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Researchers Create 3-Dimensional Chips

Spy der Mann writes "Professor James Lu and other researchers of the Rensselaer Polytechnic Institute, managed to create three-dimensional chips (coral cache) to optimize the design of future processors and prevent overheating. "Make the interconnect wire shorter, and you cut the delay time," says Lu. "A simple way to make them shorter is to stack the transistors.""

49 of 243 comments (clear)

  1. Heat by skraps · · Score: 3, Insightful

    Hopefully there will be a parallel advance in cooling technology.

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  2. 3-d by PunkOfLinux · · Score: 2, Insightful

    I think what they mean is that instead of the processor being on a single plane (a silicon wafer) it's on 2 or more wafers (stacked on top of each other or somesuch)

  3. flavor ridges by cheesebikini · · Score: 4, Funny

    Flat chips suck. These chips have flavor ridges(tm).

  4. Huh... by Peale · · Score: 3, Insightful

    I thought they'd been doing this all along.

    Guess I was just ahead of my time...in my head.

    1. Re:Huh... by BayBlade · · Score: 3, Informative

      Well, thye haven't been doing it ALL along, but they've been doing it more more than a couple years already.

      P4's currently run on a 7 layer design and AMD 64's run between 4 and 9 layers depending on the specific model.

      I'm sure IBM does the same also.

      --

      The key difference between a Programmer and a Senior Programmer is that one of them is Mexican.

    2. Re:Huh... by Zaak · · Score: 4, Informative

      They do already do this... Intel chips have more than 7 layers on them. They arent really stacked wafers either; the film-growing, dopant implanting, CMP, and other processes can be repeated many times on the same wafer.

      Didn't RTFA, but obviously this must be more than just the usual layering.


      The current 7+ layer chips are talking about metalization layers. Wires, in other words. There is only one layer of transistors, which is at the top of the silicon substrate. I am not aware of any production process which has multiple layers of transistors.

      People have been trying to build 3-D ICs for a long time because of the obvious benefits. The article describes a process of bonding multiple wafers in a stack, with wires going between the levels. Sounds to me like it would work, but it would only make the heat dissipation problem worse than it already is. My guess is 3-D chips will be used for low-power devices initially.

      TTFN

    3. Re:Huh... by InvalidError · · Score: 2, Insightful

      7-9 is the number of routing (metallization) layers. The 32-40 figure is probably the number of masks required for the whole fabbing process, including substrate doping masks, insulation masks, metallization masks, etc.

      In any case, doing "cubic" chips is not really going to be practical: volume increases faster than surface (heat transfer) area. If the power density increases faster than the transfer surface, the core will be even more likely to overheat unless the extra circuitry is low-power and can serve as a sort of heat-spreader like caches do in current CPUs.

      Also, there is the matter of IO density, the core needs to be large enough to place all these IO and power pads.

      Large, rectangular, thin chips provide plenty of heat spreading and IO bonding area thanks to large caches and all the transistors being on the same layer.

      Also, going cubic (adding semiconducting layers) would add many extra masks, at least two or three per layer. With vertical transistor spanning three layers, using these would require between eight and 12 extra masks which in turn becomes more than 50 extra processing steps. This could substantially increase failure rates by multiplying the risk of one layer contaminating another, mask misallignment and other small process variations.

      If adding layers was easy and cheap, AMD, Intel and the others would not go so far out of their way to fit their designs into the fewest layers possible. The same generally applies to PCBs.

  5. Hey... by Anonymous Coward · · Score: 5, Funny

    We complain about all the /. stories that are dupes but don't give proper credit to the editors when a non-dupe makes it past their radar. Propz to Timothy for posting an original article! Keep up the good work!

    1. Re:Hey... by ezberry · · Score: 3, Insightful

      Technically you are congratulating him for doing what he is paid to do - no more. I mean, it's an interesting story, but I don't know if he deserves congratulations because he didn't chose to not green-light it.
      Maybe the parent was being facetious, but I can't tell.

  6. Makes sense... by Bananatree3 · · Score: 3, Informative

    It all depends on density of the transistors. You can squeeze 1 square mile into a 1 inch cube, but it will take 334,540,800 individual layers to do so.

