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Scientists Teleport Information Between Ions a Meter Apart

erickhill writes with word that scientists from the University of Maryland have successfully transferred information from one charged atom to another without having it cross the intervening space of about one meter. The academic paper is available in the journal Science, though it requires a subscription to see more than the abstract. Scientists have previously teleported unmolested qubits between photons of light, and between photons and clouds of atoms. But researchers have long sought to teleport qubits between distant atoms. Light's high speed of travel makes photons good transporters of information, but for storing quantum information, atoms are a much better choice because they're easier to hold on to. 'This is a big deal,' comments Myungshik Kim, a quantum physicist at Queen's University Belfast in the United Kingdom. 'To store information as it is in quantum form, you have to have a teleportation scheme available between two stationary qubits. Then you can store them and manipulate them later on.'"

220 comments

  1. Scientists Teleport Information Between Ions by Anonymous Coward · · Score: 5, Funny

    Are they positive?

    1. Re:Scientists Teleport Information Between Ions by v1 · · Score: 2, Insightful

      MPF. that's the most entertaining one-liner I've read in days...

      --
      I work for the Department of Redundancy Department.
    2. Re:Scientists Teleport Information Between Ions by ExtremePhobia · · Score: 0, Redundant

      Are they positive?

      ha, I see what you did there!

    3. Re:Scientists Teleport Information Between Ions by weirdo557 · · Score: 2, Funny

      its uncertain

    4. Re:Scientists Teleport Information Between Ions by Anonymous Coward · · Score: 1, Interesting

      Are they positive?

      Actually, yes, necessarily: it is ytterbium.

    5. Re:Scientists Teleport Information Between Ions by Anonymous Coward · · Score: 0

      I'd rather say it's the funniest two-liner I've read in weeks.

    6. Re:Scientists Teleport Information Between Ions by kimvette · · Score: 1

      negative, however personally I shall remain neutral on the subject.

      --
      The Christian Right is Neither (Christian nor right). See: Matthew 23, Matthew 25, Ezekiel 16:48-50
    7. Re:Scientists Teleport Information Between Ions by Anonymous Coward · · Score: 0

      Are they positive?

      Actually, yes, necessarily: it is ytterbium.

      Now that I've been modded interesting: call me captain obvious; but if you didn't read TFA (The Fine Abstract):

      A quantum bit stored in a single trapped ytterbium ion (Yb+) is teleported to a second Yb+ atom [...].

  2. Unmolested? by PhrostyMcByte · · Score: 5, Funny

    Scientists have previously teleported unmolested qubits....

    Qubit molester insists entanglement was consensual, stay tuned for details at 11.

    1. Re:Unmolested? by jd · · Score: 5, Funny

      In breaking news, the molester has been ordered to both sign and not sign the Atomic Sexual Deviancy Register at the same time.

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    2. Re:Unmolested? by Arthur+Grumbine · · Score: 5, Funny

      Unfortunately, as the molester was observed complying with these requirements, it was determined that the molester only completed one of them.

      --
      Now that I think about it, I'm pretty sure everything I just said is completely wrong.
    3. Re:Unmolested? by angrydotnerd · · Score: 1

      It's a charged word.

    4. Re:Unmolested? by Terminal+Saint · · Score: 4, Funny

      Police efforts to detain the molester for questioning have been hindered by the fact that, despite knowing the molester's exact speed, his location can not be ascertained.

      --
      It's sad when choosing an installation directory on your own qualifies you as an "advanced user."
  3. Sounds neat, but I'm confused... by Chris+Burke · · Score: 4, Interesting

    All sources regarding quantum entanglement/teleportation are quite adamant that you can't use it to actually send information instantaneously. Despite there being "spooky action at a distance", any discernible information had to be transfered when you separated the photons themselves at sub-light speeds. In this case it would be atoms, but I assume it still applies? The article lists applications as super-fast quantum computers (I guess any functional quantum computer could be considered fast at what it does) and quantum encryption (a real application I've heard applied to quantum teleportation, though the encrypted data itself still has to travel at c or less).

    So, am I right, and this is basically the same ol' non-instant-communication but still quite cool kinda teleportation, only using atoms instead of photons? I'm just checking.

    --

    The enemies of Democracy are
    1. Re:Sounds neat, but I'm confused... by Snowtred · · Score: 2, Interesting

      Yeah, I know a little about Quantum, but this kind of teleportation stuff still confuses me. I know there is some kind of logic argument that shows that no actual information can be relayed by this means, but how exactly is the information being transfered? Is it at lightspeed, or something weirder?

    2. Re:Sounds neat, but I'm confused... by Normal_Deviate · · Score: 3, Interesting

      As I understand, the essence of teleportation is that collapsing the wavefunction of the first particle (by measuring it) instantly collapses the wavefunction of the second particle. What I don't understand is why this does not represent transmission of the information that the first particle has been measured. Is it not possible to test whether the second particle's wavefunction has been collapsed by, say, sending it through slits?

    3. Re:Sounds neat, but I'm confused... by bennomatic · · Score: 1

      IANAPhysicist, but my understanding is that while light speed is still an issue in physical space, the information sharing is truly instantaneous in this sort of quantum entanglement. It's not a short delay as light travels that distance, but instantaneous.

      I think the way to think of it is this: there's another (or maybe many other) dimensions in the universe that our feeble minds can't perceive. They still exist, though, and things that may appear to be far apart in space (or even time-space) may be right next to each other in these other dimensions.

      So when asking if there is a necessary delay due to the speed of light, you might be asking the wrong question, since it may seem like the light has to travel great distances across time-space from our perception, but across dimension N, it's right there.

      My metaphor is flawed here, but when standing on UC Berkeley campus, it's a looooong way to the Transamerica Pyramid in SF if you go east, not so bad if you go WSW.

      --
      The CB App. What's your 20?
    4. Re:Sounds neat, but I'm confused... by narcberry · · Score: 1

      I just don't get it.

      You "entangle" two atoms creating the qubit. You separate the atoms, then read the qubit?

      Isn't the information already present in the entanglement, prior to the separation? Isn't it like spray-painting two objects red, sending them to opposite parts of the world and then proclaiming you've got a way to teleport information across the world, but can only send one message, "red" ?

      I'm sure with all the hype I must just misunderstand the whole thing.

      --
      Modding me -1 troll doesn't make me wrong.
    5. Re:Sounds neat, but I'm confused... by MoellerPlesset2 · · Score: 1

      In this case it would be atoms, but I assume it still applies?

      Yes. Setting up the entangled state here requires both atoms to emit photons, so that occurs at light speed.
      It follows the same old rules. Although the state of one atom, once measured, will affect the other atom instantaneously, there's no possibility for FTL communication.

    6. Re:Sounds neat, but I'm confused... by Chris+Burke · · Score: 1

      IANAPhysicist, but my understanding is that while light speed is still an issue in physical space, the information sharing is truly instantaneous in this sort of quantum entanglement. It's not a short delay as light travels that distance, but instantaneous.

      Well the waveform collapse is instantaneous, yes, but as the WP says, you can't actually use it to communicate information from one end to the other.

      I really don't understand the physics of why you're not really sharing information when the waveform collapses. All I understand is that due to Relativity and time dilation, if you could communicate instantly, you could send messages backwards in time and violate causality.

      --

      The enemies of Democracy are
    7. Re:Sounds neat, but I'm confused... by plnix0 · · Score: 2, Informative
      Right. The abstract:

      Quantum teleportation is the faithful transfer of quantum states between systems, relying on the prior establishment of entanglement and using only classical communication during the transmission. We report teleportation of quantum information between atomic quantum memories separated by about 1 meter. A quantum bit stored in a single trapped ytterbium ion (Yb+) is teleported to a second Yb+ atom with an average fidelity of 90% over a replete set of states. The teleportation protocol is based on the heralded entanglement of the atoms through interference and detection of photons emitted from each atom and guided through optical fibers. This scheme may be used for scalable quantum computation and quantum communication.

      So yes, this is not true "teleportation". It relies on light actually moving from one atom to another through optical fibers.

    8. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      Nope. That is pretty much it. Except they anticipate being able to use one of the red rocks to turn the other one blue... and by "they", I mean the uninformed journalists and scientists looking for funding.

    9. Re:Sounds neat, but I'm confused... by Chris+Burke · · Score: 2, Insightful

      Well, I think that's roughly the essence of why you can't send information instantly. All information about the qubits is actually sent with the qubit itself as you separate them to whatever arbitrary distance you're going to do your 'teleportation' trick. It's a little less obvious to me exactly why that is... my understanding is that it's kinda like you have both a black and red marble and you send one around the world, well when one guy checks and sees that his marble is red, the other guy instantly knows that his marble is black. But the first guy doesn't get to pick black or red, and you always knew that the one marble would be the opposite color of the other, so you don't really know anything you didn't before.

      But I'm not really sure if what I'm saying there is even close to right.

      --

      The enemies of Democracy are
    10. Re:Sounds neat, but I'm confused... by Chris+Burke · · Score: 1

      Yes. Setting up the entangled state here requires both atoms to emit photons, so that occurs at light speed.
      It follows the same old rules. Although the state of one atom, once measured, will affect the other atom instantaneously, there's no possibility for FTL communication.

      Okay, can you clarify for me why exactly you can't? Is it because you can't actually control what state the measured atom, and thus the distant atom, will take?

      --

      The enemies of Democracy are
    11. Re:Sounds neat, but I'm confused... by sarkeizen · · Score: 3, Informative

      "teleportation" always seems to lead people to the wrong conclusions. This is about transferring the informational content of a qubit. Which you can't perfectly represent with a classical system. I can see how this as the one commenting physicist claims is a "big deal" when it comes to building quantum computers. But it's not about instantaneous matter transport or superluminal communication.

      I'm not sure what the article meant by ultra secure "quantum communication". Quantum teleportation *is* a quantum communication *channel* but it's unclear what kind of security they are talking about. Perhaps "Quantum Encryption" but that's another term that often sends people down the wrong track.

    12. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 1, Interesting

      I just don't get it.

      You "entangle" two atoms creating the qubit. You separate the atoms, then read the qubit?

      Isn't the information already present in the entanglement, prior to the separation? Isn't it like spray-painting two objects red, sending them to opposite parts of the world and then proclaiming you've got a way to teleport information across the world, but can only send one message, "red" ?

      I'm sure with all the hype I must just misunderstand the whole thing.

      I am a physicist. This is absolutely correct. The whole language is convoluted and based on false premises... teleportation? Give me a break.

    13. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 4, Informative
      If you send a single particle through a slit, you'll get a single spot. If you send many particles through slits, you'll get many spots, just as if you hadn't used entanglement -- they'll be all over the place. Either way, you won't know whether the wavefunction was collapsed by your observation or prior to it by the collapse of an entangled particle's waveform.

      Say particles A and B are entangled, and you are in a position to observe B, but not A. You have no way to know whether A has already been observed, because B will look the same to you either way, unless you already know the state of A.

    14. Re:Sounds neat, but I'm confused... by AaronLawrence · · Score: 1

      Yes, you definitely can NOT control the state. All you can do is measure the unknown state, find out what it is; and the other end will see the same state when it measures. Which of course tells you nothing of use (no information).

      --
      For every expert, there is an equal and opposite expert. - Arthur C. Clarke
    15. Re:Sounds neat, but I'm confused... by v1 · · Score: 4, Informative

      you have both a black and red marble and you send one around the world, well when one guy checks and sees that his marble is red, the other guy instantly knows that his marble is black.

      More to the point, the other guy can find out his marble is black, but only if you communicate to him that your marble was red. Thus information was transferred, but you have to communicate by other means to make it meaningful, which defeats the purpose. It's like sending someone an encrypted message over an insecure channel. Great until you realize you now have to send him the key over the same channel. Sure it's encrypted, but the means of making it useful renders it ineffective.

      --
      I work for the Department of Redundancy Department.
    16. Re:Sounds neat, but I'm confused... by Normal_Deviate · · Score: 1

      This confuses me further. Are you saying there is no way to determine whether particles are interfering with themselves, or others, due to quantum indeterminacy?

    17. Re:Sounds neat, but I'm confused... by v1 · · Score: 2, Insightful

      Although the state of one atom, once measured, will affect the other atom instantaneously, there's no possibility for FTL communication.

