Slashdot Mirror


Fiber Optic World Records Broken

Thousands of miles of existing fiber still lie dark, but as schnucki writes, "Bell Laboratories believe they have broken two world records in the use of optical fibres to transmit information." They sent 160 gigabits/sec on one wavelength, and then in a separate experiment sent 1,022 separate wavelengths down one fiber. You do the math. Check it out.

37 of 148 comments (clear)

  1. In the running.... by Wiggins · · Score: 2

    I am getting 21600 on my 56K modem at my new apartment? Did I win anything?

    --
    Funny and I thought Perl == Paid employment recently located ....hmmph.....
  2. My favourite line by rde · · Score: 2

    The first record promises to increase speed.
    Woohoo! No more poxy 299,792,458m/s! According to relativity, this means that the data can go backwards in time. Soon we'll all be complaining about anti-latency.

    Normally I wouldn't nitpick the BBC[1], but seeing as they split an infinitive in the last paragraph, I felt I had no choice.

    [1]This is a lie.

  3. 19.96 Terrabytes/sec? by Ziviyr · · Score: 2

    I'd like to have that running into my home. Perhaps we could use SimCity to demonstrate the traffic surge that will generate? The subways could be the fibers, put some commerce, here, there. Cram the schools in the lower corner, Why does SimCity insist that there have to be power generators inside the internet?

    --

    Someone set us up the bomb, so shine we are!
  4. Re:Fibre Optics vs speed of light. by Manax · · Score: 2
    Just a little thought should tell you this isn't so. If the speed of light were directly correlated to datarate, that would indicate that all fiberoptics trasmitted the same amount of data, and thus the feat that Bell Labs performed wouldn't be very interesting.

    To give a bit of background, fiberoptics is just a small glass (or other clear substance) thread, which provides a container for light to bounce through. The light always goes at the same speed (I know that isn't quite true, but close enough for this discussion).

    The data rate achieved is based on the frequencies that are transmitted. So, in order to get the higher data rates, higher frequencies are needed. (Generally.)

    --
    "Why should I be content to simply live in this world, when I, as a human being, can CREATE it?" - Oertel
  5. Stability? by nevets · · Score: 3

    I'm just curious what the error rate is. Can you send that much data without loosing a few bits. I'm impressed with the numbers regardless, but if you have a 50% error rate is that good? Also if you loose one bit per byte, can you clam anything? Did they only count the good bits sent?

    Also, what is the speed to transfer the light signals to electrical. I don't have (or have I ever heard of) an optical computer, would be nice though ;). If you send 160 Gb/s (20 GB/s), can you convert that to electrical data without making a bottleneck. I'm not an expert in this area, but I'm curious to know.

    Steven Rostedt

    --
    Steven Rostedt
    -- Nevermind
    1. Re:Stability? by BobTheJanitor · · Score: 2

      The error rate would be almost nil. Most errors on standard wires are caused by surrounding data inadvertantly manipulating the bits, known as 'bursts'. Light, on the other hand, isn't succeptable to such manipulations. The only error that I can think of that would happen in the fiber optic line would be an error in the process of making the cable, and would manifest itself every single time, instead of in the random way standard errors appear. Granted, there could be all sorts of errors converting data to light and back, but that certainly can't be written off as a fault of the cable. As long as you are able to accurately and quickly convert your data to light and back again, you should see almost no errors at all.
      Additionally, one could use Hamming code (certainly appropriate for Bell to use), for error correction. Granted, this would slow conversions, but it is the current error-correction on computers anyway.

    2. Re:Stability? by Surak · · Score: 2

      Depends on the speed of the CPU and particularly the data bus. On most PC hardware, even direct memory transfers aren't THAT fast. You need the speed in the I/O bus which is even slower....you simply wouldn't NEED that much bandwidth.

