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Quantum Entanglement of Macroscopic Diamonds

New submitter ananyo writes "A pair of diamond crystals has been linked by quantum entanglement — one of the first times that objects visible to the naked eye have been placed in a connected quantum state. 'This means that a vibration in the crystals could not be meaningfully assigned to one or other of them: both crystals were simultaneously vibrating and not vibrating (abstract). Quantum entanglement — interdependence of quantum states between particles not in physical contact — has been well established between quantum particles such as atoms at ultra-cold temperatures. But like most quantum effects, it doesn't tend to survive either at room temperature or in objects large enough to see with the naked eye.'"

160 comments

  1. weird. by notgm · · Score: 5, Funny

    this both gives me the chills, and doesn't.

    1. Re:weird. by Anonymous Coward · · Score: 0

      It simultaneously gives both you and I the chills -- the chills cannot be meaningfully assigned to either you or me.

    2. Re:weird. by thomst · · Score: 1

      this both gives me the chills, and doesn't.

      Well, then, put on a sweater ...

      ... and don't.

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    3. Re:weird. by Dishevel · · Score: 1

      I have those chills and not chills at the same time as you.

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    4. Re:weird. by mcneely.mike · · Score: 1

      It simultaneously gives both you and I the chills... and it simultaneously doesn't! FTFY.

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    5. Re:weird. by Anonymous Coward · · Score: 0

      It's probably quantum bird flu; it's probably kill you and not kill you.

    6. Re:weird. by Anonymous Coward · · Score: 0

      or not

    7. Re:weird. by Darinbob · · Score: 1

      A great disturbance in the force, like a billion voices crying and not crying out.

    8. Re:weird. by axlr8or · · Score: 1

      Well in observance to the original OP, to observe most quantum entanglement effects its on a microscopic scale and extremely cold so..... You both have to be in the same cold room to observe the single event. I deduce you probably have those chills and not chills at the same time for a reason.

    9. Re:weird. by Anonymous Coward · · Score: 0

      Knew a friend who had an apartment that had that effect. Whatever side you faced the heater felt warm, but the cold draughts made every other side feel chilly.

  2. www.quantum-vibrator.xxx by Slugster · · Score: 5, Funny

    great..... we dump all this money in some eggheads' laps, and all they can think of is to make fancy adult toys

    1. Re:www.quantum-vibrator.xxx by Anonymous Coward · · Score: 0

      Trolling or not, this comment needs more....

      Quantum entanglement on a macroscopic scale like this can some day be used to transfer energy wirelessly and without loss of effect. Using a present-day example, we could attach a transceiver to a power plant in Norway, then ship another to say Indonesia and POOF! instant restoration of power even if EVERY power plant in Indonesia is destroyed.

      Another example would be in the future. We have finally managed to colonize Mars (nice dream anyway), and when we went there, we brought a QE-transceiver with us. This made it possible to immediately start building after landing, and when the colonists felt homesick they didn't have to schedule a radiocall or prepare a manuscript from which to read and wait for a reply that would take at least 30* minutes to arrive.

      Another present-day example would be to have QE-transceivers aboard planes, trains, trucks, cars and boats, getting rid of the release of pollutants to the atmosphere.

      High-voltage powerlines for transfer of energy from one part of the world to the other could be torn down and never again desecrate and endanger the nature.

      *Based on nothing scientific and I know it. Would be glad to hear how long it really takes for a radio signal to reach Mars.

    2. Re:www.quantum-vibrator.xxx by Anonymous Coward · · Score: 0

      Nope.

    3. Re:www.quantum-vibrator.xxx by holmstar · · Score: 1

      I don't think you understand what entanglement means.

    4. Re:www.quantum-vibrator.xxx by wdef · · Score: 1

      Bell's theorem (ie entanglement) cannot be used for communication that violates the limiting velocity of the speed of light. But a workaround would be nice :=).

    5. Re:www.quantum-vibrator.xxx by Galactic+Dominator · · Score: 1
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  3. Quantum First Post! by Dutchmaan · · Score: 4, Funny

    This is a first post, and yet it isn't!

    1. Re:Quantum First Post! by Tyrannosaur · · Score: 1

      until we observe it, and cause your beloved post's wavefunction to collapse, and alas, you fail again.

    2. Re:Quantum First Post! by Anonymous Coward · · Score: 0

      No fair! Your pointing out his failure affected the outcome.

    3. Re:Quantum First Post! by cusco · · Score: 2

      While it simultaneously effected the outcome.

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  4. vibrating and not vibrating? by sl4shd0rk · · Score: 1

    so..... the two crystals each have atomic particles sharing the same nucleus or something?

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    1. Re:vibrating and not vibrating? by DogDude · · Score: 2

      No, that's quantum physics. Seemingly unrelated particles can influence each other. It's been widely known and accepted as fact since Einstein's era. It's just unusual to see it happen with such particles.

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    2. Re:vibrating and not vibrating? by Yetihehe · · Score: 1

      No, they can't really influence each others. If one of the entangled particles is under ANY influence, you have decoherence and they are not entangled anymore.

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  5. There is only "Here", There is only "Now" by Jeremiah+Cornelius · · Score: 1

    Both are the same thing, which is infinite.

    Time and space are illusions*. Try to prove them and you will only produce paradoxes.

    * lunch time, doubly so.

    --
    "Flyin' in just a sweet place,
    Never been known to fail..."
    1. Re:There is only "Here", There is only "Now" by sehlat · · Score: 2

      There is only Xul.

    2. Re:There is only "Here", There is only "Now" by Jeremiah+Cornelius · · Score: 1

      Call it what you like. I was using "Brahma" and "Reality". :-)

      --
      "Flyin' in just a sweet place,
      Never been known to fail..."
    3. Re:There is only "Here", There is only "Now" by wdef · · Score: 1

      That sounds all very nice but it also sounds like metaphysics. But do you want to unpack that for those of us who have some education in theoretical physics? I thought not.

    4. Re:There is only "Here", There is only "Now" by Thing+1 · · Score: 1

      "My girlfriend sleeps above the covers -- three feet above the covers!"

      --
      I feel fantastic, and I'm still alive.
    5. Re:There is only "Here", There is only "Now" by Thing+1 · · Score: 1

      All this time, and I just now realized that the line is also an ambiguous number-of-limbs joke, as well...

      --
      I feel fantastic, and I'm still alive.
    6. Re:There is only "Here", There is only "Now" by PJ6 · · Score: 1

      Both are the same thing, which is infinite.

      Time and space are illusions*. Try to prove them and you will only produce paradoxes.

      * lunch time, doubly so.

      If time didn't exist, everything would happen at once.

      Also, all observable dimensions (including timelike ones) are finite by definition.

    7. Re:There is only "Here", There is only "Now" by Jeremiah+Cornelius · · Score: 1

      Everything happens at once, all the time, forever.

      --
      "Flyin' in just a sweet place,
      Never been known to fail..."
  6. next step in this study by niw3 · · Score: 4, Funny

    should be an experiment with a cat & some poison

    1. Re:next step in this study by bhagwad · · Score: 1

      In this case, a woman can have an orgasm and not have it at the same time...since her state is intimately linked to the vibration of the device :D

    2. Re:next step in this study by mcneely.mike · · Score: 1

      Stick a cat in a microwave oven and turn it on. Then turn your back to it. Is the cat simultaneously both alive and dead?
      Well, maybe once the meowing stops....
      rimshot
      Wow... tough audience....

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  7. 0.05 mm by .25 mm by Anonymous Coward · · Score: 4, Informative

    They say that each phonon involves the coherent vibration of about 1016 atoms, corresponding to a region of the crystal about 0.05 millimetres wide and 0.25 millimetres long â" large enough to see with the naked eye.