  7. I'm Waiting for a 4-D Chip by DanielMarkham · · Score: 5, Funny

    Want to write a time travel game. Or maybe I already did.

    1. Re:I'm Waiting for a 4-D Chip by RobertKozak · · Score: 5, Funny


      Want to write a time travel game. Or maybe I already did.

      I did that already. QA gave me a list of bugs before I even started so I decided to not go ahead with it since it seemed like too much work.

      -- Robert

      --
      Bet this .sig looks familiar.
  8. 3d chips? by Anonymous Coward · · Score: 5, Funny
  9. The age of Terminator has Begun by Nuclear+Elephant · · Score: 2, Funny

    Quick, someone send themselves back in time to blow this guy up.

  10. Not just three dimensions by Anonymous Coward · · Score: 5, Funny

    I read in a paper recently where scientists have had some success in developing a four-dimensional transistor by using nanotubes to set up a quantum Klein bottle wherein the current passes through Bohr space and thus runs parahybolically.

    In practice, you should actually be able to use this method to set up any n-dimensional transistor, provided you can find a sufficiently clean source of power. Modern power supplies have heretofore been plagued by an excess of static dissonance.

    1. Re:Not just three dimensions by Alsee · · Score: 2, Funny

      You can compensate for that static dissonace by rotating the power harmonics.

      -

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  11. How does that prevent overheating? by Kjella · · Score: 4, Insightful

    Essentially, they say this packs it denser. And a cube vs a flat processor = less surface/transistor. I see only factors which makes this *harder* to cool. Maybe someone can explain...

    Kjella

    --
    Live today, because you never know what tomorrow brings
    1. Re:How does that prevent overheating? by Polymorph2000 · · Score: 2, Informative

      They won't manufacture these things at such a level that they become a cube anytime soon. Each layer is very small (think the micrometer (1/1000 of a millimeter) scale or smaller), and based on the article they're talking about using 3 layers.

      The majority of the height of a typical chip is the external packaging, so adding 3 or even 50 layers is unlikely to result in a noticable increase in width, so heat sink design remains unchanged.

      Sure the heat would increase if you don't change the design, but no one would do this. See layers for more info.

      The benefits to this are huge. Lets say can put down 4 layers or transistors instead of 1. If you were making a processor, you could use 3 of the layers for L2 cache (or L1 cache even), and you could potentially have 9MB of cache (1mb for half layer). Already about half of the die space on modern processors is used for L2 cache, so this would result in a huge performance increase with no redesign.

      But realistically no one would do this with current technology as the cost of the processor would increase by a factor of 4 or more.

      Another more useful example is taking the 100 billion or so transistors on a processor, and using 1/4th the area by splitting them up in 4 layers. This results in a smaller chip which means a smaller end device.

      Combine this with the current pace of miniturization, and you might just surpass Moore's law.

      Some Information on Layers: A typical processor or chip is made with a transistor layer, followed by layers of wires (9+ on some intel chips). Being able to stack layers of transistors allows for a huge increase in transistor density, and more efficient designs (less wire = less resistence = less heat). If there is less heat, you can clock the processor higher

      Disclaimer: Some of this information may be incorrect or outdated as I've only taken 1 VLSI course, and designed only 1 processor.

    2. Re:How does that prevent overheating? by karvind · · Score: 3, Informative
      Your point is well taken except there are few technological issues:

      Yield: When you stack 4 layers up, the only economical way would be to test the four layers separately before stacking. Testing means that you would need pull the signals out before you can do that. You will lose some of the wirelength reduction advantage there because you will now have to design the system for intermediate testing. No, testing after all packaging is not a viable option. Do a simple calculation, if probability of one layer working is 0.99, then probability of 4 layers working simultaneously will be (0.99)^4 = 0.96. This will significantly affect your cost.

