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Perfect Silicon Sphere to Redefine the Kilogram

MrCreosote writes "The Age reports optical specialists at CSIRO are helping create a new standard for the kilogram, based on a precise number of atoms in a perfect sphere of silicon. This will replace the International Prototype, a lump of metal alloy in a vault in Paris."

81 of 453 comments (clear)

  1. alternate theories by arun_s · · Score: 5, Informative

    I found some alternate theories that are also attempting to precisely measure the kilogram at everything2. They look pretty interesting, here's a small excerpt:

    Superconducting levitation

    This method works along essentially the same principles as the Watt Balance. In it, a superconductor of a known mass is placed within a superconducting coil. By running current through the coil, a magnetic field is generated that causes the superconducting mass to levitate. By levitating it at different positions and measuring the current required to do so, the magnetic flux can be calculated. Magnetic flux relates directly to Planck's constant, and because the force generated by the magnetically-induced levitation and the downward force of gravity must be equal, Planck's constant can thus be precisely related to the kilogram.

    Hey wait, TFA skims over what they're going to do with the Silicon ball once its made. Again, from everything1:

    X-ray interferometry is used to determine the distance between lattice planes in the silicon crystal, permitting physicists to determine, as closely as possible, the number of atoms in these spheres. Currently, a measurement accuracy of one part in 10^7 is possible, after considering all of the various sorts of error introduced in the process, but it is hoped that ten times this accuracy will be possible within five years.
    --
    I can explain it for you, but I can't understand it for you.
    1. Re:alternate theories by JanneM · · Score: 5, Insightful

      This method works along essentially the same principles as the Watt Balance. In it, a superconductor of a known mass is placed within a superconducting coil.

      If you have a lump of anything of a known mass, why bother with the rest?

      --
      Trust the Computer. The Computer is your friend.
    2. Re:alternate theories by jmv · · Score: 5, Interesting

      I personally wouldn't put too much trust into a measurement that depends on gravitational acceleration for several reasons.
      1) It means you can't move the setup somewhere else easily because gravity is location-dependent
      2) Events like the 2004 tsunami has a slight (but measurable) effect on the Earth's rotation and hence on the acceleration (because of centrifugal force) ... and most importantly
      3) Your measurement will (*literally*) depend on the phase of the moon (just like tides)

    3. Re:alternate theories by jimstapleton · · Score: 2, Insightful

      maybe because you are using the lump of known mass to measure something else.

      Duck Measurer: "I put a duck on one side of the scale, and use weights (lumps of known mass) on the other side to determine the mass of the duck."
      Some Guy: "Umm, but you already know the mass of the weights, why are you bothering?"

      --
      34486853790
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    4. Re:alternate theories by Delirium+Tremens · · Score: 4, Insightful

      You are confusing mass and weight.
      Mass = how much matter there is in an object.
      Weight = how much pull does a particular gravity (like Earth's g) has on that quantity of matter.

      That's why you could be floating (weightless) in a space ship without having lost any of your fingers or other parts of your body (mass) ;-)

    5. Re:alternate theories by _Eric · · Score: 5, Informative

      You're mixing up mass (an amount of matter) and weight (the gravitational force felt by matter). The kilogram can be used anywhere. Only using a device based on absolute measurement of weight (spring based scale) will render the device dependent on the the local gravity field. Yet, true enough, this is how most of modern electronic scales work (they could still weight a known internal mass for calibration to work that around, but I don't know if or how this is actually done).

    6. Re:alternate theories by _Eric · · Score: 2, Funny

      OK parent was perfectly right, I should have shut up.

    7. Re:alternate theories by hanshotfirst · · Score: 5, Funny

      Duck Measurer: "I put a duck on one side of the scale, and use weights (lumps of known mass) on the other side to determine the mass of the duck."
      Some Guy: "Umm, but you already know the mass of the weights, why are you bothering?"
      To see if they float, of course.
      --
      Why, oh why, didn't I take the Blue Pill?
    8. Re:alternate theories by vigmeister · · Score: 2, Informative

      The principle you outlined is related to the Avogadro's number hence the name of the project. Using the same principle and different volumes, you could use water, but it depends also on accurate measurement of temperature. It is anyway contrived and reverse engineered from the definition of units of pressure (atm uses water; torr uses Hg and so forth)

      Even if you could use the water standard, pure water is impossible to find. Purer silicon than water can be obtained which makes this project sensible. Not that they would use this technique to define the kilogram though :)

      I can't think of any applications for the damn thing though... Except QC and Calibration maybe?