  6. This is nothing New by CaptTailor · · Score: 2

    What they are doing here is called WDM (wave division multiplexing). There has been a standard for a while on WDM. But the thing is this only allows you to cram more information down one pipe it doesn't shrink the equipment on either end. They need to stick in and OC-48 for each wave length, so you would need about 1 foot ball field of space to stick all of the equiptment for this one piece of fiber. To sum it up don't expect to see any dramatic speedups anytime soon

  7. Using *one* laser by dattaway · · Score: 2

    They claim all 1022 wavelengths were transmitted at the same time with an ultra fast laser. I thought lasers emitted coherent light at one wavelength. I have seen adjustable lasers, but it was one wavelength at a time and depended on tube geometry and the die used. How do they tune their laser to transmit multiple frequencies at the same time? It sounds unbeleivable to me.

    1. Re:Using *one* laser by dej05093 · · Score: 3

      If you have a really short pulse length of e.g.
      10 fs (= 10^-14 s!) the spectral range of this
      puls covers the whole visual spectrum. If you
      pick out a small range of this spectrum using
      a grating you will enlarge the length of the
      pulse (if you have a pulse with a length of one
      ns you can't determine the frequency of this
      pulse with a higher precision than one GHz and
      vice versa).
      With fibre gratings you might be able to pick
      out a large number of different spectral ranges
      which can then be modulated individually before
      they are once again combined and put into the
      fibre. With 1550 nm wavelength the required spectral range should be at least about +- 100 nm!
      for a data bandwidth of 20 TBits/s

      Nevertheless it is really amasing!

    2. Re:Using *one* laser by Remus+Shepherd · · Score: 2

      Lasers emit coherent light, but not necessarily of one wavelength. A CO2 laser I once used for atmospheric sounding emitted 72 distinct and separately detectable frequencies.

      The real question is how you're going to transmit data over all those frequencies at once. The frequencies of the CO2 laser spectrum were set ratios of one another. To have each frequency transmit independant information, you'd either have to use multiple lasers or have some very interesting frequency gate optics. I do not work with fiber optics or data transmission...perhaps gate optics of that sort already do exist.

      --
      Genocide Man -- Life is funny. Death is funnier. Mass murder can be hilarious.
    3. Re:Using *one* laser by Tau+Zero · · Score: 2
      What they're probably doing is electrically changing the laser's index of refraction (at very high speed, of course). Doing this changes the effective length of the optical cavity, and thus the lasing frequency. Semiconductor lasers are not spectrally pure in any event, and being able to switch among several of the different resonant modes is one way to do the multi-color trick.

      The thing that gets me is that the 1022-wavelength laser and the 160 GB/sec carrier are probably incompatible; the laser almost certainly cannot be modulated anywhere near the 160 Gb/sec rate. Assuming one system can do both is not much different from assuming that because you can get a 20-ton garbage truck, and you can get a Mach 2 SST, that you can make a 20-ton Mach 2 garbage truck.
      --
      Advertisers: If you attach cookies to your banner ads,

      --
      Time is Nature's way of keeping everything from happening at once... the bitch.
  8. Woohoo! This will support more cell phones! by Christopher+B.+Brown · · Score: 2
    That's more colors than there are colors for the new "PalmGlove" cases!

    And boy, will that ever give us more bandwidth to support the increasing numbers of cellular phones!

    (Um, oops... How do you get the fibre cables out to the phones?)

    --
    If you're not part of the solution, you're part of the precipitate.
  9. They should be researching... by LordStrange · · Score: 2
    They should be researching new cable INSTALLING techniques. Who cares how much bandwidth the trunk a half mile away has if I can't have any of it? Until it cost about 3 orders of magnatude less than $450K per mile (number based on unreliable recollections) for fiber I'll be stuck in the bleak world of copper.

    Vacuous futurist idea: Imagine a very small machine that burrows from a central office/switch to your basement with very little operator attention. As it burrows it's dragging along a strand or two of lovely fiber.

    Listen to me whine! I'm lucky enough to have a cable modem and I'm STILL not content!

    --

    License: By reading this you are agreeing that you agree with me.

  10. Re:The math doesn't work like that, though by dattaway · · Score: 2

    Light can indeed cancel itself. Think of defraction patterns caused by coherent light mixed 180 degrees out of phase with itself. My physics is a little rusty, but I'm interested in fundamental harmonics created by other modulated wavelengths.

