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Climate Damage 'Irreversible' According Leaked Climate Report

New submitter SomeoneFromBelgium (3420851) writes According to Bloomberg a leaked climate report from the IPPC speaks of "Irreversible Damage." The warnings in the report are, as such, not new but the tone of voice is more urgent and more direct than ever. It states among other things that global warming already is affecting "all continents and across the oceans," and that "risks from mitigation can be substantial, but they do not involve the same possibility of severe, widespread, and irreversible impacts as risks from climate change, increasing the benefits from near-term mitigation action."

708 comments

  1. Damage or Change? by Gothmolly · · Score: 0, Troll

    Climate has always changed, the concept of "Damage" is only relevant to those affected by it. But lets pretend that they're the same thing, because it will gather more clicks.

    --
    I want to delete my account but Slashdot doesn't allow it.
    1. Re:Damage or Change? by Urkki · · Score: 5, Insightful

      Climate has always changed, the concept of "Damage" is only relevant to those affected by it.

      You mean, the same way as asteroids of various sizes have impacted into the Earth throughout the history of the planet, and "Damage" is only relevant to those affected by it?

      Yes, I agree.

    2. Re:Damage or Change? by thedonger · · Score: 2, Informative

      Climate has always changed, the concept of "Damage" is only relevant to those affected by it.

      You mean, the same way as asteroids of various sizes have impacted into the Earth throughout the history of the planet, and "Damage" is only relevant to those affected by it?

      Yes, I agree.

      Sure, why not? And it is only "damage" to the species that die out. Think of all the evolutionary opportunity there will be in the Next Phase!

      --
      Help fight poverty: Punch a poor person.
    3. Re:Damage or Change? by GameboyRMH · · Score: 4, Insightful

      I, for one, welcome our new raccoon-descended overlords.

      --
      "When information is power, privacy is freedom" - Jah-Wren Ryel
    4. Re:Damage or Change? by Anonymous Coward · · Score: 1

      And water acts like a solid at the femtosecond time scale. Yes climate always change, slowly. That's the point, it's not changing slowly anymore.

    5. Re:Damage or Change? by Anonymous Coward · · Score: 0

      I, for one, welcome our new raccoon-descended overlords.

      Agreed.

    6. Re:Damage or Change? by Anonymous Coward · · Score: 0

      Climate has not always changed slowly. Proxies have shown radical shifts in the climate on the scale of tens of years and this was when there were no hoo-mans around to burn fossil fuels and such and discounting things like asteroids.

      No, climate is not a stable thing and, yes, it can change rapidly. Just because we think we're the lords of the earth and all creation because of some ancient texts doesn't make it so and that the world will always bend knee to us.

      We'll go extinct. The climate and remaining life forms will adapt and things will go on as they have for billions of years.

    7. Re:Damage or Change? by Anonymous Coward · · Score: 0

      Exactly.

      The biosphere as we know it completely obliterated the previous hot, molten rock strewn landscape; the damage was immeasurable. Did the formation of the oceans "damage" the landscape and life on it as it they filled up? Did the receding glaciers damage the ocean salinity?
      There have been hot and wet periods, cold and icy periods and long stretches in between where things were "just right" (by our human standards). Cycles.
      We may in fact be in a period of human induced global warming or not, but climate change is going to be 100% guaranteed as long as Earth has any atmosphere of any kind. In the end the Earth will be fine, it's always fine, it will adapt and new life may or may not be able to form in the resultant environment. People may or may not be able to survive the environment but the Earth will exist until the local star swallows it up in a few billion years. Humans won't be missed by the later dominant species any more than we miss any species that has been extinct for millions of years, in other words a curiosity if we even know about them

    8. Re:Damage or Change? by Anonymous Coward · · Score: 0

      Tell that to your insurer, I'm sure they'll disagree.

    9. Re:Damage or Change? by Anonymous Coward · · Score: 1

      Think of all the evolutionary opportunity there will be in the Next Phase!

      There won't be any. Well, there will be, but those new species will never get the chance to progress up the evolutionary ladder as humans did, ever again. The reason is you need easily accessible primary resources and especially primary energy to do that, otherwise you're stuck. And we made sure (and will make sure in the time until our demise) that all those resources are fully exhausted.

    10. Re:Damage or Change? by Drethon · · Score: 1

      Climate has always changed, the concept of "Damage" is only relevant to those affected by it.

      You mean, the same way as asteroids of various sizes have impacted into the Earth throughout the history of the planet, and "Damage" is only relevant to those affected by it?

      Yes, I agree.

      Well yeah, the last couple of major asteroid impacts above Russia just broke a few windows.

    11. Re:Damage or Change? by amiga3D · · Score: 1

      They'll still have solar, wind, geo-thermal and hydro so at least next time will be green.

    12. Re:Damage or Change? by Anonymous Coward · · Score: 0

      I, for one, welcome our new raccoon-descended overlords.

      I'm betting if things get that bad we'll start fighting over 'survivable' areas (especially when it pertains to food/agricultural areas & fresh water)... and at some point the nukes will start flying. ... in which case I believe that becomes our new cockroach-descended overlords. :-P

    13. Re:Damage or Change? by Anonymous Coward · · Score: 0

      Think of all the evolutionary opportunity there will be in the Next Phase!

      There won't be any. Well, there will be, but those new species will never get the chance to progress up the evolutionary ladder as humans did, ever again. The reason is you need easily accessible primary resources and especially primary energy to do that, otherwise you're stuck. And we made sure (and will make sure in the time until our demise) that all those resources are fully exhausted.

      Nonsense. In another few 100 million years there will be lots of fossil fuels (coal, oil, gas, etc) again... it'll just take a while for 7 billion of us to get 'plowed under' by the planet and decayed/compressed/heated into stuff for whatever comes next.

    14. Re:Damage or Change? by Curunir_wolf · · Score: 1

      Think of all the evolutionary opportunity there will be in the Next Phase!

      There won't be any. Well, there will be, but those new species will never get the chance to progress up the evolutionary ladder as humans did, ever again. The reason is you need easily accessible primary resources and especially primary energy to do that, otherwise you're stuck. And we made sure (and will make sure in the time until our demise) that all those resources are fully exhausted.

      Which is why I can't understand the myopic thinking around what to do about climate change. It seems the alarmists are adamant that the agenda should be to curtail use of energy by a combination of stopping use of fossil fuels, reduction of energy use generally, and limiting human habitat to allow conservation of wildlands. It's a "hunker-down" approach which, yes, may give humans more time. Yet, if, as they claim, it's human habitat (and thus future generations of humanity) that are in danger and need preserving, it seems clear that their strategy is one that will only buy time.

      The only way to ensure the long-term viability of humanity is to spread. Whether that is colonization of space, the solar system, or multi-generational ships to other stars, is not entirely relevant, only that there must be an effort in that direction. Crawling back and tightening the apron strings to mother earth only means that humans will never grow up and leave the nest. Perhaps this is the civilization firewall that explains the Fermi paradox.

      --
      "Somebody has to do something. It's just incredibly pathetic it has to be us."
      --- Jerry Garcia
    15. Re:Damage or Change? by swillden · · Score: 1

      Climate has always changed, the concept of "Damage" is only relevant to those affected by it.

      You mean, the same way as asteroids of various sizes have impacted into the Earth throughout the history of the planet, and "Damage" is only relevant to those affected by it?

      Yes, I agree.

      Yep. In the long run, the climate will change no matter what we do... unless we learn to actively manage it. Similarly, we will get hit by a catastrophically-destructive meteor, unless we develop the technology need to identify and deflect dangerous asteroids. It's worth noting that while without our intervention the climate may stay as it is for thousands of years, it may also change in decades. The ice core records tell us that the planet is capable of warming or cooling as much as 7C in as little as 20-30 years, even without any obvious catastrophic event, and even faster given a supervolcano eruption, or a big meteor. It WILL happen.

      IMO, while it certainly makes sense to take reasonable steps to limit greenhouse gas production, we really need to focus on investing heavily in climate research, with an eventual goal of learning not only to understand but to manage our planet's climate. Actually, we should also invest a little in more strategies to cope with unpleasant climate. I say "more" strategies, because we already have a lot of them. The regions of Earth in which humans can survive comfortably without technological assistance are really small. The "natural" human carrying capacity of most of the places people live is basically zero, but we're very good at modifying our environment to adapt it to our needs. When the planet warms substantially, no doubt we'll have to apply more of those skills, so we should be thinking about which ones and how to improve our capabilities.

      --
      Note to ACs: I usually delete AC replies without reading them. If you want to talk to me, log in.
    16. Re:Damage or Change? by riverat1 · · Score: 1

      It seems the alarmists are adamant that the agenda should be to curtail use of energy ...

      It's more about changing the way we produce energy, not curtailing it. Besides, who can be against reduction of energy use through using it more efficiently?

    17. Re:Damage or Change? by thedonger · · Score: 1

      We've had a good run. Time to pick up our fiddles and enjoy the fire.

      --
      Help fight poverty: Punch a poor person.
    18. Re:Damage or Change? by Raenex · · Score: 1

      Besides, who can be against reduction of energy use through using it more efficiently?

      It's not so simple: Jevons' Paradox

  2. knuckle dragging rewards won't believe this by Anonymous Coward · · Score: 0

    Alright morons, show us how stupid you are and demonstrate your ignorance of basic scientific principals!

    1. Re:knuckle dragging rewards won't believe this by Anonymous Coward · · Score: 0

      damnitalltohell, when you say it wrong, you sound like a maroon (intentionally mis-spelled moron) - it's retards, not rewards.

  3. More urgent? by Anonymous Coward · · Score: 0, Funny

    More urgent and direct than ever? That's good because they were so calm about it up to now.

    1. Re:More urgent? by Anonymous Coward · · Score: 2, Insightful

      I love the way it's claimed to have been "leaked", as though the IPCC would sit on this. Perhaps they think making it officially a 'leak' will make people think they were going to cover it up, to trick people into thinking that "something must be done, right now!"

    2. Re:More urgent? by i+kan+reed · · Score: 2

      What thought proccesses could have led to this post?

      "Hey my conspiracy theories don't have enough conspiracy in them yet, why don't I make deniers look even crazier?"

      It's "leaked" because it's still under review prior to publication.

    3. Re:More urgent? by American+Patent+Guy · · Score: 1

      I do indeed find it interesting how these reports "leak" out every month or so. It does fit with an agenda under-supporting these reports ... after all the press releases can be orchestrated nicely when the content of the reports is known beforehand.

      ... not that anyone at the U.N. has an undisclosed agenda or anything ...

    4. Re:More urgent? by riverat1 · · Score: 1

      It's a draft of a paper that isn't due to be finalized until November. In the context of "something must be done right now!" November is essentially equal to right now.

    5. Re:More urgent? by MooseMiester · · Score: 1

      It's very simple. These folks absolutely SUCK at Public Relations. Funny thing, so does the current occupant of the White House. Maybe there is some kind of genetic pattern at play here. For all of their railing at "evil corporations" and "slick advertising" you'd think by now they would understand that the whole "green" thing has to be SOLD just like any other product.

      --
      Murphy was an optimist
  4. What? by Anonymous Coward · · Score: 5, Funny

    Are you telling me that spewing into the atmosphere millions of years of accumulated sunlight and cutting down most of the natural CO2 scrubers (trees) of the world will have negative effects? Nah! Imposible!

    1. Re:What? by emagery · · Score: 1

      Well said

    2. Re:What? by Anonymous Coward · · Score: 2, Insightful

      Are you telling me that spewing into the atmosphere millions of years of accumulated sunlight and cutting down most of the natural CO2 scrubers (trees) of the world will have negative effects?

      1. Trees do nothing
      2. Human emissions are not even stable, they are continuing to increase. 60 million barrels of oil went up in smoke 10 years ago. Today, almost 50% MORE, 90 million barrels a day. Coal, increasing too. Gas usage, increasing.

      Confused people will start talking about things like "cow farts" or "trees" or similar. These have nothing to do with global warming - the climate thing - because these do not represent sequestered carbon. These are all carbon cycle stuff. Sequestered carbon being ADDED to the atmosphere is the issue - coal, oil, gas, peat.

      If your "solution" is planting trees, and it does not include harvesting said trees and burring them in mines, then all you are doing is deluding yourself.

      PS. I like trees. They clean the air. They look nice. I grow them from seeds. But just planting them does absolutely nothing to carbon sequestration.

    3. Re:What? by makq · · Score: 3, Insightful

      As long as the tree is growing more than it is decomposing, don't they sequester carbon internally?

    4. Re:What? by dtjohnson · · Score: 2

      Yes, in the beginning there was carbon and water. Then, the water was split into hydrogen and oxygen which oxidized the carbon into carbon dioxide and left a lot of hydrogen gas drifting around. Then life spontaneously arose and converted the carbon dioxide into hydrocarbons aka "stored sunlight." Then more new life spontaneously arose which could metabolize the stored sunlight (aka food) into carbon dioxide and now here we are busily turning/burning the stored sunlight back into carbon dioxide. Now, all we need to do is to stop everyone from burning the stored sunlight and we will all live happily ever after on our beautiful planet while happily skipping naked hand in hand with naked females through meadows filled with daisies and dandelions. [editor: please add the above to the IPCC report to the world leaders]

    5. Re:What? by serviscope_minor · · Score: 1

      Confused people will start talking about things like "cow farts" or "trees" or similar. These have nothing to do with global warming - the climate thing - because these do not represent sequestered carbon.

      Not quite right. Methane is a much more potent greenhouse gas than carbon dioxide. So, taking existing atmospheric carbon in the form of CO2 and turning it into methane will increase warming.

      --
      SJW n. One who posts facts.
    6. Re:What? by Layzej · · Score: 1

      Plant growth is actually outpacing plant death:

      When I was in graduate school, that was the first time that scientists came to grips with the fact that half of the missing carbon is going into the land. The reason that was a surprise is that it is not enough just to have photosynthesis taking CO2 out of the air, what we are saying is the growth of new plants is more than the death of old plants. Things are growing faster than they are dying–and this is across the world, which was really a surprise. Almost all ecologists and forestry people before that discovery thought it was the opposite. They thought stuff was dying faster than it was growing. They thought tropical deforestation, plowing the prairie, cutting down the forest to build suburbs — all that stuff was, on the net, turning plant material into CO2. But they were wrong. On the net the CO2 is actually turning into plant material. - See more at: http://climatechangenationalfo...

      Of course it is not certain whether we are trading trees for algae, but the fact is that we have more scrubbers now than before.

    7. Re:What? by Layzej · · Score: 3, Interesting

      Yes. You are right. And currently about 1/4 of our emitted carbon is being sequestered by new plant growth that is outpacing plant death: http://climatechangenationalfo...

    8. Re:What? by Lumpy · · Score: 3, Funny

      Tree Farts? can we PLEASE start that one so we can at least get some laughter out of it.

      --
      Do not look at laser with remaining good eye.
    9. Re:What? by Anonymous Coward · · Score: 0

      we have the Kardashians that is at least 3 more scrubbers.

    10. Re:What? by joocemann · · Score: 4, Funny

      Called a 'Treef'

    11. Re:What? by Anonymous Coward · · Score: 0

      What indeed!

      http://www.indexmundi.com/energy.aspx?product=oil&graph=production

      Oil consumption has not increased much in last 10 years, it's no where near "almost 50% more"!

      Ten year (2002-2012) increase was about 15% (64943.32 in 2002 and 74643.65 in 2012).

    12. Re:What? by Anonymous Coward · · Score: 0

      And the extinction 65m yrs ago was not caused by a meteor strike.

    13. Re:What? by Anonymous Coward · · Score: 0

      That's why I have to mow the lawn and pull the weeds more this years than last. Gotcha.

    14. Re:What? by SillyHamster · · Score: 1

      Are you telling me that spewing into the atmosphere millions of years of accumulated sunlight and cutting down most of the natural CO2 scrubers (trees) of the world will have negative effects? Nah! Imposible!

      If only there was a source of new trees. Alas, we'll hit Peak Tree soon.

    15. Re:What? by BringsApples · · Score: 1

      1. Trees do nothing

      A tree can absorb as much as 48 pounds of carbon dioxide per year and can sequester 1 ton of carbon dioxide by the time it reaches 40 years old.

      Not sure if you were trying to say "nothing" to mean that "...in light of the needs, trees cannot keep up...", but saying "trees do nothing" is just crazy.

      --
      Politics; n. : A religion whereby man is god.
    16. Re:What? by asylumx · · Score: 1

      Crap... No mod points.

    17. Re:What? by s122604 · · Score: 0

      It was cold last winter, some days even colder than average, "global warming" LOL

    18. Re:What? by Anonymous Coward · · Score: 0

      All slashdot has become is unscientific propaganda for dilitant nerds too stupid to learn for themselves.

      Every day there are two articles

      1) Global Warming is going to kill us all despite the fact it's been the coldest summer on record, and the total failure of all climate projections to be even remotely correct.

      2) The Scopes Monkey Trial was the highlight of human history that must be replayed time and time again. However, while man descended from apes, evolution stopped for humans once they appeared. This means Slashdot editors must constantly ignore any and all of the thousands of new adavancements in genetics every single month, because to do so would be to prove that human evolution has only increased with the rise of civilization and the human groups are very different and becoming more so. Only mention evolution to make fun of stupid Christians, or discredit anyone famous like Nicholas Wade who dares to state the obvious: Human Equality is a ridiculous, horrible myth.

    19. Re:What? by HornWumpus · · Score: 1

      A tree sequesters carbon. But a forest is long term carbon neutral. Decomposing trees match the uptake of living trees.

      A new forest or a tree farm is taking up carbon. But in a short time all that wood will have rotted. Cities built of wood are the same kind of carbon sink as a forest. Temporary.

      Garbage dumps have the potential to sink a bunch of carbon.

      --
      John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
    20. Re:What? by alvinrod · · Score: 1

      That's to be expected, but it doesn't account for the fact that we're digging up or tapping into massive reserves of scrubbers from millions of years ago and burning them as fuel. The reason we can support an increase in plant growth is that we've added a lot of food for them into the atmosphere. Even though we have more plants, and therefore are capable of absorbing more CO2, it's not compensating for the amount that we're releasing. If we took some amount of the plants we were growing and buried them underground to prevent the carbon from being recycled into the atmosphere at some point, it would eventually balance out, but we're not doing that, so we'll still have a growing amount of CO2.

    21. Re:What? by hsthompson69 · · Score: 1

      Actually, it *is* compensating for the amount we're releasing...and more.

      http://theresilientearth.com/?...

    22. Re:What? by Anonymous Coward · · Score: 0

      I find that most /.'ers seems to ignore scientific fact, and history. The ICE has been melting for millions of years, and guess what? It is going to keep melting. This is going to continue until its gone. Man has simply not done enough research and studying of the Ice Caps to begin with to determine the rate at which it should be melting. And to dumb it down, this is no different then taking a large chunk of ice, and setting it your bath tub with cold water (even filling it with ice), once the ice gets down to a certain size it will melt at a faster rate, from its full size. If the planet was covered in ICE millions of years ago then at some point once it gets down to a certain size it too will melt at a faster rate.

      The only question it comes down to "how much impact has man created to accelerate the process?"

      I'm I denying that Global Warming is a possibility? NO! Because the Ice has been melting for millions of years. But Science is just as flawed as religion, and yet people seem to devote Science as the all knowing never wrong Religion. Science itself is nothing more then an IDEA, an IDEA can and should be subject to change and other IDEAS should always be open to possibility.

      I really fail to understand how people and scientists fail to point out that the planet was covered in ice, and that it continues to melt away. And its not really that simple because our planet has the ability to cycle and re-stock (if you will) the ice. Which would explain why it took millions of years for the Ice to get to the level it is at, without just melting away like ice in a glass of water.

      Again I'm not denying it, because it is in fact happening. But to say that science is the know/cure all is ridiculous. History of Science shows time and time again how they too fuck up and fuck up big time. It most certainly should be read, and taking into consideration, consideration: meaning it shouldn't be ignored or blown off as non-sense.

    23. Re:What? by Anonymous Coward · · Score: 0

      Monkeying around the red planet destruction button...

      Somehow I start to think I don't want to have anything to do with you...

    24. Re:What? by Layzej · · Score: 1

      Are you saying that CO2 is going down? Because that is obviously not true. Scientists have found that about 1/2 of the CO2 we release stays in the atmosphere. 1/4 is absorbed by the ocean. 1/4 by the land. The rest remains in the atmosphere: http://scrippsco2.ucsd.edu/gra...

    25. Re:What? by Anonymous Coward · · Score: 0

      No, I'm saying that as our CO2 emissions accelerate, nature is also increasing CO2 sinks.

      If 1/2 of 2000 CO2 emissions is *double* of say, 1/2 of 1980 CO2 emissions, then the question must be asked - why weren't the CO2 emissions of 1980 simply 100% absorbed (since we *know* nature can absorb that much, as it did in 2000).

      The fact that CO2 absorption rates are dependent on CO2 emissions (that is, they adapt to them), means that whatever the residual unabsorbed CO2 could very well be a product of the moderating factor, rather than a product of CO2 emissions.

      Global atmospheric CO2 levels are moderated by something more complex than a set of static sinks and human emissions.

    26. Re:What? by Stuarticus · · Score: 1

      Well, as the parent said burning peat is the problem, not drinking the water that runs off it (or whisky made from it).

      --
      If you think someone isn't free to have a different definition of "freedom" you may be a tyrant.
    27. Re:What? by Sciath · · Score: 1

      Who said sequestration is the only carbon factor that effects climate conditions? Higher carbon dioxide content in the atmosphere certainly does effect climate and the process of photosynthesis in which plant life "eats" carbon dioxide and produces oxygen certainly is a climate factor. So I doubt your sequestration/climate assertion is as absolute as you like to portray it. Granted there are a number of factors that effect climate change but you cant rule out the biosphere.

      --
      "Those who can make you believe absurdities can make you commit atrocities." - Voltaire
    28. Re:What? by thedonger · · Score: 1

      I think Islay malts used smoked peat, so at least some burning is needed.

      --
      Help fight poverty: Punch a poor person.
  5. only 2 things left to do... by Cardoor · · Score: 2

    change your name to Kamin and learn to play the flute.

  6. Delayed action by Anonymous Coward · · Score: 5, Insightful

    We'll never do anything about climate change as long as businesses can dictate law, control the EPA, and guide lawmaking through lobbyists. The Supreme Court has literally ensured this.

    I can't stand the idea that multi-billion corporations can't afford to spend 1/8th of their profit, if even that much, to operate in a more environmentally friendly manner.

    Gotta hoard and accumulate money at all costs, no matter what happens.

    1. Re:Delayed action by Anonymous Coward · · Score: 1

      http://www.ted.com/talks/pavan_sukhdev_what_s_the_price_of_nature?language=en

      Have the corps pay the community based on the cash value of economic damage they do and see the shareholders agree to environment-friendly methods.

    2. Re:Delayed action by Sarius64 · · Score: 1, Funny

      Have politicians give up their salaries to pay for carbon credits. Have progressives pay for the legions of illegals on the welfare doles now. Have conservatives pay for abortion clinics for militant atheists. Have everyone pay for the continued corporate welfare cycle that's not in the Constitution.

    3. Re:Delayed action by Layzej · · Score: 1

      We already are doing something about climate change! The price of solar is plummeting and some are suggesting that it will be a disruptive technology on the same order as the internet:

      the tipping point will arrive around 2020. At that point, investing in a home solar system with a 20-year life span, plus some small-scale home battery technology and an electric car, will pay for itself in six to eight years for the average consumer in Germany, Italy, Spain, and much of the rest of Europe. Crucially, this math holds even without any government subsidies for solar power. - http://climatecrocks.com/2014/...

    4. Re:Delayed action by FatAlb3rt · · Score: 1

      Ok, please lead by example. Spend 1/8 of your disposable income on operating more environmentally friendly. Solar panels on your house, more efficient appliances, pay a landscaper to plant trees.

    5. Re:Delayed action by MightyMartian · · Score: 1

      By the looks of it, you have a hard time sustaining a thought process for more than about two seconds.

      --
      The world's burning. Moped Jesus spotted on I50. Details at 11.
    6. Re:Delayed action by RobinH · · Score: 4, Insightful

      That would actually be illogical for an individual to do if they're mostly interested in themselves and their offspring (and people do it which shows how generous some people are, sacrificing themselves for the greater good). A single person giving up 1/8 of their income for the benefit of everyone instead of themselves is just putting themselves at an economic disadvantage. Those are resources that can't be put towards better education for their kids, buying bigger/newer (i.e. safer for themselves) vehicles, etc. This kind of stuff will only work if we agree as a society that everyone has to play along by the new rules, for the benefit of everyone as a whole. A lot of people are completely against this idea (government intrusion on freedom, etc.) but that's the only way we've ever solved problems based on the "tragedy of the commons". If there's a common resource that people have an incentive to exploit, with no limit, for essentially free (e.g. the atmosphere) then they will do it. Sure, we all breath, but there's little/no incentive to breath "more". We can, however, use more energy by burning inexpensive fuel which consumes O2 and releases CO2 into the atmosphere, and we don't, as individuals or as companies, have to pay for that "externality". Therefore we will *never* stop doing it until we all agree as a society to regulate CO2 emissions.

      --
      "I have never let my schooling interfere with my education." - Mark Twain
    7. Re:Delayed action by impossiblefork · · Score: 1

      One can't make that kind of choice unilaterally when competing against others. The companies can't either.

      Even if their founders have initially good intentions those good intentions will, when there are externalities, ultimately harm their business. This applies to everything from worker welfare or unsafe factories to harm to the environment.

    8. Re:Delayed action by Sarius64 · · Score: 1

      Well, that certainly meant nothing whatsoever. Thanks for the input!

    9. Re:Delayed action by mrchaotica · · Score: 1

      What a wonderfully free-market idea... utterly reviled by [people who claim to be] capitalists everywhere!

      --

      "[Regarding the 'cloud,'] ownership was what made America different than Russia." -- Woz

    10. Re:Delayed action by asylumx · · Score: 1

      A single person giving up 1/8 of their income for the benefit of everyone instead of themselves is just putting themselves at an economic disadvantage

      Really? Most of us pay much more than 1/8 of our income for the benefit of everyone INCLUDING ourselves anyway. It's called taxes.

    11. Re:Delayed action by Anonymous Coward · · Score: 0

      That's due to the fact the economics are based on the deeply flawed assumption that you can generalize outdated conservation of energy equations to "utility" and assume that all natural resources are limitless and assume that pollution has no cost.

    12. Re:Delayed action by HornWumpus · · Score: 1

      Having the government pull a number out of their ass is related to free markets how?

      --
      John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
    13. Re:Delayed action by cinnamon+colbert · · Score: 1

      Global GDP is about 85 trillion dollars
      0.1% - 1penney on ten dollars - is 85 billion dollars a year
      you know what they say, 85 billion here, 85 bn there, pretty soon it adds up to real money..

    14. Re:Delayed action by khallow · · Score: 1
      It helps if the tragedy of the commons problem is actually a real problem.

      We can, however, use more energy by burning inexpensive fuel which consumes O2 and releases CO2 into the atmosphere, and we don't, as individuals or as companies, have to pay for that "externality".

      What's the amount of that "externality" per gallon? Is it a few pennies or a few dollars? And if people pay for the externality and still drive, what is it to you?

    15. Re:Delayed action by RobinH · · Score: 1

      Obviously I mean voluntarily.

      --
      "I have never let my schooling interfere with my education." - Mark Twain
    16. Re:Delayed action by Anonymous Coward · · Score: 0

      The "tragedy of the commons" is solved by property rights, and what you're advocating isn't a voluntary solution, but a forced one. People do voluntarily work towards common goals and cooperate with each other when they are allowed to, but top-down, authoritarian solutions produce more ill effects than positive ones. The solution to our environmental problems are technological in nature, and technological advancement requires a free market. Already people are using more fuel efficient vehicles and designing energy efficient buildings, but there is no short-cut to technological progress.

  7. Simple English Wikipedia will come in handy by timrod · · Score: 4, Insightful

    From the article:

    The UN panel since September has published three separate reports into the physical science of global warming, its impacts, and ways to fight it. The study leaked yesterday, called the “Synthesis Report” intends to pick out the most important findings and present them in a way that lawmakers can easily understand. (Emphasis mine)

    Why do I have a feeling the report to the politicians will have to read a lot like the Simple English Wikipedia, to the point where it might not be a bad idea to get the writers for that on it.

    "Global warming is a bad thing that causes lots of problems. Burning stuff causes global warming. If you keep burning stuff, you will have a bad problem."

    1. Re:Simple English Wikipedia will come in handy by tarius8105 · · Score: 2, Insightful

      Thats not the problem though. They understand english and know how to look up big words. The problem is that they receive campaign donations from people who have an interest in keeping the status quo. If lawmakers were to pass bills that would attempt to counter global warming on a large scale, these same businesses would have a huge hit to their bottom line. The stupidity of the situation is if we made changes little by little when people started to raise alarms about global warming, we probably could have made the changes without impacting the bottom line too much.

    2. Re:Simple English Wikipedia will come in handy by jfengel · · Score: 0

      It's not even really the donors, per se, but their voters. Climate change denialism is very popular. The businesses ensure that candidates who favor them connect with those voters, but it's not like the candidate would suddenly change their mind if those donations dried up. They'd continue to be denialists. And if that politician leaves, the denialist voters will be sure to pick up another denialist candidate.

      The business help ensure denialism not with the politicians, but by funding denialist news networks and web sites. They also run attack ads (on any subject, not just climate) to defeat candidates who would oppose denialism.

      They don't need to buy politicians. They buy voters instead, by scaring them. You won't fix the candidates, who are just doing what their constituents (at least, 50%+1 of them) want. The direct donations are a pittance. It's the overall miasma of denialism that give us anti-intellectual politicians, not the other way around.

      I've got no idea how to fix it. It's famously said that you can't fix stupid, and there's a LOT of stupid.

    3. Re:Simple English Wikipedia will come in handy by dnavid · · Score: 1

      From the article:

      The UN panel since September has published three separate reports into the physical science of global warming, its impacts, and ways to fight it. The study leaked yesterday, called the “Synthesis Report” intends to pick out the most important findings and present them in a way that lawmakers can easily understand. (Emphasis mine)

      Why do I have a feeling the report to the politicians will have to read a lot like the Simple English Wikipedia, to the point where it might not be a bad idea to get the writers for that on it.

      I'm not convinced that even the "Drunk History" version would make a significant impact on politicians.

  8. Irreversible? by SternisheFan · · Score: 3, Interesting
    --- “Listen to the mustn'ts, child. Listen to the don'ts. Listen to the shouldn'ts, the impossibles, the won'ts. Listen to the never haves, then listen close to me... Anything can happen, child. Anything can be.”

    Shel Silverstein

    The 'impossible' is just something that hasn't been done yet.

    1. Re:Irreversible? by mdsolar · · Score: 1

      "Possible permanent changes include the melting of the ice sheet covering Greenland. That would boost sea levels by as much as 7 meters (23 feet) and threaten coastal cities from Miami to Bangkok along with island nations such as the Maldives, Kiribati and Tuvalu.

      The scientists said they have “medium confidence” that warming of less than 4 degrees Celsius would be enough to trigger such a melt, which would take at least a millennium.

      Other effects the report flags include reduced food security as production of crops such as wheat, rice and maize in the tropics is damaged, melting of Arctic sea ice, and acidification of the oceans."

      Irreversible is sometimes like trying to unscramble eggs. Loss of the Greenland ice sheet is like that because rebuilding it would take an ice age owing to the loss of altitude upon melting. We're not going to allow another ice age.

    2. Re:Irreversible? by Anonymous Coward · · Score: 0

      TFA has nothing to do with the possibilities of individual human achievement, and a lot to do with the politics of millions/billions of humans.

    3. Re:Irreversible? by Zocalo · · Score: 1

      "Irreversible" is a very strong word, and clearly incorrect. We're not so much talking about unscrambling eggs here as something than *can* be corrected, and in all likelihood *will* be corrected, just by leaving it alone and waiting long enough. The problem for us humans here today, of course, is that we won't we around that long and in all probability neither will many generations of our decendants. I fully expect the naysayers to latch on to this in combination with the historical record showing that the earth has been warmer than this in the past as further "evidence" that the IPCC has no clue in their rebuttals over the next few days.

      --
      UNIX? They're not even circumcised! Savages!
    4. Re:Irreversible? by mdsolar · · Score: 1

      Ah, you one of those kill all the humans types: "just by leaving it alone and waiting long enough." So, who is going to do the waiting around?

    5. Re:Irreversible? by Anonymous Coward · · Score: 0

      "Possible permanent changes include the melting of the ice sheet covering Greenland...

      Reason for a real estate boon in Greenland. Change is good, and inevitable.

    6. Re:Irreversible? by Nemyst · · Score: 1

      That's besides the point. If we act now, we have a chance at fixing it that's fairly large and wouldn't cause that many problems. If we act much later, we have fewer chances of succeeding and even success would probably mean that people (how many? thousands? millions?) have died for nothing. Saying that we can always recover is incredibly selfish, even if it's true (and frankly it's more of a gamble than I'd like).

    7. Re:Irreversible? by Anonymous Coward · · Score: 0

      "Irreversible" is a very strong word, and clearly incorrect. We're not so much talking about unscrambling eggs here as something than *can* be corrected, and in all likelihood *will* be corrected, just by leaving it alone and waiting long enough. The problem for us humans here today, of course, is that we won't we around that long and in all probability neither will many generations of our decendants. I fully expect the naysayers to latch on to this in combination with the historical record showing that the earth has been warmer than this in the past as further "evidence" that the IPCC has no clue in their rebuttals over the next few days.

      I think that by "irreversible" they mean that Life Goes On, but a lot of species won't. Eventually, IF we stabilize things and give life a chance to adapt, new species will arise faster than species can die out and in that sense, it will "reverse". Just minus some animals and trees that we may not miss at all or may miss greatly.

      The problem isn't, in the end, climate change. Climate always changes. The problem is that if we force it to change at a speed greater than life can adapt, we lose biodiversity and all the benefits that that gives us.

    8. Re:Irreversible? by wbr1 · · Score: 1

      The 'impossible' is just something that hasn't been done yet.

      Nothing is impossible eh? Go slam a revolving door.

      --
      Silence is a state of mime.
    9. Re:Irreversible? by Anonymous Coward · · Score: 0

      Well, if we can't grow wheat , rice and all that then Quinoa will save us.

    10. Re:Irreversible? by mdsolar · · Score: 1

      Do it in the face of a Republican Congressional Aide.

    11. Re:Irreversible? by SternisheFan · · Score: 1
      Touche', Sir. Unless...,

      I unmount it and throw it to the ground. Or, insult it. :*)

    12. Re:Irreversible? by Anonymous Coward · · Score: 0

      Wat.

      There are trivially-described impossible things: unbreaking an egg, for example. This is dippy poetic hogwash.

    13. Re:Irreversible? by Anonymous Coward · · Score: 0

      I hear that revolving door has had more men in it than Jenna Jameson.

    14. Re:Irreversible? by pla · · Score: 1

      The 'impossible' is just something that hasn't been done yet.

      Quoting a work of fiction doesn't make your point unless your point applies only within that world.

      Unless, of course, you think we can solve global warming by reversing the polarity of the neutron flow (or perhaps Gandalf can just not let any IR photons pass, if you prefer fantasy solutions over scifi ones).

    15. Re:Irreversible? by SternisheFan · · Score: 1

      My post never suggested an answer is 'presently' available...

    16. Re:Irreversible? by Solandri · · Score: 5, Insightful

      I have a slightly different take on it. Using absolutes like "irreversible" or "unavoidable" is dangerous is because it decreases public support for what you're trying to accomplish. People will think, "well if we can't do anything about it, then I guess there's nothing left to do but live it up in the time we have left."

    17. Re:Irreversible? by Anonymous Coward · · Score: 0

      Irreversible is sometimes like trying to unscramble eggs. Loss of the Greenland ice sheet is like that because rebuilding it would take an ice age owing to the loss of altitude upon melting. We're not going to allow another ice age.

      How do you imagine that "we" will not "allow" another ice age? Perhaps a little arrogant? Is that you, Barry?

    18. Re:Irreversible? by Obfuscant · · Score: 1

      Ah, you one of those kill all the humans types: "just by leaving it alone and waiting long enough." So, who is going to do the waiting around?

      All the people who are smart enough to move away from the coast when the sea level takes a couple of decades to rise based on the couple of decades it will take for Greenland to melt.

      The ones who won't be waiting around are the ones who are washed out to sea while standing in their houses surrounded by the incoming tide wondering when the government is going to do something about this problem. I.e., the true Darwin Award winners.

    19. Re:Irreversible? by Zocalo · · Score: 1

      Nope, just pointing out that using an absolute like "irreversible" isn't perhaps the smartest thing for the IPCC to do as it will almost certainly be seized on by the climate change deniers. Doubly so since it's demonstrably not the case except in our ability to use current science to resolve the problem.

      Frankly the only things left in doubt for me about GW is just how much of a contribution mankind has made (it's certainly not zero, but I don't think it's 100% either), and whether the changes we *can* make to reduce the symptoms will have a worthwhile effect. Given enough will we can obviously reduce our GHG emissions significantly, migrate to cleaner fuels and generally move closer to living in balance with nature, but is that enough? The irony is that the more the AGW deniers are wrong about the level of our involvement, the greater the difference that we can make by changing our ways, but if they are right then we are all doomed to ride this out, wherever nature is taking us.

      --
      UNIX? They're not even circumcised! Savages!
    20. Re:Irreversible? by mdsolar · · Score: 1

      Read the parent.

    21. Re:Irreversible? by Layzej · · Score: 1

      Why can't it be both? Irreversible damage has been caused (but is not yet widespread), and we risk causing irreversible and widespread damage.

    22. Re:Irreversible? by mdsolar · · Score: 1

      Most likely 110% since 1950. http://www.realclimate.org/ind...

    23. Re:Irreversible? by Anonymous Coward · · Score: 0

      I've slammed a revolving door before. Just push backwards on it.

    24. Re:Irreversible? by Obfuscant · · Score: 1

      Read the parent.

      I read the parent. He said that those who are around today won' t be around long enough to see the recovery. As in, the recovery will take longer than a human lifetime.

      Also read you, where you changed that to "kill all the humans" and asked who would be around. I told you: anyone who isn't stupid enough to stand still and expect the government to solve their problems for them.

    25. Re:Irreversible? by mdsolar · · Score: 1

      Leaving it alone is accomplished through the demise of our decedents.....

    26. Re:Irreversible? by ChrisMaple · · Score: 1

      Anything can be.

      Based on that statement and the unquestionable moral and scientific authority of Shel Silverstein, I've ordered a gross of square circles. The supplier claims to have found a way to make PI equal seven.

      --
      Contribute to civilization: ari.aynrand.org/donate
    27. Re:Irreversible? by SternisheFan · · Score: 1

      Anything can be.

      Based on that statement and the unquestionable moral and scientific authority of Shel Silverstein, I've ordered a gross of square circles. The supplier claims to have found a way to make PI equal seven.

      Hmmm.... https://www.google.com/search?...

    28. Re:Irreversible? by Your.Master · · Score: 1

      Are you saying that it's impossible to do something irreversibly?

      The statement is a pithy comment about can-do attitudes. Taken strictly, it's a logical absurdity. Don't take it strictly.

    29. Re:Irreversible? by Anonymous Coward · · Score: 0

      What's your definition of "irreversible damage"? Isn't every tick of time "irreversible"? Can any change be considered "damage"?

    30. Re:Irreversible? by Layzej · · Score: 1

      Why don't you read the report and find out?

    31. Re:Irreversible? by patriceweber · · Score: 1

      No, irreversible in ecological terms means that you move from a stable state with a given biodiversity level to another stable state with a different biodiversity level. Both communities (plant, animals, ecological functions) are stable but in the transition process, you might have lost a lot of species that become locally or globally extinct. Easing on the stressors (climate change) will not bring back your original communities. They are gone. It's like transitioning from rainforests to grasslands both are stable ecosystems with very different biodiversity levels and you might have lost the forests species for good.

    32. Re:Irreversible? by Obfuscant · · Score: 1

      Leaving it alone is accomplished through the demise of our decedents.....

      No, "leaving it alone" is accomplished by doing nothing. Decedents will have nothing to do with it. How can they? They're already dead.

      You claimed the OP was looking for the death of all humans. That's just false, and I corrected you on it. Leaving it alone means not forcing the system we don't fully understand to try to change to our whim, unlike those who would whip the waves to stop the tide.

      Those who don't use the decades we have to adapt, well, they're standing on the shore whipping the waves or floating out to sea in the house they expected the government to protect. But to claim that expecting people to adapt is calling for the death of all humans is just patently absurd. Kind of like blaming something on the demise of decedents.

    33. Re:Irreversible? by mdsolar · · Score: 1

      OK maybe he is just not clear that leaving it alone means ending our use of fossil fuel. Sounded like he expected that to end when we do.

  9. Impacts by mdsolar · · Score: 2, Informative

    “Without additional mitigation, and even with adaptation, warming by the end of the 21st century will lead to high to very high risk of severe, widespread, and irreversible impacts globally,” the UN Intergovernmental Panel on Climate Change said in the draft.

    1. Re:Impacts by Intrepid+imaginaut · · Score: 5, Interesting

      It was kind of going that way anyhow though, either to a tropical earth or back towards a new ice age. And really given the choice the tropical option is less destrcutive. As I understand it we were in an interglacial until people started digging up sequestered carbon and injecting it into the atmosphere. Either way I don't believe it will be possible to stabilise the climate over the mid to long term, at least not with our current technology, so maybe its best just to prepare to adapt to these changes.

    2. Re:Impacts by Archangel+Michael · · Score: 3, Insightful

      Good for nature, bad for man. Just like O2 Poisoning the planet when it was overrun by Plant life. Life adapts. Humans haven't always been around, and won't be around forever. Because we are aware of our own demise doesn't change these facts.

      --
      Agent K: A *person* is smart. People are dumb, stupid, panicky animals, and you know it.
    3. Re:Impacts by Anonymous Coward · · Score: 3, Insightful

      Is it sane, given foreknowledge of your own demise and the power to avert it, to charge full-steam-ahead toward that demise? If humanity were a person, we'd lock it up for its own safety.

    4. Re:Impacts by knightghost · · Score: 2, Insightful

      All I see is "the world is ending!" without any realistic measurements provided. Show me what it's going to cost at each point, and when. The simplest, lowest cost adaptation is simply to build above future sea levels. The lowest cost food change is crop switching and genetic manipulation. The simplest - and probably only - long term solution is reducing population numbers.

    5. Re:Impacts by Anonymous Coward · · Score: 4, Informative

      “Without additional mitigation, and even with adaptation, warming by the end of the 21st century will lead to high to very high risk of severe, widespread, and irreversible impacts globally,” the UN Intergovernmental Panel on Climate Change said in the draft.

      Oh great. "The sky is gonna fall! Almost 100 years from now!!! Disaster is looming!!!!"

      And people wonder where deniers come from?

      Here's a hint: exaggeration and catastrophic alarmism destroy credibility.

    6. Re:Impacts by Anonymous Coward · · Score: 5, Insightful

      Those are a lot of conclusions to draw when you openly admit that you have insufficient measurements and cost estimates.

    7. Re:Impacts by Anonymous Coward · · Score: 2, Interesting

      Yes, we should prepare, but we can not adapt.
      With are current Greenhouse gas release, there isn't an endpoint survivable by humans. It will get two warm for food growth, anywhere.
      People act like, well it will happen and we will just farm 200 miles more north.

      Please learn something:

      Average planetary temperature and CO2 concentration for the past billion years or so

      Important points:

      1. Average planetary temperature now is about 12C. Average temperature for most of the past billion years or so is 22C
      2. Average CO2 concentration today is EXTREME geological LOW. It's been as high as > 7000ppm
      3. There's pretty much ZERO correlation between CO2 and temperature.

      Note well that if temperatures go up 2C, we've still got 8C to go before the planet reaches its "normal" average temperature.

    8. Re:Impacts by mi · · Score: 2, Insightful

      Ah, this is a lot more persuasive than your earlier attempt, but still not quite good enough... Citation needed much? (No, IPCC-produced documents don't count — members of the panel are government-appointed politicians, not scientists.)

      Please, don't hate.

      --
      In Soviet Washington the swamp drains you.
    9. Re:Impacts by Anonymous Coward · · Score: 0

      The climate is already inherently stable. That's why it doesn't warm up to 1000 degrees and then cool to -200 degrees periodically.

    10. Re:Impacts by blue9steel · · Score: 4, Informative

      Yes, we should prepare, but we can not adapt. With are current Greenhouse gas release, there isn't an endpoint survivable by humans. It will get two warm for food growth, anywhere. People act like, well it will happen and we will just farm 200 miles more north.

      Hogwash. Even in the IPCC A1FI scenario, the most pessimistic case presented, total global warming by 2100 is 1.4C to 6.4C. Yes, that would have significant bad effects but it's not going to mean the end of agriculture across the entire planet. Earth isn't going to turn into Venus. The average temp at the equator now is 30C while in Siberia it's only 0.5C. So, if we look at the average high temperature for Novosibirsk during the hottest month of July (25.7) and add the high end of the worst case scenario (6.4C) then we only get 32.1C, so yeah moving north will be an option. I'd expect massive droughts in the equatorial zones, the collapse of many third world governments and a huge refugee crisis but that's not the same as saying it's unsurvivable by humans as a species.

    11. Re:Impacts by Anonymous Coward · · Score: 1

      "Realistic measurements" being, for you, the actual measurement of the earth exploding, right?

      The Stern report gives the costs of mitigation. But you haven't bothered to read it, have you, despite your protestation that you need it.

      PS free to leave first.

    12. Re:Impacts by NotDrWho · · Score: 2

      Yes, we should prepare, but we can not adapt.

      Unless this planet gets up to Venus level heat (and I'm pretty sure that's impossible), then humans will adapt.

      --
      SJW's don't eliminate discrimination. They just expropriate it for themselves.
    13. Re:Impacts by Anonymous Coward · · Score: 1

      Yes, indeed. We would lock humanity up in a global centrally planned economy where consumption of fossil fuels is curtailed and permits to use them are dispensed based upon political considerations, then we could live in complete "safety" for a thousand years.

      Humanity lives in every habitat on the planet. Humans and cockroaches will survive just about anything. I'm much more concerned that we have a world worth living in than that we will be able to live in the world.

    14. Re:Impacts by Anonymous Coward · · Score: 0

      Dont you know reality and historical record has nothing to do with AGW!! Shame on you! And please, do not bring up the fact that no models have been proven to predict reality. Also, do not bring up the constant "re-evaluation" of temperature measurements due to improper procedures and outright lying.

      None of this has ANYTHING to do with people earning money-- oopss, i mean people saving the earth-- from AGW

    15. Re:Impacts by NotDrWho · · Score: 4, Insightful

      We don't have foreknowledge of shit. It's a pretty epic level of arrogance to think we've suddenly acquired the ability to accurately see 100 years into the future when EVERY SINGLE ATTEMPT in the past to accurately predict anything even 20 years in the future has failed MISERABLY and has been LAUGHABLY wrong.

      The only thing that I predict about what this planet is going to look like 100 years from now is that it's going to be nothing like what anyone expects today.

      --
      SJW's don't eliminate discrimination. They just expropriate it for themselves.
    16. Re:Impacts by nine-times · · Score: 1

      Well, we could still work to try to lessen/minimize the damage and instability.

      Like, if you had gangrene on your arm, and the doctor announces, "I'm sorry, but we can't save the arm, the damage is irreversible," you wouldn't go, "Ah, well. It's impossible to save the arm. Time to wait it out and adapt."

      At least, I'd hope you wouldn't. That's when you have an operation, try to save as much of your arm as you can. And then you think about what caused the gangrene in the first place, and try to not do that ever again.

    17. Re:Impacts by Anonymous Coward · · Score: 0

      Since the current concentration of CO2 in the atmosphere has just passed a year-averaged mean of 400ppm (Up from a pre-industrial value of 280ppm) you may not want to take a graph that shows it plunging to zero at the present very seriously.

    18. Re:Impacts by amiga3D · · Score: 1

      I expect the population to shrink drastically when the wars start. A nuclear winter should clear up the global warming thing.

    19. Re:Impacts by Anonymous Coward · · Score: 4, Interesting

      1. Average planetary temperature now is about 12C. Average temperature for most of the past billion years or so is 22C
      2. Average CO2 concentration today is EXTREME geological LOW. It's been as high as > 7000ppm
      3. There's pretty much ZERO correlation between CO2 and temperature.

      Note well that if temperatures go up 2C, we've still got 8C to go before the planet reaches its "normal" average temperature.

      Ok, I'll accept that... of course the first mammals appeared on the planet around say 225million years ago, and were the size of perhaps a mouse or smaller. Larger mammals have been found around 100million years ago, around the size of a large rat perhaps... it wasn't until say 55million years ago the earliest ancestor for man/primates appeared, Archicebus, which would fit in the palm of your hand and weigh maybe an ounce.

      So maybe instead of the past "billion years" we should focus on say the past 50million, where temperatures and CO2 levels were at a level where a mammal like mankind could survive on most of the planet? Seems rather pointless to say the planet has been "22C average" when at the time it was mankind didn't exist, and more than likely with a 10C increase over current temperatures it's unlikely human beings could survive in many areas (a 100F desert will kill in a day or two w/o water - imagine 120-130F?).

      I mean, unless you're worried about ants, cockroaches, and mammals the size of mice, and shrews, it might be wiser to focus on temperatures that human beings can and have survived in, and not some 'average' that includes numbers from many (up to 950million) years before anything even remotely human-like existed. Because, yes, "life" existed at 7000ppm and 22C - but not human life.

    20. Re:Impacts by fyngyrz · · Score: 2

      I'd expect massive droughts in the equatorial zones

      Why? Equatorial zones have a great deal of ocean water, which certainly isn't going to change. That water will evaporate faster, the atmosphere will contain more humidity, and therefore there will be more precipitation, if the average temperature is up a few degrees C. How does that constitute the precursors for anticipating equatorial droughts?

      I can see marginal areas (US midwest, for instance) baking off the little bit of moisture they have and not reaching any threshold of precipitation, followed by dustbowls and so on, but at the equator? Why would droughts happen there?

      --
      I've fallen off your lawn, and I can't get up.
    21. Re:Impacts by Layzej · · Score: 1

      Uncertainty is one reason we should tread lightly here. You mention that we have sometimes failed to accurately predict the future. This failure has often resulted in catastrophe. Take the Atlantic fisheries as an example. If we had greater certainty we would have know how far we could exploit that resource without destroying it:

      An imperfect understanding of the ocean ecosystem; technical and environmental challenges associated with observation techniques, which led to incomplete data on the resource (the cod); and the naturally high levels of variability in the population due to dynamic environmental factors (such as ocean temperature) combined to make it arduous to discern the effects of exploitation. Unfortunately, this led to predictions about the cod stock that were mired in uncertainty, making it more difficult for the government to choose the appropriate course of action. - http://en.wikipedia.org/wiki/C...

      I agree that it is a "pretty epic level of arrogance" to presume that we know exactly how much more carbon we can safely emit. The truth is that we don't.

    22. Re:Impacts by Anonymous Coward · · Score: 2, Insightful

      Yes, we should prepare, but we can not adapt.
      With are current Greenhouse gas release, there isn't an endpoint survivable by humans. It will get two warm for food growth, anywhere.
      People act like, well it will happen and we will just farm 200 miles more north.

      Hogwash. Even in the IPCC A1FI scenario, the most pessimistic case presented, total global warming by 2100 is 1.4C to 6.4C. Yes, that would have significant bad effects but it's not going to mean the end of agriculture across the entire planet. Earth isn't going to turn into Venus. The average temp at the equator now is 30C while in Siberia it's only 0.5C. So, if we look at the average high temperature for Novosibirsk during the hottest month of July (25.7) and add the high end of the worst case scenario (6.4C) then we only get 32.1C, so yeah moving north will be an option. I'd expect massive droughts in the equatorial zones, the collapse of many third world governments and a huge refugee crisis but that's not the same as saying it's unsurvivable by humans as a species.

      You make the obvious mistake, of course, that "average" = "max"... sorry, but what if the average temp at the equator became 20C (dropped 10C) while the average temp in Siberia rose from 0.5C to 16.5C (16C increase), the "average" is still 6C right? While I'd agree it's unlikely the equator will cool that much, when speaking in averages it's absurd to start talking about temperatures rising by 'that amount' everywhere in the world, only by that amount across the entire planet - we're talking a biosphere with weather patterns, water currents and air currents affected by the temperatures in various regions. A "6C" rise in average global temperature may well wind up being 12C in one area and -6C in another.

      It's hard to judge how it will affect the planet because we can only guess to some degree (with some scientific computer modeling) how melting ice caps and warming ocean will affect the water flows (arctic 'conveyer belt' for example) - which will affect weather patterns as the changes increase. Of course, we can predict some things - for instance that *if* climate change is the cause of the current drought issues in CA and the midwest, and it persists or even gets worse, our ability to grow food crops in those areas may be severely depleted (or eliminated). What if hurricanes and tornadoes becomes more frequent? Forest fires in the western states becoming more frequent because of the dryness? Will we even be able to *afford* to fight them? If the ice melts at the poles (and Greenland, etc) and sea level rises - something like 80%+ of the population of the US now lives in coastal areas - if storms become more frequent and sea level is higher what happens to those cities? Imagine "Katrina" on steroids across the entire eastern seaboard...

      So, no, it might not "wipe out the human species" by any means, but if food production gets harder due to drought, fresh water is harder to find (we're already draining aquifers, Lake Meade is seriously depleted - what do you think happens to Las Vegas then?), we might well see human population go from 7.1+billion to a small fraction of that (100million say). Might not be a bad thing for the planet, but I'm betting if you're one of the 7 billion that don't make it you might not think so. ;)

    23. Re:Impacts by Anonymous Coward · · Score: 0

      So, change. Because impact is nothing except measurable change over human time periods. Neither bad nor good. Could easily be "âoeWithout additional mitigation, and even with adaptation, warming by the end of the 21st century will lead to high to very high risk of severe, widespread, and irreversible rainbows globally" or "âoeWithout additional mitigation, and even with adaptation, warming by the end of the 21st century will lead to high to very high risk of severe, widespread, and irreversible tornados globally"

    24. Re:Impacts by blue9steel · · Score: 1

      Well, obviously impacts will vary depending on the local geography, but for the most part I was talking about lakes and rivers drying up. In general, higher temperatures lead to more frequent & more severe droughts.

    25. Re:Impacts by AutodidactLabrat · · Score: 1

      Based on the effects on the west coast of Africa, the French and Germans experience with heatwaves and California / Baha experience with profound drought, I think we're not talking tropical, but desertification on a mass scale.
      Couple that with the torrential rains across the Midwest and what you have is the 'extrema' predictions, not a balmy palm-tree laden world.

    26. Re:Impacts by AutodidactLabrat · · Score: 1

      IPCC not good enough for you? Then how about Koch funded 0.01% papers? They too acknowledge the coming weather extrema.
      They just pretend we have nothing to do with it via fossil fuels.