      Cheers!
      --
      Vig

      --
      Atheist: Buddhist in a Prius
    9. Re:alternate theories by Anonymous+Cowled · · Score: 3, Funny

      Villager > If... she... weighs... the same as a duck,... she's made of wood.
      Bedevere > And therefore?
      Villager > A witch!

    10. Re:alternate theories by Software · · Score: 2, Insightful
      At the risk of being pedantic, people in spaceships orbiting earth are not weightless; the Earth's gravity has an effect on them (namely, keeping them in orbit). Their sensation of weight will be zero, because they are essentially in free fall, but they still have weight.

      To be fair, though, you didn't specify that the person was in orbit. Maybe you were thinking of in interstellar space, where a person would be weightless.

    11. Re:alternate theories by Locklin · · Score: 2, Informative

      If your referring to the parent which talks about the balance - it is in fact referring correctly to mass. A balance measures mass, a spring scale or other force measuring device measures weight.

      If you meant a different parent, then disregard.

      --
      "Knowledge is the only instrument of production that is not subject to diminishing returns" -Journal of Political Econom
    12. Re:alternate theories by jimstapleton · · Score: 3, Insightful

      they are using flux to measure mass.

      Actually, the discussion involves using EM Flux as a way to calibrate mass measurements.

      Or, using the duck analogy further - then finding (or making) a duck that precisely matches the needed measurements...

      Regardless, the goal here is to get a reliable way to reproduce accurate mass meausre, without having a chunk of known mass available at or available to the reproduction site.

      --
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    13. Re:alternate theories by thegnu · · Score: 2, Insightful

      Maybe you were thinking of in interstellar space, where a person would be weightless.

      Not to be pedantic here, either, but maybe you'll just be in an imperceptibly slow freefall in an imperceptibly large orbit.
      --
      Please stop stalking me, bro.
    14. Re:alternate theories by shaitand · · Score: 2

      Begone foul grammar troll.

    15. Re:alternate theories by mobby_6kl · · Score: 2, Informative
      At the risk of sounding ignorant due to the lack of a PhD in physics, I thought people in spaceships (in orbit at least) are weightless. The gravity is still present so it's not zero gravity, but since there's no force acting on them other than gravitational acceleration, they are indeed in free fall and are thus weightless.

      Walter Lewin seems to agree with this:

      "If I jump from a tower which is 100 (?) meters high, I will be weightless for about 4 seconds, ignoring the air drag."
      From this video lecture, wich deals with this issue.
    16. Re:alternate theories by mrvan · · Score: 2, Insightful

      Probably shouldn't be feeding the trolls here, but GP is probably Dutch from his nick, and in Dutch the same word is spelled with 'sf'.

      If being unAmerican is the same as being mentally retarded it seems we're right back in the days of the terrorism^H^H^H communism scare

    17. Re:alternate theories by Linker3000 · · Score: 3, Funny

      In order to comply with National Legislation, witch burning must be made carbon neutral by the planting of an equivalent number of new trees in the enchanted forest.

      --
      AT&ROFLMAO
  2. First of all by alx5000 · · Score: 2, Insightful

    ... no sphere made of atoms will ever be a perfect one.
    Second, if that rusty lump in Paris defines what a kilogram is, in no way is this sphere gonna change that.

    --
    My 0.02 cents
    1. Re:First of all by Corporate+Troll · · Score: 4, Informative

      Second, if that rusty lump in Paris defines what a kilogram is, in no way is this sphere gonna change that.

      That's wrong. The lump is not rusty, because the lump is platinum-iridium which is quite unreactive so that corrosion ("rust") won't affect the material. Corrosion alters the weight, you know.

      Second, it can change the definition. The metre used to be a platinum rod in Paris, now it is defined in how much distance light does in a certain (very short) time. Here it will be that the kilogram will be defined as N silicium atoms. (Where N is a very large number) Scientists do not like definitions based on objects, they prefer definitions based on universal constants. All this could of course be read in the article....