    0.05 mm is roughly 1/4 the width of a human hair. Of course, I still can't see it, because it's just a patch of vibrations on a much larger diamond.

    1. Re:0.05 mm by .25 mm by Loveless62 · · Score: 1

      The article also implies that the entanglement only lasts a few picoseconds. I'm not sure I would consider that visible by the naked eye (I realize that the summary only suggests that the objects involved are visible to the naked eyes, not the effect itself). I guess it's a start, though.

    2. Re:0.05 mm by .25 mm by CSMoran · · Score: 1

      1016 atoms, corresponding to a region of the crystal about 0.05 millimetres wide and 0.25 millimetres long

      Dawg, you got your lengthscales all messed up, man.

      --
      Every end has half a stick.
    3. Re:0.05 mm by .25 mm by holmstar · · Score: 1

      Well, of course you can't observe the effect directly with your eyes. The light bouncing off of the diamond would break the entanglement.

  8. Harmony at last.. by RenHoek · · Score: 4, Funny

    Neat... Now I can get a pair of diamond vibrators and please both my wife and mistress at the same time!

    1. Re:Harmony at last.. by roc97007 · · Score: 3, Funny

      Or not, at the same time.

      --
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    2. Re:Harmony at last.. by Baloroth · · Score: 5, Informative

      Actually, no, because they are quantum entangled only one of them can vibrate at a time. So you can still only please one at at a time, you just don't know which one it will be until they tell you.

      --
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    3. Re:Harmony at last.. by blueg3 · · Score: 1

      I was actually going to mention this, and was pleasantly surprised to discover someone else pointing out what the common superposed state of entangled objects is.

    4. Re:Harmony at last.. by Bucky24 · · Score: 1

      So (jokes aside) does that mean that if you vibrate one the other is forced to stop vibrating? (I don't understand quantum physics very well)

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    5. Re:Harmony at last.. by Baloroth · · Score: 4, Informative

      No. The experiment took one photon, and sent it along two possible paths without recording which path it took, which causes a vibration in one (and only one) diamond. Since the path of the photon was random, and not recorded, you cannot say which diamond is vibrating. The way the researchers put it (better than the summary IMO) is "Neither the statement 'this diamond is vibrating' nor 'this diamond is not vibrating' is true.” You cannot selectively vibrate one. In fact knowing which one vibrates destroys the entanglement. It does, however, tell you the state of the other diamond (the opposite) without observing it directly, which creates a few paradoxes and is the source of the whole 'spooky action thing.'

      Don't feel to bad if you don't understand it, even quantum physicists don't understand quantum physics very well. The mechanics behind what is really happening in entanglement is still unknown, there is only guesswork as to how it might happen.

      --
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    6. Re:Harmony at last.. by tom17 · · Score: 2

      A great explanation, which made sense. But now I just have more questions. Like, "I will put a ball in one of these boxes, but I will not tell you which one I put it in. Now from your perspective, Neither the statement 'this box has the ball in it' nor 'this box does not have the ball in it' is true. You have no way of selecting which box I put the ball in." How is this any different?

      What I am saying is, I don't see how there is any 'entanglement' there. It's just either in one diamond or the other. It's only our perception that doesn't know which one it is in.

      I'd really love to get my head around this one day lol.

    7. Re:Harmony at last.. by bhagwad · · Score: 1

      Just to clarify - not being able to measure it doesn't mean there's an "underlying reality" which we haven't been able to observe. It's not that one of them really is vibrating and we just don't know which. They're both entagled meaning both of them are vibrating and not vibrating...or not.

    8. Re:Harmony at last.. by Baloroth · · Score: 2

      Well, as others point out I oversimplified things a bit. Quantum physics states that, in a sense, both and neither are vibrating so long as they are entangled, and only one actually vibrates once observed. However I believe that many view that as merely a mathematical system for approximating what is really going on (don't take my word for this, as I am by no means sure about this point), but that goes well past my knowledge. In your example, there is an objective reality about which box the ball is in. It may or may not (and experiments indicate not) be true that there is an objective reality about which diamond is vibrating prior to the observation.

      --
      "None can love freedom heartily, but good men; the rest love not freedom, but license." --John Milton
    9. Re:Harmony at last.. by Anonymous Coward · · Score: 0

      There isn't entanglement in that situation, because the choice wasn't random in the quantum sense. It's not that we don't know which one is vibrating, it's that when the path the photon takes is literally not chosen when it makes the split. Half of the photon's probability density wave goes one way, half goes the other. Both diamonds are half-vibrating and half-not. The reason it's not just our perspective is that both paths are actually, physically linked. I'm not sure what the diamond vibrations could affect, but if you look at the standard double-slit experiment you can see how the split paths of a single photon can still interfere with eachother before the state is measured.

      If your ball/box system were truly engangled, you would be able to - say - put both boxes on two sides of a scale, and they would balance out, even though one should be empty and the other should contain a ball. When you opened the one box to see if it contained the ball or not, then both boxes would suddenly and randomly take on their "correct" weight. (Except not really, because weight isn't a quantum state, but it's better than a car analogy.)

    10. Re:Harmony at last.. by Normal+Dan · · Score: 1

      I had your problem for the longest of times too. No one seemed bothered that this given explanation was no different than a classical example. And it seems most people don't ever think about it to the level that you have. (So congratulations I guess).

      I think what you want to look at is Bell's Theorem. http://en.wikipedia.org/wiki/Bell's_theorem

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    11. Re:Harmony at last.. by doug141 · · Score: 1

      I'd really love to get my head around this one day lol.

      then you should read http://www4.ncsu.edu/unity/lockers/users/f/felder/public/kenny/papers/bell.html

    12. Re:Harmony at last.. by jpapon · · Score: 1

      What I really don't get is why observation would destroy the entanglement. That just doesn't seem possible. They either are entangled, or they aren't. Mere observation by a third unrelated party shouldn't matter. Someone needs to just kill that goddamn cat.

      --
      -- Let us endeavor so to live that when we pass even the undertaker shall be sorry. -- M. Twain
    13. Re:Harmony at last.. by Anonymous Coward · · Score: 2, Insightful

      Well, as others point out I oversimplified things a bit. Quantum physics states that, in a sense, both and neither are vibrating so long as they are entangled, and only one actually vibrates once observed. However I believe that many view that as merely a mathematical system for approximating what is really going on (don't take my word for this, as I am by no means sure about this point), but that goes well past my knowledge. In your example, there is an objective reality about which box the ball is in. It may or may not (and experiments indicate not) be true that there is an objective reality about which diamond is vibrating prior to the observation.

      But how can you prove that both diamonds were in a simultaneous state until observed? It seems just as likely that the photon went one way or the other and your just now finding out which way it went when you observed it.

      Just like the two boxes, one has a ball and one doesn't. Just cause you don't know which one has the ball, doesn't mean it simultaneously exists and doesn't exist.

    14. Re:Harmony at last.. by holmstar · · Score: 2

      Observation requires interaction with the entangled object. Interacting with it causes the wave function to collapse and the object "chooses" a definite state. There is no way to passively observe the entangled object.

    15. Re:Harmony at last.. by holmstar · · Score: 2

      That's called a hidden variable theory, and experiments have been done that show that hidden variable theories are incorrect.

    16. Re:Harmony at last.. by johanwanderer · · Score: 1

      A great explanation, which made sense. But now I just have more questions. Like, "I will put a ball in one of these boxes, but I will not tell you which one I put it in. Now from your perspective, Neither the statement 'this box has the ball in it' nor 'this box does not have the ball in it' is true. You have no way of selecting which box I put the ball in." How is this any different?