    27. Re:Impacts by fyngyrz · · Score: 3, Informative

      You *do* realize that the equatorial zone is generally tropical, wet as heck, and quite a bit warmer than everywhere else, yes? And that plants thrive on CO2?

      Doesn't follow that making it warmer will make it drier. That doesn't seem to be how it works. Drier happens when water sources go away. There's no reasonable postulate for that which would apply to most equatorial regions.

      --
      I've fallen off your lawn, and I can't get up.
    28. Re:Impacts by ShanghaiBill · · Score: 3, Interesting

      Those are a lot of conclusions to draw when you openly admit that you have insufficient measurements and cost estimates.

      There are plenty of "no regrets" policies, that should be done regardless of global warming. We should reduce our fuel consumption and dependence on imported oil for reasons of economics and national security. Third world countries should reduce population growth through education and better access to contraception, because that is their path out of poverty.

    29. Re:Impacts by BasilBrush · · Score: 0

      EVERY SINGLE ATTEMPT in the past to accurately predict anything even 20 years in the future has failed MISERABLY and has been LAUGHABLY wrong.

      That's quite easily proved wrong. Here's two examples:

      Moore's law is a prediction that is just coming up to 50 years old, and has been uncannily accurate.

      http://en.wikipedia.org/wiki/M...

      In 1705, Edmond Hally predicted a visible comet would appear in the sky in 1758. A successful 53 year prediction made at a time when no other person in the world realised comets could be periodic.

      Predictions of stuff like flying cars is of course doomed to failure. But spotting a trend and predicting based on it is a perfectly reasonable and successful prediction technique. Both these are of that kind, and so is climate change.

    30. Re:Impacts by mrchaotica · · Score: 1

      Humanity lives in every habitat on the planet.

      No, it doesn't. There is no self-sustaining population of humans in the ocean, or in Antarctica, or underground.

      --

      "[Regarding the 'cloud,'] ownership was what made America different than Russia." -- Woz

    31. Re:Impacts by mi · · Score: 3

      IPCC not good enough for you?

      Certainly not. The panel would be disbanded, if Climate Change turned out to be a hoax so all members are interested in maintaining the fear. The fear may still be justified, but the glaring conflict of interest disqualifies their reports as evidence.

      I would not trust them any more, than I would trust an "anti-poverty" politician to eliminate poverty — what is he going to run on come next elections?

      Then how about Koch funded 0.01% papers?

      You had the opportunity to offer a link, but chose not to... Is it because you don't have one.

      --
      In Soviet Washington the swamp drains you.
    32. Re:Impacts by Curunir_wolf · · Score: 1

      Well, we could still work to try to lessen/minimize the damage and instability.

      Like, if you had gangrene on your arm, and the doctor announces, "I'm sorry, but we can't save the arm, the damage is irreversible," you wouldn't go, "Ah, well. It's impossible to save the arm. Time to wait it out and adapt."

      At least, I'd hope you wouldn't. That's when you have an operation, try to save as much of your arm as you can. And then you think about what caused the gangrene in the first place, and try to not do that ever again.

      Oh, okay, I get it. So who gets to decide which parts of the human population to cull?

      --
      "Somebody has to do something. It's just incredibly pathetic it has to be us."
      --- Jerry Garcia
    33. Re:Impacts by nine-times · · Score: 1

      The "gangrenous arm" isn't part of humanity in this metaphor. It's the damaged environment.

    34. Re:Impacts by AutodidactLabrat · · Score: 1

      So you clearly haven't done any reading on arctic temperature rise. That 1.4 - 6.4 degrees will not be uniformly spread and the arctic will see the worst of it. Result? Jet stream distortions, radically rising temperatures across the grain belt and, add in the calthrate outgassing, the rapid loss of ice cover and reduced albedo, the situation will go from hot to hungry in an enormous rush.

    35. Re:Impacts by knightghost · · Score: 3, Insightful

      The Stern report assumes that how we do things doesn't change, which is fundamentally incorrect. We constantly change. fivethirtyeight.com has had a few backwards-looking comprehensive stat reports that show we do adapt and that this type of report is bogus.

      Climate change is happening and will continue to happen. Society isn't going to abandon oil so researchers need to quit having that fantasy. What are REAL ways that society will agree to change? The simplest is to quit building below anticipated sea levels (probably by adjusting insurance rates... put a cap of CPI-U+5% yearly increase to make it politically palatable). Focus on that - it's an area of society and economics that has a decent chance of actually being changed.

    36. Re:Impacts by jasno · · Score: 1

      I don't have a dog in this race, but I've got to point out that California is actually in a relatively wet period and if it returns to it's formerly dry state then California will be fine. The people, maybe not so much, but California has been much drier in the past.

      --

      http://www.masturbateforpeace.com/
    37. Re:Impacts by jbmartin6 · · Score: 1

      This is a great intersection of goals. Getting rid of coal power for cleaner alternatives has a lot of benefits even if you lend no credence to AGW.

      --
      This posting is provided 'AS IS' without warranty of any kind, implied or otherwise.
    38. Re:Impacts by Anonymous Coward · · Score: 0

      actually, many reports tie all the global warming to exactly the fact that there are too many people on the planet so the ultimate solution to global warming is population reduction. I'm hoping that it will be through a naturally occurring pandemic that will cut a swath through all classes. My nightmare is that it will be a manufactured pandemic which means that select people will have been vaccinated in advance.

      I faced a similar situation when I was being diagnosed with a lymphoma. One of the early doctors in the process asked what my education and profession were. When I told him, his comment was "you have some skills then." almost as if the fact of having some useful skills meant that I'd get treated better than someone who scrounges pop bottles for a living. Very disturbing.

    39. Re:Impacts by WhiplashII · · Score: 1, Informative

      Even worse, every prediction they have made about actual temperature has been falsified. Every single one! Five year predictions, wrong, ten year predictions, even further off, 15 year predictions way out of line, 20 year predictions so far off that statistics has falsified the models to 99% confidence levels.

      Note that as time goes further out, the predictive power decreases dramatically. That is the opposite of the claim "we can predict climate on 100 year scales but not weather on yearly scales."

      If your predictions get further and further from the truth as time goes on, you do not get to continue to use those predictions to force others to go without.

      --
      while (sig==sig) sig=!sig;
    40. Re:Impacts by AutodidactLabrat · · Score: 1, Troll

      Seriously, your only alternative is paid-for shillls by the oil industry and you are going to reject the work of 250,000 Climate scientists, statisticians and space-climate researchers.
      This is idiocy turned into an art form.
      so, that said PBS How Exxon Shaped the Climate Debate (denialism exposed)

    41. Re:Impacts by Anonymous Coward · · Score: 0

      Humans possibly will adapt, altough their numbers will radically decrease..

      Our civilisation and way of life will almost certain not survive. Once flooding and drought will spark off world-wide famine, civil behaviour will crumble. Those that survive will almost certain not in great enough number to keep the minimal production cycle, that marks the modern society, up and running.

    42. Re:Impacts by Anonymous Coward · · Score: 0

      "Oh noes! Not the Koch brothers! Thave me! Thave me!" (runs around flapping my arms like a faggot)

    43. Re:Impacts by Anonymous Coward · · Score: 0

      Fear not, Gay Boy... The Koch Brothers cannot harm you as long as I am near.

      Manbearpig, though...

      OH NOES! Not Manbearpig!!!!! (runs around flapping my arms around like a faggot)

    44. Re:Impacts by Anonymous Coward · · Score: 1

      I'd expect massive droughts in the equatorial zones, the collapse of many third world governments and a huge refugee crisis but that's not the same as saying it's unsurvivable by humans as a species.

      So you're saying the next hundred years will be the same as the past hundred years.

    45. Re:Impacts by blue9steel · · Score: 1

      It depends on where the current water is coming from. For example, coastal areas backed by a mountain range with onshore breezes would probably get wetter as greater amounts of seawater evaporate, form clouds and then dump precipitation before going over the mountains. For areas that rely on lakes and rivers the situation will be the opposite as evaporation rates exceed the natural refill rate, see northwestern Kenya for an example.

    46. Re:Impacts by blue9steel · · Score: 1

      In the worst case scenarios it could be quite bad indeed, but that's not the same as "it will get too warm for food growth anywhere". Even in the probable scenarios food prices are likely to rise significantly and many of the worlds poorer citizens will experience famine, war and social collapse. The chances of species extinction however are quite slim.

    47. Re:Impacts by Anonymous Coward · · Score: 0

      I agree that it is a "pretty epic level of arrogance" to presume that we know exactly how much more carbon we can safely emit. The truth is that we don't.

      However, the "Our climate models deviate increasingly from actual recorded temperatures over the last twenty years, but one or more of these 50 causes explains the deviation (we have no rigorous proof that any of them actually had any effect, but we're sure at least one of them is the cause), and we're certain that our predictions for the next century are accurate, so you should implicitly believe our apocalyptic predictions" mantra does not inspire confidence.

    48. Re:Impacts by Anonymous Coward · · Score: 0

      Well if half of you idiots would quit trying to force us all to live differently there wont be a reason to go to war.

      But trying to force everyone to live a particular way in order to prevent some hypothetical? Thats a very good reason to go to war against who the fuck ever would do such a thing.

    49. Re:Impacts by camg188 · · Score: 1

      So maybe instead of the past "billion years" we should focus on say the past 50million

      Ok. Consider the Cenezoic era, the "Age of Mammals". For a majority of this era it has been so warm that there have been no polar ice caps

    50. Re:Impacts by Anonymous Coward · · Score: 0

      I'd expect massive droughts in the equatorial zones,

      You should quit speculating and look at the geologic record, where pretty much the opposite is found.
      Higher temperatures put a lot of moisture into the atmosphere.

    51. Re:Impacts by Anonymous Coward · · Score: 0

      Once flooding and drought will spark off world-wide famine,

      Well which is it? Flooding or drought? One sort of negates the other.

    52. Re:Impacts by Anonymous Coward · · Score: 0

      Especially when one considers that their temperature estimates from previous reports are higher than existing conditions.

    53. Re:Impacts by ksheff · · Score: 1

      Exactly. Lots of people tune things out when others start talking about "doing X for the environment". They are tired of the Chicken Little warnings and the "holier than thou" attitude that often accompanies the message. They do tend to pay attention to "doing X will save you money/make your life more comfortable/whatever".

      --
      the good ground has been paved over by suicidal maniacs
    54. Re:Impacts by Anonymous Coward · · Score: 0

      Unless this planet gets up to Venus level heat (and I'm pretty sure that's impossible), then humans will adapt.

      I'm not as sure as you are that we'll be able to adapt fast enough, but putting that aside, it seems to me that we can adapt by cutting down the human population to more sustainable numbers (through famine and war, probably) or we can adapt by changing our life styles to a more sustainable version. I guarantee that if we don't make an effort to do the latter then the former is going to bite us in the ass.

      You can put your head in the sand and wait for us to 'adapt' but I prefer a future where my descendants aren't having to worry about being culled.

    55. Re:Impacts by Anonymous Coward · · Score: 0

      That what we were trying to do, but governments and conservatives were unwilling to change their habits and stonewalled everything. So, now some of you might soon own beachfront property where none was before.

    56. Re:Impacts by ksheff · · Score: 1

      That's true with or without climate change.

      --
      the good ground has been paved over by suicidal maniacs
    57. Re:Impacts by Anonymous Coward · · Score: 0

      Really???

      It that really all people are talking about when they talk about the oil industry's disinformation campaign?

      Did you even read it?

      In 1997 the CEO of Exxon (an engineer) became convinced that global warming fears were overwrought. Despite it not being in his companies interest--- according to your article-- he lobbied against it because he thought it was wrong. The campaign tailed off in 2005.

      Pay no attention to the vast conflict of interest of the alarmists--- no. Look at this small public relations campaign from a decade ago.

      Your mountain is a molehill.

    58. Re:Impacts by lessthan · · Score: 1

      How long is your timeline? The weather service says that most of California is in "exceptional" drought conditions. Looking at the legend with a little gallows humor, it looks like they might have added "exceptional" to the scale because "extreme" was no longer a sufficient descriptor. I would hope their timeline is at least a couple of hundred years. So why would you say wet?

      --
      Space Shuttle was a program that strapped humans to an explosion and tried to stab through the sky with fire and math
    59. Re:Impacts by lessthan · · Score: 1

      I can't find anything about the Arctic, but the Antarctic ice pack has been around since the Eocene, which means it has been around for most of the Cenozoic.

      --
      Space Shuttle was a program that strapped humans to an explosion and tried to stab through the sky with fire and math
    60. Re: Impacts by sandertje · · Score: 2

      You're condemning my entire country to oblivion! Are you seriously suggesting the billions of people on this planet who live on the coast move somewhere else? Good luck with that. That's a bare minimum of three wars or so.

    61. Re: Impacts by sandertje · · Score: 1

      Warmer air can hold more moisture. That's why.
      Puerto Rico and Suriname are both firmly located in the tropics. Both had an unprecedented drought this year (still ongoing in Suriname).

    62. Re: Impacts by sandertje · · Score: 1

      I can confirm this. I live in western Europe, where rain ought to be in the form of drab, drizzly days. Summer always had more concentrated showers, but during the last ten years the incidence of tropical-style thunderstorms in summer has ever increased. This summer, again, broke the record of rainiest summer in recorded history by inches of rain, even tho it's been pretty warm and sunny.

    63. Re: Impacts by sandertje · · Score: 1

      Yet. Infrastructure for life below the ground is present in large quantities all over the world, there basically already are colonies in Antarctica (even tho we might call them "research stations"), and the oceans... Well... That's just a matter of time.

    64. Re:Impacts by riverat1 · · Score: 1

      The panel would be disbanded, if Climate Change turned out to be a hoax so all members are interested in maintaining the fear.

      Since none of the members of the panel are paid to be on it why should they care?

    65. Re:Impacts by riverat1 · · Score: 1

      The two are not mutually exclusive. In fact it is possible to have flooding in the middle of a drought without ending the drought. They operate on different timescales.

    66. Re: Impacts by johnsnails · · Score: 1

      I live south more than 200km south of the equator you insensitive clod!

    67. Re:Impacts by Anonymous Coward · · Score: 0

      You should realize that moving an average up a temperature scale does not necessary mean that you displace the distribution linearly on the right of the scale, which is what I understand by reading your examples.

      5 C variation is nothing to us in daily and local variation, but as an average, it is what differentiates our current climate from what it was like when the mammoths were roaming the earth and the vegetation in Spain was close to permafrost.

    68. Re: Impacts by mrchaotica · · Score: 1

      All of those places require that supplies like food get shipped in from less extreme environments. If you're not self-sustaining, then you're "visiting" there, not "living" there.

      --

      "[Regarding the 'cloud,'] ownership was what made America different than Russia." -- Woz

    69. Re:Impacts by blue9steel · · Score: 1

      So, no, it might not "wipe out the human species" by any means, but if food production gets harder due to drought, fresh water is harder to find (we're already draining aquifers, Lake Meade is seriously depleted - what do you think happens to Las Vegas then?), we might well see human population go from 7.1+billion to a small fraction of that (100million say). Might not be a bad thing for the planet, but I'm betting if you're one of the 7 billion that don't make it you might not think so. ;)

      That's a pretty extreme scenario but within the range of possibility. I think for something that severe to occur we'd need to see a lot of positive feedback effects that we're not really sure about at the moment. Of course, if we had any brains at all we'd be building nuclear power plants like they're going out of style, but unfortunately the environmentalists are ensuring that serious global warming will occur by blocking all of the better but not perfect alternatives to coal.

    70. Re:Impacts by blue9steel · · Score: 1

      We don't have foreknowledge of shit. It's a pretty epic level of arrogance to think we've suddenly acquired the ability to accurately see 100 years into the future when EVERY SINGLE ATTEMPT in the past to accurately predict anything even 20 years in the future has failed MISERABLY and has been LAUGHABLY wrong.

      The only thing that I predict about what this planet is going to look like 100 years from now is that it's going to be nothing like what anyone expects today.

      That's true, but there are steps we could take that we should be doing anyways. For example, externalized costs should always be re-internalized. Currently we allow coal power plants to spew pollution into the air without paying for it. A simply air pollution tax, set at different rates for different pollutants would solve much of that in a market friendly way.

    71. Re:Impacts by amiga3D · · Score: 1

      Nah, the wars will come when resources get short and nations go to war to control what remains. When people get hungry and cold they become very dangerous.

    72. Re:Impacts by Anonymous Coward · · Score: 0

      Actually, with big data analytics models, we do suddenly have this ability...

    73. Re: Impacts by KenHansen · · Score: 1

      Oil that we don't burn here in the US is still burned somewhere, most likely in a less-efficient, dirtier manner than it would if imported into the US. By lowering imports we make more fuel available which results in more pollution, not less.

    74. Re:Impacts by Anonymous Coward · · Score: 0

      Either that or you and all your denier cronies are too stupid to distinguish between exaggeration and fact.

    75. Re: Impacts by Anonymous Coward · · Score: 0

      Wow D.A. runs rampant, one active volcano emits more greenhouse gases and atmospheric pollution in two weeks than the entire human race in a year, how do you mitigate that? Put a cork in it

    76. Re: Impacts by fyngyrz · · Score: 1

      Is this year actually a warmer year? Didn't I just read that we're in a 20-year hiatus in the warming trend?

      Yes, warmer air holds more moisture -- anyone who has worked the steam tables to convert between relative and absolute humidity knows that (and I have done so for my auroral photo opportunity prediction freeware), but it's also susceptible to precipitating more moisture when convection brings that moist air up into the colder altitudes. That's why tropical rainfall tends to be in deluges as compared to, for instance, the typical rain shower in Pennsylvania. We know for a fact that the tropics are warmer and wetter in terms of rainfall amounts per year -- and that since they are warmer, their air can hold more moisture. But that's not stopped them from having much more rainfall than anywhere else. While there certainly may be outlier statistics, the general case seems clearly to be: warmer = wetter = more rainfall.

      Temperate rainforests get as much 100 inches / year. Tropical rainforests get up to 400 inches / year. If it's not the heat that's doing it, what do you propose is the mechanism?

      If it *is* the heat that's doing it, then what is the mechanism where more heat, heat that corresponds with previous tropical climates in the earth's past, won't repeat the same effect here? Looking at the past CO2 level graphs as correlated with plant growth and temperature, there's a very strong correlation with CO2 and plant growth, and with temperature. Plants love CO2, but they still need moisture to survive, and where there's more plant growth, it's pretty much a certainty that there's a significant water supply.

      So far, anyway, the idea of warming in the tropics -- or anywhere there's basically unlimited water and related prevailing winds -- leading to drought seems to be a non-starter.

      It's not that I can't accept it, it's just that to accept it, I need a sound scientific reason to do so. Just saying that one expects drought in the tropics seems like hand-waving at this point. There are plenty of legitimate concerns - a slight, very, very slow rise in sea level, movement of crop-appropriate bands in cultivated areas, that sort of thing, but tropical drought doesn't appear to be one of them.

      Also, recent news shows increased plant growth worldwide... something to think about in a situation where CO2 is known to be increasing at an accelerated rate.

      --
      I've fallen off your lawn, and I can't get up.
    77. Re: Impacts by AutodidactLabrat · · Score: 1

      Don't tell that to nuclear France that had to shut down reactors due to overheated rivers (Where is all that tropical rainfall) in 2010?

    78. Re:Impacts by AutodidactLabrat · · Score: 1

      says those whose Scientific Objectivity is for sale to Exxon and the gaggle of Koch Brothers propagandists and those who quote ECONOMISTS as if they were actual climatologists.

    79. Re:Impacts by AutodidactLabrat · · Score: 1

      Agreed. There will be food. The rich will get it. The poor will riot, pillage and behead them.
      Patterns of history will not be denied for long and the Russian saying "hungry bellies make revolution" is exactly what the world cannot afford any longer
      But to avoid it, taxes now is a far better solution than military occupation later.

  10. Re:Beyond what humans can do by Cardoor · · Score: 3, Funny

    ready guys? 1....2...3.... get him!!!

  11. well... by argStyopa · · Score: 1, Funny

    I just hope global warming increases to the point where it can self-pop the popcorn I like to eat when these histrionic sorts of things come out. All the sound and fury, so little actually accomplished! Whee!

    It's also likely that global warming might deliver pre-melted butter for the popcorn. Damn, what's wrong with this again?

    --
    -Styopa
    1. Re:well... by mellon · · Score: 2

      Well, if you aspire to be (as opposed to eat) sous vide steaks, I guess there's no problem at all.

  12. Don't Worry! by Anonymous Coward · · Score: 5, Funny

    Don't worry. Seriously, some very rich people who made a fortune selling gas and coal have assured us that these climate change alarmists are just a bunch of melodramatic liars. There's nothing to worry about.

    1. Re:Don't Worry! by Anonymous Coward · · Score: 0

      Guess what? There's now a bunch of very rich people selling us wind generators, building plants to produce ethanol for fuel and solar cells to install on our homes. If you don't think that creates a bias in the AGW promoter camp them you have a long way to go to understand the human condition.

    2. Re:Don't Worry! by Moof123 · · Score: 3, Interesting

      Yes, rapacious capitalism tends mostly to believe in whatever lines their pockets at the moment.

      Your mention of ethanol is a great example. Ethanol on the whole is a big loser both in therms of wasting food, wasting tax dollars subsidizing it, not reducing carbon emissions, and greatly using up public will with a massive sideshow. Monsanto loves it, as do lots of industrial farmers (there are no family farmers left of consequence, just in campaign ads).

      If our government was not already captured by the current lot, we could use laws to adjust incentives to get these rapacious capitalists to cause less harm by letting them fight over dollars in solar rather than oil. Sadly, changing the status quo scares the hell out of the current set of rapacious capitalists, so they spend part of their massive profit to manipulate the system to keep their cash cow protected. We as voters have been gerrymandered into being mostly irrelevant, so we cannot do much anymore. Weak minded kumbaya green folks are their own worst enemies, expecting that hugs and good will toward mankind will magically solve the problem (and they SUCK at math).

    3. Re:Don't Worry! by Lumpy · · Score: 1

      here is the kicker, anyone with an IQ over 100 and not lazy can make their own wind generators. In fact if you are not completely inept you can easily generate all the electricity you need with low cost parts that are available. All of the knowlege you need is right in front of you, you just have to take the time to search for it and read it.

      Drilling for oil, then refining it yourself with todays available devices and parts is significantly harder than a solar,wind and battery installation.

      --
      Do not look at laser with remaining good eye.
    4. Re:Don't Worry! by Anonymous Coward · · Score: 0

      Don't worry. Seriously, some very rich people who made a fortune selling gas and coal have assured us that these climate change alarmists are just a bunch of melodramatic liars. There's nothing to worry about.

      How about the very rich people who made a fortune selling oil, gas and coal and now assure us that climate change is real?
      http://en.wikipedia.org/wiki/Tom_Steyer

    5. Re:Don't Worry! by volmtech · · Score: 1

      The US and European union could reduce our carbon output to post Civil War levels and global carbon dioxide levels will still increase because we can't stop China and India from using more coal and oil and we can't keep the Amazon forest from being cut down. But a few individuals can attempt geoengineering. Mostly I suspect it will be business as usual until it's way to late to do anything else.

    6. Re:Don't Worry! by SecurityGuy · · Score: 1

      If you live somewhere with sufficient wind. In my part of .us, there's often not even a breeze unless it's stormy. I checked, and it looks like average wind speeds here are 4.5m/s at 80 meters. 4.5m/sec sounds breezy, and I wouldn't be surprised if that's enough to drive a generator, but 80m is really very, very tall for something in my yard. At a guess, it's about 2x the tallest tree I have.

    7. Re:Don't Worry! by Anonymous Coward · · Score: 0

      Don't forget the rich professors and scientists. They're not super-rich, but they're certainly not poor. They have a lot more to gain promoting climate alarmism than promoting climate rationalism.

    8. Re:Don't Worry! by Alioth · · Score: 1

      If the US and Europe were to reduce carbon output to post civil war levels (i.e. effectively go back to some sort of agrarian lifestyle), China and India certainly wouldn't be using more coal and oil. It is the US and Europe which is driving the demand for fuel in China. It's not Chinese peasants buying all the stuff China puts out, it's generally the West that's fuelling China's increasing demand.

    9. Re:Don't Worry! by Anonymous Coward · · Score: 0

      I don't know, I think you're the one with the low IQ. With the parts I can easily and affordably get, and with the speed the wind usually blows, I might be able to make a couple of watts. Yeah, that's not going to cut it. Hell, those big ass ones, what are those, a megawatt or two? Yeah, if they're big enough, or you have enough of them, you can power things, but enough small ones is probably cost prohibitive, and big enough, well, I don't have access to crains, and the whole cost thing again for my personal use.

    10. Re:Don't Worry! by Lumpy · · Score: 1

      Herp Derp there much?

      --
      Do not look at laser with remaining good eye.
    11. Re:Don't Worry! by Anonymous Coward · · Score: 0

      If I didn't live in a townhouse, I would. As it is, I would love to be able to move 50 miles east of my current location, but driving 75 miles one way to work is just not realistic, and getting a new job that compensates me as well as the current one is highly unlikely.

      Face it, if you live in the city, it is highly unlikely you have more then a flowerbed of land and likely don't own your roof, even if you own the walls, the condos and townhouse hoa owns it. Heck, most people that live in a city are renters and certainly don't have the ability to just add in a wind generator.

      Believe me, I'm steadily working on one day owning several acres and a small house. The tricky part is exploring homeowners laws where your property exist and really understanding what you can and cannot do on your own land.

    12. Re:Don't Worry! by Anonymous Coward · · Score: 0

      LOL!
      And I'm not an Anonymous coward! Come here and say that!

  13. Re:Beyond what humans can do by Kythe · · Score: 1

    You will be remembered for your contributions on this issue, I'm sure. What I'm not sure about is whether you'll like how you're remembered.

    --

    Kythe
  14. Re:Interesting slam of Judith Curry by drfred79 · · Score: 0

    MDSOLAR why do you post links from that biased site every time climate comes up? Do you work for them? Post from respectable sources.

  15. I don't believe it by slashdice · · Score: 1, Flamebait

    Barack Obama healed the earth with his inaugural address in 2008!

    --
    Copyright (c) 1990 - 2014 Dice. All rights reserved. Use of this comment is subject to certain Terms and Conditions.
  16. It's IPCC...not IPPC by dtjohnson · · Score: 3, Informative

    At least get the acronym for the name of the organization predicting doom right. And...there's no hurry for action. The climate is currently taking a 'hiatus' from warming due to the alleged storage of heat in the deep ocean. Forecasts for the upcoming winter are...cold.

    1. Re:It's IPCC...not IPPC by Anonymous Coward · · Score: 1

      We know it will warm up because of the models. Those models didn't predict a warming hiatus or storage of heat in the deep oceans. But lets make policy choices based on what those models say. If you don't agree, you hate science and probably beat your wife.

    2. Re:It's IPCC...not IPPC by Anonymous Coward · · Score: 0

      No, that is completely incorrect. There is no "hiatus" from the process of human impacts on the planet; the changes continue in the deeper oceanic currents, the ability of which to contain further added heat being further reduced. As an example, imagine I have been stealing $10 from your checking account every month - clear and obvious, and you want to stop it. But then I switch and begin taking $10 instead from your savings account. You don't see it when you balance your checkbook, you never check your savings account, and so you can pretend it's not happening, but the day you need to access your savings account and there is nothing there, you're screwed.

      And of course, I, who am stealing the money from savings, can insist over and over again that there is nothing wrong with your checking account and you are obviously hysterical and trying to frame me.

    3. Re:It's IPCC...not IPPC by Anonymous Coward · · Score: 0

      I don't think that is what is being said. To follow you banking analogy, imagine I check my checking account balance and notice it's a bit low every month, but I don't really know how much my wife is spending from the checking account, or how much she transfers between checking and savings makes so I'm a bit suspect that someone is stealing money from my account.

      My neighbor's kid tells me because my kid seems to have $10 extra every week, that my kid had been stealing $10 from my checking account every month but in order to fool me decided to switch and take $10 from my savings account so maybe I don't notice. Since my balancing my checkbook is so complicated that it takes 100's of PhD's and research scientist to do and they can't quite agree on exactly what my checking account balance should be, I'm a bit skeptical.

      However, since I can't trust what my kid says, and I don't know exactly how he might be doing it, I say Fuck IT! and I decide to just either punish my kid by turning him over to the police, or punish my entire family by spending $10 less per week on food and clothes, just in case he's been stealing the $10 because I'm afraid that I might be screwed in the end...

      However my neighbor's kid (who is the same one that attempted to implicate my kid) tells my that I am not qualified to make any decision about this matter and I need to refer this problem to the united nations and be forced to live by whatever decision they come to... yeah, right...

    4. Re:It's IPCC...not IPPC by cinnamon+colbert · · Score: 1

      glad to see someone is up on the latest news.
      however, if you read those storage papers, they usually conclude with something like, extra warming when the storage stops...

    5. Re:It's IPCC...not IPPC by strikethree · · Score: 1

      The climate is currently taking a 'hiatus' from warming due to the alleged storage of heat in the deep ocean.

      I am not part of this Global Warming thing; either for or against. I believe in trying not to affect the environment as much as possible and I am aware of all of the yelling and screaming; however, heating the deep parts of the ocean scare me like building an atom bomb in my basement scares me.

      Do you recall the huge tsunami that hit Indonesia, Thailand, etc? IIRC it was back in 2007 or so. That was nothing compared to what heating the depths of the ocean will do. The ocean is HUGE and the thermal inertia is just O.M.F.G. huge. Storing that much energy on the planet can only be a VERY bad thing. I have no idea what will happen because of that amount of energy being stored but it will not be good if it is not released again VERY slowly and carefully.

      --
      "Someone needs to talk to the tree of liberty about its ghoulish drinking problem." by ohnocitizen
    6. Re:It's IPCC...not IPPC by Anonymous Coward · · Score: 0

      Facts: Climate change, constantly since climate began. Global warming "hiatus" (meaning none measured) going on 18 years, now. Explanation for the hiatus a result of heat sinking in the deep oceans, a hypothesis un proven and speculative, in hopes of saing warming still looms (as did the "deep freeze" a few decades earlier).

  17. Re:Beyond what humans can do by Njorthbiatr · · Score: 1

    We can make it rain, actually. It's called cloud seeding.

  18. Re:Beyond what humans can do by emagery · · Score: 2, Insightful

    Do you really have so little concept as to the scale of human damage? A single average-sized car puts out 4.75 metric TONS of carbon every year (and about 2-3 years worth during its construction and a little bit more during its destruction.) At last check there were more cars in the use being operated than there are drivers... and that's just one country... whilst this amount is being dwarfed by carbon emissions tied up in industrial agriculture (local/natural agriculture trends toward carbon neutral to negative, but can only sustain modest populations the likes of which we haven't seen on earth for over a century.) The fact that YOUR individual contribution to the damage done is a drop in the bucket does nothing to deny the fact that you are not the only person on earth... it's a tiny place in the grand scheme of things and we've overrun the place and are spending carbon, water, and oxygen like there's no tomorrow... which is no longer a mathematically implausible scenario as a result. The world's WORST extinction level event was also a climate change one, and we've reach the same levels at 40000x the speed... if life couldn't cope at that snail's pace (~1000000 years of constant hawaii-style volcanic carbon farting, killing off some 95% of all life) why do you think it (or we) will fare any better doing the equivalent of flying this jet into a brick wall?

  19. My 0.02 by DaMattster · · Score: 1

    I'm far from an expert but the drought conditions out west are certainly telling something.

    1. Re:My 0.02 by Anonymous Coward · · Score: 0

      The west has been unusually wet in the recent past. Going back a bit longer, there were centuries of drought.

          "The two most severe megadroughts make the Dust Bowl of the 1930s look tame: a 240-year-long drought that started in 850 and, 50 years after the conclusion of that one, another that stretched at least 180 years."
      http://www.mercurynews.com/science/ci_24993601/california-drought-past-dry-periods-have-lasted-more

    2. Re:My 0.02 by Bob+the+Super+Hamste · · Score: 1

      People should live in a desert.

      Seriously why to people do water intensive farming in a desert in an effort to preserve their water rights? I am not all that sympathetic to farmers and ranchers that through our governments subsidy rules and their use it or lose it water rights are having a hard time in what normally is a desert. Guess what you live in a desert and if you can't get the water to grow your alfalfa, lettuce, grape, etc crops maybe you should be trying to grow those things there.

      --
      Time to offend someone
    3. Re:My 0.02 by Jane+Q.+Public · · Score: 0

      I'm far from an expert but the drought conditions out west are certainly telling something.

      That's weather, not climate. Plus, even factoring in the hot & dry SW, according to the raw data the "lower 48" of the U.S. still experienced one of the coldest years on record so far.

      Globally, catastrophic weather events are at a much lower level than they were 10 or even 20 years ago.

    4. Re:My 0.02 by Anonymous Coward · · Score: 0

      [citation needed]

    5. Re:My 0.02 by Anonymous Coward · · Score: 0

      Here is a supply of the word "not". Please apply liberally to the paragraph above.

      not
      not
      not
      not
      not

    6. Re:My 0.02 by Jane+Q.+Public · · Score: 1

      [google needed]

      This ain't Wikipedia. The information is easy enough to find.

    7. Re:My 0.02 by Layzej · · Score: 1

      Likely if the information was easy to find he would have cited it. I did a Google search and found information to the contrary:

      "The higher frequency of extreme weather events is influenced by climate change... Munich Re first warned about global warming way back in 1973, when it noticed that flood damage was increasing.... The trend lines in Munich Re’s charts are compelling. They show that the insured and uninsured losses from natural catastrophes have been on the upswing since work on the company’s database began in earnest in 1980." -http://www.theglobeandmail.com/report-on-business/rob-magazine/an-industry-that-has-woken-up-to-climate-change-no-deniers-at-global-resinsurance-giant/article15635331/?page=all

    8. Re:My 0.02 by Kohath · · Score: 1

      Not people should live in a desert.

      Not seriously why to people do water intensive farming in a desert in an effort to preserve their water rights? I am not all that sympathetic to not farmers and not ranchers that through our governments subsidy rules and their use it or lose it water rights are having a hard time in what normally is a desert. Guess not what you live in a desert and if you can't get the water to grow your alfalfa, lettuce, grape, etc crops maybe you should be trying to grow not those things there.

    9. Re:My 0.02 by ChrisMaple · · Score: 1

      The central valley of California has good soil, warmth, and dependable sunshine. All that's missing for great agriculture is dependable water. The mid-west, America's breadbasket, suffers fairly cold winters and occasional severe floods.

      People make do with what they have and operate in whatever economic conditions prevail. If water becomes too rare and hence too expensive, California farms will fail. Food prices will go up for everyone, and some California farmers will be impoverished. If water does not become too expensive, almost everyone wins.

      --
      Contribute to civilization: ari.aynrand.org/donate
  20. Re:Interesting slam of Judith Curry by thedonger · · Score: 1

    MDSOLAR why do you post links from that biased site every time climate comes up? Do you work for them? Post from respectable sources.

    Wikipedia says it will be 75 degrees (F) and sunny for the rest of time! [citation needed]

    --
    Help fight poverty: Punch a poor person.
  21. Re:Beyond what humans can do by emagery · · Score: 1

    typos notwithstanding

  22. Re:Beyond what humans can do by jeffmflanagan · · Score: 1, Interesting

    It's funny how delusional people like frikken lazers think that pointing out that he's in Republican alternate reality means that nuts are censoring his message. These AGW deniers are just as cracked as evolution deniers, and are often the same people. I hope he gets some professional help.

  23. Climate damage is never irreversible by gurps_npc · · Score: 2
    They probably meant irreversible in a reasonable amount of time.

    But I absolutely assure you it is possible to undue all damage- if we are willing to pay a ridiculous amount of money to do it.

    Now, biological extinctions may be unpreventable, but we can always turn the clock back on climate change.

    --
    excitingthingstodo.blogspot.com
    1. Re:Climate damage is never irreversible by Nemyst · · Score: 2

      I don't think the worry with climate change was ever that we'd destroy Earth. It's just that it's in our best interests to avoid a certain species of apes from going extinct. Even that is unlikely, but I'm not sure you'd enjoy the possibility of millions or billions of people dying to an extinction-level event. Who's to say you'd be among the survivors, or your children?

    2. Re:Climate damage is never irreversible by jandrese · · Score: 1

      The "irreversible" part is talking about Ice Sheets that can't reform unless we have another ice age. Even if we got the average yearly global temperature back down to pre-industrial levels the ice sheet won't reform because the winter snow would be falling at a lower altitude where it will melt in the summer. So either we get this climate change situation under control in a hurry, or we start building a whole lot of seawalls around our coastal cities and just learn to deal with flooding.

      --

      I read the internet for the articles.
    3. Re:Climate damage is never irreversible by gurps_npc · · Score: 1
      Or we set up a situation where we have another 'year without a summer', only this time on purpose. (i.e. artificially create a volcanic eruption). This allows the ice flows to reappear. After that super cold year, we go back to normal.

      I am not saying this is a good idea, just that we could do it, reversing the problem.

      --
      excitingthingstodo.blogspot.com
    4. Re:Climate damage is never irreversible by Anonymous Coward · · Score: 0

      I read somewhere that when the Earth heats a certain point from climate change there will be a point of no return since a feedback loop will occur. We would need to terra form our own planet from orbit or something crazy like that.

  24. It'd hardly be surprising. by Anonymous Coward · · Score: 0

    And in all honesty, what the human race should focus on right now is conserving as much life as possible.
    In a living state that is. The seed and DNA systems are good and should still keep going, but they won't be useful for us over the next century when half the human race ends up dying off due to massive eco-collapse.
    We are still a long ways off of recreating these creatures from 3D printing machines, or even implantation. (although I would certainly hope to be proven wrong by the mammoth revival project)

    What we need to do is make smarter, compact arcologies dotted all around the world. Preferably near renewable power sources like waterfalls that we know 100% will not fail even if the sun grew 5%.
    Better yet, make artificial water falls by planting more trees on hills. Trees are hugely important for generating water from the air. You could try DIY it, which we can do, but scaling it up will still have that initial cost. These trees would be essentially free and will be a reasonable size by the time anything might be bad.

    People are going to have to give up some spacial freedoms for the sake of the human race. All these big houses, huge empty gardens, all have to go.
    You don't and rarely do use them. Smaller efficient homes are easier to heat and manage, and are generally more cosy anyway.
    Large shared gardens and farms. And more to the point, vertical gardens and farms. These require special attention to weight distribution and engineering, but they can be done very easily even at a consumer level. (you can make pretty simple aquaponics farms from wood and metal containers)
    Buildings and offices that have dual uses. Say for example a clothes store in the morning, then it becomes a bar at night. I've rarely seen businesses that operate like this. Shame, they have a huge building sitting there doing nothing for several hours. Waste if you ask me. They could be making loads of money if they made dual purpose.
    So so many more things similar to this.

    Our planet is failing. And this matters not of your opinions on it, how much crap you have been fed from the media, it is a plain and simple fact: the climate is changing at a disastrous level.
    We haven't experienced this since the last ice age. Not even that volcano that caused a several season winter was that bad.
    Large numbers of things will die unless we preserve them in artificial environments.
    Places like the Eden Project are incredibly successful and the right direction for such preservation.
    And the construction itself is also very well done, and simple as well. Hexagonal building will surely become more important in the years to come, it is strong and easy to construct. (it also uses pentagons too, but hexagons are just that bit better)
    I quite liked the idea of that Hexagonal Building that was used for a possible Mars habitat. The layout I disagreed with a little, the bedroom and bathroom should be switched to be beside the other bedroom, but the idea is sound and very workable. 3D printable as well.

    Will it happen? Will it fuck. We care more about stupid religious wars, obsessively collecting pointless data and stupid resource wars that are only going to get worse to the point where we will likely end up wiping ourselves off the planet, along with billions of other lifeforms.
    Literally if every country sat down right now and said "no, let's fix this shit", it could work.
    Look at all the spending you see on things like the US Military. Imagine if that was put in to preserving our future. There would even be a problem any more.
    Shits wasteful and pointless. And the results barely even last a decade before there is more conflict.
    Only regular people will be able to get this done. Depending on governments is pointless now. They have all failed us. And trying to get them evicted from their positions of power will only cause more conflict.
    Given my country is likely going to be thrown in to a awful mess within the next week due to a silly independence attempt (which I agree with on some levels, but it is still too early to decide), I'm already making plans to fix the mess that the possible government will leave us in.

    1. Re:It'd hardly be surprising. by Anonymous Coward · · Score: 0

      smaller homes are only more efficient if they are built in groups in large structures. the problem is that a large surface to volume ratio means more heat can be more quickly lost or gained by the space inside. To offset this you have to build big and that's just what thins like smart growth and densification are all about. The destruction of the single family home in favour of the large, dense apartment structures.

      Of course, it doesn't hurt that it costs you, maybe, twice what a set of houses would normally sell for if you tear them down and put up a 100 unit apartment block that you then sell for a $25 million dollar profit. Ah, yes, sustainability is good business.

    2. Re:It'd hardly be surprising. by Anonymous Coward · · Score: 0

      > And in all honesty, what the human race should focus on right now is conserving as much life as possible.

      Fuck no. We've got about 4.5 billion humans too many already!

    3. Re:It'd hardly be surprising. by Anonymous Coward · · Score: 0

      Dig deep into Agenda 21 and you'll find that the top limit is 500 million so we're way past the 4.5 billion too many already.

      (I saw one paper suggesting we down grade the number of allowable people on the planet to 100 million. Don't quite know how we're going to keep the marvels of modern technology going with only 100 million on the planet but, hey, I'll probably be one of the culled so it won't be my problem.)

    4. Re:It'd hardly be surprising. by slew · · Score: 1

      Motivation to preserve? There's really no good motivation for preserving DNA other than historical preservation. Think of this like preserving the source code for apple //e prodos. The ecosystem which that source code was valuable has been long lost, probably never to come again. Newer source code that serves a similar ecological niche in the new eco-system will evolve and probably be better than it ever was.

      Some people seem to be obsessed with a philosophy no different than modern day Noah's ark where we somehow survive a major calamity and reboot the past. However, when confronted with modern day evidence of the problems with mono-culture and invasive species which threaten to unbalance whole ecosystems, they somehow fail to see that these survivors of this modern day Noah's ark are likely the vehicles of the new mono-culture and invasive species of our own making. Are we so important that our historical status-quo existence (e.g., the foods we enjoy from our childhood and furry animals we like to watch) trumps the natural development of the ecosystem, or should we learn to adapt or perish as nearly all other species under the sun?

      I don't think we ask these types of questions enough. Certainly we have done quite a bit of homo-forming of our planet (e.g., dams, farming, agriculture, mining, industry) over the millennia to get where we are today, but should attempting to recapture the past really be a goal? Or are we just introspectively thrashing ourselves with self-hate for currently/temporarily being at the top of the food chain of our planet? With great power comes great responsibility, but on the other hand is this chant the new "white-man's burden"?

  25. Models may differ from reality by bhlowe · · Score: 0

    Do these studies properly account for ALL animal flatulence? Including whales? I didn't think so.

    1. Re: Models may differ from reality by Anonymous Coward · · Score: 0

      When it comes to distractions, a fart is as good as a shiney. It isn't really all the oil we've been burning that's causing problems, it's... cow farts. Yup, cow farts. And whale farts, too.

    2. Re: Models may differ from reality by bhlowe · · Score: 1

      You give up using energy first. Let me know how it goes. (For what its worth, I drive an electric car and have 10KW solar panels on my house.)

    3. Re: Models may differ from reality by Layzej · · Score: 1

      You give up using energy first. Let me know how it goes. (For what its worth, I drive an electric car and have 10KW solar panels on my house.)

      It sounds like you are carbon negative. In that case, you could tell us how it goes. Are you suffering horribly?

    4. Re: Models may differ from reality by bhlowe · · Score: 1

      If you have cash, going green is easy and wonderful. If you're working poor, you're screwed. The US government can pretend to "invest" in green technology, but eventually the tens of trillions in debt and unfunded mandates will catch up with reality.

    5. Re: Models may differ from reality by Anonymous Coward · · Score: 0

      I agree you use solar energy, but in how many generations will reduced petrol and electricity bills pay it off?

    6. Re: Models may differ from reality by ChrisMaple · · Score: 1

      Take a look and think about this: http://xkcd.com/1338/

      --
      Contribute to civilization: ari.aynrand.org/donate
  26. Re:Well, There You Go. by jeffmflanagan · · Score: 1

    You sound as far gone as Glenn Beck. You're completely lost if you actually believe the wingnut delusion that you've posted.

  27. Re:Interesting slam of Judith Curry by i+kan+reed · · Score: 2

    Please characterize the bias.

    I won't reject your claims of bias out of hand(and benefit of the doubt is pretty much entirely what deniers rely on for everything so my patience is a little limited.

    This isn't "Watts up with that" where there's a financial payment for having the right opinions. These are scientists with appropriate credentials discussing common misinformation.

    If there is a bias, there must A: be an undisclosed or clearly concerning motivation or B: some kind of oversight problems.

    I don't mind discussing bias, but I want it to be more than "It calls my out my flawed opinions".

  28. Expert site by mdsolar · · Score: 1

    RealClimate is an expert site. That is where you will find reliable information.

    1. Re:Expert site by i+kan+reed · · Score: 1

      You know, honestly, the piles of mindless hate you get for a relatively benign opinion and posting news stories in support of that benign opinion tends to make me more, and not less, sympathetic to your positions.

    2. Re:Expert site by jandrese · · Score: 1

      Expert spin doctor site, yes. Just don't confuse anything on there with reasoned analysis.

      --

      I read the internet for the articles.
    3. Re:Expert site by mdsolar · · Score: 1

      Is that you Judith?

    4. Re:Expert site by Anonymous Coward · · Score: 0

      Yes, the site does look expert, it's just that Gavin is batshit.

  29. IPPC... by monkeypushbutton · · Score: 1

    .. is that organisation similar to the IPCC? Insert snark about editors here.

  30. "Leaked" huh... by Anonymous Coward · · Score: 0

    Because they would never want the media to get a hold of this document...

  31. In that case no need to change anything by Anonymous Coward · · Score: 0

    I mean, if the sky is falling, why bother making our last days uncomfortable by trying to change anything, might as well just keep it up.

    I have environmental institutions just as much as I hate deniers. Look, if you are going to present the argument that we're totally and completely fucked, why wouldn't the rational response be "Let's ignore it because whether or not they're right, there's no difference".

  32. Summer Court power grab by kit_triforce · · Score: 0

    Looks like Queen Titania or someone else is making a play for power, Someone call Harry before the ebola viruses get too happy.

  33. at least not with our current technology.... by mdsolar · · Score: 0
  34. Oh Well by Anonymous Coward · · Score: 0

    A-la gun control, then we should do NOTHING about it! Duh!

  35. Re:Beyond what humans can do by Impy+the+Impiuos+Imp · · Score: 2

    I am fine being remembered for pointing out yet again we will be better off in 100, 200 or 300 years keeping the economy strong and forging ahead with technological advancement than slowing it by draconian clamps on the economy (there are many clamps beside environmental remediation).

    100 years ago we barely had simple planes and no antibiotics. Horses were still common in the streets. Had they slowed down their growth to "help" us, well, thanks for nuthin', Gentleman Jim.

    The best thing we can do for future generations is keep things going.

    I remain confident it is the hyperventillation crowd that will be proved murderously dangerous idiots in the long run. I am fine going down on record with that prediction.

    --
    (-1: Post disagrees with my already-settled worldview) is not a valid mod option.
  36. Beyond what humans can do by Anonymous Coward · · Score: 0

    Your entire argument is that you can't see how humans can affect the whole world thus they must not be able to. Bad reasoning.

    Moreover, your argument that humans can't make it rain or affect the weather locally is patently false. It rains more during the weekend in human populated areas due to pollution build up during the work week. This same pattern is not seen in the open ocean lending support to the fact that our pollution is causing the variation. http://www.nature.com/nature/journal/v394/n6693/abs/394561a0.html

    So, yes we can and do change the weather locally. We also change it globally.

  37. Re:Beyond what humans can do by OzPeter · · Score: 1

    Anyone who thinks they can affect the whole world this much is a moron or shill for some environmental group.

    So how do you account for:

    The hole in the ozone layer and the successful global response to fix it

    Acid rain destroying forests and the successful global response to fix it?

    Were they also not man made problems that affected the world as a whole?

    --
    I am Slashdot. Are you Slashdot as well?
  38. Thats been answered. by geekoid · · Score: 0

    ". To all you science people, correlation does not equal causation. "
    no shit, Sherlock.

    " How else do you explain the many periods of warming and cooling in the past long before humans even existed?"
    There are different way the earth can warm. The effect of shoving more green house gasses into the atmosphere causes warming on top of other trends. There is no doubt about this at all.

    https://www.ipcc.unibe.ch/publ...

    " I rest my case"
    You did not, in any way, 'make a case'. You might want to learn what the means.
    If you want to make a case, you need to start by showing which one of these is false:

    1) The Earth gets lots of light from the sun
    2) Visible light emits IR when it strike something
    3) CO2 absorbs energy from IR
    4) Humans but more green house gasses into the air then can be absorbed.

    The basic science on warming is trivial. Literally any of these can, nad have, been test by any decent College lab. Hell, even A good high school lab could do it. This is why deniers never talk about the actual science and only talk about cherry picked data points, or make ad homs.

    So, the climate is warming due to more energy being trapped.
    Climate Change is the impact AGW has on the climate. They are related but separate issues.
    So, why would adding energy to a system not change it?
    At this point, some knuckle head is about to slam his meat hooks onto his keyboard in what he thinks is a clever retort,. I will take this time to remind him the new equilibrium is only reach when the change in energy stops, and there is no rule saying the planet need to be livable when equilibrium is achieved.

    More to the point:
    Why do you think there is a 97% consensus? Why do you think countries whose best interest would be that there is no AGW agree there is AGW?
    Some people think there is a weird conspiracy. That would mean the China is in on it for no reason. Why?

    --
    The Kruger Dunning explains most post on /. http://en.wikipedia.org/wiki/Dunning%E2%80%93Kruger_effect
    1. Re:Thats been answered. by Anonymous Coward · · Score: 0

      Why do you think there is a 97% consensus?

      Low scientific standards. The claims made by climate 'scientists' based on their data would not be accepted for publication or taken seriously in many other fields of science.

    2. Re:Thats been answered. by Anonymous Coward · · Score: 0

      You should actually see for yourself what passes in other fields of science. When I was in graduate school doing work on computational fluid dynamics, the PI (principal investigator) of my lab required all students to take a class where it was just reviewing papers. The class taught how to ask questions about a paper, how to identify shortcomings and how to tell if the paper contributed to the field in a meaningful way. We would select from most recent articles in stuff like "Journal of Heat Transfer" and see ridiculous papers. Maybe 1-3 papers in the entire course didn't have significant flaws. And this is in a field of hard physics/engineering, not something in climate science. If you have 97% consensus, that's reason to believe the work is reasonably accurate.

      Hell, in medicine, you don't even need 95% consensus for experimental treatments to be offered. This is because doctors have come to an agreement that it is better to have the option of a risky experimental treatment for terminally ill patients than to wait for conclusive research with p less than 0.5.

    3. Re:Thats been answered. by Anonymous Coward · · Score: 0

      Why would adding energy to a system not change it?

      Because of the leap of faith you made on that it is, in fact, a net positive change of energy. The biggest problem with the argument is that you propose that science has it all figured out and there is no doubt as to what the conclusion is. But then we see that the methane bubbling up from the ocean may have a much bigger impact than we once thought, or perhaps that someone's journal arbitrarily threw out some numbers they deemed to be outliers with no explanation to back it up.

      If the model isn't static, how can there be a conclusion?

      So I guess I'm a knuckle head (ad homs?) because I don't accept a moving target as conclusive science.

    4. Re:Thats been answered. by HornWumpus · · Score: 1

      What? 97% indicates an echo chamber.

      Healthy science requires descent.

      --
      John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
    5. Re:Thats been answered. by david_thornley · · Score: 1

      Healthy science requires dissent on things that are still being seriously questioned. AGW is not seriously questioned by climate scientists; they're figuring out what's happening, how it's happening, what's likely to happen in the future, that sort of thing.

      --
      "When you have eliminated the unacceptable, whatever is left, however improbable, must be the truthiness" - Holmes
  39. Where should I buy land to offset these changes? by Kevin+by+the+Beach · · Score: 1

    I believe that the climate will change (getting warmer & sea level rise). So, my question is... If I want the best property for possible self sufficiency where would that be? My first thoughts would be a minimum of 50' above sea level, and on the windward side of a large geographic feature (plateau / mountain) . The problem I haven't worked out is the variability of Ocean currents and prevailing winds? Will a currently Dry region increase in Precipitation, or should I stick with regions that get 20+ inches of rain on annual average? (and hope it doesn't change). I grew up on the "Tug Hill" plateau in New York, and their micro climate is influenced by their latitude, altitude, prevailing winds, and proximity to the Great Lakes. It may be a good place to track their micro climate going forward.

  40. Re:Well, There You Go. by drfred79 · · Score: 1

    What I didn't notice in your post was any type of rebuttal, only a personal attack.

  41. Re:Well, There You Go. by Anonymous Coward · · Score: 0

    Fortunately, science isn't like religion. Reality exists regardless of belief, so it'll be what it'll be. Humanity will probably survive long enough one way or another to settle the outcome of this irrefutably.

  42. Re:Well, There You Go. by geekoid · · Score: 0

    In some case, it will be top down. This will be in things like, building codes, emission guidlines etc.

    If it gets too bad, then I will be all for a top down solution involving guns and the removal of corporate charters.
    This is like 97% of all astronomers saying , there is a dark asteroid coming in a couple a hundred years the size of australia, we need to take action. And then large corporation and anti tax groups say 'no it isn't'. And 'your model isn't 100% perfect, therefor it's wrong and invalid!" and people saying. I'll believe it when I see it!" even though it will be too late to do anything about it.

    In that case, I would also support taking action, even if it had to be a forced action.
    This isn't about a different of opinion on a sports team, or tax code, or privacy. Its about something that will make all the irrelevant if we don't take action now.

    --
    The Kruger Dunning explains most post on /. http://en.wikipedia.org/wiki/Dunning%E2%80%93Kruger_effect
  43. Re:Well, There You Go. by Anonymous Coward · · Score: 1

    I think you're just too young to have experienced the politics of the 60s and 70s.

    Those that went through it are well aware of the intimate connection between environmentalism and anti-capitalism.

    Much of that connection was hidden during the 80s and 90 as the economy took off while the environment still improved. But that connection still exists, with many in the environmental movement still holding to radical anti-capitalism.

  44. Re:Beyond what humans can do by jandersen · · Score: 1

    How your comment got modded Insightful is a mystery. You don't give any arguments, you just postulate.

