I was in your situation three years ago. I lost my domain simply because I forgot to renew it, so I had to wait three years before two other buyers decided it wasn't worth the money.
Now my crackpot friends have something to add to their theories... the Mayan Calendar, the solar system passing through the plane of the galaxy, and the end of analogue tv MUST mean that 2012 is the end of the world!
That will be the next great "bad physics" movie:
The sun has run out of hydrogen! We must drive a giant drill into the center of the SUN to explode twelve hydrogen bombs or America will be destroyed!
early in the late 1910s. WTF does that mean? Can we get an editor here, please? It means sometime likely between 1915-1919 inclusive.
It makes sense if you think "the late 1980s" or "the late 1820s"... "the late 1910s".
If the 58000 hours is not cumulative, then this represents 4.6 millenia of computing time. If that were done with one processor, about 180 supernovae would explode in our galaxy during the computation.
It's basically just a very expensive hotel - you can stay for $20M USD, but that only if you go through the Russians. For the States, it has produced zero revenue; for science, it has produced nothing of interest. Ever wondered why NASA projects to kill the funding over the next decade?
By the way, you'd need 1 car driving over it every second for 50 years to cover the cost of the ramp. Are my numbers wrong or is this not a very good idea?
Lots of people are asking about the power/energy/cost/etc but I haven't seen any really thorough or consistent answers. I'll give it a shot.
Assume the car is going ~40km/h = ~10m/s. The ramp looks like its about 1m across.
1m / 10m/s = 0.1 sec to cross the ramp.
0.1s * ~10kW = 0.1s * 10kJ/s = 1kJ of energy transferred every time you drive over it.
Let's say some car has a mass of 1600kg. It would lose:
(1/2)(1600kg)v^2 = 1kJ
v = 1.1m/s = 4km/h of speed
In terms of gasoline, this would be the equivalent of: (energy density of gasoline = 45.7MJ/kg)
1kJ / 45.7Mj/kg = 2.19e-5kg
2.19e-5kg * 1000L/803kg = 2.73e-5 litres of gasoline. (gasoline has a density of 803kg/1000L)
This costs you (if you live in Toronto):
2.73e-5L * $0.85/L = $2.3e-5 (canadian dollars) every time you drive over it and generate 1kJ of energy.
Compare this to the cost of electricity:
$0.1/kWh * 1h/3600s = $2.7e-5/kWs = $2.7e-5/kJ (in canadian dollars)
So it may be a little bit cheaper to have you drive over the thing than to power the lights with normally generated electriciy. Except you're the one paying, instead of the city.
Let's say you drive over 10 of these in one day. What is the cost per year?
$2.3e-5 * 10 * 365 = 8.4 cents per year. Not really significant.
Slashdot Mirror
Clearly a 2% preference for iOS means it represents the entire female gender! /s
Source: http://blog.nielsen.com/nielsenwire/online_mobile/us-smartphone-battle-heats-up/
What happens to those who are currently imprisoned on possession charges?
...you must add the .pdf extension.
If we are willing to INDICT for making false claims about tubes, we should IMPEACH for making false claims about WMDs.
You can see a few of the first photos here! (Not a trap)
Why not promote this in a more positive light? Change the headline to "placebo effective treatment for mild depression"!
Your link to beyond is incorrect, which is unfortunate since it is so spectacular.
More info is available hereI was in your situation three years ago. I lost my domain simply because I forgot to renew it, so I had to wait three years before two other buyers decided it wasn't worth the money.
Now my crackpot friends have something to add to their theories... the Mayan Calendar, the solar system passing through the plane of the galaxy, and the end of analogue tv MUST mean that 2012 is the end of the world!
Are you Tom Duck from Dalhousie? I've heard of you, I am in the space program at York.
Included on the lander is a Canadian-built weather station.s -lander.html
http://www.cbc.ca/technology/story/2007/08/04/mar
That will be the next great "bad physics" movie: The sun has run out of hydrogen! We must drive a giant drill into the center of the SUN to explode twelve hydrogen bombs or America will be destroyed!
Fun: chmod g=r my.brain Scary: chmod g=rw my.brain
I just realized... I totally missed the point. Oops
Soon to be renamed: Trantor!
If the 58000 hours is not cumulative, then this represents 4.6 millenia of computing time. If that were done with one processor, about 180 supernovae would explode in our galaxy during the computation.
http://video.google.com/videoplay?docid=1996259363 769507120&hl=en
Short answer: nothing!
It's basically just a very expensive hotel - you can stay for $20M USD, but that only if you go through the Russians. For the States, it has produced zero revenue; for science, it has produced nothing of interest. Ever wondered why NASA projects to kill the funding over the next decade?
"I shall take the heart," returned the Tin Woodman; "for brains do not make one happy, and happiness is the best thing in the world."
It's the Martians. They buried their attack force in Mt. St. Helens millenia ago, and now they've come to claim our world for themselves!
By the way, you'd need 1 car driving over it every second for 50 years to cover the cost of the ramp. Are my numbers wrong or is this not a very good idea?
Lots of people are asking about the power/energy/cost/etc but I haven't seen any really thorough or consistent answers. I'll give it a shot.
Assume the car is going ~40km/h = ~10m/s. The ramp looks like its about 1m across.
1m / 10m/s = 0.1 sec to cross the ramp.
0.1s * ~10kW = 0.1s * 10kJ/s = 1kJ of energy transferred every time you drive over it.
Let's say some car has a mass of 1600kg. It would lose:
(1/2)(1600kg)v^2 = 1kJ
v = 1.1m/s = 4km/h of speed
In terms of gasoline, this would be the equivalent of: (energy density of gasoline = 45.7MJ/kg)
1kJ / 45.7Mj/kg = 2.19e-5kg
2.19e-5kg * 1000L/803kg = 2.73e-5 litres of gasoline. (gasoline has a density of 803kg/1000L)
This costs you (if you live in Toronto):
2.73e-5L * $0.85/L = $2.3e-5 (canadian dollars) every time you drive over it and generate 1kJ of energy.
Compare this to the cost of electricity:
$0.1/kWh * 1h/3600s = $2.7e-5/kWs = $2.7e-5/kJ (in canadian dollars)
So it may be a little bit cheaper to have you drive over the thing than to power the lights with normally generated electriciy. Except you're the one paying, instead of the city.
Let's say you drive over 10 of these in one day. What is the cost per year?
$2.3e-5 * 10 * 365 = 8.4 cents per year. Not really significant.
Interesting!