  11. the big news by Haven · · Score: 3

    I think the most impacting news is that optic "router". That is going to have the biggest effect. We dont' need 160gb/s if it has to be converted into an electronic signal everytime it switches fiber lines.

  12. Sampling rates, digital, and misc cool stuff by Signal+11 · · Score: 5
    Just incase you guys didn't know - the reason fiber optic can go so fast is because it transmits analog signals. That means you can layer several hundred harmonics on a single frequency and create a very complex waveform. The trick is in the decoding - converting it to digital. That's where all the sample-rate jazz comes into play.

    This isn't really revolutionary new technology.. we've known about stuff like this for awhile. There's a nearly infinite number of ways to encode frequencies, and stack things onto each other.

    I find myself wanting of the ability to insert IMG tags here. :( In short, picture a sine wave. Now along the slope of one, picture another sine wave attached to it. And so on. I suspect they're doing something like that. Actually, TVs do something like this - it's how the sync pulses and whatnot work. Very facinating technology. Also very old by today's standard, but still very useful.



    --
    1. Re:Sampling rates, digital, and misc cool stuff by Surak · · Score: 2

      Right...not unlike modems except on a phone line there is a very limited number of sine waves that can be fit and there amplitude and frequency are quite limited...early modems were 110 bps, then 300 then faster...the max speed of the medium never changed (POTS are limited to 33,600 bps) only the encoding techniques changed ...

    2. Re:Sampling rates, digital, and misc cool stuff by tzanger · · Score: 3

      not unlike modems except on a phone line there is a very limited number of sine waves that can be fit and there amplitude and frequency are quite limited...early modems were 110 bps, then 300 then faster...the max speed of the medium never changed (POTS are limited to 33,600 bps) only the encoding techniques changed ...

      Not quite...

      Modern modems use QAM to send data, not discrete sine waves. If I'm not mistaken "raw" sine waves haven't been used since 300 baud modems... You know the ones where you had the switch to select originate or answer. :-)

      POTS is limited to 2400 baud. You achieve everything faster by encoding more than one bit per "transition" or baud. Modems these days aren't. They are "just" DSPs which don't actually modulate based on a carrier, rather just output what is necessary to achive the symbol.

      Picture a graph centered at the origin. x is phase and y is amplitude. You don't just have +1 and -1. you have (if I'm not mistaken) 6 or 8 levels along each axis. you can choose any of those phases with any of those amplitudes. Essentially you end up with 64 or 256 possibilities per symbol. (I'm pretty sure it's 256)...

      Anyway what I'm trying to describe is a constellation pattern... They're usually illustrated like this:


      . . . . | . . . .
      . . . . | . . . .
      . . . . | . . . .
      . . . . | . . . .
      --------+--------
      . . . . | . . . .
      . . . . | . . . .
      . . . . | . . . .
      . . . . | . . . .


      Each dot represents a possible symbol. You can only spit out 2400 symbols per second over POTS but you can send multiple bits per symbol, or baud, giving you speeds faster than 2400bps.

      The 56k limit on POTS has its roots in how T1s are actually set up and transmitted. T1s are actually transmitted as 193-bit-long frames, 8000 times per second. One of those bits is required to keep frame sync, leaving a payload of 192 bits per frame, giving you 1.536mbps. T1s originally carred voice, sent as 8-bit PCM data. Twelve 193-bit-long frames are logically grouped together and called a super frame. The 6th and 12th frame in the larger super frame had 1 bit used for frame sync as usual, but then instead of the remaining 192 bits being used as 24 8-bit channels, 24 7-bit channels were sent, with the LSB used for line status for each channel (busy, off-hook, etc.). This loss of the LSB every 6 frames wasn't very noticable for voice, but over data it just isn't cool. ESF is similar to SF but 24 193-bit frames were grouped instead of 12 so that 4 bits of framing could be used instead of just 2, on the 6th, 12th, 18th and 24th frame. AFAIK those extra two bits weren't ever really used, they just duplicated the info in the original 2 line status bits.