      The one part of that conclusion I don't get (and I've seen it several times to this point in the thread) is this: Why can't it relay binary information? If I entangle them, separate them, then either DO or DO NOT measure the first, and then measure the second, won't that tell me if the first one was measured or not?

      Hmmm thinking on this I have to ask for clarification on the purpose of the measuring. I was assuming when you say you measure it, it's an on/off kind of thing. Is it more correct to say that in my above scenario, the way to tell if the second measurement produces information, is to compare it to the measurement of the first? That makes more sense as to why it's a pointless exercise. Because after taking the second measurement, the measurement itself is not enough, you have to compare it with the first measurement? Which requires communication which you are trying to avoid?

      --
      I work for the Department of Redundancy Department.
    18. Re:Sounds neat, but I'm confused... by MoellerPlesset2 · · Score: 5, Informative

      Okay, can you clarify for me why exactly you can't? Is it because you can't actually control what state the measured atom, and thus the distant atom, will take?

      Sure, I'll try: A quantum 'entangled' state means that two systems are in an 'undefined' state in the quantum sense, that are interdependent.
      When one is measured, the other one will _instantanously_ adopt whatever state is 'required' to complement the other one. So one 'knows' instantly what the other is doing, so to speak. Which means a sort of information has been transferred at FTL speed.

      The reason why this can't actually be used for communication is twofold: One is exactly as you said: Because you can't know which state you'll measure, you can't transfer information through that alone. The second reason is that, an entanglement between two systems occurs only if there's an (unmeasured) interaction between them.

      That means you either separate the two systems from each other (as in the classic example of entangled photons moving apart), or as in this case, by letting them interact with photons - that travel at light speed. Either way though, light speed is the best you can do.

    19. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      Quantum Physicists are the only people in the world who could take random crayon, break it in half, put each half in a box, send each box halfway around the world, open both boxes at the same time, and call the fact that the crayons are the same colour at that instant "an instantaneous transfer of information".

      Anyone else looking at that exchange would say "fuck, we seriously fucked up these equations, even if they do model reality pretty closely." Quantum Physicists say "fuck, that's weird... but these equations do such interesting things, they must be how reality works on a fundamental level!"

      Yeah, it's mostly just an issue of terminology, but if you say "information hasn't been exchanged at this point", but by that point the relation between states has been firmly established, then information has been pretty well fucking exchanged, even if you don't know how.

    20. Re:Sounds neat, but I'm confused... by Hurricane78 · · Score: 1

      You would not violate causality. If you transmit the information about some bet from yesterday from A to B, and it reaches B yesterday, and B would instantly send it back, then it would reach A instantly after A transmitted the information.

      But I also wrote above, how you could actually transmit information with it. I remember this from a "Spektrum der Wissenschaft" (German version of the "Scientific American") special issue.

      --
      Any sufficiently advanced intelligence is indistinguishable from stupidity.
    21. Re:Sounds neat, but I'm confused... by shadowbearer · · Score: 1

        You could send something as simple as a yes/no - yes, I've read your message , or no, I haven't.

        Add a few more entanglements to it, and you could send more. One time pad X wrt x. If this particular part gets read, yes; if that other part doesn't get read, no.

        On/off? requiring a shared sequence.

        Someone who understands it better, correct me and be more clear, please.

      SB

      --
      It's old. The more humans I meet, the more I like my cats. At least they are honest.
    22. Re:Sounds neat, but I'm confused... by Chris+Burke · · Score: 2, Funny

      It's like sending someone an encrypted message over an insecure channel. Great until you realize you now have to send him the key over the same channel. Sure it's encrypted, but the means of making it useful renders it ineffective.

      Sure you can, you just need to use public key encryption. So I guess you're saying we need public key quantum entanglement?

      Just kidding, thanks for the clarification. :)

      --

      The enemies of Democracy are
    23. Re:Sounds neat, but I'm confused... by jd · · Score: 2, Funny

      Which goes to prove that teleporting physicists have lost their marbles.

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    24. Re:Sounds neat, but I'm confused... by Hurricane78 · · Score: 1

      Wrong. In Vienna they are transmitting entangled particles trough the air of half the city (between two towers) right now, and then when they reached the target, they can change the local entangled particle. Thereby instantly changing the remote particle.

      So please stop trolling and inform yourself

      Here's how it works, in simple words.

      --
      Any sufficiently advanced intelligence is indistinguishable from stupidity.
    25. Re:Sounds neat, but I'm confused... by disputationist · · Score: 1

      Apparently the use of the term 'teleportation' is causing a lot of confusion. In QM, two particles that have identical states (quantum numbers) are considered indistinguishable; if they were switched, you wouldn't know. TFA describes a process that allows an entire state to be transferred instantaneously from one particle (or system) to another, and since in QM they are the same, the particle has been 'teleported'. There is nothing superluminal here, since before the state can be transferred you have to send some information across at kosher speeds.

    26. Re:Sounds neat, but I'm confused... by mhall119 · · Score: 4, Informative

      You can't determine if a particle is in a super-position or not, because any measurement of it will instantly collapse the waveform on both particles, and if you collapse yours first you will be unable to receive the information being transmitted by the other. You will need to know that the other entangled particle has already been collapsed, before you read yours, and that information still has to get to you by a conventional method.

      --
      http://www.mhall119.com
    27. Re:Sounds neat, but I'm confused... by blueg3 · · Score: 2, Informative

      No, it doesn't. View it from the perspective of the two measuring parties. We'll call them Abe and Bob.

      Each particle has a 50% chance of being in one of two states, + or -. Entanglement means that if Abe's particle is +, Bob's is -, and vice versa.

      Abe measures his particle. Regardless of if his particle is + or -, that doesn't tell him if Bob measured his particle or not. While the values of the measurements are dependent on one another, without information from the other measuring party, the measurer can't tell the difference between the entangled and collapsed states.

    28. Re:Sounds neat, but I'm confused... by Normal_Deviate · · Score: 1

      I thought the essence of the 2-slit experiment was that you can detect quantum indeterminacy without measuring the quantum state, and hence without collapsing the waveform, by observing whether the various possible quantum states are interfering with each other. In the case of 2 slits, if you get fringes you have indeterminacy (particles are going through both slits) and if you get spots then the wavefunctions are collapsed (the particles have been forced to choose a slit). I assume there is an analogous test to see whether particles have been forced to choose their polarization. This seems to be all you need for instant transfer of the message "I have measured the polarization".

    29. Re:Sounds neat, but I'm confused... by Have+Brain+Will+Rent · · Score: 1

      AFAIK whether or not the information is somehow invisibly stored with the entangled entities and so travels with them as they are separated at V = C is an open question.

      --
      The tyrant will always find a pretext for his tyranny - Aesop
    30. Re:Sounds neat, but I'm confused... by mhall119 · · Score: 2, Interesting

      The 2-slit experiment observed quantum super-position, not entanglement. The quantum state was measured when the photons hit the opposite wall, and that measurement only measured the collapsed state, not the super-position. The super-position was only observed in the pattern of interference in the collapsed states.

      The super-position being measured was caused by the photon passing through the two-slits, so even if you took an entangled photon, collapsed it's partner, and sent it through the double-slit, it would still be in a super-position with regard to which slit it passed through, regardless of anything that happened to it's partner.

      --
      http://www.mhall119.com
    31. Re:Sounds neat, but I'm confused... by plnix0 · · Score: 1

      Yes, you definitely can NOT control the state. All you can do is measure the unknown state, find out what it is; and the other end will see the same state when it measures. Which of course tells you nothing of use (no information).

      Actually, the other end will see the opposite state. But it's the same information-wise.

    32. Re:Sounds neat, but I'm confused... by plnix0 · · Score: 1

      The one part of that conclusion I don't get (and I've seen it several times to this point in the thread) is this: Why can't it relay binary information? If I entangle them, separate them, then either DO or DO NOT measure the first, and then measure the second, won't that tell me if the first one was measured or not?

      The 'two' are really one system. If you measure the second, you will get the value of the second. From this, you will also know the value of the first, in essence measuring it at the same time. The values of both will be "collapsed". You won't know whether the first had already been measured, because whether it had been or not, all you get by measuring the second is its value. Not the meta-information 'has-been-measured-before'.

    33. Re:Sounds neat, but I'm confused... by Jamu · · Score: 2, Informative

      Relativity implies that if information goes from A to B instantaneously for some observers, it also goes from A to B in finite time for some other observers. For all the other observers it goes from A to B in negative finite time, from B to A, in other words. For causality, for A to cause B, then information must always travel from A to B.

      Any instantaneous wavefunction collapse cannot transmit information from distant locations, it must create new information for those locations, i.e. a random value.

      --
      Who ordered that?
    34. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 1, Interesting

      no you are wrong, the posts above you are closer.

      as you said in the post you linked, you are "just a curious guy". please don't deny most of the last century of physics just because something seems cool when you don't have any understanding of it.

      thanks.

    35. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      yeah I was thinking if you have 2 billion quantum entangled atoms, a billion on each side of some divide, numbered 1 to a billion, you could unentangle the atoms in that list that correspond to 0 and transfer a gigabit of information?

    36. Re:Sounds neat, but I'm confused... by TapeCutter · · Score: 5, Funny

      "You could send something as simple as a yes/no - yes, I've read your message , or no, I haven't. [snip] Someone who understands it better, correct me and be more clear, please."

      Analogy:
      I have two basket balls, one has a cat inside - I don't know which one.
      I send one basket ball to you.
      I open my basket ball (observation).
      I find it empty so I can deduce the cat is in yours (no information is transfered to you).
      I cannot tell if you have opened yours and observed the cat as dead or alive.
      You open yours and find a dead cat (observation).
      Information is transfered in the normal manner when you call me up and ask why I sent you a dead cat in a basketball.

      --
      And did you exchange a walk on part in the war for a lead role in a cage? - Pink Floyd.
    37. Re:Sounds neat, but I'm confused... by drinkypoo · · Score: 2, Interesting

      So I guess you're saying we need public key quantum entanglement?

      Wouldn't it be hilarious if that turned out to be the case? If you just knew enough about the other member of your pair, that you could actually transmit information? It would make your comment one hell of a Doug Adams-type footnote.

      --
      "You're right," Fisheye says. "I should have set it on 'whip' or 'chop.'"
    38. Re:Sounds neat, but I'm confused... by MoellerPlesset2 · · Score: 1

      I'm not sure what the article meant by ultra secure "quantum communication". Quantum teleportation *is* a quantum communication *channel* but it's unclear what kind of security they are talking about.

      It's the same situation as in 'quantum cryptography'. That is, you can't eavesdrop on it, and while there is information being transferred 'classically' in the open, it gives no help in identifying what's being transferred. I agree it's a bit of a stretch though, because this is a fairly impractical scheme for doing it, if it's your sole purpose.

      There's absolutely no superluminal communication going on though.

    39. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 1, Funny

      Lightspeed? Pfft. It is at Ludicrous Speed!

    40. Re:Sounds neat, but I'm confused... by everweb · · Score: 1

      Is is possible to determine whether either of the particles has been changed to a 'defined' state without 'defining' its state ? Has someone already peeked into the cat's box ?

    41. Re:Sounds neat, but I'm confused... by DigiShaman · · Score: 1

      Abe measures his particle. Regardless of if his particle is + or -, that doesn't tell him if Bob measured his particle or not. While the values of the measurements are dependent on one another, without information from the other measuring party, the measurer can't tell the difference between the entangled and collapsed states

      Let's suppose both Abe and Bob are some form of apparatuses (like a modem). Both of the devices are right next to each other to start with. Inside each device, they have an internal atomic clock. The idea is to get both of them in perfect sync (or close to it) without either one knowing they are in sync. Now, start measuring the states and perhaps the other device will check the state on its end.

      I would image this would be an "implicit" form of communication and the results happen FTL. But even if this works, there would still have to be some form of real-time calibration between the devices to take place due to time-dilation once the two devices are separated at great distances (say, opposite ends of our solar system). It shouldn't be hard as long as the flow of communication continues.

      Assuming I understanding this correctly; if one of the two paired devices loses power or something, they would have to physically be brought back together for a manual re-synchronization at light speeds.