    Humans can't even make it rain or change the weather locally

    Really? Just one example: the notorious London smog. Most major cities used to be covered in the filthy stuff until burning coal in cities was largely banned; does that not qualify as weather? It certainly changed the atmosphere in large, local areas.

    Anyone who thinks they can affect the whole world this much is a moron or shill for some environmental group

    Hmm, right. Another example: man-made plastic pollution is now found everywhere - with the possible exception of Antarctica. You find it everywhere, even in the middle of the Pacific, and it does in fact affect wildlife. Or how about the fact that manmade chemicals can now be measured in just about every sample of water you can come about? The truth is that mankind does in fact influence every environment on the planet; the good news is that this also means that we can choose to use our influence to make things better.

    But it's certainly not manmade

    You know that, do you? How? Evidence, please.

    correlation does not equal causation

    However, it does equal correlation - and correlation means there is some sort of connection. Climatologists have come up with some very likely explanations, unlike you.

    How else do you explain the many periods of warming and cooling in the past long before humans even existed?

    That one is brought forth all the time, but it is a nonsense argument. The only thing it proves is that climate change can be caused by other things than human activity; nobody has ever denied that, and in fact, for many years the preferred theory was that we didn't affect climate, but we have had to abandon that idea, because the observable facts speak against it.

    I rest my case before the nuts here censor my message

    As you already knew, nobody was going to 'censor' your opinions. In fact, you have been modded up - strange as it seems. But you just had to try to milk the 'freedom of speech' card for what it was worth, didn't you? You should be ashamed.

  45. Yep, sure is by istartedi · · Score: 0

    The San Francisco valley is now a bay. The great barrier kangaroo hunting grounds have been flooded. The Siberian land bridge has been submerged. Irreversible, horrible, and irreparably damaged. Damaged I say! Worse yet, there will be no Frost Faire on the Thames this year.

    --
    For all intensive purposes, "whom" is no longer a word. That begs the question, "who cares"?
  46. Re:Beyond what humans can do by Nemyst · · Score: 1

    So what's your research? What data did you take to make this conclusion? What are your hypotheses and theories regarding the current warming trend? Oh wait, you're just knee-jerking because you think we can't possibly have done it.

    We can't make it rain? You've not heard of cloud seeding, have you? No, we don't have the power to control the weather locally, because that involves some truly massive amounts of energy. Thing is, on a global scale, humanity throws out truly massive amounts of energy. How much?

    Everyone knows of the Mount St. Helens eruption from 1980. That eruption was fairly large (though not that large, sure): it released 24 megatons of energy in total. In 2008, humanity consumed almost 144,000 TW-hours of energy. That's 5000 St. Helens eruptions every year, or 14 eruptions per day. We consume INCREDIBLE amounts of energy, yet you believe that our exhaust fumes cannot possibly affect the climate? Volcanoes are known to be able to, though!

    Note that this isn't meant to be a scientific proof or anything of the sort. You just seem to be unaware of the scale to which humanity has developed. Yes, we are most certainly able to affect the planet on a global scale, and that includes global warming. If you need another example, I'd just point at what global thermonuclear war would've done to the planet and leave it at that.

    Oh, and you know what's one of the big flaws in your argument? There can be many causes for one consequence... It's well accepted that there are natural cycles of cooling and warming, but that doesn't preclude that other factors can also contribute to the global temperature, like humans. For someone so quick to throw out the tired old meme of logic "correlation does not mean causation", you sure seem fine with making major logical faults when they suit your perspective.

  47. Must be getting old by mdsolar · · Score: 1

    I was reaching for revolutionary opinions but could only get the benign shelf....

  48. Re:Beyond what humans can do by Kythe · · Score: 1

    The great thing about science and scientific predictions: in the end, whether it's right or wrong doesn't depend upon your political biases.

    --

    Kythe
  49. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    The site has a science bias. It publishes articles written by scientists. Obviously this doesn't play well for those interested in the various narratives spun by Watts Up with That.

  50. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Global warming has affected all continents, oceans, etc. - very powerful

    Yes. Just like humans. We've affected all continents, and all oceans.

    Humans can't even make it rain or change the weather locally. Anyone who thinks they can affect the whole world this much is a moron or shill for some environmental group.

    Except we can make rain and change the local weather. You're probably in a locally air-conditioned environment right now. There are billions of others in the same situation. That's a MASSIVE change in local weather in the aggregate. Nobody WANTS to deliberately do it on the Macro-scale, just like nobody wants to dam the straits of Gibraltar, but it could be done. And arguably, the Dust Bowl was a result of doing it unintentionally, by undesirable methods recognized and since corrected.

    Global warming exists. Anyone who denies that is also a moron. But it's certainly not manmade. To all you science people, correlation does not equal causation. How else do you explain the many periods of warming and cooling in the past long before humans even existed??

    How do you explain the difference between a human being starting a fire, and one started naturally? They exist, don't they?

    I rest my case before the nuts here censor my message.

    You need to stop hanging out with squirrels man.

  51. This day in Slashdot history... by Anonymous Coward · · Score: 0

    I can't help but notice on this day in slashdot history there was an article posted in 2004 about how outsourcing is good for you. Likely 10 years from now we'll all be laughing just as hard at this 2014 article about how the world is ending due to climate change.

  52. Re:Beyond what humans can do by FireFury03 · · Score: 4, Insightful

    single average-sized car puts out 4.75 metric TONS of carbon every year

    That sounds an unreasonably high figure.

    Petrol weighs about 737g / l, so 4750Kg of petrol is 6445 litres.
    Wikipedia says the carbon content of petrol is up to about 85%: http://en.wikipedia.org/wiki/P...
    So 6445/0.85 = 7582 litres of petrol contain 4.75t of carbon.
    Wikipedia suggests average fuel economy is somewhere around 5l / 100Km: http://en.wikipedia.org/wiki/F...
    7582*100/5 = 151640Km - I'm pretty sure that the average car doesn't travel 152Mm/year!

    Lets assume you're talking about tons of CO2 rather than tons of carbon.
    Apparently we multiply litres of petrol by 2.331 to get Kg of CO2 emitted: http://www.carbontrust.com/res...
    So 4750/2.331 = 2038 litres. At 5l / 100Km, this gives us 2038*100/5 = 40760Km - ok, a vaguely more reasonable figure.

    Apparently the average company car does around 30,000Km/year and the average private car does about 12,000Km: http://www.racfoundation.org/m...

    So the average is going to be well under 41Mm and around an order of magnitude less than the 152Mm you claimed!

    I'm certainly not saying that climate change is nothing to worry about - I think it's a big problem and whether or not you think it's man made, dumping vast amounts of crap into the atmosphere can't possibly be a bright idea. But I really wish people wouldn't just invent bogus "facts" to back up their arguments - the arguments should stand up for themselves, if you need bogus data to prop them up then you've got something really badly wrong somewhere.

  53. Lets Regulate all Carbon Life forms by Anonymous Coward · · Score: 0

    If we can just get control over every carbon life form on the planet and pass broad sweeping regulations to control all c02 output we might have a chance. We will need to create these systems of "force" to serve the greater good and once again avert the end of the world. I propose we create 10 new government regulatory agencies that will employ 10,000 specialist on climate change. These specialist much each pass 10 new policies per month that effect every aspect of our daily "American lives". When we lead by example the rest of the world will start caring..........

    Or we could just populate Mars as a insurance policy, oh wait I just read the Mars polar icecaps are melting at a unprecedented rate along with every other planet in the solar system.........

    1. Re:Lets Regulate all Carbon Life forms by Layzej · · Score: 1

      Oooooooor... How about a revenue neutral carbon tax? We could tax the carbon at the port of entry. Since it is revenue neutral we would want to lower income or sales tax - things we ought to be trying to encourage rather than tax.

  54. Re:Beyond what humans can do by Kohath · · Score: 1

    How many times have doomsday predictions been proven correct?

  55. Re:They're getting desperate... by Anonymous Coward · · Score: 1

    Yes, thousands of scientists from around the world have successfully orchestrated a massive conspiracy in order to reduce fossil fuel consumption. They've managed to do this in the face of the fossil fuel industry being one of the largest and most profitable industries on the planet. They've managed to hide all evidence of this conspiracy and prevent a single defector from coming for with personal knowledge of this conspiracy. Even dissenters within the field of climate science know nothing of the conspiracy, which means the conspiracy was able to predict who would be willing to join with 100% accuracy.

    Here's the thing, if they can do this I'm absolutely terrified of their capabilities. They've put to shame every single intelligence agency, terrorist organization, and criminal cartel on the planet. And all they want is for us to speed up the transition from fossil fuels, which we'll have to do anyway as they'll eventually run out. So I say give it to them, before they start applying their skills more directly.

  56. Impacts by Anonymous Coward · · Score: 0

    to quote George Carlin: "The Earth is fine - the people are f*cked."

  57. Re:Beyond what humans can do by FrozenToothbrush · · Score: 2

    Denier! Denier! Everyone point and make an angry face!

  58. Irreversible? by PPH · · Score: 0

    Well then screw it. I'm fueling up the SUV and towing the ski boat down to the lake to enjoy these last few years before The End Of The Earth.

    --
    Have gnu, will travel.
  59. Fear, Uncertainty, and Doubt by jackspenn · · Score: 1, Insightful

    I haven't see this much FUD since Eric S Raymond published the Microsoft Halloween Documents in 1998.

    Which, is interesting given that the temperature recordings since 1998 have been flat and every climate model projection for that period has been wrong, and "scientists" are now trying to stuff the missing heat from failed computer models into the only place they can, which is similarly flawed computer models with "heat" trapped deep in the oceans, orginally, convient because there was limited historic data, but now this flaw is turning out to be equally untrue. Plus, the whole CERN Climategate docs.

    --
    Respect the Constitution
    1. Re:Fear, Uncertainty, and Doubt by Anonymous Coward · · Score: 0, Troll

      SHHHH! Don't point out facts that are not debatable or it will turn in to more of the "IRREVERSIBLE!" or "PUSHED TO THE BREAKING POINT" or "IF WE DON'T ACT NOW WE WILL ALL DIE" mantra from those making a living off of climate change. Do dig in to their "97%" number either. It might not actually make sense then they will claim you are "A rich person that makes money off of coal and gas!!!" or even better "A Koch brothers supporter!"

    2. Re:Fear, Uncertainty, and Doubt by Jane+Q.+Public · · Score: 1, Troll

      and "scientists" are now trying to stuff the missing heat from failed computer models into the only place they can, which is similarly flawed computer models with "heat" trapped deep in the oceans, orginally, convient because there was limited historic data, but now this flaw is turning out to be equally untrue. Plus, the whole CERN Climategate docs.

      Did you mean UEA?

      In any case, trying to pretend the heat is "trapped" deep in some ocean is the only desperate move they have left to try to claim their models have any real validity.

    3. Re:Fear, Uncertainty, and Doubt by Layzej · · Score: 0

      In any case, trying to pretend the heat is "trapped" deep in some ocean

      This is bizarre. We've measured a rise in ocean heat content: http://en.wikipedia.org/wiki/O...

      How do you suppose that finding a rise in global heat content amounts to "trying to pretend". Could it be another conspiracy theory? (http://slashdot.org/comments.pl?sid=5452767&cid=47611623).

    4. Re:Fear, Uncertainty, and Doubt by Jane+Q.+Public · · Score: 2

      Who is "we"?

      Yeah, right. So you indirectly cite Levitus as the basis for your argument.

      You'll have to do better than that. The raw data does not show this, unless like the Levitus paper you're willing to draw conclusions from localized data and ignore the rest of the world. Which, it must be said, is a technique warmists are rather famous for. It's a form of lying. Like saying the current drought in California is "climate".

  60. Re:Well, There You Go. by Anonymous Coward · · Score: 0

    While the phrasing may not be great, GP does have a point: whether climate change is a real threat or not, it is most certainly pushed as a reason for increased government interference (as are many other things).

  61. OK, that's it then. by Anonymous Coward · · Score: 1

    Will the last one turn off the lights ?

  62. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    This is the delusional right wing spin on that argument, I know because I've lost a few really gullible older gentlemen in my family to the right wing delusion factory:
    1) Those scientists are funded to do this research so it obviously behooves them to find warming and be alarmist so they can receive more grants and funding.
    2) They are modeling into the future and nobody knows how accurate the models are, you cant predict everything that's going to happen.

    And there was another one that I cant remember that got rattled off at me but I cant remember it. I gave up at that point in the conversation, wrote them off as the delusional idiots they are and convinced myself I'd make sure to go to the polls and try and cancel them out in any election. What's most irritating about it for me is it's mostly old ass (white) people that tune into the right wing outrage factory and they're basically flipping us all the bird on the way out the door.

  63. and what can we do? by nblender · · Score: 2

    Buy another LED light bulb? Buy an electric vehicle? Eat vegetarian?

    Given there are no good alternatives when it comes to voting time, it seems like we're basically along for the ride..

    1. Re:and what can we do? by mdsolar · · Score: 1

      Depends on where you live. In China your vote probably does not do much. In the US, voting for President Obama has set in place a climate policy to cut emissions 83% by 2050. In Canada, there will be an opportunity to pull the country out of climate rogue status coming up. Australia fluctuates based on voting. In Germany, you can vote, but the direction they are taking is already pretty settled. In India, the new PM Narendra Modi has written a book about climate change called "Convenient Action: Gujarat’s Response to Challenges of Climate Change" http://www.narendramodi.in/con...

    2. Re:and what can we do? by Anonymous Coward · · Score: 0

      Have you tried buying pitchforks?

    3. Re:and what can we do? by Anonymous Coward · · Score: 0

      Buy from a low-carbon electricty supplier if you can. That would be renewables or nuclear generation, so Ecotricity or EDF in the UK both have low CO2 per TWh generation figures.

  64. Re:Beyond what humans can do by wiit_rabit · · Score: 1

    4.75 TONS of carbon sure sounds like a lot...
    Based on my best guesses from the Internet (Thanks Wolfram-Alpha), The weight of the Atmosphere is ~5.1 x 10^18 Kg, C02 is approx 395ppm. CO2 fraction is then 2.00 x 10^17 Kg or ~4.7 x 10^13 TONS One percent of that is ~4.7 x 10^11 TONS. So we need approx 10^11 cars to make up 1% of the CO2 fraction. My point, (and I do have one) is that TONS sound like a lot, but the Atmosphere is really BIG. Also 395ppm is not really a lot of CO2 as compared with historical evidence.

  65. Re:Interesting slam of Judith Curry by Lumpy · · Score: 1

    I want to know what the Witch Doctors of New Orleans think about it. We all know that that is the real authority on what is happening in the world.

    --
    Do not look at laser with remaining good eye.
  66. Stay calm by Anonymous Coward · · Score: 0

    So, now that we've determined that climate change is inevitable, can we stop worrying and learn to love the bomb? To paraphrase my contemporaries: WOO! YOLO!...WOO!

  67. Re:Beyond what humans can do by Lumpy · · Score: 1

    " can you please tell me how we are going to deal with all of those people displaced by this natural phenomenon?"

    That is all a part of his trickle down economics on how the wealthy's cast off cash will flow down to solve that problem, we just need to give the wealthy a LOT more money.

    --
    Do not look at laser with remaining good eye.
  68. Re:Beyond what humans can do by Areyoukiddingme · · Score: 1

    A single average-sized car puts out 4.75 metric TONS of carbon every year

    Bullshit.

    Density of gasoline: 0.73 kg/L
    Typical gas tank capacity: 57 L
    Typical number of fillups per year: 52

    0.73 * 57 * 52 = 2200 kg/year.

    Gasoline contains various different organic molecules starting from hexane and running up through decane. Hexane is C6H14, so the carbon makes up 84% of the mass. Octane is C8H18, so the carbon makes up 80% of the mass. Call it 82%.

    A single average-sized car emits 1800 kg of carbon every year. Less than 2 metric tons.

  69. Re:Beyond what humans can do by MightyMartian · · Score: 1

    How many actual scientific doomsday predictions can you think of?

    --
    The world's burning. Moped Jesus spotted on I50. Details at 11.
  70. Get China on the phone by NotQuiteReal · · Score: 2

    China accounts for 42% of the carbon emissions. US and Europe combined are 20%, so even if "the rich" country bankrupted themselves trying, they can't solve the problem alone.

    --
    This issue is a bit more complicated than you think.
    1. Re:Get China on the phone by mdsolar · · Score: 1
    2. Re:Get China on the phone by Alioth · · Score: 1

      China is our off shored CO2 producer. China only produces this much because of Western demand for their goods.

    3. Re:Get China on the phone by Anonymous Coward · · Score: 0

      F**k China. Earth killer.

    4. Re:Get China on the phone by Anonymous Coward · · Score: 0

      Oh please. That link blatantly redefines what "carbon emissions" are, purely in order to get the US off the hook and paint China as the bad guys. (Similar story with grouping "US and Europe" together, when their emission patterns are hugely different.)

      Newsflash, China has approximately twice as many people as the US and Europe combined. Even if we take this bullshit measurement as valid, they're only beginning to catch up in emissions per head.

    5. Re:Get China on the phone by Anonymous Coward · · Score: 0

      they're only beginning to catch up...

      duh - that's why the future relies on their cooperation.

    6. Re:Get China on the phone by Squidlips · · Score: 1

      How about a stiff import tariff / carbon tax on all the junk imported from China?????

  71. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 2

    The site has a science bias. It publishes articles written by scientists. Obviously this doesn't play well for those interested in the various narratives spun by Watts Up with That.

    You mean science like the Cook "97%" survey they supported and cited, which was such a laughable parody of responsible statistics that a middle-schooler could show it to be invalid?

  72. Re:Well, There You Go. by crywalt · · Score: 1

    You do realize there's almost no socialism anywhere in the world at this point, right? Even China has given it up.

  73. Re:Interesting slam of Judith Curry by Layzej · · Score: 0
    I'm not too interested in you conspiracy theories (for instance your wacky theories on Obama's birth cirtificate: http://slashdot.org/comments.p...).

    The 97% consensus paper has been replicated numerous times. The scientists own evaluation of the reviewed papers found an even stronger result. Just last month another replication was published: http://pubs.acs.org/doi/abs/10...

  74. Dont worry by Anonymous Coward · · Score: 0

    Relax, the market will take care of it!

  75. Leaked? by kick6 · · Score: 2

    Really? Climate change groups have secret reports that need to be leaked because people are just DYING to get the details? Something about this concept seems...well complete bullshit.

    1. Re:Leaked? by Anonymous Coward · · Score: 0

      Actually the article indicates that this report is waiting to be vetted by the various governments in question before it's released to the general public. I, for one, would be very interested in seeing exactly how the final report varies from the leaked version.

    2. Re:Leaked? by Anonymous Coward · · Score: 0

      Hey U.N. – show us your tipping points!
      http://wattsupwiththat.com/2014/08/27/hey-u-n-show-us-your-tipping-points/

    3. Re:Leaked? by Anonymous Coward · · Score: 0

      I was snooping around a building (marked 666) and came across a discarded paper. Naturally, being the conscientious person that I am, I picked up the paper and written inside was a note: "Chicken Little was right."

  76. Irreversible? by dfn5 · · Score: 1

    The article's title is "Irreversible Damage Seen ..." and the very first line is "Humans risk causing irreversible and widespread damage ...". Well, which is it?

    --
    -- Thou hast strayed far from the path of the Avatar.
  77. Coal is vegetation, i.e. Trees by Anonymous Coward · · Score: 0

    Respectfully, you have no idea what you are talking about.

    1. You do know that coal is old vegetation right? Left alone not all of the carbon trees absorb gets dumped back into the atmosphere when they decompose. That's how coal came about in the first place! http://www.ket.org/trips/coal/agsmm/agsmmhow.html. Even before that, a forest where there was non before represents a hell of a lot of sequestered carbon in that live vegitation (or visa versa in the destruction case)

    2. We're not talking about the number of carbon atoms here. We're talking about the contribution to global warming. Grass takes in carbon dioxide from the atmosphere. Cow eats grass. Cow farts out methane molecules containing the same carbon atoms the grass took in. While the number of carbon atoms did not change, it's still bad because the methane has a much larger impact on global warming than the same number of carbon atoms in the original from of carbon dioxide.

    1. Re:Coal is vegetation, i.e. Trees by HornWumpus · · Score: 1

      Only relatively rare conditions sequester carbon on geological time scales. The Amazon rainforest is not sequestering carbon. The rare example that is sequestering carbon that springs to mind is the Okefenokee swamp.

      --
      John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
    2. Re:Coal is vegetation, i.e. Trees by AaronW · · Score: 1

      There also was a long period of time where fungus and bacteria were unable to digest lignin so dead plant material would just accumulate. This is what formed most of our coal. Only later were fungus and bacteria able to evolve mechanisms to break down and use the lignin.

      While it is possible to sequester plant based carbon, it would require heating it to charcoal and burying it in order to prevent it from being recycled back into the atmosphere.

      http://www.scientificamerican....

      --
      This post is encrypted twice with ROT-13. Documenting or attempting to crack this encryption is illegal.
    3. Re:Coal is vegetation, i.e. Trees by Stuarticus · · Score: 1

      How much carbon does it support compared to bare rock?

      --
      If you think someone isn't free to have a different definition of "freedom" you may be a tyrant.
  78. I've got mod points... by Flavianoep · · Score: 0

    and I'm going to mod down everyone of those Climate change-deniers!

    --
    Linux is for people who don't mind RTFM.
    1. Re:I've got mod points... by Flavianoep · · Score: 0

      D'oh!

      --
      Linux is for people who don't mind RTFM.
  79. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    You really may want to check some other data on this.

    Shows the math used:

    http://www.epa.gov/cleanenergy/energy-resources/refs.html

  80. Reality by Anonymous Coward · · Score: 0

    And still, nothing will change. Millions of people will die horribly due to flooding, lack of food, lack of clean water and the wars that will become a near constant thing in the next century. Only a small, tiny percentage of the population will have access to the necessary resources -- and that will not change.

    Let's be honest here, we -know- humanity. We called it down on ourself and sure as hell aren't going to fix it. This handbasket has long ago set a course for the firey regions and almost all of us are in it.

    Pessimistic? Sure. Negative? Assuredly so.

    But above all, realistic.

  81. I miss when /. was technical... by Anonymous Coward · · Score: 0

    rather than this Republican celebration circle-jerk. We get it. You're happy there is irreversible damange. Just stop shoving it in our faces and go celebrate in private.

  82. Perhaps, but answered very poorly by Anonymous Coward · · Score: 0

    TL;DR - We lack the scientific knowledge to make accurate long-term predictions of the climate.

    First, you might reference AR5 rather than AR4.

    Your points have nothing to do with the IPCC scenarios, as they rely on hypothesized positive feedback mechanisms that increase warming. We've already seen most of the greenhouse effect warming from carbon dioxide. Meanwhile, these (non-predictive!) model scenarios seem to keep getting worse, while important factors are tied to carbon dioxide or hand waved away. We can't even measure and explain all of the natural factors, so claiming to have separated artificial ones is difficult.

    There is only one natural energy input - the sun, which has been repeatedly disclaimed as irrelevant, even as the modern maximum has ended.

    Meanwhile, there is far more research to be done on the climate effects of the dread chemical dihydrogen monoxide. Not only is it the most potent greenhouse gas, there remain significant scientific questions about cloud formation, which is not modeled with any accuracy.

    The climate will continue to change, regardless of our (in)action. So long as the current homeostasis continues, as it has for the duration of the holocene, humanity will be fine. Nothing we've seen so far has left the historic bounds of natural variability. However, remember that natural variability says that this interglacial will eventually end, so we'd damned well better learn enough to maintain it with geoengineering before the next ice age drags down civilization. That's the only scientifically feasible doomsday scenario, not runaway warming.

    Perhaps you should read the 97% consensus paper that is so heavily (mis)quoted. There's a lot of great science on climate, and more every year, but there is no consensus of looming disaster, except from those who wish to use it as an opportunity to force changes in society.

  83. Future Schlock by fyngyrz · · Score: 1

    Is it sane, given foreknowledge of your own demise and the power to avert it, to charge full-steam-ahead toward that demise

    It's not my demise; it is the demise of others, sometime in the future. I fully expect to live out the rest of my life comfortably. I rather suspect that's the same set of conditions you face when you describe these worst case scenarios to others. Some of us are sensitive to the woes of future persons, some of us are not. But it's always at least one step removed from today's reality.

    In the USA, just look at the number of people who would let the financially low performing suffer the slings and arrows of disease and injury without any particular concern or guilt; you can measure that directly by the resistance to the ACA, which remains substantial, even though it's working out pretty well if you actually take the time to look at the numbers. When people don't concern themselves with the other people in town, who are there and suffering right now, isn't it a bit optimistic to expect them to concern themselves with some abstract, unknown set of people who will exist after most of them have died anyway?

    You're better off looking to technology to solve this than compassionate outlooks among the citizenry.

    I'm going to go back to watching the news now, where I can learn more about us shooting up Afghanistan for no particular reason other than to prop up our MI complex, as we've kind of worn out Iraq now. You know, because we care. We'd be in Africa "helping" them too, you know, if we needed more income. I'm sure their day will come, though. Both Africa and South America are deep future market resources for our weapons manufacturers. Caring. It's what we do!

    --
    I've fallen off your lawn, and I can't get up.
  84. Next ice age not allowed by mdsolar · · Score: 1

    As pointed out by James Hansen in his book "Storms of my Grandchildren" it would take a small factory dumping chloroflorcarbons into the atmosphere to prevent the next ice age. It is trivial.

    1. Re:Next ice age not allowed by greg_barton · · Score: 1

      Yes, he also advocates for nuclear power. Hansen is awesome.

    2. Re:Next ice age not allowed by mdsolar · · Score: 1

      Wrongly so however. http://www.rmi.org/Knowledge-C...

    3. Re: Next ice age not allowed by greg_barton · · Score: 1

      Wow, you are a complete Lovins acolyte. How does it feel to be only out for your own gain while ignoring the needs of the planet?

    4. Re: Next ice age not allowed by mdsolar · · Score: 1

      When you understand the math, you'll understand that you are mistaken.

    5. Re: Next ice age not allowed by greg_barton · · Score: 1

      Ditto.

      But, as you freely admit, your math is influenced by $$$.

    6. Re: Next ice age not allowed by mdsolar · · Score: 1

      Precisely, and Hansen has not looked at the way the poor economics of nuclear power take away opportunities to cut emissions faster and more completely.

  85. How about... by Anonymous Coward · · Score: 0

    ...if you concoct a way to kill all the ISIL assholes while mitigating climate change? That might win some support.

  86. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    I'm not too interested in you conspiracy theories (for instance your wacky theories on Obama's birth cirtificate: http://slashdot.org/comments.p...).

    Ad-hominem at its best. Of course that's what I have learned to expect from "Laysej", otherwise known as "khayman80". Someone who seems actually proud to be running sock-puppet accounts on Slashdot. So... what does "conspiracy theory" have to do with one person's bad paper? Are YOU suggesting that there is some kind of "conspiracy" going on? I didn't. In fact I have several times described here on Slashdot how a situation can look like "conspiracy" to some people without there actually being any conspiracy. So the only person suggesting ANYTHING about "conspiracy" here is you.

    The 97% consensus paper has been replicated numerous times.

    Hah! Has it really? By whom? Are you referring to Naomi Oreskes, who was also blatantly guilty of selection bias?

    This "97%" figure came from a selected subset of the respondents, who were only 29% of those surveyed. And the subjective selection process was not even remotely valid or even scientific. Objective interpretation of the same data came up with a figure more like 0.5%.

    Cook's paper is an even bigger joke than Oreskes' paper was. And so is the work of Cook's friend and collaborator Lewandowski.

  87. Re:Interesting slam of Judith Curry by BasilBrush · · Score: 1

    You're a birther? Fuck me, you're an imbecile. I've lost what little respect I had for your opinions. You have to be insane or a deliberate liar to be a birther.

  88. Re:Beyond what humans can do by Layzej · · Score: 1

    If we are optimistic about a technological solution, wouldn't it be in our interest to move forward with those solutions instead of continuing to get our energy from burning stuff?

  89. Re:Interesting slam of Judith Curry by BasilBrush · · Score: 1

    Shut the fuck up you imbecile. If you can't even accept a birth certificate your head is so far up your own rectum no one can hear you.

  90. Cats by fyngyrz · · Score: 1

    Nah, it's almost certain to be big cats. Perfect apex predators. They can deal with heat, cold, wind; they can kill anything, climb like crazy, swim, they're fast as hell, stronger than just about anything, they instinctively use available terrain features for cover and shelter, they come equipped with deadly weapons, and they're very smart and wily. Common mutations already include thumbs and other extra digits, and they have a short enough breeding and maturation cycle that populations can recover in a very short time span, given only that mankind isn't around to defeat them using already developed technology.

    --
    I've fallen off your lawn, and I can't get up.
    1. Re:Cats by jbmartin6 · · Score: 1

      I think apex predators won't be able to position themselves as overlords. How would they recruit allies? There's just not enough cooperation among these sorts.

      --
      This posting is provided 'AS IS' without warranty of any kind, implied or otherwise.
    2. Re:Cats by VorpalRodent · · Score: 1

      As Red Dwarf proved pretty clearly, everything in your premise is completely wrong. The Cat was none of those things.

      --
      Take it to the limit, everybody to the limit, come on, everybody fhqwhgads.
    3. Re:Cats by fyngyrz · · Score: 1

      All Red Dwarf proves -- again -- is that the English have really low standards when it comes to comedy. Ok, you did produce Python, admittedly some of the best comedy ever, but it appears that was a fluke. You're responsible for Dr. Who, and I'll never, ever forgive you for that.

      --
      I've fallen off your lawn, and I can't get up.
    4. Re:Cats by riverat1 · · Score: 1

      So you're saying our successors will be Kzinti?

  91. Again? by Anonymous Coward · · Score: 0

    If they say this often enough someone might eventually believe it.

  92. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    "Laysej", otherwise known as "khayman80"

    Another conspiracy theory?

  93. Re:Beyond what humans can do by ChrisMaple · · Score: 1

    Probably a couple dozen, evenly split between nuclear holocaust and enviro-catastophes, and that's just limiting it to those whose due dates are already past. Nothing interesting happened. (Calling them scientific is a bit of a stretch, however.)
    There are plenty of religious ones, too.

    --
    Contribute to civilization: ari.aynrand.org/donate
  94. China and India by Anonymous Coward · · Score: 0

    I am sure that they are laughing at this one...

  95. Re:Beyond what humans can do by Anonymous Coward · · Score: 1

    Your calculations are probably overly optimistic by assuming 5L/100km, which while a reasonable manufacturer's estimate for the newest passenger cars, doesn't reflect the "average" efficiency of the fleet of variably-aged vehicles on the road, or the choices that people make when choosing their vehicles. Those "fleet" numbers tend to float around 1.5 to 2x as bad, depending upon country and whether or not you strictly include only passenger cars rather than "light trucks" that include SUVs and other popular passenger vehicles. "Your mileage may vary", a lot, but the averages are reasonably well established.

    Some calculations incorporate more than just CO2 emissions because, of course, cars emit more than CO2. They include things such as NO2 and even apparently some methane, which can be expressed in terms of their greenhouse gas effects too. It would be CO2 equivalent rather than strictly CO2, which might be another source for a discrepancy.

    In any case, you may be interested in this US EPA page which estimates the average output at exactly the 4.75 tonnes/year/vehicle that the previous poster suggested. All the data that went into the calculation is outlined on that page, although the mix of Imperial and metric units makes it a bit hard to follow without doing some conversions along the way. Calling it 4.75 tonnes/year for *cars* would be wrong, because it includes more than cars. It includes all those SUVs, light trucks, and other common passenger vehicles that get significantly poorer mileage.

  96. No conspiracy is needed when by Anonymous Coward · · Score: 0

    You have group-think. The problem gets even larger when lots of money is on the line on one side of an issue; scientists supporting global warming claims are getting BILLIONS of dollars from governments, think tanks, and wealthy donors and those at universities are getting tenured positions. Scientists opposing global warming caims are not getting any of these things, and have even recieved death threats against not only themselves but also their families.

  97. Damage or Change? by Anonymous Coward · · Score: 0

    There is no mechanism to trap carbon underground anymore. The old mechanism, where trees grow then fall over and don't rot away is no longer an option. As millions of years ago bacteria and fungus evolved to break down the tough cell walls of trees and woody plants. All that coal we pull out of the ground is a one way trip. One way, unless we create some rather cutting edge technology and invest a lot of energy (and money) into the process of sequestration.
    It would be far simpler to ban all fossil fuels today. Sure, people will starve when the farms can't be plowed. But it's a reversible problem. Having many farms blow away in drought and sand storms is going to starve more people long term.
    Obviously banning fossil fuels would have consequences, it would be a hard road initially. But we would survive it.

    But no, let's all slide into oblivion together. That is the more comfortable path.

  98. Re:Interesting slam of Judith Curry by Anonymous Coward · · Score: 0

    The press release for Mr. Obama's books even stated that he was born in Kenya. You would think an astute scholar would have noticed a discrepancy about his birthplace and have it corrected. He knew he could play it for all it was worth, and suckers would believe any controversy was his opponents' fault. But then, I expect no less from you than complete lack of thinking skills on any subject related to your religion.

  99. Re:Beyond what humans can do by ColdWetDog · · Score: 1

    Sounds good! Where do I sign up?

    Oh. Wait.

    --
    Faster! Faster! Faster would be better!
  100. Re:Beyond what humans can do by LWATCDR · · Score: 1

    Cars are a red Herring for carbon emissions. It is Electricity that is the big issue.
    The simple solution is to replace coal with nuclear, and wind backed by natural gas peaking plants.
     

    --
    See my blog http://ilovecookes.blogspot.com/ for light hearted technical information.
  101. Good News Everybody! by Anonymous Coward · · Score: 0

    Now that we know it is irreversible, there is no longer ANY reson to do cap-and-trade, or any other tax-and-regulate scheme to save us all from AGW. In fact, we should shut down all the climate study activities immediately and re-direct all that "green" money into something more practical and actually important: developing the tech to allow people to live with the effects of the (now admitted to be unavoidable) consequences.

    Time to re-open the coal mines and fire-up those power plants that give consumers the most energy for their dollars! We need the increased economic activity. We need to shift the money from studying carbon sequestration, carbon emissions, etc into studies of improved dams, dikes, locks and levies, wildfire fighting capabilities, and many other things that (unlike all the "green" garbage) are actually always useful to people all around the world in all climates due to basic weather instabilities.

  102. Re:Interesting slam of Judith Curry by Curunir_wolf · · Score: 1

    This isn't "Watts up with that" where there's a financial payment for having the right opinions.

    Actually, it operates on exactly that principal. The owners and operators of the site are financially dependent on the ideas espoused in the articles, and are in fact publicity whores with more interest in popular opinion that truth.

    --
    "Somebody has to do something. It's just incredibly pathetic it has to be us."
    --- Jerry Garcia
  103. IPCC members by mod+prime · · Score: 0

    Your source does not say that IPCC members are not scientists, as that would be an obvious lie. They are scientists and associated academics. Also you should try finding better sources if you seek to be persuasive.

    1. Re:IPCC members by mi · · Score: 3

      Your source does not say that IPCC members are not scientists, as that would be an obvious lie.

      A person may remain an academic and retain various titles, but he stops being a scientist when his research is done not to advance knowledge, but to confirm an already held conviction. Perhaps, you did not read to this text:

      A panel of climate experts are telling the House Science Committee that politics often gets in the way of good science at the Intergovernmental Panel on Climate Change (IPCC), as well as in the U.S. government’s own climate research.

      Climate scientists and researchers who dissent even slightly from the talking points of politicians and environmental groups are intimidated and ostracized, said one congressional witness. Politics, the witness said, takes a lead role over science in the study of global warming.

      --
      In Soviet Washington the swamp drains you.
    2. Re:IPCC members by mod+prime · · Score: 1

      No - in such an environment when they are producing reports they are not performing scientific studies, but a person that does this does not cease to be a scientist. There may be some people in the IPCC who have ceased original research and may not be regarded as a 'scientist' if you want to be exclusionary, but that is not true of all of them.

  104. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    No, I am not a "birther", as I have explained many times here on Slashdot, in some detail.

    Do you always believe what other people say, as long as it fits your pre-conceived notions?

  105. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    Another conspiracy theory?

    No, but I find it very interesting that both of you have the same mannerisms, you're the only two who have written certain things to me, or used certain phrases, and usually about the same subjects. Not to mention the often "fortuitous" timing of your comments.

    If you're not a sock-puppet, then you're a clone. And that's very far from a compliment.

  106. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    I find it very interesting that both of you have the same mannerisms...

    You don't just "find it very interesting". You have jumped to the conclusion that several people who disagree with you must all be the same person. That's just nutty.

  107. Well good!!! by Anonymous Coward · · Score: 0

    Now it's irreversible and already done, so can we stop arguing and just get back to business and do away with nonsensical carbon offsets and so called "climate summits"?

  108. Well of course. by Anonymous Coward · · Score: 0

    Once the sky has fallen, you can't put it back up.

  109. Jane/Lonny Eachus "isn't" a birther by khayman80 · · Score: 1

    ... he's never sorted out that mess about his birth certificate, either. I know that lots of amateurs claimed "fake"... but lots of well-respected professionals have claimed "fake" since then, and no answers have been forthcoming. And probably never will. [Jane Q. Public, 2012-11-08]

    Genuine, well-renowned graphics experts have examined Obama's supposed birth certificate, and it's definitely a fake. It's not even a very good fake. [Jane Q. Public, 2012-11-08]

    Obama isn't even eligible to be President. His birth certificate (I'm not talking about the first flap and all the amateurs) is fake. Verified later by actual graphics experts. And not even a very good fake. [Lonny Eachus, 2012-11-07]

    ... There is actually quite a bit of very strong evidence of fakery. Having said that: I know of no proof that Obama himself was necessarily behind any of it. [Jane Q. Public, 2012-11-09]

    That isn't "conspiracy theory", it has been proved beyond doubt. Not saying HE did it. But somebody did. [Lonny Eachus, 2012-07-10]

    ... I also have not claimed that Obama was directly involved in the forgery. But one must ask: why would the White House post a fake? And why would they then take it down if it were NOT a fake? ... [Jane Q. Public, 2012-11-10]

    Somebody is lying. I'm not claiming, myself, that it's a forgery. But it HAS been altered. Which (if it were genuine) would be STUPID. [Lonny Eachus, 2011-05-03]

    ... EVERY OTHER piece of documentation that Obama has produced to support his citizenship (like his selective service registration) have overt signs of "forgery" written all over them. ... [Jane Q. Public, 2013-08-15]

    ... the "birth certificate" released by the White House last year is a fake. And also Obama's Selective Service card. [Lonny Eachus, 2012-07-02]

    One really has to ask: why is it that ALL available documentation of Obama's citizenship appears to be forged? And before you argue with me: yes, there is A LOT of real evidence, and it ALL points to forgery. Explanations offered so far don't wash. [Lonny Eachus, 2013-07-21]

    Those of you who know me may remember that I downloaded a copy of the original birth certificate file myself, and personally confirmed [Lonny Eachus, 2012-07-02]

    I got the cert. online myself and looked. Alteration was OBVIOUS. Why Whitehouse would offer it as proof of anything is a mystery. [Lonny Eachus, 2013-07-21]

    ... I am certain because I downloaded a copy of it and examined it myself, layer by layer. I did read analyses on the Internet, but I confirmed the truth of some of them myself. ... [Jane Q. Public, 2014-07-31]

    1. Re:Jane/Lonny Eachus "isn't" a birther by Jane+Q.+Public · · Score: 1

      As I've explained many times before: having issues with certain documents does not equal claiming that Obama was born elsewhere.

      Further, it turns out that you are ignorant of reasons I've turned up (and mentioned before) why such alterations might actually have perfectly legitimate reasons behind them. No conspiracy necessary.

      But no; you ignore those and only post those things, out of context, in order to make me appear to be a "birther" when I have explained to you several times that I don't claim to have any idea where Obama was born, and don't claim that those documents are evidence that he was born elsewhere. Hint: rabidly claiming that Obama was born elsewhere is what makes somebody a "birther". I don't fit that category.

      You take comments out of context that seem to support your argument, but when taken IN context, together with other statements I have clearly made, the "birther" claim is shown to be false.

      And you know this, because I have explained it to you repeatedly. So your tirade above is nothing more than a sneaky form of lying.

      And it's really interesting how you're always there to jump in and defend "Laysej". Clone? Sock-puppet?

  110. Now add nukes by PeterM+from+Berkeley · · Score: 1

    Add nuclear weapons to the massive societal disruptions you mention, and you might indeed have a situation that's unsurvivable by humans as a species....

    --PM

    1. Re:Now add nukes by blue9steel · · Score: 1

      That depends on the size of the nuclear exchange. Modern nukes are airburst, low radiation weapons (in comparison to the old style ground impact weapons). A major exchange could pretty easily mean the end of our current technological civilization but one big enough to actually wipe out all human life is pretty unlikely.

  111. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 0

    Shut the fuck up you imbecile. If you can't even accept a birth certificate your head is so far up your own rectum no one can hear you.

    Yes, we've observed you playing the "La la la la, can't hear you" game for quite some time now.

  112. Capitalism means never having to think ahead... by Anonymous Coward · · Score: 0

    about anything but money. It's a system of conversion of resources to Wal-mart quality goods and services, plus some actual good stuff for the 1%.

  113. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Yes much like the libs that blame everything on AGW. "Extreme" Weather? AGW!!! Increased disease? AGW!! Racial tensions? AGW!!!!!

      How can anyone take someone serious that say weather is not the climate but "extreme weather" is a result of climate change? Yes, I know all the bullshit that surrounds that little theory, but why they in a debate when a person that believes in AGW and touts the science of it all, ends debate when you use science to poke hole in the theory?

      Throw in the democrats programing the lemmings to spout over and over "it's the Koch brothers fault" to everything then it doesn't take a Rhodes Scholar to figure out the scam of it all. It's all about money. Headline like the one to this story keep the dollars flowing.

  114. Good! by Anonymous Coward · · Score: 0

    Now the GW pansies can STFU and we can move on with our lives, knowing that any attempts to save us are futile and a waste of money. Me, I'm gonna go cut down a tree and drink a cold brew in celebration.

  115. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    You don't just "find it very interesting". You have jumped to the conclusion that several people who disagree with you must all be the same person. That's just nutty.

    Really? Can you point out where I have said this to other people? Hint: no, you can't, because I haven't. You're the only one doing this.

  116. Re:Interesting slam of Judith Curry by BasilBrush · · Score: 0

    Do you always believe what other people say, as long as it fits your pre-conceived notions?

    khayman80's links are to your own posts, claiming Obama's birth cert to be a fake.

    Of course it may be that you no longer belive in the conspiracy theory you used to expound. But denying it just makes you a liar. And reflects on the nonsense you post on other topics, such as AGW.

  117. math err? Re:Beyond what humans can do by Fubari · · Score: 1

    Wikipedia says the carbon content of petrol is up to about 85%: http://en.wikipedia.org/wiki/P... [wikipedia.org]
    So 6445/0.85 = 7582 litres of petrol contain 4.75t of carbon.

    I'll start by saying thank you for the analysis; that was thought provoking.

    The numerator above seems off: what is 6445 ?

    For the weight of a big tub of petroleum containing 4.75t carbon, I think you'd have:
    4.75 tons of carbon / .85 = 5.938 tons of petroleum.

    To see how many Liters of petroleum that would be, we get:
    5,938 Kg of petroleum / ( .737 Kg/L ) = 8,057 L.

    Using that average fuel economy of 5L/100Km yields a range of
    8,057L / ( 5L/100Km ) = 1,611 / (1/100km) = 161,100 Km
    (Or 100,040 miles for our readers in Burma, Liberia and the United States.)
    Which is indeed a LOT of driving in one year.

    The oracle of Yahoo Answers suggested that 19,000 to 24,000 km (12,000 to 15,000 miles) is a more reasonable average.
    So by carbon weight, yeah... the gp's claim for Carbon is roughly a factor of 8 too high (161,100 km / 20,000 km/yr).

    You raise a good point considering whether the gp meant 4.75 tons of CO2 instead of carbon.
    To do this I think we need to revise our petroleum footprint.
    You'll recall we first derieved that above based on just the target carbon weight.
    We'll take the same approach for our target CO2 weight.

    So... to get 4,750 KgCO2 emissions we need to burn a certain amount of petroleum.
    That works out to 4,750 KgCO2 / (2.331 L/KgCO2) = 2,037.8 L of petroleum.
    Which yields an alleged annual distance of:
    2,038 L / ( 5L / 100Km )
    = 408 / ( 1 / 100Km)
    = 408 * 100Km
    = 40,800 Km (25,351 miles)

    Which is closer, but still off by a factor of at least 2 unless maybe they were talking fleet cars.
    *shrug* don't know... it is hard to tell what point they were making.
    (and yeah, this was much more fun to do over lunch than reading yawn-inducing project requirements :-) )

    1. Re:math err? Re:Beyond what humans can do by FireFury03 · · Score: 1

      The numerator above seems off: what is 6445 ?

      4.75 tons of petrol is 6445 litres. Since petrol is 85% carbon, we can divide the 6445 litres by 0.85 and we get 7582 litres of petrol containing 4.75 tons of carbon.

      For the weight of a big tub of petroleum containing 4.75t carbon, I think you'd have:
      4.75 tons of carbon / .85 = 5.938 tons of petroleum.

      Your answer is wrong: 4750 Kg of carbon / 0.85 = 5588 Kg of petrol. It looks like you divided by 0.80 instead of 0.85?

      5588 Kg of petrol / 0.737 = 7582 litres of petrol.

    2. Re:math err? Re:Beyond what humans can do by FireFury03 · · Score: 1

      Oh yeah, I'll also point out that the original poster's numbers stuck out like a sore thumb before I even looked up the figures: Petrol is lighter than water, so its immediately obvious that 4.75 tons is going to be over 4750 litres (at current forecourt prices, about £6000) and I know I don't buy anywhere close to that amount of petrol each year. Doncha just love the metric system for making such things so obvious. :)

    3. Re:math err? Re:Beyond what humans can do by Fubari · · Score: 1
      r.e. .8 vs .85
      argh :-)

      The numerator above seems off: what is 6445 ?

      4.75 tons of petrol is 6445 litres. Since petrol is 85% carbon, we can divide the 6445 litres by 0.85 and we get 7582 litres of petrol containing 4.75 tons of carbon.

      For the weight of a big tub of petroleum containing 4.75t carbon, I think you'd have: 4.75 tons of carbon / .85 = 5.938 tons of petroleum.

      Your answer is wrong: 4750 Kg of carbon / 0.85 = 5588 Kg of petrol. It looks like you divided by 0.80 instead of 0.85?

      5588 Kg of petrol / 0.737 = 7582 litres of petrol.

  118. Re:Beyond what humans can do by ChrisMaple · · Score: 1

    mostly old ass (white) people

    Translation: Experienced members of the most successful and technologically advanced people on earth. People who, except for their failure in raising the current generation, generally did things correctly.

    --
    Contribute to civilization: ari.aynrand.org/donate
  119. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 0

    The chart showed global ocean heat content from 0-2000m. Other papers show the same result. The article you cited does not say otherwise. Did you even read it?

  120. China is our fault. by bussdriver · · Score: 2

    China makes everything, for everybody. We pay them to do this, part of the reason everybody pays them is because they are willing and we are not. Since we are not immediately and directly impacted by CO2 ...plus it is invisible... we are simply too shallow to realize it harms us indirectly. Just as people shop at Walmart and wonder why their jobs disappeared (forcing them to shop at Walmart more.)

    Is it MY fault I shot you in the foot, when you told me to do it?

    1. Re:China is our fault. by HornWumpus · · Score: 1

      We import more stuff from Mexico then China. We also manufacture more stuff then China (but do it in a highly automated fashion).

      --
      John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
    2. Re:China is our fault. by bussdriver · · Score: 1

      I don't believe it, show me some proof Mexico does more than China. You must be measuring things in a goofy way. I have been looking at the "Made in" labels on everything out of habit since the 90s; I know I'm not the best sample but it does give me enough to notice some changes over time. Japan actually sells us a ton of stuff-- but they have it made in China too... I've seen stats showing we get more from Japan than China, but it was more of a number game because it was still largely Chinese... (because they outsource a lot too.) The polluting stuff nobody wants, everybody outsources that to China. Your Mexican Ford car may have some American labor and more Mexican labor but it probably contains a great many Chinese products... the ones that naturally are cheaper to get from over there. ... how does one measure it? by weight (then the steel gets bias) by number of products (china likely wins) by cost, by margin, by total $ traded? what you pick greatly decides the outcome.

      In the end, I bet you that the CO2 costs migrated to China, just as labor costs push migration

      Hell, about HALF the eggs you eat in the USA come from china! I have info 1st hand from somebody who packs bulk Chinese eggs into USA made cartons for the store-- which say USA on the carton, but the eggs... from China mega farms. Now our organic Chickens are being shipped to China to be hacked up and then back to us! WTF? OIL needs to become more expensive so all this shipping cost turns into the new tariff - physics imposed-- since mankind can't seem to look out for their fellow man.

  121. Lies, Hockey Stick, IPPC are a Rothchilds tool. by Anonymous Coward · · Score: 0

    I love how the Rothchilds use fear to play humanity like fools. First communism, Then terrorism, now climate change. All the inside jobs such as gulf of tonkin, 9/11, and even the latest about how the James Foley video has been completely discredited as a fake by experts (source: https://www.youtube.com/watch?v=AkoSo2PrX8k) - In order to push the new Iraq agenda to justify bringing in thousands of new troops - all agendas pushed by the Rothchilds and their banking cabal friends to enslave humanity and own us. Back to the IPPC though

    First we know for a FACT that all of the "science" of the IPPC was completely discredited. Hockey stick graphs, blatant lies, and in bed with banks/big government.

    Second we know that the entire "Man made climate change" movement was started by Rothschild bankers in order to tax humanity for their "carbon footprint" source: https://www.youtube.com/watch?v=FdqNds9pNuI

    So now that we know the IPPC has been discredited as a complete tool and has nothing to do with science, can we stop referencing them as an actual source on anything scientific? You think slashdot might know better, but I guess not.

  122. Jane/Lonny Eachus "isn't" a birther by khayman80 · · Score: 1

    Hint: rabidly claiming that Obama was born elsewhere is what makes somebody a "birther". [Jane Q. Public, 2014-08-27]

    In True Scotsman style, you can't be a "birther" unless you have rabies. Except you've previously implied that what makes someone a "birther" is claiming Obama's birth certificate is fake:

    I was not a "birther". But I might have been... I thought the President had already proven his birth situation. Apparently not. [Lonny Eachus, 2011-04-29]

    I was not a "birther". But now I am tempted. Apparently there is pretty good evidence that Obama's new birth certificate is fake. [Lonny Eachus, 2011-05-01]

    I have to admit: most of my doubts are now gone. The President's birth certificate (shown so prominently on Oprah) is a fake. [Lonny Eachus, 2011-05-01]

    Now, look. I'm not trying to say that Obama was not born in the United States. However, the preponderance of the evidence does suggest that. [Lonny Eachus, 2012-05-18]

    The publisher's website said Obama was born in Kenya until 2 months AFTER he announced he was running for President. exm.nr/LksgJ9 [Lonny Eachus, 2012-05-18]

  123. Socialist? by bussdriver · · Score: 1

    What you propose is an import tariff and possibly a local carbon tax. This will not work because:
    A) Any new taxes are for socialists. period. no compromise.

    B) Lowering taxes is good but a completely separate issue with raising taxes; you can not link the two no matter how logical. See A.

    C) Tariffs are anti-capitalist. for communists... insert your favorite slander here... The invisible hand of (god) the free market shall not be shackled by tariffs, blasphemer!

    D) The US Chamber of Commerce is always right and they oppose such things (please ignore the Chinese behind the curtain. No, we won't show you our member list.)

    E) Big Government. Government is only for shooting protesters and executing criminals; how dare you socialists demand government interfere with the market! (aka our lobbyists and "donors")

    1. Re:Socialist? by Layzej · · Score: 1

      I don't think that these types of polarizing caricatures are helpful. I believe in a free market solution to this problem. There are many others who also prefer a conservative based solution to this problem. You are dismissing half of the population as science denying yahoos when what you need to be doing is coming together to figure out whether your solutions are at all compatible with ours.

  124. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    Sure. You accused an AC of being a sock puppet of me because she agreed with me... or are you not considering her "other people" because you've already concluded that she's me?

  125. "Skeptics" bring up Climate Engineering? by bussdriver · · Score: 0

    Anybody find it odd that the skeptics (if given enough time) end up talking about Climate Engineering?

    The very science and experts they distrust as part of some left wing global conspiracy are supposed to engineer (use science) to make the planet so they can continue to do whatever they wish? WTF, is it with this new age "science will save us" religious-like belief that people have? So many of them are religious types or superstitious (same thing to me) as well and yet they see no parallels?

    Why do smart people have to continually be saving the morons from themselves? You'd think we'd never have evolved if this was always this case.

  126. Re:Well, There You Go. by HornWumpus · · Score: 1

    Western University Humanities departments, a theme park in Poland and North Korea.

    --
    John McAfee 'It was like that time I hired that Bangkok prostitute; to do my taxes, while I fucked my accountant'
  127. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    In that case you've really got this locked up quite tight. Any evidence contradicting your theory can be dismissed as part of the ruse itself.

  128. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Your mileage is way off. 20km/liter is about 60mpg, which is very rare outside of small hybrid engines. using an optimistic 30mpg as the standard gives about 60,000 miles per year, which I'll agree is still way off. 15,000 miles is more typical in the US at least.

    So using that estimate, it looks like 1.2 metric tons of carbon is more typical for actual emissions. If you factor in the the hydrocarbons used to deliver said fuel and build the car, I'm sure it pumps it up (not 4x though).

  129. Bloomberg? by Anonymous Coward · · Score: 0

    Anything that has Michael Bloomber tied to it is something I assume to be propaganda.

  130. Problem, soils aren't well developed further north by Anonymous Coward · · Score: 0

    A soil ecosystem takes centuries to mature. Good luck farming the rocky glaciated areas that are now boreal forest.

  131. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    How were they supposed to raise us when they were so busy leaving our mothers for other women and buying sports cars because there's no really good male plastic surgery augmentation for what they seek to augment. They simply stood on the shoulders of their fathers, then shirked their responsibility to anyone else in this world later in life in an effort to get theirs.

    But yeah they were obviously damn geniuses, doing things the right way, the lot of them.

  132. multi-stable systems by Anonymous Coward · · Score: 0

    we've almost certainly been pushing the system 'up hill' from a local stable point. If we stopped now, it probably would slip back down to that stable point we find comfortable. Keep pushing until we pass the top of the hill, and it starts sliding down into a completely different stable point -- that's irreversible. I hope we find that new local minimum comfortable.

  133. don't forget the O2 part of the equation by Anonymous Coward · · Score: 0

    Carbon has an atomic weight of about 12, oxygen about 16. You're right about the carbon; the previous post was misrepresenting CO2 numbers as carbon numbers. If we multiply your 41Mm of carbon by (12+16*2)/12 (and thus calculate the CO2 emissions from the C emissions), we get 150Mm of CO2. This probably explains the previous post's error.