      Bigger L2 onchip cache: Actually that may not help that much. If you have ran the SPEC2000 or latest benchmarks, too large a L2 cache doesn't help. Yes SPEC benchmarks are not the real world applications. But making L2 bigger also means larger access time. In the end you may end up not gaining anything. A more interesing idea would be to put on-chip main memory. Again the major latency is not due to its being off-chip but due to memory architecture design itself. The only overhead you will save by bringing main memory on chip will be the multiplexing of signals and buffers. That is a small fraction of the off-chip memory latency. The main bottleneck is still the access from the rows and banks.

      Is it really 3D ?: Actually it is not really 3D as you cannot connect two layers where you want. Due to technology problems, the interlayer connections are much bigger than rest of the features. They also have lot of electrical resistance. For example RPI technology requires interlayer interconnects to be 4-6 microns wide with 4-6 microns distance. That is a lot of real estate on chip if you consider that transistor gate length in production is 90 nm. So there is a long way to go.

      Is 3D useful for microprocessor? That is still a debate. But there is somewhere else it may be useful: heterogenous integration. If you want to integrate RF, Analog and Digital: you can make them separately and optimize them separately. In the end you stack them up and that seems to be more promising application.

  12. Already been done. by Anonymous Coward · · Score: 2, Funny

    Frito Lay developed the 3d chip a long time ago: Doritos 3D

  13. Diamond heat sinks by Anonymous Coward · · Score: 2, Interesting

    I remember there were tests using diamond deposited on chips as a strong heat conductor. The whole point was to help make multilayered chips possible. Haven't read anything lately but it sounded promising.

  14. See-through Super-Chips! by Savantissimo · · Score: 4, Informative

    This is really cool stuff. Essentially they're making silicon wafers smaller by removing all the silicon in the substrate after the wafer is fabbed. Then they can put this few-micron-thick layer onto another fabbed wafer - perhaps made with a different process - then they can repeat the process. This allows sensor, analog, processor and memory to be made in the best processes for each function but with communication channels tens of thousands of wires wide and only microns long.

    This article is worth reading - this is going to be huge. Also there is a really fantastic picture of a see-through microprocessor wafer with the article.

    From the article:

    Wafer-level stacking also allows for short connections between different types of chips. "Particularly today the industry is trying to combine memory with the processor, and more than half of the chip is taken up by memory," Lu explains. "When we stack layers, we have a processor on the bottom and layer the memory on top, with a short access time between them." Lu says the reduction of memory access time would be a huge advancement for large-scale computer clusters calculating nuclear reactions and weather broadcasting, for example.

    "You are also creating new functionality," says Nalamasu. "Such technology has vast implications, for example, integrating biochips with silicon chips. The wonderful thing is that if we adopt this technology, we'll develop things we can't even envision today."

    --
    "Is life so dear, or peace so sweet, as to be purchased at the price of chains and slavery?" - Patrick Henry
    1. Re:See-through Super-Chips! by Antique+Geekmeister · · Score: 2, Interesting

      In the short term, expect to see a lot of failed wafers. The alignment problems between different fabricated wafers are going to make the interconnectors mismatch and fail under stress, or as manufactured junctions "creep", especially under thermal load. Also expect to see some nasty behavior with capacitive or inductive coupling between transistors which are vertically on top of each other, instead of merely adjacent. Groundplane, groundbounce, and other related issues are about to take a quantum leap in complexity with this approach.

  15. shorter wires = less resistance by SuperBanana · · Score: 4, Informative
    Hopefully there will be a parallel advance in cooling technology.

    There is, sort of. If the wires are shorter, they have less resistance end-to-end assuming they have the same thickness, are made from the same material, etc etc. Less resistance means less heat (and maybe core voltage could be lowered slightly too, since there would be less of a voltage drop). However, I honestly don't know how much heat comes from the actual junctions versus circuit pathways.

    1. Re:shorter wires = less resistance by jumpingfred · · Score: 4, Insightful

      Most of the heat is disapated accross the transisors. Shorter wires may reduce the capacitance which would lower the amount of charge moving which would lower power.

    2. Re:shorter wires = less resistance by geekee · · Score: 4, Insightful

      "There is, sort of. If the wires are shorter, they have less resistance end-to-end assuming they have the same thickness, are made from the same material, etc etc. Less resistance means less heat (and maybe core voltage could be lowered slightly too, since there would be less of a voltage drop). However, I honestly don't know how much heat comes from the actual junctions versus circuit pathways."