      --
      Life is not for the lazy.
    42. Re:Sounds neat, but I'm confused... by myrdos2 · · Score: 1

      "Now two American physicists have made an important breakthrough by proving that two quantum channels with zero capacity can carry information when used together. That's interesting because it indicates that physicists may have been barking up the wrong tree with this problem: it implies that the quantum capacity of a channel does not uniquely specify its ability for transmitting quantum information (abstract)."

      http://tech.slashdot.org/article.pl?sid=08/08/06

      So does this mean it is possible to send information using entangled particles, but we just have no idea how to do it?

    43. Re:Sounds neat, but I'm confused... by flyingsquid · · Score: 2, Funny
      Yeah, I know a little about Quantum, but this kind of teleportation stuff still confuses me. I know there is some kind of logic argument that shows that no actual information can be relayed by this means, but how exactly is the information being transfered? Is it at lightspeed, or something weirder?

      More importantly, does this kind of teleportation make the same cool sound as the teleportation the original "Star Trek"?

    44. Re:Sounds neat, but I'm confused... by Phroggy · · Score: 2, Interesting

      Hmm.

      Is there any way this could be used, not for sending FTL messages, but exchanging a cipher? You said you can't know which state you'll measure, but if you can measure some as-yet-unknown random state at one end and measure the corresponding state at the other end, then you should be able to use this random pattern of bits to encode a message, which would then be transferred through traditional (light speed or slower) means. The message could be intercepted in transmission, but the cipher couldn't be.

      --
      $x='S24;r)>63/* h@<5+oZ)32"5cz';$me='phroggy'x$];
      $x=~y+ -xz+\0-Tx+;print$_^chop$me for split'',$x;
    45. Re:Sounds neat, but I'm confused... by symbolset · · Score: 1

      Previously entangled qbits decay to the same state, even though their decay is separated by space and time.

      Therefore, it's not necessary for light in its travels to cover all the granular space bits between point A and point B. The line has gaps and lands, and touching the lands between A and B is optional.

      Did I miss something? You physicists and math weenies weigh in here.

      --
      Help stamp out iliturcy.
    46. Re:Sounds neat, but I'm confused... by RightSaidFred99 · · Score: 1

      Let me tell you why the whole thing is bullshit. It's bullshit because if it was true they absolutely _could_ send information with it - yet they hadn't.

      Let me tell you how - time. You and I will come to an agreement. We shall entangle two particles and you shall have one and I shall have one. You will "collapse the waveform" or whatever these Star Trek raised modern physicists want to call it on an even second to send a "1" and on an odd second to send a "0". Since I will instantly see the change on my magic fairy dust atom we shall be able to send information by measuring the time of the change. Sure, our bandwidth won't be real hot, but it's a good experiment, no?

      Hasn't happened, and will never happen because the whole "spooky action at a distance" thing is bullshit.

    47. Re:Sounds neat, but I'm confused... by Zazzalicious · · Score: 1
      No, read this excellent site for info on why the hidden variable theory (both things sprayed red) does not (as far as our knowledge currently indicates) hold water.

      http://www.ipod.org.uk/reality/reality_entangled.asp

      Quote: " Einstein believed the correct way out of this paradox was to assume that Bob's photon (and all particles) possessed some sort of fixed properties which were hidden from our view (generally referred-to as hidden variables). No faster-than-light communication is then required: the particle properties were set when the particles were created. Crucially, though, this would mean the particles possessing more information than quantum theory said they should have. If particles had these hidden variables then quantum theory was wrong."

    48. Re:Sounds neat, but I'm confused... by Khyber · · Score: 1

      I thought it was as simple as just modifying the spin of one entangled particle half to make the other half change, and this could be used as a form of one-way data communication. I didn't think you'd have to store the information beforehand when splitting entangled particles.

      I've also heard that the 'spooky effect' may actually be faster than light. Not good for teleportation but great for data transmission. If we could just build a device, put it on the moon, and have it's entangled twin on earth, and we could do a lag test. The moon is just over one light-second away from us. So to and back would be around two and a half seconds or so, quite measurable lag. Hell even a satellite in space would be just as easy.

      Now building the things, that's a different story.

      --
      Still waiting on Serviscope_minor to wake up to fucking reality and realize that Jessica Price isn't going to fuck him.
    49. Re:Sounds neat, but I'm confused... by grumbel · · Score: 4, Insightful

      The way I understand it:

      * you generate two entangled quantum things
      * you move them apart
      * you look at one of them and figure out its state, by that you knock it out of the superposition
      * magic happens and the (inverse of that) state is transported to the other thing
      * you look at the other thing an confirm that the state is as expected

      Since the stuff is in superposition you shouldn't be able to tell its state beforehand, but due to looking at the other thing an teleportation you can. The other thing has the inverse state thing since they must obey conservation of angular momentum (i.e. one spins up, then the other spins down).

      Now what I don't get is why this involves any 'teleportation' or quantum weirdness at all. Analog experiment:

      * you have two boxes
      * you put into one of those boxes a ball at random
      * you move them apart
      * you look into your box and can now tell if a ball is in the other box or not
      * no magic necessary, no teleportation happens, since the state of both boxes is fixed from the start

      I don't get why this teleportation thing is anything special, since as far as I understand it, its completly normal and matches exactly what you would expect.

    50. Re:Sounds neat, but I'm confused... by azenpunk · · Score: 1

      wait...Schrodinger was a globetrotter?

    51. Re:Sounds neat, but I'm confused... by grumbel · · Score: 1

      I assume you could, but then wouldn't it be the same as just taking a disk with one-time pads with you?

    52. Re:Sounds neat, but I'm confused... by naam00 · · Score: 1

      You cannot measure if the particle has been measured. Your own act of measuring collapses the wave funtion, there's no way to know if it has been measured already at the other end without being told that it has/hasn't happened. You can be sure of -what- they will have measured though.

    53. Re:Sounds neat, but I'm confused... by kmac06 · · Score: 1

      Congratulations, you have independently discovered quantum cryptography (or more accurately, quantum key distribution).

    54. Re:Sounds neat, but I'm confused... by ortholattice · · Score: 1
      Here's yet another very simplified high-level explanation. Alice has a quantum state that is a superposition of 0 and 1, and she wants to teleport this state to Bob. With the help of an additional "entangled pair" that Alice and Bob share, Alice combines her state and her entangled pair half in a certain way, then makes a measurement that destroys her original quantum state. The measurement results in two classical bits. She transmits these two classical bits to Bob. Bob uses the classical bits to reconstruct Alice's original quantum state on his end.

      The speed of teleportation is limited to how fast the classical bits can be transmitted, which is the speed of light.

      However, here is the amazing thing. Alice's state can be represented mathematically by a complex number, and this complex number is reproduced in Bob's reconstruction of her original state at his end. In principle, a complex number holds an infinite amount of information (since its real components hold an infinite number of decimal places). So, in effect Alice is transmitting to Bob an infinite amount of information with the assistance of 2 classical bits. There is a sense in which the quantum entanglement has already transmitted this infinite amount of information to Bob instantaneously - the moment Alice makes her measurement, actually - but Bob needs the two classical bits to make use of this instantaneously transmitted infinite information to reconstruct a quantum state holding the hidden complex number at his end.

      There is a further subtlety here. Even though the transmitted quantum information is infinite, it resides in its own "world" hidden from humans. We can't measure this hidden complex number directly. The hidden complex number determines a probability of measuring a 0 or 1, and we can only estimate this probability with repeated experiments of the same setup over and over (each time destroying the hidden complex number i.e. the teleported state).

      But - and this is important - as long as we don't do a measurement that destroys the hidden complex number, we can play with the quantum state, in combination with other such quantum states. These "other" things can be truly amazing and are the whole point of quantum computers. The challenge is to manipulate and coax the hidden quantum world into interacting in useful ways, so that at the very end of such manipulations we can measure a set of 0 or 1 answers that gives us, for example, a factor of a huge number.

      One other thing. If Alice doesn't transmit the classical bits, Bob has still received one of four possible quantum states (instantaneously in fact), each with an infinite amount of information. Unfortunately, there is nothing that Bob can do to try to determine any of this infinite information - it is all hidden, and the mathematics conspires to forbid its discovery. This is why "real" (human observable) information can't be transmitted faster than light.

    55. Re:Sounds neat, but I'm confused... by KDR_11k · · Score: 1

      What I'm more wondering about is how we know they are in a superposition and actually collapse when we measure rather than collapsing when they are separated.

      --
      Justice is the sheep getting arrested while an impartial judge declares the vote void.
    56. Re:Sounds neat, but I'm confused... by sfazzio · · Score: 4, Informative

      A completely valid arguement-- until 1964:
      http://en.wikipedia.org/wiki/Bell's_theorem

    57. Re:Sounds neat, but I'm confused... by sfazzio · · Score: 1

      It depends on what kind of information you're talking about, classical information or quantum information. You most certainly cannot sent classical information faster than the speed of light. As for the logic behind this thought experiment, you may want to check out:
      http://en.wikipedia.org/wiki/Bell's_theorem

    58. Re:Sounds neat, but I'm confused... by TapeCutter · · Score: 1

      Yes, but not in this universe.

      --
      And did you exchange a walk on part in the war for a lead role in a cage? - Pink Floyd.
    59. Re:Sounds neat, but I'm confused... by The_Wilschon · · Score: 2, Informative

      You can't send quantum information faster than light either. You can cause change to propagate faster than light, but no actual information is conveyed by that change. It is a subtle, but important, distinction.

      --
      SIGSEGV caught, terminating

      wait... not that kind of sig.
    60. Re:Sounds neat, but I'm confused... by ThreeGigs · · Score: 2, Informative

      Wrong.

      The only way to tell if your waveform has collapsed is by measuring it. And measuring it collapses it.
      Thus *every* time you check to see if yours has been collapsed, it will always show as collapsed.

      Go look at yourself in a mirror.
      Now close your eyes.
      Now, you cannot tell when your reflection has opened its eyes, unless you open yours, and if you open yours, the reflection will have its eyes open.

      Same with the waveforms. No matter what, if you look, it'll be collapsed, and you can't tell if it was collapsed before you looked at it, or because you looked at it.

    61. Re:Sounds neat, but I'm confused... by afabbro · · Score: 1

      you have both a black and red marble and you send one around the world, well when one guy checks and sees that his marble is red, the other guy instantly knows that his marble is black.

      More to the point, the other guy can find out his marble is black, but only if you communicate to him that your marble was red.

      You lost me...

      • In New York, I have a magic marble.
      • In Los Angeles, you have my entangled magic marble.
      • In New York, I check my marble and find out it's red. I thus know yours is black.
      • In Los Angeles, you check your marble and find out it's black. You thus know mine is red.

      Are you saying that we can both check, but there's nothing useful to be done with that information? I guess to be useful, I'd have to have a set of marbles and be able to force #1 to red, #2 to red, #3 to black, #4 to red, etc. to make a communication, which you could then read in reverse on your side. This forcing is impossible...?

      --
      Advice: on VPS providers
    62. Re:Sounds neat, but I'm confused... by v1 · · Score: 1

      Are you saying that we can both check, but there's nothing useful to be done with that information?

      Yes. The transmission of information would be for one of you to know either (A) the color of your marble, or (B) the color of the other person's marble, without having looked at your marble.

      Just because one of you can LOOK at your marble, and know the color of BOTH marbles, does not imply the movement of information. The one that looked at his marble still has to get on the phone and call the other and say "hey my marble is RED!" for the other guy to know anything. Requiring communication to avoid communication is pointless.

      Additionally and somewhat related, before you looked at your marble, you already knew there was a red and black marble. When you looked at your marble, you spent an observation to gain information. You only gained one piece of information, not two, because it was already known that if your marble was red theirs was black etc. The second piece of information was already known. It wasn't know to be red or black, it was known to be opposite. So to discover the identity of one is to discover the identity of both. Also, by spending that observation you didn't gain information for the person with the other marble, unless they too spend an observation by listening to you tell them what color your marble was.

      --
      I work for the Department of Redundancy Department.
    63. Re:Sounds neat, but I'm confused... by blueg3 · · Score: 1

      Incorrect. You can never measure a particle as being in an entangled state or a superposition of states. When Abe measures the state of his particle, it's either 0 or 1, regardless of whether Bob has already measured his particle. He cannot make any observations of its state without measuring it.