      Since every 6 frames you're missing a bit and it's not possible for the modem to know which frames will be missing the bit, the modem only relies on the 7 bits being clean. So now you've got 7 bits sent 8000 times a second for 56000bps instead of the theoretical 64000bps per channel over a 'clean' T1 channel.

      This concludes your lesson. If you want to know more, just email me. Hopefully this isn't too far off topic, but it *is* some history about how POTS works with digital transmission. :-)

  13. Re:Who's gonna dig new cables by Duke+of+URL · · Score: 2

    Qwest has their fiber-optic lines setup so you don't need to dig them up to replace them. They just yank them out of the conduit. They have 2 conduits set up, one is full right now, the other is empty (if I recall), so they can string the fiber in it, with no digging up the lines.

    Older companies like AT&T have to do more work to redo their fiber lines.

    BTW, a post further down the line here there is a post which implies that Lucent makes fiber-optic lines for sale. I know they do optical research, but Corning makes the majority of the optical lines sold. Corning's symbol is GLW for interested investors.

  14. Re:Fibre Optics vs speed of light. by Haven · · Score: 2

    No, not at todays processing speeds. You could though push electrons through copper at roughly the speed of light. Think of it like this. You have marbles(electrons), and a pipe(copper or any other conductive medium). You can push the marbles through the copper to near the speed of light, but due to laws of relativity the electrons will never be able to be transmitted the speed of light.

  15. And the pr0n providers are already slavering... by Christopher+B.+Brown · · Score: 2
    Does this mean that Feel-O-Vision is about to come to public release ?

    (Feel free to modify words in that sentence so as to provide bad jokes. There are ample options available...)

    --
    If you're not part of the solution, you're part of the precipitate.
  16. I just did the math... by iCEBaLM · · Score: 2

    160,000,000,000 * 1022 = 163,520,000,000,000 bits
    163,520,000,000,000 / 8 = 20,440,000,000,000 bytes
    20,440,000,000,000 / 1024 = 19,960,937,500 kbytes
    19,960,937,500 / 1024 = 19,493,103.02734375 Mbytes
    19,493,103.02734375 / 1024 = 19036.233425140381 Gbytes
    19036.23342514038 / 1024 = 18.590071704239 Tbytes

    That is some bandwidth on ONE FIBER....

    -- iCEBaLM

  17. math by Haven · · Score: 2

    can it do 160gb/s over all 1022 channels?

  18. Re:can you say .... by QuMa · · Score: 2

    What's wrong with cable modem? It modulates and demodulates, right?

  19. Profit motive by Tau+Zero · · Score: 2
    You think Bell Labs is going to share this tech with ANYONE?
    Yes, I do. Selling the technology is how they make their money; if they kept it to themselves, the next company to get a product out there would lock up the market and eat Bell's lunch.
    --
    Advertisers: If you attach cookies to your banner ads,
    --
    Time is Nature's way of keeping everything from happening at once... the bitch.
  20. Re:can you say .... by Surak · · Score: 2

    yup...99% of all cable is carrying analog waves, which makes it a cable modem (MODulator/DEModulator)

  21. Someone flunked Fourier analysis by Tau+Zero · · Score: 4
    Vary the single wavelength's amplitude (intensity) alone, and it's still single frequency while carrying data too.
    I see you never studied for a ham radio license or anything else of the sort.

    Varying the intensity of a light source creates "sidebands", the same as it does for RF. These "sidebands" are wavelengths slightly longer and shorter than the "carrier". What you see as an amplitude variation is really the interference of the carrier and the sidebands, as they slip in (high amplitude) and out (low amplitude) of phase over time. If you have a carrier frequency of F and a modulation frequency of M, you'll create sidebands at F+M and F-M. If you have really good filters you can suppress one of the sidebands and still carry all the information, and if you have really good frequency references as well you can ditch the carrier and only bother sending one sideband (you can use the frequency reference at the receiving end to supply the "carrier" for demodulation); this is how SSB radios work.