  134. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Only problem is that the hole in the ozone layer is not fixed, no-one takes any notice of it anymore because they can make more money out of Global Warming
    http://ozonewatch.gsfc.nasa.gov/

  135. And the Ohio Valley polar bear population by Anonymous Coward · · Score: 0

    has been completely wiped out. The huge lakes left after the retreat of the ice sheets flooded nearly 100,000 square miles.

  136. Re:They're getting desperate... by ChrisMaple · · Score: 1

    The conspiracy is not "to reduce fossil fuel consumption", it's to gain political power. It's not a hidden conspiracy, mostly it's quite open in its actions; it's the motives that are somewhat hidden because few people lusting after political power have any need to communicate that lust.

    And they haven't successfully hidden all evidence: East Anglia.

    --
    Contribute to civilization: ari.aynrand.org/donate
  137. why do we care by cinnamon+colbert · · Score: 1

    obviously, because global warming may lead to something very bad and very $$; if it doesn't lead to these things, not a lot of people will care.
    How do we know global warming might lead to something bad , at least in a quantitative sense ?
    All (all) of our detailed knowledge is from computer programs (climate models) which simulate changes in the future

    However, It is an observed fact (fyfe) that over the last ten years, the surface temp of the earth has not increased as much as predicted by models; the models fail.
    The models also can't reconstruct the last few thousand years (Liu), where we Know what happened.

    This anomaly is the main current argument of denialists (those who think global warming is not occurring, or is not manmade, or is not important) and cause for concern among climate scientists.

    Several attempts have been made to find the missing heat without great acceptance, eg Cowtan (who are not, afaik, climatologists) say that the missing heat is in the Arctic, which is not well measured by instruments.
    It appears that Chen and Tung have found the answer: the earth is warming, but the heat is going into the ocean instead of the atmosphere.

    SO: the models are clearly not accurate even on a 10year time scale.
    so why should we take seriously alarmist views about the future ?
    I guess it is probability: if there is even a X% chance that something really bad could happen, is it worth spending ~ 0.5% of global GDP (~ 850 billion dollars a year) to prevent this possible catastrophre ?

    Me personally, my house is about 5 miles and 200 feet up from the Atlantic Ocean, so global warming is good for me: I get beachfront property......

    Fyfe
    http://hypergeometric.wordpres...

    liu
    http://www.pnas.org/content/ea...

    cowtan
    http://onlinelibrary.wiley.com...

    chen and tung
    http://www.washington.edu/news...

  138. Costs of end of life care by Anonymous Coward · · Score: 0

    Like, if you had gangrene on your arm, and the doctor announces, "I'm sorry, but we can't save the arm, the damage is irreversible," you wouldn't go, "Ah, well. It's impossible to save the arm. Time to wait it out and adapt."

    At that point, you get an amputation and adapt to being left handed.

    Or if you had cancer throughout your body, and the doctor announces, "I'm sorry, but we can't stop the cancer, the damage is irreversible", would you want to spend millions of dollars and incomprehensible pain for useless chemo and radiation therapy, or start hospice care and get to work on your bucket list?

  139. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Yup - and the alarmist predictions have been laughably wrong.

    http://wattsupwiththat.com/201...

  140. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Wikipedia suggests average fuel economy is somewhere around 5l / 100Km: http://en.wikipedia.org/wiki/F...

    ...then wikipedia is wrong as hell! This translates to the US equivalent ~47mpg. I can count the cars available in the US on one hand that even *advertise* a fuel economy this high. A quick google search tells me that the average mpg of cars *sold* in theUS in recent years has been around half that.

  141. Alarmists have No Credibility by Anonymous Coward · · Score: 0

    Let's look at the credibility of the AGW alarmists. There is an extremely complex non-linear partial differential equation that describes the temperature of a finite volume of atmospheric gas over time.

    Variables in the equation include initial conditions, radiation from the sun, the effect of cloud cover, humidity, the magnetic field of the earth, distance from the poles, heat constants of the various elements that make up the surface and near surface layers of the earth, and the makeup of the atmospheric gas. Nobody knows all of the variables, how they interact, or if the "constants" are really constant (for example the flux of cosmic radiation, or the strength and direction of the earth's magnetic field). What these AGW promoters are saying is that the entire equation boils down to how much CO2, a trace gas at 0.04%, is in the atmosphere, and not only that, but only the tiny part that man has added since around 1900. Never mind that the temperature has been going up and down for millennia, no it is the 0.003% CO2 from humans that is the forcing function. This does not even pass the laugh test and these "scientists" know it.

  142. Re:Beyond what humans can do by Anonymous Coward · · Score: 0

    Deniers? Versus what, that you are an AGW climate molester? Probably a molester of specifically very young childlike climate?

  143. Re:Where should I buy land to offset these changes by ChrisMaple · · Score: 1

    Being on the windward side of several mountain ranges doesn't seem to be helping California.

    --
    Contribute to civilization: ari.aynrand.org/donate
  144. Jane/Lonny Eachus "isn't" a 9/11 Truther by khayman80 · · Score: 1

    That still doesn't explain why the owner of the building himself said that they blew it up. Or why the BBC reported its fall 20 minutes before it actually fell. ... blah blah [Jane Q. Public, 2008-08-24]

    ... Kinda hard to argue with the owner of the building when he publicly says he did it on purpose! ... why did the OWNER say that it was done on purpose? ... A NY radio station was told beforehand that the building was going to be demolished. The BBC reported the fall of the building 20 minutes before it actually fell. ... the odds are strongly against the idea that WTC 7 collapsed due to fire. ... Does this prove that WTC 7 did not collapse because of the fire? No, of course not. But the credibility of any "official" story by now is very, very thin. [Jane Q. Public, 2008-08-24]

    ... for example lumping 9/11 together with the moon landing. Those are not even remotely the same class of questions. ... On 9/11, for example, there are some very serious questions, raised by very reputable scientists. Not "conspiracy theorists". [Lonny Eachus, 2012-02-10]

    Your "examples" should not all be grouped together, since some of them are at vastly different levels of "known", compared to the others. For example, some (but by no means all) of the "9/11 truthers" (a very derogatory phrase) have some good evidence to cite. This is hardly something an area that is "unequivocally known". ... Further, while flouride may not be a communist plot, there are some very serious ethical issues involved with putting it in drinking water. [Jane Q. Public, 2010-02-24]

    ... it goes on to say that fluoridated products should NEVER be ingested by children, because of possible adverse effects. Then it goes on further to say that THERE IS EVIDENCE of other harmful effects from fluoride, PARTICULARLY the form that is commonly put in drinking water. Now, I want to emphasize something: I am not a “conspiracy theorist”, and I do not believe there is some giant conspiracy to stupidify America via the drinking water. But this is what I very much **DO** believe: When there are serious, scientifically valid questions about adverse physical effects of a substance (as their are with fluoride), you’re a moron if you want to put it in the drinking water. [Lonny Eachus, 2013-10-19]

    ... One thing working in the conspiracy theorists' favor is the fact (discovered by reputable scientists with expertise in the subject and no conflict of interest, and independently verified) that the dust from the buildings contained bits of high-tech thermite. Not your everyday garage variety, either, but real high-tech stuff that is usually only available to government and military. ... there is documented, solid and confirmed evidence, by university scientists, that not only was there thermite, it was of a particular, restricted commercial variety. ... The 9/11 Commission report is nothing but a jok

    1. Re:Jane/Lonny Eachus "isn't" a 9/11 Truther by Jane+Q.+Public · · Score: 1

      And your point is?

      Do you have a particular argument to refute? If so, why didn't you refute it long ago?

      Oh, that's right. You aren't very good at refutation. I forgot.

    2. Re:Jane/Lonny Eachus "isn't" a 9/11 Truther by Jane+Q.+Public · · Score: 1

      See, there you go again. Out of context links to things said long ago, in some kind of half-assed attempt to prove something.

      Just a brief sample: GPS. Turned out that the people who were arguing with me were wrong, but I was wrong too. Although I assert that I was closer than they were. My statement that three satellites were sufficient to triangulate a point space (given arbitrarily fine precision) was correct. Others were arguing that it requires 4. It turns out GPS uses a minimum of 4, but the 4th is a ground station (not satellite) used to correct for errors, not necessary for the basic triangulation.

      So that wasn't nonsense. In fact not only was I essentially correct about the geometry, I was the one who found the actual answer to that one and told everyone else.

      Let's see... Rossi. At no time did I say the Rossi affair was not a hoax. I mentioned that he had sold one or two of his devices (and he had sold at least one). What of it? The U.S. navy has been looking into similar LENR reactions for decades, as have other scientists. That's a fact. Go ahead, try to refute it. In fact what I said about Rossi was wait and see.

      YOUR problem is that you claim these things are nonsense, but you haven't disproved a single one of them. Why not?

      It's ad-hominem. Plain and simple. By presenting these things (which YOU can nonsense, out of context), you are merely making yet another attempt at character assassination. I am not impressed.

      Oh... and I was only partly wrong about the NATO rounds. The originals were exactly as I described them. It turned out that the UN declared the standard rounds too deadly, so they were changed to be heavier with a steel insert. I wasn't wrong, my information was just old. I hadn't known about the change, which occurred around 1980 or so.

      So sure, I've made some small errors. And admitted them when I did. But that is only a minority of links above, which you are apparently trying to claim are all "nonsense". Like the beta decay: after some initial confusion I asked how the oscillations take place, and someone answered. I admitted that I was wrong.

      You don't see the comments where I admitted I was wrong in your links above, do you? Why is that? No need to answer: the obvious answer is again that this is not an attempt at presenting factual information, it's simply an attempt to make me look bad, using underhanded (and illegitimate) tactics. Not to mention that in a lot of it I wasn't wrong at all, you just think I was.

      But like I said before: this kind of shit is exactly what I have learned to expect from you.

      One last thing, to anybody else who has bothered to wade through all his bullshit: ask yourselves why he's keeping a record of ALL the comments I made on Slashdot over a period of years that he thinks were wrong. Do YOU do that to people? No, you don't, do you? That's because YOU are probably a normal human being, who doesn't stalk or obsess over strangers.

    3. Re:Jane/Lonny Eachus "isn't" a 9/11 Truther by Jane+Q.+Public · · Score: 1

      Condescendingly lecturing a veteran like this was wrong:

      I made a mistake and admitted it. Are you trying to claim that you don't make mistakes? You won't even dare to have your analysis of Spencer's thought experiment be seen by someone who actually has a degree in chemistry or physics, and some familiarity with the issue.

      No, after delt0r answered, you insisted he must not have understood your point. After I repeated delt0r's point, you claimed that you had got yourself sorted out already and accused me of butting in and insulting you.

      Re-hashing old shit which has been explained to you before. I made a mistake and admitted it. Yes, I argued at first, but I found out I was wrong and explicitly said so. YOU don't think my admission was good enough for your taste. Too damned bad. I still admitted it.

      Because you're galloping faster than any Gish Gallop I've ever seen, and because despite your protests you seldom accept refutations for longer than about 5 minutes anyway.

      Nope. You are conflating 2 different arguments here, which has been one of the hallmarks of your own arguments. Not my problem.

      I probably don't have more than about a month to live, so I'm obsessing over my legacy. The misinformation you're spreading seems like the biggest current threat to humanity, so I'll spend my final days debunking you.

      Hahaha. First, I don't believe you, and second, you'd have to do a lot better than this. And if I were you I'd pick something more worthy to spend my final time on, than personally attacking someone who has done nothing to you but be a victim of your vicious character attacks for years. I have already brought this to the attention of an attorney, who referred me to another because it's not his specialty. Further action is pending.

      One disturbing possibility is that you can't experience shame, which is why I'm trying to figure out why you're shamelessly posing as a woman. Maybe the way you were raised could help answer this question.

      I experience shame just fine, when I have something genuine to be ashamed about. You haven't shown me any. Do you honestly expect me to feel shame over arguments with YOU? Jesus, you have an amazing ego. Narcissus would be proud.

      And digging up 3 mentions of the same story on Twitter, some from 5 years ago, and some 2 years apart? Man, that must have taken some digging. Yes, I did check them out, which took quite a while by the way, so I know. You obviously have a serious (and possibly dangerous) obsession to be poring over someone else's records this way. I repeat: if you really believe we are the same people, then why doesn't the word "stalking" occur to you? Internet stalking is a crime in California. And you can bet that, as I have said before, I am keeping records. You may not like me but at least I am not a social criminal like some people I could name.

      But I am curious: why have you collected those 3 mentions of one story, which was obviously intended to be humorous? Of course you left the humor part out, didn't link to that, which was just as obviously intentional on your part, and again one of your consistent habits: taking things out of context, and pasting them together to give a false impression.

      I also wonder why you have a habit of linking to archives, or indirect links to other links, rather than the originals. I suspect that it is to prevent others from following the information stream, and seeing what the conversation was really about.

      I meant what I said to Demena. I dismissed the possibility that you're transgendered after you claimed that was quite literally not your problem. But if your gay-bashing bigot father left you confused about your gender then I'll apologize, retract my accusations, and support you as you experiment with your gender identity.

      I'm not in the slightest confused. Or amb

    4. Re:Jane/Lonny Eachus "isn't" a 9/11 Truther by Jane+Q.+Public · · Score: 1

      And if you really are dying, I will leave you with this parting gift:

      Despite your obsession, and the extent of your research, I still know things you don't. Why do you think I've felt free to be so glib? I've been watching you make a fool of yourself, ever since you revealed what a despicable human being you are (again, just my opinion of course, but I've had some confirmation).

      My advice to go do something more worthwhile was sincere. Because if you don't, after you are gone, I will quite happily reveal those things and your "legacy" won't be quite what you thought it was.

      That's not a threat in any way, it's just a description of the truth. I haven't been attacking YOU, it has all been coming FROM you. And this topic on Slashdot is just one more example that anybody can see. I have defended myself where I felt it to be necessary, but NOBODY else on this Earth has made it necessary. Just you. I haven't tracked you down and harassed you. You have done that to me. I haven't made a habit of jumping in to other conversations, just to try to humiliate YOU. But you have done so to me. Etc., etc ad nauseum.

      So get stuffed. I am far beyond tired of your incessant BULLSHIT. If you want to contemplate something before you die, I would suggest starting with meditating on why you have been such an incorrigibly rude, insufferable human being who makes a habit out of maliciously harassing others. Was it your own upbringing?

  145. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1
    The article said that Levitus made unwarranted assumptions. Further, quote:

    To single out one variable, namely radiation through the atmosphere and the associated âgreenhouse effect,â(TM) as being the primary driving force of atmospheric and oceanic climate, is a simplistic and absurd way to view the complex interaction of forces between the land, ocean, atmosphere, and outer space.

    Simplistic and absurd. Gee, where have I seen that before? Oh, yeah. Your other posts here.

  146. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1
    Let's see what else that oceanographer/climatist has to say. Quote:

    Yet, here I sit in the middle of the Pacific Ocean, surrounded by papers (peer-reviewed, I guess I should add) which conclude:

    (1) For the past two decades at least, and possibly for the past seven decades, the Earthâ(TM)s true surface air temperature has likely experienced no net change;

    (2) there should have been a sizable CO2-induced increase in atmospheric radiative forcing during that time, but there wasnâ(TM)t. That must mean that a suite of compensatory feedbacks overwhelmed the âoegreenhouseâ impetus for warming; implying, therefore,

    (3) that the planet will not warm from any man-produced increases in CO2; indicating

    (4) any increases in temperature will likely fit the global trend of +0.048ÂC/decade, that is, about 0.5ÂC this centuryâ" the rate of warming that has existed since the Little Ice Age, centered around 1750 in Europe, South America, and China; suggesting

    (5) that the heat storage in the upper ocean takes place in the upper 100 meters, and the magnitude provides a rise in temperature at those depths of 0.5ÂC in the past 50 years (in those parts of the ocean for which we have data);

    (6) this global warming (and cooling) of the ocean occurs on biennial, ENSO, decadal and interdecadal period scales; thence,

    (7) the ocean thermal changes on centennial-period scales, which appear as the warming trend through the past 50 to 100 years, can be explained by means of intrinsic internal modes of the Earth going through their normal cycle of warming and cooling, independent of both radiative and anthropogenic influences.

  147. Pretty much by Sycraft-fu · · Score: 1

    If you tell me that the Earth is going to change for the worse, and there's nothing we can do to stop it, then my response is we shouldn't try. We should instead work on how to survive the change. No reason to waste resources trying to stop something that can't be, spend them on dealing with it instead.

    Likewise if you tell me Earth is doomed, and there's nothing we can do to stop it, then my response is that we should just not worry about the future at all, and enjoy what time we have left because there isn't anything else to do.

    However if you tell me that we are creating a problem, but we can fix that problem by changing what we are doing, then I'm interested in hearing what you propose we do, what it would cost, how it would mitigate the problem, etc, etc.

    If a problem is solvable then it makes sense to talk about what it would take to solve it. If a problem is just something we can't do anything about then we shouldn't worry about trying.

  148. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    That has nothing to do with measuring ocean heat content. That is just the opinion of some guy on the internet regarding the implications of increased ocean heat content. Someone who is apparently not that familiar with the concept of conservation of energy.

  149. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    Yup. You found a guy on the internet who represents the 2%. Good job. Even this guy admits that the ocean is warming, so you also managed to find a link that contradicts the point you are trying to make.

  150. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    There wasn't any "evidence". It was an AC who jumped into the conversation, in EXACTLY the same way you and khayman80 do. Using some of the very same phraseology, and the timing was (yet again) very weirdly coincidental. Further, khayman80 is known to have used sock-puppet accounts, and even admitted it to me once. (He doesn't seem to realize that, but there is a record of it.)

    So no, bringing up an AC sock-puppet is not really evidence of anything, since it is known that khayman80 has used them.

  151. Jane/Lonny Eachus "isn't" a 9/11 Truther by khayman80 · · Score: 1

    My point is that you've been spreading nonsense like a firehose for years, and each time your Sauron-class Morton's demon convinces you that you're right and the other person isn't very good at refutation. This doesn't just apply to your nonsense about climate change, dark matter, neutrino oscillation, the Casimir effect and Maxwell's equations, creationists, Obama birthers and 9/11 Truthers.

    It also applies to your nonsense about conservation of energy, beta decay, quantum computing, nuclear isomers, Cherenkov radiation, virtual particles, infinities, string theory, cold fusion, R o s s i ' s E - C a t L E N R h o a x, peltier coolers, GPS, bicycle stability, control theory, hyperbolic trajectories,

  152. Jane Q. Public is Lonny Eachus by khayman80 · · Score: 1

    Is this the record you claim I "don't seem to realize" or can you link to an earlier squirrel?

    1. Re:Jane Q. Public is Lonny Eachus by Jane+Q.+Public · · Score: 1

      Although I have kept records of some of your comments, why do you expect I would have them handy? Not everybody shares your particular brand of obsession.

      I don't keep links to all your past comments at hand, or generally bother to search for them, for 2 reasons: (1) I just don't care much about you or past shit you've written, with one exception but I don't particular want to discuss that. And (2) unlike you, I'm just not that kind of weirdo. I have better uses for the records I keep.

    2. Re:Jane Q. Public is Lonny Eachus by Jane+Q.+Public · · Score: 1

      In fact, the more I read of these old streams, the more I've found where I was actually correct. (Like the one on bicycle stability for instance.) I have a copy of that paper right here and it says I was correct.

      Etc. Funny how when I say I'm done putting up with your bullshit, you try to ad-hominem me into replying more. You're weird, guy.

      But I really am done putting up with your bullshit. Your attempts to shame me haven't been coming off too well, you know.

    3. Re:Jane Q. Public is Lonny Eachus by Jane+Q.+Public · · Score: 1

      Unwilling.

      I have no obligation to prove every statement I make to you on Slashdot. In fact I have very good personal reasons for not wanting to tell you: I don't want to give you an opportunity to try to bullshit your way out of yet another aspect of your antisocial behavior. No fear: the records are safe.

  153. Thinking outside the box yields a better solution by GPS+Pilot · · Score: 1

    A lot of people are completely against this idea (government intrusion on freedom, etc.) but that's the only way we've ever solved problems based on the "tragedy of the commons"

    Really... government coercion the only way? No one voluntarily shares their assets for the benefit of the greater good? The facts say otherwise:

    "Total giving to charitable organizations was $335.17 billion in 2013 (about 2% of GDP). This is an increase of 4.4% from 2012. Although this is the fourth straight year that giving has increased, it is still not at the pre-recession level of $349.5 billion seen in 2007."

    Charitable giving increases as a person's disposable income increases -- and not linearly, either: as income grows to exceed a person's basic needs, people tend to increase the percentage of income given to charity. That's why a 10x increase in GDP would result in greater than a 10x increase in charitable giving.

    So if we just resume pursuing pro-growth policies for a few more decades, private charity will be more than capable of providing the entire social safety net -- bigger and better than our current social safety net -- and government will be able to streamline itself and stop performing that function. (Which will be a quite virtuous circle that has further benefits for the economy.) There is also quite a bit of value in the fact that it will be 100% funded by voluntary contributions, and 0% by coercive confiscation.

    When philanthropists perceive that the social safety net is well-funded, they will shift a portion of their giving to other charitable purposes of their choosing: for example, subsidizing clean energy projects.

    Remember, pursuing pro-growth policies is the key to realizing this rosy future. That means growth we come by honestly, as opposed to short-term growth that is forced by unsustainable, house-of-cards measures -- like deficit spending, or the Fed holding interest rates artificially low.

    --
    That that is is that that that that is not is not.
  154. Re:Beyond what humans can do by swillden · · Score: 1

    Global warming exists. Anyone who denies that is also a moron. But it's certainly not manmade.

    I don't get the focus on whether or not the warming is anthropogenic. Should we ignore all problems that we didn't make?

    Supposing that the warming isn't primarily anthropogenic, there's still plenty of reason to believe that the greenhouse gases we're adding are making it worse, and in fact we can even make some reasonable estimates of how much worse they're making it.

    At the end of the day, you'd really better hope that you're wrong about our ability to modify the climate. Because the current climate of Earth is not typical. In fact, there isn't really a "typical" climate for the planet. Ice core histories show us that it swings between much hotter than it is, and much, much colder (by "colder", think "equatorial oceans frozen 30 feet deep for millenia"). Both extremes will be unpleasant for us, and I say "will", not "would", because it's gonna happen. When? We have no idea. We know that climate changes can happen very rapidly (couple of decades), even without an obvious precipitating event (big meteor, supervolcano eruption, etc.), and that they come at apparently-random intervals.

    So if we want this planet to be nice for us long-term, we'd better learn to engineer our climate. Or get even better at adapting our local environment. Or both.

    --
    Note to ACs: I usually delete AC replies without reading them. If you want to talk to me, log in.
  155. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    Right. So you've never accused anyone else of being a sock puppet because everyone else you've accused is a sock puppet. I concede. Your logic cannot be refuted.

  156. Good News! by gelfling · · Score: 1

    We a rock solid apocalypse. Hopefully 6/7ths of the world will die out.

  157. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    That has nothing to do with measuring ocean heat content. That is just the opinion of some guy on the internet regarding the implications of increased ocean heat content. Someone who is apparently not that familiar with the concept of conservation of energy.

    Hilarious. Yeah, just "some guy" on the internet. Well, let's see:

    Robert E. Stevenson, an oceanography consultant based in Hawaii, trains the NASA astronauts in oceanography and marine meteorology. He was Secretary General of the International Association for the Physical Science of the Oceans from 1987 to 1995, and worked as an oceanographer for the U.S. Office of Naval Research for 20 years. ... author of more than 100 articles and several books, including the most widely used textbook on the natural sciences.

    Right. Just some guy. And yes, his article DOES address heat content. And has about 40 references. (I didn't count.)

    Typical warmist ad-hominem bullshit. "I've never heard of him so he must be an idiot and wrong."

  158. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1
    Almost, but not quite. Quote:

    (5) that the heat storage in the upper ocean takes place in the upper 100 meters, and the magnitude provides a rise in temperature at those depths of 0.5ÂC in the past 50 years (in those parts of the ocean for which we have data);

    (6) this global warming (and cooling) of the ocean occurs on biennial, ENSO, decadal and interdecadal period scales; thence,

    (7) the ocean thermal changes on centennial-period scales, which appear as the warming trend through the past 50 to 100 years, can be explained by means of intrinsic internal modes of the Earth going through their normal cycle of warming and cooling, independent of both radiative and anthropogenic influences.

    If you read the whole article, he very explicitly says that the climate is NOT experiencing anthropogenic warming. Based on his pile of peer-reviewed papers (see his list of references).

    If you want to argue the matter, then go argue with him. If you want to refute his references, then do so. I'm just reporting what he said. It's kind of pointless to argue with me about it.

  159. Re:Interesting slam of Judith Curry by Jane+Q.+Public · · Score: 1

    That isn't what I said, so it isn't my logic in question here.

  160. Jane Q. Public is Lonny Eachus by khayman80 · · Score: 1

    So you're unable/unwilling to produce these records that you claimed I "don't seem to realize"? Irony?

  161. Attention Walmart shoppers by Anonymous Coward · · Score: 0

    Kill yourself, kill yourself now, we'll give you a coupon for 25% off a coffin!

  162. Jane/Lonny Eachus "isn't" a 9/11 Truther by khayman80 · · Score: 1

    ... I was only partly wrong about the NATO rounds. ... I wasn't wrong, my information was just old. ... [Jane Q. Public, 2014-08-27]

    Condescendingly lecturing a veteran like this was wrong: "Bullshit, dude. Maybe where your tour was... Just plain bullshit. ... Give up, man. You are trying to argue with someone who knows what she's [she's?!?] talking about. ... Jeez, dude. Do you even read your own bullshit? ... You may know more than I do about what the military is currently doing, but I do know something about 5.56 ballistics, thank you very fucking much. ... maybe you know more about what the military is doing these days, but if that's what they're doing, they're being just plain stupid. ..."

    ... So sure, I've made some small errors. And admitted them when I did. But that is only a minority of links above, which you are apparently trying to claim are all "nonsense". Like the beta decay: after some initial confusion I asked how the oscillations take place, and someone answered. I admitted that I was wrong. ... [Jane Q. Public, 2014-08-27]

    No, after delt0r answered, you insisted he must not have understood your point. After I repeated delt0r's point, you claimed that you had got yourself sorted out already and accused me of butting in and insulting you.

    You've repeated this pattern ad nauseum. After your neutrino rant, you repeatedly claimed that I missed where you admitted you were wrong and asked me "why didn't you bother to repeat the part...?" when I actually had repeated that part and responded to it.

    In fact, the more I read of these old streams, the more I've found where I was actually correct. (Like the one on bicycle stability for instance.) I have a copy of that paper right here and it says I was correct. ... [Jane Q. Public, 2014-08-27]

    It's more likely that your Sauron-class Morton's demon told you that it says you were correct. Just like you've insisted you were still correct about punctuation despite never providing sentences with the plurals of i, a, and u.

    ... YOUR problem is that you claim these things are nonsense, but you haven't disproved a single one of them. Why not? ... in a lot of it I wasn't wrong at all, you just think I was. ... [Jane Q. Public, 2014-08-27]

    Because you're galloping faster than any Gish Gallop I've ever seen, and because despite your protests you seldom accept refutations for longer than about 5 minutes anyway.

    ... One last thing, to anybody else who has bothered to wade through a

  163. Re:Interesting slam of Judith Curry by riverat1 · · Score: 1

    LOL. There are some local climate contrarians (to put it nicely) here in Oregon who are convinced I'm a sock puppet for David Appell. I find it amusing and an indication of how easily they latch on to erroneous ideas.

  164. Re:Interesting slam of Judith Curry by riverat1 · · Score: 1

    I don't know how they are financially dependent on that. Don't you think we'd be studying the climate regardless of the reality of global warming?

    As far as being more interested in popular opinion than truth, that argument always baffles me. There is a reality to what they are studying that can't be changed by bias or wishful thinking. As scientists their reputations a dependent accurately reporting their findings. If they are found to have purposely fudged their research their careers are over and their reputation is mud. It's possible they are wrong but if they are they are honestly wrong.

  165. Genocide is the only answer! by Anonymous Coward · · Score: 0

    Get the world's population down to 20 million to save for planet. Most of humanity must die, except for a few handpicked elites and enough servants to sustain their lifestyle. For everyone else, its off to the gas chambers.

  166. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    The ocean is warming. To disprove this you linked to a site that concedes the ocean is warming. Good job.

  167. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    In order to disprove the fact that the ocean is warming you've linked to a site that concedes that the ocean is warming. Good job.

  168. Re:Interesting slam of Judith Curry by Layzej · · Score: 1

    I suppose, if we have to be sock puppets, we could do worse. :P

  169. leaked? It must be official then by Anonymous Coward · · Score: 0

    Oooo, it's a "leaked" report. Boy, that must make it even more important and legitimate than all of the other reports of global warming / climate change / whatever. Just follow the money. If the climate isn't "changing" then there's no need for more research grant money, Al Gore carbon tax scams, etc. Wake up, sheeple.

  170. Martial Law by Anonymous Coward · · Score: 0

    "If this bill is not passed there will be martial law tomorrow" - Financial Crisis

    I don't particularly like folks who spit rubbish to incite fear among the masses to have their way i.e. global warming.

  171. Re:Interesting slam of Judith Curry by Curunir_wolf · · Score: 1

    Actually, some of them (such as Joshua Halpern a.k.a. ‘Eli Rabett’) are paid directly by taxpayer funding to blog on places like realclimate.org. So, yes, there is a financial motivation.

    As far as "well what's wrong with that if they are telling the truth", that always seems to be the go-to, but it apparently is only acceptable to trot out this defense for alarmists, and never for skeptics like Watt. The minor and late-to-the-game contribution from Heritage that alarmists use to beat Watt over the head with is nothing but a red herring and ad hominem used to distract from debate on the real issues anyway, and it pales in comparison to Peter Gleick's fraud and forging of documents to discredit his opponents.

    Be that as it may, you seem to be under the impression that these guys have some interest in "truth" or "honesty", and that is simply not the case. As Gleick demonstrated, they have no interest in truth, and any will use any means to further their agenda. They are only interested in science when it supports that agenda, and when it doesn't they will throw out science and use other tactics instead. There are many examples of editing of comments on the site, decption and lies, etc., - there is no real discussion allowed. That's not surprising since it is run by Fenton Communications, run by David Fenton, an unapologetic anti-Semite and propagandist that would have made Goebbels proud.

    The point of the site isn't even to promote science, it's to promote "consensus".

    --
    "Somebody has to do something. It's just incredibly pathetic it has to be us."
    --- Jerry Garcia
  172. Re:Thinking outside the box yields a better soluti by frank_adrian314159 · · Score: 1

    Why of course! Because many of these "charitable organizations" are 503c's for "research and non-partisan education" like the Heritage Foundation and MoveOn.org who's tireless work benefits us all so much.

    --
    That is all.
  173. More climate clickbait by MooseMiester · · Score: 1

    The people at the IPCC seem to have a learning disability. They don't seem to understand that publishing DIRE predictions year after year only works if such predictions actually come to pass... Especially once one has been caught lying with statistics already...

    What these idiots (and others) are doing is more harmful to climate science, more harmful to the environment, and more harmful to the planet than all the so called evil opposition. Because every time some fool stands up and tries to "Sell" climatology using a dire prediction - and that prediction fails to come to pass - the credibility of climatology in general is called into question.

    --
    Murphy was an optimist
  174. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    The ocean is warming. To disprove this you linked to a site that concedes the ocean is warming. Good job.

    The ocean is always warming. Somewhere. And cooling elsewhere. There are known natural cycles. So yes, the ocean may be warming in some areas, but let's go back to context: OP was about deep warming that stores away supposed anthropogenic warming. The author of the article I linked to says it isn't so.

    So... nice attempt to move the goalposts, but it didn't work. AGW theory refuted. Again.

  175. Our climate has always changed. It's not new. by ntime60 · · Score: 1

    Humans haven't caused the climate to change or warm. The planet has been in a warming cycle for the last 50,000 years. The current Global Warming or Climate change only takes into account the human activity for the last couple hundred years. The planet on an average has been significantly hotter and colder than where it currently is over the course of the life of the planet. We as good custodians of the planet should not pollute, pure and simple. Why? Simply because this is our ONLY home, we should keep it in as good of a condition as we can. It is in our best interest to do so. Our contributions to our planet are having an impact and will continue to do so unless we change our direction. The planet will be here long after we are gone and life will most likely continue as it has in the past. But that future may not have humans in it unless we change and evolve. At the rate we are going, I see our own extinction within the next 200 years.

  176. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    Right now the ocean is (on average) warming by quite a bit. Here is the latest data: http://davidappell.blogspot.co... . This may be due to natural cycles (which it is!), but if the ocean is warming, and the atmosphere is warming, then there is a radiative energy imbalance causing that warming. That's physics.

    What we are seeing in atmospheric temperatures is a steady increase in temperatures due to GHG. Transposed on top of this is the natural ebb and flow of energy from the atmosphere to the ocean and back. This is called ENSO and PDO. When we are in a negative phase of the PDO and ENSO we see more energy moving from the atmosphere to the ocean. When we are in a positive phase we see a spike in atmospheric temperatures (See the super-ElNino of 1998 for example).

    So what we are measuring makes perfect sense to a scientist. When you look at the evidence (if you are willing to look at the data at all) you see "desperate" people "trying to pretend" something or other. What nonsense!

  177. How Long? by Anonymous Coward · · Score: 0

    A question for everyone who thinks that CO2 controls the climate. How long with rising CO2 and flat or falling temperatures before you admit your theory is wrong? 20 years? 30? Never?

    All 5 of the major datasets (RSS, UAH, HadCRUT4, GISS, NCDC) show no warming for between 14 and almost 18 years. In that time CO2 has risen 8-10%.

    Here are 2 predictions. First I predict that CO2 will continue to increase because
    China and other countries don't care about CO2. They don't even care about real pollutants much less CO2. Second I predict it will get colder over the next 20-30 years. Why?

    Dr Libby in the 1970s said that "looking forward it will stay cold until the mid 80s (it did), then it will warm by about 1/4 degree F until the end of the century (it did), then it gets cold". When asked how cold she was predicting a 1-2 degree F drop with an
    outside chance of a 3-4 degree drop. Pray it is the former.

    Dr Easterbrook in 2001 said the PDO was done it's positive warm cycle and that we were in for 25-30 years of cold weather. How cold? We have his good, bad and ugly predictions based on previous negative cold phases of the PDO. Pray it is the first one.

    Dr Abdusamatov in 2006 said we are at the top of the temperature sine wave and it will be 200 years of cold weather. Pray he is wrong.

    Why do I join with them and side with their predictions? While past performance is not a guarantee of future correctness it is a lot better record than the IPCC and their
    dozens of models of which none have been accurate. They are all based on CO2 controlling the climate and the other 3 are all cyclical natural cycles. I'll go with those who have a good track record at predicting future climate. Dr Libby is the most impressive as her prediction is 30+ years going and still accurate.

  178. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... I'm not in the slightest confused. ... [Jane Q. Public, 2014-08-28]

    That's what I told Demena.

    ... I still know things you don't. Why do you think I've felt free to be so glib? I've been watching you make a fool of yourself, ever since you revealed what a despicable human being you are (again, just my opinion of course, but I've had some confirmation). My advice to go do something more worthwhile was sincere. Because if you don't, after you are gone, I will quite happily reveal those things and your "legacy" won't be quite what you thought it was. That's not a threat in any way, it's just a description of the truth. ... [Jane Q. Public, 2014-08-28]

    Empty bluster won't stop me from continuing to debunk your civilization-paralyzing misinformation as long as I can.

    ... you still have yet to share with us what this "civilization-paralyzing misinformation" is. It isn't in the links you provided above. And you're still wrong about Spencer and Latour. [Jane Q. Public, 2014-08-28]

    Yes it was. And you're still spreading Dr. Latour's civilization-paralyzing Slayer misinformation:

    ... The plate cannot cause the heat source to be hotter because that would require NET heat transfer in the other direction. ... [Jane Q. Public, 2014-08-20]

    No. Again, warming the heat source doesn't require net heat transfer from the plate to the source. At equilibrium, power in = power out. Because electrical heating power is constant, the heat source warms even if net "power out" decreases. It doesn't have to reverse direction (plate to source) in order to warm the source.

    Maybe an analogy would help. Suppose water flows from a bathtub faucet at a rate of 1 liter/minute. The drain is open, letting water out at 1 liter/minute. Since water in = water out, the bathtub water level is constant.

    Now partially close the drain so water only leaves at 0.5 liter/minute. Since water in > water out, the bathtub water level rises.

    Raising the bathtub water level doesn't require that the drain reverse direction and start pumping water up from the drain into the bathtub. Because the faucet pours a constant 1 liter/minute into the tub, raising the water level only requires reducing the water out.

    1. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Yes it was. And you're still spreading Dr. Latour's civilization-paralyzing Slayer misinformation:

      You are implying that my stance on AGW is because of politics? Hahahaha! That's a hoot.

      And re: Latour, your argument is just asinine. Especially from someone who claims to be a physicist. First, your bathtub analogy is completely irrelevant to the situation at hand. A plate near the heat source is NOT even remotely the same as closing the drain on a bathtub, because the total power out of the system (it's a closed system with heat being removed, remember?) remains constant, as you have so conveniently observed. The plate has no influence whatever on the state of the whole system. You are neglecting the (physically) largest part of it, which is the outside wall.

      You are neglecting other things as well. For example, you're conflating electrical power with "emissive power" or irradiance, which are different things, in different units. Sheesh. You'd at least expect a "physicist" to get that much right.

      So I gave that much away. And you still didn't deserve it. Further, you are still denying the S-B law, though you continue to deny that you're denying it.

      And there is more. I haven't given away anything that you should not have been able to easily figure out yourself. One has to wonder why you didn't.

      But here's the kicker: it is abundantly obvious that the things you have done were NOT done for purposes of saving "civilization". Because if they were, you'd have taken them to the doorstep of the people who are actually responsible for dessiminating them to the public, rather than someone in a completely different field on Slashdot. Gotcha. Your intention has merely been to smear me, by whatever cheating means you have managed to come up with. The evidence is all over Slashdot. Look in a mirror, man.

      Now I have given you your bone, doggie. GO AWAY.

    2. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I'll answer in the morning. You haven't demonstrated what you think you have.

    3. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Correction: some time tomorrow or over the weekend. Not in the morning. I have other things to do.

    4. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      I have looked this over, and looked at my references again. And you're still wrong. You're mischaracterizing the thermodynamics of this experiment rather egregiously. I don't know whether you are doing it intentionally or otherwise, but you're doing it.

      I mentioned this to you several times, but you haven't picked up on it: just for one thing, you're claiming to be using flux but flux has an areal component which you are not accounting for. You say power in = power out, which may be true, but that total power is being transferred via emissive power, which is in W/m^2. Nowhere are you accounting for this. As I stated before: you are conflating power and emissive power, and you can't do that. Where are your areas? It might conserve energy but without areas you do not have the information required to calculate actual radiative temperature.

      There are number of other factors you are 're not accounting for. My statement stands: your attempted analysis of Spencer's thought experiment is nothing but a clusterfuck pretending to be physics.

      I told you where you can find a complete treatment of the actual thermodymics of this situation. If you'd actually read it and understood it (and were honest), you'd know that with a reasonable degree of precision it is correct.

      You state on your website:

      Radiation is proportional to T**4, so the magnitude of actual transfer is only related to T(h)**4 - T(c)**4 because hot objects absorb radiation from cooler objects. Thatâ(TM)s consistent with the second law because hot objects radiate more power to cold objects than vice versa.

      Yes, this is true (with the exception of the word "only"), but you are neglecting so many other factors that this statement is meaningless in context. Nobody is claiming this statement is essentially wrong... in fact I've made it myself several times. But the devil is in the details. As you show quite well by going on to misapply it:

      Nonsense. Start with conservation of energy just inside the chamber walls at equilibrium: power in = power out.

      The plate is heated by constant electrical power flowing in. The cold walls at 0ÂF (T(c) = 255K) also radiate power in. The heated plate at 150ÂF (T(h) = 339K) radiates power out. Using irradiance (power/m**2) simplifies the equation:
      electricity + sigmaT(c)**4 = sigmaT(h)**4

      This is a joke, right? Trying to see if I'd catch it?

      Again, among other things you are substituting irradiance for power without factoring in any area. That's just simply bad math. And I repeat: you have also invalidly ignored other factors which may not be ignored.

      Create a realistic scenario, draw yourself a diagram, and run some actual numbers on them rather than just tossing equations around without seeing how they fit together in the real world.

      I repeat: get the experiment with the two separate plates (actively heated plate and passive plate) right first. Then you can move on to a fully-enclosing plate. You say it's simpler but in a way it's not; you're trying to ride a bicycle when you haven't even managed to ride your tricycle without falling off.

      There are numerous sources, including physics and engineering textbooks, which contradict your analysis and conclusions. Why don't you try the engineering textbooks Latour cited, which have examples of real-world situations? After all: ultimately what we're talking about here is the real world, not a thought experiment.

    5. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      My point in the last post, which I have made before and will repeat, is that either you're not competent to analyze this, or (probably more likely), you are attempting yet again to misdirect from the real science.

      Your behavior has been classic: call someone who disagrees a nutcase (which you have done both explicitly and implicitly many times now) or "conspiracy theorist", and then when that doesn't work, and you are pushed to the wall, misdirect with half-answers that seem to be real but which are actually just straw-man arguments. You have done this so many times now it is becoming quite hilarious. But it's still a pain in the ass, and it's still antisocial behavior if not worse.

      An actual, complete analysis of the situation gives actual, real answers which contradict your conclusions above. You have continued to try to weasel out of it, but it isn't working. The facts still remain and you're still wrong.

    6. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      Spencer's INITIAL description of his thought experiment. As I have told you several time. This first, then more if you want to get into it. I will not discuss this with you in the other order, AS I HAVE TOLD YOU. Because until you get that right, you're not going to get the other one right. If you continue to argue the other case first, then we are done, and I will write you off as hopeless.

      Again, as long as the enclosing shell is nearly the same size as the heated plate, those areas are nearly irrelevant. And because it's a simpler problem (like a tricycle) one should master it before trying to ride a bicycle with complicated view factors. I already specified my areas. Again, neglecting area ratios predicts that the heated plate warms from 150F to 235F after it's enclosed. Accounting for area ratios similar to Earth's predicts that the heated plate warms from 150F to 233.8F.

      No "enclosing shell". Two parallel plates. The original thought experiment is two parallel plates (we can make them of equal volume and dimensions just to simplify, but it's not necessary). I repeat: we briefly discussed "even if it were enclosing" but that's a complication of the original, and we'll solve the original first.

      What the fuck am I doing? I actually started to solve this for you, after telling you I wouldn't. It must be very late on a Friday night.

      Also, I don't think we're assuming black bodies. The best we can realistically do is grey bodies that absorb in all the relevant frequencies under discussion.

      What the hell. Anything is better than your "thermal superconductors" that you then claim are different temperatures on different sides. Do you remember that is the second time you tried to pull that? I bet not.

    7. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Pardon me.

      s/equal volume and dimensions/equal dimensions

    8. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Oh, Jesus Christ. I actually started to have a serious discussion with you, then you had to obfuscate it and throw n all this other bullshit.

      Every goddamned time. I thought we'd actually settle this scientifically, once and for all, but I see that you were never really interested in that anyway. I think other readers (which there WILL be) will conclude the same.

      Really sorry if you're dying, but if so (I didn't believe it for a moment) you can go knowing that you abdicated on a chance to prove to the world that you can solve "civilization-paralyzing misinformation".

      And I will know that you went exactly as you (from what you have shown me, anyway) deserve: unknown and deservedly so.

      I offered to work through this with you reasonably, from start to finish. Even after you have repeatedly demonstrated that I have to reasonable obligation to you, to do so. You have refused.

      End of discussion. End of ALL discussions with you, as far as I am concerned. Given that I have often offered to discuss this openly with you, and you have continually refused, then the matter is done. You lose by default because you refuse to lose like a man.

    9. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, I said both sides of a thermal superconductor enclosing shell are at 149.6F.

      Haha. Here are your words.

      At equilibrium, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K).

      A_h*T_h^4 = A_c2*T_c2^4 (Eq. 3)

      For the moment, let's pretend the enclosing shell is a thermal superconductor, so its inner temperature is also 149.6F (338.5K). Energy conservation at equilibrium just inside the enclosing shell shows [dumbscientist.com] that the heated sphere will warm to an equilibrium temperature of 233.8F (385.3K)

      But its inner temperature ISN'T 149.6F, because it's being heated from the inside, not the outside. You calculate a temperature due to heating on the inside, with its area, then account for a reduced temperature on the outside due to increased area, then try to turn around and say the temperature on the inside is the same as the outside.

      I'm not changing a thing. This is the same criticism I gave before (just in more detail). And you're STILL full of shit, you pretender.

    10. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      I'm repeating that, with the quotations done properly, so I can save it for posterity.

      No, I said both sides of a thermal superconductor enclosing shell are at 149.6F.

      Haha. Here are your words.

      At equilibrium, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K).

      A_h*T_h^4 = A_c2*T_c2^4 (Eq. 3)

      For the moment, let's pretend the enclosing shell is a thermal superconductor, so its inner temperature is also 149.6F (338.5K). Energy conservation at equilibrium just inside the enclosing shell shows [dumbscientist.com] that the heated sphere will warm to an equilibrium temperature of 233.8F (385.3K)

      But its inner temperature ISN'T 149.6F, because it's being heated from the inside, not the outside. You calculate a temperature due to heating on the inside, with its area, then account for a reduced temperature on the outside due to increased area, then try to turn around and say the temperature on the inside is the same as the outside.

      I'm not changing a thing. This is the same criticism I gave before (just in more detail). And you're STILL full of shit, you pretender. This is the most ludicrous thing I've heard coming from someone who claims to be a real scientist in years.

      I've heard some "doozies", as they say, but it's doubly hilarious that I've pointed this out to you three times, and here you are still trying to defend it, rather than simply saying "Oops, I messed up."

      It is A WASTE OF MY TIME to argue with you. You don't learn. I won't do it any more. And I'm going to give a copy of this to my grandchildren.

    11. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Over a period of MORE THAN TWO YEARS, I have repeatedly tried to engage you in a thorough analysis of this experiment. EVERY TIME, you have done (usually incorrectly) a partial analysis, then declared the subject proved. But it never was. When pressed, you resorted to the same kind of bullshit you have pulled here, with ad-hominem, not-sequiturs, and straw-men. NEVER daring to face the full problem in real detail.

      Because you KNOW Latour was correct. And it isn't just him. TEXTBOOKS about practical applications of thermodynamics say so.

      You have NEVER, ONCE, tackled the problem head-on. Always a little twist here, a little change there, let's ignore areal exposure to the ambient radiation, ad nauseum. Always weaseling sideways, never quite taking on the task of REFUTING LATOUR, even though that's what you claimed to be doing, with all your misdirection.

      Well, I'm going to give you the benefit of the doubt, even though I honestly don't believe you deserve it. I am willing to concede that you really are a Kool-Aid drinker, and can't accept that the dogma isn't what you thought it was. That's preferable to believing that you're simply a malicious lying sonofabitch.

      I am fucking well done here.

    12. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, I'm not wrong. You calculated the outside temperature from the inside temperature, saying it's LOWER because of its greater area. This much is correct.

      THEN you try to say that with a thermal superconductor, the inner temperature would be the same as outside. Except you just calculated that outside temperature from a WARMER interior. You quite literally can't have it both ways. EITHER you're claiming a superconductor has a different temperature on both sides, or you're claiming that the inside has 2 different temperatures simultaneously.

    13. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      See? Same shit different day. You won't sit down and do the calculations start-to-finish, instead you do one small part, then start indulging in your hallmark game of out-of-context he-said, she-said, toss in a straw-man, then claim it's all proved. Here's a classic example of the kind of straw-man arguments you introduce:

      I've stressed that this thought experiment has been tested for decades in the real world. Radiation shields allow for more accurate measurements of gas temperatures using thermocouples:

      "The greatest problem with measuring gas temperatures is combatting radiation loss. ... surround the probe with a radiation shield ... The thermocouple bead radiates to the shield which is much hotter than the surrounding walls. Thus the radiative loss and hence temperature error is significantly reduced. The shield itself radiates to the walls."

      Here is an excellent example of this (19.3.2), which illustrates why it is a straw-man argument that is not relevant to the problem at hand. In this case the walls are warmer, not cooler, and the radiation shield is blocking the thermocouple from the radiation inward from the chamber walls, so that it can get an accurate temperature reading of the air without interference from the walls. In your case, it is the opposite: the walls are cooler than the thermocouple. But in neither case is the situation a representation of equilibrium (for example in this case, air is convecting away some of the heat of the thermocouple). The shield is absorbing and emitting radiation, too, it's just that it is isolated from the chamber walls, and so is closer to the ambient temperature of the medium being measured.

      This is in no way related to our experiment at all. It is in a vacuum. There is no "medium" to measure, with an ambient temperature. Not even remotely. It's simply another illustration of the depths of hand-waving you will go to, rather than actually doing all the calculations on the actual experiment from start to finish.

      All you're doing is tossing in more straw-men and irrelevancies. You won't do the actual experiment. The only reasonable conclusion to be drawn here is that you won't do it because you know you're wrong.

    14. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      And I want to be clear about this: I'm not demanding anything from you. YOU are the one who proclaimed Latour wrong, therefore it is your burden to demonstrate that he actually is, by showing exactly where he is incorrect.

      I really don't give a damn whether you believe it or not. I'm not the one following you around, casting personal aspersions against YOU. I've just been defending myself from YOUR malicious attacks.

      The whole point: You claimed Latour was wrong. But you refuse to back up your claim by showing WHERE in his calculations he was incorrect. That's your burden and you haven't been meeting it. Until you do, you have no argument to make. You can throw all the ad-hominem and straw-man arguments and irrelevancies in that you want, but none of it proves you correct. Until you actually show where Latour made a mistake, in his actual calculations related to this experiment, you're wrong by default.

    15. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Don't you see that you threw in this whole "thermal superconductor" schtick without considering what properties a thermal superconductor must actually have?

      In order to superconduct, it must be the same temperature everywhere, always. The only way this would be even remotely possible were if it were a perfect radiator, with emissivity of 1. It would also be a perfect absorber, absorptivity of 1. Regardless of wavelength.

      So while this might not technically be true, for all practical purposes it is: a thermal superconductor would be completely transparent to all radiation, and there is no way to heat it or cool it in relation to its surroundings. It has no "thermal mass".

      So it would have absolutely no effect on anything in this experiment. For practical purposes, it would not exist.

      Your idea that you can get around this by placing some kind of thin lining on its interior doesn't work. It's still as though it weren't there at all... all you have left for practical purposes is the thin shell, nothing else.

      Trying to use it as part of your demonstration won't wash. Every time you try to demonstrate something with it, you end up contradicting yourself. (Which I have pointed out to you many times now. Not just twice, more like 5 or 6 times.)

      That's why I say: no more prevarication. No more beating about the bush. Take Spencer's original challenge, apply Latour's thermodynamic treatment of it, and show where it is wrong.

      Anything else constitutes failure to back up your claim that Latour is wrong and -- as you have said more than once -- some kind of nutcase. You've had more than 2 years. That is plenty.

    16. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Remember that the inner surface of the enclosing shell is different than the surface of the heated plate. The inner and outer surfaces of the enclosing shell are at exactly the same temperature because it's a thermal superconductor. That's what I've always been saying, despite your attempts to pretend otherwise.

      I quoted your words above.

      At equilibrium, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K).

      In order for what you say to be correct, then the "enclosing shell" you refer to is not the heated plate enclosing the source. Which would mean you were talking about a completely different experiment, not even the one Spencer mentioned with the heated plate enclosing the source.

      I'm not interested. Original experiment. Latour's treatment of it. Show where he was wrong. Period. Stop prevaricating.

    17. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Superconductors are distinguished from aluminum by internal properties, not radiative surface properties. That's because conduction happens inside materials, whereas radiation is emitted and absorbed on surfaces.

      You're not thinking.

      We're talking about the context of SPENCER'S experiment. The only heat transfer in or out is radiation. It order for it to actually superconduct all the heat absorbed, it has to dispose of that heat somehow. The only way it has to do that is to super-radiate as well (emissivity very close to 1). This is the only logical conclusion. Otherwise it could not be a thermal superconductor; it would build up heat and HAVE TO conduct it away more slowly, like any other material. And there is a similar argument for absorptivity.

      You keep wanting to have things both ways but that isn't going to work.

      I am aware that the only thing that has an emissivity and absorptivity of 1 is a black body. I'm not stupid. But your hypothetical thermal superconductor could not store heat like a black body and remain a superconductor. That's a contradiction. So it's a different creature, from your imagination. This is why I say: leave it out. There is no way you can try to demonstrate anything else with it, either, without leading to a contradiction. And it's not part of the original experiment anyway; it's nothing but misdirection.

    18. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      As I've repeatedly and consistently stressed, "T_c" is only identical on both sides of the enclosing cold plate if it's a thermal superconductor.

      We have never disagreed on this. The problem is that there is no such thing as a thermal superconductor of this kind, and you aren't seeing that it leads to contradictions. The only way it could exist would be if it had NO thermal effect on its surroundings whatever. So it's the ultimate straw-man argument. There is no way it can be legitimately used to demonstrate anything.

      Since you just linked to this excellent example, did you notice that MIT solved this problem at the very top and got a completely different answer than Dr. Latour?

      No, they didn't, because it's a different problem, being given a theoretical treatment. You keep doing that, but I'm not buying. Two infinite plates, neither of which is heated, is not even remotely the same situation, and it's also theoretical only. They're not taking into account certain real-world factors pertaining to Spencer's experiment. Latour does. Not that they're doing anything wrong... given the context of their situation: infinite non-heated grey bodies. This is not Spencer's experiment.

      I've showed that Dr. Latour was wrong because his claim violates conservation of energy. Again, in physics that's a really big mistake.

      No, you didn't. You did not point to a calculation he performed on Spencer's situation and prove it wrong. You took what you incorrectly called an analogous situation and called that wrong. Which has been my whole point here. You keep claiming something else represents Spencer's experiment, but you won't tackle Spencer's actual, original experiment. You have consistently refused, for over 2 years.

      You can toss around equations all you like, but if you're not applying them to the experiment actually under discussion (and you haven't been), you're still not proving anything. You're just moving the goalposts.

      And that's why I've said I'm out of here. You continue to refuse to actually do what you said you'd done: refute Latour's treatment of Spencer's challenge. You can keep prevaricating and beating around the bush and straw-manning and moving the goalposts, and I'll just keep telling you why you're wrong. Or rather, no I won't. I've done that too many times already.

    19. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      And I'm going to repeat this, just one more time, in the (probably vain) effort to get you to get it straight:

      Take Spencer's original experiment, with two separated, non-enclosing plates, and show SPECIFICALLY where Latour was wrong in his calculations. THEN, if you like, you can move on to the enclosed-source situation.