  3. Re:"perfect" sphere by Aladrin · · Score: 4, Insightful

    No, it's impossible. What they -really- mean is that it'll be perfect as far as we are able to measure it. And it has absolutely nothing to do with what is really important here: They are counting the atoms of silicon in a kilogram and will use that measurement as the basis for the kilogram, instead of some lump of metal in a vault.

    The kilogram will not change, only a proposed scientific definition of it.

    The sphere doesn't mean -anything- except that it'll weight exactly a kilogram and be amazingly round.

    There's either a lot of media spin, or someone's attempt to get his work recognized and used. From what I can see, there's not a single soul that has dedicated to USING this new scientific definition, other than those directly involved with the project.

    --
    "If you make people think they're thinking, they'll love you; But if you really make them think, they'll hate you." - DM
  4. The real reason they are changing it by antifoidulus · · Score: 3, Funny

    is because they are embarrassed of the fact that a T-rex managed to steal the original one and now they need a replacement.

  5. Ah yes... by Nerdposeur · · Score: 4, Funny

    ..but how can they make sure the new kilogram weighs a kilogram? :)

    1. Re:Ah yes... by at0mjack · · Score: 4, Informative

      They don't. The idea isn't to make the new sphere weigh a kilogram. The idea is to redefine the kilogram in terms of the weight of an atom of silicon (i.e. 602383623523895723945743 atoms of Si-14 weigh exactly 14 grams). The idea of the ultrapure and ultraround Si sphere is that (a) you can measure the lattice spacing of the Si atoms in it using x-ray crystallography, so you know how far apart the Si atoms are, and (b) you can measure the diameter of your ultraround sphere very accurately, so you can calculate its volume very accurately. Given these two, you can calculate with very small error bars how many atoms of Si there are in the sphere, and given the definition of the kg in terms of how many atoms of Si make up a kg you can calculate exactly how much the sphere weighs.

      You can then stick it on your balance that needs calibrating, and twiddle the dials until the balance thinks that the sphere weighs the same as the calculated weight.

  6. Re:"perfect" sphere by TapeCutter · · Score: 2, Funny

    "but can you ever really get a perfect anything?"

    The whole notion of "silicon balls" sounds fake to me!

    --
    And did you exchange a walk on part in the war for a lead role in a cage? - Pink Floyd.
  7. Re:"perfect" sphere by Gorshkov · · Score: 3, Funny

    May God have mercy on your soul if you ever attempt to call a woman a physical object to her face.

  8. I always thought that by oliverthered · · Score: 3, Insightful

    A kilogram was equal to 1000 millilitres of water and that 1000 millilitres of water would fit into a space 10cm cubed.

    If they've already defined the metre using constants, isn't something like this the best way of defining a kilogram.

    --
    thank God the internet isn't a human right.
    1. Re:I always thought that by at0mjack · · Score: 5, Informative

      The main problem with this as a definition is that water expands and contracts with temperature. So, if you wanted to define the kilogram in terms of a volume of water, you need to specify the temperature at which you are making the measurement. Temperature isn't something you can measure with very high precision (parts per million or parts per billion), so you end up with unavoidably large errors. As a result this is useless as a basic standard, the essence of which is that you should be able to repeat the standard measurement and get the same answer to N decimal places.

    2. Re:I always thought that by gkhan1 · · Score: 2, Informative

      That's wrong, actually. I mean, practicality doesn't really figure into defining the other units, how practical is it to define a meter as the length light travels in 1/299,792,458ths of a second? The point is that it has to be absolute. 1 dm^3 of water at 4 degrees Celsius (whatever that is in Kelvin) is exact and absolute. Plus, we already have a similar definition, the Kelvin is defined as exactly 1/273.16 of the temperature of the triple point of water. If the hokey-ness of measuring temperature figures into the kg, it should figure into the definition of the Kelvin.

      No, the REAL reason this is an impossible way to define mass is pressure. Water density depends ever so slightly on the pressure it is in. Pressure is measured in Pascals, and as we all know that 1 Pa = 1 N / 1 m^2 is the definition of the Pascal, and that Newton's second law is 1 N = 1 kg * 1 m/s^2. Which means that if you used this method, you would use the kilogram to define the kilogram. Not dice soldier. That's why we have a rusty lump.

  9. Re:don't need to create it to define it by setagllib · · Score: 4, Insightful

    The point of having a physical object is that it can be used as a root for calibrating devices. From there you can calibrate more devices on each other. The further you get, the less likely you are to be precise, but the chances are pretty good that little deviations up and down will cancel out overall. But it's absolutely important to have an exact starting point, and a physical object is the only way to do that.

