, and all the boys against the opposite wall. Then, every ten seconds, they walked toward each other until they were half the previous distance apart. A mathematician, a physicist, and an engineer were asked, "When will the girls and boys meet?"

    The mathematician said: "Never."
    The physicist said: "Eventually, they will come to a point where they would be required to move less than 1.616252(81)×1035 meters closer together. From the uncertainty principle, we know we cannot measure position more accurately than that. So either they will not move at all, or they will superimpose at that point."
    The engineer said: "Well... in about two minutes, they'll be close enough for all practical purposes."

  20. Re:Humans are just biased towards natural numbers by blueg3 · · Score: 4, Informative

    They're not proving "0.99999 = 1" at all. That's not true. They're proving that "0.999... = 1". One is an infinite sequence of digits, and the other isn't. The distinction is important. The proof of "0.999... = 1" has nothing to do with rounding, and to suggest so indicates a (common) gross misunderstanding of the problem.

    First, you only measure things with such poor precision because you're working well above the quantum level.

    Second, natural numbers are certainly important. For one, they're critical to our understanding of the rest of mathematics, which is important for fancy things like being able to take measurements and manipulate them at all. For another, we work with whole numbers of objects all the time -- two apples, ten antelope, four huts, etc. It's not "10 +/- 0.01 antelope".

  21. Re:Finally by AshtangiMan · · Score: 3, Funny

    I think about this from time to time when messing with changing units. 2 cm squared is 4 cm2 and 4>2. But .02 m squared is .0004 m2 and .0004 .02. They both describe the same amounts. I obsessed over this for a while one day until I realized that the relative values of a scaler and an area meant little, but for a while I was really worried.

  22. Re:Cat and Mouse by blueg3 · · Score: 5, Funny

    An infinite number of mathematicians walk into a bar. The first one orders a beer. The second one orders a half a beer. The third orders a quarter of a beer. The bartender says, "You're all idiots," and pours two beers.

  23. More fun... by digitig · · Score: 3, Informative

    It's more fun to work out why this proof fails when using non-standard analysis (in which 0.999... != 1).

    --
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  24. I've had this argument more times than I'd like by Benfea · · Score: 3, Insightful

    The problem with the argument you present is that people who don't believe 0.999...=1 also don't believe that 0.333...=1/3. They can't quite wrap their heads around the concept of infinity, so in their minds 0.333... continually comes closer to 1/3, but never quite reaches it because they can only imagine a finite number of digits. They honestly think of infinity as being a really large finite number, so they believe that no matter how many digits you add to 0.333..., it never quite reaches 1/3.

    Another part of the problem is that many people simply can't wrap their heads around is that they don't separate the idea of a number and the symbols used to represent numbers, thus they cannot grasp that some numbers can be represented in more than one way by our number system.

  25. I've tried what you suggest, and it DOESN'T WORK by Benfea · · Score: 3, Insightful

    As soon as you get to "You know you can represent 1/3 as 0.333... right?", you hit a brick wall. People who believe that 0.999... does not equal one also believe that 0.333... does not equal 1/3, and for many of the same reasons. Taking your approach, you simply shift from arguing about whether or not 0.999... equals one to arguing about whether or not 0.333... equals 1/3. You have to get at the root of the problem of why they refuse to believe those numbers are equal before you can get anywhere.

  26. Re:I've tried what you suggest, and it DOESN'T WOR by Omestes · · Score: 5, Interesting

    People who believe that 0.999... does not equal one also believe that 0.333... does not equal 1/3, and for many of the same reasons.

    For once in my life I can claim someone is underestimating the average person!

    I don't believe .999... = 1. Let me qualify that a bit, I intellectually and academically know it, but on a softer, more psychological level, I don't actually believe it. When presented with it, my first reaction would be "Hell no! Stupid.", even though I know it is true.

    Why? Because your mapping two concepts that we all were taught as a kid isn't true. Does .9 = 1? Or .99? Or .999? or ... Or .999999999999(a ridiculous but non-infinite number of times)? Most grade school kids would say "no", and be correct. Then you hit the infinite jump, and suddenly it becomes true. So you run into two problems, the problem of it not being immediately obvious (common sense), and the problem of conceptualizing infinity.

    On a lower level, its like saying A = ~A. You have a proof saying basically that ~A was A all along, so the actual preposition was wrong, which makes sense, but on a surface level all you can see is A =~A.

    I have no problem whatsoever with 1/3 = 0.3333... This makes sense, its like stating A = A. 1/3 being 0.3333 is obvious. I would even get in trouble in lower level math classes for not mucking with fractions, and going straight for the decimals, since I never say fractions outside of cookbooks and socket sizes. 1/3 = 0.33333... makes sense, it is clear and obvious, and can be explained with a single phrase (not a proof); "the "/" means division". .999999... doesn't have this.

    No, I'm not stupid, or at least for this reason. I know damn well that 0.9999... = 1, and if I ever find myself in a situation where that bit of knowledge can be applied (usefully, not just for building my ego on the internet), I will do it properly. My first reaction is still "bullshit!" on a visceral level, though. I don't perceive it as true, even if I know it is.

    I suppose I can map this experience to most of the "social knowledge vs. science" debates in our culture currently. I won't.

    --
    A patriot must always be ready to defend his country against his government. -edward abbey
  27. In base 10 it is 0.14285714285711. by spaceturtle · · Score: 3, Informative
    In base 8, .11111111 = 1/10 + 1/100 + 1/1000 ... which in base 10 is 1/8 + 1/64 + 1/512 + ... = 0.14285714285711...., which multiplied by 7 is clearly 0.999... (which can be more succinctly represented as "1").

    Also a terminology issue, the number of ones in 0.111111... is indeed "Countable".