      This is one of the first things asked and answered about entangled states. Despite involving a seemingly-nonlocal connection between two particles, it's impossible to use entanglement to violate locality (move information faster than light).

    64. Re:Sounds neat, but I'm confused... by blueg3 · · Score: 1

      I think you've skipped what the key part of your communication system is.

      The problem is that you can obtain zero information about the particle without measuring it. You can measure it exactly once. When you measure it, you have a 50% chance each of seeing + or -. It's impossible to measure "has the state collapsed". It's just that with entangled particles, whatever Abe measures must happen to be the opposite of what Bob measures. The only way to use this property to convey information is if Abe tells Bob, "hey, I've measured my particle now, and the result was X". (However, that costs one bit of communication, and the particle can only convey one bit of data.)

    65. Re:Sounds neat, but I'm confused... by sfazzio · · Score: 1

      If you have two entangled qubits separated by a large distance, and you make a measurement on one qubit, the state of the other qubit will change instantaneously. That is to say, the quantum information associated with both of the qubits will change instantaneously over a large distance. You're right in saying that "no actual information is conveyed by that change," if by information you mean classical information-- you certainly couldn't send a message faster than the speed of light. But quantum information is a very different concept.

    66. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      That would be quantum crypography, yes.

    67. Re:Sounds neat, but I'm confused... by DigiShaman · · Score: 1

      Ahh ok, now I understand. Thanks for clearing it up.

      --
      Life is not for the lazy.
    68. Re:Sounds neat, but I'm confused... by TexVex · · Score: 1

      1. General Relativity shows us that if it were possible to travel or communicate faster than light, then it would be possible to communicate with the past.

      2. If you can communicate with the past, then either causality does not apply or the universe has some way set up to deal with potential paradox. Lack of evidence to the contrary seems to indicate that causality holds and the universe can't allow paradox.

      3. Alternatively, there are many worlds theories and other such stuff to allow for communication with an alternate universe's past, but I don't think there's strong evidence to support those kinds of theories.

      4. If causality holds and temporal paradox is not possible, then the universe could still allow for communication with the past, but only in some way that could not allow for paradox to arise. Like, for instance, if the universe were completely deterministic.

      So, in order for FTL to be a reality, the universe must be far weirder than we can imagine -- either effect can precede cause, or the entire structure of spacetime (to include the complete past and future the universe) is set in stone, or there are an infinite number of alternate universes.

      So, that's just Relativity. Now, along comes quantum physics, which shows that there actually are measurable quantum effects that operate faster than light. This is the whole point of Bell's Theorem, which proves to us that either local realism doesn't hold, or the universe is deterministic, or there is a third option that our math and logic and philosophy just can't understand right now.

      --
      Fun with Anagarams! LADS HOST, SHALT DOS. HAS DOLTS. AD SLOTHS, HATS SOLD. ASS HO, LTD.
    69. Re:Sounds neat, but I'm confused... by franl · · Score: 1

      What the parent describes is a local-hidden-variables model (the cat being the hidden variable). QM predicts something different. See http://en.wikipedia.org/wiki/Bell's_theorem.

    70. Re:Sounds neat, but I'm confused... by russotto · · Score: 1

      Your box-and-ball experiment is analagous to a "local hidden variable" theory, and they've been ruled out experimentally.

    71. Re:Sounds neat, but I'm confused... by franl · · Score: 1

      We shall entangle two particles and you shall have one and I shall have one. You will "collapse the waveform" or whatever these Star Trek raised modern physicists want to call it on an even second to send a "1" and on an odd second to send a "0". Since I will instantly see the change on my magic fairy dust atom we shall be able to send information by measuring the time of the change. Sure, our bandwidth won't be real hot, but it's a good experiment, no?

      No. You will not "instantly see the change" to your entangled particle/atom. You must perform a measurement that _always_ gives a random result. The only thing QM promises (and it's quite a promise) is that your random measurement result will always be perfectly correlated to the random measurement result at the other end. This happens even if the two measurement events are so far apart there is not enough time for a signal to move at lightspeed between them.

      Weird, huh?

    72. Re:Sounds neat, but I'm confused... by franl · · Score: 1

      So does this mean it is possible to send information using entangled particles, but we just have no idea how to do it?

      No. Superluminal signaling leads to reverse causality (future events affecting past events), and that's widely considered impossible.

    73. Re:Sounds neat, but I'm confused... by Phroggy · · Score: 1

      I assume you could, but then wouldn't it be the same as just taking a disk with one-time pads with you?

      Yes, but then the disk could be intercepted between point A and point B. If it's a quantum thingie that happens simultaneously on both ends, there's no chance of interception.

      --
      $x='S24;r)>63/* h@<5+oZ)32"5cz';$me='phroggy'x$];
      $x=~y+ -xz+\0-Tx+;print$_^chop$me for split'',$x;
    74. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      Because what it collapse to is completely random, and the receiver cannot tell that the state has been collapsed.

    75. Re:Sounds neat, but I'm confused... by sootman · · Score: 2, Informative

      I have two basket balls, one has a cat inside - I don't know which one.

      The heavier one. Duh. :-)

      --
      Dear Slashdot: next time you want to mess with the site, add a rich-text editor for comments.
    76. Re:Sounds neat, but I'm confused... by TapeCutter · · Score: 1

      Sorry, forgot the /jk tag.

      --
      And did you exchange a walk on part in the war for a lead role in a cage? - Pink Floyd.
    77. Re:Sounds neat, but I'm confused... by blueg3 · · Score: 1

      It's only odd because superposed states don't naturally make sense to people -- understandable, as no macroscopic objects undergo superposition. Entangled particles are not really any different than any other superposition -- it's just that they seem so different because in our real-world experiences, that sort of behavior would require communication.

    78. Re:Sounds neat, but I'm confused... by Anonymous Coward · · Score: 0

      This is exactly the essence of the "hidden variable" theory. However, the theory (or at least any simple form of it) was disproved by the Bell experiments that others have linked to. The theory behind the experiments is a bit involved, because it uses statics from many particles rather than experiments on one individual particle to prove its point.

    79. Re:Sounds neat, but I'm confused... by DrSkwid · · Score: 1

      > the state of the other qubit will change instantaneously

      The change was from undetermined to determined.

      > [they] then measured the first atom (A), thus destroying the delicate quantum information it contained, and also destroying the entanglement. That left the original qubit intact in only the second, recipient atom (B), completing the teleportation.

      To send information would require "setting" the qubit in A and re-observing B. The moment someone does that then it's news.

      --
      There are places where the networks are not touching,and there are places where they are-Boeing's Lori Gunter
  4. Scotty! by Anonymous Coward · · Score: 0

    Beam me up!

    1. Re:Scotty! by bluefoxlucid · · Score: 0, Redundant

      We come in peace! Shoot to kill, shoot to kill, shoot to kill! We come in peace! Shoot to kill! Scotty, beam me up!

  5. Beam me up by Cyrus20 · · Score: 0, Redundant

    Beam me up Scotty!!!

  6. A quantum physicist? by MoellerPlesset2 · · Score: 1

    Is there any other kind?

    1. Re:A quantum physicist? by philspear · · Score: 1

      An indiscrete physicist.

    2. Re:A quantum physicist? by PachmanP · · Score: 1

      well there's those string theory guys, but they might not actually be physicists...

      --
      You're thinking small. Why miniaturize the laser, when we could instead enlarge the sharks? -John Searle
    3. Re:A quantum physicist? by ozphx · · Score: 4, Funny

      You mean a qubit molester?

      --
      3laws: No freebies, no backsies, GTFO.
    4. Re:A quantum physicist? by thatgun · · Score: 1

      Well, I think you know the answer to that.

    5. Re:A quantum physicist? by Anonymous Coward · · Score: 0

      You magnificent bastard!

  7. All Scotties aside... by samriel · · Score: 0

    We know now that we can indeed transmit information through space. Now, all we have to do is find a way to kick Heisenberg's ass and precisely measure each particle, and transcribe that as information. In all seriousness, we could indeed be frickin' teleporting to work in the next 100 years. Or shorter. Let's hope we invent time travel first, so we don't have to.

    1. Re:All Scotties aside... by BiggerIsBetter · · Score: 1

      In all seriousness, we could indeed be frickin' teleporting to work in the next 100 years. Or shorter. Let's hope we invent time travel first, so we don't have to.

      What makes you think there's a difference? Walking across town would appear instantaneous if you went back the precise amount of time it takes you to walk there, except that you'd be that much older when you arrived.

      --
      Forget thrust, drag, lift and weight. Airplanes fly because of money.
  8. How fast is it really? by alvinrod · · Score: 1

    TFA (The Science News article) states 'instantly' and I can't actually read the academic paper (bugmenot doesn't seem to have a working login) but does anyone who's more familiar with this area know whether or not it's actually limited to the speed of light, or if we're actually seeing something that's capable of moving faster.

    The article makes it sound as though it's instantaneous, but has this actually been measured to show that it's instantaneous or is the relatively short distance at which the "teleport" is performed only making it seem as though it were instantaneous? The implications of something like that are freaking sweet, but I don't really want to get my hopes up.

    1. Re:How fast is it really? by ITEric · · Score: 1

      I don't know about you, but when were talking about light traveling 1m vs. "instantly", I'd be pretty impressed if they could actually measure a difference.

      --
      The most exciting phrase to hear in science, the one that heralds new discoveries, is not 'Eureka!' but 'That's funny...
    2. Re:How fast is it really? by blueg3 · · Score: 2, Informative

      You most certainly can measure the propagation time of light over distances of one meter. It takes on the order of 10^-8 seconds for light to travel 1 m, and we have time measurement devices better than ns. (Actually, using clever techniques, you can do way better than meters.)

    3. Re:How fast is it really? by Anonymous Coward · · Score: 0

      > I don't know about you, but when were talking about light traveling 1m vs. "instantly", I'd be pretty impressed if they could actually measure a difference.

      Light is as slow as heck. We can measure down to below an attosecond (10^18 s) in the lab, which is 10^10 (well over a billion) times less than the time it takes light to travel a metre.

      And "instantly" doesn't mean "damn fast", it means instantly, in zero time. Collapse of entanglement propagates from one particle to its entangled partner instantly, regardless of distance.

      Check out Bell's Theorem if you want to know more.

  9. A question that maybe someone might answer... by joocemann · · Score: 1

    From the article they are saying that the entanglement has occurred, etc.... they also say that they know the entanglement occurs 1/100M times or so.

    My question... If observation destroys the situation they describe, how to they know the entanglement happened at all?

    Anyone know?

    1. Re:A question that maybe someone might answer... by disputationist · · Score: 2, Informative

      They know it was entangled because they prepared the state way. For example, if you have a spin zero particle that splits up into two particles, and you measure one as spin up, the other must be necessarily spin down, no matter how far away it is, because of the conservation of angular momentum. Or you can think of a neutral particle splitting into positive and negative ones. So I guess it is ultimately the consequence of some conservation law.

    2. Re:A question that maybe someone might answer... by franl · · Score: 1

      The parent is correct, as far as it goes. The weird bit that QM adds is that the two entangled particles will be measured to have a random spin, but they are always opposite spins. Do the experiment a million times, and each measurement gives "spin up" 50% of the time and "spin down" 50% of the time, but the other measurement is always the opposite. If the measurement events are spacelike-separated (i.e., no signal can move between them), how can they give correlated but totally random results? The standard QM explanation is that measuring one particle instantaneously collapses the wavefunction that describes both particles, thus fixing the result of the other measurement. This is Einstein's "spooky action at a distance" that he so hated.

  10. IANAP Questions for someone who is. by John.P.Jones · · Score: 1

    Okay I am not a physicist, but am interested in understanding a bit more about what is going on here.

    Is the following description (model) a reaonably accurate portrayal of what is happening here?

    We have two atoms (A1 & A2) that are in two different (non-entangled) quantum states (Q1 & Q2), at two locations (L1 & L2) separated by 1 m, at which point we allow A1 to interact (quantum mechanically) with a photon which then is 'transmitted' along the vector (L2-L1) and is then 'received' at L2 and allowed to interact with A2 to evolve its quantum state. The process is repeated a finite number of times, after which A2 is left in a quantum state Q1 (the initial state of A1). Or does A2's state simply approach Q1 with some non-zero but bounded error?