      What I am saying is, I don't see how there is any 'entanglement' there. It's just either in one diamond or the other. It's only our perception that doesn't know which one it is in.

      I'd really love to get my head around this one day lol.

      Actually, it works exactly as the entangled diamonds in this case. I don't know which box the ball is in, so you can bring one box to Mars, keeping one here on earth. Upon opening the box here (measure) and finds that it is empty, I can instantly conclude that the box on Mars has the ball.

      All this assumes that the boxes remain "entangled". If someone changes the content of the travelling box en route to Mars, then all bets are off.

    17. Re:Harmony at last.. by sonamchauhan · · Score: 1

      OK, _what's_ called a hidden state variable theory? Please? :)

    18. Re:Harmony at last.. by OneAhead · · Score: 1

      Following good /. tradition, I'm being too lazy to actually read the paper (though I read the news release on the Nature website) and am just expecting someone else to explain it for me. I do accept that the photons at the 2 sides of the beam splitter are entangled - this is expected behavior for photons and has been amply demonstrated. My question is: does this necessarily imply that the phonons in the diamonds are entangled? What if the interaction with the diamond "qualifies" as a measurement? You'd still get a Stokes photon because a photon has interacted with a diamond at some point, and when "reading out" the phonons, you'd still discover that exactly one of the diamonds will have vibrational energy and the other one not, but they've never been entangled...

      I'm sure the authors have somehow excluded this possibility, but it is a bit sloppy that the news release doesn't mention how, because that would be the actual tour de force that would make the paper worthy of Nature.

    19. Re:Harmony at last.. by tom17 · · Score: 1

      So it is all about perception then and not in reality. In my example, the perception is that it's entangled until observed, but in *reality* the ball is already in one of the boxes.

      From what I read elsewhere in this thread, this is not how it actually works. In reality, something is in fact in both states and it is only the measurement that makes it settle into one state or the other. This just doesn't make sense so I would like to know why they are so sure about this :)

    20. Re:Harmony at last.. by tom17 · · Score: 1

      Yeah. and in layman terms please :)

    21. Re:Harmony at last.. by Anonymous Coward · · Score: 0

      I don't really understand why entanglement is referred to as 'spooky action'.

      As I understand it, quantum physics (as an area of study and theory) began when it was noticed that when excited, chemicals gave off light in very precise bands as opposed to a rainbow. Physicists had expected a rainbow. The lack of "smudging" between bands lead to the theory that the electrons could only exist at discrete distances from the nucleus (I think they refer to these as shells).

      My point is: it appears basic to quantum physics that electrons exist here and there but nowhere in between. Hence, they "hop" from shell to shell without actually traversing the distance in between.

      I see this as suggesting that the electrons don't "see" the distance between the shells as existing.

      In the case of quantum entanglement, two particles are entangled and once the state of one is determined, the entanglement ensures that the second state is also known. The problem I've heard is that physicists can't determine how the information from the first particle was imparted to the second so that it could then take its defined state. Some physicists have theorized that "messenger particles" are generally responsible for delivering this type of information but in the case of the entangled particles, this would take time as they are separated by distance and, in any event, no such messengers have been observed.

      Here's the problem I have with this: If an electron can "hop" from shell to shell without traversing the distance in between, why couldn't messenger particles do the same between entangled particles? If an electron can "hop" some small distance, why should it matter if the distance separating these two particles is "substantial".

      This has bugged me for a while, so I'd really appreciate any thoughts you might have on the subject.

      Cheers,
      Bruce.

    22. Re:Harmony at last.. by jpapon · · Score: 1

      Yes the wave-particle duality is still an amazing thing to me, especially when applied to all matter rather than just high frequency EM radiation.

      --
      -- Let us endeavor so to live that when we pass even the undertaker shall be sorry. -- M. Twain
    23. Re:Harmony at last.. by wdef · · Score: 2

      Don't feel to bad if you don't understand it, even quantum physicists don't understand quantum physics very well.

      Richard Feynman once said of quantum theory: "Don't ask how it can be like that. Nobody knows how it can be like that!"

      The mechanics behind what is really happening in entanglement is still unknown, there is only guesswork as to how it might happen.

      Not quite true at least for the other end of the process, the so-called collapse of the wave function, when one makes a measurement and entangled states decohere. As I've posted once before a while ago, what is going on there was worked out in detail by a gifted yet relatively unknown (outside of theoretical physics circles) Australian mathematical physicist, HS Green http://en.wikipedia.org/wiki/Herbert_S._Green perhaps best known for his ground breaking work in fluids and as a protege of Max Born, who described Bert Green, in a letter to Einstein, as "brilliant". This side of his work has not got the recognition it deserves. Green proved that the collapse of the wave function to the single measured state that we perceive has nothing to do with mystical mumbo jumbo and can be entirely accounted for by the mathematics of the interaction between the set of possible states and the environment. Or something like that. Unfortunately the silly wikipedia article does not reference that work, I'll have to find it again and put it there.

    24. Re:Harmony at last.. by NeutronCowboy · · Score: 1

      Hidden varriable theory is the idea that your model is incomplete - that there is some effect that is hidden to you that controls where the photon went,and which atom is actually vibrating. Those theories have been proven incorrect. See also http://en.wikipedia.org/wiki/Hidden_variable_theory

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    25. Re:Harmony at last.. by NeutronCowboy · · Score: 1

      There's lots of math behind the certainty, and a few experiments that confirm the math. :) And as someone else said - no one understands QM.

      --
      Those who can, do. Those who can't, sue.
    26. Re:Harmony at last.. by narcc · · Score: 1

      But now I just have more questions. Like, "I will put a ball in one of these boxes, but I will not tell you which one I put it in. Now from your perspective, Neither the statement 'this box has the ball in it' nor 'this box does not have the ball in it' is true. You have no way of selecting which box I put the ball in." How is this any different?

      It is very very different. In this case the "ball" is actually in both "boxes" at once. Upon observing one of the "boxes", the ball is in one or the other, but not before. (Reality has a lot to do with knowledge and knowability [what can, in principle, be known] -- in your case, the location of the ball is both known and knowable.)

      Freaky, isn't it? Relativity is just as wacky and unintuitive, but we managed to get used to that quickly enough.

    27. Re:Harmony at last.. by DrFalkyn · · Score: 1

      A great explanation, which made sense. But now I just have more questions. Like, "I will put a ball in one of these boxes, but I will not tell you which one I put it in. Now from your perspective, Neither the statement 'this box has the ball in it' nor 'this box does not have the ball in it' is true. You have no way of selecting which box I put the ball in." How is this any different?

      What I am saying is, I don't see how there is any 'entanglement' there. It's just either in one diamond or the other. It's only our perception that doesn't know which one it is in.

      Understanding wave-particle duality and the nature of light is critical to understanding modern physics. The easiest way I know of explaining this is through double-slit experiment.

      With the double-slit experiment, you pass light between two slits that are space closely together (on the order of the wavelength of light). If you then place a screen some distance away from the slits, you will observe an interference pattern. Thomas Young used this experiment in the early 1800s and it appeared to settle the issue of nature of light (namely, that it travelled as a wave) in the physics community.

      Then in 1905, Einstein wrote a paper which deduced that the photoelectric effect could only be explained using a particle model for light (This is what he won the Noble prize for, not for relativity ...).

      The problem is that something can't be a wave and particle. Waves can interfere and pass through each other, but particles cannot (they collide). So, which is light? Since the time of Newton, it was suspected to be a wave, due to interference. Young's double slit experiment was especially convincing.