      I don't think people are worried about the heat dissipated in the actual wire. High resistance wires require you to use additional buffers to generate signals with acceptable rise/fall times due to rc charging effects. This costs more power.

      --
      Vote for Pedro
    3. Re:shorter wires = less resistance by ToasterofDOOM · · Score: 3, Interesting

      I have to correct you. Since I = V/R where I is the current in amperes, V is the voltage, and R is the resistance in ohms, less resistance means more current. Current is what creates heat and gets work done. Resistance isn't friction, it's simply the volume of electron flow possible through any given medium. Your observation that there would be more resistance was correct, however it would result in more heat. Take basic high school physics before youn try to work that out again. I would know - we did a demonstration in which two different types of hot dogs were used as resistors. Generic brand hot dogs had much more resistance and didnt do much. Ballpark hot dogs OTOH had less and started to smoke within minutes. Also, if you look on the inside of you computer all those little resistors have thousands to millions or more ohms or resistance.

      --
      I am Spartacus
    4. Re:shorter wires = less resistance by XchristX · · Score: 2, Interesting

      None of this is relevant in the long run. Eventually, chip manufacturers will hit the blank wall of the Heisenberg Uncertainty Principle. As you try to cram more transistors into smaller spaces (even in 3-D), you localize the electron wavefunctions (not to mention that cuttoff is achieved only if the electrons are in conduction bands, which will cease to exist if the transistors are too small). This means that they delocalise in Momentum space, and their Shannon entropy goes up, causing them to heat up drastically and eventually melt. Solid State Technology has taken us far enough, trying to stack chips will only prolong the inevitable. Researchers should focus on a fundamentally new method of computation, like using entangled Greenberger-Horne-Zeilenger states or Bell states for computational purposes.

      --
      l'Homme n'est Rien l'Oeuvre Tout: Gustave Flaubert to George Sand
    5. Re:shorter wires = less resistance by CTho9305 · · Score: 2, Informative

      I suggest taking a look at this paper which discusses theoretical limits on the binary switching model.

  16. Simple? by Detritus · · Score: 3, Insightful
    "A simple way to make them shorter is to stack the transistors."

    There must be a new meaning of the word "simple" that I'm not familiar with.

    --
    Mea navis aericumbens anguillis abundat
  17. Been done before, 23 years ago by chiph · · Score: 3, Interesting
    IBM used a multi layer ceramic module with thermal conduction system on the water-cooled System 3090 mainframe, and still uses the technology today in their zSeries 990, known as the "T-Rex".

    The center layers of the substrate include 16 wiring planes arranged in x-y pairs to maximize wiring efficiency. Metallized, 0.12-mm-diameter vias on 0.5-mm centers are used for x-plane-to-y-plane connections. Voltage reference planes are appropriately interspersed for signal wiring impedance control.

    See: Thermal Conduction Module: A High-Performance Multilayer Ceramic Package

    Chip H.
  18. Hexahedral ICs by mbstone · · Score: 4, Funny
    In other news, Intel engineers have developed a new dual-core motherboard featuring twin hexahedral processors and a new socket design.

    "We've gone beyond zero insertion force -- you just throw the cubes into the enclosure and they will connect," said an Intel spokesman.

    According to the spokesman, the functionality of the system will depend on the orientation of the chips as they land in their respective sockets. If the chips land on 7 or 11, Windows will run; 2, 3, or 12 produces the Blue Screen of Death. Similarly, any other number will produce an exception unless it is thrown again before a 7.

    1. Re:Hexahedral ICs by Alsee · · Score: 2, Funny

      In other words this is a crap design?