    It's a lot easier to measure a large object than a small one and multiply it, since a small error will also multiply out. What I don't get is how they intend to build an exact number of atoms into the sphere. You would need some other exact measurement, like number of electrons for calculating precise electrolysis procedures.

    --
    Sam ty sig.
  10. What's it useful for? by Max+Romantschuk · · Score: 3, Interesting

    Except for the challenges of making one, what's it useful for? You can't use it to calibrate anything, the wear and tear caused by the friction of handling would eventually change it's mass and defy it's purpose. Is the actual "finished product" good for anything else than sitting in another vault somewhere?

    --
    .: Max Romantschuk :: http://max.romantschuk.fi/
    1. Re:What's it useful for? by meringuoid · · Score: 2, Interesting
      Except for the challenges of making one, what's it useful for? You can't use it to calibrate anything, the wear and tear caused by the friction of handling would eventually change it's mass and defy it's purpose.

      It's hierarchical. You use the standard kilogram to calibrate other, slightly less exalted standard kilograms. So the one kept in London and the one in New York and the one in Tokyo get calibrated against the one in Paris. Then you calibrate actual working weights against those.

      --
      Real Daleks don't climb stairs - they level the building.
    2. Re:What's it useful for? by dargaud · · Score: 3, Informative

      You can't use it to calibrate anything, the wear and tear caused by the friction of handling would eventually change it's mass and defy it's purpose.
      Yes you can. The problem with the current reference weight is that it cannot be reproduced. Here you have a definition: this volume (4/3.Pi.R^3) contains such an amount of Si atoms. We define their individual mass and we define the whole sphere to be one kilo, ergo we can build another one. Just like defining the meter as a distance covered by light, here it's the weight of a given number of atoms.
      --
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    3. Re:What's it useful for? by jabuzz · · Score: 2, Interesting

      It's extremely unlikely that the spehere has a mass of exactly one kilogram. What you do is assign a mass to an individual Si atom, and count the number of atoms in the sphere. You then have a mass for that sphere. The more accurately you can count the atoms the more accurate the mass assigned to the sphere.

      The idea behind this is that rather than having a absolute reference mass in a vault in Paris, we can create new reference masses at will, so we can have additional ones in London, one in New York, one in Tokyo etc. with no need to refer them back to the one in Paris.

      The fact the reference SI spheres all have slightly different masses is not important. As long as we know exactly what the mass of each sphere is, then it can be used to calibrate other secondary masses, which can in turn be used to calibrate/produce tertiary masses.

    4. Re:What's it useful for? by AikonMGB · · Score: 2, Informative

      The sphere itself, no; you would use it in some experiments (carefully, to reduce error) for whatever purpose, and then you would put it back in the vault. However, once this Si sphere is complete they will know to some level of accuracy X how many Si atoms make up the sphere. That way this company can just create more spheres, count the number of Si atoms in it and as long as the interferometry matches the number of Si atoms they set as being 1kg to within their limits of measurement, then these other Si spheres can also be used to do the same experiments with the same level of accuracy and precision (two different things).

      The key difference between these Si spheres and the hung of metal alloy in paris is that these spheres are reproduceable. You would have an incredibly hard time creating a hunk of metal alloy the exact same mass as that in Paris; furthermore, I presume these spheres are less susceptible to degradation due to environmental effects.

      In essence, we're re-defining the kilogram so that instead of the formula 1kg=1(Hunk of Metal) we have 1kg=X(Si atoms), where X (my understanding, anyway) is what they are trying to determine as closely as possible. Once this standard is actually set, they will select an exact number of Si atoms in the middle of their error distribution and say "this is the definition for 1kg!", even if that means there's a tiny change in what 1kg really is, since the difference is so small that we wouldn't be able to tell there was one until years down the road when we have more accurate sensors to measure both mass and number of atoms. But even then, the number they chose wouldn't change.