      The modern answer is "It depends, depending on how the experiment is performed." If you repeat Young's interference experiment, but place a detector at each slit, you will not get an inteference pattern, you will get two sharp peaks on the screen centered around each slit. This is what you would expect from a particle model of light (the photon must pass through one slit or the other, it cannot pass through both). Even if you do the experiment so slowly, and only allow single photon at a time to pass through the slit, you will still get an inteference pattern.

      In brief, what happens is when you make an observation, the wave function of the particle is said to "collapse" onto one state or the other. But, when we aren't observing, the particle exists in a superposition of all possible states.

    28. Re:Harmony at last.. by urusan · · Score: 1

      That's not entirely correct. Experiments show that either any hidden variable theory OR the principle of locality is incorrect. It could be that there is a non-local hidden variable theory that is correct.

    29. Re:Harmony at last.. by narcc · · Score: 1

      Interacting with it causes the wave function to collapse

      Well, that's actually a huge problem. See, if a particle interacts with the system, it too becomes entangled.

      The fact of the matter is that no one has a clue what causes the wave function to collapse (or if it even does at all).

    30. Re:Harmony at last.. by m50d · · Score: 1

      By measuring strong nonclassical correlations between Raman-scattered photons, we showed that the quantum state of the diamonds has positive concurrence with 98% probability.

      I'm guessing that the two diamonds scattered photons the same way, proving that they were in the same state, even though we also know "only one of them" was vibrating. But since I don't have access to read the full paper I can't be sure.

      --
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    31. Re:Harmony at last.. by ShakaUVM · · Score: 1

      >>In my example, the perception is that it's entangled until observed, but in *reality* the ball is already in one of the boxes.

      Nope. (Well, in the non-quantum physical ball case, yeah, sure, one ball was in a box. But it's not a very good analogy.)

      Your concept of 'realism' has to be thrown out the window. Or your belief in the speed of light as the great cosmic speed limit. Read more here: http://en.wikipedia.org/wiki/Principle_of_locality

      When you're not observing an electron, the electron ceases to have a definite position. If you'd like to imagine it as a smear, or a cloud, that's a reasonably accurate analogy. You may *think* that an electron secretly has a position when you're not looking at it, but you'd be wrong. (Unless the speed of light limitation is wrong.) The wavefunction IS the reality, at least according to certain interpretations.

      Brian Greene's Fabric of the Cosmos has a reasonably good explanation here:
      http://books.google.com/books?id=DNd2K6mxLpIC&lpg=PA82&ots=ub6L_OJfGU&dq=mulder%20and%20scully%20quantum%20physics&pg=PA81#v=onepage&q=mulder%20and%20scully%20quantum%20physics&f=false

    32. Re:Harmony at last.. by Samizdata · · Score: 1

      Or at alternating times.

      --
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    33. Re:Harmony at last.. by narcc · · Score: 1

      The experiment took one photon, and sent it along two possible paths without recording which path it took, which causes a vibration in one (and only one) diamond.

      Not even close.

    34. Re:Harmony at last.. by mikael · · Score: 1

      Sounds like a programming concept called "lazy evaluation". A particular data field might be a combination of different input parameters. Sometimes it becomes more efficient not to update such values just when their inputs change, but only when they are read.

      --
      Vintage computer adverts: http://www.vintageadbrowser.com/computers-and-software-ads
    35. Re:Harmony at last.. by Anonymous Coward · · Score: 0

      I'm still fuzzy on the merits of wife-mistress entanglement. Is it a good thing or a bad thing?

    36. Re:Harmony at last.. by Anonymous Coward · · Score: 0

      I'm not a physicist but last I heard Bohm's non-local hidden-variable theory was still valid (ie. not proven incorrect). It seems a lot more sane than entanglement (at least to a programmer).

  9. Someone correct me if I'm wrong but... by Shadow+of+Eternity · · Score: 4, Interesting

    As near as I can understand this they're entangled so that vibrations in one are indistinguishable from vibrations in another, they both do the same thing at the same time (or near it at least)... doesn't this imply the ability to entangle two whatevers and transit information via entanglement induced vibrations?

    --
    A bullet may have your name on it but splash damage is addressed "To whom it may concern."
    1. Re:Someone correct me if I'm wrong but... by Baloroth · · Score: 4, Informative

      No, since when you establish the vibrations you don't know in which one it occurs. So while you could establish vibrations in a distant diamond (or particle), at least theoretically, you never know when you do so which one is actually vibrating. When they set it up, they used 1 photon that could travel and strike either diamond, creating the vibrations. Without measuring the photon's path, they didn't know which one it hit and therefore which on would be vibrating. This caused the entanglement.

      Two things: 1), the photon itself had to be able to strike both (so not FTL at all for this setup) and 2) no useful information was encoded in this experiment. One thing you could do, though, would be send one diamond one direction and the other another way. Either can know the other diamond's state by reading his own (the other is in the opposite), and no one else can, since anyone else reading it would collapse the state, and a second reading would have a different result (I believe this is more or less how quantum cryptography works). Quantum entanglement is useful for transferring information (in other cases), but the mechanics still don't allow FTL information transfer, they just allow you to encode more in less space by having two bits quantum entangled. I don't completely understand the physics of that.

      --
      "None can love freedom heartily, but good men; the rest love not freedom, but license." --John Milton
    2. Re:Someone correct me if I'm wrong but... by blueg3 · · Score: 1

      It doesn't. That would fall within "quantum teleportation". It turns out that you need to transmit information in order to perform meaningful quantum teleportation, so it can't be used to transmit information any faster than you already could. (Even though, without knowing the details of how quantum teleportation works, it certainly seems like one ought to be able to.)

    3. Re:Someone correct me if I'm wrong but... by LateArthurDent · · Score: 3, Insightful

      As near as I can understand this they're entangled so that vibrations in one are indistinguishable from vibrations in another, they both do the same thing at the same time (or near it at least)... doesn't this imply the ability to entangle two whatevers and transit information via entanglement induced vibrations?

      No, they are in opposite states. If you measure one of them, you'll determine that it is either vibrating or not. If it is vibrating, the other diamond is not, if it's not vibrating, the other diamond is vibrating. Before the measurement, they're entangled, so they are considered to be both vibrating and not vibrating simultaneously.

      That said, I don't know much about quantum effects, so I can't read the paper and understand it, but the description in the article made it seem like what's actually happening is just that the experiment is set up such that only one diamond can be vibrating, but you don't know which one it's going to be. So at all times, one of the diamonds is vibrating, the other is not, and you only know which is which when you measure one of them. Which doesn't sound like anything special. It's like me getting two playing cards, an Ace and a King, and putting them in a table face down. Then I ask you, "which one is the card in the left?" and you answer, "it's both a King and Ace. Until I flip it over, and then I can tell you what the other one is." Which is ridiculous, the card is one card specifically, you just don't know which one it is. So I suspect the media writeup screwed up, although it still seems way better than most, since they didn't mention stuff like ftl communications which pops up in almost every entanglement story even though we all know entanglement can't enable ftl communication.

    4. Re:Someone correct me if I'm wrong but... by dreemernj · · Score: 1

      I think it is a bit different then that since, as they mention, both diamonds are both vibrating and not vibrating simultaneously. It isn't the case that one is vibrating and the other is not vibrating and you just don't know yet because you haven't measured. They are both in both states until you measure. The entanglement means that when you measure one and collapse the superposition of simultaneously vibrating and not vibrating to determine which state it is in, the other diamond will be in the opposite state. So you are collapsing the superposition of one of the diamonds without actually measuring it.