      -

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  19. 3D chips by Wardini · · Score: 3, Informative

    There are a lot of hurdles that this document doesn't really get into. It does mention manufacturing but here are some hard core items that need to be considered. 1. Yield goes as e^(-alpha * A) where A is your area and alpha is your yield coefficient. So if you have non-yielding chips on one wafer and you mate it to another wafer that also has non-yielding chips, your total yield goes down at somehting like Y^L where L is the number of layers and Y is the yield given above and Y is 1. So if your yield is 75% and you have 5 layers then your final yield will be only 23%. 2. Testing. If a whole wafer is bad and you put it in your stack of chips, all the chip stacks will be bad. It would be best to test before you put those wafers together. Thats not easy. 3. Packaging is a big issue. Will it be standard wire bonding or something else. Does this thing really generate a lot less heat? And are the interconnects really a lot shorter. If the chip to chip connects cost the same as inter die vias then maybe so but my guess is that those chip to chip connections are a lot more expensive and take a lot more area than vias within the same chip. And alignment of one wafer to the next is also an issue along with getting good interconnect all the way through those stacks. Anyway, those are some thoughts. Its clear to me that 3D chips are a long way off and have there place in very specialized applications in the near term due to the complexities mentioned above. Wardini

  20. ALMOST not off-topic by Kagura · · Score: 4, Informative

    I'd like to thank the author, Spy der Mann, for having the foresight to make a coral cache of the site before posting. Kudos to you, mate.

  21. Gene Amdahl?? by seven+of+five · · Score: 2, Informative

    Didn't Gene Amdahl blow a fortune trying to do this 20+ years ago? I think the company was Trilogy. They did succeed in some die stacking technology but I think they ended up selling the ideas and it went nowhere.

  22. Sorry that isn't covered in High School Physics. by hackwrench · · Score: 2

    At least not in the USA.

    I always thought it was the resistance that caused heat and not the current.
    Anybody got any links that demonstrate what the correct situation is?

    ...and I want a good explanation, not one that just says it is so.

  23. Re:Sorry that isn't covered in High School Physics by ColaMan · · Score: 4, Informative

    It's all interrelated.

    The basic Power equation (in Watts) is Volts times Amps (V*I) .

    Aha! But from Ohms law, Volts is Amps times Resistance (V=I*R). And Amps is Voltage over resistance (I=V/R).

    So substituting back into the original equation ,Power can also be defined as :

    P = (I*R)*I = I^2R
    P = V*(V/R) = V^2R

    So you can hopefully see from all that mess, any change of voltage,current,resistance will change power dissipated.

    --

    You are in a twisty maze of processor lines, all alike.
    There is a lot of hype here.
  24. Re:Sorry that isn't covered in High School Physics by Tolookah · · Score: 3, Informative

    wow... that's so wrong.

    resistance is like the size of a pipe that water is flowing through, consider voltage like water pressure and the current like the flow of the water. the smaller the pipe is, the more pressure you need to pass the water through at the same speed.

    For the next blurb to make sense, I need to say that while transformers step up Voltage, the power calc is the same on both sides of it (V*I on one side == V*I on other side)

    Power lines are actually really low impedance (resistance in AC) wires, but due to their astounding length they have pretty high resistance. To reduce power loss in power lines, the electrical companies step up the Voltage using a transformer. They do this because if you up the voltage in the middle step, (the power lines) the loss in power is much less, as the current delivered to the end user is much less than that going through the lines.

    Thus ends your /. tutorial on power line transmission. For more basic information, along with images, check the howstuffworks article on power distrobution: http://science.howstuffworks.com/power.htm

  25. Re:Sorry that isn't covered in High School Physics by ChatHuant · · Score: 2, Informative

    I always thought it was the resistance that caused heat and not the current. Anybody got any links that demonstrate what the correct situation is?

    (The following is extremely simplified, and ignores alternating voltages, capacitive and inductive effects).

    Two equations:

    U = I*R (Ohm's law)
    and
    E = U*I

    E is the heat energy
    U is the voltage
    I is the current

    Now, it depends on your situation. If your power source is constant voltage (or, in more engineering terms, it has low internal resistance, for example mains power), U is pretty much constant. The current through a load is then determined by the resistance of the load (using equation 1). The amount of heat you get is then proportional to the current, and inversely proportional to your resistance. So, if you plug in a heater to the wall, the lower the resistance of the heating coil, the more current flows through the circuit and the more heat energy you get.