      Aikon-

    5. Re:What's it useful for? by 22mcdaniel · · Score: 2, Interesting

      I think the kilogram is the last unit of measurement that hasn't been defined in terms of fundamental physics phenomena.
      Most definitions depend on the (hopefully) invariant properties of nature and are removed from effects of man. Nobody can drop the definition of the meter stick; its definition cannot be changed by war, by incorrect handling, by temperature, by location, by time. The definition of the meter is the same whether you are on mars or earth.
      I remember reading some time ago that people are worried that the mass of the kilogram is changing. Diffusion of atoms into and away from its surface and even its infrequent handling may change its mass. The precision of the kilogram is limited by these uncertainties.
      To recap:
      meter - Length that the speed of light travels in 1/299,792,458th of a second.
      second - Duration of 9,192,631,770 transitions between two hyperfine levels of a cesium 133 atom.
      kilogram - Weight of a chunk of metal in a jar.

  11. Re:"perfect" sphere by Anonymous Coward · · Score: 5, Funny

    >May God have mercy on your soul if you ever attempt to call a woman a physical object to her face.
    Especially if he compares her to a perfect sphere.

  12. Okay geeks... by Dan+East · · Score: 3, Funny

    A perfect sphere, down to the atom, of 1 kg silicon would require pi to what precision?

    Dan East

    --
    Better known as 318230.
    1. Re:Okay geeks... by richard.cs · · Score: 2, Interesting

      Work it out if you really want to know but it's not a problem, even if pi were needed to make the sphere which it isn't. I remember readong somewhere a while ago (it may have been on slashdot, may have been somewhere else) that 34 decimal places of pi are sufficient to calculate the radius of the uiverse to within the width of a hydrogen atom.

      It's fairly easy to prove that this is roughly correct if you look up the the two sizes. Compare the orders of magnitude.

    2. Re:Okay geeks... by AnotherBlackHat · · Score: 2, Funny

      640 digits of PI ought to be good enough for anyone.

      -- Should you believe authority without question?

  13. Re:"perfect" sphere by ozmanjusri · · Score: 4, Informative
    There's either a lot of media spin, or someone's attempt to get his work recognized and used.

    It's important enough for laboratories in Germany, Italy, Belgium, Japan, Australia and USA to invest a great deal of time and effort.

    The spheres are being made by CSIRO's Centre for Precision Optics. They've been making precision spheres for research since the late '80s, and have all the recognition they need from anyone who has a clue.

    Have a look here; http://www.tip.csiro.au/IMP/Optical/spheres.htm. It might help you understand the project better.

    --
    "I've got more toys than Teruhisa Kitahara."
  14. Re:"perfect" sphere by CommunistHamster · · Score: 5, Funny

    It makes the calculations simpler.

  15. Re:Huh? by Yvanhoe · · Score: 4, Informative

    A lot of units can be defined using physical properties : a second is 9,192,631,770 periods of a precise physical reaction (transition between the two hyperfine levels of the ground state of the caesium-133 atom according to the wikipedia), a meter is the distance travelled by light in a 1/299,792,458 of a second and so one, Volts, Joules, etc... are defined this way. Mass, however, was not yet related to physics constants. So there is a "yardstick" for kilograms. A platinium cylinder was made a century ago, the closest we could get to what was considered a kilogram at this time and it was proclaimed "the exact measurement of a kilogram is the mass of this particular object". It is stored somewhere in Paris. I am sure that modern scientists will manage to conceive an experiment with a great precision to transform the kilogram unit into the abstraction it is supposed to be.

    --
    The Wise adapts himself to the world. The Fool adapts the world to himself. Therefore, all progress depends on the Fool.
  16. Silicon has 14 electrons per atom by tepples · · Score: 2, Informative

    What I don't get is how they intend to build an exact number of atoms into the sphere. You would need some other exact measurement, like number of electrons for calculating precise electrolysis procedures. The number of electrons in a crystal equals the number of protons. But "silicon" is defined as the element with 14 protons per atom. So the number of electrons equals the number of atoms times 14.
  17. This is about measuring the Paris kilo by femto · · Score: 5, Informative

    The CSIRO project is about determining how many silicon atoms are equivalent in mass to the current standard kilogram. Once that number is established the actual kilogram in Paris is redundant. If it gets lost or destroyed we can reconstruct the kilogram by counting out 'n' silicon atoms. It also means anyone can construct their own kilogram by counting out 'n' silicon atoms, without having to go to Paris to do a comparison.

    It is a separate (but related) project to figure out the second part of the project: how to easily count out 'n' silicon atoms, so creating a universally available standard. One way might be to make a silicon sphere, like the CSIRO, but most people don't have the ability to do that.