    If so, can you answer these questions and if not, how does the difference between my model of what is happening and what is actually happening effect the validity of the question and its answer (to the extent that it is still valid)...

    Throughout these interactions is the state evolution of A1 minimal so that the state is still near or identical to Q1 and these two atoms are now entangled or is the initial atom A1 left in a vastly different quantum state Q3? Or perhaps we can exchange the two quantum states (obviously this would require bi-directional photon communication).

    If the final state of A1 is different then its initial state, can we modify the procedure to allow A1 & A2 to converge on a common state Q3?

    Is the 4-momentum part of this quantum state (obviously the position is not)?

    If you are cloning a state Q1 which has a corresponding energy E1 how does that energy relate to the cumulative energy of the transmitted photons (I assume the process isn't reasonably efficient), and is that difference dependent on the initial energy of the A2 atom?

  11. Bell's theorem by plnix0 · · Score: 1
    According to Bell's Theorem, separated particles can be correlated such that observing one will affect the state of the other, disproving locality. However, the no-communication theorem states that this cannot actually be used to communicate.

    The idea of instant communication is quite fascinating, but it doesn't really apply to this study. The communication they showed is not truly instantaneous, as it relies on the transport of photons from one atom to another (read the abstract, which says as much).

    1. Re:Bell's theorem by blueg3 · · Score: 2, Insightful

      The teleportation is instantaneous. (A philosophy-inclined physicist might object to you applying the label "instantaneous", since it implies a signal is propagating instantaneously -- but there's no signal at all.) However, the teleportation cannot be used for communication without information transfer -- which means the communication is bound by the speed you can transfer that information (which is lightspeed).

    2. Re:Bell's theorem by MoellerPlesset2 · · Score: 1

      You're talking about entanglement, not 'teleportation'. This uses entanglement but it is _not_ instantaneous in any way. It requires having each atom emit a photon, allowing for those photons to become entangled, then performing a measurement on them, and "classically" communicating the results of that measurement so that the 'receiving' end knows what phase to put on a microwave pulse that has the end result of recreating the state that's being transferred.

    3. Re:Bell's theorem by blueg3 · · Score: 1

      I suppose depending on what part you view as the "teleportation", it is either instantaneous or limited to communication speed, yes. Typically, people have referred to the state swap between entangled particles as the real "teleportation", which is an instantaneous process. To perform the whole teleportation procedure, one side has to communicate data to the other during the procedure, yes.

  12. Bah! by GaryOlson · · Score: 5, Funny

    My mother always knew what I had done without anyone telling her. Or whatever I was going to do before I took action. I hear other mothers have the same ability. Therefore, all mothers must exist in some state of constant quantum communication with each other.

    --
    Every mans' island needs an ocean; choose your ocean carefully.
    1. Re:Bah! by ustolemyname · · Score: 1

      Mild correction: all mothers must exist in some state of constant quantum communication with their children.

    2. Re:Bah! by Voyager529 · · Score: 1

      No, I've gotten busted a few times by my friends' mom. They're in a constant state of quantum communication with all kids and moms.

  13. No, they have not discovered the ansible... by plnix0 · · Score: 1

    Any use of the word "instantly" is, quite simply, hype. It's instantaneous like an "instant message" is instantaneous. Not that this isn't a cool discovery; it is. But it's not teleportation and it's not instant communication.

    1. Re:No, they have not discovered the ansible... by 93+Escort+Wagon · · Score: 2, Informative

      Any use of the word "instantly" is, quite simply, hype. It's instantaneous like an "instant message" is instantaneous. Not that this isn't a cool discovery; it is. But it's not teleportation and it's not instant communication.

      No, "spooky action at a distance" is indeed instantaneous. It's a quantum phenomena - it's not based on the information being transmitted (which would indeed be limited to the speed of light).

      --
      #DeleteChrome
    2. Re:No, they have not discovered the ansible... by plnix0 · · Score: 1

      Right, but the transfer of information is still not instantaneous. Just the transfer of the quantum state.

  14. Just read it yourself by Anonymous Coward · · Score: 0

    http://rapidshare.com/files/188497112/quantum_teleportation_486.tar.html

    Consider this as a long and very detailed "quote" ;)

    Please subscribe to Science magazine if you can.

    Freedom of knowledge, teh internetz has you.

    1. Re:Just read it yourself by Anonymous Coward · · Score: 0

      Much appreciated.

  15. A New Form of Wireless by Nom+du+Keyboard · · Score: 2

    Adds a whole new meaning to the term: wireless.

    --
    "It's the height of ridiculousness to say for those 9 lines you get hundreds of millions."
    1. Re:A New Form of Wireless by Anonymous Coward · · Score: 0

      No, actually, it still means pretty much the same thing it always did. No wires.

    2. Re:A New Form of Wireless by markdavis · · Score: 1

      Absolutely. Quantum computing aside, the idea of wireless communications via entanglement is absolutely fascinating. It could lead to instant communication with anyone, just about anywhere in the universe! No towers, no RFI, and absolutely secure from point to point. The major downside is that you probably have to have a centralized "entanglement switchboards" to actually relay the communications from one person to another, since you can't entangle every device to every other possible device. So that would be the weak point for security and reliability (and big brother spying).

      Anyway, I can imagine a day when my portable computer/communications device, whatever form that takes, can talk to just about anything, without ever having to think about where I am, and possibly with unimaginable runtime and unimaginable bandwidth.

      Oh well, back to the wonderful world of cell towers and WiFi....

    3. Re:A New Form of Wireless by Anonymous Coward · · Score: 0

      The major downside is that you probably have to have a centralized "entanglement switchboards" to actually relay the communications from one person to another, since you can't entangle every device to every other possible device. So that would be the weak point for security and reliability (and big brother spying).

      No problem. Just use a Borg encryption algorithm.

    4. Re:A New Form of Wireless by RightSaidFred99 · · Score: 1

      The other downside: it's science fiction and will never happen.

    5. Re:A New Form of Wireless by markdavis · · Score: 1

      It is science fiction now, but why would you say it will never happen? We can't know that. It might seem like "magic" now, but my scenario is based on current science experiments. I am sure a lot of the technology we use now was science fiction to people just 50 years ago.

  16. And it begins.... by Proudrooster · · Score: 1

    Just think, if they can figure out how this works or at least how to exploit it. You could use these for secure long distance communication. No more cell towers, just entangle some particles, put one in a rack and the other in the cell phone.

    I am curious to know if this "spooky action at a distance" as Einstein referred to it, is faster than light communication. We won't know this until we put one in a Mars rover and launch it. I would also be interested to know if these particles are entangled in another dimension outside of space time. I hope this can be figured out in our lifetime.

    1. Re:And it begins.... by blueg3 · · Score: 1

      It is not faster-than-light communication. We will know immediately, and do. (You don't need large time scales to test "immediate" communications -- we can measure that to sufficient resolution on Earth.)

      I'm not sure your statement on "if [they] are entangled in another dimension" is really meaningful. Entanglement is a property of objects in quantum states.

      You can already exploit it, though -- it's fairly similar to the basis for quantum "encryption" (by one definition), which is not encryption at all, but a form of communication that is impossible to intercept without rapid detection. You can create these states with photons, which is what is done. It's unreasonably complex to use outside of special applications and cool demos, though.

    2. Re:And it begins.... by wdef · · Score: 1

      I'm not sure your statement on "if [they] are entangled in another dimension" is really meaningful. Entanglement is a property of objects in quantum states.

      Well, mathematically speaking quantum states can be construed as existing in a Hilbert space, of which physical "real" space is a subspace. But that is just a construct that gives the right answers. Hilbert space only has a "physical" meaning when a measurement is made (when the so-called "collapse" of the wave function seems to occur). Also, Hilbert spaces of different numbers of dimensions are required to model different problems in QM (and this is true in classical mechanics also). If the poster is asking "do we need more than 3+1 physical dimensions to model some physical entanglement problems in QM?", I think the answer could probably be yes, though it's a long time since I studied QM.

      Also, the poster may be thinking of the fascinating Many Worlds interpretation of QM, in which each possible outcome for a measurement exists in a separate parallel universe. This hypothesis has been said to explain by a single photon can interfere with itself - because photons are "aware" of their sister states in parallel universes.

    3. Re:And it begins.... by blueg3 · · Score: 1

      Hmm. I think your interpretation of what a Hilbert space is differs quite significantly from what I've learned.

  17. Mod patent up. by Hurricane78 · · Score: 3, Informative

    Yeah. I will try to give a simplified explanation to non-experts (I'm just a curious guy myself):

    First you entangle two particles. Then you let one travel somewhere. (If at bumps into another particle on that way, the particle loses the entanglement.)
    Now if you "measure" the first particle, the "wavefunction" (the entanglement) of both particles collapses in a specific way.

    By measuring that traveled particle, you can get the information on how the other particle got manipulated when it lost the entanglement.
    The nice thing about this is, that it is instantly. There is no measurable delay.

    So you could theoretically entangle a ton of material with another ton of material, and then send the first ton up to some remote planet. (Which of course would take very long. But you could send it at very high speeds which no human could survive too. For example by using a rocket that uses nuclear explosions as propulsion.)
    Say you have defined, that you can use 0.5 kg of material every year for each side, and split the ton in such "blocks". Then you just write the outgoing 0.5 kg block (you collapse the entanglement) over the year, and read the incoming 0.5 kg block at the end of every year. By using a special encoding, you can detect where the data ends, and where the data collapsed trough your measurement. Or you just pipeline the to-be-written data on both sides, and read at the end of every month, week, day, hour, minute, second... whatever is most reasonable. (Making it a buffered transfer of blocks.)

    This would give you a thousand years of infinite-speed (depending on your read rate) communication with the bandwidth of 0.5 kg of material per year (~1,37 g per day). (The amount of bits depends on the material.)

    --
    Any sufficiently advanced intelligence is indistinguishable from stupidity.
    1. Re:Mod patent up. by EdZ · · Score: 4, Informative

      Oh, if it were that easy. When you collapse the wave function my measuring one 'end' of your hypothetical particle-block, you: have NO WAY of influencing HOW it collapses, and thus cannot send any information to the other 'end'. You cannot determine what spin you will observe, only that the opposite spin will be observed on the other particle.

    2. Re:Mod patent up. by tylerni7 · · Score: 3, Insightful

      I don't think that is how it works (although IANAP)

      If you check to see if a block you have is collapsed, then suddenly it becomes collapsed, even if it wasn't before. That means you can't tell what it was supposed to look like before.

      The other option is to only look at the entangled matter after you are sure it has collapsed, and see how the collapsing happened. However, this is also impossible. The way the qbits collapse is completely random, so you can't get any useful information out of reading them.

      The best way to think about it is you have two coins taped to each other head to tail or something.
      Then the coins are flipped, and separated without looking at them. Then take these coins to opposite ends of the universe.
      Now, as soon as one coin is observed, the value of the other coin is known as well. However, looking at either coin does not help to relay information. The only way to do that would be to know how the coin was going to land before looking at it. Or to be able to somehow observe the coin and know if the other has been observed.

    3. Re:Mod patent up. by Arguendo · · Score: 1

      IANAP but am curious.

      If you can still control WHEN it collapses, can't you send information as long as both sides have awesome time references? E.g., if it collapses on an even second, it's a 1, and if it collapses on an odd second, it's a 0. I understand that practical applications would be enormously complex, but it seems like you should be able to send information in principle if you can control some aspect of it.

    4. Re:Mod patent up. by plnix0 · · Score: 1

      There are different ways of measuring, each of which have a different effect on the particle. When measuring an electron, you can orient your measuring device at any of three different perpendicular angles. The angle at which you measure affects the probability of the entangled particle registering at the (opposites of) that angle and the other two angles. See here.

    5. Re:Mod patent up. by Chandon+Seldon · · Score: 3, Informative

      Unfortunately, you can't do either of the things you want to do. Relativity says you can't have synchronized clocks and quantum mechanics doesn't give you any way to know when/if the wave was collapsed.