      I'm not buying anything else. No straw-man, no moved goalposts, no new introduced factors like "thermal superconductors".

    20. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Again, we'll have to agree to disagree about thermal superconductors. That's why I've repeatedly pointed out that I've already solved [dumbscientist.com] this problem with an aluminum enclosing shell, and it also warms the heated plate (aka Jane's "source") to ~233.8F.

      You solved part of the problem, under different conditions, as I have repeatedly pointed out.

      Let's get this straight: rather than tackling the actual problem you claimed to have refuted, you solved a different problem under different conditions, and called that refutation.

      Even if your analysis of that problem were 100% correct, this is the very definition of a straw-man argument.

      So why do you refuse to just take Spencer's original challenge, with two non-enclosing plates (i.e., the challenge I originally presented to you), and simply show me where Latour was wrong about it, as you have so often claimed? After 2 years I can only conclude that you are not able to do it. I don't know of a single other plausible reason why you have refused to do this.

      Again, Dr. Spencer's actual, original experiment included the possibility of a fully-enclosing passive plate.

      That got a minor mention later in his article, is not included in his diagrams, and is NOT the problem I originally presented to you. As I have said many times before, AFTER you refute Latour's calculations regarding Spencer's original challenge, which did not have the passive body enclosing the heat source, I would be happy to move on to the other issue... with no additional stipulations or additions to the problem Spencer describes. But you haven't gotten there yet. Cart before the horse, with a straw-man riding the cart.

      That was the challenge I presented you you. For 2 years now, you have been going far out of your way to do everything BUT that, which leads me to believe that is your new custom definition of "rebut". (I would say that last sentence is a jest, but in fact it is only partly so.)

      We can agree that one should solve simpler problems before moving on to more complex problems, but we seem to disagree about which of the scenarios in Dr. Spencer's original experiment is simpler.

      That wasn't my point. I'm not saying we should solve simpler problems before moving on to more complex problems. I'm saying the challenge originally given to you is to be met before moving on to something else and claiming it irrelevant. I only wrote that "in a way" it's not simpler. But again that is beside the point, which you appear to be attempting to sidestep again.

      Again, solving a problem without spherical symmetry means you'll have to solve for equilibrium temperatures which aren't constant across the heated and passive plates. Those equilibrium temperatures wouldn't be simple numbers. They'd be complicated functions that would vary across the plate surfaces. Contrast that with a spherically symmetric enclosing plate, where equilibrium temperatures are just simple numbers.

      I only claimed Latour was correct "with a reasonable degree of precision". He states himself in his original article that these are working approximations used for engineering, which in practice must have minor adjustments made experimentally for final product (when dealing with things like furnaces, which often have complex internal geometry). It's good enough for real world engineering, according to both Latour and the textbooks. So you don't get a pass on that basis, either.

      Why don't you just shut up and do it? Why have you been so mightily struggling, like a fish on a hook, to avoid it?

    21. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Again, I don't have enough time to program a finite element model to account for the fact that a non-fully-enclosing plate would cause plate temperatures to vary across their surfaces.

      I've already explained why this is BS excuse. Latour didn't need finite element modeling to come up with a reasonably precise answer, and neither would you. Further, you don't have to explain to me what finite element modeling is. I was doing large-scale finite element models back in the 90s.

      By the way, since you keep insisting that only a particular geometry could refute Dr. Latour's treatment

      There you go again. Same shit different day. I have written no such thing. Back to the original context: I asked you to refute Latour's treatment of Spencer's challenge, as shown in his diagrams and descriptions of his original article on the subject. I did not claim "only" this would refute Latour. But this is indisputably true: only this would refute Latour about this. Not the "enclosing" variant of the problem. I'm simply sticking to the original challenge. I am not claiming it's the "only" thing that could possibly refute Latour at all. It's just that it is the specific thing I challenged you to refute. I have no reason to apologize or make excuses for sticking to the original challenge as I first presented it to you.

      The challenge originally described by Spencer (including his diagrams) represents approximately the general case. You claim (I disagree but I don't want to get into that here, because it's irrelevant to this challenge) that you have refuted Latour in a specific case but not in the general one.

      I simply asked why you refuse to show where Latour was wrong in Spencer's original challenge, not the "enclosing" variant of it. That was my original challenge to you, and there is no ambiguity about it. I have stuck to that and haven't changed it.

      I am aware Latour's equations allow for K=1, but that's just one special case, not the general solution, and not the original challenge Spencer described. Both Spencer and Latour say "even if..." but again that is not the general case. I had reasons for bringing up the specific problem that Spencer originally described but those reasons are my own, and I don't really owe you an explanation. You can take the challenge or pass on it, but if you pass on it, you haven't met it.

      could you please show where he specified the dimensions of the plates?

      Why? It might be convenient, but it's hardly necessary to demonstrate the point. Just the general geometry and some rough ratios. Neither party stipulated a "specific" geometry, just a general description of the basic problem. And that's fine, because that is all that is actually needed. If you want to solve for specific dimensions go ahead. You might find it easier to do that way, and the answer would be unambiguous. I don't really care.

    22. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Latour's answer is ridiculous Sky Dragon Slayer nonsense which violates conservation of energy, as I've shown.

      It is the engineering textbook answer. Claiming it is nonsense does not make it so. It was your own model that violated conservation of energy. But to see why, it's easiest to solve the general case first, then look at a specific case. I told you I had reasons to solve the general case first.

      But you're just continuing to refuse, as I expected. After 2 years, I consider that to be an admission of defeat. Asking me to assume anything else is asking far too much.

      Once again, solving a problem without spherical symmetry means you'll have to solve for equilibrium temperatures which aren't constant across the heated and passive plates. Those equilibrium temperatures wouldn't be simple numbers. They'd be complicated functions that would vary across the plate surfaces. Contrast that with a spherically symmetric enclosing plate, where equilibrium temperatures are just simple numbers.

      Derived equations are available which give approximations with reasonable precision. Or you can assume particular dimensions of the general case which simplify the math. I said that was a bullshit excuse, I meant it when I said it, and I still mean it.

      Are you disputing that equilibrium temperatures for a non-enclosing plate would vary across the plate surfaces rather than being simple numbers like with a spherically symmetric fully enclosing plate?

      I am disputing that given reasonable chosen dimensions it is anywhere near an intractable problem.

      Because, unless you dispute the above facts, that would require a complicated finite element model due to its lack of spherical symmetry. I simply don't have that much time left. And again, we'd have to test that complicated model in a case where an analytic solution is available anyway...

      Well, then, I guess you do admit defeat. It doesn't take much time to obtain a textbook on the subject (you were given references 2 years ago and it's not that hard to find others). But you choose what you want to do. I warned you that if you really do have limited time, you would be better off spending your time elsewhere.

      I don't wish harm on anybody. But I have a low tolerance for bullshit and I don't appreciate being attacked under false pretenses. The only "attacks" I have made against you have been in self defense. Just maybe it's time to leave me alone.

    23. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, the PSI Sky Dragon Slayers told you it's the engineering textbook answer. I showed you MIT's final expression which reduces to my Eq. 1 for blackbodies, and is consistent with these equations and Eq. 1 in Goodman 1957. Physicists and engineers have been using thermodynamics for decades in the real world that contradicts Dr. Latour's Slayer nonsense.

      Utter nonsense. You showed me an answer for a completely different problem which does not apply here. You keep doing this. I said I wouldn't do this, but here are just SOME ways your analysis is completely full of shit. Here is what you stated on your website and elsewhere:

      Electric input of 509 W/m2 is constant and the walls are held at 0ÂF (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150ÂF (339K).

      Utter nonsense. The temperature of the outside of your enclosing sphere is determined entirely by its absorption minus its emission, with absorptivity and emissivity factored in. If your interior heat source were emitting at (your figure) 509W/m^2, and that is being absorbed by the interior surface of your enclosing sphere (which MUST have larger radius than the source, since they can't contact), then your outside surface, being of even larger area, must therefore be colder. (This is if we assume a black body and can ignore emissivity and absporptivity... which Spencer did not actually do. He mentioned black bodies but did not say he was applying the idea to his thought experiment. I am saying that even if they were black bodies, this would be true.)

      So you're INVENTING ENERGY OUT OF THIN AIR. Then, as if that were not enough, you try to pull off THIS gem, which is really quite hilarious. I know I keep using that word, but that's because it's hilarious:

      But the second plate also radiates the same power in, toward the enclosed heated plate. Just like the cold chamber walls do. Now consider conservation of energy just inside the second plate (but outside the first) at equilibrium. We can solve for the insulated heated plateâ(TM)s temperature using Eq. 1 by setting Tc = 150ÂF (339K). That yields an insulated heated plate temperature of 235ÂF (386K).

      No, it doesn't! The irradiation is total for the entire hollow sphere, not for each surface. You have to divide the total irradiance by the entire surface area, including the interior and exterior!!! You can't say the total is emitted by BOTH surfaces! You have just multiplied its power output, from nothing!

      If (just for example) the enclosing sphere were very thin, so that the interior area were nearly the same as the exterior, then you would have just nearly DOUBLED the total power output! That is NOT VALID. It violates conservation of energy.

      As I stated before: it is YOUR treatment of this experiment that is absolute fantasy. Not only are you creating energy by assuming your exterior temperature of the shell, you compound your error by then creating energy from the vacuum by saying your hollow sphere radiates its total power (W/m^2) power inward AND outward at the same time.

      I'm really not sorry to say this after your past behavior, but showing you're wrong is just plain dirt simple. And not JUST wrong, but so ridiculously wrong that I can (and will, believe me!) use it as entertainment for certain of my friends.

    24. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      And if you don't believe that you have to divide the total emission by the total area, then maybe NASA can convince you.

      What makes it doubly hilarious (there's that word again), is that you try to factor absorption for EACH surface, interior and exterior, but then just willy-nilly assume that the TOTAL emission is then emitted from each side.

    25. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Let's be very clear, just so we understand each other here:

      In your descriptions you keep assuming things rather than calculating them. And some of your assumptions do not appear to be valid. You may have meant something other than how I interpreted your words, but that's why it's pretty damned hard to prove anything without calculating it all the way through.

      Further, you have had a strong tendency to use imprecise terms, which causes confusion. For example: power (W) is not the same as irradiance (W/m**2) and they may not be willy-nilly conflated. So why don't you draw a diagram, and simply perform all the calculations? No more beating around the bush, no more introduction of new elements. I'll even go with your own example of the passive plate enclosing the heat source, for now. I consider that to be a pretty major concession that I don't think you deserve.

      So, there is a heat source of area X. Go ahead and assume it's a sphere if you like. Like Spencer, we can assume that the electrical power in is constant, and enough to heat the source to 150 deg. F, inside a larger enclosure which is kept (by means of which we need not concern ourselves), at 0 deg. F. We can also assume, like Spencer, that the properties of our materials do not change with temperature.

      Then an enclosing plate is introduced, at a temperature (initially) less than that of the source. We can, if you wish, assume it is a hollow sphere, of some reasonable thickness, so the interior and exterior areas differ, and of a smaller external radius than the outside wall, so again they don't touch. Vacuum in between. And we begin our analysis. The starting point and equilibrium are both relevant points that should be calculated.

      Since this is supposed to be an approximation of a real-world situation, we should use real materials with real emissivities and absorptivies. Just to keep everybody honest.

      I don't insist, but to avoid ambiguity and to make things expressible on a standard keyboard, this is how *I* would label things: S for heat source, so radiative temperature T of S would be T(s). Passive plate (or shell) P. Outside enclosure or wall W. Absorptivity A so absorptivity of P would be A(p). Emissivity E.

      Radiant power = (sigma)T**4, where sigma = approx. 5.67 * 10**-8 W/m**2 K**-4

    26. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      But let's also be clear about this: even given potential misunderstandings, your prior analysis was still wrong. It is VERY easy to show this.

      Presume you have an initial source at T = 150 deg. F. It has a surface area of 1 m**2. Therefore (let's just assume your figure for power output here, it doesn't really matter and it's good enough for this illustration): it's emission is 509W/m**2. Let's say the EXTERIOR of your enclosing shell has an area of 2 m**2.

      However, your words (though in a slightly different context): power in = power out. Since the total power (W/m**2 times X m**2) must be the same in as out, the exterior of your shell cannot have the same irradiance. The same must be true if this were just one solid sphere, rather than a hollow sphere enclosing another sphere.

      Solving for the Stefan-Boltsmann relation at 509W/m**2 times 1 m**2 is total number of watts. If you try to multiply the same emission rate over 2 m**2 you get a DIFFERENT answer. That's just a fact. By assuming an external temperature of 150 deg. F, you have just created tangible energy from the vacuum. Congratulations.

    27. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I've already showed you that the outer surface of an enclosing shell with an area ratio similar to Earth's warms to ~149.6F. I've explained that neglecting area ratios is a tricycle: a simple approximation that helps us learn. It's like the "frictionless pulley" or "massless rope" or "blackbody" approximations. Again, in this case the tricycle isn't too inaccurate compared to the bicycle, it's much easier to learn, and it provides a sanity check on the more complicated calculation. As the area ratio approaches "1.0" the bicycle should give the same answer as the simpler tricycle. And it does.

      Bullshit. I quoted your exact words above. You don't get to plug later calculations back into your original erroneous analysis and call it good. And I have already explained why it is not possible to do this and still get valid answers. 2 * X is not the same as 1 * X. It is not valid to multiply your power output with no further power input. It's a violation of conservation of energy. So you're still falling off your tricycle.

      Repeat: if we give the sphere which is the heat source, at 150 deg. F, an area of 1 m**2, and the outer area of the enclosing sphere an area of 2 m**2, and (as YOU have said), power in = power out, then the exterior surface cannot be the same temperature. This is not even advanced physics, it's simple damned algebra.

      And even Spencer did not assume net heat transfer from the exterior walls, which is fine because the exterior walls cannot be of greater temperature so according to the S-B law there is no net heat transfer to the interior objects. T(w)
      All else being equal, the amount of power input necessary to heat an object with 1 m**2 surface to 150 deg. F is not enough to heat an object of similar material with 2m**2 surface area to the same temperature! If you try to assume the same radiative temperature over greater area, you must have greater input, or else you have done your math badly. I have stated this to you a number of times. Your attempt at analyzing this challenge violates conservation of energy. Period. This is unequivocal.

      And no, it's not like the blackbody approximations because we're talking about real objects here, so emissivity will not be same as absorptivity, BUT that's really irrelevant to this particular point. You're just clownishly hand-waving again, because even if they were black bodies, they would still have to obey S-B and you would still be wrong.

      I quoted your actual analysis above, which you wrote some time ago and claimed it was a refutation of Latour. Your math is wrong. Further, it is not valid to take other calculations you did later, using different assumptions, plug them back into the original problem and claim that all is good. If you want to change your figures, then START OVER AND DO IT RIGHT. It isn't valid to make other assumptions then just plug those calculations back into the original problem as though that made no difference.

      You are only illustrating why I have said all along that you're full of bull, and you have been all along. Either you are incapable of doing this properly, or you're just bullshitting everybody for reasons of your own. And as I have stated before, I believe it is your own strange way of further harassing me.

      No, you linked to another PSI Sky Dragon Slayer.

      Hahahahaha! Now, THIS is ad-hominem at its finest. I did write NASA when I meant ESA, but that is beside the point. It is the information content you must refute, not the person, and the information is clear: the chart (straight from ESA) contains a 0.5 factor because a plate has 2 sides, and you have to calculate emittance from BOTH sides. No matter what the shape of your object, you have to calculate emittance from ALL its surfaces if you want to get the correct answer for temperature. You don't get to take the total emittance and multiply it, which you implied in the analysis I quoted.

      If you can do it better NOW, then do it better. Don't j

    28. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I've already showed you that the outer surface of an enclosing shell with an area ratio similar to Earth's warms to ~149.6F. I've explained that neglecting area ratios is a tricycle: a simple approximation that helps us learn. It's like the "frictionless pulley" or "massless rope" or "blackbody" approximations. Again, in this case the tricycle isn't too inaccurate compared to the bicycle, it's much easier to learn, and it provides a sanity check on the more complicated calculation. As the area ratio approaches "1.0" the bicycle should give the same answer as the simpler tricycle. And it does.

      Bullshit. I quoted your exact words above. You don't get to plug later calculations back into your original erroneous analysis and call it good. And I have already explained why it is not possible to do this and still get valid answers. 2 * X is not the same as 1 * X. It is not valid to multiply your power output with no further power input. It's a violation of conservation of energy. So you're still falling off your tricycle.

      Repeat: if we give the sphere which is the heat source, at 150 deg. F, an area of 1 m**2, and the outer area of the enclosing sphere an area of 2 m**2, and (as YOU have said), power in = power out, then the exterior surface cannot be the same temperature. This is not even advanced physics, it's simple damned algebra.

      And even Spencer did not assume net heat transfer from the exterior walls, which is fine because the exterior walls cannot be of greater temperature so according to the S-B law there is no net heat transfer to the interior objects. T(w)
      All else being equal, the amount of power input necessary to heat an object with 1 m**2 surface to 150 deg. F is not enough to heat an object of similar material with 2m**2 surface area to the same temperature! If you try to assume the same radiative temperature over greater area, you must have greater input, or else you have done your math badly. I have stated this to you a number of times. Your attempt at analyzing this challenge violates conservation of energy. Period. This is unequivocal.

      And no, it's not like the blackbody approximations because we're talking about real objects here, so emissivity will not be same as absorptivity, BUT that's really irrelevant to this particular point. You're just clownishly hand-waving again, because even if they were black bodies, they would still have to obey S-B and you would still be wrong.

      I quoted your actual analysis above, which you wrote some time ago and claimed it was a refutation of Latour. Your math is wrong. Further, it is not valid to take other calculations you did later, using different assumptions, plug them back into the original problem and claim that all is good. If you want to change your figures, then START OVER AND DO IT RIGHT. It isn't valid to make other assumptions then just plug those calculations back into the original problem as though that made no difference.

      You are only illustrating why I have said all along that you're full of bull, and you have been all along. Either you are incapable of doing this properly, or you're just bullshitting everybody for reasons of your own. And as I have stated before, I believe it is your own strange way of further harassing me.

      No, you linked to another PSI Sky Dragon Slayer.

      Hahahahaha! Now, THIS is ad-hominem at its finest. I did write NASA when I meant ESA, but that is beside the point. It is the information content you must refute, not the person, and the information is clear: the chart (straight from ESA) contains a 0.5 factor because a plate has 2 sides, and you have to calculate emittance from BOTH sides. No matter what the shape of your object, you have to calculate emittance from ALL its surfaces if you want to get the correct answer for temperature. You don't get to take the total emittance and multiply it, which you implied in the analysis I quoted.

      If you can do it better NOW, then do it better. Don't j

    29. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Crap. The above, where it says T(w), should have been:

      T(w) [is less than] T(p) [is less than] T(s).

      Yes, I know Slashdot character handling is a pain in the ass, and it catches me often too, when I try to express "greater than" or "less than". Even so, I'm not installing Sage right now. Better things to do. I have reasons for wanting it public-readable, and I will accept nothing else.

    30. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I tried those before here a long time ago and it didn't work. But maybe they changed things. So here's another try.

      < >

    31. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Well, I'll be darned. It works now. I'll see if others are working now too. Like

    32. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I had reasons for choosing the variable names that I chose. I am well aware that they are not according to convention. But for just one factor out of several, neither is Slashdot's character handling. Again, just for one example, I used capital E for emissivity rather than epsilon because it shows up well here. And rather than using upper- and lower-case characters for one body vs another, for example, an upper-case letter with subscript() works just fine. I have a couple of other reasons as well, I didn't just say this arbitrarily. At least this way when you refer to what you call the "heated plate" I know which one you mean without ambiguity.

      Regardless, you are already skipping ahead. What do you want to use for material? We might as well use the same material throughout. So if you want to use aluminum for source, passive plate, and walls that is fine with me.

      We know then, from ESA that the emissivity of aluminum in vacuum is approximately 0.15, and absorptivity 0.05.

      I have been too busy to work through this this evening. I'll return tomorrow, if I'm not still too busy. I haven't even looked at your other posts.

    33. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Nope. That one did not work.

    34. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      As you said, the best we can realistically do is graybodies where emissivity = absorptivity. If you'd like to use a different emissivity just let me know, and we can both independently calculate the required electricity to check each other's answers.

      After considering the situation I changed my mind. Since we are discussion what is supposed to be a real model of a real situation, we can use real emissivity and absorptivity. And the emissivity of aluminum (as you pointed out yourself some time ago) is different from the absorptivity by a factor of about 3. The ESA figures are observed figures for aluminum plates in near-vacuum, so those figures would appear to be perfect.

      And as I stated before, I am busy and I don't have time to figure out your nomenclature right now. That's why I wanted to agree on one.

      I do have one more comment I want to make tonight, though. I will reply to the relevant post of yours. It is pointless to continue 3 separate threads at once.

    35. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches equilibrium. I promise to provide public-readable versions of my Sage worksheet from now on.

      This is one of the whole problems with your analysis. THERE IS NO THERMODYNAMIC EQUILIBRIUM IN THIS EXPERIMENT. There is a steady-state, but no actual equilibrium. That is not possible, because we are actively pumping heat in at one "end", and pumping it out of the other.

      Since one of the requirements of thermodynamic equilibrium is that all surfaces be at the same temperature, it will never be achieved because the experiment requires that the outside wall be maintained at 0 deg. F, yet we are still pumping significant heat in to the center.

      Therefore Kircchoff's law does not apply to this experiment, and no situation arises in which the temperatures are the same everywhere, or the emissivities vs absorptivities. There is a steady-state arising from active (but constant) exchange. But there is no equilibrium.

    36. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Earlier, when I saw your mentions of equilibrium, I thought you were referring to the steady-state that would eventually be achieved. But even though you mentioned Kircchoff's law, it didn't sink in to my brain that you were referring to actual, literal equilibrium.

      Uh-uh. As they say in my neck of the woods: it ain't happenin'.

    37. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      In contrast, you're citing ESA figures from page 32 which are at 0K (-273C). But nothing in this experiment is anywhere near that cold.

      Nonsense. They are figures at at incident radiation of 1367 W/m^2, which is sunlight at 1 AU, for the very reason that it is an approximation of Earth insolation. So in fact it would make a good representative example of what Spencer's model is supposed to be all about. Or do you (like Spencer) claim that space is "cold"?

      But since you want to try to mischaracterize everything I say, and pick it all apart for reasons of your own, have it your own way. This is simply not very important.

      You were right when you said [slashdot.org] the best we can realistically do is graybodies where emissivity = absorptivity. Otherwise we'd need to derive a new equation where heat transfer is an integral over wavelengths. In other words, we'd have to recreate MODTRAN [wikipedia.org]. I simply don't have time for that.

      As I mentioned before, ESA gives observed values for integrated emissivity and absorptivity for aluminum. This is a good approximation and it is used in the real world for aluminum in a vacuum. If you really insist on gray bodies that's up to you; but I do not acknowledge that there is any legitimate reason to NOT use reasonable approximations of integrated absorptivity and emissivity.

      We might be talking past each other. What you're calling steady-state is what I'm calling equilibrium. Radiative thermodynamic equilibrium doesn't require all surfaces to be at the same temperature, it simply means that temperatures don't change with time. At radiative equilibrium, power in = power out, which also means irradiance in = irradiance out.

      You USED this before to ASSUME all surfaces were at the same temperature! I quoted you saying it in a post above, and you referenced that passage just the other day. In fact this was the source of much of the misunderstanding here. I did not understand why you were assuming some of the things you were assuming, and so my conclusion was that you were just messing with me. (And I am still not convinced that you were not.) THERE IS NO RADIATIVE EQUILIBRIUM HERE. THERE IS NO THERMAL EQUILIBRIUM HERE. None. You may not assume them.

      I've already shown that MIT used Kirchhoff's law to derive heat transfer between gray bodies. I've already shown that Goodman 1957 tested the gray body approximation (Kirchhoff's law) and found that it's valid for aluminum at the temperatures in this experiment.

      Note that my definition of equilibrium is consistent with this one: "In physics, radiative equilibrium is the condition where a steady state system is in dynamic equilibrium, with equal incoming and outgoing radiative heat flux and negligible heat transfer by conduction and convection."

      In other words, irradiance in = irradiance out at radiative thermodynamic equilibrium. We're just using different words to describe the same concept.

      No, we aren't, and you are incorrect. Actual thermodynamic equilibrium DOES require that there is no radiative transfer, and you aren't going to get it both ways. A steady-state is NOT the same thing as equilibrium. In Spencer's challenge, thermodynamic equilibrium does not exist. Radiative equilibrium does not exist. At no time are ANY of the surfaces in this experiment at the same temperature, and there is constant radiative transfer between bodies. This is another example of how you have played fast-and-loose with terminology. You do not get to re-define equilibrium any way you choose. Just no.

      Kircchoff's law (and MIT's example) both assume no bodies involved are storing thermal energy, and there is thermal equilibrium. In fact that is how Kircchoff's law is derived: technically Kircchoff's law only applies at thermal equilibrium. MIT was free to apply it in their example because th

    38. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      The long underline was an editing mistake.

    39. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Those ESA absorptivities are for absorption of sunlight. Consider the first diagram here which shows that 6000K sunlight has much shorter wavelengths than the radiation from objects at the temperatures we're considering. In fact they hardly overlap. But the emissivities are for radiation emitted by much cooler objects. That's one reason why those ESA emissivities aren't equal to their absorptivities.

      I repeat that these are under conditions of Earth-absorptive-surface insolation, which was what Spencer's experiment was supposed to emulate. But whatever.

      But the emissivities are for radiation emitted by much cooler objects.

      No, they are not. They are reported for the previously stated conditions: 1367 W/m^2 in incident radiation. But again: whatever. I already stated that this is not important enough to argue the point. I'm not conceding your point, but I'm willing to move on with gray bodies.

      Once again, I never said that. In reality, I said that both sides of a thermal superconductor are at the same temperature. This was the source of much of the misunderstanding here, and you strongly objected to the notion of a thermal superconductor. Again, that's why I calculated the small temperature difference across an aluminum shell with finite conductivity.

      Yes, you did say that, and anybody who wants to can read it on your website. And you wrote it BEFORE any discussion with me of "thermal superconductors". I will quote it again here:

      Electric input of 509 W/m2 is constant and the walls are held at 0ÃF (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150ÃF (339K).

      You were referring to "the second plate", as opposed to the "heated plate". That corresponds to what I have been calling the "passive" or "enclosing" plate. And you further referred to a supposed thermal equilibrium that doesn't exist.

      Which fantasy would you prefer we believe? A thermal superconductor that makes no sense in this context, or an equilibrium which does not exist in this context? And you don't have the excuse that you meant "steady state", because the figure you gave would only be appropriate for actual equilibrium.

      But enough of old arguments. Let's move on.

      I was using this definition: "When incoming solar energy is balanced by an equal flow of heat to space, Earth is in radiative equilibrium and global temperatures become relatively stable."

      Great. Except that it doesn't pertain to Spencer's challenge for several reasons. First, the chamber walls in Spencer's experiment are not "empty" space, but a material body that is being actively refrigerated, while the "enclosing passive plate" is being heated on the other side. So that plate is not in radiative equilibrium with the chamber wall or with anything else for that matter. In fact that would be impossible. There are other reasons why that description does not match Spencer's challenge, but that is irrelevant for now. One is enough.

      Dr. Spencer disagrees: "Eventually the second plate will also reach a state of equilibrium, where its average temperature (letâ(TM)s say 100 deg. F) stays constant with time."

      It is unfortunate that Spencer plays almost as fast-and-loose with terms as you do. That is a steady state. It is NOT "equilibrium". They are different things.

      If you don't particularly mind, could we finally take the very first step in this calculation? Please?

      Yes, I mind very much. There is no point in doing any calculations at all until we rid you of the false assumptions you have been making about this experiment (as I have been trying to do). They h

    40. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Thermodynamic equilibrium is when every object is in thermal and radiative equilibrium as its surroundings.

      Not a single object in Spencer's described challenge -- at any time -- meets these criteria. When everything is in thermal equilibrium -- as you have noted -- they are all at the same temperature. That never happens here.

      The passive plate MAY be said to reach radiative equilibrium at some point... I stated that incorrectly before, and I apologize for doing so. I'm correcting it here so we don't have any misunderstandings.

      There is no thermal equilibrium. Period. None. There MAY (and eventually would) arise a condition of radiative equilibrium for the (enclosing, passive, however you want to describe it) plate. But the other objects (heat source and chamber walls) do not meet this criteria because they are heated/cooled by means that may be other than radiative. "The system" is not in radiative equilibrium.

      Without thermal equilibrium (which unequivocally does not occur here), Kircchoff's law does not apply, except perhaps in coincidental specific cases. It may not be assumed.

    41. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      To be even more clear, because I want to eliminate all misunderstands, this statement that I made above is incorrect:

      Great. Except that it doesn't pertain to Spencer's challenge for several reasons. First, the chamber walls in Spencer's experiment are not "empty" space, but a material body that is being actively refrigerated, while the "enclosing passive plate" is being heated on the other side. So that plate is not in radiative equilibrium with the chamber wall or with anything else for that matter. In fact that would be impossible. There are other reasons why that description does not match Spencer's challenge, but that is irrelevant for now. One is enough.

      Mea culpa. The outside of the enclosing passive plate would eventually reach radiative equilibrium with the chamber walls. But not thermal equilibrium. Further, the inside of the passive heated plate would reach radiative equilibrium with the heat source. But not thermal equilibrium in that case either. Nor, for that matter, is that same plate in thermal equilibrium even with itself, since realistically its inside and outside surfaces must be at different temperatures, in order to be at radiative equilibrium with those opposing surfaces.

      Because I was incorrect to state that there is no radiative equilibrium, I was incorrect to state that a roughly analogous situation does not apply to Spencer's experiment. The opposing surfaces do reach radiative equilibrium. But it is still not very relevant here, because thermal (and therefore thermodynamic) equilibrium still does not exist.

    42. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Meh. It seems there is no end to clarifying. But it is also simplifying, in a sense, because it is eliminating irrelevant sidetracks:

      I can conceive of a situation in which an enclosing, passive plate, of specific dimensions, might manage to be the same temperature on the inside and the outside in these circumstances. But I'm not going to bother getting sidetracked trying to do the calculations to either prove it or disprove it, because if it ever arose at all it would be a very rare special case, and whether it does or not is irrelevant to the central point.

    43. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Once again, no. I never said that all surfaces were at the same temperature. I've already explained that the final outer temperature of the enclosing shell doesn't happen at the same time as the initial temperature of the heated plate. Initially, the heated plate is at 150F and the enclosing shell is cooler than 100F. But because power in > power out, the plates slowly warm to a new steady-state.

      You did say it, quite clearly. I quoted you twice and linked to your web page. LATER you changed your tune. I can accept that you changed it later, but you did say it.

      Further, in your link there, you say:

      Jane's insistence that "a non-zero difference is all we need" between the heated plate's initial temperature of 150F and the enclosing plate's final temperature of ~150F was interesting. In this thought experiment [archive.today], the enclosing plate was initially cooler than 100F.

      It is interesting, because it is the heart of the matter. Since, according to the S-B relation, if we are using gray bodies as you have several times insisted we use, the direction of net energy transfer via radiation at any given time is determined solely by the temperature difference and nothing else. Therefore (this is elementary logic), a non-zero difference in radiant temperature *IS* all we need, if we are using gray bodies, to determine which body is transferring energy to the other. At no time in this experiment are the temperatures equal, so net heat transfer is always in one direction and only one direction.

      You then go on to say above:

      By the time the outer temperature of the enclosing shell is ~149.6F (accounting for area differences), the heated plate is ~233.8F.

      But you do not give any justification for this answer, you just throw it out there.

      Earlier, you explained in some detail that you had calculated this number for thermal equilibrium using Kircchoff's radiation law. But as I've explained many times now, there is no thermal equilibrium so Kircchoff's law does not apply. Try again.

      It feels as though I'm explaining to a high-school student who has never seen a physics problem before. Since the enclosing, passive plate is at all times cooler than the heat source, and therefore NET heat transfer is only outward from the heat source to that plate, then the only net energy input to the source remains the original electrical input.

      So let's put 2 + 2 together here, which is really quite simple. We don't even need any math (but I welcome VALID math, if you can think of any to offer):

      [1] Initial electrical input to heat source does not change.

      [2] Since all other components of the system at all times remain cooler than the heat source, net power transfer to the rest of the system is invariably FROM the source TO the rest of the system. Nothing has been introduced to change that.

      [3] Therefore, net input of power (energy per unit time) to the source remains a CONSTANT.

      [4] Therefore, since any temperature of the source that is higher than the initial radiative equilibrium (150 deg. F) represents higher power output from that same source, any such higher temperature would violate conservation of energy.

      Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

      NO, we do not agree with that, because as you state yourself that equation is derived from Kircchoff's radiation law, which does not apply here. Sheesh. How many different ways must I explain this?

    44. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I keep finding myself in a position where I feel I should explain, but I am at a loss as to why I should have to, because I am discussing this with someone who is supposed to have been a physics major.

      You pointed out to MIT's derivation of energy transfer between infinite gray bodies. It does not apply here because (a) we have specifically defined areas, they are not infinite, and (b) that derivation makes use of Kircchoff's law which does not apply in Spencer's challenge.

      This is a very simple but essential concept: I am not going to agree to calculations that were derived based on a physical principle that does not apply to the problem. This is a very basic concept. I do not agree with trying to solve a problem starting with invalid assumptions.

    45. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      And just to hammer it home, here it is again, as a direct quote from your website, except that I have replaced the "degree" symbol with "deg." to compensate for Slashdot's character handling:

      For the moment, letâ(TM)s pretend the enclosing shell is a thermal superconductor, so its inner temperature Tc1 is also 149.6 deg. F (338.5K). Energy conservation at equilibrium just inside the enclosing shell shows that the heated sphere will warm to an equilibrium temperature of 233.8 deg. F (385.3K)

      Here are two invalid assumptions in two consecutive sentences. The first postulates a thermal superconductor (which is neither necessary or relevant), and the second assumes a THERMAL equilibrium that does not exist.

    46. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Huh? Of course we need the emissivities to model gray body heat transfer. If you'd like to solve the simpler problem of black body plates, then we can set the emissivities to 1, but I thought you wanted to skip that simpler problem.

      Pardon me. That was a mistake on my part. I was thinking of specific wavelength emissivities and absorptivities, and was conflating that with your epsilons in my head. It was late and my thinking was muddled.

      By all means, let's use emissivities and absorptivities. But you'll still have to modify your equation if that is based on the one you borrowed from MIT. I repeat that Kircchoff's law does not apply here.

      What we have left is rather simple, except for "view factor". The view factor of the enclosing plate for radiation outward from the heat source is 1 or very close to it. The view factor of the heat source for radiation emitted by the enclosing plate is more complicated.

      Not that it matters in the latter case, since because T(p) < T(s), no matter now much of the radiation from P strikes S, no net amount is absorbed; it is all reflected, transmitted, or scattered according to S-B.

    47. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Sigh. No, again I must correct myself. I would apologize for the confusion, but I'm not the one who has been causing it. I've just been getting mixed up in the maze of your assumptions.

      Your second sentence above does not assume a thermal equilibrium. What it does, though, is violate conservation of energy.

      If the power input to the object we call the heat source is constant, and it is the only net power input to the system (the outer walls are refrigerated), then we have a contradiction.

      Enough power (for illustration we can assume your figure of 509W/m^2 but I haven't checked it for accuracy) is being input to warm the heat source to an initial temperature of 150 deg. F.

      I am aware that the enclosing passive plate will absorb power and convert it to thermal energy. But even you admit that it remains cooler than the heat source.

      Your figure of 233 deg. F radiant temperature at what you called "equilibrium" represents a constant radiative power output from the heat source greater than its initial power output at 150 deg. F. Where is this additional power coming from?

      S-B law says all the heat transfer in the system under discussion is outward from the heat source. So from whence comes this magical additional power you have calculated?

    48. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I've been explaining for over a month that the heated plate warms after it's enclosed. I realize you don't agree, which is why I'm trying in vain to get you to finally perform a single, solitary calculation of your own.

      I never said I disagree with this. Please find where I said that. On the contrary; I definitely agree that it warms. In fact it must: Spencer stipulated that it was to be inserted when it was colder than the heat source.

      I have been doing calculations. I just haven't been showing them here, because there isn't any point yet. Before there is any point to showing calculations, we must agree that certain conditions either do or do not exist, given the parameters of this experiment. That is what I am trying to sort out with you now.

    49. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      As I said: "Energy is conserved, which means that if you draw a boundary around some system (like the heated plate), power going in minus power going out equals the rate at which energy inside that boundary changes. At equilibrium, that rate is zero because the system doesn't change. So at equilibrium, power in = power out."

      I explicitly said a system in "equilibrium" doesn't change, which Jane calls "steady-state".

      I call it "steady state" because that is how radiative equilibrium is defined. It is a condition in which radiative transfer between elements of the system remains constant. I prefer to make sure this is kept distinct from thermal equilibrium.

      I just want to make sure we're all talking about the same things. Because in the past, we sure as heck were not.

      Why would Jane think mentioning Kirchhoff's law means that I'm somehow trying to claim that all surfaces are at the same temperature? I first mentioned Kirchhoff's law by linking to MIT's explanation:

      Stop being obtuse. You were throwing around the term "equilibrium" rather loosely, and at one point you mentioned that "at equilibrium" the outer surface of the enclosing passive plate must be at the same temperature as the surface at the heat source:

      Electric input of 509 W/m^2 is constant and the walls are held at 0F (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150F (339K).

      Now, if it isn't a reasonable conclusion that by this you meant thermal equilibrium, I don't what is, since you are claiming the heat source and the passive plate are the same temperature. Of course upon closer examination it could not have been actual thermal equilibrium, because you also mention the walls are at 0 degrees F, but then what actual kind of "equilibrium" you were referring to is worse than ambiguous, because at radiative equilibrium the stated condition is impossible. So why the hell are you trying to blame me for being confused? The condition you described is impossible, so how do you expect me to know what "equilibrium" you mean?

      "... the relation "absorptance = emittance" is known as Kirchhoff's Law. It implies that good radiators are good absorbers. It was derived for the case when "body temperature = cavity temperature" and is not strictly true for all circumstances when the temperature of the body and the cavity are different, but it is true if the absorptance and emittance are not functions of wavelength. This situation describes a 'gray body.' ... "

      Very well. You refuse to use real materials with measured absorptivities and emissivities, and insist on using gray bodies and Kirchhoff's law, neither of which actually represent Spencer's experiment in anything like the real world, even though it was intended to be a model of the real world.

      I get that. But I want to make sure everyone else gets it too.

      I offered to use real materials with measured emissivities in the approximate temperature range we are talking about (though you refuse to acknowledge that), but you refuse to use them.

      Just so we know where we stand. I have already explained to you that there is no need to resort to gray bodies, and that we have plenty of information to calculate more realistic, real-world results. But whatever. You refuse to do anything but what you want to do, so let's just go with it for now. But I reserve the right to re-visit this issue.

    50. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Once again, I never said that all surfaces were at the same temperature.

      Look, let's get this straight: what you actually meant was completely ambiguous for several reasons. You used the term "equilibrium" and you said:

      Electric input of 509 W/m^2 is constant and the walls are held at 0F (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150F (339K).

      Will you acknowledge that no matter what you meant, this is still wrong? If the enclosing passive plate must radiate out the same power as the enclosed heat source, it cannot be at the same temperature, because radiated power is measured in W/m^2, and there are more m^2 in the enclosing passive plate. Therefore (SIMPLE MULTIPLICATION), because there is greater area they could not be at the same temperature and radiate outward the same power.

      No matter how you try to bullshit your way around this, it is still WRONG.

    51. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      It's just so hard to work my way though your maze of comments, some of which are correct, and others which are provably bullshit (see my other comments above).

      THE FIRST STEP in mutually working your way through a problem is agreeing on the statement of the problem, as you well know. THAT is why I have not willing to get into calculations yet. That and nothing else. So let's make sure we agree on the statement of the actual experiment. I want you to acknowledge these in so many words, before I am willing to move forward. Because I'm just plain tired of your bull.

      1. Conditions apply as per Spencer's experiment:

      2. Constant input power sufficient to heat the source to a radiative temperature at radiative equilibrium of 150F.

      3. Outer chamber walls actively cooled to a maintained radiative temperature of 0F.

      4. Passive plate (which you insist in your variant of Spencer's challenge fully encloses heat source, with vacuum between).

      5. Passive plate is introduced at a temperature that is cooler than the heat source.

      6. Any other conditions that were actually contained in Spencer's challenge but not mentioned here.

      7. Your own condition: you insist on using gray bodies, because you claim you're dying (or something of the sort, you really didn't specify so I won't assume), you don't have the spare 15 minutes or so it might take to do approximate, more real-world calculations, and want to use Kirchhoff's law (although it really isn't necessary) to make your life easy.

      8. I reserve the right to re-visit this same scenario using more real-world materials, emissivities and absorptivities.

      Are we agreed on these conditions? I want a simple yes or no. Anything else, and I am not willing to continue.

    52. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I've been explaining for over a month that the heated plate (aka Jane's "source") warms after it's enclosed.

      Yes, you've been explaining it but you haven't been backing it up. See my other comment. Once we agree on the statement of the problem, we can move forward. I haven't been trying to block you, I've only been trying to get you to unambiguously agree to terms.

      If Jane agrees that the heated plate (aka Jane's "source") warms after it's enclosed, then that's great news! In that case, we can all agree that the mainstream physics describing the greenhouse effect is accurate, obeys the laws of thermodynamics, and proves that the Sky Dragon Slayers are wrong.

      No. Jane does not agree that "the heated plate" (if by that you mean THE HEAT SOURCE), gets warmer when it's enclosed. THIS IS WHAT I'VE BEEN TRYING TO TELL YOU.

      You need to use more precise language. In plain English, you have one heat SOURCE in this experiment, and THE OTHER plate is being "heated" by it. So the "heated plate" is the passive plate.

      You insist on using confusing terminology, and wonder why other people have a hard time with it. Jesus, I'm glad you weren't one of my physics profs.

      I suggested a standard terminology and variable names to avoid exactly this problem. You have refused to use them. That's your goddamned problem, and you don't get to complain about it.

      I'm really looking forward to showing this latest exchange to my friends.

    53. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Once again, no. I've repeatedly explained [slashdot.org] that the outer surface of the enclosing passive plate is never at the same temperature as the heat source.

      And once again, NO, it doesn't matter. I don't care at what time you assume this to be. Because we have a constant power input which has radiative power output at X W/m^2, which is required to reach the radiative temperature of 150F.

      You then (at ANY time, I don't care when) claim that a larger surface is at the same temperature, which requires the same amount of W/m^2. But you have more m! So the total power output is greater than your input.

      There is no way to weasel out of this, man. You're trying to output more power than you're putting in. This isn't even 11th-grade physics.

      Let's try it at something more like your level:

      You have 200 beans equally distributed among 10 squares. If you now take those beans, and divide them equally among 25 squares of the same size, how many beans do you now have per square?

      Show your work.

    54. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Cute. I've repeatedly explained ad nauseum that neglecting area ratios is an approximation. I've already shown how tiny the effects are for Earth's area ratio. Does this mean you don't intend to perform even the simplest calculation to confirm this? Why don't we check to see wrong these approximations are, by actually doing some calculations? Finally? Please?

      THERE'S NOTHING "CUTE" ABOUT IT!

      IT'S AN ACCURATE ASSESSMENT OF YOUR ERROR!

      This is not "approximation", it's fucking logical error! JESUS CHRIST, man, you can't talk your way around this.

      X / 3 = X / 3.

      X / 6 < X / 3

      End.

    55. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      If your time is really short as you say, then just abandon those recent sidetracks (which is in your own best interest anyway) and let's continue.

      If you agree to the problem description I laid out above, in this comment, just say yes. Then we can continue.

      But I will repeat, and keep repeating as long as necessary, that unless we agree on what it would take to refute Latour, then there is no point in going further. You can violate thermodynamics all you want, and it doesn't prove a damned thing.

    56. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      You're sidestepping again, and you're ignoring the important point, again.

      This is a sidetrack, about an OLD comment you made that was stupid and inaccurate. You can argue about THAT comment until the cows come home and die of old age, and you still won't be correct. BUT IT'S IRRELEVANT TO THE POINT NOW AT HAND.

      If you want to move on, see my other comments which describe the problem. If you continue to refuse to agree to the definition of the problem, I will (with every justification in the logical world) declare you in default.

      STOP THE BULLSHIT. It is pretty obvious what it would actually take to refute Latour. I have described in my other comment a statement of the actual challenge. If you refuse to agree with my description of the problem, without having a reasonably valid objection, I shall (with perfect justification) declare you in default.

    57. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      BEFORE you do the math, the problem must be defined. No reasonable scientist would disagree with that. So far, you have refused at every turn to define the problem, even though this is the well-known first step to proving anything.

      If you continue to just bullshit your way around, as I have stated I will declare you in default and damned few reasonable people would disagree.

    58. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      NO. See my comment above. One more bullshit comment like this, and as I said, I will just call you a clown and few reasonable people will disagree.

      Will you, yes or now, agree to the definition of Spencer's experiment, as I have already described and asked you now about 3 times.

      That is the FIRST step in solving any problem. I will not agree to any math regarding the problem until we have an agreement about what the problem is. Anything else is nonsense.

      ONCE THAT IS DONE, I agree to move on with calculations about the problem before us.

    59. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I asked for a simple yes or no. You did not give me a simple yes or no, you had to bury it in the middle of about 500 words about other things. If you had simply written "yes", one word, you would have saved both of us about 20 minutes.

      I am entirely convinced that you are deliberately trying to make things difficult.

      SO... you have agreed. Now we may proceed with calculations. But I will not, more, tonight.

      But -- and this is no joke -- I expect you to show and describe your work. We start from extant conditions and proceed from there, in a step-wise manner. My intent, as it was before, is to minimize confusion and misunderstandings, which it is pretty obvious have been rampant. So... as is often the case in programming, if we proceed slowly in a step-wise manner, we achieve the end result all the sooner, because errors don't crop up.

      I was serious about this: you have had a tendency to make assumptions and use terms loosely. We have had LOTS of misunderstandings here, and I am willing to chalk some of them up to communications problems, but not all of them.

      So let's go slowly, and start simply. The first step is to define the initial conditions. We have a fixed power input, which heats the "source" (and I am calling it that for good REASONS), which we are assuming is a spherical body. Specific dimensions are up to you, I really don't care very much, although I have to wonder why you picked radii that seem so inconvenient... but on the other hand I admit that I did not do any calculations at this point using your dimensions
      So, since we are starting fresh, describe your equation now, what the variables represent, and how you arrived at the formula. I suspect that it is a bit premature.

      I will check in again tomorrow.

    60. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      You are a bit too eager to "pounce" with your solution. There was no need to repeat it 3 times. "I say it 3 times" does not make your analysis correct. Only correct analysis will. I will proceed from this post.

      Once again, you zoomed ahead and did not proceed carefully. You are overlooking things. If you want this to be an actual solution of the problem, then let's do the problem completely. I have stated several times that I am only willing to do this if you agree to do it thoroughly.

      Once again, energy is conserved, which means that if you draw a boundary around some system (like the heated plate), power going in minus power going out equals the rate at which energy inside that boundary changes. At steady-state, that rate is zero because the system doesn't change. So at steady-state, power in = power out.

      I agree, as long as you can legitimately draw a boundary around your system. So let's start out by drawing appropriate boundaries around out initial system.

      I agree with your calculations for area. However I do not agree with your calculation for initial power output (which corresponds to our constant input).

      We know the initial temperature of the heat source: 338.7K.

      The acknowledged formula for finding radiative power from temperature is just (sigma epsilon)T^4. There are no other factors involved, so our power input is equivalent to the power output of the heat source. There is no reason to not assume perfect efficiency here. You don't show your work here, just an unreadable Sage file, so I don't know where the discrepancy lies.

      This formula for radiative power output from radiative temperature and the corresponding formula for temperature from power both make use of (sigma epsilon), and epsilon is a scalar, so I will abbreviate it to (se) and pre-calculate it to make later calculations easier (I am using an HP, not Sage):

      (se) = ((5.67 * 10^-8 W/m^2) / K^4) * 0.11 = (6.24 * 10^-9 W/m^2)/K^4

      So here now is the reason for this preliminary setup: in our initial steady-state, heat source is 338.7K so total power output from the heat source (and therefore constant power input to the system) is just (se) * 338.7^4 * area

      Therefore radiative power (W/m^2) = (6.24 * 10 ^-9) * 338.7^4 = 82 W/m^2

      So then the total power of the heat source is 82 W/m^2 * 510.064 m^2 = 41.886 * 10^3 W

      This does not seem like an unreasonable figure for heating a 12+m dia. sphere with 510 m^2 surface area to 150F.

      So who is wrong and why?

      No point in going further until we straighten this out.

    61. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      YOU are contradicting yourself: "Power out = power in", you said. Right?

      I have calculated the radiative power output using nothing more than area (~ 510 m^2), radiative temperature (338.7K), the emissivity you gave (0.11), and the well-known and proven relation:

      Radiative power out (in W/m^2) = emissivity * sigma * T^4, where sigma is the Stefan-Boltzmann constant.

      This is the textbook solution. Please show where it is incorrect. Simply asserting that it is incorrect is not sufficient.

    62. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      One way to see this is to consider how much power the electrical heater would need if the chamber walls were also at 150F. The correct answer is zero watts, because the heated plate wouldn't lose net heat to walls at the same temperature. But since your expression doesn't depend on the chamber wall temperature, you wouldn't be able to obtain the correct answer of zero in that case.

      No, I am not wrong, you are. You are describing a radiative power difference, or net transfer.

      That is not what I was doing. I was simply calculating the net power output of the heat source at 150 deg. F using the textbook example of how to do that.

      It is not a difference. It is a constant radiative power output that depends on NOTHING else but temperature and emissivity, and the S-B constant.

      It doesn't matter what temperature an opposing surface is at. I'm calculating the power output of THIS surface, at THIS temperature. As long as the temperature OF THIS SURFACE remains the same, the radiative power output remains the same. The way to calculate it is well-known and I have clearly stated it in my calculations.

    63. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      The required electrical power to keep the heated plate at 150F is completely independent of the chamber wall temperature?

      No. That is not what I wrote. You are drawing a conclusion that does not follow from my actual words. Making assumptions again.

      It is dirt simple to show you are wrong.

      The initial conditions, with the surface of the heat source at 338.7K, ARE A STEADY-STATE. The radiative transfer between the surface of the heat source and the chamber wall is already accounted for. You are trying to account for it twice. It is easy to show this.

      The temperature of this surface is a GIVEN, initial steady-state condition. It is known, and a constant at this time. YOU are trying change it, and give one surface 2 different temperatures at the same time.

      Proof: all we have to do is plug your value for radiative power output back into the known, canonical equation for radiative temperature.

      Temperature is the 4th root of ( (power in W/m^2) / (se) ). So using your calculated value: 4th root of ( (29.399) / ((6.24 * 10^-9 W/m^2) / K^4) ) = 4th root of 3749839743.59 = 247.46K = -14.24 degrees F.

      However, we already know what this temperature is, because it's a given:: 150 deg F (338.7K).

      Your value gives a wrong answer. Your methodology contradicts itself, which is what I have been saying all along.

      Plug my 82.12 W/m^2 back into the same canonical equation for radiant temperature for a given radiative power output, and the answer comes out just as it should: 150 degrees F.

      If you can't even get the initial conditions right, we might as well stop here.

    64. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I calculated the radiant power out from a surface of ~510 m^2 at 150 degrees F, using the canonical textbook formula for doing so.

      I did nothing more. I did not need to do anything more. The system is in a steady-state and the temperature is known.

      Wait... I did do something more. I also showed that your own calculation was incorrect.

    65. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      You have not only made assumptions that don't actually apply, you have thrown around equations without carefully considering how they apply to the clearly stated problem. I said this in the beginning, and I have proven it now.

      We already know, at the given steady-state, that the heat source is at 338.7K. We already know it is a sphere with a surface area of approximately 510 m^2. You have insisted we assume that it is a gray body. Given those two numbers, the emissivity, and the Stefan-Boltzmann constant, we calculate the power out: 82.12 W/m^2.

      We do not need to do anything else at this point. We already know that this is the temperature GIVEN any heat transfer to the walls... which we have not calculated yet. I was going to go on to do that, but it isn't necessary now. We've seen that you're already wrong.

      This was precisely why I insisted we do this slowly and carefully, and explain our steps. Because I knew you were doing it incorrectly (I said so) and that it would show up in the calculations. I did not expect it quite this soon, but there it is.

      YOU may not understand that I have already proved your "refutation" wrong, but I assure you that other people will have no such difficulty. And they will have ample opportunity to see this, because I'm going to post it all online.

    66. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I wasn't TRYING to calculate heat transfer. I was only calculating radiative power out. That was a necessary step to THEN going on to calculate the radiative power of the chamber walls, and THEN calculating the net heat transfer.

      The TEMPERATURE of the heat source does not depend on heat transfer. It is an independent variable. On the contrary: the net heat transfer depends on the temperature, not the other way around.

      We have already seen that you have mis-applied your equation and arrived at a power out figure that gives an incorrect value of temperature, which is an already known value.

      Your "refutation" is disproved, almost before we've properly begun.

      QED

      I don't care if you don't understand that. Other people will.

    67. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      If you want to be clear, then let's be clear:

      I was not trying to calculate electricity. I was merely calculating radiative power out of the heat source at a known temperature.

      The next step (because, as I have repeatedly stated, I am going slowly and carefully, in a step-wise manner) would have been to calculate the radiative power out of the chamber walls.

      I was not calculating any heat transfer. On the contrary: heat transfer is dependent on those two values. I hadn't even calculated the second value yet.

      I have been very straightforward and clear about what *I* am doing.

      Furthermore, your value for electricity is completely irrelevant to the problem at hand, which was to calculate internal temperatures under the given conditions.

      In these initial conditions, I'm stating that the radiant power of the heat source is 82.12 W/m^2.

      I admit that I made an error somewhere, and plugged in the wrong number. 29.4 / (6.24 * 10 ^-9) is indeed 4711538461.55, and the 4th root of that is 261.99K, or 11.91 degrees F.

      However: as you have said, let's be clear: you throw around terminology fast and loose, and you have refused to show your calculations, which leads to misunderstandings. So: what, then, do you claim that 29.4 W/m^2 figure represents and why?

      I don't give a rat's ass about "electricity" at this point. The radiative power, (we are using units of W/m^2) of a gray body surface depends only on its temperature, its area, its emissivity, and the Stefan-Boltzmann constant. I do not need to know what the net heat transfer is to calculate this value (which IS 82.12 W/m^2 at the surface of the heat source under the given conditions). The total radiated power in Watts is: W/m^2 times the area. This is all pure textbook stuff. It matters not a whit at this point what that radiation strikes AFTER it is emitted. Even considering that right now is premature.