    What does this mean for optical fiber? It limits how close together your "colors" can be based on how fast each one is modulated. The sidebands get farther and farther from the carrier as the modulation gets faster, and if the sidebands start clashing you get crosstalk and data errors.
    --
    Advertisers: If you attach cookies to your banner ads,

    --
    Time is Nature's way of keeping everything from happening at once... the bitch.
  22. Re:speed of light == c only in a vacuum! by Otto · · Score: 3

    The speed of light through any medium is less than the speed of light in a vacuum. Sometimes light can be made to travel through a medium faster than it's natural rate. This results in a nifty "light shockwave" which I believe is called cherenkov radiation.

    Yep. You can see some cool pics of this effect at http://www.nuc.umr.edu/Reactor/Reactor.ht ml, along with a pretty good explanation of how. It's pretty neat the way it actually happens..

    Furthermore, the light in a fiber actually zig-zags down the fiber channel and does not travel straight down it. This also reduces the signal's speed from c.

    Actually it increases the distance of travel which gives an appearent speed difference from c, which is just as good as slowing it down. :-)



    ---

    --
    - Give a man a fire and he's warm for a day, but set him on fire and he's warm for the rest of his life.
  23. Bandwidth vs. Latency. by schon · · Score: 2

    it's often been said (though I'm not sure how true it is now) that current data transfer methods may seem fast, but they still don't beat the "data transfer rates" of simply filling a stationwagon full of data tapes, and driving it yourself to the destination.

    True, but the thing that this approch doesn't take into account is latency. (which, depending on the length of the drive, and how long it takes to load/unload the stationwagon, can range from ~5 minutes, to several days..)

    If I'm playing a game of quake, I'll get my ass whopped if I rely on the stationwagon method :o)

    I think that (although the bandwith is considerably smaller) this is a step in the right direction. :o)

  24. Re:Fibre Optics vs speed of light. by Mr+Z · · Score: 3
    I'm curious, can the speed of light be measured in Gb/s?

    *sigh* People keep getting rate of propogation confused with rate of transfer. This is latency vs. bandwidth folks.

    For instance, consider the ancient communication method consisting of two people atop hills signalling with lanterns and shades. The latency is really low because the light propogates at near 3e8 m/s in air. The bandwidth sucks. Now consider a freight-train loaded to the gills with DVD-ROMs. The bandwidth is enormous, but the latency sucks.

    The speed of light governs how quickly a packet of data gets from point A to point B. Bandwidth measures the total number of packets of data that you can send from point A to point B at a given time. The two are different, unless you somehow treat each photon as its own packet of data, and we're not there yet.

    --Joe
    --
  25. Paying for it three times. Also standards. by Ungrounded+Lightning · · Score: 3
    We need to run fiber to every home in the nation with gov't footing a large chunk of the bill (otherwise no one would do it).

    We'll run fiber to the homes shortly, if something isn't developed soon that's even better. (Take a look at the recent Scientific American articles on the current candidates.)

    Individual fibers to the home are a lot of bux. But a multiwavelengh fiber to the neighborhood and a passive wavelength divider (think prisim) and a bunch of short fibers to the house look like a good cost-tradeoff.

    But having the government pay for it means you get to pay for whichever solution they chose at least three times - once for the install, twice more for the administrators. And the government will chose the wrong one. And the government won't even chose the best price/performance combo for the data rate they do chose.

    Sure the government built the Interstates (kinda). And then they installed a 55 MPH speed limit - city, prarie, or deserted desert. Let them wire your home (or your kid's school) and they'll do it badly, expensively, and use it as a wedge to control the content.

    The fact that I can plug in a *crank* telephone (not pushbutton, not rotary,... a crank phone) from 189x and *still* use it to make and receive calls on POTS lines should say something about the state of telephone tech in supposed advanced nations like the US.

    Actually, it says more about good standards lasting a long time. Just like the Roman's choice of wheel spacing affecting cars, trains, and spacecraft components (that are shipped on trains) to this day.