      --
      -- The act of censorship is always worse than whatever is being censored. Always.
    6. Re:Mod patent up. by illegalcortex · · Score: 1

      If they can't tell that the other end has already collapsed when they check one end, then how do they know this whole entangling thing works and both ends collapse in tandem?

    7. Re:Mod patent up. by shaitand · · Score: 1

      Because the other end is at the opposite side of the lab. Light detect by their eyes tells them whether their assistant collapsed one end and the comparison of measurement tells them whether they read the same information their assistant did.

      But all of this verification requires information to be passed by ordinary non-quantum means and if you are going to do that you might as well just send a radio signal.

    8. Re:Mod patent up. by Zazzalicious · · Score: 1

      That is so wrong... you cannot transfer information at above the speed of light. You can demonstrate that a measurement at one end instantly affects the other end, but there is NO WAY of using that fact to actually transfer information. i.e. You have to have knowledge of the results of the measurement at both ends to make the inference that entanglement exists. That knowledge can only travel at the speed of light.

    9. Re:Mod patent up. by Hurricane78 · · Score: 1

      Do you have any information on this, other than all-caps words?

      Because I read a multitude of articles and papers of people, doing exactly what you claim to be impossible.

      I'm even going to find an article on it for you: http://www.innovations-report.de/html/berichte/physik_astronomie/bericht-32526.html
      They "beamed" particles 600m far. Which is exactly a collapse of the entanglement with transfer of information without any delay. And this is from 2004!
      And here's the guy who did it: http://homepage.univie.ac.at/franz.embacher/Quantentheorie/
      Go on, and tell him that he did not do what he claims, and that you know more about quantum theory than he does. Please. Go on.
      Because I'd love to see the answer you will get.

      --
      Any sufficiently advanced intelligence is indistinguishable from stupidity.
  18. Re:Sounds neat, but parent needs a MOD UP by Chris+Burke · · Score: 1

    Thank you for the explanation, that was very helpful.

    One more question, about measurement. Is there any way to know that measurement has taken place at the other end and your local qubit has collapsed? Or would determining that constitute a measurement in and of itself, meaning if it hadn't been collapsed it then would be so you wouldn't know what happened? I mean, I know the answer is you can't communicate instantly, I'm just figuring out why (mostly to help explain to people with roughly my same layman's understanding of physics why instant communication is impossible).

    --

    The enemies of Democracy are
  19. Damn... by fenix849 · · Score: 4, Funny

    Ok, who voted for the beammeupscotty tag?

    I can't think of a worse place to be beamed, than 'up scotty'.

  20. O, how about this for an explanation? by ivoras · · Score: 1

    You have two entangled particles A and B and send particle B somewhere else. Then you take a reading of A and call this reading X. You don't really know what is the meaning of X - did you observe it first or did someone else observed B first but you do know that if someone observed B next he will certainly get reading X back to him. Thus it's useless for communication.

    The only way this seems useful to me is if we need to keep something perfectly identical to something else, but it can't work that way either, since quantum effects don't work on bigger scales (nothing's preventing you from smashing particle B but it won't affect particle A at all, right?)

    It's sort of pointless on a bigger scale - tear a piece of paper in the dark, then send one piece in another room, come back to the first one and turn on the light - you can certainly declare the the shape of the tear of the other piece will perfectly match what you have here :) In other words, there's no analogy we can use, at all, for any communication purpose.

    --
    -- Sig down
  21. Bell's Theorem can do FTL comms just fine by Anonymous Coward · · Score: 0

    Just arrange entangled pairs A+B of qubits in a line, separate the A's from the B's while preserving the linear order, and send the line of B's somewhere remote at less than lightspeed while leaving the line of A's behind.

    Then encode some information as lengths of time pulses, and apply those lengths to the line of A qubits as intervals between adjacent qubit collapse (read each one to make it collapse). The corresponding B's will collapse instantly in the same order and with the same time intervals, and the information you encoded as collapse intervals is available identically and instantly at location B, regardless of distance. Note that the value to which each qubit collapses is irrelevant: data is carried by the time intervals between loss of entanglement in adjacent qubits in the line.

    Since the encoded data was not carried by the slow-moving B qubits on their outbound trip, but is entirely new data available only at the time that the A's are collapsed, this is FTL transfer of information which can be used to communicate at arbitrary distance. Note also that two A+B pairs give you bidirectional communication, and this works instantly despite the time slip between A and B inertial frames on B's outbound journey. Time travel of information (forward in time in one direction and backwards in time in the other) is going to provide endless hours of heated debate. ;-)

    Pity that you can use the entangled qubits only once. I guess outbound motherships are going to be carrying as large a store of them as they possibly can, and they're going to be priceless. (Particularly since qubits collapse rather easily so you need redundancy and a very robust encoding scheme to avoid data loss.)

    And leave poor Einstein alone. He never did feel at home with QM, but liking it is not a prerequisite for being able to use it. Reality likes to be bizarre occasionally. ;-)

    1. Re:Bell's Theorem can do FTL comms just fine by plnix0 · · Score: 1

      Seems clever, but how do you detect disentanglement?

    2. Re:Bell's Theorem can do FTL comms just fine by Anonymous Coward · · Score: 0

      That appears to have a variety of solutions, all dependent on the specific details of qubit implementation (look up entanglement detection and witnesses). It's a very active area.

      But it's a separate issue from the principle of FTL communication of information through Bell.

      Of course, a showstopper could appear at any time ... but then, so could new opportunities. ;-)

    3. Re:Bell's Theorem can do FTL comms just fine by franl · · Score: 1

      He can't. He's basically saying that his measurements will impose a pattern on the series of particles one one side, and a correlated pattern on the series of particles on the other side. The _problem_ is that the patterns are random on both sides.

      Seriously, FTL signaling enables reverse causality (i.e., future events affecting past events). And that just isn't going to happen.

  22. what, no glitter involved? by Eil · · Score: 1

    Hey physics types: So I take it this can in no way lead to the future development of the transporter?

    1. Re:what, no glitter involved? by WarJolt · · Score: 1

      E=mc^2
      Only works if you destroy the original.

  23. Transmutation of elements. by Anonymous Coward · · Score: 0

    This may be an enormous breakthrough but these scientists are wasting their time. They should be spending their time (and budgets) working on transmutation of elements. Then, we can turn gold into a much more desired substance, lead.

  24. The Metamorphosis of Prime Intellect by xonar · · Score: 1
  25. Apparently all our physicists have finally left /. by dhudson0001 · · Score: 1

    ...for kurzweilAI.net

  26. Re:Sounds neat, but parent needs a MOD UP by MoellerPlesset2 · · Score: 1

    One more question, about measurement. Is there any way to know that measurement has taken place at the other end and your local qubit has collapsed? Or would determining that constitute a measurement in and of itself, meaning if it hadn't been collapsed it then would be so you wouldn't know what happened?

    A good question. Now, determining if the thing has collapsed would require a measurement. Any interaction that could be used determine the state is a measurement of the state. But, that doesn't mean it's impossible to tell the difference, in the sense that we still know that's what happens.

    Consider the opposite scenario: One system does not or can not 'know' that the other has been measured. That constitutes what they call a 'local hidden variable theory'. In other words, that the state of the system/particle isn't actually undefined and never was - it had a 'hidden' value, one that you just didn't know about until you measured it. That's the only alternate explanation for how the thing can 'know' which value to assume once it's measured (e.g. clockwise polarization for a photon if it was entangled with a photon that'd been measured as counterclockwise-polarized)

    I'm almost hesitant to call it an 'alternative' explanation, because it's really the simpler idea. The states aren't genuinely undetermined, it's jus that we don't know what it is. However, it's also the wrong explanation - because of http://en.wikipedia.org/wiki/Bell's_theorem. A brilliant bit of work that showed you could in fact test and measure whether there were such local hidden variables. There aren't. Quantum weirdness won the battle.

    So you can tell that the states are genuinely undefined, and you can tell that this collapse occurs instantly. But you can't tell whether the collapse has actually occurred in any particular case. Now that I think of it, if you could, it would allow for FTL communication since you could communicate by, say, measuring or not measuring one of the particles at some predetermined points in time.

  27. Don't know if I'd be concerned about the security. by Anonymous Coward · · Score: 0

    For protection of information, there's still the encryption method of your choice.

    And as far as prosecution goes, all the switchboard would tell you is the terminal - not the user, not the location, and if the terminal is modular (as many NICs and cell radios are), possibly not even the computer itself.

  28. Re:Sounds neat, but parent needs a MOD UP by getuid() · · Score: 5, Informative

    Is there any way to know that measurement has taken place at the other end and your local qubit has collapsed?

    Crash course in quantum mechanics, perhaps this explains it: a binary quantum mechanical system is in a linear superposition of states A and B. That is, it is either 100% A, or 100% B, or anything in between; for example 70% A and 30% B.

    Now if you measure, you would only get "pure" results, i.e. purely A or purely B. If the system was pure (i.e. 100% B) before the measurement, you get what it was. If the system was mixed (say, 70-30), and you had the chance to measure the system more than once, then you get A in 70% of the cases, or B in 30%. For example: make 1000 copies of the system, and measure each of them. Roughly 700 (give/take a few) would be A, roughly 300 would be B.

    The biggest problem is that you don't have 1000 exact copies -- unlike with classical information, basic QM forbids cloning of a system. So you basically have one shot, and if you happen to measure B, you'll never know whether it was because of a 100% pure B state, or simply because you "got lucky".

    I mean, I know the answer is you can't communicate instantly, I'm just figuring out why (mostly to help explain to people with roughly my same layman's understanding of physics why instant communication is impossible).

    While the "quantum information" is being transfered instantaneously, the problem is that the quantum state is not transfered 1:1 onto the target. It is ... "twisted". Imagine that like x*A+y*B (-> teleport ->) y*A+x*B. Now you know that the numbers x and y mean the same in both systems -- you just don't know exactly how they would be twisted after the teleportation. There are 4 possibilities how they can be twisted, and all 4 are equally probable, there's nothing you can do to favor the one over the other.

    However, after the teleportation, the guy at the source can tell how they have been twisted (because the teleportation act itself is a measurement, which's result tells him exactly what happened), but the guy at the target does not.

    So at first, even if the guy at the target knows that the atom has been "teleported", he stil doesn't know which one of the 4 twisted flavors of the original atom he got. If he just takes a "wild guess" and tries to measure, he'll get a statistical result which reveals absolutely no information about the actual coefficients.

    The target-guy needs the source-guy to tell him which of the 4 twists occured, or in short: needs an information transfer in order to be able to "untwist" his atom and have an exact copy.

    Again, the important part is that if the target-guy does not "untwist" his atom, but instead decides to go away and measure it anyway, he'll have an overall chance of 50-50 (regardless of the original x and y) to measure either A or B, so there's no information whatsoever that he could gain, not even from repeating the experiment.

    It's the "twist" that makes the twist with teleportation... :-)

  29. Spooky Action at a Distance by plnix0 · · Score: 1
  30. Just for clarification... by arclyte · · Score: 1

    This experiment is about the teleportation of qubits, not to be confused with the 1982 experiment involving the teleportation of Q*bert, wherein, after falling off the bottom of his pyramidal cubes, the protaganist would teleport back to the top of said pyramid.

  31. Re:Sounds neat, but parent needs a MOD UP by Allicorn · · Score: 1

    Cracking explanation. Cheers!

    --
    OMG!!! Ponies!!!
  32. God's Rootkit by Anonymous Coward · · Score: 0

    With this modern parade of hard-to-grasp physics discoveries, it feels as if we may soon get admin access to the universe. I can't wait, as that means we will soon be able to flood Heaven with spam.

    G0d, Mak3 her sore w ur MonSteR MemBER!!!

  33. My understanding... by MisterMikeyG · · Score: 1

    This type of thing is interesting in the realm of secure communications. Information does and can not travel faster than the speed of light, so don't get hung up on that. What you DO have is a communication medium like, say, fiber optics. By using a quantum medium, the state becomes disrupted upon measuring it. This means that each end can account for the other's measurement and thus be unconditionally certain that no other party has read the transmitted message. This is ideal for operations such as key distribution. I'd note that this process would actually be slightly slower to communicate than fiber optics. You have to send a traditional message over a non quantum wire communicating to the other party when and how to measure the quantum state. It's only application, arguably, is in network security. Quantum COMPUTATION, however, is a different subject. This is not that.