      If I misunderstood, and your 29.4 W/m^2 represents something other than radiative power at the surface of the heat source at 338.7K, then please state clearly in plain terms what it IS supposed to represent, so we can move on.

      The next step in the problem I am analyzing, because as I stated I am doing this in a careful stepwise manner precisely to avoid these misunderstandings is to calculate the radiative power of the chamber walls at 0 deg. F, or 255.37K.

      But let me be clear: I don't give a damn about electricity at this point. In fact, I don't give the slightest damn whether the sphere is heated by steam, or an internal campfire, or burning unicorn farts. We know the power required for a gray body of the given area and emissivity to have a radiative temperature of 338.7K.

      That is all I was saying. Nothing else. Trying to assume what I'm doing with that number before I do it is magical thinking.

    68. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      It's not a matter of the equation. I repeat: you jumped way ahead, and used a shortcut. That's not what I am doing, and that's the source of the problem here.

      I've only calculated the radiant power value of one surface so far! I haven't even calculated the second yet. So how you could you possibly think I had calculated net heat transfer?

      I'm not trying to calculate your "electricity" value. I don't want to calculate your electricity value. I'm starting from the basics, and working all the way through. I'm not using your shortcut. Is this clear?

      Do you have a problem with my formula for calculating radiant power of a gray body surface at a given temperature? If not, I will continue. I repeat: it isn't dependent on any heat transfer, the only variables are emissivity and temperature. With that, and the Stefan-Boltzman constant, you can calculate the radiant power value.

    69. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      If you want to be technical, what I calculated is variously called irradiance, radiant emittance, radiosity, or radiant exitance. And sometimes "emissive power", and probably by other names too.

      It is not radiant flux, or radiant energy. Nor is the irradiance (I'll use that term from now on for clarity) of the heat source I calculated dependent on the chamber wall in any way. I repeat: the only variables for calculating this value for a gray body are temperature and emissivity. It is independent of any other object, and it is independent of absorbed incident radiation.

    70. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Very well. As I say I'm doing intermediate calculations for later.

      So initial irradiance of the heat source at 338.7K is 82.12 W/m^2

      Initial radiative output of heat source at 338.7K is 82.12 W/m^2 * 510.065 m^2 = 41886.54 W

      Irradiance of the outer wall at 255.37K = (se)T^4 = (6.24 * 10^-9 W/m^2) / K^4 * 255.4^4 = 26.55 W/m^2

      We agreed on gray bodies, so absorptivity = emissivity = 0.11.

      The "view factor" from the spherical heat source to the chamber wall is 1. All radiated output intercepts the wall.

      Incident radiation on chamber wall: 41887W / 512.469 m^2 is 81.73 W/m^2

      81.73 W/m^2 incident radiation * 0.11 absorptivity = 8.99 W/m^2 absorbed.

      So transfer from source to walls is = 8.99 W/m^2 absorbed * 512.469 m^2 = 4607.09 W

      This makes perfect sense, since the areas are not that much different and the absorptivity is only 0.11.

      Are we in agreement so far? I know I'm taking the long way around. I said I would.

    71. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I didn't assume a black body. But whatever.

      We understand that I'm still working on the initial conditions, correct? There is no "enclosing plate" at this point.

      You can also ignore the latter part involving absorbed radiation for now. It isn't really relevant to anything I am doing at this time.

      It would seem that the next logical step would be to calculate the net power loss of the heat source to its surroundings under these conditions, applying the Stefan-Boltzmann law directly. Using the same variable names I used earlier:

      power = (se) * radiating area * (T(s)^4 - T(w)^4) = (se) * 510.065 * (338.71^4 - 255.37^4) =

      (6.24 * 10^09 W) / (m^2 *K^4) * 510.065 * (13,161,702,663.0 - 4,252,844,523.22) = 28387.68 W

    72. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, I have no intention of finishing today. I am busy and I have been putting in what little time I have had to "spare".

      Please explain why conductivity is relevant. We are examining the system in steady-state.

      The plate is inserted into the system colder than the heat source (Spencer's stipulation).

    73. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I objected to thermal superconductors because they led to contradiction.

      I am curious: how do you propose to calculate the outer temperature first?

    74. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      So you object to calculating heat transfer via radiation by using radiative transfer equations?

      By the way: upon looking at the situation more closely, I found that applying the S-B law directly does not apply in this exact situation. (I looked because it gave a much different answer than the one I had already calculated.) It applies when a body is radiating to its ambient surroundings, not between two bodies. (We don't have "ambient" surroundings per se... just vacuum between 2 bodies.)

      My first method of calculating the heat transferred was the correct one: ( (epsilon) * (sigma) * T(s)^4 * Area(s) ) - ( (epsilon) * (sigma) * T(w)^4 * Area(w) )

      Factoring out (es) you get ( T(s)^4 * Area(s) ) - ( T(w)^4 * Area(w) ), which only holds of course when e = a.

    75. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      At the original steady-state without the shell, the net radiative power leaving the source equals the constant electrical power heating the source. This constant power doesn't change even after the shell is inserted.

      Yes, this was one of the reasons I took the time to calculate the irradiance = radiative power output / m^2.

    76. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      We already know what the radiated power output of the heat source is, given the initial conditions, which I calculated via a far simpler and unambiguous equation which we know to be relevant: (epsilon)(sigma)T^4.

      No "electricity" needed. Your "electricity" figure is NOT the "power out" of the heat source. It is a figure for total power consumed that I do not agree applies in this instance, since we have a refrigerator on the outside which also consumes power.

      To put it another way, your "electricity" figure is not power output of source it is a figure for a DIFFERENCE, which I do not agree applies in this instance.

      Again, using (epsilon)(sigma)T^4:

      Radiative emittance of heat source under initial conditions: 82.12 W/m^2

      You already agreed with this figure.

      Total radiative power out = (82.12 W/m^2) * (510.065 m^2) = 41886.54 W

      You are contradicting yourself. Either this is the correct figure, or it is not.

    77. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Never mind. I will back up on that, at least for now.

      If we assume that power output of the exterior surface of the enclosing shell is the same as it was from the heat source under initial conditions (something I am not yet ready to stipulate, since we are not at thermal equilibrium), I calculate a temperature, using my own shown above, at 338.49K.

      However, I want to make this clear: I am not convinced that your power in = power out assumption is correct in this case, because we have a refrigerated outer shell, which also consumes power (we do not yet know how much), which keeps things OUT of thermal equilibrium. We are adding power in the center, and we are removing power at the outside. But because of Spencer's conditions, I am not convinced at this point that we can assume power is conserved.

      If everything were at thermal equilibrium, I would be convinced. But at the very least, we would have to calculate the difference between power consumed by the refrigerator on the outside, between initial and final conditions. Do we have enough information to do that?

      What is the ambient temperature? What is the volume of the chamber wall?

    78. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Energy is always conserved.

      Of course it is.

      Let me rephrase what I was saying: at least theoretically, the power at the chamber wall is allowed to vary, in order to keep the temperature at 0 degrees F.

      But, if we draw a boundary around the system, and assume that the ONLY power in is what we put in, and the ONLY power out is what is removed, then of course it must be conserved.

      I was simply expressing my concern that your electricity figure may not be properly observing those boundaries. If your electricity figure is simply power in - power out, I fail to see why you need to calculate it in such a fashion. I think it is an unnecessary complication and potential source of error.

    79. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Perhaps it would be more informative if you calculate ENERGY in and ENERGY out, since that is what is actually conserved.

      You seem to keep forgetting that (A) power is a RATE, not a unit of energy, and (B) we are not at thermal equilibrium.

      Classical example from Wikipedia: running up the stairs requires more power than walking up the stairs, because more energy is expended per unit time. (Granted, the time period is also shortened, but it still illustrates that they are not the same.)

      Let me give you a physics example: We have a gray-body hemisphere, emissivity 0.5, with radius of the flat surface 1.00 m and temperature T of 200K. We do NOT assume thermal equilibrium.

      The area of the curved part is 6.28 m^2, of the flat part is pi, so the total area is 9.42 m^2.

      We have incident radiation hitting the flat surface of 229.64 W/m^2. (We draw a "boundary" around our hemisphere, so that is our "system", and the incident radiation is the only "power" input.)

      Our total input -- our ONLY power input -- is 229.64 W/m^2 * pi = 721.44 W.

      Total amount absorbed = 721.44 * 0.5 = 360.72 W.

      Emittance is 0.5 * sigma * T^4 = 0.5 * 5.67 * 10^-8 * 1600000000 = 45.36 W/m^2

      Total power output in this case is emittance + unabsorbed incident radiation, which would normally be "radiosity", except radiation is only being absorbed on one surface. (I.e., our "view factor" F is only 1/3.)

      Since emissivity = 0.5, total "reflected" (i.e. unabsorbed) radiation is 360.7 W

      Total power out then is 45.36 W/m^2 * 9.42 m^2 = 427.29 W + 360.72 W = 788.01 W.

      788.01 W != 721.44 W (!!!) Power is not conserved.

      Obviously this does not represent radiative steady-state.

      Now let's take an even simpler example: a black body sphere of surface area 1 m^2 inside a spherical "black body cavity" with area of 2 m^2, at thermal equilibrium.

      Obviously, since radiative power = (epsilon)(sigma)T^4, both surfaces are radiating the same power in W/m^2.

      However, the inner surface of the cavity has twice as much area, so the total power radiated is twice as much. Power is not conserved.

      If you tried to argue that the increased power would warm up the interior sphere, then you're no longer in thermal equilibrium.

      So... are you suggesting that if I hollowed out enough of a mountain to make a hollow rock sphere (assume the rock is diffuse gray body) 1000 m diameter, suspended a 1m dia. sphere of the same rock in the center, and evacuated the cavity: the inner sphere is going to get much hotter than the surrounding rock?

      Power in = power out would seem to demand that very thing.

    80. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Correction to one of the equations above. Total power out then is (45.36 W/m^2 * 9.42 m^2 = 427.29 W) + 360.72 W = 788.01 W.

    81. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, before you jump all over my black body example, I am aware that view factor has to be taken into account.

      But that is actually part of my point: a simple power-in = power-out view is not always the right answer.

      It is true that the interior of the cavity is radiating twice as much power out. There is a view factor involved, which may account for the difference. But the view factor does not involve power output of the radiating body. We know what that is. Much of it is being re-absorbed by the interior of the cavity, true. But it shows how power-in = power-out calculations can easily mislead.

    82. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Further, the above example of the black body suspended in the black-body cavity at thermal equilibrium shows why your "conservation of energy just inside the heated plate surface" is more complex than you make it out to be.

    83. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      I will do you a favor here, and say: don't bother to go calculating the energy, either.

      The problem is that an analysis of this kind, based on the assumption that power-in = power-out, is doomed to fail except in coincidental cases. Even conservation of energy can give very misleading results.

      The black body example I gave shows why your "energy conservation just inside the surface" won't work. Aside from just "view factor" and a few other things, a certain amount of the power in (often a very significant amount) just ends up going right back out, but you often don't see that in the formulas.

      Quote from one of my references, "Fundamentals of Heat and Mass Transfer", by Inropera, et al., 6th edition, 2006, p13. I have to type this in by hand from the book so any typographical errors are mine. Emphasized words have been capitalized.

      Relationship to Thermodynamics

      At this point it is appropriate to note the fundamental differences between heat transfer and thermodynamics. Although thermodynamics is concerned with the heat interaction and the vital role it plays in the first and second laws, it considers neither the mechanisms that profide for heat exchange nor the methods that exist for computing the RATE of heat exchange. Thermodynamics is concerned with EQUILIBRIUM states of matter, where an equilibrium state necessarily precludes the existence of a temperature gradient. Although thermodynamics may be used to determine the amount of energy required in the form of heat to pass from one equilibrium state to another, it does not acknowledge that HEAT TRANSFER IS INHERENTLY A NONEQUILIBRIUM PROCESS. For heat transfer to occur, there must be a temperature gradient and, hence, thermodynamic nonequilibrium. The discipline of heat transfer therefore seeks to do what thermodynamics is inherently unable to do, namely, to quantify the RATE at which heat transfer occurs in terms of the degree of thermal nonequilibrium. This is done via the rate equations for the three modes ...

      Heat transfer requires a temperature gradient, and therefore thermodynamic non-equilibrium (as we established early on). I was hoping you would catch on that this also implies that power-in = power-out is not necessarily true, and in fact that is probably a very rare exception.

      Therefore, you aren't going to prove anything with this approach. I wanted to stop you before you wasted more of your time.

    84. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No. I've repeatedly told you that power in = power out demands that an unheated inner sphere will be at exactly the same temperature as the chamber walls.

      That isn't quite what you said. This is what you said:

      One way to see this is to consider how much power the electrical heater would need if the chamber walls were also at 150F. The correct answer is zero watts, because the heated plate wouldn't lose net heat to walls at the same temperature. But since your expression doesn't depend on the chamber wall temperature, you wouldn't be able to obtain the correct answer of zero in that case.

      I already understand this, and I mentioned it myself in the post above. My point was that it does not translate directly into power in = power out at a boundary just inside the cavity surface. It most certainly does not if the bodies are not in thermal equilibrium, which again I must point out this system is not in. See my reference again. By the way, the author is Incropera, not "Incopora". Slip of the keyboard, there.

      As for the rest, I am out of time right now and will reply tomorrow if I have more time.

      Just one last closing comment tonight, though: I am aware that energy in a system must be conserved. But "system" is not anywhere you choose to draw a line. In the case of heat transfer, energy does not have to be conserved between two bodies at different temperatures. That was what Incorpora was saying in his book. And that is why I balk at your "conservation of energy just inside the surface".

    85. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Damn. Finger slipped again.

    86. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      The reason my "dirt simple" calculation was wrong, as any reader of this exchange should be able to tell (and so should you have), that I misunderstood what your power figure represented.

    87. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, of course I got the same answer, given your assumption that power-in = power-out: 149.59F.

    88. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Are you also then presuming that power transferred from the outer surface of the enclosing plate to the chamber walls is the same as the power transferred from the heat source to that plate?

    89. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No. Energy is always conserved. Always.

      Did you actually read what I wrote?

      Just no. Energy of an entire system is conserved. It need not be conserved between individual elements of that system. That's what I've been saying.

      HEAT TRANSFER is expressed in Joules. What it is a Joule? It is a unit of energy.

      HEAT TRANSFER is always in one direction. Heat transfer between two bodies that are not at thermal equilibrium does not conserve energy between those two bodies. On the contrary: it is a flow of energy in one direction. If energy was conserved between those two bodies, then no heat transfer could take place and they must necessarily then be in thermal equilibrium. But the bodies in this system are NOT in thermal equilibrium.

      Are you getting that yet?

      I did not claim energy was not conserved for the entire system. I claimed only what is obviously true, and what textbook physics tells us is true: heat (energy) transfer between two bodies that are not at thermodynamic equilibrium is not required to conserve energy between those two bodies.

    90. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      And also obviously, I was referring to NET heat transfer.

    91. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Obviously at radiative equilibrium energy between objects in the system is being transferred at a constant rate.

    92. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I'm not sure I agree with your wording. It could easily be misinterpreted to mean something it does not.

      I agree that power in minus power out of your boundary equals power through that boundary, which at radiative steady-state represents a constant rate of energy flow through that boundary.

      Please continue.

    93. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Given your assumptions so far, I will not dispute your calculation of the temperature of the inner surface of the enclosing plate.

      Please continue your calculations, as a reply to my other comment, so we can continue this exchange in a linear fashion.

    94. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I prefer my wording, which I think most people would agree is an equivalent statement regarding your drawn boundary, but (in my opinion) is less open to misunderstanding.

      I agree that power into your boundary minus power out of your boundary equals the power through the boundary, which at radiative equilibrium is equivalent to a constant rate of energy flow through that boundary.

      Were you trying to say something else? If not, let's please move on.

    95. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Since you keep place qualifiers on energy conservation, your wording isn't equivalent to mine because my statement applies even for systems that aren't in radiative equilibrium.

      But that should not matter because we are discussing a system in radiative equilibrium. If it were in disequilibrium, the only change would be the removal of "radiative equilibrium" and the word "constant", since it is radiative equilibrium that forces it to be constant.

      I don't necessarily have a problem with a broader definition, but I prefer to stick to things that are pertinent to this discussion.

      So can we move on?

    96. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      But the other objects (heat source and chamber walls) do not meet this criteria because they are heated/cooled by means that may be other than radiative. "The system" is not in radiative equilibrium.

      But that should not matter because we are discussing a system in radiative equilibrium.

      Really? Since when?

      Sigh. We've already had this discussion. That upper quote was from 5 days ago, and we quickly established that it was incorrect. Since then, we went on to agree that at steady-state, the system is in radiative but not thermal equilibrium. Are you now retracting that agreement? Because there is definitely no thermal equilibrium, and without at least radiative equilibrium, there is no equilibrium at all and we might as well just stop again right here. Here is my later comment, in full:

      To be even more clear, because I want to eliminate all misunderstands, this statement that I made above is incorrect:

      Great. Except that it doesn't pertain to Spencer's challenge for several reasons. First, the chamber walls in Spencer's experiment are not "empty" space, but a material body that is being actively refrigerated, while the "enclosing passive plate" is being heated on the other side. So that plate is not in radiative equilibrium with the chamber wall or with anything else for that matter. In fact that would be impossible. There are other reasons why that description does not match Spencer's challenge, but that is irrelevant for now. One is enough.

      Mea culpa. The outside of the enclosing passive plate would eventually reach radiative equilibrium with the chamber walls. But not thermal equilibrium. Further, the inside of the passive heated plate would reach radiative equilibrium with the heat source. But not thermal equilibrium in that case either. Nor, for that matter, is that same plate in thermal equilibrium even with itself, since realistically its inside and outside surfaces must be at different temperatures, in order to be at radiative equilibrium with those opposing surfaces.

      Because I was incorrect to state that there is no radiative equilibrium, I was incorrect to state that a roughly analogous situation does not apply to Spencer's experiment. The opposing surfaces do reach radiative equilibrium. But it is still not very relevant here, because thermal (and therefore thermodynamic) equilibrium still does not exist.

      My comment was in reference to whether this system is in thermal equilibrium, because I claimed (correctly or incorrectly), that Kirchhoff's Law did not apply. You produced a reference that it did apply to gray bodies even if not in thermal equilibrium, so I agreed you could go on with Kirchhoff's Law and see where it led.

      So that was the state we were in when we continued: no thermal equilibrium, but I understood that we had agreed that the hollow spherical passive plate must be in radiative equilibrium with its surroundings, since there is no other input or output allowed.

      Your wording could easily be misinterpreted to mean a constant other than zero. Didn't you mean that net power through that boundary at radiative steady-state represents zero energy flow through that boundary? If not, our misunderstanding is much more fundamental than I first thought.

      No, I very definitely did NOT mean net power at radiative steady-state represents zero energy flow. There is heat transfer which is energy, which represents NET flow in one direction. That's what heat transfer is: an energy IMBALANCE, which means non-zero.

      Example 1: If you draw a boundary around the burner of a gas furnace, inside the colder walls of the furnace, the RADIANT energy flow into and out of that boundary is NOT a net zero. It is definitely a positive number, from burner across the boundary to the wall. That energy is heat transfer .

      However: there IS p

    97. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Now, again in the interest of avoiding misunderstanding:

      In our system, there IS input to the heat source, which obviously must come from outside. And in that sense (much like the gas burner), it is relevant to say that the net energy flow through that boundary is zero. I certainly do agree with that.

      But that was the whole point of my attempts to word things precisely: so that this kind of misunderstanding does not arise.

      If you meant zero net energy across your boundary, including the power input to the heat source, then yes of course I agree that the net must be zero. At steady-state, you won't be putting more out than you put in, or vice versa.

    98. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Since we've had to agree to disagree about the definition of the term "equilibrium" (whether radiative or thermal), it's necessary to agree on the fundamental principle of energy conservation using a simple statement that doesn't use the term "equilibrium" (of any kind).

      Wait. Are you claiming that the enclosing hollow sphere is NOT at radiative equilibrium with its surroundings?

      The only input and output are radiation, and it is at steady-state.

      But I have already agreed, at least in principle, that as long as you are including energy in via "electricity" or whatever is heating the heat source, then your definition of "net zero across the boundary" should apply.

      I did not realize you intended to include that figure. I thought you were attempting to say that there was no net energy transfer between the bodies.

    99. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      On general principle, yes. When all factors are considered, this is true. I haven't disagreed with this general principle, and at this point I'm only really interested in seeing the rest of your calculations. Please explain what calculations you are using where, because I find it hard to tell the Sage-formatted calculations apart.

    100. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, energy is conserved even when the bodies aren't in thermal equilibrium. As long as nothing inside the boundary is changing, power in = power out.

      That wasn't what I was saying. But never mind, because it is just a misunderstanding, and it's really irrelevant at this point.

      As I said before, this is a general principle which is true.

      I don't know what more you want.

    101. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I don't see why you keep asking if I agree with your methods.

      I wanted to reach agreement on the nature of the problem, to make sure we had it defined clearly.

      But as far as I am concerned, pretty much everything beyond that is just your explanation of how you do it.

      I *do* want and appreciate explanation. Don't misunderstand me there. But you said your purpose here was to explain something to me. So please, by all means, proceed with the explanation.

      I likely won't have opportunity to see it until tomorrow sometime at the earliest, though.

    102. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I haven't even tried to calculate an answer yet.

      I won't know if I agree with your method until I see it.

    103. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      In action, that is.

    104. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I was worried that Jane was just trolling, and had no intention of ever acknowledging my method even if I described them from start-to-finish. Now that I've described my method from start-to-finish and Jane is pretending that he hasn't seen my method "in action" it seems like my worries came true.

      I'm not pretending anything. Where is your method in action? Is there an answer in there somewhere? You told me you were going to calculate the temperature of the heat source at steady-state.

      This is utter nonsense. I simply asked you for an explanation of how you calculated the figure you stated (long) before, after we agreed on the nature of the problem and the initial conditions.

      Your methodology does does not require my approval in order to explain it. It's either your methodology, or it's not. If you were writing a paper about it, would you ask people who had never seen the problem before for your approval before publishing it? If you had the courage of your conviction, that is, and felt it was the correct solution.

      Jane, if you won't do a single, solitary calculation of your own, could you at least please stop pretending that you haven't seen my method from start to finish? Here's my last step again:

      STOP attempting to put words in my mouth! This is worse than an obnoxious habit of yours, it is a form of lying.

      It is obvious that I have done calculations. I merely stated that I haven't calculated a solution yet. And THAT is largely due to what I clearly stated before: I have been busy, and don't have a lot of time to devote to this right now. I've been trying to squeeze in what I could, around work and other obligations.

      You've been bugging me for a very long time now about this, and this was supposed to be YOUR EXPLANATION of how this works TO ME. So I have been waiting to see it completed. You have no reason to complain about whether I "agree" with your methodology. Either your analysis stands on its own, or it does not.

      I have explained several times now that these Sage equations are not exactly straightforward and easy to read. I have been doing my own calculations in a clear and straightforward manner, making them as easy to read as possible. You really expect me to read this stuff?

      The last line displays the answer.

      Where? The "answer" being the temperature of the heat source at steady-state, which you said you would calculate? I don't see it.

      Again, there appears to be a misunderstanding somewhere. I don't know where it is.

    105. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Once again, you've seen my method in action from start to finish. I've repeatedly asked if we can agree on that method before posting my final numerical answer. That's because I think you deserve a chance to show that you're capable of judging my method based on its physics, as opposed to reflexively objecting if my numerical answer contradicts the PSI Sky Dragon Slayers.

      I will judge your method based on its physics, when I see your answer. You don't need my approval of your method to show it to me. You're asking me to approve of how a house was painted before you painted it. It should be no surprise that I balk at this request.

      In a normal exchange of this kind, you would solve the problem, then justify your steps. Or do them at the same time. You're trying to get me to approve of your steps before you have fully taken them. That's... weird. I repeat that you don't need my approval to do something you claim you've already done.

      For instance, suppose I told you that my final numerical answer agrees with the PSI Sky Dragon Slayers. Would that make you agree with my method's physics? In that case, would you really be agreeing with my method, or agreeing with the answer you want to hear?

      No, and once again I resent the insulting personal remark. I have given you no genuine reason to say this.

      Regardless of the answer you come up with, I want to see the individual steps justified. I don't, however, have any interest in agreeing to supposed "justification" of your answers before I've even seen them. That leads to misunderstandings and ambiguity. I don't care if you solve each equation first and then explain it afterward. In fact I'd vastly prefer that you do. I do want to see the justification. There's no doubt of that. But in asking for agreement before you even do the math, you're putting the cart before the horse. Suppose you transposed a number somewhere in your calculation. Should I then agree with your answer if your methodology were correct, but you made some other error? That would be ridiculous.

      I intend to check your steps thoroughly AFTER you're done anyway, regardless of whether you explain before or afterward. If I have any specific objections at that time, I will bring them to your attention. That is the proper way to do things.

      If you won't know if you agree with my method until you see my final numerical answer, you're depriving yourself of this chance to demonstrate your intellectual integrity.

      Bullshit. I won't agree until I see the answer because I want to check your work. It's that simple. And you have given me here a perfect example of how you continue to toss in ambiguities when they're completely unnecessary:

      As before, that net radiative power is described by Wikipediaâ(TM)s equation which accounts for areas and view factors.

      I just want to make it very clear why I object to the way you ask for agreement, all the while throwing in ambiguities. You say you're using the equation for radiative power, when you're linking to the equation for heat transfer.

      We already know what the equation for radiative power is: (epsilon)(sigma)T^4.

      soln4[0].rhs().n()

      Further, you've twice written that the last line contains the solution, when in fact it contains nothing of the sort.

      So before you ask me to agree to things, MAYBE you should damned well be careful to make them clear in the first place?

      Even better, just do the damned calculation, then we can discuss it. You're wasting our time. I have repeatedly told you I don't have much to spare right now, and you claim to have even less.

      I will have no more time to devote to this until this evening. I'll check back then.

    106. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Ironically, you actually are judging my method based on its physics, which is actually a step forward:

      NO!!! I was not "judging your method". I was describing your nasty habit of confusing the issues. Two very different things.

      Once again, your equation is only for net radiative power (or net heat transfer) to a 0K blackbody.

      NO, it is not. It is the equation for THE RADIATIVE EMITTANCE (often called radiative power) of a surface. Its instantaneous value does not depend on surrounding conditions or nearby bodies. The only variables are emissivity and temperature.

      I repeat: that equation has nothing directly to do with heat transfer, though heat transfer equations may rely upon it.

      This is just another example of how you have tended to obfuscate things. What I stated was a very straightforward, textbook equation that has nothing at all to do at all with "nearby 0K blackbodies".

    107. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Once again, we'll obviously have to agree to disagree about the net heat transfer between two gray surfaces.

      What the HELL are you talking about? I understand the equation from Wikipedia. I just happened to mention that you called it a power equation rather than a heat transfer equation. THAT IS ALL. Then later, you called my emittance equation a heat transfer equation. That's not anything I did, that's something you did.

      Here are your words, complete with the link I was referring to:

      As before, that net radiative power is described by Wikipedia's equation which accounts for areas and view factors.

      Anybody who follows that link can see that it is a heat transfer equation, not a "net radiative power" equation.

      THEN I gave you an equation for radiant emittance: (epsilon)(sigma)T^4, and you called it a "heat transfer" equation having something to do with 0K black bodies, which is simply false. That equation, for gray bodies, can be found here.

      Now, when I simply pointed out these apparent MISTAKES in terminology to you, in order to try to keep things straight, you're throwing a fit. Well, don't try to blame this on me. I was just explaining why the things YOU have been saying lead to confusion. I will not apologize for simply trying to sort out basic misunderstandings.

      Again, you seem to be asserting that Jane's equation should be used instead of Wikipedia's equation. Is that the case? If so, all you need to do to catch up is to list the values you'll plug into that equation, like I did. This would only take a few minutes. If you're confused and need help, just ask.

      Why would you think that? Have I said anything like this? Answer: no, I have not, as just about any reader should have little trouble understanding. In fact I told you twice now that equation was incorrect. I've stated it right here in black and white.

      I did not assert any other equation is "correct". I'm letting YOU show me YOUR methods. That's what you said you were going to do, right?

      So, I don't know what the hell is going on. Are you drunk?

      I will repeat what I have already stated several times: the only things I "insisted" upon were that we agree on the initial conditions of the problem. I do not insist you use any particular equations. This is YOUR show, which I am participating in only as a courtesy. I'm just following along.

      Either get on with it, or not. But if you refuse to do what you told me I was coming here to see you do (refute Latour), then you refuse. That has nothing to do with me, and you don't get blame it on me.

      Get the hell on with it, or not. Whichever you do, it's YOUR choice. I am very, very close to calling you full of shit and posting this where everyone can see it.

    108. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      My honest opinion is that YOU are the one who is trolling, and never intended to actually refute anybody at all. You simply wanted to waste more of my time.

    109. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      You're just confirming what I said earlier. You're finally proving that you were full of bull all along.

      We'll obviously have to agree to disagree that I explicitly used the equation for net radiative power, and linked to an equation described as: "The radiative heat transfer from one surface to another is equal to the radiation entering the first surface from the other, minus the radiation leaving the first surface."

      We're not "agreeing to disagree" on anything. You're just plain wrong. You just confirmed exactly what *I* said above: that this is a heat transfer equation, but you called it a "net radiative power" equation.

      We've agreed that net radiative power is power out minus power in through a boundary, but we'll obviously have to agree to disagree that Wikipedia's radiative heat transfer is "equal" to net radiative power.

      We will most certainly have to disagree on that, because it's wrong. That equation is for finding Q, the net heat transfer, which is not "equal" to power at all. It is energy in Joules.

      If you are using it to calculate "net radiative power", then clearly show here how you have manipulated the equation to solve for power instead, so that other people can check your work.

      If I was "throwing a fit" by saying we'll obviously have to agree to disagree, then what's this?

      Yes, you are quite clearly throwing a fit, and comparing it to something else doesn't change that, or make anything else you have said correct. I had plenty of good reason for stating what I did in the quotes you post here, and those reasons are ALSO soon to be part of a widely-read (very possibly and we can hope) public record. AND... that is all completely beside the real point. You're stalling, and obfuscating again.

      No, you haven't even taken a single solitary step towards solving for the enclosed source temperature. But I've repeatedly tackled the full problem in real detail.

      Except for your final answer. And whether *I* have done it is completely immaterial. You claimed Latour was wrong, and that you had successfully refuted him. So where is your final answer for the temperature of the heat source at stead-state? THAT was what you said you were calculating, so where is it?

      This particular Slashdot thread is not MY show, it is yours. You demanded it. I have given you all the opportunity you asked for. So where's the punchline? Where's the finale?

      It would only take you a few minutes to write down the equation and values that could be used to solve for the enclosed source temperature. Is the only reasonable conclusion to be drawn here that you won't do it because you know you're wrong?

      How could I possibly be "wrong"? I'm not doing anything. This is YOUR claim, not mine. This is what YOU said YOU could do. It has nothing to do with me, except that I (very reluctantly, for reasons we're seeing now) agreed to be your audience.

      In the time it's taken you to write all these incoherent rants and talk about washing people's balls, you could've written down the equation and values describing the enclosed source temperature. In fact, you could've done that many times over. Instead, you cuss in ALL CAPS. Are you really going to give a copy to your grandchildren?

      Why should I do that? YOU said you were going to refute Latour. It wasn't my claim. You got partway through, now you refuse to finish, and you're trying to blame ME somehow? How do you figure?

      You know what Latour's claims and math were. (They're not mine, they're his.) You proclaimed loudly that he was wrong (actually your words were much stronger than that), and that you had refuted him. I called bullshit, and now here we are. You wanted an opportunity to show that you were honest. Here it is.

      I have no

    110. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      No, Jane. I linked to Wikipedia's equation [wikipedia.org] for radiative heat transfer, which is in Watts, not Joules.

      Ahah. Very well, you caught me on that one. I was not aware of the dot-notation. I never pretended to be a physicist. I don't see that notation in the engineering references I have handy.

      Your comment about my radiative power equation though was referencing that that same page, but that wasn't what *I* was actually referencing. It might be relevant to black bodies in some way but my own sources (and Wikipedia, too, at the link I showed you) say it is the radiative power out of a gray body at temperature "T" and emissivity "epsilon", and I used it to compute power out of the heat source initially, remember? Our radiated power figures for the heat source in initial conditions agreed, even if you calculated it a different way.

      The final answer for the enclosed source at steady-state is 385.4 K (234.1 F). Anyone with a calculator could have verified this based on my comment yesterday.

      Certainly, I could have found it with my calculator easily enough. But I had reasons for wanting YOU to post it yourself. Among those reasons, but not the only one, was that it was YOUR claimed refutation, not mine. You get to take either credit or blame, not me.

      So! Great news! You have finally completed your claimed refutation of Latour. I shall examine it in detail and get back to you. Probably tomorrow some time.

      Just so we are absolutely clear on what your claim is: starting at the agreed-upon initial conditions, heat source at 150F, when a hollow sphere is suddenly inserted into the chamber, completely surrounding the heat source, of the specified dimensions, then when allowed to reach steady-state the actual temperature of the heat source is 234.1 degees F.

      Did I summarize that accurately enough? I don't want to re-hash the initial conditions we agreed upon. I still agree with them.

      If so, will you really be happy to declare to everyone that you were wrong? Or was that a lie?

      Of course. I don't mind admitting it when I'm wrong. But I have to check your work first. I already strongly suspect that there is a large hole in your reasoning, but I will not have time to check it until tomorrow. Stay tuned.

    111. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      If they don't archive this thread, I will have my answer for you a bit later today. I have other obligations.

    112. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      The first thing I want to do here is ask a question of khayman80. Did he take over 2 years to fully -- and at least somewhat clearly -- explain the methodology for his "solution" to this problem because he honestly thought he had the correct answer, or because he's just a trolling, malicious, lying son of a bitch?

      I do not know the answer for certain, but for a number of reasons I am strongly convinced of the latter.

      I ask because for 2 years now he has berated me, publicly derided and taunted me, and (in my strong opinion) libeled me, based on my position regarding Spencer's challenge, even though I knew he was wrong all along, but in order to prove it to everybody else in an understandable way, he had to explain his methods clearly. It's hard to disprove something when it's not clearly defined.

      But now he has. And now I can show clearly, to someone with high school level math skills, that he was utterly, abjectly, and rather pathetically wrong, and the "Slayers", as he calls them, were right all along. Because, you see, as I know from experience, it isn't enough to show people the right way. At the same time it is necessary and desirable to show beyond doubt that "global warming alarmist" bullshit is just that: bullshit.

      What's funny, khayman80, is that you may have thought I was being funny or incompetent with my interjections, but I was actually feeding you hints all along the way about the right way to do this and the correct answer, but you didn't take any of those hints. Not one. Did you really think I was refusing to "agree" with your assumptions because I was stupid? Again: was that due to mere incompetence and arrogant belief in your own abilities and contempt for others? Or was it because you were protecting your political ideology, or global warming religion, or maybe JPL grant money? I really don't know, and I really don't care, but now I can show the world very clearly, using your own words, that you were wrong the whole time. I would thank you for that but you don't deserve thanks.

      Let's summarize briefly: I suggested to you earlier that the problem was simpler than how you were treating it. I also gave you some good hints that some of your assumptions were incorrect. And I even gave you a QUOTE from an engineering textbook explaining that if you aren't careful, "thermodynamic" reasoning could get you into a lot of trouble when it comes to heat transfer.

      I'm going to start by showing the correct answer. I am going to show my basic work but not all the intermediate steps. You are capable of doing those on your own. Later I'm going to do a full writeup and post this on the internet, some time later. After my brief explanation of the correct answer, I'm going to explain more thoroughly where you went wrong.

      I will make use of only ONE of your assumptions: that the enclosing plate (hollow sphere) is, due to thermal conductivity, approximately the same temperature on both sides. It's only 1mm thick after all, and the thermal conductivity of aluminum was a stipulation of yours so it will be the same to a couple of decimal places, give or take. So the answer won't be exact, but it will be reasonably accurate. Certainly close enough to demonstrate the concept.

      I am also going to make one assumption myself (which is not really an assumption, but a calculation): given the dimensions stipulated by khayman80, the difference between the outside and inside areas of the enclosing hollow sphere are not enough to matter given the precision of our other calculations. (About 0.0001 m^2, give or take.) This simplifies our equations quite a bit.

      Here are the initial conditions we agreed upon: a central sphere of dimensions listed below, with enough power input to heat it to 150 deg. F (338.71K) in radiative steady-state with chamber walls that are actively cooled to 0 deg. F (255.37K).

      As for variable names, I do not intend to fully use "standard" notation because this explanation isn't for physicists, it's for others wh

    113. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Correction: "reflecting on CLUE #2, and the fact that the "view factor" from 1 to 2 (F12) = 1, PLUS our assertion that area of 2 is close enough to the area of 3 to ignore, we get the rate of heat transfer from surface 1 to surface 4"

      Should have just been: "reflecting on CLUE #2, and the fact that the "view factor" from 1 to 2 (F12) = 1, we get the rate of heat transfer from surface 1 to surface 4"

      The relationship between areas 2 and 3 are not relevant until later.

    114. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      I almost forgot to mention another aspect of khayman80's folly.

      He could have discovered he was wrong almost 2 years ago, almost immediately, by checking his work. He didn't. And this was the result:

      He assumed that the total power output of the heat source was available on the OUTSIDE of the enclosing hollow sphere. We now know this was incorrect. He then used that to calculate a hotter temperature for the heat source itself. That may have made sense, giving his (incorrect) assumption about how "power in = power out" worked. BUT... he got a value for temperature almost 100 degrees F hotter than before.

      Remember the S-B law? That means the POWER output of that heat source was much greater. It doesn't matter where it was coming from... according to his own reasoning (which would be correct for the heat source itself), it can only be as hot as the power that is input lets it. Power out p = (epsilon)(sigma)T^4. Period. No two ways about it. So if there is a greater T, there is higher power output, and it has to come from somewhere. His heat source is going to draw more power from whatever is powering it.

      But wait! There's more!

      All he had to do was continue this magical thinking. Now transfer this power out back to the outside of the enclosing sphere, the way he did it the first time. Then he can back-calculate, the same way he did the first time, and get an even HOTTER figure for the heat source. Then he can transfer this power back out to the outside of the enclosing sphere again, and continue ad infinitum!

      It's hilarious, because khayman80 accused me of spreading "civilization-paralyzing misinfomation". But if the universe really worked according to the information HE has been spreading, it would result in a thermal runaway and destroy itself in an extremely brief period of time. For the price of a few kilowatts.

      khayman80, otherwise known as Bryan Killett, you're either a liar of a fool. As I said before, I don't know which, but I've proved that it MUST be one of the two.

    115. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Jane's obligations include continuing to spread misinformation about ocean acidification even after I've repeatedly debunked him.

      So I predict that Jane's answer won't include any equations that could be used to calculate the enclosed source temperature. Instead, he'll probably grace us with another lengthy, incoherent rant about "problems" in my analysis which are (as usual) too vague to be expressed in equations. In the extremely unlikely event that Jane musters up the courage and competence to actually write down an equation that could be used to calculate the enclosed source temperature, it will almost certainly violate conservation of energy.

      Wrong again. Or perhaps I should say STILL.

    116. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Another minor correction: I stated that "the difference in area" between 2 and 3 was only about 0.001, or some such. That was not quite correct. What I meant was in the process of doing my calculations, I discovered that the difference made by the difference in area was only about 0.001. So I determined that it could safely be ignored, given the fairly loose precision of our other calculations.

    117. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1
      Holy crap, I just discovered another error. Pardon me, folks, but despite khayman80's nasty remarks elsewhere, I really have been busy. Between work, doing work on the car that had to be done today, and schooling a physicist on why his physics is awful, I've been very, very busy.

      This is what I wrote:

      Think of it this non-tecnical way: radiant heat transfer is a function of difference in temperatures. If you have two differences, A = X - Y and B = Y - Z, then A - Z = (X - Y) plus (Y - Z).

      What I meant was this:

      Think of it this non-tecnical way: radiant heat transfer is a function of difference in temperatures. If you have two differences, A = X - Y and B = Y - Z, then (A + B) = (X - Z).

    118. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      As I said, in the unlikely event that you wrote down equations, they'd violate conservation of energy. Thermodynamic thinking like this leads one back to reality, not astray. Draw a boundary inside the inner surface of the enclosing shell at your steady-state values. Since nothing inside that boundary is changing, power in = power out. But that's completely impossible. Your solution violates conservation of energy, as predicted.

      Violating conservation of energy is something you do quite well, you complete bozo.

      You ASSUMED that power at the surface of the heat source = power at the outer surface of the hollow sphere. You did NOT take into account that the sphere radiates from BOTH surfaces. You can even fucking add 2 + 2.

      THEN, you neglected to do the most basic check of your work, such as: applying the S-B relation to your new, hotter heat source. You just hoist yourself by your own petard, dude, because our input is a FIXED amount of power, but you upped your output by almost 100 degrees F. Draw your line JUST around your heat source. Where is that extra power coming from? S-B law says that power is ONLY related to temperature and emissivity, and the emissivity hasn't changed.

      So where is that extra power coming from? Thin goddamned air?

      I made a couple of very minor errors, which I have corrected. My basic proof still stands, and you are still wrong.

      In fact, you're a complete loon.

      I either included or referenced all the equations that were necessary to solve the problem. It's not my fault if you still can't do it.

    119. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      s/you can even add/you can't even add

      My keyboard needs cleaning.

    120. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      Further, if you have a problem with my equations (including my minor corrections) you are welcome to do your own and prove me wrong.

      But you aren't going to, because I'm not wrong, in any basic way. I might have gotten a hundredth or a thousandth off here or there, but unlike you I did double-check your work. All while (according to you) I was spouting something off on Facebook or something.

      I spent about an hour and a half on this, give or take, between my regular work, and working on the car. That includes identifying your errors, and determining what the right way to do it was.

    121. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      One more correction and again it's minor, but again I plea that I have been very busy and had to dash this off in a hurry:

      In my list of "clues" toward the bottom, Clue #1:

      The bit about "Barring any issues like 'view factor'" was an irrelevant comment because that relates to interactions between bodies and my whole point was that the S-B equation for radiative power from a body does not include other bodies. The part about "view factor" can be left out of that passage without affecting its correctness.

    122. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      We have already shown that your particular application of "drawing boundaries" here was a MISAPPLICATION of the principle you are trying to use.

      The "enclosing shell" (if by that you mean the passive plate that was inserted) is acted upon only by radiation. You should have drawn your shell around THAT, and that alone. And you should at least have tried drawing your boundary around your own goddamned heat source, both for initial conditions and your final result, to check your work. But you didn't. What you got was a universe-busting violation of conservation of energy.

      But of course you are still trying to defend something which YOU claimed earlier is not valid to do. There is a word for that.

      Face it. You've been spouting the wrong answer for 2 years, and using it to justify calling OTHER PEOPLE names, and bullying them online, and other nasty antisocial behavior.

      But even if I made a small mistake somewhere (I did NOT make a large one), you're still busted.

    123. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      s/should have drawn your shell/should have drawn your boundary

    124. Re:Jane/Lonny Eachus goes Sky Dragon Slayer by Jane+Q.+Public · · Score: 1

      But again: if you need to "draw a boundary", it needs to be drawn around the passive plate itself. We have already firmly established that your "boundary" around the heat source and the "enclosing shell" is even thermodynamically incorrect. It leads to an erroneous result of very close to (within a few thousandths) DOUBLE the radiative power from that surface that actually exists.

      I have explained this to you 3 times now. If you can't get it through your head, that's your problem and nobody else's.

      As I said, I am going to write this up more thoroughly, elsewhere. But I have presented enough here for anybody who is really interested to figure it out without too much difficulty. Present company apparently excepted.

  179. Re:Thinking outside the box yields a better soluti by Anonymous Coward · · Score: 0

    And there's no personal benefit to donating to charity. It's not like it will drop you into a lower tax bracket or something. Oh wait...

  180. What do you expect from a liberal rag? by don2545 · · Score: 1

    Bloomberg is another one of the liberal fanatics that does no9t understand the correlation between sunspots and the earth temperature through time. There is scientific evidence that cold periods on earth correlate to an absence of sunspots. But the do-gooders who want to destroy our economy and control our lives through the EPA, do not let facts get in the way of their quest for domination. "Dark Winter" by John L. Casey expresses the data far better than anyone I have seen.

  181. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    A plate near the heat source is NOT even remotely the same as closing the drain on a bathtub, because the total power out of the system (it's a closed system with heat being removed, remember?) remains constant, as you have so conveniently observed. [Jane Q. Public, 2014-08-28]

    Completely backwards, as usual. I've never observed any such ridiculous nonsense. That's actually Jane's ridiculous "observation" which I've already tried to correct:

    "... Hopefully it's also clear that Jane's also wrong to claim that the power used by the cooler is required to be constant. The chamber wall temperature is held constant, so the power used by the cooler temporarily decreases after the enclosing plate is added, until it reaches equilibrium."

    I've repeatedly said the electrical heating power is constant, and that adding an enclosing plate temporarily reduces power out until the heated plate warms to a higher equilibrium temperature.

    ... Since the temperature of every other object is less than that of the heat source, there is no net heat flow TO the heat source, therefore the heat source does not become hotter. This is, and has been, the whole of Latour's argument, and it is valid. It is not crazy speculation by some nitwit... [Jane Q. Public, 2014-08-02]

    Again, Eq. 1 describes equilibrium temperature:

    electricity + sigma*T_c^4 = sigma*T_h^4 (Eq. 1)

    Eq. 1 shows that Jane and "the whole of Latour's argument" are wrong. Net heat transfer doesn't have to flow from plate to source in order to cause the heat source to be hotter. Just reducing the net heat flow from source to plate is sufficient to warm the plate, as long as electrical heating power is constant.

    ... you're conflating electrical power with "emissive power" or irradiance, which are different things, in different units. Sheesh. You'd at least expect a "physicist" to get that much right. So I gave that much away. And you still didn't deserve it. ... Now I have given you your bone, doggie. GO AWAY. [Jane Q. Public, 2014-08-28]

    No. As I originally said: "Using irradiance (power/m^2) simplifies the equation... Sage solves Eq. 1 for a constant electric input of 509 W/m^2."

    So the variable "electricity" has always been in the same units as irradiance, which made the equations simpler. The electrical power used by the heater is "electricity" times the surface area of the heated plate. I've repeatedly noted that electrical heating power is constant, which means that the variable "electricity" is also constant unless the heated plate shape-shifts to change its surface area. Just to be clear, I haven't been considering shapeshifting plates.

    Again, it's fascinating that Jane keeps wrongly implying my previous calculations had units confused, but didn't point out the actual units confusion in the eq. 4 I posted.

  182. between the mitigating lines.. by Mr_Nitro · · Score: 1

    the important thing is that 'mitigation' doesn't turn into mega corporations taking control of the new, next-level artificial climate 'service' ? Excellent!!.....feeling sick already..

  183. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Typo: Just reducing the net heat flow from source to plate is sufficient to warm the source...

  184. We need to talk about externalities, fairness & by Paul+Fernhout · · Score: 1

    I said this years ago -- the change is effectively irreversible and we should accept it and deal with it. See my essay "On Climate Change vs. the Singularity".
    http://groups.google.com/group...

    CO2 pollution and related climate change is an externality of centuries of human industrial development and fossil fuel burning, as well as likely poor farming practices leading to topsoil loss (a major carbon reservoir), and also livestock production. As a consequence, many people in low lying areas will be flooded, and others will have bad weather and lose harvests, (negative externalities) while some others will get warmer or wetter weather and have bigger harvests (positive externality). Essentially, global climate change is just a bigger example of, say, a valley being flooded to make a hydroelectric dam. Who pays the costs and who gets the benefits?

    We could tax fossil fuel use and topsoil loss and livestock production to discourage it and redistribute that tax as a global basic income. But that is not enough because past advantages are not evenly distributed globally. So, we could tax capital as well (including patents and copyrights) and also distribute that as a global basic income to make up for such losses. Then people who are negatively affected by climate change will at least be able to afford to move elsewhere. In general, we could also look at the specific winners and losers of climate change and also look at taxing and redistributing to just those people, but that seems harder to figure out.

    Of course, all this is easier said than done without a world government -- and that has its own problems. I can hope that we transition globally to a post-scarcity society in the next few decades (including dirt-cheap solar, hot and cold fusion energy, widespread productive robotics and AI) and many of these issues become uninteresting or trivial to resolve given global abundance. Of course, abundance and such a AI/robotics singularity also poses its own problems. And those issues related to an economic, political, and/or evolutionary singularity in the next few decades may well be more important to think about and plan for than a, by comparison, relatively simpler problem of global climate change.

    --
    A 21st century issue: the irony of technologies of abundance in the hands of those still thinking in terms of scarcity.
  185. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    I'm just not going to take it very seriously if it's yet another "adjusted" dataset from NOAA. There are too many demonstrated problems with their "adjustments".

  186. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    When you look at the evidence (if you are willing to look at the data at all)

    I'm just not going to take it very seriously if it's yet another "adjusted" dataset from NOAA

    Ha ha ha ha! Nailed it didn't I! Tell me more about your 911 truther or birther theories!

  187. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    You nailed nothing. I am not a "birther", or other kind of conspiracy nut. The problems with NOAA temperature adjustments (like TOBS for just one example) are well documented. No conspiracy necessary. Just incompetence.

  188. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    Well documented at the conspiracy sites you visit? Certainly not in the scientific literature.

  189. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    Certainly not in the scientific literature.

    Actually, yes it is. This first example isn't NOAA, it is just for illustration, because it was a handy but excellent example of the same kind of shenanigans. (Note, I'm not claiming "conspiracy" here but incompetence and certain other circumstances can lead to the same net result.) The data is from official sources, the same datasets that scientists use, as is the progressive "adjustment" of same. The historical (official) record is quite clear. The linked story is not itself "the scientific literature", of course, but the official historical temperature data IS.

    Now go look at NOAA and GISS explanations of their TOBS "adjustments" for just one more example, and compare them against analyses of the actual historical temperature records (which are, in fact, the very basis of much of the "scientific literature" ). It's not just there, it's all over the place for anyone who bothers to look. Not that I expect you to. You appear to want people to not look, by calling anyone who dares to question authority a nutcase conspiracy theorist.

    Nice try, but it won't work.

  190. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... power in = power out. ... Using irradiance (power/m**2) simplifies the equation: electricity + sigmaT(c)**4 = sigmaT(h)**4

    This is a joke, right? Trying to see if I'd catch it? Again, among other things you are substituting irradiance for power without factoring in any area. ... [Jane Q. Public, 2014-08-29]

    Again, start with power in = power out through a boundary with surface area "A". Using irradiance (power/m^2) simplifies the equation because we can divide both sides by "A" to obtain irradiance in = irradiance out.

    ... I mentioned this to you several times, but you haven't picked up on it: just for one thing, you're claiming to be using flux but flux has an areal component which you are not accounting for. You say power in = power out, which may be true, but that total power is being transferred via emissive power, which is in W/m^2. Nowhere are you accounting for this. As I stated before: you are conflating power and emissive power, and you can't do that. Where are your areas? It might conserve energy but without areas you do not have the information required to calculate actual radiative temperature. ... [Jane Q. Public, 2014-08-29]

    Again, as long as the enclosing shell is nearly the same size as the heated plate, those areas are nearly irrelevant. And because it's a simpler problem (like a tricycle) one should master it before trying to ride a bicycle with complicated view factors. I already specified my areas. Again, neglecting area ratios predicts that the heated plate warms from 150F to 235F after it's enclosed. Accounting for area ratios similar to Earth's predicts that the heated plate warms from 150F to 233.8F.

    So the tricycle isn't too inaccurate compared to the bicycle, it's much easier to learn, and it provides a sanity check on the more complicated calculation. As the area ratio approaches "1.0" the bicycle should give the same answer as the simpler tricycle. And it does.

    Incidentally, that tricycle is much more accurate than Jane's prediction that the heated plate remains at 150F even after it's enclosed.

    ... I repeat: get the experiment with the two separate plates (actively heated plate and passive plate) right first. Then you can move on to a fully-enclosing plate. You say it's simpler but in a way it's not; you're trying to ride a bicycle when you haven't even managed to ride your tricycle without falling off. ... [Jane Q. Public, 2014-08-29]

    No. A spherical heated plate with a fully-enclosing shell has spherical symmetry, so the heated and enclosing plate temperatures are constant across their surfaces. That's why the equilibrium temperature solutions are just simple numbers.

    However, if the passive plate doesn't fully enclose the heated plate then the heated and enclosing plate temperatures would be complicated functions of spherical coordinates theta and phi. That's a unicycle, not a tricycle.

    ... There are numerous sources, including physics and engineering textbooks, which contradict your analysis and conclusions. Why don't you try the engi

  191. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Correction: However, if the passive plate doesn't fully enclose the heated plate then the heated and passive plate temperatures...

  192. Sources of water by fyngyrz · · Score: 1

    The moisture source for lakes and rivers is -- inevitably -- precipitation over lands upstream. Either as direct runoff, or as recurring eruptions from underground aquifers. If the prevailing winds don't bring the more humid air over the cooler, higher landscape, sure, you'll see drought. But you'd see it anyway, more heat or not. When the prevailing winds are bringing more moisture over those same types of terrain, you're going to see more precipitation, not less.

    The historical record bears this out. When the earth is warmer, we get (a lot) more plant growth. That's simply not going to happen if the precipitation is reduced for any reason. And, at least as far as I am aware at this time, there is no mechanism that would cause reduction in precipitation. Warmer air holds more moisture, yes, and that effect is in full view in the tropics -- with deluge level rainfall when that moist air hits colder atmosphere and the moisture inevitably precipitates as rain. 400 inches / year as opposed to about 100 inches / year in otherwise similar temperate regions.

    I would certainly agree that if the wind patterns change, then the rainfall will too. In both directions. But it seems a little farfetched to say that such changes will result in a consistent decrease in winds traveling onshore. What would such a claim be based upon?

    --
    I've fallen off your lawn, and I can't get up.
    1. Re:Sources of water by blue9steel · · Score: 1

      My understanding is that Global Warming will tend to accentuate both flooding and drought. Essentially by adding more energy to the system we're creating greater volatility in weather patterns.

  193. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    So your theory is that time of day affects the temperature 2000 meters below sea level? You is crazy. You feed your brain with garbage and literally believe every conspiracy theory from 911 trutherism to birther theories about Obama. There is literally no evidence that would dissuade you from any of your pet conspiracies. (and by literally I don't mean figuratively). Why do conversations with deniers always end up with crazy?

    Out of curiosity... Lewendowsky published a paper showing that conspiracy theorists are more likely to reject science. You seem to be a paragon for this theory. I'd like to know - what do you think of it?

  194. Re:Interesting slam of Judith Curry by riverat1 · · Score: 1

    I pretty much ignore all that political bullshit about who's funding what. I care mostly about the science. I have yet to find any reason to think there will be a major overturning of the primary points of current climate theory. There are a lot of details still to be nailed down but that increasing CO2 will cause the climate to warm and the cause of increasing CO2 is primarily human in origin is not in question.