    The POTS standard is about getting audio from the switch in the city to the houses in the city and to the farms around it. The last mile of the audio part of that job hasn't changed materially since Bell and Strowager. A cheap low-tech solution does it, so why pay a bunch of bux to replace it with something that doesn't interact? Especially when doing so creates an administrative nightmare for no advantage.

    Data is now hitting the wall on the capacity of the infrastructure designed for voice, so you need to replace part or all of it to go beyond.

    --
    Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
  26. Huxley's Visions by Christopher+B.+Brown · · Score: 2

    I think that they called them feelies in Brave New World...

    --
    If you're not part of the solution, you're part of the precipitate.
  27. Even more off topic by A+nonymous+Coward · · Score: 2

    But funny! so please don't mark this down :-)

    Winston Churchill is reputed to have answered, when accused of ending a sentence with a preposition, "That is something up with which I shall not put".

    --

  28. Re:What if amplitude changes only at zero crossing by Tau+Zero · · Score: 2
    Amplifying a pure sine wave "exactly at the zero crossings" to eliminate sidebands is not possible because the amplification or deamplification cannot happen instantaneously without an infinite amount of power and since the amplitude change would always take some non-zero amount of time, the sine wave will deform over that period. The deformarions show up as other frequencies.
    Actually, it's worse than that. You can view any waveform as a collection of pure sinewaves at various frequencies and phases (integral from 0 to infinity of e^(i*omega*t) f(t) dt). The wave you're describing would have a corner, an instantaneous change in slope, there at the zero crossing. (Exactly where, zero crossing or otherwise, doesn't matter.)

    But since this is all put together from sinewaves, which are nice and continuous, how the heck do you get a corner? In practice you can't, because it requires frequency components out to infinity (and infinite bandwidth!). But even an approximation of that "corner" requires other frequency components which add during the high-amplitude section, and then they all come together at the "corner" and suddenly they all subtract from the "carrier" for the low-amplitude section. All of these different frequency components mean lots and LOTS of sidebands. You can hear this in Morse code communications; if a keying network isn't set correctly and it cuts the signal off abruptly, you can hear the sidebands (key clicks) far away from the sender's carrier frequency. An over-modulated AM signal that "flat-tops" (clips)or cuts off completely causes broadband "splatter" which can be heard well off the channel too.

    The way to limit bandwidth is to vary things smoothly, with no edges or corners. It may not be intuitive, but this is an area where your intuition doesn't get much experience.
    --
    Advertisers: If you attach cookies to your banner ads,

    --
    Time is Nature's way of keeping everything from happening at once... the bitch.
  29. Switching at zero crossings doesn't help by Ungrounded+Lightning · · Score: 2
    Changing amplitude only at zero crossings rather than at other places changes the details of how the energy is smeared among frequencies, but doesn't change the fact, or amount, of the smearing.

    You can derive the result of amplitude modulation from the trignometric identity:

    sin(a) * sin(b) = sin(a+b) + sin(a-b)

    By treating the carrier as a sine wave and the modulation as a sum of sine waves, and using the normal properties of real-number multiplication and addition you can work out the spectrum that results from amplitude modulating a carrier with any periodic waveform. It gets slightly more complicated for aperiodic waveforms, but the basic result is the same: A pair of sidebands, on either side of the carrier, that reproduce the spectrum of the modulating signal.

    To send more bits on an AM carrier you essentially have to either modulate the signal faster (spreading out the spectrum of the modulating signal and thus that of the modulated signal) or modulate it more finely (using more bits to control the amplitude). The number of bits you can cram into the second is limited by the signal-to-noise ration of the channel (i.e. when you get near the noise your least significant bits get corrupted).

    The Nyquist sampling criterion gives you a quantitative limit on this: If you have a band-limited signal, you can encode it with a number of bits-per-second equal to 2 times the bandwidth times the base-2 log of the signal-to-noise ratio, and reproduce it to within the the noise threshold. So that's the absolute maximum number of bits the signal can carry.

    --
    Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
  30. See It at Bell Labs! by SgtPepper · · Score: 2

    Read bell labs blurb on their web site here they do get a /bit/ more technical...not much though i'm afraid...