  34. Leapping by Anonymous Coward · · Score: 0

    So this has nothing to do with the Quantum Leap guy?

  35. unmolested??? by freedom_india · · Score: 1

    Holy crap! The feminism thing is a tad too much to digest:

    Scientists have previously teleported unmolested qubits

    Unmolested?? Where they expecting that these female ions would be molested by male ions on their way to their homes???
    Why The Fuck they can't use normal words like "unchanged", "bit copy".
    This feminism thing has gone too far...
    I hope we go back to the pre-WW2 era when women were easier to control and men worked...

    --
    "Doing what i can, with what i have." ~ Burt Gummer
  36. Interstellar communication. by plasmacutter · · Score: 1

    Assuming something like this works at much longer distances, this could be applied to interplanetary and interstellar communication.

    Imagine a martian colony being seamlessly connected to the internet on earth through circuits which utilize this kind of information.

    --
    VLC FOR MAC IS DYING! IF YOU DEVELOP, PLEASE SAVE IT!!
    1. Re:Interstellar communication. by Carbon016 · · Score: 1

      Quantum entanglement cannot be used for classical information.

    2. Re:Interstellar communication. by plasmacutter · · Score: 1

      Quantum entanglement cannot be used for classical information.

      when last I heard of this on a documentary, it had to do with two particles mirroring each other's spin, and when that spin changed, it was mirrored.

      Sounds like binary to me.

      --
      VLC FOR MAC IS DYING! IF YOU DEVELOP, PLEASE SAVE IT!!
    3. Re:Interstellar communication. by Carbon016 · · Score: 1

      No, it cannot be used for classical information due to the basic principles of quantum entanglement. You cannot send information over a channel when you don't know the spin of either entangled particle: this is equivalent to sending random binary data, because while you know the particle the other guy gets is going to be the opposite of yours, you don't know what particle you have.

      Think of it like this: you're a kid, you have a friend, Santa Claus has only two presents: a Game Boy and a rock. Christmas Day, neither of you know what presents you got: if you open your present and it's a Game Boy, you'll know he has a rock, but he can't know that without opening his present too, unless you tell him. Your opening the box has no effect on the outcome, other than you know what the other guy has. In fact, you don't even know what you sent until you observe the particle.

      This has been better explained by others in other comments but it is important to make sure people don't think this is some sort of crazy FTL Star Trek thing.

  37. For communication... by Anonymous Coward · · Score: 0

    Why can't there just be a set time for measuring the ion (or whatever)? For instance, Particle A will be measured by 4:00, so when I measure particle B I will know that A is already measured.

    Now I'm not sure I'm understanding this, but why wouldn't that work?

    1. Re:For communication... by H3g3m0n · · Score: 1

      I was just thinking that, but I don't think you can tell when a particle is measured without measuring it which then collapses the waveform anyway.

      --
      cat /dev/urandom > .sig
    2. Re:For communication... by franl · · Score: 1

      I don't think you can tell when a particle is measured without measuring it which then collapses the waveform anyway.

      Sort of. Neither side can tell when the wavefunction collapses due to the other side performing a measurement. Both sides see completly random (but correlated) results from their measurements. It is that randomness that prevents superluminal signaling.

  38. Here's the whole link by Savantissimo · · Score: 1
    --
    "Is life so dear, or peace so sweet, as to be purchased at the price of chains and slavery?" - Patrick Henry
  39. Don't feel bad by Weaselmancer · · Score: 1

    The mods didn't get the joke, but I did.

    --
    Weaselmancer
    rediculous.
    1. Re:Don't feel bad by InfiniteLoopCounter · · Score: 1

      Are you absolutely certain? I got a different picture and some people might have a different interpretation also.

    2. Re:Don't feel bad by Eudial · · Score: 1

      I prefer a formulation where there is no bras.

      Okay, this one was a bit obscure even for slashdot. It's funny because of Dirac.

      --
      GAAH! MY PRINTER IS ON FIRE!!! PUT IT OUT! PUT IT OUT!
  40. Quantum Entanglement by Thangalin · · Score: 1

    http://www.davidjarvis.ca/dave/entanglement - Introduction to Q.E. without math.

  41. The question by Frozen+Void · · Score: 1

    How much it faster then speed of light?

  42. The Ansible by n3tcat · · Score: 1

    orson scott card's a visionary. See?

  43. Re:Sounds neat, but parent needs a MOD UP by Anonymous Coward · · Score: 0

    I've never read any of the things you wrote anywhere. Until you provide references, I'd take your post with a grain of salt.

  44. Best science PR stunt ever ... by jopet · · Score: 1

    to call quantum entanglement "teleportation".

  45. So they tell us by Anonymous Coward · · Score: 0

    How do we know what they claim is true?

  46. Re:Sounds neat, but parent needs a MOD UP by Anonymous Coward · · Score: 0

    OK that seems to make sense, you can teleport information instantly, but the information is randomized and is unreadable. This would make reading the state of the atom impossible.

    But what I don't understand is why, if you can still transfer that an atom has been teleported... And if there are 4 possible 'twists', then why cant you send between 1 and 4 atoms - the first is the message carrier, no following atom means twist 1, 1 following atom means twist 2, etc.

    Please explain for me, someone! >.

  47. Re:Sounds neat, but parent needs a MOD UP by CookedGryphon · · Score: 1

    Interesting.... Forgive my gross misunderstanding but is it possible to make a pair where they both have a higher chance of being A than B when observed. In an extreme case 90% chance of it being A for both particles, but the other particle still has to be B.

    Thus you could convey the information that the other particle was read at the other end and thus take it in turns to send information, synchronising so you know the other side has already been `written' to. There would only be a 10% chance of misreading.

  48. Think of it like this by Giant+Electronic+Bra · · Score: 1

    2 entangled quantum states are like 2 magic coins. When you flip one coin and it comes up heads, the other coin comes up tails.

    Now, suppose I flip my coin, and your 100 light years away. You don't know if I have flipped my coin or not, nor if it came up heads or tails. You flip yours, it comes up tails, you now know mine must have come up heads. What information has passed between us? ALL we each know is how the other's coin came up. There is no way to use that fact to communicate anything else.

    Now, you CAN use it as say an encryption key, but the encrypted data STILL needs to be transmitted between both parties, and that is subject to relativistic limitations.

    So, in some sense a quantum state is 'teleported' between two entangled systems, but no actual information is exchanged which is of any use to anyone. Where it becomes interesting from a computing perspective is when you teleport superpositions of states, which allows you to store or move qbits around reliably and accurately (because they don't have to actually travel through the intervening distance, where they would most likely be perturbed). You still can't transmit information instantly because there is classical information required (how the other guys 'coin' flipped) required to interpret whatever answer you get.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  49. Good as far as it goes by Giant+Electronic+Bra · · Score: 5, Informative

    Here's an illustration of the non-tranmission of information via entanglement.

    Suppose we have a pair of 'magic coins'. Either coin can be flipped and come up either heads or tails, and the other coin will always come up the opposite.

    Now, suppose 2 people meet in New York and agree that they will meet again in Oslo if Amy's coin comes up heads and Bill's coin comes up tails, or they will meet in Sidney if Bill's coin comes up heads and Amy's coin comes up tails. Then Amy goes to Peking and flips her coin. It comes up heads, so she meets Bill in Oslo.

    The information, which city they will meet in, was AGREED ON BEFORE HAND, it wasn't 'transmitted' by the flip of the coins. The information was in Amy's head when she went to Peking, it traveled by a classical channel governed by relativistic limitations.

    This can be seen explicitly if you assume that Amy and Bill DIDN'T agree on which face of the coins meant Oslo or Sidney. In that case when Bill and Amy flip their coins they DO know that their opposite number's coin came up the other way, but neither of them knows which city to go to! In other words, no information was conveyed between them BY the flip of the coins.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
    1. Re:Good as far as it goes by Anonymous Coward · · Score: 0

      The information, which city they will meet in, was AGREED ON BEFORE HAND, it wasn't 'transmitted' by the flip of the coins. The information was in Amy's head when she went to Peking, it traveled by a classical channel governed by relativistic limitations.

      Or you can say instead that the information was encoded before transmission. If you don't know the code, you won't get the message.

    2. Re:Good as far as it goes by eclectro · · Score: 1

      From your post, we can determine in a non-relativistic manner that Bill is actually cheating on Alice.

      --
      Take the cheese to sickbay, the doctor should see it as soon as possible - B'Elanna Torres, "Learning Curve"
    3. Re:Good as far as it goes by wamatt · · Score: 1

      Something bugs me still.

      If Bill or Amy flip a coin, then instantly the other one KNOWS the other person flipped a coin at that point in time.

      How is that not information teleporting? Bill knows for sure the exact time Amy is sitting next to her coin flipping it. (as opposed to out partying etc).

    4. Re:Good as far as it goes by franl · · Score: 2, Informative

      If Bill or Amy flip a coin, then instantly the other one KNOWS the other person flipped a coin at that point in time.

      Nobody has said that. How can Bill's measurement force Amy to make her measurement at the same time? That's not possible. Especially since "at the same time" has no meaning for spacelike-separated events (cf. the Relativity of Simultaneity).

      This is what happens: Bill measures a random value. Amy measures a random value. The two values are both random, but 100% correlated with each other. Bill knows what value Amy measures and vice versa, but no information has been transmitted, because the values are random.

    5. Re:Good as far as it goes by ivan256 · · Score: 1

      The "ball in a box" analogy from the parent post is much better. It doesn't require a "magic" coin.

  50. Better get some content filters mandates... by sega01 · · Score: 1

    Or else they could be stealing our precious music industry's songs at the speed of light!

  51. No, it wouldn't by Giant+Electronic+Bra · · Score: 1

    Because you would have to AGREE BEFOREHAND on what each collapse MEANT. Each series of measurements on each end is RANDOM. Thus all each end of the channel knows is a random number. They each know the SAME random number (or its inverse which is the same thing). It is just a random number, it contains no information.

    In order for information to be passed, the two sides would have to agree (by communicating using a classical channel) as to what they would interpret their random numbers to mean. The information thus ALREADY EXISTS at each end of the quantum channel and no new information is passed beyond that by the quantum channel.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  52. It's a start! by blackjackshellac · · Score: 1

    I think now would be a good time to do a field test on Bush/Cheney.

    --
    Salut,

    Jacques

  53. Implications for quantum encryption... by argent · · Score: 1

    The researchers then measured the first atom, thus destroying the delicate quantum information it contained, and also destroying the entanglement. That left the original qubit intact in only the second, recipient atom, completing the teleportation.

    If this works, then theoretically couldn't an attacker entangle a third qubit with the original two, measure that (and destroy the entanglement), and leave the two originals unchanged?

    (yes I know there's a prodigious amount of handwaving here, but it's *entangled* handwaving)

  54. Basically by Giant+Electronic+Bra · · Score: 1

    Suppose Bob and Amy entangle 2 coins so if one comes up heads, the other comes up tails. Now they go away from each other and each flip their coin. All they know is that the other's coin came up opposite to that, and which way the two together came up is random. If they want the way the two came up to 'mean' something, they have to agree on that meaning BEFORE they go apart (or by radio etc). THAT is the information, and it wasn't transmitted 'faster than light', it was carried in their heads or it was carried by radio etc.

    The actual situation is a bit more complex than that, but from an information perspective this the right way to think about it.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  55. Because the measurements you each make at each end are RANDOM. You each know that the measurements made by the other end are the same as yours, but that doesn't amount to 'information'. You would have to agree beforehand what EVERY possible sequence of random values would be when it was actually measured, which means all the information you could possibly transmit would have to be carried with each party (subject to classical relativistic mechanics).

    Thus you each DO 'know' something when you do your measurements, but that knowing in and of itself is uninformative, and neither party has any control over WHAT is transmitted.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  56. Nonsense by Giant+Electronic+Bra · · Score: 1

    The flaw in your reasoning is you cannot TELL by looking at your qubit whether or not the other qubit has been measured yet or not. Thus the scheme you propose is simply impossible.

    All the two sides can determine is that they each end up with the same measurements whenever they DO measure their entangled states. Unless they agree beforehand on what that information means it is just a random number which they both share.