  195. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    Don't be an ass. That isn't what I said. I was explaining why NOAA's datasets are not trustworthy. No more, no less.

    On second thought, based on recent experience, I won't tell you to not be an ass anymore, because if you did you'd disappear.

  196. won't work. by bussdriver · · Score: 1

    Being a realist, I know the system is so far gone with corruption (which heavily leveraged capitalism) that the democracy has been functionally dead for decades and despotism is the destination. Despotism is inevitable, as Franklin predicted but the end times for this democracy are upon us.

    Finding compatible solutions with you believers in the faith is not really worth it; the few sane conservatives who are not blinded with emotion have no influence over their mob of dolts goosestepping us into dystopia. Sure there are "left wing" bad outcomes but that is not anywhere near today; or possible in my lifetime.

    The fanatics of today won't allow actual capitalism, they are too easily sold on economic anarchy by the powerful who only like whatever gives them power/wealth-- capitalism can get them to the top so they like it, but once they have power they hate capitalism and undermine it. The whole situation today is painfully ironic. You can try to educate those who will listen to you into reasonable positions or you can join the other side so that their lost positions and compromises steer more towards your ends.

    Problem with many of the market solutions I've heard so far is they involve way too much trust in a market system which has already run a muck. Carbon trading was the most naive thing I couldn't believe how many fell for it. (even those who were willing to accept the known flaws... it only really worked if you made everybody join the market and most played reasonably fair... at which point you may as well tax and/or regulate because that would be probably be easier.)

    1. Re:won't work. by Layzej · · Score: 1

      Well, we agree about carbon trading...

  197. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    Right, You read it on a conspiracy theory page that you mistook for scientific literature. Anyhoodle. You must have some thoughts on Lewendowsky? I feel like you could have written that paper.

  198. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    Right, you're just making shit up now and attributing it to me.

    That's called "lying".

  199. Re:Ocean heat content is rising - Levitus 2012 by Jane+Q.+Public · · Score: 1

    Let's be clear:

    You have made it abundantly clear that your interest here is to try to make me look bad. You can pretend you are having an "argument" all you like, but an objective observer can (has, actually) easily see that it is not so.

    I have no reason to participate in your game and give you the satisfaction, regardless of the fact that (past evidence shows, and that's another truth) you would lose anyway. I have better things to do with my time.

    To put it another way: this isn't worth my time. I will not respond further.

  200. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    Which part is made up? You referenced a web blog and said that it was scientific literature. The birther and truther quotes are all cited. You are a conspiracy theorist and you do reject the science. So what was made up and why would you have any problem with the Lewendowsky study linking conspiracy ideation to science denial?

  201. Re:Ocean heat content is rising - Levitus 2012 by Layzej · · Score: 1

    I concede that no one could win an argument with you. You reject all data that shows you are wrong. What would be the point in 'arguing' with a person who is not rational?

  202. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Spencer's INITIAL description of his thought experiment. As I have told you several time. This first, then more if you want to get into it. I will not discuss this with you in the other order, AS I HAVE TOLD YOU. Because until you get that right, you're not going to get the other one right. If you continue to argue the other case first, then we are done, and I will write you off as hopeless. ... No "enclosing shell". Two parallel plates. The original thought experiment is two parallel plates (we can make them of equal dimensions just to simplify, but it's not necessary). I repeat: we briefly discussed "even if it were enclosing" but that's a complication of the original, and we'll solve the original first. [Jane Q. Public, 2014-08-30]

    Once again, solving a problem without spherical symmetry means you'll have to solve for equilibrium temperatures which aren't constant across the heated and passive plates. Those equilibrium temperatures wouldn't be simple numbers. They'd be complicated functions that would vary across the plate surfaces. Contrast that with a spherically symmetric enclosing plate, where equilibrium temperatures are just simple numbers.

    Are you disputing those facts, or do you really not see which of these problems is more complicated?

    ... Also, I don't think we're assuming black bodies. The best we can realistically do is grey bodies that absorb in all the relevant frequencies under discussion. ... [Jane Q. Public, 2014-08-30]

    I already solved the problem for graybodies, and showed that the graybody equation reduces to the blackbody equation. That's why it's useful to solve the simpler blackbody problem first, to provide a sanity check on the more complicated solution.

    ...Anything is better than your "thermal superconductors" that you then claim are different temperatures on different sides. Do you remember that is the second time you tried to pull that? I bet not. [Jane Q. Public, 2014-08-30]

    I've never claimed that, but this is the second time you've tried to pretend I have. Once again:

    ... its outer temperature is 149.6F ... pretend the enclosing shell is a thermal superconductor, so its inner temperature is also 149.6F ... [Dumb Scientist]

    So, first you postulate a thermal superconductor, and then assert that it has a far higher temperature on one side than on the other? What a magical world you must live in. [Jane Q. Public]

    No, I said both sides of a thermal superconductor enclosing shell are at 149.6F.

  203. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Spencer's INITIAL description of his thought experiment. As I have told you several time. This first, then more if you want to get into it. I will not discuss this with you in the other order, AS I HAVE TOLD YOU. Because until you get that right, you're not going to get the other one right. If you continue to argue the other case first, then we are done, and I will write you off as hopeless. ... No "enclosing shell". Two parallel plates. The original thought experiment is two parallel plates (we can make them of equal dimensions just to simplify, but it's not necessary). I repeat: we briefly discussed "even if it were enclosing" but that's a complication of the original, and we'll solve the original first. [Jane Q. Public, 2014-08-30]

    Once again, solving a problem without spherical symmetry means you'll have to solve for equilibrium temperatures which aren't constant across the heated and passive plates. Those equilibrium temperatures wouldn't be simple numbers. They'd be complicated functions that would vary across the plate surfaces. Contrast that with a spherically symmetric enclosing plate, where equilibrium temperatures are just simple numbers.

    Are you disputing those facts, or do you really not see which of these problems is more complicated?

    ... Also, I don't think we're assuming black bodies. The best we can realistically do is grey bodies that absorb in all the relevant frequencies under discussion. ... [Jane Q. Public, 2014-08-30]

    I already solved the problem for graybodies, and showed that the graybody equation reduces to the blackbody equation. That's why it's useful to solve the simpler blackbody problem first, to provide a sanity check on the more complicated solution.

    ...Anything is better than your "thermal superconductors" that you then claim are different temperatures on different sides. Do you remember that is the second time you tried to pull that? I bet not. [Jane Q. Public, 2014-08-30]

    I've never claimed that, but this is the second time you've tried to pretend I have. Once again:

    ... its outer temperature is 149.6F ... pretend the enclosing shell is a thermal superconductor, so its inner temperature is also 149.6F ... [Dumb Scientist]

    So, first you postulate a thermal superconductor, and then assert that it has a far higher temperature on one side than on the other? What a magical world you must live in. [Jane Q. Public]

    No, I said both sides of a thermal superconductor enclosing shell are at 149.6F.

  204. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Jane, you just quoted me saying that "its outer temperature is 149.6F ... let's pretend the enclosing shell is a thermal superconductor, so its inner temperature is also 149.6F"

    Don't you see how my quote shows you were wrong to twice pretend that I'd claimed otherwise?

  205. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... you KNOW Latour was correct. And it isn't just him. TEXTBOOKS about practical applications of thermodynamics say so. ... [Jane Q. Public, 2014-08-30]

    Again, I already showed you that MIT's equation reduces to my Eq. 1 for blackbodies, and is consistent with these equations and Eq. 1 in Goodman 1957. I've stressed that this thought experiment has been tested for decades in the real world. Radiation shields allow for more accurate measurements of gas temperatures using thermocouples:

    "The greatest problem with measuring gas temperatures is combatting radiation loss. ... surround the probe with a radiation shield ... The thermocouple bead radiates to the shield which is much hotter than the surrounding walls. Thus the radiative loss and hence temperature error is significantly reduced. The shield itself radiates to the walls."

    These radiation shields have been used since at least Daniels 1968 (PDF), and they work like Dr. Spencer's insulating plate. They slow radiative heat loss from the hotter thermocouple. If Jane and Dr. Latour's Sky Dragon Slayer misinformation is correct, why have accurate thermocouples used radiation shields since at least 1968? Isn't that an example of a "real world" situation that's ultimately what we're talking about?

    But its inner temperature ISN'T 149.6F [Jane Q. Public, 2014-08-30]

    After twice pretending that I'd claimed the inner temperature wasn't equal to its outer temperature of 149.6F... now you make that incorrect claim yourself? Bizarrely, I have to point out that a thermal superconductor enclosing shell will have an inner temperature equal to its outer temperature, exactly as I originally said.

    This reminds me of your other similar mistake that you haven't acknowledged:

    A plate near the heat source is NOT even remotely the same as closing the drain on a bathtub, because the total power out of the system (it's a closed system with heat being removed, remember?) remains constant, as you have so conveniently observed. [Jane Q. Public, 2014-08-28]

    Completely backwards, as usual. I've never observed any such ridiculous nonsense. That's actually Jane's ridiculous "observation" which I've already tried to correct:

    "... Hopefully it's also clear that Jane's also wrong to claim that the power used by the cooler is required to be constant. The chamber wall temperature is held constant, so the power used by the cooler temporarily decreases after the enclosing plate is added, until it reaches equilibrium."

    I've repeat

  206. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    No, I'm not wrong. You calculated the outside temperature from the inside temperature, saying it's LOWER because of its greater area. This much is correct. THEN you try to say that with a thermal superconductor, the inner temperature would be the same as outside. Except you just calculated that outside temperature from a WARMER interior. You quite literally can't have it both ways. EITHER you're claiming a superconductor has a different temperature on both sides, or you're claiming that the inside has 2 different temperatures simultaneously. [Jane Q. Public, 2014-08-30]

    Remember that the inner surface of the enclosing shell is different than the surface of the heated plate. The inner and outer surfaces of the enclosing shell are at exactly the same temperature because it's a thermal superconductor. That's what I've always been saying, despite your attempts to pretend otherwise.

    The surface of the heated plate at equilibrium, however, is warmer than the inner surface of the enclosing shell. It has to be.

    Here is an excellent example of this (19.3.2), which illustrates why it is a straw-man argument that is not relevant to the problem at hand. In this case the walls are warmer, not cooler, and the radiation shield is blocking the thermocouple from the radiation inward from the chamber walls, so that it can get an accurate temperature reading of the air without interference from the walls. In your case, it is the opposite: the walls are cooler than the thermocouple. But in neither case is the situation a representation of equilibrium (for example in this case, air is convecting away some of the heat of the thermocouple). The shield is absorbing and emitting radiation, too, it's just that it is isolated from the chamber walls, and so is closer to the ambient temperature of the medium being measured. This is in no way related to our experiment at all. It is in a vacuum. There is no "medium" to measure, with an ambient temperature. Not even remotely. [Jane Q. Public, 2014-08-30]

    I've repeatedly linked to that excellent example. Despite your incoherent protests, it's a relevant example where a passive plate reduces radiative heat loss from a warmer source, warming it to a higher equilibrium temperature. It's a real world example which shows Jane and the Sky Dragon Slayers are wrong.

    See? Same shit different day. You won't sit down and do the calculations start-to-finish, instead you do one small part, then start indulging in your hallmark game of out-of-context he-said, she-said, toss in a straw-man, then claim it's all proved. ... It's simply another illustration of the depths of hand-waving you will go to, rather than actually doing all the calculations on the actual experiment from start to finish. All you're doing is tossing in more straw-men and irrelevancies. You won't do the actual experiment. The only reasonable conclusion to be drawn here is that you won't do it because you know you're wrong. [Jane Q. Public, 2014-08-30]

    Don't you see the irony here? I've repeatedly done the calculations "start-to-finish" by deriving and solving equations describing the final equilibrium temperature of the enclosed plate using increasingly realistic scenarios. I've repeatedly told you that you'd only be able to understand this thought

  207. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Don't you see that you threw in this whole "thermal superconductor" schtick without considering what properties a thermal superconductor must actually have? In order to superconduct, it must be the same temperature everywhere, always. The only way this would be even remotely possible were if it were a perfect radiator... [Jane Q. Public, 2014-08-30]

    Superconductors are distinguished from aluminum by internal properties, not radiative surface properties. That's because conduction happens inside materials, whereas radiation is emitted and absorbed on surfaces.

    ... The only way this would be even remotely possible were if it were a perfect radiator, with emissivity of 1. It would also be a perfect absorber, absorptivity of 1. Regardless of wavelength. So while this might not technically be true, for all practical purposes it is: a thermal superconductor would be completely transparent to all radiation... [Jane Q. Public, 2014-08-30]

    No. As I've explained, emissivity = 1 and absorptivity = 1 is the definition of a blackbody. A completely transparent material would have transmittance = 1 and absorptivity = 0. Blackbodies can't be transparent.

    ... a thermal superconductor ... has no "thermal mass". So it would have absolutely no effect on anything in this experiment. For practical purposes, it would not exist. Your idea that you can get around this by placing some kind of thin lining on its interior doesn't work. It's still as though it weren't there at all... all you have left for practical purposes is the thin shell, nothing else. ... [Jane Q. Public, 2014-08-30]

    I've already solved this problem with an aluminum enclosing shell rather than a thermal superconductor shell. Both shells warm the heated plate to ~233.8F.

    ... That's why I say: no more prevarication. No more beating about the bush. Take Spencer's original challenge, apply Latour's thermodynamic treatment of it, and show where it is wrong. Anything else constitutes failure to back up your claim that Latour is wrong and -- as you have said more than once -- some kind of nutcase. You've had more than 2 years. That is plenty. [Jane Q. Public, 2014-08-30]

    Dr. Spencer's original challenge included the possibility of a fully-enclosing passive plate. And so did Dr. Latour. Note that Dr. Latour never specifies the dimensions of the plates (as Jane began to) before wrongly concluding that T remains 150. This means his incorrect conclusion must apply to all geometries, including a fully-enclosing passive plate. In fact, notice that Dr. Latour explicitly allows for K = 1 and k = 1, which describes a fully-enclosing blackbody passive plate.

    So Dr. Latour wrongly claimed that a fully-enclosing passive plate wouldn't warm the heated plate. I've shown that his claim violates conservation of energy. As long as the shell is warmer than the chamber walls (which it is), the net radiative heat loss from the heated plate is reduced. So power in > power out, which means the heated plate either warms or energy isn't conserved. Just like how a bath

  208. Re:Well, There You Go. by drfred79 · · Score: 1

    Every country is socialist to one extent our another or another. The world isn't black and white. I just wish people who believed in socialism stopped scapegoating capitalism to prove their point or found excuses like fake man-made global warming.

  209. doom....Doom...DOOOOOM! by Anonymous Coward · · Score: 0

    If only the damage to the hoax of anthropomorphic climate change was irreversible so people would stop believing in such nonsense....

  210. Re:Well, There You Go. by crywalt · · Score: 1

    Socialism, by definition, is where the government owns the means of production. This isn't even partially the case almost anywhere any more, unless you really stretch the meaning of ownership. I may be exaggerating somewhat; there may still be state-owned companies here and there. But, really, socialism barely exists today.

  211. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    At equilibrium, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K).

    In order for what you say to be correct, then the "enclosing shell" you refer to is not the heated plate enclosing the source. Which would mean you were talking about a completely different experiment, not even the one Spencer mentioned with the heated plate enclosing the source. [Jane Q. Public, 2014-08-31]

    We might be talking past each other. What you're calling the "source" is what I've been calling the "heated plate" with temperature "T_h" in all my equations. I've called the other enclosing plate the "cold plate" with temperature "T_c". As I've repeatedly and consistently stressed, "T_c" is only identical on both sides of the enclosing cold plate if it's a thermal superconductor.

    I'm sorry for any confusion this caused, but as you can tell I really am talking about the experiment Dr. Spencer mentioned. We're just using different words, and again I'm sorry for not noticing this miscommunication earlier. I take full responsibility.

    ... But your hypothetical thermal superconductor could not store heat like a black body and remain a superconductor. That's a contradiction. So it's a different creature, from your imagination. This is why I say: leave it out. There is no way you can try to demonstrate anything else with it, either, without leading to a contradiction. And it's not part of the original experiment anyway; it's nothing but misdirection. [Jane Q. Public, 2014-08-31]

    We'll have to agree to disagree about thermal superconductors. I'm sorry for trying to simplify the problem in a way that ultimately just caused us to waste so much time. Again, I take full responsibility.

    But again, I've already solved this problem with an aluminum enclosing shell, and it also warms the heated plate (aka Jane's "source") to ~233.8F.

    ... I'm not interested. Original experiment. Latour's treatment of it. Show where he was wrong. Period. Stop prevaricating. [Jane Q. Public, 2014-08-31]

    That was Dr. Spencer's original challenge. He included the possibility of a fully-enclosing passive plate. And so did Dr. Latour's treatment of it. If you don't agree, please show where Dr. Latour specifies the dimensions of the plates before wrongly concluding that T remains 150. Also, why did Dr. Latour explicitly allow for K = 1 and k = 1, which describes a fully-enclosing blackbody passive plate?

    Dr. Latour really did wrongly claim that a fully-enclosing passive plate wouldn't warm the heated plate (aka Jane's "source"). I've shown that his claim violates conservation of energy. As long as the shell is warmer than the chamber walls (which it is), the net radiative heat loss from the heated plate (aka Jane's "source") is reduced. So power in > power out, which means the heated plate either warms or energy isn't conserved. Just like how a bathtub fills up.

    "Stop prevaricating"? Really? I've showed that Dr. Latour was wrong because his claim violates conservation of energy. Again, in physics that's a really big mistake.

    Since you just linked to this

  212. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... The problem is that there is no such thing as a thermal superconductor of this kind, and you aren't seeing that it leads to contradictions. The only way it could exist would be if it had NO thermal effect on its surroundings whatever. So it's the ultimate straw-man argument. There is no way it can be legitimately used to demonstrate anything. [Jane Q. Public, 2014-09-01]

    Again, we'll have to agree to disagree about thermal superconductors. That's why I've repeatedly pointed out that I've already solved this problem with an aluminum enclosing shell, and it also warms the heated plate (aka Jane's "source") to ~233.8F.

    No, they didn't, because it's a different problem, being given a theoretical treatment. You keep doing that, but I'm not buying. Two infinite plates, neither of which is heated, is not even remotely the same situation, and it's also theoretical only. They're not taking into account certain real-world factors pertaining to Spencer's experiment. Latour does. Not that they're doing anything wrong... given the context of their situation: infinite non-heated grey bodies. This is not Spencer's experiment. [Jane Q. Public, 2014-09-01]

    No, it's exactly the same problem. The same infinite sum of absorption and reflection. The plates are only "infinite" to avoid having to model fringing field effects around the plate edges. And note that Dr. Latour doesn't model edge effects either, so his plates are either infinite or the passive plate completely encloses the "source". Either way, there would be no edges.

    Notice that the first example MIT applies their final equation to is a thermos bottle where the inside wall is heated by hot fluid.

    You did not point to a calculation he performed on Spencer's situation and prove it wrong. You took what you incorrectly called an analogous situation and called that wrong. Which has been my whole point here. You keep claiming something else represents Spencer's experiment, but you won't tackle Spencer's actual, original experiment. You have consistently refused, for over 2 years. ... You continue to refuse to actually do what you said you'd done: refute Latour's treatment of Spencer's challenge. [Jane Q. Public, 2014-09-01]

    Again, Dr. Spencer's actual, original experiment included the possibility of a fully-enclosing passive plate. And so did Dr. Latour's treatment of it. If you don't agree, please show where Dr. Latour specifies the dimensions of the plates before wrongly concluding that T remains 150.

    In fact, as far as I can tell nobody's specified the plate dimensions except for me. Since the argument I'm refuting never specified the plate dimensions, why would the plate dimensions matter?

    ... I repeat: get the experiment with the two separate plates (actively heated plate and passive plate) right first. Then you can move on to a fully-enclosing plate. You say it's simpler but in a way it's not; you're trying to ride a bicycle when you haven't even managed to ride your tricycle without falling off. ...

  213. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I'm not saying we should solve simpler problems before moving on to more complex problems. [Jane Q. Public, 2014-09-01]

    Okay, then we disagree. It's always helpful to solve simpler problems before moving on to more complex problems. The simpler problem is easier to learn, and often serves as a sanity check on the more complex problem.

    That got a minor mention later in his article, is not included in his diagrams, and is NOT the problem I originally presented to you. As I have said many times before, AFTER you refute Latour's calculations regarding Spencer's original challenge, which did not have the passive body enclosing the heat source, I would be happy to move on to the other issue... with no additional stipulations or additions to the problem Spencer describes. But you haven't gotten there yet. Cart before the horse, with a straw-man riding the cart. [Jane Q. Public, 2014-09-01]

    Again, Latour's calculations allowed for K = 1: "K is the fraction of radiation from the first bar absorbed by the second colder bar, 0 < K <=1."

    The only way K = 1 is if the cold plate completely encloses the first heated source. Otherwise, radiation from the side of the source opposite the cold plate couldn't possibly be absorbed by the cold plate, which would force K < 1. So once again, the fact that Dr. Latour included the possibility that K = 1 means that his claim applies to all geometries.

    If not, why doesn't he deal with edge effects? The only ways to eliminate edge effects are if the plates are infinite, or if the cold plate completely encloses the heated source.

    Why don't you just shut up and do it? Why have you been so mightily struggling, like a fish on a hook, to avoid it? [Jane Q. Public, 2014-09-01]

    Again, I don't have enough time to program a finite element model to account for the fact that a non-fully-enclosing plate would cause plate temperatures to vary across their surfaces. But even if I did, the first thing I'd do after debugging it would be to check the finite element solution in a case where a simple analytic solution can be obtained. Namely, a fully-enclosing passive plate, where the plate temperatures are simple numbers.

    By the way, since you keep insisting that only a particular geometry could refute Dr. Latour's treatment, could you please show where he specified the dimensions of the plates? Or where Dr. Spencer did? Otherwise, even if I had enough time to do so, how could I possibly program this complicated finite element model with the specific geometry that would finally convince you the Slayers are wrong?

  214. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I've already explained why this is BS excuse. Latour didn't need finite element modeling to come up with a reasonably precise answer, and neither would you. [Jane Q. Public, 2014-09-01]

    Latour's answer is ridiculous Sky Dragon Slayer nonsense which violates conservation of energy, as I've shown.

    Once again, solving a problem without spherical symmetry means you'll have to solve for equilibrium temperatures which aren't constant across the heated and passive plates. Those equilibrium temperatures wouldn't be simple numbers. They'd be complicated functions that would vary across the plate surfaces. Contrast that with a spherically symmetric enclosing plate, where equilibrium temperatures are just simple numbers.

    Are you disputing that equilibrium temperatures for a non-enclosing plate would vary across the plate surfaces rather than being simple numbers like with a spherically symmetric fully enclosing plate?

    I simply asked why you refuse to show where Latour was wrong in Spencer's original challenge, not the "enclosing" variant of it. [Jane Q. Public, 2014-09-01]

    Because, unless you dispute the above facts, that would require a complicated finite element model due to its lack of spherical symmetry. I simply don't have that much time left. And again, we'd have to test that complicated model in a case where an analytic solution is available anyway...

  215. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Maybe I should explain what I meant by saying that equilibrium temperatures for a non-enclosing plate would vary across the plate surfaces. Consider Dr. Spencer's first illustration. Presumably the heated plate at "150F" has finite conductivity, so its lack of spherical symmetry means that its corners will be cooler than the plate's side's midpoints. That's because the corners are closer to the cold chamber walls than those midpoints.

    An integral over the heated plate's surface might average to "150F" but (unlike a spherically symmetric plate) it can't have that temperature everywhere as long as it has finite conductivity. But at least the single heated plate has bilateral symmetry; the left and right hand side midpoints have the same temperature.

    Adding a cool plate removes even that bilateral symmetry. The left hand side's midpoint warms the least because it's still radiating to the 0F chamber walls. The right hand side's midpoint warms the most because it's now radiating to the (initially) 100F cold plate.

    Since enclosing a spherically symmetric plate warms it from 150F to ~233.8F for area ratios similar to Earth's, the right hand side's midpoint won't warm past ~233.8F. But it has to warm to conserve energy because at equilibrium power in = power out.

    I can't be more specific without programming a finite element model. But Dr. Latour never even allowed for the heated plate's temperature to be different on each side. As long as we're only considering materials with finite conductivity, this would only be possible for a spherically symmetric enclosing plate.

    Dr. Latour's answer wasn't "reasonably precise". He claimed that the heated plate wouldn't warm at all when the cold plate was added, even if it completely enclosed the heated plate such that K = 1. This is a specific prediction of "0.0000...F" warming. Since energy conservation means that adding a cold plate has to warm the heated plate, he's only off by a factor of infinity.

  216. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... It is the engineering textbook answer. Claiming it is nonsense does not make it so. It was your own model that violated conservation of energy. But to see why, it's easiest to solve the general case first, then look at a specific case. I told you I had reasons to solve the general case first. ... Well, then, I guess you do admit defeat. It doesn't take much time to obtain a textbook on the subject (you were given references 2 years ago and it's not that hard to find others) ... [Jane Q. Public, 2014-09-01]

    No, the PSI Sky Dragon Slayers told you it's the engineering textbook answer. I showed you MIT's final expression which reduces to my Eq. 1 for blackbodies, and is consistent with these equations and Eq. 1 in Goodman 1957. Physicists and engineers have been using thermodynamics for decades in the real world that contradicts Dr. Latour's Slayer nonsense.

    That's why Jane, Dr. Latour and the rest of the Slayers disagree with the American Institute of Physics, the American Physical Society, the Australian Institute of Physics, and the European Physical Society.

    ... I am disputing that given reasonable chosen dimensions it is anywhere near an intractable problem. ... [Jane Q. Public, 2014-09-01]

    I never said the problem is intractable. Just that it's more complicated than the spherically symmetric problem. Again, do you dispute that equilibrium temperatures for a non-enclosing plate would vary across the plate surfaces rather than being simple numbers like with a spherically symmetric fully enclosing plate?

    Maybe I should explain that. Consider Dr. Spencer's first illustration. Presumably the heated plate at "150F" has finite conductivity, so its lack of spherical symmetry means that its corners will be cooler than the plate's side's midpoints. That's because the corners are closer to the cold chamber walls than those midpoints.

    An integral over the heated plate's surface might average to "150F" but (unlike a spherically symmetric plate) it can't have that temperature everywhere as long as it has finite conductivity. But at least the single heated plate has bilateral symmetry; the left and right hand side midpoints have the same temperature.

    Adding a cool plate removes even that bilateral symmetry. The left hand side's midpoint warms the least because it's still radiating to the 0F chamber walls. The right hand side's midpoint warms the most because it's now radiating to the (initially) 100F cold plate.

    Since enclosing a spherically symmetric plate warms it from 150F to ~233.8F for area ratios similar to Earth's, the right hand side's midpoint won't warm past ~233.8F. But it has to warm to conserve energy because at equilibrium power in = power out.

    I can't be more specific without programming a finite element model. But Dr. Latour never even allowed for the heated plate's temperature to be different on each side. As long as we're only considering materials with finite conductivity, this would only be poss

  217. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Electric input of 509 W/m2 is constant and the walls are held at 0F (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150F (339K).

    Utter nonsense. The temperature of the outside of your enclosing sphere is determined entirely by its absorption minus its emission, with absorptivity and emissivity factored in. If your interior heat source were emitting at (your figure) 509W/m^2, and that is being absorbed by the interior surface of your enclosing sphere (which MUST have larger radius than the source, since they can't contact), then your outside surface, being of even larger area, must therefore be colder. ... So you're INVENTING ENERGY OUT OF THIN AIR. ... [Jane Q. Public, 2014-09-02]

    I've already showed you that the outer surface of an enclosing shell with an area ratio similar to Earth's warms to ~149.6F. I've explained that neglecting area ratios is a tricycle: a simple approximation that helps us learn. It's like the "frictionless pulley" or "massless rope" or "blackbody" approximations. Again, in this case the tricycle isn't too inaccurate compared to the bicycle, it's much easier to learn, and it provides a sanity check on the more complicated calculation. As the area ratio approaches "1.0" the bicycle should give the same answer as the simpler tricycle. And it does.

    ... your prior analysis was still wrong. It is VERY easy to show this. Presume you have an initial source at T = 150 deg. F. It has a surface area of 1 m**2. Therefore (let's just assume your figure for power output here, it doesn't really matter and it's good enough for this illustration): it's emission is 509W/m**2. Let's say the EXTERIOR of your enclosing shell has an area of 2 m**2. However, your words (though in a slightly different context): power in = power out. Since the total power (W/m**2 times X m**2) must be the same in as out, the exterior of your shell cannot have the same irradiance. The same must be true if this were just one solid sphere, rather than a hollow sphere enclosing another sphere. Solving for the Stefan-Boltsmann relation at 509W/m**2 times 1 m**2 is total number of watts. If you try to multiply the same emission rate over 2 m**2 you get a DIFFERENT answer. That's just a fact. By assuming an external temperature of 150 deg. F, you have just created tangible energy from the vacuum. Congratulations. [Jane Q. Public, 2014-09-02]

    When the area ratio departs far from 1.0, the tricycle becomes very inaccurate, so one should use the more complicated bicycle. But again, the Earth's area ratio is roughly 1.0025, so in that case the tricycle isn't too inaccurate.

    Once again, I've already accounted for the area ratio to obtain the more complicated and more accurate solution.

    But the second plate also radiates the same power in, toward the enclosed heated plate. Just like the cold chamber walls do. Now consider conservation of energy just inside the second plate (but outside the first) at equilibrium. We can solve for the insulated heated plate's temperature using Eq. 1 by setting Tc = 150F (339K). That yields an insulated heated plate temperature of 235F (386K).

    No, it doesn't! The irradiation is total for the entire hollow sphere, not for each surface. You have to divide the total irradiance b

  218. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Obviously we'll have to agree to disagree. But I thought you wanted to do some actual calculations? As you say, it's pretty damned hard to prove anything without calculating it all the way through. So why don't we take the first step?

    ... it's pretty damned hard to prove anything without calculating it all the way through. ... So why don't you draw a diagram, and simply perform all the calculations? ... I'll even go with your own example of the passive plate enclosing the heat source, for now. ... Then an enclosing plate is introduced, at a temperature (initially) less than that of the source. We can, if you wish, assume it is a hollow sphere, of some reasonable thickness, so the interior and exterior areas differ, and of a smaller external radius than the outside wall, so again they don't touch. Vacuum in between. And we begin our analysis. The starting point and equilibrium are both relevant points that should be calculated. ... I don't insist, but to avoid ambiguity and to make things expressible on a standard keyboard, this is how *I* would label things: S for heat source, so radiative temperature T of S would be T(s). Passive plate (or shell) P. Outside enclosure or wall W. Absorptivity A so absorptivity of P would be A(p). Emissivity E. ... [Jane Q. Public, 2014-09-02]

    Here's my Eq. 2 using your variable names:

    net heat flow = sigma*(T(s)^4 - T(w)^4)/(1/E(s) + 1/E(w) - 1) (Eq. 2J)

    Note that it reduces to my simpler blackbody Eq. 1 if E(s) = E(w) = 1.

    If you'd like me to clarify what my variable names for a particular equation would be in your terminology, just ask.

    I've specified the dimensions. The heated plate is a sphere with radius 6371 mm and surface area A_h. The enclosing plate is a 1 mm thick concentric shell with an inner radius of 6378 mm, surface area A_c1 on the inside, and A_c2 on the outside. The chamber is also a concentric sphere with inner radius 6386 mm, so there's a 7 mm gap on both sides of the enclosing shell. Again, the plates and walls are oxidized aluminum.

    At equilibrium, net heat flow out (in W/m^2) equals "electricity". The first step is to calculate that constant variable "electricity" which describes electrical power per square meter heating the sphere to 150F without an enclosing shell. I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches equilibrium.

  219. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches equilibrium. I promise to provide public-readable versions of my Sage worksheet from now on.

  220. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Slashdot character handling is a pain in the ass, and it catches me often too, when I try to express "greater than" or "less than".

    HTML characters "& gt;" for "greater than" and "& lt;" for "less than" (without the spaces).

  221. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... What do you want to use for material? We might as well use the same material throughout. So if you want to use aluminum for source, passive plate, and walls that is fine with me. We know then, from ESA that the emissivity of aluminum in vacuum is approximately 0.15, and absorptivity 0.05. [Jane Q. Public, 2014-09-02]

    Again, the materials are oxidized aluminum with emissivity = 0.11 for these temperatures. As you said, the best we can realistically do is graybodies where emissivity = absorptivity. If you'd like to use a different emissivity just let me know, and we can both independently calculate the required electricity to check each other's answers.

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches equilibrium. I promise to provide public-readable versions of my Sage worksheet from now on.

  222. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    As you said, the best we can realistically do is graybodies where emissivity = absorptivity. If you'd like to use a different emissivity just let me know, and we can both independently calculate the required electricity to check each other's answers.

    After considering the situation I changed my mind. Since we are discussion what is supposed to be a real model of a real situation, we can use real emissivity and absorptivity. ... [Jane Q. Public, 2014-09-02]

    You were right when you said the best we can realistically do is graybodies where emissivity = absorptivity. Otherwise we'd need to derive a new equation where heat transfer is an integral over wavelengths. In other words, we'd have to recreate MODTRAN. I simply don't have time for that.

    After considering the situation I changed my mind. Since we are discussion what is supposed to be a real model of a real situation, we can use real emissivity and absorptivity. And the emissivity of aluminum (as you pointed out yourself some time ago) is different from the absorptivity by a factor of about 3. The ESA figures are observed figures for aluminum plates in near-vacuum, so those figures would appear to be perfect. [Jane Q. Public, 2014-09-02]

    I've never pointed that out. I've repeatedly shown you Goodman 1957 where Table 1 lists aluminum's emissivity as 0.113 from 100C to 300C.

    In contrast, you're citing ESA figures from page 32 which are at 0K (-273C). But nothing in this experiment is anywhere near that cold.

    Also note that Goodman 1957 specifically tests the gray body approximation and concludes that "Pure aluminum appears to act like a gray body when its radiating surfaces are at temperatures lower than 400C."

    Again, if you'd like to use a different emissivity just let me know, and we can both independently calculate the required electricity to check each other's answers.

    THERE IS NO THERMODYNAMIC EQUILIBRIUM IN THIS EXPERIMENT. There is a steady-state, but no actual equilibrium. That is not possible, because we are actively pumping heat in at one "end", and pumping it out of the other. Since one of the requirements of thermodynamic equilibrium is that all surfaces be at the same temperature ... [Jane Q. Public, 2014-09-02]

    We might be talking past each other. What you're calling steady-state is what I'm calling equilibrium. Radiative thermodynamic equilibrium doesn't require all surfaces to be at the same temperature, it simply means that temperatures don't change with time. At radiative equilibrium, power in = power out, which also means irradiance in = irradiance out.

    ... Kircchoff's law does not apply to this experiment, and no situation arises in which the temperatures are the same everywhere, or the emissivities vs absorptivities. There is a steady-state arising from active (but constant) exchange. But there is no equilibrium. [Jane Q. Public, 2014-09-02]

    Earlier, when I saw your mentions of equilibrium, I thought you were referring to the

  223. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Nonsense. They are figures at at incident radiation of 1367 W/m^2, which is sunlight at 1 AU, for the very reason that it is an approximation of Earth insolation. So in fact it would make a good representative example of what Spencer's model is supposed to be all about. ... ESA gives observed values for integrated emissivity and absorptivity for aluminum. This is a good approximation and it is used in the real world for aluminum in a vacuum. [Jane Q. Public, 2014-09-03]

    Those ESA absorptivities are for absorption of sunlight. Consider the first diagram here which shows that 6000K sunlight has much shorter wavelengths than the radiation from objects at the temperatures we're considering. In fact they hardly overlap. But the emissivities are for radiation emitted by much cooler objects. That's one reason why those ESA emissivities aren't equal to their absorptivities.

    Here's a good explanation of this problem: "... white paint is quoted as having an absorptivity of 0.16, while having an emissivity of 0.93.[9] This is because the absorptivity is averaged with weighting for the solar spectrum, while the emissivity is weighted for the emission of the paint itself at normal ambient temperatures. ..."

    If you really insist on gray bodies that's up to you; but I do not acknowledge that there is any legitimate reason to NOT use reasonable approximations of integrated absorptivity and emissivity. [Jane Q. Public, 2014-09-03]

    Since the absorption values you indirectly cited are for absorption from the 6000K radiation from the Sun, that seems like a legitimate reason not to use those values in a thought experiment where nothing is at 6000K. Again, another reason is that we'd have to recreate MODTRAN to derive heat transfer between non-gray bodies where emissivity and absorptivity are arbitrary functions of wavelength.

    And once we debugged that new MODTRAN clone, we'd have to test it in a simple case, like the case of gray bodies where emissivity and absorptivity don't depend on wavelength. So we might as well solve the simple problem first.

    We might be talking past each other. What you're calling steady-state is what I'm calling equilibrium. Radiative thermodynamic equilibrium doesn't require all surfaces to be at the same temperature, it simply means that temperatures don't change with time. At radiative equilibrium, power in = power out, which also means irradiance in = irradiance out.

    You USED this before to ASSUME all surfaces were at the same temperature! I quoted you saying it in a post above, and you referenced that passage just the other day. In fact this was the source of much of the misunderstanding here. ... [Jane Q. Public, 2014-09-03]

    Once again, I never said that. In reality, I said that both sides of a thermal superconductor are at the same temperature. This was the source of much of the misunderstanding here, and you strongly objected to the notion of a thermal superconductor. Again, that's why I calculated the small temperature difference across an aluminum shell with finite conductivity.

    That's also

  224. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    You USED this before to ASSUME all surfaces were at the same temperature! I quoted you saying it in a post above, and you referenced that passage just the other day. In fact this was the source of much of the misunderstanding here. ... [Jane Q. Public, 2014-09-03]

    Once again, I never said that. In reality, I said that both sides of a thermal superconductor are at the same temperature. This was the source of much of the misunderstanding here, and you strongly objected to the notion of a thermal superconductor. Again, that's why I calculated the small temperature difference across an aluminum shell with finite conductivity. [Dumb Scientist]

    Yes, you did say that, and anybody who wants to can read it on your website. And you wrote it BEFORE any discussion with me of "thermal superconductors". I will quote it again here:

    Electric input of 509 W/m^2 is constant and the walls are held at 0F (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150F (339K).

    You were referring to "the second plate", as opposed to the "heated plate". That corresponds to what I have been calling the "passive" or "enclosing" plate. ... [Jane Q. Public, 2014-09-03]

    Once again, no. I never said that all surfaces were at the same temperature. I've already explained that the final outer temperature of the enclosing shell doesn't happen at the same time as the initial temperature of the heated plate. Initially, the heated plate is at 150F and the enclosing shell is cooler than 100F. But because power in > power out, the plates slowly warm to a new steady-state. By the time the outer temperature of the enclosing shell is ~149.6F (accounting for area differences), the heated plate is ~233.8F. This doesn't change even if we neglect area differences: the enclosing shell and the heated plate are never at the same temperature. Again, that's why I called them T_c and T_h.

    So once again, I never said that all surfaces were at the same temperature.

    If you don't particularly mind, could we finally take the very first step in this calculation? Please?

    Yes, I mind very much. There is no point in doing any calculations at all until we rid you of the false assumptions you have been making about this experiment (as I have been trying to do). They have been leading to incorrect results, and moving on would be a waste of everybody's time. ... There is no equilibrium in this experiment, either thermal or radiative. Period. You may not assume them, or use formulas that are only appropriate for equilibrium. Get past that and move on, or stay stuck here. That's up to you. But unless and until you do, there is simply no need for me to go any further. Your refutation to this point has been demonstrated to be invalid. [Jane Q. Public, 2014-09-03]

    I'm very sorry. I take full responsibility. Can we please move on?

    ... you can take out the epsilons, since I thought we had already agreed we don't need them. (If they represent emissivity.) ...

  225. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once again, no. I never said that all surfaces were at the same temperature. I've already explained that the final outer temperature of the enclosing shell doesn't happen at the same time as the initial temperature of the heated plate. Initially, the heated plate is at 150F and the enclosing shell is cooler than 100F. But because power in > power out, the plates slowly warm to a new steady-state. By the time the outer temperature of the enclosing shell is ~149.6F (accounting for area differences), the heated plate is ~233.8F. This doesn't change even if we neglect area differences: the enclosing shell and the heated plate are never at the same temperature. Again, that's why I called them T_c and T_h.

    You did say it, quite clearly. I quoted you twice and linked to your web page. LATER you changed your tune. I can accept that you changed it later, but you did say it. [Jane Q. Public, 2014-09-04]

    Once again, no. I never said that all surfaces were at the same temperature. I've already explained that the final outer temperature of the enclosing shell doesn't happen at the same time as the initial temperature of the heated plate.

    By the time the outer temperature of the enclosing shell is ~149.6F (accounting for area differences), the heated plate is ~233.8F.

    But you do not give any justification for this answer, you just throw it out there. [Jane Q. Public, 2014-09-04]

    I've been explaining for over a month that the heated plate warms after it's enclosed. I realize you don't agree, which is why I'm trying in vain to get you to finally perform a single, solitary calculation of your own. But even if you don't agree with my statement that the heated plate warms after it's enclosed, can't you at least acknowledge that this is what I'm saying rather than trying to pretend that I somehow said all temperatures are the same?

    ... It may not be assumed that the temperatures are the same! As you have done at least once. ... [Jane Q. Public, 2014-09-03]

    Once again, I never said that all surfaces were at the same temperature.

  226. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Earlier, when I saw your mentions of equilibrium, I thought you were referring to the steady-state that would eventually be achieved. ... [Jane Q. Public, 2014-09-02]

    As I said: "Energy is conserved, which means that if you draw a boundary around some system (like the heated plate), power going in minus power going out equals the rate at which energy inside that boundary changes. At equilibrium, that rate is zero because the system doesn't change. So at equilibrium, power in = power out."

    I explicitly said a system in "equilibrium" doesn't change, which Jane calls "steady-state". I repeatedly asked Jane if we could agree on that, but a month later Jane objected:

    ... Kircchoff's law does not apply to this experiment, and no situation arises in which the temperatures are the same everywhere, or the emissivities vs absorptivities. There is a steady-state arising from active (but constant) exchange. But there is no equilibrium. [Jane Q. Public, 2014-09-02]

    Earlier, when I saw your mentions of equilibrium, I thought you were referring to the steady-state that would eventually be achieved. But even though you mentioned Kircchoff's law, it didn't sink in to my brain that you were referring to actual, literal equilibrium. Uh-uh. As they say in my neck of the woods: it ain't happenin'. [Jane Q. Public, 2014-09-02]

    ... A steady-state is NOT the same thing as equilibrium. ... You do not get to re-define equilibrium any way you choose. Just no. ... [Jane Q. Public, 2014-09-03]

    ... That is a steady state. It is NOT "equilibrium". They are different things. ... [Jane Q. Public, 2014-09-03]

    Note that my definition of equilibrium is identical to this one: "Class 6- Equilibrium Temperature: Equilibrium means no change with time. ... In equilibrium, we expect ENERGY IN = ENERGY OUT ..."

    Also note that this definition of equilibrium doesn't require a planet's south pole to be at the same temperature as its equator, or its surface to be at the same temperature as its tropopause (for planets with an atmosphere).

    But from now on I'll call the system in "steady state" when its temperatures don't change with time, in the naive hope that we might actually be able to finally take the very first step in this calculation.

    ... THERE IS NO RADIATIVE EQUILIBRIUM HERE. THERE IS NO THERMAL EQUILIBRIUM HERE. None. You may not assume them. ... In Spencer's challenge, thermodynamic equilibrium does not exist. ... in Spencer's challenge there very definitely is no equilibrium. [Jane Q. Public, 2014-09-03]

    ... Kircchoff's law (and MIT's example) both assume no bodies involved are storing thermal energy, and there is thermal equilibrium. In fact that is how Kircchoff's law is derived: technically Kircchoff's law only applies at thermal equilibrium. MIT was free to apply it in their example because thermal equilibrium was assumed. However in Spencer's challenge there very definitely is no equilibrium. It is not appropriate to assume it or try to apply it here: the whole point is that we are trying t

  227. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... you had calculated this number for thermal equilibrium using Kircchoff's radiation law. But as I've explained many times now, there is no thermal equilibrium so Kircchoff's law does not apply. ... as you state yourself that equation is derived from Kircchoff's radiation law, which does not apply here. ... [Jane Q. Public, 2014-09-04]

    ... You pointed out to MIT's derivation of energy transfer between infinite gray bodies. It does not apply here because ... that derivation makes use of Kircchoff's law which does not apply in Spencer's challenge. ... [Jane Q. Public, 2014-09-04]

    ... you'll still have to modify your equation if that is based on the one you borrowed from MIT. I repeat that Kircchoff's law does not apply here. ... [Jane Q. Public, 2014-09-04]

    No, I calculated this number for a system which doesn't change with time. From now on I'll call this condition "steady-state" but that doesn't change the fact that my equations are based on conservation of energy in a system that doesn't change with time. Again, I only mentioned Kirchhoff's law to explain MIT's gray body approximation. Since emissivity isn't a function of wavelength, all surfaces aren't required to be at the same temperature.

    ... You pointed out to MIT's derivation of energy transfer between infinite gray bodies. It does not apply here because (a) we have specifically defined areas, they are not infinite... [Jane Q. Public, 2014-09-04]

    Notice that the first example MIT applies their final equation to is a thermos bottle which doesn't have infinite walls. That's because a thermos bottle has no edges (just like our fully enclosed plate!) so the infinite plate approximation applies. If not, why did MIT use their equation to model a thermos? Were they talking about a thermos with infinite walls?

    ... any temperature of the source that is higher than the initial radiative equilibrium (150 deg. F) represents higher power output from that same source, any such higher temperature would violate conservation of energy. [Jane Q. Public, 2014-09-04]

    No, Jane. If power in != power out in steady-state, that would violate conservation of energy. Because my equations are based on the principle that in steady-state power in = power, their solutions satisfy conservation of energy.

    Your figure of 233 deg. F radiant temperature at what you called "equilibrium" represents a constant radiative power output from the heat source greater than its initial power output at 150 deg. F. Where is this additional power coming from? [Jane Q. Public, 2014-09-04]

    No. The radiative power output is exactly the same as before the heat source was enclosed. It's hotter because radiative power output is proportional to T_h^4 - T_c^4. Before the heat source was enclosed, it was radiating to the chamber walls at T_c = 0F. After it's enclosed, it's radiating to the inside surface of the enclosing plate which is at T_c > 0F.

    But as you said, it's pretty damned hard to prove anything without calculating it all the way through. So let's finally take the very first s

  228. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I've been explaining for over a month that the heated plate warms after it's enclosed. I realize you don't agree, which is why I'm trying in vain to get you to finally perform a single, solitary calculation of your own.

    I never said I disagree with this. Please find where I said that. On the contrary; I definitely agree that it warms. In fact it must: Spencer stipulated that it was to be inserted when it was colder than the heat source. ... [Jane Q. Public, 2014-09-04]

    I've been explaining for over a month that the heated plate (aka Jane's "source") warms after it's enclosed. I've only been wasting my final days because Jane's repeatedly disagreed by supporting Dr. Latour's ridiculous Sky Dragon Slayer claim that the heated plate (aka Jane's "source") simply remains at 150F after it's enclosed:

    ... the heat source does not become hotter. This is, and has been, the whole of Latour's argument, and it is valid. It is not crazy speculation by some nitwit, it is straightforward application of Stefan-Boltzmann law. Q.E.D., indeed. If the above inequalities hold (and they do), Latour's conclusion is the only one that is mathematically valid. [Jane Q. Public, 2014-08-02]

    ... The plate cannot cause the heat source to be hotter ... [Jane Q. Public, 2014-08-20]

    If Jane agrees that the heated plate (aka Jane's "source") warms after it's enclosed, then that's great news! In that case, we can all agree that the mainstream physics describing the greenhouse effect is accurate, obeys the laws of thermodynamics, and proves that the Sky Dragon Slayers are wrong.

  229. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    You were throwing around the term "equilibrium" rather loosely, and at one point you mentioned that "at equilibrium" the outer surface of the enclosing passive plate must be at the same temperature as the surface at the heat source:

    Electric input of 509 W/m^2 is constant and the walls are held at 0F (255K). Therefore, the second plate has to radiate the same power out as the heated plate did before it was enclosed. So energy conservation at equilibrium requires that the second plate be at 150F (339K).

    [Jane Q. Public, 2014-09-04]

    Once again, no. I've repeatedly explained that the outer surface of the enclosing passive plate is never at the same temperature as the heat source.

    I've been explaining for over a month that the heated plate (aka Jane's "source") warms after it's enclosed.

    Yes, you've been explaining it but you haven't been backing it up. [Jane Q. Public, 2014-09-04]

    Again, Jane might not agree with the fact that the heat source warms after it's enclosed. But again, Jane could at least acknowledge that this is what I'm saying rather than trying to pretend that I somehow said all temperatures are the same. Please?

    Will you acknowledge that no matter what you meant, this is still wrong? If the enclosing passive plate must radiate out the same power as the enclosed heat source, it cannot be at the same temperature, because radiated power is measured in W/m^2, and there are more m^2 in the enclosing passive plate. Therefore (SIMPLE MULTIPLICATION), because there is greater area they could not be at the same temperature and radiate outward the same power. No matter how you try to bullshit your way around this, it is still WRONG. [Jane Q. Public, 2014-09-04]

    I've repeatedly explained ad nauseum that neglecting area ratios is an approximation. I've already shown how tiny the effects are for Earth's area ratio. For weeks you've refused to perform even the simplest calculation to confirm this. Why don't we check to see wrong these approximations are, by actually doing some calculations? Finally? Please?

    ... You refuse to use real materials with measured absorptivities and emissivities, and insist on using gray bodies and Kirchhoff's law, neither of which actually represent Spencer's experiment in anything like the real world, even though it was intended to be a model of the real world. I get that. But I want to make sure everyone else gets it too. I offered to use real materials with measured emissivities in the approximate temperature range we are talking about (though you refuse to acknowledge that), but you refuse to use them. Just so we know where we stand. I have already explained to you that there is no need to resort to gray bodies, and that we have plenty of information to calculate more realistic, real-world results. But whatever. You refuse to do anything but what you want to do, so let's just go with it for now. But I reserve the right to re-visit this issue. [Jane Q. Public, 2014-09-04]

    ... you insist on using gray bodies, because ... you don't have the spare 15 minutes or so it might take to do approximate, more real-world calculations, and want to use Kirchhoff's law (although it really isn't necessary) to make your life easy. ...

  230. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... You then (at ANY time, I don't care when) claim that a larger surface is at the same temperature, which requires the same amount of W/m^2. But you have more m! So the total power output is greater than your input. There is no way to weasel out of this, man. You're trying to output more power than you're putting in. This isn't even 11th-grade physics. Let's try it at something more like your level: You have 200 beans equally distributed among 10 squares. If you now take those beans, and divide them equally among 25 squares of the same size, how many beans do you now have per square? Show your work. [Jane Q. Public, 2014-09-04]

    Cute. I've repeatedly explained ad nauseum that neglecting area ratios is an approximation. I've already shown how tiny the effects are for Earth's area ratio. Does this mean you don't intend to perform even the simplest calculation to confirm this? Why don't we check to see wrong these approximations are, by actually doing some calculations? Finally? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  231. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Then it should be easy to show how badly this approximation screws up the calculation, right? So why don't we check to see wrong these approximations are, by actually doing some calculations? Finally? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  232. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I already said yes.

    Could we finally take the very first step in this calculation? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  233. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Let's finally move on. Could we finally take the very first step in this calculation? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  234. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I already said yes.

    Could we finally take the very first step in this calculation? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  235. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once again, I already said yes.

    Could we finally take the very first step in this calculation? Please?

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If so, we can move on to the next step, which is calculating the final outer surface temperature of the enclosing shell once it reaches Jane's "steady-state".

  236. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once again, energy is conserved, which means that if you draw a boundary around some system (like the heated plate), power going in minus power going out equals the rate at which energy inside that boundary changes. At steady-state, that rate is zero because the system doesn't change. So at steady-state, power in = power out.

    I've specified the dimensions. The heated plate is a sphere with radius 6371 mm, surface area A_h, temperature T_h and emissivity epsilon_h. The enclosing plate is a 1 mm thick concentric shell with emissivity epsilon_c, an inner radius of 6378 mm, surface area A_c1 and temperature T_c1 on the inside, and A_c2 and T_c2 on the outside. The chamber walls at temperature T_c are a concentric sphere with inner radius 6386 mm, so there's a 7 mm gap on both sides of the enclosing shell. The plates and walls are oxidized aluminum, which are treated as gray bodies.

    Since the enclosing shell has no edges and has nearly the same area as the heated plate, MIT's infinite plate approximation describes net heat flow (in W/m^2):

    net heat flow = sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1) (Eq. 2)

    At steady-state, net heat flow (in W/m^2) equals the electrical input. Note that MIT's Eq. 2 reduces to my Eq. 1 for blackbodies where epsilon_h = epsilon_c = 1.

    The plates and chamber walls are made of oxidized aluminum with emissivity = 0.11.

    Here's my Eq. 2 using Jane's variable names:

    net heat flow = sigma*(T(s)^4 - T(w)^4)/(1/E(s) + 1/E(w) - 1) (Eq. 2J)

    Note that it reduces to my simpler blackbody Eq. 1 if E(s) = E(w) = 1.

    If you'd like me to clarify what my variable names for a particular equation would be in your terminology, just ask.

    At steady-state, net heat flow out (in W/m^2) equals "electricity". The first step is to calculate that constant variable "electricity" which describes electrical power per square meter heating the sphere to 150F without an enclosing shell. I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    I calculated 29.4 W/m^2, which is less than with the simpler blackbody plates because aluminum isn't a perfect emitter or absorber.

    Show your calculations where we can see them. I'm not doing this just for me, I want to show other people just how much a clown you actually are. I am not going to install Sage today just to check your math, and probably neither is anybody else who sees this. ... I have reasons for wanting it public-readable, and I will accept nothing else. [Jane Q. Public, 2014-09-02]

    #Calculate constant electrical power/area heating 1st plate.
    var('sigma T_c T_h electricity epsilon_h epsilon_c')
    eq1 = electricity == sigma*(T_h^4 - T_c^4)/(1/epsilon_h + 1/epsilon_c - 1)
    soln1 = solve(eq1.subs(T_c=255.372,T_h=338.706,sigma=5.670373E-8,epsilon_h=0.11,epsilon_c=0.11),electricity)
    soln1[0].rhs().n()

    ANSWER: 29.3986743761843

    Can we agree on that? If not, a month ago I said we could use Wikipedia’s equation which includes areas. After I mentioned view factors, Jane agreed that the relevant view factor is 1.0 or

  237. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    The acknowledged formula for finding radiative power from temperature is just (sigma epsilon)T^4. There are no other factors involved... So who is wrong and why? No point in going further until we straighten this out. [Jane Q. Public, 2014-09-05]

    You're wrong. I've repeatedly explained how to calculate the required electricity. Note that conservation of energy at steady-state demands that the temperature of the chamber walls be taken into account.