  18. perfect, well-rounded, bouncy by siddesu · · Score: 5, Funny

    silicon spheres will define the standard ... will they be coming in pairs by any chance?

    1. Re:perfect, well-rounded, bouncy by Sinbios · · Score: 2, Funny

      Silicon not silicone.

      --
      Anyone can "stand up for what they believe", but it takes a very brave individual to change what they believe. - Loundry
  19. This also affects the pound by tepples · · Score: 3, Informative

    Of course you've already heard about this in the EU. Slashdot is a primarily US focused site, and as we all know the US is stuck with retarded imperial measurements. A U.S. pound is defined as exactly 0.45359237 kg, just as a foot is exactly 0.3048 m. Therefore, any changes to the kilogram's definition also affect that of the pound.
  20. Re:"perfect" sphere by metlin · · Score: 3, Funny

    Would you rather a square? =)

    Reminds me of a story - a friend had gotten a boob-job and we were all out for dinner one night. Another common friend of ours hadn't known this and the first time he saw her, he burst out - "You've grown three dimensionally!"

  21. Re:Huh? by dschuetz · · Score: 4, Informative

    OK, someone's going to have to explain this for me. Why do we have to have an actual object to define a weight?

    You don't. That's just the way we've done it in the past. I read a really interesting article a couple months ago in American Scientist magazine called An Exact Value for Avogadro's Number that addresses exactly this question. In the past, Avogadro's Number (6.02andchange x 10^23) was defined experimentally, based on the reference kilogram. These scientists propose reversing that -- defining the number absolutely, based on the number of atoms of a particular element that fit within a sphere of a certain size. It's sort of similar to what they're doing with the silicon sphere, but it's all done on paper, rather than by actually manufacturing an artifact.

    The advantage of this, they say, is that the number will remain constant and not be affected over time as refinements in building and measuring such "reference kilograms" change the accepted mass of a kilogram. They make several other arguments, as well, but it's much better if you just read the article. :) It's also mentioned that a similar approach was taken to defining the meter, based on an absolute definition of the speed of light.

  22. Insert random breast implant joke here. by JDark · · Score: 2, Funny

    Jenna Jameson do your part for science.

  23. SI horsepower by Bromskloss · · Score: 5, Funny

    One horsepower is the power of the reference horse in an archive in Paris.

    --
    Swedish plasma phys. PhD student; MSc EE; knows maths, programming, electronics; finance interest; seeks opportunities
  24. Re:Huh? by nine-times · · Score: 4, Insightful

    Ok, people are giving snarky answers here, but I'll try to give you a more straight answer.

    The only way we have to keep a standard unit is to have an object with that unit and call that the standard. Let's say you were building some sort of a scale that would measure weight in kilograms; you'd have to calibrate it first. This means that you'd have to find an existing weight that was one kilogram, put it on the scale, and mark that this weight is a kilogram. But then how do you find a 1 kilogram weight? You have to measure it on some scale that's already calibrated correctly. This chain continues, and has to end somewhere.

    So the two questions I anticipate are:

    1. why not keep an already calibrated scale?
    2. why do we need a particular weight stored somewhere, instead of continually basing the measurement on kilograms measured on other scales?

    To answer the first question, a scale would be harder to maintain accurately. It could break, and calibrations don't hold forever. You'd have to re-calibrate it every so often, and how do you do that without an object known to be exactly 1kg?

    The answer to the second question (which I imagine might have been your question all along) is a little more complicated. Let's imagine that we have no exact 1kg object stored anywhere that we use as the standard. So one guy in a lab is using an iron ball as his 1kg weight, calibrating scales with it, and selling scales to others. The iron ball slowly rusts over time, and the weight of the ball changes a little. Someone takes one of the scales calibrated with the rusty balls and does the same thing, but this time with his own hunk of iron, but the environmental conditions in this guy's lab aren't as controlled, and he tends to get water condensation on his iron ball, meaning it rusts faster and each calibration varies depending on how much water has collected.

    Now, imagine it keeps on like this for 75 years, with different guys selling scales, getting their original measure from someone else, and then using their less-than-perfect means to continue calibrating and making scales. After 75 years, there are some drastically different "kilograms" floating around I buy a scale, measure out 1 kilogram, take it to a different scale and get 1.5 kilograms, while another says .75 kilograms. In this case, who's kilogram is "correct"? When the issue was raised, people would say, "Oh, if only we had a standard "kilogram" to compare them to!"