    A less perfect voltage source (say, a battery) has significant internal resistance; the more current you extract from it, the more its voltage drops. Your first equation becomes U = I*(R+r), with R being the internal resistance of your battery. You'll get most power from this setup when the resistance of your load equals the internal resistance. At this point, the heat generated in the battery is equal to the heat generated in the external load.

    And, for fun, you can also build current sources, that force a certain current through any load you connect to them (within limits, of course). They do this by changing their output voltage to match the resistance of the load. There are *many* uses for such sources in electronic devices.

  26. fractal chip? by lawpoop · · Score: 2

    If we have a solid block chip, it's going to get very hot on the inside. Could they design some kind of fractal chip to create a reasonable trade-off between interconnection and surface space so that we could blow air over more of the chip?

    --
    Computers are useless. They can only give you answers.
    -- Pablo Picasso
  27. The Star Trek solution by some+guy+I+know · · Score: 2, Funny
    localize the electron wavefunctions [...] conduction bands [...] delocalise in Momentum space [...] Shannon entropy [...] entangled Greenberger-Horne-Zeilenger states
    Why not just reverse the polarity of the Heisenberg compensators and realign the plasma relays so that the main deflector dish emits a phased tachyon burst of Crayola radiation?
    Problem solved!
    --
    Those who sacrifice security to condemn liberty deserve to repeat history or something. - Benjamin Santayana
  28. Re:Sorry that isn't covered in High School Physics by ColaMan · · Score: 2, Insightful

    You need to look at the whole picture.
    It's not really a case of "where the current is going" - the current flows through the entire circuit, from one side of your voltage source to the other. The important thing to remember is that the current never changes through the whole circuit. The number of electrons/second (amps) is constant through the whole circuit. Only the voltage drop matters as you traverse the circuit. The part of the circuit with the biggest voltage drop across it consumes the most amount of power.

    So, you get a small voltage drop across your wires, which gets turned into a small amount of heat. You normally have a large voltage drop across your load, which gets turned into useful work.... plus a bit of heat- nothing's 100% efficient.

    For example, in an electric motor, the bulk of it is converted to mechanical work... which is still measured in watts, and *that* eventually gets converted to heat (by friction somewhere). The remainder gets lost due to the resistance in the motor windings.

    --

    You are in a twisty maze of processor lines, all alike.
    There is a lot of hype here.
  29. Way too late, but... by anzha · · Score: 3, Interesting

    Seymour Cray with the Cray 3 had his processor bricks made of Gallium arsenide. The wikipedia article has flaws (I'll try to fix later) but it has the point that he went down the route of the 3d chip and circuitry much earlier than this /. story.

    A brilliant man, Seymour...

    --
    Do you know why the road less traveled by is littered with the bones of the unwary?
  30. Re:Sorry that isn't covered in High School Physics by ChatHuant · · Score: 2, Informative
    You can say E=U*I all you want, but that doesn't demonstrate it so. It makes more sense to me that the heat given off should equal a percentage of current * resistance

    I'm not sure I understand what you're looking for, but if you simply want the heat as a function of current and resistance, then replace U in equation 2 and you'll get

    E = I^2 * R


    There you go; you can verify the formula experimentally; double the current and watch the heat output increase four times. It's easiest if you have a calorimeter, but it should be easy to improvise a desktop setup sufficient for a qualitative verification.
  31. Preposterous Scale Integration ... by Ungrounded+Lightning · · Score: 2, Interesting

    PSI is almost upon us.

    FYI: PSI is a tale I spun in the '70s or so, when Large Scale Integration (LSI - eventually with a company named after it) and Very Large Scale Integration (VSLI) were industry buzzwords for ICs with a higher level of integration than a single-digit count of gates or flops to be externally interconnected.

    PSI would involve:
    - constructing a 3-D "chip"
    - using ion beam epitaxy and doping to build it up in layers
    - testing as you go using electron beams for power and signal injection and higher-voltage electron beams for "positive" voltage injection and as test prods (using secondary emission to pull more electrons than they insert and/or to read the voltage on the chip's internal nodes)
    - turning up the beam current to vaporize (and later rebuild correctly) any defective component so the whole thing ends up flawless despite its large gate count. (100% yield!)
    - using diamond for the semiconductor (mainly for its stability and heat conduction properties)
    - running it in an inert atmosphere (so it can get up to red-hot without burning up or converting into graphite)
    - building it as an approximate cube - up to, say, 6 feet on a side
    - powering and cooling it on two opposing faces
    - with water-cooled silver bus-bars the size of the faces
    - connecting it by covering the other four faces with optic fibers for I/O (to interconnect with integrated light-emitting and sensing devices).