    One way to see this is to consider how much power the electrical heater would need if the chamber walls were also at 150F. The correct answer is zero watts, because the heated plate wouldn't lose net heat to walls at the same temperature. But since your expression doesn't depend on the chamber wall temperature, you wouldn't be able to obtain the correct answer of zero in that case.

  238. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    YOU are contradicting yourself: "Power out = power in", you said. Right? I have calculated the radiative power output using nothing more than area (~ 510 m^2), radiative temperature (338.7K), the emissivity you gave (0.11), and the well-known and proven relation: Radiative power out (in W/m^2) = emissivity * sigma * T^4, where sigma is the Stefan-Boltzmann constant. This is the textbook solution. Please show where it is incorrect. Simply asserting that it is incorrect is not sufficient. [Jane Q. Public, 2014-09-05]

    ... It doesn't matter what temperature an opposing surface is at. I'm calculating the power output of THIS surface, at THIS temperature. As long as the temperature OF THIS SURFACE remains the same, the radiative power output remains the same. The way to calculate it is well-known and I have clearly stated it in my calculations. [Jane Q. Public, 2014-09-05]

    The required electrical power to keep the heated plate at 150F is completely independent of the chamber wall temperature? Really? Doesn't this seem a even little strange to you? You're claiming that we'd have to pump 41.886 * 10^3 W into the heated plate regardless of the chamber wall temperature? Even if the chamber wall temperature were also 150F? Why would we need to continually heat a plate that's at the same temperature as its surroundings? Where would that energy go?

    Another way to see that you're wrong is to write down the incorrect equation you're describing. Here it is in your notation:

    electricity = sigma*E(s)*T(s)^4

    As I've stressed, it's helpful to compare complicated solutions to simpler ones. If we set E(s) = 1 then your equation should reduce to the simpler blackbody solution.

    Once again, a blackbody plate is heated by constant electrical power flowing in. Blackbody cold walls at 0F (T(w) = 255.4K) also radiate power in. The heated plate (Jane's "source") at 150F (T(s) = 338.7K) radiates power out. Using irradiance (power/m^2) simplifies the equation:

    electricity + sigma*T(w)^4 = sigma*T(s)^4 (Eq. 1J)

    Since Jane's proposed equation doesn't reduce to the simpler Eq. 1J for blackbodies where E(s) = 1, it's wrong.

    Note that the equations I've shown here all reduce to the correct blackbody equation.

  239. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Just so we're clear, you calculated that a heated plate would need 82.12 W/m^2 to keep it at 150F, regardless of the chamber wall temperature?

  240. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    No, I am not wrong, you are. You are describing a radiative power difference, or net transfer. That is not what I was doing. I was simply calculating the net power output of the heat source at 150 deg. F using the textbook example of how to do that. ... [Jane Q. Public, 2014-09-05]

    Calculating the necessary electrical power to keep the heated plate (Jane's "source") at 150F requires calculating net radiative transfer. Despite Jane's claim, Jane didn't calculate net radiative power output. Jane actually just calculated the radiative power out from the heated plate. The net radiative power output which determines the necessary electricity is "power out - power in" so Jane's missing the same half of the equation that all Sky Dragon Slayers miss.

    ... It is dirt simple to show you are wrong. ... all we have to do is plug your value for radiative power output back into the known, canonical equation for radiative temperature. Temperature is the 4th root of ( (power in W/m^2) / (se) ). So using your calculated value: 4th root of ( (29.399) / ((6.24 * 10^-9 W/m^2) / K^4) ) = 4th root of 3749839743.59 = 247.46K = -14.24 degrees F. However, we already know what this temperature is, because it's a given:: 150 deg F (338.7K). ... [Jane Q. Public, 2014-09-05]

    Jane plugged my net radiative power transfer into an equation describing only "power out". A nonsensical answer is expected, but Jane should also check his arithmetic: "4th root of ( (29.399) / ((6.24 * 10^-9 W/m^2) / K^4) ) = 4th root of 3749839743.59".

    Instead, I got "4th root of 4711378205.13 = 261.99K = +11.91 degrees F."

    I noticed Jane's arithmetic error because his more fundamental mistake is completely ignoring the power radiated in from the chamber walls, and reflections from those aluminum walls. So Jane's "dirt simple" calculation is only valid for blackbody chamber walls at 0K (-459.7F), rather than the 255.4K (0F) aluminum walls in this experiment.

    Of course, that would only be possible after an infinite number of steps. But I calculated something similar out of whimsy last month: "Fully exposing the plate to the cosmic microwave background radiation cools it to 13F (263K), which is lower than before because the CMBR is a blackbody and aluminum chamber walls aren't."

    Because Jane is unintentionally treating the chamber walls as a 0K blackbody, my +13F CMBR prediction shouldn't have been much warmer than Jane's -14F prediction. The comparatively tiny 2.7K CMBR temperature didn't seem like it could cause my CMBR prediction to be ~27F warmer than Jane's 0K prediction. And it didn't. After Jane's arithmetic was corrected, my CMBR prediction is only ~1F warmer than Jane's 0K prediction.

    But those whimsical scenarios are different from the actual experiment with aluminum chamber walls at 255.4K (0F).

    ... The radiative transfer between the surface of the heat source and the chamber wall is already accounted for. You are trying to account for it twice. ... [Jane Q. Public, 2014-09-05]

    Accounted for how? Where did Jane's calculation depend on the chamber wall temperature?

    The required electrical power to keep the heated plate at 150F is completely independent of the chamber wall temperature?

    No. That is no

  241. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    #Calculate constant electrical power/area heating 1st plate. ... ANSWER: 29.3986743761843 ... Can we agree on either of these solutions?

    ... radiative power (W/m^2) = (6.24 * 10 ^-9) * 338.7^4 = 82 W/m^2 ... total power of the heat source is 82 W/m^2 * 510.064 m^2 = 41.886 * 10^3 W. This does not seem like an unreasonable figure for heating a 12+m dia. sphere with 510 m^2 surface area to 150F. So who is wrong and why? No point in going further until we straighten this out. [Jane Q. Public, 2014-09-05]

    Once again, I calculated the electrical power/area necessary to keep the heated plate (Jane's "source") at 150F inside 0F chamber walls, and asked if we could agree. Jane calculated a different value, then asked "who is wrong and why?" Since I calculated the electrical power necessary to keep the heated plate (Jane's "source") at 150F inside 0F chamber walls, the only way Jane's calculation could show that someone was "wrong" is if we were calculating the same value.

    ... I was not trying to calculate electricity. ... your value for electricity is completely irrelevant to the problem at hand... So: what, then, do you claim that 29.4 W/m^2 figure represents and why? I don't give a rat's ass about "electricity" at this point. ... If I misunderstood, and your 29.4 W/m^2 represents something other than radiative power at the surface of the heat source at 338.7K, then please state clearly in plain terms what it IS supposed to represent, so we can move on. ... I don't give a damn about electricity at this point. ... [Jane Q. Public, 2014-09-06]

    So what electrical power is necessary to keep the heated plate (Jane's "source") at 150F inside 0F chamber walls? Once again, I got 29.4 W/m^2.

  242. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    It's always best to agree on the equation before plugging values in. That way disagreements about the physics of the equation can be resolved before wasting time crunching numbers.

    So instead of asking you what electrical power is necessary to keep the heated plate (Jane's "source") at 150F inside 0F chamber walls, I should've asked you to simply write down your equation which determines that electrical power based on the experiment configuration.

    This would only require a 1 line answer. I've shown that I'm happy with your variable names, so feel free to use them.

  243. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... Do you have a problem with my formula for calculating radiant power of a gray body surface at a given temperature? If not, I will continue. ... [Jane Q. Public, 2014-09-06]

    Again, I've agreed that a heated plate (Jane's "source) surrounded by 0K blackbody walls would require 82 W/m^2 to stay at 150F. I agreed because the whimsical calculation of 13F I did last month with a heated plate surrounded by the 2.7K blackbody CMBR agreed with Jane's corrected "dirt simple" calculation of 11.91F.

    I also agree because changing the chamber walls to a 0K blackbody in my equation yields 82 W/m^2.

    So please continue.

  244. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Please continue.

  245. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I can't stand the suspense. What's Jane's next step? Everything Jane's said makes me think his next step will be to calculate the irradiance in.

    net irradiance = irradiance out - irradiance in

    net irradiance = sigma*E(s)*T(s)^4 - sigma*E(w)*T(w)^4 (Jane's equation?)

    Before Jane plugs in T(w) = 255.4K (0F), could Jane very quickly just say if this is really Jane's equation for net irradiance? Please? I know Jane is a busy professional, so just a yes/no answer would help.

  246. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I've agreed that a heated plate (Jane's "source) surrounded by 0K blackbody walls would require electrical heating power per square meter of 82 W/m^2 to stay at 150F, and 26.5 W/m^2 to stay at 0F. That's because changing the chamber walls to a 0K blackbody in my equation yields those answers.

    So please continue. The next step is to calculate the enclosing shell's final outer steady-state temperature. Then we account for the finite conductivity of the shell to obtain its final inner steady-state temperature. Finally we solve for Jane's "source" final steady-state temperature. Hopefully we can finish this today?

  247. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    And the next step is...?

  248. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Finite conductivity is relevant because Jane's previously objected to thermal superconductors. But that doesn't apply to the next step, which is simply calculating the enclosing shell's final outer steady-state temperature once it's added.

  249. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    So finite conductivity is relevant.

    We need two constants to calculate the outer shell temperature. The chamber walls are held at 0F, which is one constant. The electrical power heating the source is another constant. At the original steady-state without the shell, the net radiative power leaving the source equals the constant electrical power heating the source. This constant power doesn't change even after the shell is inserted.

    Given these two constants, we can solve for the enclosing shell's outer temperature once it reaches steady-state.

  250. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I've always been calculating heat transfer via radiation by using radiative transfer equations.

    Again, the next step is calculating the enclosing shell's final outer steady-state temperature once it's added. Since I've already done this, would you like to me repeat my answer, or would you like to be brave and show your calculation?

  251. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once it reaches steady-state, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K):

    A_h*T_h^4 = A_c2*T_c2^4 (Eq. 3)

    Again, a more accurate answer can be obtained using Wikipedia's equation

    #Calculate outer temperature of enclosing shell. var('sigma T_c T_h A_c A_h F_hc power epsilon_h epsilon_c') eq1 = power == sigma*(T_h^4 - T_c^4)/((1-epsilon_h)/(epsilon_h*A_h) + 1/(A_h*F_hc) + (1-epsilon_c)/(epsilon_c*A_c)) soln2 = solve(eq1.subs(T_c=255.372,sigma=5.670373E-8, epsilon_h=0.11, epsilon_c=0.11, F_hc=1, A_h=511.346241712453, A_c=512.469109758699,power=15028.4258648090),T_h) soln2[0].rhs().n() ANSWER: 338.629792627809

    This is 149.9F, which shows that my simpler method of accounting for the area ratio underestimated the shell's outer steady-state temperature by ~0.3F.

  252. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    (Fixed formatting.)

    Once it reaches steady-state, the enclosing shell radiates the same power out as the heated plate did before it was enclosed. But its area is 1.0025 times larger, so its outer temperature is 149.6F (338.5K) instead of 150.0F (338.7K):

    A_h*T_h^4 = A_c2*T_c2^4 (Eq. 3)

    Again, a more accurate answer can be obtained using Wikipedia's equation

    #Calculate outer temperature of enclosing shell.
    var('sigma T_c T_h A_c A_h F_hc power epsilon_h epsilon_c')
    eq1 = power == sigma*(T_h^4 - T_c^4)/((1-epsilon_h)/(epsilon_h*A_h) + 1/(A_h*F_hc) + (1-epsilon_c)/(epsilon_c*A_c))
    soln2 = solve(eq1.subs(T_c=255.372,sigma=5.670373E-8, epsilon_h=0.11, epsilon_c=0.11, F_hc=1, A_h=511.346241712453, A_c=512.469109758699,power=15028.4258648090),T_h)
    soln2[0].rhs().n()

    ANSWER: 338.629792627809

    This is 149.9F, which shows that my simpler method of accounting for the area ratio underestimated the shell's outer steady-state temperature by ~0.3F.

  253. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Now to calculate the enclosing shell's inner temperature. At steady-state, power in = power out through some boundary. This time, draw the boundary within the enclosing shell. Again, constant electrical power flows in. But all the other boundaries we drew were in vacuum, so heat transfer was by radiation. This time the boundary is inside aluminum, so heat transfer out is by thermal conduction.

    electricity = k*(T_h - T_c)/x (Eq. 4)

    The shell's thickness "x" is 1mm, and the thermal conductivity "k" of aluminum is 215 W/(m*K). We just found that:

    Outer shell temperature: 338.629792627809 K (149.864 F).

    So:

    Inner shell temperature: 338.629929668632 K (149.864 F).

    Of course, that's a flat plate approximation of heat conduction through a spherical shell, which is derived here. That more accurate equation yields:

    #Calculate enclosing shell's inner temperature.
    var('T_c T_h power k r_c1 r_c2')
    eq2 = power == 4*pi*k*r_c1*r_c2*(T_h - T_c)/(r_c2 - r_c1)
    soln3 = solve(eq2.subs(T_c=338.629792627809,power=15028.4258648090,k=215,r_c1=6.378,r_c2=6.379),T_h)
    soln3[0].rhs().n()

    Inner shell temperature: 338.629929346551 K (149.864 F).

    Now for the final step. Calculate the steady-state temperature of the enclosed heated plate (Jane's "source").

  254. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    At the original steady-state without the shell, the net radiative power leaving the source equals the constant electrical power heating the source. This constant power doesn't change even after the shell is inserted.

    Yes, this was one of the reasons I took the time to calculate the irradiance = radiative power output / m^2. [Jane Q. Public, 2014-09-07]

    I'm glad we agree that at the original steady-state without the shell, the net radiative power leaving the source equals the constant electrical power heating the source.

    ... No "electricity" needed. Your "electricity" figure is NOT the "power out" of the heat source. It is a figure for total power consumed that I do not agree applies in this instance, since we have a refrigerator on the outside which also consumes power. To put it another way, your "electricity" figure is not power output of source it is a figure for a DIFFERENCE, which I do not agree applies in this instance. ... [Jane Q. Public, 2014-09-07]

    If we don't need to know how much constant electrical power (total, or the irradiance per square meter) heats the source, why did you take the time to calculate the net irradiance out?

    I've repeatedly failed to explain that the power consumed by the refrigerator on the outside is irrelevant. So obviously we'll have to agree to disagree about that.

    ... Radiative emittance of heat source under initial conditions: 82.12 W/m^2. You already agreed with this figure. Total radiative power out = (82.12 W/m^2) * (510.065 m^2) = 41886.54 W. You are contradicting yourself. Either this is the correct figure, or it is not. ... [Jane Q. Public, 2014-09-07]

    I've repeatedly agreed that a heated plate (Jane's "source) surrounded by 0K blackbody walls would require 82 W/m^2 to stay at 150F. Jane's agreed that at the original steady-state without the shell, the net radiative power leaving the source equals the constant electrical power heating the source.

    That's why no electrical heating power would be necessary to keep a heated plate at 150F if the chamber walls were also at 150F.

    Jane, the next step is to calculate the enclosing shell's final outer steady-state temperature once it's added. Did you get a different answer than me?

  255. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... No "electricity" needed. Your "electricity" figure is NOT the "power out" of the heat source. It is a figure for total power consumed that I do not agree applies in this instance, since we have a refrigerator on the outside which also consumes power. ... [Jane Q. Public, 2014-09-07]

    ... I am not convinced that your power in = power out assumption is correct in this case, because we have a refrigerated outer shell, which also consumes power (we do not yet know how much), which keeps things OUT of thermal equilibrium. We are adding power in the center, and we are removing power at the outside. But because of Spencer's conditions, I am not convinced at this point that we can assume power is conserved. If everything were at thermal equilibrium, I would be convinced. But at the very least, we would have to calculate the difference between power consumed by the refrigerator on the outside, between initial and final conditions. Do we have enough information to do that? ... [Jane Q. Public, 2014-09-07]

    Energy is always conserved. A boundary drawn around a system that isn't changing always has power in = power out. Always. Because energy is always conserved.

    Once again, I've repeatedly failed to explain that the power consumed by the refrigerator on the outside is irrelevant. So obviously we'll have to agree to disagree about that.

  256. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    If it's an unnecessary complication, it should be easy to show the simpler method. If it's a potential source of error, please quantify that error by taking the next step: calculating the enclosing shell's final outer steady-state temperature once it's added. Did you get a different answer than me?

  257. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    A boundary drawn around a system that isn't changing always has power in = power out. Always. Because energy is always conserved.

    ... Let me rephrase what I was saying: at least theoretically, the power at the chamber wall is allowed to vary, in order to keep the temperature at 0 degrees F. But, if we draw a boundary around the system, and assume that the ONLY power in is what we put in, and the ONLY power out is what is removed, then of course it must be conserved. I was simply expressing my concern that your electricity figure may not be properly observing those boundaries. If your electricity figure is simply power in - power out... [Jane Q. Public, 2014-09-07]

    Maybe this will help. It seems like Jane might think I meant power in = electrical heating power, and power out = cooling power of the chamber walls.

    If so, that's not what I meant, and I'm sorry for not being more clear. I take full responsibility.

    Just to be clear, power in = power flowing into the boundary in question, and power in = power flowing out of that boundary.

    In my opinion, solving thermodynamics problems is mostly about choosing the most informative boundaries, then calculating steady-state solutions by setting power in = power out through that boundary.

    From the start, the largest boundary I drew was "just inside the chamber walls" so the chamber walls and the cooler have always been outside all the boundaries. That means any power used by the cooler is simply being moved from some point outside the boundary to another point which is also outside the boundary. Because that power never crosses the boundary, it's irrelevant.

  258. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ACK! SORRY! Just to be clear, power in = power flowing into the boundary in question, and power out = power flowing out of that boundary.

  259. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once again, energy is conserved, which means that if you draw a boundary around some system (like the heated plate), power going in minus power going out equals the rate at which energy inside that boundary changes. At steady-state, that rate is zero because the system doesn't change. So at steady-state, power in = power out.

    Perhaps it would be more informative if you calculate ENERGY in and ENERGY out, since that is what is actually conserved. You seem to keep forgetting that (A) power is a RATE, not a unit of energy, and (B) we are not at thermal equilibrium. ... [Jane Q. Public, 2014-09-07]

    No. Once again, I said that power going in minus power going out equals the rate at which energy inside that boundary changes. Once again, that rate is zero if the system doesn't change.

    ... are you suggesting that if I hollowed out enough of a mountain to make a hollow rock sphere (assume the rock is diffuse gray body) 1000 m diameter, suspended a 1m dia. sphere of the same rock in the center, and evacuated the cavity: the inner sphere is going to get much hotter than the surrounding rock? Power in = power out would seem to demand that very thing. [Jane Q. Public, 2014-09-07]

    No. I've repeatedly told you that power in = power out demands that an unheated inner sphere will be at exactly the same temperature as the chamber walls.

    ... I am aware that view factor has to be taken into account. ... [Jane Q. Public, 2014-09-07]

    Using what equation? A month ago I said we could use Wikipedia’s equation which includes areas, and later mentioned view factors. I've been using this equation to calculate the net heat transfer between the heated plate (Jane's "source") and the chamber walls.

    If that's the equation Jane is thinking about using to take account of the view factor, Jane should ponder what happens in that equation when the two temperatures in that equation are equal. As I've repeatedly said, the net heat transfer goes to zero when the two temperatures are equal. Regardless of their areas.

    ... 788.01 W != 721.44 W (!!!) Power is not conserved. ... Power is not conserved. [Jane Q. Public, 2014-09-07]

    ... a simple power-in = power-out view is not always the right answer. ... it shows how power-in = power-out calculations can easily mislead. [Jane Q. Public, 2014-09-07]

    ... The black body example I gave shows why your "energy conservation just inside the surface" won't work. Aside from just "view factor" and a few other things, a certain amount of the power in (often a very significant amount) just ends up going right back out, but you often don't see that in the formulas. ...

  260. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... My point was that it does not translate directly into power in = power out at a boundary just inside the cavity surface. It most certainly does not if the bodies are not in thermal equilibrium, which again I must point out this system is not in. ... [Jane Q. Public, 2014-09-07]

    It absolutely does translate directly into power in = power out at a boundary just inside the cavity surface when everything inside that boundary isn't changing. In that case, the rate at which energy changes inside the boundary equals zero, which means power in = power out.

    ... energy does not have to be conserved between two bodies at different temperatures. That was what Incorpora was saying in his book. ... [Jane Q. Public, 2014-09-07]

    No. Energy is always conserved. Always.

    Once again, the next step is calculating the enclosing shell's final outer steady-state temperature once it's added. This should have only taken you a few minutes to calculate. Did you get a different answer than me?

  261. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    The reason my "dirt simple" calculation was wrong, as any reader of this exchange should be able to tell (and so should you have), that I misunderstood what your power figure represented. [Jane Q. Public, 2014-09-07]

    I'm very sorry for not being more clear. I take full responsibility.

    It absolutely does translate directly into power in = power out at a boundary just inside the cavity surface when everything inside that boundary isn't changing. In that case, the rate at which energy changes inside the boundary equals zero, which means power in = power out.

    Are you also then presuming that power transferred from the outer surface of the enclosing plate to the chamber walls is the same as the power transferred from the heat source to that plate? [Jane Q. Public, 2014-09-07]

    Anything else would violate conservation of energy. But we still have one more step before the net power transferred from the heat source to that enclosing plate becomes relevant.

    No, of course I got the same answer, given your assumption that power-in = power-out: 149.59F. [Jane Q. Public, 2014-09-07]

    Excellent. And can we also agree about the enclosing aluminum shell's final inner steady-state temperature?

    Now to calculate the enclosing shell's inner temperature. At steady-state, power in = power out through some boundary. This time, draw the boundary within the enclosing shell. Again, constant electrical power flows in. But all the other boundaries we drew were in vacuum, so heat transfer was by radiation. This time the boundary is inside aluminum, so heat transfer out is by thermal conduction.

    electricity = k*(T_h - T_c)/x (Eq. 4)

    The shell's thickness "x" is 1mm, and the thermal conductivity "k" of aluminum is 215 W/(m*K). We just found that:

    Outer shell temperature: 338.629792627809 K (149.864 F).

    So:

    Inner shell temperature: 338.629929668632 K (149.864 F).

    Of course, that's a flat plate approximation of heat conduction through a spherical shell, which is derived here. That more accurate equation yields:

    #Calculate enclosing shell's inner temperature.
    var('T_c T_h power k r_c1 r_c2')
    eq2 = power == 4*pi*k*r_c1*r_c2*(T_h - T_c)/(r_c2 - r_c1)
    soln3 = solve(eq2.subs(T_c=338.629792627809,power=15028.4258648090,k=215,r_c1=6.378,r_c2=6.379),T_h)
    soln3[0].rhs().n()

    Inner shell temperature: 338.629929346551 K (149.864 F).

    Now for the final step. Calculate the steady-state temperature of the enclosed heated plate (Jane's "source").

  262. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... Energy of an entire system is conserved. It need not be conserved between individual elements of that system. That's what I've been saying. ... Heat transfer between two bodies that are not at thermal equilibrium does not conserve energy between those two bodies. ... [Jane Q. Public, 2014-09-07]

    Can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

  263. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Obviously at radiative equilibrium energy between objects in the system is being transferred at a constant rate. [Jane Q. Public, 2014-09-07]

    This principle applies even for systems that are changing, and even for systems that aren't in radiative equilibrium.

    Again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

  264. A massive toupee by Trogre · · Score: 1

    We could somewhat control the effects of global warming with a large array of satellites that unfolded large solar panels like big umbrellas to divert sunlight otherwise destined for Earth, controlled to keep the Earth within a desired temperature range.

    I'm not saying it's practical at all, but it is within our means.

    --
    "Nine times out of ten, starting a fire is not the best way to solve the problem." - my wife
  265. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Given your assumptions so far, I will not dispute your calculation of the temperature of the inner surface of the enclosing plate. Please continue your calculations, as a reply to my other comment, so we can continue this exchange in a linear fashion. [Jane Q. Public, 2014-09-08]

    I'm glad you don't dispute the enclosing shell's inner temperature of ~149.9F, but we should agree on my assumption that energy is conserved before proceeding.

    Can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

    I'm not sure I agree with your wording. It could easily be misinterpreted to mean something it does not. I agree that power in minus power out of your boundary equals power through that boundary, which at radiative steady-state represents a constant rate of energy flow through that boundary. [Jane Q. Public, 2014-09-08]

    How could my wording be easily misinterpreted? Once again, this fundamental principle applies even for systems that are changing, and even for systems that aren't at radiative steady-state.

    Again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

    Maybe an analogy would help. The rate at which water flows into a bathtub minus the water flowing out equals the rate at which water in the bathtub changes. No qualifications needed.

    If we can't agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes, could you please explain exactly why we can't agree on this?

  266. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    This principle applies even for systems that are changing, and even for systems that aren't in radiative equilibrium. Again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

    How could my wording be easily misinterpreted? Once again, this fundamental principle applies even for systems that are changing, and even for systems that aren't at radiative steady-state.

    I prefer my wording, which I think most people would agree is an equivalent statement regarding your drawn boundary, but (in my opinion) is less open to misunderstanding. I agree that power into your boundary minus power out of your boundary equals the power through the boundary, which at radiative equilibrium is equivalent to a constant rate of energy flow through that boundary. Were you trying to say something else? If not, let's please move on. [Jane Q. Public, 2014-09-08]

    Once again, this principle applies even for systems that are changing, and even for systems that aren't in radiative equilibrium. Again, that's why I disagree with your claim that:

    ... energy does not have to be conserved between two bodies at different temperatures. That was what Incorpora was saying in his book. ... [Jane Q. Public, 2014-09-07]

    Since you keep place qualifiers on energy conservation, your wording isn't equivalent to mine because my statement applies even for systems that aren't in radiative equilibrium.

    Once again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes? Even for systems that are changing? Even for systems that aren't in radiative equilibrium?

  267. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Since you keep place qualifiers on energy conservation, your wording isn't equivalent to mine because my statement applies even for systems that aren't in radiative equilibrium.

    But that should not matter because we are discussing a system in radiative equilibrium. ... [Jane Q. Public, 2014-09-08]

    Really? Since when?

    ... There is no thermal equilibrium. Period. None. There MAY (and eventually would) arise a condition of radiative equilibrium for the (enclosing, passive, however you want to describe it) plate. But the other objects (heat source and chamber walls) do not meet this criteria because they are heated/cooled by means that may be other than radiative. "The system" is not in radiative equilibrium. ... [Jane Q. Public, 2014-09-03]

    ... I don't necessarily have a problem with a broader definition, but I prefer to stick to things that are pertinent to this discussion. So can we move on? [Jane Q. Public, 2014-09-08]

    Since Jane's insisted that the system is not in radiative equilibrium, it's necessary to agree on a general principle that applies even for systems that aren't in radiative equilibrium. Then we can move on.

    Can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

    I'm not sure I agree with your wording. It could easily be misinterpreted to mean something it does not. I agree that power in minus power out of your boundary equals power through that boundary, which at radiative steady-state represents a constant rate of energy flow through that boundary. [Jane Q. Public, 2014-09-08]

    I prefer my wording, which I think most people would agree is an equivalent statement regarding your drawn boundary, but (in my opinion) is less open to misunderstanding. I agree that power into your boundary minus power out of your boundary equals the power through the boundary, which at radiative equilibrium is equivalent to a constant rate of energy flow through that boundary. ... [Jane Q. Public, 2014-09-08]

    ... it is radiative equilibrium that forces it to be constant. ... [Jane Q. Public, 2014-09-08]

    Your wording could easily be misinterpreted to mean a constant other than zero. Didn't you mean that net power through that boundary at radiative steady-state represents zero energy flow through that boundary? If not, our misunderstanding is much more fundamental than I first thought.

  268. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... there is definitely no thermal equilibrium, and without at least radiative equilibrium, there is no equilibrium at all and we might as well just stop again right here. ... no thermal equilibrium ... [Jane Q. Public, 2014-09-08]

    That's why I'm trying to see if we can agree on a general principle that applies even to systems that aren't in thermal equilibrium.

    ... why the hell are you trying to blame me for being confused? The condition you described is impossible, so how do you expect me to know what "equilibrium" you mean? ... [Jane Q. Public, 2014-09-04]

    Since we've had to agree to disagree about the definition of the term "equilibrium" (whether radiative or thermal), it's necessary to agree on the fundamental principle of energy conservation using a simple statement that doesn't use the term "equilibrium" (of any kind).

    ... I very definitely did NOT mean net power at radiative steady-state represents zero energy flow. ... [Jane Q. Public, 2014-09-08]

    Then our statements aren't equivalent, which means there's an innocent misunderstanding here. To help resolve this miscommunication, could we please agree on a general principle that applies to all systems, even if they're not in thermal or radiative equilibrium?

    Once again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

  269. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... there is definitely no thermal equilibrium, and without at least radiative equilibrium, there is no equilibrium at all and we might as well just stop again right here. ... no thermal equilibrium ... [Jane Q. Public, 2014-09-08]

    That's why I'm trying to see if we can agree on a general principle that applies even to systems that aren't in thermal equilibrium.

    ... why the hell are you trying to blame me for being confused? The condition you described is impossible, so how do you expect me to know what "equilibrium" you mean? ... [Jane Q. Public, 2014-09-04]

    Since we've had to agree to disagree about the definition of the term "equilibrium" (whether radiative or thermal), it's necessary to agree on the fundamental principle of energy conservation using a simple statement that doesn't use the term "equilibrium" (of any kind).

    ... I very definitely did NOT mean net power at radiative steady-state represents zero energy flow. ... [Jane Q. Public, 2014-09-08]

    Then our statements aren't equivalent, which means there's an innocent misunderstanding here. To help resolve this miscommunication, could we please agree on a general principle that applies to all systems, even if they're not in thermal or radiative equilibrium?

    Once again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

  270. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Since we've had to agree to disagree about the definition of the term "equilibrium" (whether radiative or thermal), it's necessary to agree on the fundamental principle of energy conservation using a simple statement that doesn't use the term "equilibrium" (of any kind).

    Wait. Are you claiming that the enclosing hollow sphere is NOT at radiative equilibrium with its surroundings? [Jane Q. Public, 2014-09-08]

    No. I'm saying that since we've had to agree to disagree about the definition of the term "equilibrium" (whether radiative or thermal), it's necessary to agree on the fundamental principle of energy conservation using a simple statement that doesn't use the term "equilibrium" (of any kind).

    Once again, can we agree that energy conservation means that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes?

  271. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    On general principle, yes. When all factors are considered, this is true. I haven't disagreed with this general principle, and at this point I'm only really interested in seeing the rest of your calculations. Please explain what calculations you are using where, because I find it hard to tell the Sage-formatted calculations apart. [Jane Q. Public, 2014-09-08]

    In order to explain what calculations I'm using, we have to first agree on the fundamental principle all my calculations are based on.

    I'm glad we agree that power going in minus power going out through some boundary equals the rate at which energy inside that boundary changes.

    Notice that this general principle applies to all systems, even if they're at different temperatures or out of (thermal/radiative) equilibrium.

    Now suppose that nothing inside that boundary is changing with time. Since this includes the energy inside that boundary, the rate at which energy inside the boundary changes is zero. This means power in = power out through any boundary where nothing inside that boundary is changing with time.

    If we can agree so far, just say "yes" and ignore the rest of this comment. Then we can move on to the final step, which is calculating the enclosed source temperature.

    If we can't agree, here's why we first need to agree that power in = power out through any boundary where nothing inside that boundary is changing with time.

    ... a simple power-in = power-out view is not always the right answer. ... it shows how power-in = power-out calculations can easily mislead. [Jane Q. Public, 2014-09-07]

    ... your "energy conservation just inside the surface" won't work. ... [Jane Q. Public, 2014-09-07]

    How could it mislead? Why won't it work? As long as nothing inside the boundary is changing, a simple power in = power out view is always the right answer.

    ... The problem is that an analysis of this kind, based on the assumption that power-in = power-out, is doomed to fail except in coincidental cases. Even conservation of energy can give very misleading results. ... power-in = power-out is not necessarily true, and in fact that is probably a very rare exception. Therefore, you aren't going to prove anything with this approach. I wanted to stop you before you wasted more of your time. [Jane Q. Public, 2014-09-07]

    How is it doomed to fail? How could it give very misleading results? As long as nothing inside the boundary is changing, power in = power out is necessarily true.

    ... it does not translate directly into power in = power out at a boundary just inside the cavity surface. It most certainly does not if the bodies are not in thermal equilibrium, which again I must point out this system is not in. ... [Jane Q. Public, 2014-09-07]

    No, energy is conserved even when the bodies aren't in thermal equilibrium. As long as nothing inside the boundary is changing, power in = power out.

    ... energy does not have to be conserved between two bodies at different temperatures. That was what Incorpora was saying in his book. ... [Jane Q. Public, 2014-09-07]

    N

  272. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Now that we've agreed on the inner shell temperature of ~149.9F, let's take the last step. Calculate the enclosed source temperature.

    Draw a boundary just inside the inner surface of the enclosing shell. Because nothing in the boundary is changing with time, power in = power out. The same constant electrical power flows in as before the shell was added. Net radiative power flows out from the source to the enclosing shell's inner surface.

    As before, that net radiative power is described by Wikipedia’s equation which accounts for areas and view factors.

    #Completely surrounded by shell with finite conductivity.
    var('sigma T_c T_h A_c A_h F_hc power epsilon_h epsilon_c')
    eq1 = power == sigma*(T_h^4 - T_c^4)/((1-epsilon_h)/(epsilon_h*A_h) + 1/(A_h*F_hc) + (1-epsilon_c)/(epsilon_c*A_c))
    soln4 = solve(eq1.subs(T_c=338.629929346551,power=15028.4258648090,sigma=5.670373e-8,epsilon_h=0.11,epsilon_c=0.11, F_hc=1, A_h=510.064471909788, A_c=511.185932522526),T_h)
    soln4[0].rhs().n()

    ... Please explain what calculations you are using where, because I find it hard to tell the Sage-formatted calculations apart. [Jane Q. Public, 2014-09-08]

    The first line "var('sigma..." declares my variables.
    The line "eq1 = power == sigma..." is my "power in = power out" equation using Wikipedia's equation for net radiative power.
    The next line plugs in all the relevant variables and solves it for the enclosed source temperature T_h.
    The last line displays the answer.

    So I've described my method for calculating the enclosed source temperature from start to finish. Before I post that final answer, can we agree with my method? If not, could you please describe your method?

  273. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Now that we've agreed on the inner shell temperature of ~149.9F, let's take the last step. Calculate the enclosed source temperature.

    Draw a boundary just inside the inner surface of the enclosing shell. Because nothing in the boundary is changing with time, power in = power out. The same constant electrical power flows in as before the shell was added. Net radiative power flows out from the source to the enclosing shell's inner surface.

    As before, that net radiative power is described by Wikipedia’s equation which accounts for areas and view factors.

    #Completely surrounded by shell with finite conductivity.
    var('sigma T_c T_h A_c A_h F_hc power epsilon_h epsilon_c')
    eq1 = power == sigma*(T_h^4 - T_c^4)/((1-epsilon_h)/(epsilon_h*A_h) + 1/(A_h*F_hc) + (1-epsilon_c)/(epsilon_c*A_c))
    soln4 = solve(eq1.subs(T_c=338.629929346551,power=15028.4258648090,sigma=5.670373e-8,epsilon_h=0.11,epsilon_c=0.11, F_hc=1, A_h=510.064471909788, A_c=511.185932522526),T_h)
    soln4[0].rhs().n()

    ... Please explain what calculations you are using where, because I find it hard to tell the Sage-formatted calculations apart. [Jane Q. Public, 2014-09-08]

    The first line "var('sigma..." declares my variables.
    The line "eq1 = power == sigma..." is my "power in = power out" equation using Wikipedia's equation for net radiative power.
    The next line plugs in all the relevant variables and solves it for the enclosed source temperature T_h.
    The last line displays the answer.

    ... I don't see why you keep asking if I agree with your methods. ... [Jane Q. Public, 2014-09-08]

    Because you've seemed to disagree with my method. That's why I've described my method for calculating the enclosed source temperature from start to finish. Before I post that final answer, can we agree with my method? If not, could you please describe your method?

  274. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    I haven't even tried to calculate an answer yet. I won't know if I agree with your method until I see it. In action, that is. [Jane Q. Public, 2014-09-08]

    Once again, you've already seen my method. I just described my entire method start to finish once again because that's what you demanded:

    ... Create a realistic scenario, draw yourself a diagram, and run some actual numbers on them rather than just tossing equations around without seeing how they fit together in the real world. ... [Jane Q. Public, 2014-08-29]

    See? Same shit different day. You won't sit down and do the calculations start-to-finish, instead you do one small part, then start indulging in your hallmark game of out-of-context he-said, she-said, toss in a straw-man, then claim it's all proved. ... It's simply another illustration of the depths of hand-waving you will go to, rather than actually doing all the calculations on the actual experiment from start to finish. All you're doing is tossing in more straw-men and irrelevancies. You won't do the actual experiment. The only reasonable conclusion to be drawn here is that you won't do it because you know you're wrong. [Jane Q. Public, 2014-08-30]

    I was worried that Jane was just trolling, and had no intention of ever acknowledging my method even if I described them from start-to-finish. Now that I've described my method from start-to-finish and Jane is pretending that he hasn't seen my method "in action" it seems like my worries came true.

    Jane, if you won't do a single, solitary calculation of your own, could you at least please stop pretending that you haven't seen my method from start to finish? Here's my last step again:

    Now that we've agreed on the inner shell temperature of ~149.9F, let's take the last step. Calculate the enclosed source temperature.

    Draw a boundary just inside the inner surface of the enclosing shell. Because nothing in the boundary is changing with time, power in = power out. The same constant electrical power flows in as before the shell was added. Net radiative power flows out from the source to the enclosing shell's inner surface.

    As before, that net radiative power is described by Wikipedia’s equation which accounts for areas and view factors.

    #Completely surrounded by shell with finite conductivity.
    var('sigma T_c T_h A_c A_h F_hc power epsilon_h epsilon_c')
    eq1 = power == sigma*(T_h^4 - T_c^4)/((1-epsilon_h)/(epsilon_h*A_h) + 1/(A_h*F_hc) + (1-epsilon_c)/(epsilon_c*A_c))
    soln4 = solve(eq1.subs(T_c=338.629929346551,power=15028.4258648090,sigma=5.670373e-8,epsilon_h=0.11,epsilon_c=0.11, F_hc=1, A_h=510.064471909788, A_c=511.185932522526),T_h)
    soln4[0].rhs().n()

    ... Please explain what calculations you are using where, because I find it hard to tell the Sage-formatted calculations apart. [Jane Q. Public, 2014-09-08]

    The first line "var('sigma..." declares my variables.
    The line "eq1 = power == sigma..." is my "power in = power out" equation using Wikipedia's equation for net radiative power.
    The next line plugs in

  275. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... Where is your method in action? Is there an answer in there somewhere? You told me you were going to calculate the temperature of the heat source at steady-state. This is utter nonsense. I simply asked you for an explanation of how you calculated the figure you stated (long) before, after we agreed on the nature of the problem and the initial conditions. ... [Jane Q. Public, 2014-09-08]

    Once again, you've seen my method in action from start to finish. I've repeatedly asked if we can agree on that method before posting my final numerical answer. That's because I think you deserve a chance to show that you're capable of judging my method based on its physics, as opposed to reflexively objecting if my numerical answer contradicts the PSI Sky Dragon Slayers.

    I haven't even tried to calculate an answer yet. I won't know if I agree with your method until I see it. In action, that is. [Jane Q. Public, 2014-09-08]

    You've seen my method from start to finish. If you're capable of judging my method based on its physics, why won't you know if you agree with my method until you see my final numerical answer? For instance, suppose I told you that my final numerical answer agrees with the PSI Sky Dragon Slayers. Would that make you agree with my method's physics? In that case, would you really be agreeing with my method, or agreeing with the answer you want to hear?

    If you won't know if you agree with my method until you see my final numerical answer, you're depriving yourself of this chance to demonstrate your intellectual integrity.

    Alternatively, you could finally explain your own method of solving for the enclosed source temperature.

    ... I haven't calculated a solution yet. And THAT is largely due to what I clearly stated before: I have been busy, and don't have a lot of time to devote to this right now. I've been trying to squeeze in what I could, around work and other obligations. ... [Jane Q. Public, 2014-09-08]

    Since it's important to agree on the equations before plugging in values, all you have to do to describe your method is to state the equation you're using, and state the values you'll plug in. This would only take about five minutes. I know because that's what I did below.

    ... I have explained several times now that these Sage equations are not exactly straightforward and easy to read. I have been doing my own calculations in a clear and straightforward manner, making them as easy to read as possible. You really expect me to read this stuff? ... [Jane Q. Public, 2014-09-08]

    Once again, I'm sorry. I take full responsibility. I've changed the formatting so that each value being plugged in is on its own line. Does that make it more readable? I've also added some comments to the code which might help you understand it:

    Now that we've agreed on the inner shell temperature of ~149.9F, let's take the last step. Calculate the enclosed source temperature.

    Draw a boundary just inside the inner surface of the enclosing shell. Because nothing in the boundary is changing with time, power in = power out. The same constant electrical power flows in as before the shell was added. Net radiative power flows out from the source to the enclosing shell's inner surface.

  276. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... I will judge your method based on its physics, when I see your answer. ... [Jane Q. Public, 2014-09-09]

    No, that's my entire point. I already described my physics. If you need to see my final numerical answer before you can judge my method, then you're not actually judging my method based on its physics.

    Ironically, you actually are judging my method based on its physics, which is actually a step forward:

    As before, that net radiative power is described by Wikipedia’s equation which accounts for areas and view factors.

    I just want to make it very clear why I object to the way you ask for agreement, all the while throwing in ambiguities. You say you're using the equation for radiative power, when you're linking to the equation for heat transfer. We already know what the equation for radiative power is: (epsilon)(sigma)T^4. [Jane Q. Public, 2014-09-09]

    Once again, your equation is only for net radiative power (or net heat transfer) to a 0K blackbody. But I've obviously failed to explain net radiative power (or net heat transfer) between two gray surfaces, so we'll have to agree to disagree.

    But this is good. You're actually judging my method based on its physics! I'm proud of you, Jane!

    You seem to be asserting that Jane's equation should be used instead of Wikipedia's equation. Is that the case? If so, all you need to do to catch up is to list the values you'll plug into that equation, like I did. This would only take a few minutes. If you're confused and need help, just ask.

  277. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Once again, we'll obviously have to agree to disagree about the net heat transfer between two gray surfaces.

    Again, you seem to be asserting that Jane's equation should be used instead of Wikipedia's equation. Is that the case? If so, all you need to do to catch up is to list the values you'll plug into that equation, like I did. This would only take a few minutes. If you're confused and need help, just ask.

  278. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    As before, that net radiative power is described by Wikipedia’s equation which accounts for areas and view factors. [Dumb Scientist]

    ... You say you're using the equation for radiative power, when you're linking to the equation for heat transfer. We already know what the equation for radiative power is: (epsilon)(sigma)T^4. [Jane Q. Public, 2014-09-09]

    And then:

    Once again, we'll obviously have to agree to disagree about the net heat transfer between two gray surfaces. [Dumb Scientist]

    What the HELL are you talking about? I understand the equation from Wikipedia. I just happened to mention that you called it a power equation rather than a heat transfer equation. THAT IS ALL. [Jane Q. Public, 2014-09-09]

    We'll obviously have to agree to disagree that I explicitly used the equation for net radiative power, and linked to an equation described as: "The radiative heat transfer from one surface to another is equal to the radiation entering the first surface from the other, minus the radiation leaving the first surface."

    We've agreed that net radiative power is power out minus power in through a boundary, but we'll obviously have to agree to disagree that Wikipedia's radiative heat transfer is "equal" to net radiative power.

    ... THEN I gave you an equation for radiant emittance: (epsilon)(sigma)T^4, and you called it a "heat transfer" equation having something to do with 0K black bodies, which is simply false. ... [Jane Q. Public, 2014-09-09]

    Again, we'll obviously have to agree to disagree that I explicitly used the equation for net radiative power (or net heat transfer). If I hadn't, it might make sense for Jane to say "We already know what the equation for radiative power is: (epsilon)(sigma)T^4."

    Again, we'll obviously have to agree to disagree that I explicitly used the equation for net radiative power (in Watts). If I hadn't, it might make sense for Jane to say we already know that equation is the equation for radiant emittance (in W/m^2).

    Once again, if I had explicitly used the equation for net radiative power, Jane's equation would only be valid for net radiative power (or net heat transfer) to a 0K blackbody. But I've obviously failed to explain net radiative power (or net heat transfer) between two gray surfaces, so we'll have to agree to disagree once again.

    ... Now, when I simply pointed out these apparent MISTAKES in terminology to you, in order to try to keep things straight, you're throwing a fit. Well, don't try to blame this on me. I was just explaining why the things YOU have been saying lead to confusion. I will not apologize for simply trying to

  279. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    We will most certainly have to disagree on that, because it's wrong. That equation is for finding Q, the net heat transfer, which is not "equal" to power at all. It is energy in Joules. [Jane Q. Public, 2014-09-09]

    No, Jane. I linked to Wikipedia's equation for radiative heat transfer, which is in Watts, not Joules. You can verify this by noticing the "dot" over the heat transfer "Q" on the left hand side of that equation. In physics-speak, a "dot" means a "time derivative" so that equation is in units of power (Watts). Or you could've checked the units on the right hand side, and verified that they're also in units of Watts, just like I said.

    ... So where is your final answer for the temperature of the heat source at stead-state? THAT was what you said you were calculating, so where is it? ... [Jane Q. Public, 2014-09-09]

    The final answer for the enclosed source at steady-state is 385.4 K (234.1 F). Anyone with a calculator could have verified this based on my comment yesterday.

    ... How could I possibly be "wrong"? I'm not doing anything. This is YOUR claim, not mine. ... [Jane Q. Public, 2014-09-09]

    Your claim that the source doesn't warm after the passive plate is added is wrong.

    ... Why should I do that? YOU said you were going to refute Latour. It wasn't my claim. You got partway through, now you refuse to finish, and you're trying to blame ME somehow? How do you figure? ... [Jane Q. Public, 2014-09-09]

    The final answer for the enclosed source at steady-state is 385.4 K (234.1 F). Anyone with a calculator could have verified this based on my comment yesterday.

    ... Hahaha! I've been WAITING for you to show me how this is done. I've asked you about five times now to show me. What are you waiting for? I want you to show us how you did what you claimed you have already done -- refute Latour -- so I, and anyone else who reads this later, can check your work. ... Here's your incentive: if you can actually, successfully complete a refutation of Latour, and show us, and it checks out, I will be happy to declare to everyone that I was wrong and you were right about that issue. You have my word. I will shout it out loud. I'll admit it here on Slashdot and even open a Twitter account and post it there. ... I have said what I have to say, unless and until you decide to post the rest of YOUR refutation of Latour. if I have to finish your problem for you, using YOUR methods, I'm still going to declare you a failure, regardless of whether the answer turns out to be correct. Because YOU claimed you could do it. So show us. [Jane Q. Public, 2014-09-09]

    The final answer for the enclosed source at steady-state is 385.4 K (234.1 F). Anyone with a calculator could have verified this based on

  280. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Just so we are absolutely clear on what your claim is: starting at the agreed-upon initial conditions, heat source at 150F, when a hollow sphere is suddenly inserted into the chamber, completely surrounding the heat source, of the specified dimensions, then when allowed to reach steady-state the actual temperature of the heat source is 234.1 degees F.

    Did I summarize that accurately enough? I don't want to re-hash the initial conditions we agreed upon. I still agree with them.

    Yes, that summary is accurate enough.

  281. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... Slashdot has a time limit on these old threads. If you don't post the rest by tomorrow, they will likely close the thread and archive it. I don't know the exact time limit but I have given you plenty of time already, and overly indulged you, but that is ending now. You stated yourself, just above, that it is not difficult to do. ... If this thread is archived before you post the last bit of your supposed refutation (you still have plenty of time), I am going to declare you a fraud and a failure. ... [Jane Q. Public, 2014-09-09]

    After this thread is closed, this conversation can continue here.

  282. Wrong question by cwsumner · · Score: 1

    The question is not if the global warming from CO2 could be bad. The real question is, if that would be worse than turning huge amounts of concentrated authority over to Control Freaks. With the resulting nuclear war that might destroy all life on earth!

    I hope that we can find a solution that does not go to either extreme...

  283. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    Jane's obligations include continuing to spread misinformation about ocean acidification even after I've repeatedly debunked him.

    So I predict that Jane's answer won't include any equations that could be used to calculate the enclosed source temperature. Instead, he'll probably grace us with another lengthy, incoherent rant about "problems" in my analysis which are (as usual) too vague to be expressed in equations. In the extremely unlikely event that Jane musters up the courage and competence to actually write down an equation that could be used to calculate the enclosed source temperature, it will almost certainly violate conservation of energy.

  284. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    We now insert our hollow sphere (somehow, suddenly and magically, it doesn't matter, this is assumed) which fully encloses the heat source. It is 7mm away from the heat source, and it is 7mm away from the wall. And we let things come back up to radiative steady-state.

    And now, to do this properly, we must make a bit of a mental leap, which may be difficult for some people: the total heat transfer now from heat source to the chamber wall is equal to: (heat transfer from heat source to the inside of the enclosing plate) PLUS (heat transfer from the outside of the enclosing plate to the wall).

    This is a place where "thermodynamic thinking" will mess you up. Some people will insist that the TOTAL heat transfer must take place between EACH object. But that is simply not true. This was CLUE #3: a quote from a heat transfer engineering textbook about how "thermodynamic thinking" will lead one astray. [Jane Q. Public, 2014-09-10]

    As I said, in the unlikely event that you wrote down equations, they'd violate conservation of energy. Thermodynamic thinking like this leads one back to reality, not astray. Draw a boundary inside the inner surface of the enclosing shell at your steady-state values. Since nothing inside that boundary is changing, power in = power out. But that's completely impossible. Your solution violates conservation of energy, as predicted.

  285. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    In all that time, did you ever consider drawing a boundary between the source and the enclosing shell at your proposed steady-state temperatures, then calculating power in = power out using the original constant electrical power you calculated before the source was enclosed?

  286. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    But again, did you ever consider drawing a boundary between the source and the enclosing shell at your proposed steady-state temperatures, then calculating power in = power out using the original constant electrical power you calculated before the source was enclosed?

  287. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    We have already shown that your particular application of "drawing boundaries" here was a MISAPPLICATION of the principle you are trying to use. ... [Jane Q. Public, 2014-09-10]

    Jane agreed that the general principle is true that power in = power out through a boundary where nothing inside the boundary is changing. But now that this general principle contradicts Slayer dogma, Jane considers it a misapplication.

    Jane might wonder why cooler power wasn't included in "power in = power out": because it just moves energy from one point outside the boundary to another point that's also outside the boundary. In the same way, energy moved from one point inside the boundary to another point that's also inside the boundary isn't included in the equation describing conservation of energy.

    ... You should have drawn your shell around THAT, and that alone. And you should at least have tried drawing your boundary around your own goddamned heat source, both for initial conditions and your final result, to check your work. But you didn't. What you got was a universe-busting violation of conservation of energy. ... [Jane Q. Public, 2014-09-10]

    Ironically, power in = power out through all the boundaries I've constructed. That includes the boundary around my own "goddamned heat source". But that's not true for Jane's solution, because it violates conservation of energy.

    ... The rate of energy transfer from surface 1 to 2 is (p12) = (e*s) * ( T1^4 - T2^4 ). And T1 is known! ... (e*s) * ( 338.71^4 - T2^4 ) ... [Jane Q. Public, 2014-09-10]

    The enclosed source temperature at steady state is known to be 338.71 K (150F)? No, absolutely not. The chamber wall temperature is constant at 0F, and the electrical power heating the source is constant. But the enclosed source temperature is only constant in Jane's PSI Sky Dragon Slayer bizarro world.

    Jane assumed the source's final enclosed steady state temperature was exactly the same as before it was enclosed. Surprise, Jane found that the source didn't warm! As a result, he got nonsensical answers and had to invent a new energy conservation law where power adds to the energy inside a boundary even if it never crosses that boundary.

  288. Jane/Lonny Eachus goes Sky Dragon Slayer by khayman80 · · Score: 1

    ... if you need to "draw a boundary", it needs to be drawn around the passive plate itself. We have already firmly established that your "boundary" around the heat source and the "enclosing shell" is even thermodynamically incorrect. ... [Jane Q. Public, 2014-09-11]

    Good grief. How predictably ridiculous. All boundaries where nothing inside changes have power in = power out. Seriously. All of them. That's why I tried to convince you that this general principle is true, but obviously we'll have to agree to disagree.

    We have already shown that your particular application of "drawing boundaries" here was a MISAPPLICATION of the principle you are trying to use. ... [Jane Q. Public, 2014-09-11]

    Jane agreed that the general principle is true that power in = power out through a boundary where nothing inside the boundary is changing. But now that this general principle contradicts Slayer dogma, Jane considers it a misapplication.

    Jane might wonder why cooler power wasn't included in "power in = power out": because it just moves energy from one point outside the boundary to another point that's also outside the boundary. In the same way, energy moved from one point inside the boundary to another point that's also inside the boundary isn't included in the equation describing conservation of energy.

    ... You should have drawn your shell around THAT, and that alone. And you should at least have tried drawing your boundary around your own goddamned heat source, both for initial conditions and your final result, to check your work. But you didn't. What you got was a universe-busting violation of conservation of energy. ... [Jane Q. Public, 2014-09-11]

    Ironically, power in = power out through all the boundaries I've constructed. That includes the boundary around my own "goddamned heat source". But that's not true for Jane's solution, because it violates conservation of energy.

    ... The rate of energy transfer from surface 1 to 2 is (p12) = (e*s) * ( T1^4 - T2^4 ). And T1 is known! ... (e*s) * ( 338.71^4 - T2^4 ) ... [Jane Q. Public, 2014-09-10]

    The enclosed source temperature at steady state is known to be 338.71 K (150F)? No, absolutely not. The chamber wall temperature is constant at 0F, and the electrical power heating the source is constant. But the enclosed source temperature is only constant in Jane's PSI Sky Dragon Slayer bizarro world.

    Jane assumed the source's final enclosed steady state temperature was exactly the same as before it was enclosed. Surprise, Jane found that the source didn't warm! As a result, he got nonsensical answers and had to invent a new energy conservation law where power adds to the energy inside a boundary even if it never crosses that boundary.