    No information has passed from one end of the channel to the other.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  57. No, he just doesn't understand by Giant+Electronic+Bra · · Score: 1

    quantum mechanics, lol.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
  58. Re:Sounds neat, but parent needs a MOD UP by getuid() · · Score: 1

    But what I don't understand is why, if you can still transfer that an atom has been teleported... And if there are 4 possible 'twists', then why cant you send between 1 and 4 atoms - the first is the message carrier, no following atom means twist 1, 1 following atom means twist 2, etc.

    Please explain for me, someone! >.

    That's a common misconception about teleportation: You don't *actually* transfer atoms. You transfer only quantum-mechanical properties.

    The target matter has to already exist at the other end. What you do is transfer the quantum-mechanical properties of one atom at site #1 onto an atom at site #2, without actually *knowing* (or having to know :-) what the atom at site #1 looked like in the first place. All you know at the end of the day is that, if you done it right, atom at #2 looks exaclty like the one at #1 used to look like.

  59. Re:Sounds neat, but parent needs a MOD UP by getuid() · · Score: 1

    Interesting.... Forgive my gross misunderstanding but is it possible to make a pair where they both have a higher chance of being A than B when observed.

    At the sending end, yes. At the receiving end, not. That's the key problem: the receiving end is in one of the four states of maximum uncertainty, called the "Bell states". Each of the state is equally probable, and until you know *exactly* which one of the four it is, you cannot extract any useful information other than pure randomness out of the process -- *regardless* of how the source was prepared (i.e. even if the source was prepared to be purely A, you'd still get a 50-50 chance of measuring either A or B after teleportation, if you don't have any knowledge about which Bell state your target system is immediately after teleportation).

  60. Re:Sounds neat, but parent needs a MOD UP by getuid() · · Score: 1

    Look up for "EPR Paradoxon" and "Bell states" in the usual physical journals. Start with Einstein et al., Phys. Rev. 47 / 777 (1935) -- that was the first time it was theoretically described -- and work all your way up until Bennet et al. Phys. Ref. Lett. 70 / 1895 (1993), when it was experimentally proven for the first time. Be sure to have a copy of J.S. Bell's "Physics 1" from 1964 lying around.

    Second thought: you might want to read tbe Bennet paper first and work click way through the references downwards until you read the Eintein/Podolsky/Rosen one. Then read your way up again through the trail of clicks you left behind.

    Oh, and get a decent book on quantum mechanics. Althoug a little non-standard, it's actually undergrad stuff, if you bother to read the papers I told you...

  61. links to the paper by Anonymous Coward · · Score: 0

    PNGs made from the PDF:
    Page 1
    Page 2

  62. Yeah, Bells's theorem... by gr8_phk · · Score: 3, Interesting

    Bell's theorem (which is a logical argument) and common sense (which we base logical arguments upon) are at odds. So the physicists side with "spooky action at a distance" because it's more phun. They've been taking the "magic" path ever since Einstein and relativity came along and said reality is unintuitive (which it is, but it follows from his assumptions which were based on observation). Witness "dark matter" and "dark energy" and "string theory".

    Back to the topic at hand, no one can explain what is different about a particle whose wave function has "collapsed" and one that hasn't. If you can tell the difference, then you can use entangled pairs to communicate instantly at a distance. One person makes a measurement or not, and the other guy checks for the collapsed-ness of his particle - instant transmission. But since no one knows what the collapse means we just chalk it all up as magic - or unknowable, or parallel universes, etc... By the way, the collapsedness of the particles wave function is therefore a hidden variable that we don't have access to. This proves the existence of hidden variables in contradiction to Bell's theorem, and offers the distinct possibility that the spin is also there all along as a "hidden variable".

    I thus predict that an overturn of at least one assumption in Bell's theorem will be one of the biggest headlines in physics some time this century.

    1. Re:Yeah, Bells's theorem... by grumbel · · Score: 1

      They've been taking the "magic" path ever since Einstein and relativity came along and said reality is unintuitive

      The fun part with relativity is that its not half as magical as it looks on the first view, it follows naturally when you accept that the speed of light is constant. Similarly a lot of quantum mechanics follows naturally when you accept that energy is quantized, which isn't all that far fetched to begin with, since matter is too. The annoying problem with quantum mechanics is that its pretty hard for a lay person to find any information on it that stays to the experimental facts instead of drifting away into magical interpretations.

      Little video I ran across while googling for Beel's Theorem. Can't say I understand much of it, but at the end it started talking about boxes and balls as well...

    2. Re:Yeah, Bells's theorem... by sfazzio · · Score: 2, Interesting

      What's with all of the physics time-travelers from the 1960s? Bell's theorem has repeatedly passed experimental muster, and has become a cornerstone of quantum information theory-- a field which has lead to any number of testable (and subsequently tested) predictions.

  63. Ball metaphore by DrYak · · Score: 1

    In an over simplified way :

    * you move them apart

    If the balls where quantic, both box would weight exactly half a ball until opened.
    The boxes contain both state at the same time : ball and no ball.
    Only when opened the boxes will make up their mind and choose which state their are in.

    * no magic necessary, no teleportation happens, since the state of both boxes is fixed from the start

    That's where the difference between quantum mechanics and normal everyday macroscopic physics kicks in : with quantum physics the state of the boxes is NOT fixed from the start.
    If you could roll back time and restart the experiment, the ball could very well end up in the other box, with a 50% probability.

    Of course, you can't roll-back time. So scientist resort to more complicated experiments to prove that. See the references that the other /.ers gave you.

    --
    "Sufficiently advanced satire is indistinguishable from reality." - [Tips: 1DrYakQDKCQ6y52z6QbnkxHXAocMZJE61o ]
  64. RFI: What does MPF mean? by Anonymous Coward · · Score: 0

    n/t

  65. Re:Sounds neat..but FTL is real by Anonymous Coward · · Score: 0

    Quantum information transport at instantaneous speeds is a reality. Scientists in labs all over the world basically know this but do not report it in order to protect careers, grants, governmental official secrets acts, preserve intents to develop new technologies of 'possible military significance, etc. Quantum action at a distance probably tunnel out of 'visible space time' and into higher dimensional space. Arthur Eddington in the 1920's stated that one result of GR would be if taken literally would be that planets could not have stable orbits because the physics would not work. Statements to this effect do exist on the internet; do not just take this writer's word for it. Occasionally word leaks out that FTL and associated Cerenkov radiation has been detected. And other word sometimes leaks out that quantum transport has been found to be instantaneous, followed shortly afterward by 'official denials, retractions, damage control, and copious lying. Of course none dare to call 'it' lying. Rest assured the climate of fear and cynicism surrounding these issues serve purposes of other nations not nearly as fearful of harming entrenched energy and communications interests, like Russia and China. Maybe some of this patho-skepticism is really at the hands of agents of these nations who are in positions of subversion and espionage and propaganda and treason on our society. Some of these agents would even stoop to post idiotic messages on bulletin boards to distract and trivialize the benefits of products based on this new physics. Instantaneous transport through higher dimensional or eleven dimensional space is new physics, a superset of what we think we know, and IS being checked by agencies all over the world no matter what is said publicly. Calls to mind the developement of the American SST. Demonstrators, quislings, other traitors and fellow travelers guaranteed by their orchestrated opposition to this only meant that the SST's that DID get developed were anybody but American: the European Anglo-French SST and the Russian Tu-144. The same could be our fate again, only the consequences of the agents of our willful failure will be far reaching and permanent.

  66. Mod Parent Funny by Anonymous Coward · · Score: 1, Informative

    n/t

  67. Re:Sounds neat, but parent needs a MOD UP by franl · · Score: 1

    The states aren't genuinely undetermined, it's jus that we don't know what it is. However, it's also the wrong explanation - because of http://en.wikipedia.org/wiki/Bell's_theorem. A brilliant bit of work that showed you could in fact test and measure whether there were such local hidden variables. There aren't. Quantum weirdness won the battle.

    This is true, but to be clear, Bell's Theorem shows that the correlation between spatially-separated measurements predicted by local-hidden-variables theories is less than the correlation predicted by QM (i.e., QM predicts the measurements are _more_ correlated than local hidden variables can make them). Now that the experiments have been performed, QM is generally considered the winner.

  68. But they DON'T know by Giant+Electronic+Bra · · Score: 2, Informative

    At no point can either Amy or Bill determine whether or not the other coin has been flipped. All they can say for sure is that WHEN IT IS, it will come up a certain way. Maybe it already has been flipped, maybe it hasn't. The only way to find out would be using a classical communications channel.

    There is a CORRELATION between the two 'coins' with entanglement, but there is NO causality. Flipping one coin does NOT cause the other one to flip, this has actually been verified by various iterations of experiments testing Bell's hypothesis. The logic is a bit trickier and my simple analogy isn't good enough to explain it, but in actual quantum mechanics if one flip caused the other, then certain experiments could be devised which would have different results than if the two flips are merely 'coincidence'.

    This is one of the amazing things about QM. There is actually NO causality anywhere in QM, only a distribution of the probabilities in a particular special type of function space. Causality is an emergent phenomenon which only exists at the 'macroscopic' level. Even then it isn't absolute. I believe it was Stephen Hawking who once quipped that Cthulhu could materialize in the middle of the Pacific Ocean at any moment and no law of physics would be broken.

    There are a LOT of other interesting ideas which come out of this, like questions about the meaning of entropy, which leads into questions like the Anthropic Principle.

    --
    "Malo periculosam, libertatem quam quietam servitutem." -- Jefferson
    1. Re:But they DON'T know by wamatt · · Score: 1

      THanks that helps. So does the following reasoning make sense...

      I assumed that multiple measurements were possible. This is wrong?

      A coin if you looking at it is a macro object, but essentially you are taking hundreds of measurements per second by staring at it, waiting for it to change.

      In the quantum world you only get once chance at measuring it, (because doing so destroys it state), hence temporal information WON'T be transferred, since you won't know when to measure?

  69. I molest qubits for a living! by Master+of+Transhuman · · Score: 1

    BWAHAHAHAHAHAHAHAHAHAH!!!!

    Qubit molester!

    BWHAHAHAHAHAHAHAHAH!!!

    --
    Richard Steven Hack - This sig is TOO GODDAMN SHORT TO DO ANYTHING USEFUL WITH! MORONS!
  70. Re:Sounds neat, but parent needs a MOD UP by Anonymous Coward · · Score: 0

    Nice explanation. Care to apply that to quantum cryptography? I thought that quantum cryptography enabled its users to know when someone intercepted the message. For example, if Amy sends a message to Bob, and Charlie intercepts it, Charlie's action would collapse the waveforms, which would indicate his presence to Amy and/or Bob.

    But if Amy and Bob always see a collapsed waveform when they observe their message (which makes perfect sense to me), how can they tell if Charlie was involved?

  71. Encore! by Hordeking · · Score: 1

    And for their next feat, they will teleport a cat!

    --
    Disclaimer: The opinions and actions of the US Gov't are in no way representative of those held by this author or its ci
  72. Entanglement = holographic phase coherence? by Anonymous Coward · · Score: 0

    If the universe is 2D, and what we observe is actually a hologram, then:

    If two particles are entangled it might be the equivalent of their waves being coherent, or somesuch.

    The act of "disturbing" this through a measurement actually means that a different wavefront interacts with the one representing one of the electrons. This causes it to go out of phase, and take on nature X. Going out of phase however interacts with the phase of the electron it is entangled with, causing that to take on nature Y.

    This would explain:

    - Why entangling stuff is tricky and random, and not fully understood
    - Why measuring one electron causes the other to change behaviour
    - Perhaps why speed and location is impossible to know at the same time? Because measuring one characteristic would disturb the wave enough to change the other characteristic

    If true, it should mean in theory it could be possible to determine a way to interact with an electron in such a way that you can know exactly which "molestation" you are inflicting on it - thereby violating causality and transmitting information. I've never understood exactly why that couldn't be done anyway.

    Holographic universe could even explain antimatter - if electrons are represented by certain waves, then positrons might be the same waves in the inverse phase, essentially a perfect intereference pattern. If they collide, they cancel each other out.

    If this leads to a nobel prize for someone, I'd love a share.
    - MA, Southampton