      --
      1 (short ton / firkin) = 89.1432354 slugs / keg
    5. Re:Someone correct me if I'm wrong but... by narcc · · Score: 1

      Quantum mechanics does sound ridiculous, but it's the best-tested theory we have. Again, it's not that you "don't know" or "can't know" which path, which crystal, which whatever -- it really is "both" (e.g. "both paths", "both crystals"). It's frighteningly unintuitive, but this has held up experimentally (see: Bell's Inequality).

      For some reason, slashdotters seem to desperately want to return to a nice, neat, deterministic, Newtonian billiard-ball universe where everything appeals to our intuition. Unfortunately for them, this is getting less and less likely every year.

    6. Re:Someone correct me if I'm wrong but... by inviolet · · Score: 1

      No, since when you establish the vibrations you don't know in which one it occurs. So while you could establish vibrations in a distant diamond (or particle), at least theoretically, you never know when you do so which one is actually vibrating. When they set it up, they used 1 photon that could travel and strike either diamond, creating the vibrations. Without measuring the photon's path, they didn't know which one it hit and therefore which on would be vibrating. This caused the entanglement.

      Close. The entanglement is created by the fact that the photon COULD HAVE chosen either one. Because the photon was not observed in such a way that it had to collapse into particle-ish behavior, the photon never had to choose which one to hit. Therefore, each crystal was AND was not hit by the photon. They only 'decide' who took the photon when the rest of reality (e.g. an observer, or an interaction with another incident particle) needs to know exactly who took it.

      --
      FATMOUSE + YOU = FATMOUSE
    7. Re:Someone correct me if I'm wrong but... by ThosLives · · Score: 1

      This is also the part of quantum superposition that I don't understand. Given the text in the article and other things I've read, it does seem like it's the case you described with the cards. Yet the claim of quantum mechanics is is that, no, really, the diamonds (in the experiment) are indeed in both states simultaneously until they are measured. What I don't understand is how the measurement collapses the state, versus the collapse happening before the measurement (more like the cards).

      The conceptual problem I have is essentially one of causality - how do measurement cause the state to collapse in a probabilistic way (as opposed to some other way)? Especially when the measurement probe (in this case, a photon) only targets a specific geometric location.

      My personal opinion is that any single quantum event is deterministic, but we can't predict single events, so we use many events; because we are measuring many events, we can only come up with a probabilistic description.

      I liken this to flipping a fair coin: The coin undeniably lands with one side face up or face down, but I cannot reliably predict which side it will be. I can only measure it after the fact. But, I can reliably say that if I do the experiment enough times, I will get 50% heads and 50% tails.

      For entangled particles, I see it like two coins taped to each other and flipped as one unit, then split apart without looking at either of them. Then, when you look at one of them, you know exactly what the other will be. But the nature of this is probabilistic rather than deterministic, because I don't know what the result of any particular test will be; only what the result of a collection of tests will be. The key difference is, they two coins are in a particular state both before and after I measure them; I just don't know which one it is.

      Can any of the physics PhD's out there shed more light on this subject?

      --
      "There are a dozen opinions on a matter until you know the truth. Then there is only one." - CS Lewis (paraprhase)
    8. Re:Someone correct me if I'm wrong but... by jfengel · · Score: 2

      Nobody completely understands what "measurement" means, but in this case, what it means is that you have to interact the diamond with an even larger-scale system (i.e. your measurement apparatus, and then your eyeballs reading that measurement apparatus, and so on).

      The more mass you add to the experiment, the smaller the variation can be, until it is effectively nonexistent. It must be in one state or the other, and you know that the two states will necessarily be opposite.

      But as long as the objects are isolated from the rest of the world, they can potentially maintain superposition. It is in neither one state nor the other.

      What you're talking about is called a "hidden variables theory"; the idea that it really is in one state or the other, but we just don't know which. That's classical uncertainty, rather than quantum uncertainty.

      Surprisingly, it is possible to detect the difference between quantum uncertainty and classical. It's been done, and the hidden variables were ruled out. The explanation is rather involved; let's just say that it has to do with the difference between summing up all of the possibilities for the state (including the classically impossible ones), and you get a small difference. The WP article on it actually pretty good:

      http://en.wikipedia.org/wiki/Bell's_theorem

    9. Re:Someone correct me if I'm wrong but... by flosofl · · Score: 1

      Not a PhD, but I think the point is they actually aren't in particular state before they are measured (observed). They're smeared across all possible states at the same time. So the coins are equally heads AND tails. It's not until observation happens that it collapses into a this coin is heads or this coin is tails. Look up the double slit photon experiment. I seem to remember reading it and ALMOST having an epiphany. You may fare better.

      And no, I cannot explain it or even understand WHY that is. All I know is it makes my brain hurt.

      --
      "This calls for a very special blend of psychology and extreme violence" - Vyvyan "The Young Ones"
    10. Re:Someone correct me if I'm wrong but... by bhagwad · · Score: 1

      No - the puzzling nature of entaglement lies in the fact that until you measure it, no result has actually occurred - even for a single quantum experiment. So in this case, it's not as if one of the diamonds is secretly vibrating and we just don't know which one. As Bell's experiments have proved multiple times, there's no "hidden reality." The two diamonds really are vibrating and not vibrating at the same time.

      Only when an observation is made, does the wave function "collapse" and only at that time does one of them actually vibrate or not vibrate. Till that observation however, they are neither...and they are both...for real!

    11. Re:Someone correct me if I'm wrong but... by Anonymous Coward · · Score: 0

      This sounds like complete BS :)

      So, if I flip a quarter -- there is a 50/50 chance it has heads up (versus tails up). What you seem to be saying is that the quarter is both heads up and heads down at the same time. And once I look at it (measure it), then the two sides come "untangled" and it is not until that point that the two sides determine which one should be up and the other down.

      How exactly can you prove (or better yet disprove) your assertion that both particles are BOTH vibrating and not vibrating at the same time? I can say there is a unicorn in my closet, but it always vanishes when I open the door too (prove me wrong).

    12. Re:Someone correct me if I'm wrong but... by tom17 · · Score: 1

      OK, I get what people are saying now. Not that 'it's in one state or the other, only measurement will show which one state' but that 'it is in BOTH states' and only measurement will make it become in one state.

      Fine, I would accept that, but I can't 'just accept' things. This will likely make life hard for me as I need to know why they think this. As without anything backing it up, it's just an 'idea'.

      So I imagine to understand the proof that something is in two states at once, I will need to learn quantum mechanics? Or is there a layman explanation that clarifies why they are so sure that thing X is in both states Y & Z simultaneiously rather than only being in one unknown state?

    13. Re:Someone correct me if I'm wrong but... by kylemonger · · Score: 1

      Heh, no, I don't want to return to a classical universe. I like computers too much for that. I just wish there was some way quantum theory could make intuitive sense. Besides enabling the construction of modern computer hardware, quantum theory has firmly poked its head into the bailiwick of even software types like me in the form of BQP and what other NP problems it might contain, so I can't really ignore it. But at the same time, whenever I read a description of superposition I feel like a rube being enticed to play three card Monty.

    14. Re:Someone correct me if I'm wrong but... by LeadSongDog · · Score: 1

      No, only when the wave function collapses have you made an observation. I can't understand why this is so frequently stated backwards. The collapse is the observation. To paraphrase, a tree only falls in the forest once someone sees it lying on the ground.