    Of course the point of the yarn, in addition to potentially being possible, is the appearance of the resulting device:

    An enormous supercomputer in the form of a 6-foot cube of diamond, glowing slightly red from operating heat, supported by water-cooled silver bus bars in an inert atmosphere within a glass bottle (ala a vacuum tube), with millions of optic fibers to provide it with sufficient I/O.

    Just the sort of thing you'd find as a component in, say, one of the later Skylark spacecraft of E. E. (Doc) Smith's Golden-age SF stories.

    --
    Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
  32. Re:Sorry that isn't covered in High School Physics by b100dian · · Score: 2, Informative

    "Power" is the measure of energy per time unit ( that is, P = E/t ).
    The heat dissipation is directly proportional (by a material-specific constant) with that energy (E), which is
    E = P*t = V*I*t = V^2*t/R
    As mentioned before, the heat dissipation wont' drop because the resistence is lower, but because that lower resistance allows a similar drop in voltage, and E depends on the square of V

    --
    gtkaml.org
  33. Industry has been there, tried that by Ancient_Hacker · · Score: 2, Informative
    this is mighty obvious... but lots of prroblems:
    • each layer of logic takes many steps of masking, diffusion, etching, washing. Each step, even if carefully done, kills a certain percentage of the chips. If you try adding another layer of logic, the yield goes WAAAY down, making the whole process uneconomical
    • You have a 2D-3D mismatch-- heat gets produced in 3D but carried off in only 2D. It's hard enough to cool one thin layer, much harder to keep two layers cool enough.
    • There's considerable capacitive coupling between the layers.. Signal rise times go blooeay, as does the signal to noise ratio. All bad things.
    • Even if you could build and test the layers separately, you still are going to lose chips in the bonding and wiring process.
    • IBM has been promising this kind of thing for about 30 years now. With ideas like frozen mercury for interconnects. Hasnt happened yet.
  34. High school Physics insufficient by zippthorne · · Score: 2, Informative
    Or rather the experiment you pointed out is technically correct, but it does not fully model the situation. In fact, without any followup at all to that expermient describing more complicated circuits or at the very least, mentioning their existance, I would say that your high school cheated you.

    In your frankfurter experiment, The voltage was the same across each of the dogs and so the only thing that was different was the current as a result of the conductivity of the sausages. In this case, P = VI = V^2/R for each of the dogs.

    If you had connected the hot dogs in series, like this:
    Vs+ - {Generic} - - {Ballpark} - gnd
    + - Vgen - -+ + - Vbpark - +

    Vgen + Vbpark = Vs+
    Pgen + Pbpark = Ptotal
    Pgen = Vgen*I
    Pbpark = Vbpark*I
    You would create a voltage divider network. The analysis for which goes like this: The current through any loop in the circuit is constant (e.g. the same current would be going through both the dogs, but the voltage supply would "see" a higher overall resistance so the total current would be less than in either case.)

    In this case, the largest voltage drop is across the higher resistance. since the current is the same through both, the generic dogs will dissipate the most heat in this isntance.

    Imagine cutting the generic dog to a length that made it less resistive than the ballpark. In this case, the total current would increase from the previous, and the ballpark would have the large voltage drop.

    A simple power supply regulator does just that: it puts a resistance in series with the load and adjusts that resistance so that the voltage across the load is the same no matter the load. This presents some serious efficiency issues when the unregulated voltage is significantly greater than the desired voltage.

    In fact, the IC is more complicated than that, introducing parallel and series parallel circuits, and transconductance elements, capacitance and even quantum tunnelling, but suffice to say, in general, the lower the wire resistance, the lower the fraction of heat disipated by the wires themselves.
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