    And so we have someone keep a physical reference object under very controlled conditions and of materials that will prevent corrosion or other corruption to the material.

  25. Re:What about the pound? by simong · · Score: 2, Informative

    Yes, there are standard Imperial weights and measures. I seem to recall that one set are on display at the Tower of London. However, the pound now seems to be legally defined as 0.453 592 37 kilogram.

  26. single isotope by Tzinger · · Score: 3, Informative

    Standards for weights, mass, distance or any other measure, are critical in the calibration of instruments. This calibration provide the means that to compare product specifications and research results.

    This particular effort is a very interesting set of challenges. It requires the use of single isotope of silicon; calibrations for distance and roundness, and a sophisticated means to to count the atoms. This last step requires the silicon to be perfectly crystalline.

    Measurement is itself a very interesting study bordering on metaphysics and philosophy. The desire to measure things has been at the heart of a lot of scientific investigation, economics and other areas of study. Ref "Abstract Measurement Theory" by Louis Narens https://mitpress.mit.edu/catalog/item/default.asp? ttype=2&tid=6345/

    --
    "If all the American people want is security, let them live in prisons." Eisenhower
  27. Re:Huh? by Rob+the+Bold · · Score: 2, Informative

    OK, someone's going to have to explain this for me. Why do we have to have an actual object to define a weight?

    The kg is a unit of mass, not weight.

    --
    I am not a crackpot.
  28. Exam by matt+me · · Score: 4, Funny

    Weird. I read about this in an exam I took last week. It stated that the present standard kilogram is a mass of platinum and iridium kept at STP underground, and asked what factors might affect the mass of the standard kilogram when it is measured. I answered if any isotopes of platinum or iridium decay, or if the standard kilogram had a velocity close to the speed of light.

  29. Trying to be helpful -- do not flame please by hummassa · · Score: 4, Informative

    You are being very dense here.

    TODAY: 1kg = the mass of the "rusty lump" in Paris. We don't know how many atoms of Ir and Pt the "rusty lump" have. So, if the "rusty lump" changes mass (and it changes with time because of being rustier all the time) AND because the "rusty lump" is used to calibrate scales all over the world, the kilogram is effectively changing with time. This is BAD.

    WHAT THE GUYS ARE DOING: they are trying to make the most perfect silicon sphere possible that weights the same as the "rusty lump". Once they get to do that, they will count the atoms of silicon on the sphere, using interferometry. Suppose the # of atoms of the shpere is M.

    WHAT WILL WE GOT THEN: 1kg = M atoms of silicon. This definition will never change, and if the silicon spheres rust or break or change weight by any circunstances, we make new ones with M atoms and we have a forever-constant definition of a kilogram. This is GOOD.

    Got it? They did the a similar thing with the meter -- the original was a rod roughly 1m in size, then they did some measurements and said (*) "oh, one meter is the length that the light takes 1/299,792,458 of a second to go through in vacuum." and now they can do as many calibrating rods as needed, provided they make them the length that the light takes 1/299,792,458 of a second to go thru.

    (*) actually the meter had an intermediate definition of "1,650,763.73 wavelengths of the orange-red emission line in the electromagnetic spectrum of the krypton-86 atom in a vacuum", but the new definition has the advantage of setting the light speed at exactly 299,792,458 m/s.

    --
    It's better to be the foot on the boot than the face on the pavement. ~~ tkx Kadin2048
    1. Re:Trying to be helpful -- do not flame please by painandgreed · · Score: 2, Insightful

      WHAT WILL WE GOT THEN: 1kg = M atoms of silicon. This definition will never change, and if the silicon spheres rust or break or change weight by any circunstances, we make new ones with M atoms and we have a forever-constant definition of a kilogram. This is GOOD.

      Yes, but which isotope of Si? Three occur in nature in various quanities. Did they use just a single isotope? If not, what are the various percentages?