      --
      Oh, I'm sorry sir, I thought you were referring to me, Mr. Wensleydale.
    15. Re:Someone correct me if I'm wrong but... by bhagwad · · Score: 1

      It's been proved alright. But yes - to understand it completely you need some pretty heavy theoretical knowledge/math skills. As with most things in science these days, it's not "blindly accepting" if you choose whom to believe based on their authenticity. So "blindly accepting" something when the overwhelming majority of qualified scientists back it is a very smart move. Without doing that, I would have to doubt everything from relativity to the formation of starts. I've never actually tested whether or not the speed of light is constant regardless of the frame of reference. But I "believe" it because enough qualified people say so after the Michelson Morley experiment.

      So your best bet is to "just accept" it after seeing who says so and are they reliable, and are they independent and is there a consensus?

    16. Re:Someone correct me if I'm wrong but... by Anonymous Coward · · Score: 0

      How exactly can you prove (or better yet disprove) your assertion that both particles are BOTH vibrating and not vibrating at the same time? I can say there is a unicorn in my closet, but it always vanishes when I open the door too (prove me wrong).

      You can neither prove nor disprove it because their is no independent observer, nothing "outside" which can look "inside". There is no gap between subject and object.

    17. Re:Someone correct me if I'm wrong but... by tom17 · · Score: 1

      Hmm. I can try I guess :)

      Don't forget that the overwhelming majority of qualified scientists have backed up lots of incorrect things over the eons of our scientific history. That said, I get that the scientific methods these days are far more strict and would not allow for such mistakes such as the word being flat and in he centre of the universe. But still, you have to wonder. It seems too odd to not have to wonder :)

    18. Re:Someone correct me if I'm wrong but... by wdef · · Score: 1

      Is this because computing science majors are lousy at physics or what? The reverse is usually not true - theoretical physicists can have trouble getting gigs in physics and, because of their powerful mathematical backgrounds and ability to deal with difficult levels of abstract thought, often end up working in computing areas. Google prefer to hire mathematics majors over CS majors.

    19. Re:Someone correct me if I'm wrong but... by wdef · · Score: 1

      There are little tricks - analogies only - that they sometimes feed experimental physics undergraduates to help them grasp QM ideas, eg the "bead on a wire" picture. But these are all bullshit really. QM, at least now, only really makes sense mathematically.

    20. Re:Someone correct me if I'm wrong but... by ThosLives · · Score: 1

      I did try to read and understand the article on Bell's theorem, but it didn't really elucidate anything to me. Perhaps I'll read it again...

      Ok, I've re-read it and I still don't understand it completely. The one interesting thing about Bell's inequality is that it (seems to?) only applies to correlations made on large numbers of trials rather than a specific trial itself. I'm not sure if I understood that correctly. I think I pretty clearly understood that the inequality only applies to entangled particles, though, not single-particle events.

      I also don't quite understand the differentiation between local and non-local hidden parameters.

      But, at the end of the day, I actually have to ask myself the question, Does it matter if the state of an unmeasured system is indeterminate? After all, isn't that the definition of an unobserved system? I've also been curious as to how the measurement itself affects the results - that is, is the measurement itself taken into account in the results? (Or is this what the article means by the 'detection loophole'?)

      --
      "There are a dozen opinions on a matter until you know the truth. Then there is only one." - CS Lewis (paraprhase)
    21. Re:Someone correct me if I'm wrong but... by tom17 · · Score: 1

      Ok, so I have tried to soak in Bells Theorem. http://www4.ncsu.edu/unity/lockers/users/f/felder/public/kenny/papers/bell.html

      I made it up to the conclusion. I need to go through the probability math again slowly, but I trust they are right.

      And my, that is odd. I guess I have to accept the results of those experiments and they don;t fit with locality. I am *starting* to get a grasp of this now, not that it makes (common) sense yet lol.

    22. Re:Someone correct me if I'm wrong but... by TexVex · · Score: 1

      I do that at a macroscopic scale and at room temperature on a daily basis. Quantum mechanics is a huge scam.

      QM predicts and experiments have verified that when pairs of entangled photons are passed through polarizing filters, they correlate at a rate that is a function of the difference in angle between the filters. If you do the same experiment with pairs of non-entangled photons, the results never correlate.

      Go wrap your head around that. Seriously, think about it. In order for that kind of correlation to happen, each member of the entangled pair must be connected in some way across time and space. You can't replicate that kind of experiment by flipping coins.

      After you've understood the thing well enough, then try calling QM a huge scam.

      There are a lot of incredibly smart people who make this kind of thing their life's work, and a random anonymous nobody like you has no right at all to disrespect them or the truths they are working to discover.

      --
      Fun with Anagarams! LADS HOST, SHALT DOS. HAS DOLTS. AD SLOTHS, HATS SOLD. ASS HO, LTD.
    23. Re:Someone correct me if I'm wrong but... by bhagwad · · Score: 1

      Yes - the quarter is both heads and tails...and neither as well. And this has been proved...decades ago. Check out the Bell experiments for details.

    24. Re:Someone correct me if I'm wrong but... by Anonymous Coward · · Score: 0

      Since Bells inequality refers to the probability of events happening it must rely on large numbers of trials. It is like testing how a dice is loaded, you have to roll it a lot to work it out.

      I think an important thing to understand is the effect of a measurement, also a measurement is done mathematically by applying an operator. For Bells inequality a measurement can give one of two possible answers, 1 or 0, after the measurement the particle is forced into the state corresponding to the measurement. So we have the |1> and |0> states corresponding to measurements of 1 and 0, we call these eigenstates (because when you operate on them they are unchanged). A general state, can be a composition of these eigenstates i.e. a|0> + b|1> where a^2+b^2=1, now when you measure this state you find you get 0 with probability a^2 and 1 with probability b^2. You can think of plotting this on a graph with a on one axis and b on the other which will plot a circle of possible states.

      Now in the previous paragraph I have been talking about measuring a state, this was slightly misleading because there is not just one way to measure the particle, instead we can measure it in different ways, lets call the operator I was talking about earlier A. So A puts the particle into state |0> or |1>. Now we can define another B which will put the particle into the state |B1> = 1/sqrt(2)*(|0> + |1>) or |B0> = 1/sqrt(2)*(|0> - |1>) with a measurement of 1 and 0 respectively. Now if we use operator B we put the particle into |B0> or |B1> then we can work out the probabilities of what measurement we will get from A, this is just probability (1/sqrt(2))^2 for both 1 and 0.

      At this point I will get a little bit less rigorous and appeal to the idea that my reasoning can be extended simply, also I will assume the entangled particles are fermions. Here you can see that using operator B determined the 'result' of A (result is in quotes because it affects the probability not the actual measurement but they are equivalent if you repeat it a lot). In the case of entangled particles modifying one 'instantly' (special relativity makes instantly poorly defined) changes the other so measuring one particle with B puts the other particle into the opposite eigenstate of B. As we saw earlier this will affect the result when measuring with A. Here we see the difference from the classical picture, if both particles do not communicate, (i.e. they decide what state they are in when they are separated) then measuring the first particle with B cannot affect the measurement of the second particle, but experiments have verified that it matches the probabilities calculated using quantum mechanics.

      Because of the probabilistic nature of the measurements it turns out you in fact need 3 different operators to produce different probabilities to the classical calculation. Also I have not been entirely rigorous but have tried to keep things simpler as much as possible so hopefully it is clearer. The key idea is that different operators can be used to measure the state if a different 'direction'.

    25. Re:Someone correct me if I'm wrong but... by Anonymous Coward · · Score: 0

      What about non-local hidden-variable theory?

    26. Re:Someone correct me if I'm wrong but... by sFurbo · · Score: 1

      it's not that you "don't know" or "can't know" which path, which crystal, which whatever -- it really is "both" (e.g. "both paths", "both crystals").

      Doesn't that depend on the interpretation? In the Copenhagen intepretation, it is both. In the many-world interpretation, it does both, but in two different universes. In the de Broglie-Bohm interpretation, it follows one path, but the wave-function follows both.

    27. Re:Someone correct me if I'm wrong but... by BitZtream · · Score: 2

      I really wish people would stop using retarded statements like 'both are vibrating and not simultaneously since that is 100% wrong.

      Their states are undetermined, but they are in one specific state, not both. When you start making stupid states like 'its doing two opposite things at the same time' you start to make people realize that you don't actually understand what you're describing.

      Just like Schrodinger's cat. Its not that the cat is both alive and dead, its that you just cant' know, the explanation for it originally was simply a shitty one that continues to perpetuate by people who don't actually understand it.

      Its retarded explanations like this that make people think QM is nuts. QM is very well defined, the people describing it are, 9 times out of 10, morons who need to stop thinking because they read a wikipedia article that they understand what QM is.

      --
      Persistent Volume manager for Kubernetes - https://github.com/dwimsey/openshift-pvmanager
    28. Re:Someone correct me if I'm wrong but... by BitZtream · · Score: 0

      it really is "both" (e.g. "both paths", "both crystals").

      No, it really isn't. You're confusing a mathematical explanation for reality and reality itself.

      --
      Persistent Volume manager for Kubernetes - https://github.com/dwimsey/openshift-pvmanager
    29. Re:Someone correct me if I'm wrong but... by narcc · · Score: 1

      You're confusing a mathematical explanation for reality and reality itself.

      Not at all. This isn't exactly the difficult bit of QM here! I'm astonished so many lay-persons still think so damn classically (It's like they're part of some Newtonian cult! Science moved on a long time ago.)

      Go read up on the double-slit experiment (where the single photon takes both paths and interferes with itself) and, of course, Bells Inequality.

    30. Re:Someone correct me if I'm wrong but... by Anonymous Coward · · Score: 0

      You have a lot of anger, but you're still wrong. Please google hidden variables; it has been proven there are none, but you are claiming there are.

  10. FTL Communications by fryguy451 · · Score: 1

    Next up, control a Mars rover in real-time.

    1. Re:FTL Communications by nomel · · Score: 1

      Yeah, who needs the laws of physics anyways!?

      You still need a, at most, speed of light communication channel to correlate the two.

    2. Re:FTL Communications by RPGillespie · · Score: 1

      at most or at least? To me, if the 2 crystals will be vibrating at the same time regardless of distance, the only lag would be in interpreting the vibrations on either end.

    3. Re:FTL Communications by nomel · · Score: 3, Informative

      Unfortunately, this is not the implementation of the universe.

      Here are some answers to the question, Does quantum entanglement allow faster-than-light information transfer?, given by scientists.

    4. Re:FTL Communications by Anonymous Coward · · Score: 0

      Killashandra? Is that you?

    5. Re:FTL Communications by BitZtream · · Score: 1

      Except the vibrations are not controllable and only work once. All you can do is determine what state the current atom is in, you can't effect it, and as such, you can't affect change on the other end.

      --
      Persistent Volume manager for Kubernetes - https://github.com/dwimsey/openshift-pvmanager
  11. His Dark Materials by ThunderBird89 · · Score: 1

    When can we have a perfectly secure, instantaneous communicator that even works across universes and can be carried by tiny humanoids?

    --
    Hyperbole: I use it liberally!
  12. Just in time for Christmas shopping by Accidental+Angel · · Score: 2

    Entangled diamond jewelry -- how else can you demonstrate the superposition of your commitment to your one true love? (For 10 picoseconds.)

  13. Diamonds really are forever by Anonymous Coward · · Score: 1

    Ansibles are mere steps away.

    1. Re:Diamonds really are forever by newcastlejon · · Score: 1

      Mere steps? I don't think so.
      I'd say ansibles are more of a quantum leap away.

      --
      If God forks the Universe every time you roll a die, he'd better have a damned good memory.
    2. Re:Diamonds really are forever by anomalous3 · · Score: 1

      Ctrl+F "Ansible". Wow, that was fast.

  14. Does this mean... by Slutticus · · Score: 1

    Does this mean my wife could have a diamond of twice the size, until she looks at it?

  15. A new musical! by Anonymous Coward · · Score: 0

    Diamonds are a scientist's beeeest frieeeeend!

    /goes away dancing and singing gracefully

  16. Large enough to see by Hentes · · Score: 1

    They say that each phonon involves the coherent vibration of about 1016 atoms, corresponding to a region of the crystal about 0.05 millimetres wide and 0.25 millimetres long — large enough to see with the naked eye.

    Problem is, if someone actually saw them the experiment wouldn't work.

    1. Re:Large enough to see by zlives · · Score: 1

      only if she is already entangled... otherwise they just are.

    2. Re:Large enough to see by zlives · · Score: 1

      sorry wrong thread.

  17. Re:Is this again just a theory? by Taibhsear · · Score: 4, Informative

    Did you actually read the article? "Cheap words" make up all science and literature. They explained everything they did in the article. Or do you expect them to post all their experimental data on this brief web article?

    "When we detect the Stokes photon we know we have created a phonon, but we can't know even in principle in which diamond it now resides," says Walmsley. "This is the entangled state, for which neither the statement 'this diamond is vibrating' nor 'this diamond is not vibrating' is true."

    To verify that the state has been made, the researchers fire a second laser pulse into the two crystals to 'read out' the phonon, from which the laser photon draws extra energy.

  18. Diamonds: by DC2088 · · Score: 1

    Simultaneously are and are not a girl's best friend.

    1. Re:Diamonds: by zlives · · Score: 1

      only if she is already entangled... otherwise they just are.

  19. Re:Is this again just a theory? by Anonymous Coward · · Score: 1

    You're correct. As of the 2007, the Scientists Guild requires all scientific evidence to be accompanied by visible light videos for stringent pixel examination. And, looking at a 2009 amendment, two viewpoints are required if the entire scene is many times smaller than a wavelength of the color orange, as it most likely is here.

  20. umm..ok by zlives · · Score: 1

    "The optical properties of diamond make it ideal for producing tiny optical circuits on chips." what does that have to do with quantum states.... or am i missing something.

  21. Explain to me again by Anonymous Coward · · Score: 0

    Will someone explain to me again why must we consider two "superimposed" states, that "both" occurred, until we measure one of the two?

    Why can't we just say that we don't know which of the two states happened until we measure it? Why all the ambiguity??

    1. Re:Explain to me again by bhagwad · · Score: 1

      Because the Bell experiments destroyed that notion thoroughly....decades ago. It's not that we don't know. Reality takes a back seat until an observation takes place.

    2. Re:Explain to me again by wdef · · Score: 1

      The Many Worlds hypothesis may help you. While abused a bit in sci-fi like "Sliders" it appears it may really describe reality and is an relatively easy way to understand how a quantum computer can do many calculations in parallel. Each parallel calculation effectively occurs in a different universe. It does hurt your head to think about this.

  22. Great by RPGillespie · · Score: 1

    Now let's give one diamond to my ISP, and one to me, and maybe I can get some information at a decent speed.

  23. the science education is what your're missing by Anonymous Coward · · Score: 0

    Sounds like you're missing the actual science education.

  24. Other macroscopic examples by Anonymous Coward · · Score: 0

    As far as I understand, the key is that the photon (and phonon) leave everything as it was. If the photon (or the phonon) somehow changed the state of the diamond crystal, the entanglement couldn't take place.

    So I can suggest an even more mundane example of "Schrödinger's cat:" light traveling through the air. A photon leaves the lightbulb as a superposition of all directions (a ball wave) and interacts with the air molecules. But you can't tell which precise air molecules it "touches." No momentum or energy (or other quantum numbers) is transferred to them so the air is left intact by the photon. However, the interaction can be observed generally by the fact that the photon hits the screen "late."

    What I find interesting is that light that is reflected off a mirror retains its quantum properties (interference). That means that a photon that is reflected back does not change the momentum of the mirror (measurably) because otherwise you could detect the change after the fact and determine the path taken by the photon.

  25. Day of the Tentacle by Anonymous Coward · · Score: 0

    Same plot

  26. Living Proof? by Anonymous Coward · · Score: 0

    So Mitt Romney is living proof of quantum mechanics?

  27. Car analogy by Anonymous Coward · · Score: 0

    Let me try this one...

    You have a T shaped tunnel. Car goes in at the bottom, the drivers gets instructions to pick left or right at random. On both sides of the tunnel exits, you put a large glass plate across the road. Now you send off the car. It's important that you don't look which exit the car takes, no peeking! After enough time has passed for the car to have exited the tunnel, one of the glass plates will be broken, the other not. The 2 glass plates are now in an entangled state, you do not know which one is broken and which not until you look, you just know one of them is broken.

    According to TFA the difficulty with the experiment seems to be that most cars never exit the tunnel. They must be using mice for drivers.

  28. Not wierd. by Anonymous Coward · · Score: 0

    but rather... spooky.

    --
    AL

  29. Can we detect wavefunction collapse, or not? by Normal_Deviate · · Score: 1

    Detecting wavefunction collapse is trivial, just look for interference between the possible states, ala the two-slit experiment. HOWEVER, if the collapse of an entangled wavefunction can be detected, than FTL information transmission is possible, because collapsing one half of an entangled pair will instantly collapse the other half, causing the interference pattern (or whatever) to disappear. So what am I missing?

  30. The Task Ahead... by 0xG · · Score: 1

    ...is for us to simulate quantum entanglement in a digital object.
    We have done it with neural networks, we can do this.
    It will be very difficult (possibly profitable too), but a truly epic breakthrough.
    Think of it.

    --
    A pox on web designers who feel that window.innerWidth == screen.availWidth
    1. Re:The Task Ahead... by wdef · · Score: 2

      People here are looking for a physical level of understanding which probably does not exist. QM is *all* mathematics. We have already described entanglement mathematically. Programs are just algorithms and algorithms are just mathematics. So your "simulation" is somewhat redundant? Just a thought.

  31. Vibrating diamonds are a girl's best friend by OneAhead · · Score: 1

    I mean, what's not to like about them? So many uses!

  32. Statistics not particles by dak664 · · Score: 4, Interesting

    Let us not lose sight of the fact that a photon is a statistical convenience, not a particle, and a phonon is even less a particle. You can't send "one photon" and detect "one phonon". These are statistical coincidence measurements that detect correlated behavior between the two diamonds after an electromagnetic interaction that can not transfer less than Planck's constant of action. Either diamond would show a 50% excitation in the absence of the signal from the other. Spooky action at a distance is inferred from correlation of the states over a large number of events. Which is why quantum computing is not going to be as fast as everyone thinks it will be.

  33. Lodestone Resonator by bradgoodman · · Score: 1

    Can you say: "Lodestone Resonator"?? :-O

  34. What does those stones cost? by Sla$hPot · · Score: 1

    They cost a million bucks and they don't.
    Huh?..Can i bring them home? : Yes and no!
    WTF?? : Perhaps!

    Jokes aside, i think entangled wedding rings would sell pretty well.
    What about entangled ethernet cards for finance banks and hardcore gamers.
    Or entangled radiators. Throw some in the Sahara dessert and sell the entangled cast iron opposites for $2.000 each :-O

  35. Screams... by Trax3001BBS · · Score: 1

    I thought entanglement required products from the same origin.

    Just when I figured I might have a small handle on things quantum...

  36. The future is coming by Anonymous Coward · · Score: 0

    This might be the event we look back on 100 years from now as the closest thing to the fictional dilithium crystals.

    JJ

  37. Understanding Quanum Entanglement.. by atticus9 · · Score: 1

    Coming from a non-physicist - when people talk about a superposition of two particles that are quantum entangled are they just saying "we know an event happened to one of these particles we just don't know which one until we look". For example if I had two cards layed face down, and picked one at random, could I argue that the cards were "entangled" because if one was picked, the other was "instanteneously" known to be not picked, regardless of distance, and until I looked the two cards were in a "superposition" of both being picked and not picked?

    If that's the case, then in quantum computing, why would someone be able to store or process an exponentially increasing amount of information through having more qubits? (since users would only see one unchanging state if the ever observed their data) Also it would seem there's any number of macroscopic ways to simulate a supercondition without the need to entangle individual photons.

    1. Re:Understanding Quanum Entanglement.. by narcc · · Score: 1

      when people talk about a superposition of two particles that are quantum entangled are they just saying "we know an event happened to one of these particles we just don't know which one until we look"

      Not even close.

  38. amused, not amused by Anonymous Coward · · Score: 1

    We are both amused and not amused.

  39. Re:Is this again just a theory? by Anonymous Coward · · Score: 0

    Is this again just a theory?
    Am i missing something or there is still no evidence?

    You are definitely missing something.

    A theory is the top of the food chain, otherwise known as a fact.
    A theory is something never once proven wrong, and so far always shown to be correct.

    So no evidence means it is a "guess"
    Wording your "guess" into a form that can be proven false means it now becomes a "hypothesis"
    A hypothesis that has never once been proven incorrect is then called a "theory" in science and "fact" in real life.

    If any of the three, a theory, hypothesis, or guess is ever proven false, then it gets bumped down one below guess, and we now call it "incorrect"

  40. It is simple by qasar.es · · Score: 1

    P1. We can only know for certain what we measure. C1. So, the best physical law can only predict future measurements. C2. So, it is not the case that the particle is vibrating and not vibrating, but rather that we can not know if the particle is vibrating, or not, before we perform a measurement.

  41. Elitzur–Vaidman bomb testers by Anonymous Coward · · Score: 1

    Does it matter if the state of an unmeasured system is indeterminate? After all, isn't that the definition of an unobserved system?

    take a look at Elitzur–Vaidman bomb tester thought experiment:

    Consider a collection of bombs, some of which are duds. Suppose these bombs carry a certain perfect property: usable bombs have a photon-triggered sensor which will absorb a photon and detonate. Dud bombs have a malfunctioning sensor which will not interfere with any photons.[4] The problem is how to separate at least some of the usable bombs from the duds. A bomb sorter could accumulate dud bombs by attempting to detonate each one. Unfortunately, this naive process destroys all the usable bombs.

    apparently, quantum mechanics allows one to actually identify (some) working bombs without blowing them um.

  42. Re:Is this again just a theory? by narcc · · Score: 1

    A theory is the top of the food chain, otherwise known as a fact.
    A theory is something never once proven wrong, and so far always shown to be correct.

    Lies! How this particular bit of misinformation entered the mainstream I'll never know.

    A theory is a predictive model. A hypothesis is a testable prediction. There are plenty of theories (that are still theories) which have been abandoned because the predictions they make are not supported by evidence and experiment. (You don't test a theory, you can't, you can only test the predictions that it makes!)

  43. quantum space by Anonymous Coward · · Score: 0

    like a hyperspace but outside normal space allows this communication to happen, can i prove it nope but its logical.