  30. Re:What about the pound? by ArieKremen · · Score: 2, Informative

    I have moved from metric countries to the US, and have actually researched that issue. Turns out, that the US is implicitly metric!!! The "Customary US Units of Measurement" are defined by relating them to metric base units, e.g. 1 yd = 3 ft = 36 in = 36 in * 2.54 cm/in = 91.44 cm. Weights are similarly defined. The "implicit conversion" is based on bills passed in the early 70's

    --
    -- Cave quid dicis, quando, et cui
  31. Re:What about the pound? by Rostin · · Score: 2, Informative

    Actually, a pound is sometimes both a mass and a weight. It's one of the stupider quirks of the customary system. When the distinction is important and not obvious from the context, pounds mass (lbm) or pounds force (lbf) is specified. The "conversion" between the two involves a constant, usually written as g-sub-c.

    lbf = lbm * (accel due to gravity) / g-sub-c

    constant = 32.174 lbm*ft*s^-2*lbf^-1

    That way, one lbm weighs very close to 1 lbf.

    http://en.wikipedia.org/wiki/Pound-force

  32. I can think of a better material. by frostilicus2 · · Score: 3, Funny

    I'd prefer A non-perfect sphere of Silicone .

    --
    Nothing sucks like a Vax, nothing blows like a PowerMac G4
    1. Re:I can think of a better material. by stud9920 · · Score: 2, Funny

      I'd prefer two.

  33. Re:"perfect" sphere by ozmanjusri · · Score: 4, Informative
    They're probably also going to get a lot of opposition to changing the 'definition'.

    No, it's widely accepted as a necessary step towards being able to define the unit of mass in terms of a specific number of carbon 12 atoms. Look, it would be a lot better for this discussion if you made the effort to learn what the project was for.

    Just because you personally don't understand it doesn't make it "media spin" or otherwise redundant. There's more information here http://www.npl.co.uk/mass/avogadro.html, including an FAQ which might clear up some of your misconceptions.

    --
    "I've got more toys than Teruhisa Kitahara."
  34. Re:As of today, by jabuzz · · Score: 2, Informative

    Wrong what we are trying to do is count the number of Si atoms in a sphere so we can say sphere X has a mass of Y, and then use the sphere to calibrate other masses. We already have a number for how many silicon atoms in a kilogram, and once we can count atoms precisely enough that preexisting number will be fixed.

  35. The standard kilogram has been losing mass by ribuck · · Score: 3, Informative

    A new standard is needed because the "standard kilogram" held in France has been slowly losing mass, about 50 micrograms in the last 100 years, compared to other reference masses. It's not known how this has occurred.

    Wikipedia - Kilogram
    http://en.wikipedia.org/wiki/Kilogram

    Slashdot: The Changing Definition of 'Kilogram'
    http://science.slashdot.org/article.pl?sid=03/05/2 7/023252

  36. Re:"perfect" sphere by Alchemar · · Score: 2, Interesting

    The real purpose of the project is to produce a reproducable standard. If something was to happen to the lump of metal that currently defines a kilogram, there is no reliable way to reproduce it. You can make another lump of metal and weigh it, but even the most precise scale we have been calibrated back to the original lump of metal plus or minus the error of the machine. The problem is that the errors are cumulative. If we have to replace the lump of metal several times, it will be less and less precise. If however we can base the weight on a physical constant, then we can use that physical constant to calibrate future scales on. There will be errors based on the precision of the machine, but they are no longer cumulative. If you build a more precise machine, you get a more precise measurement.

  37. It should be a perfect cube by clickety6 · · Score: 2, Funny

    ...that way they'll be able to find it again after they put it down somewhere.

    "Zut alors! Pierre, le sphere parfait - ou est-ce que tu le placer?

    "C'etait sur le table, Jean-Claude"

    "Merde, il avait roller sous le sofa encore!"

    --
    ----------------------------------- My Other Sig Is Hilarious -----------------------------------
  38. Re:"perfect" sphere by BMazurek · · Score: 2, Interesting

    I remember a small magazine (called Science Digest, IIRC) I read in the mid 80's. It was short little science articles, probably a couple hundred words each (at most)...not unlike RSS feeds today, perhaps.

    One article was about scientists making the most perfect sphere to date out of some crystal. It was measured to be so perfectly round that if you scaled it up to the size of the earth, it's highest peak would be 12 feet higher than it's lowest point.

    I'm sure the technology for this thing has improved a lot in 20 years.

  39. Would you trust Austalians for that ? by boule75 · · Score: 2, Funny

    I mean, come on, would you Australians to define scientific standards? I won't!

    For starters, those guys believe the South is on the top and North is at the bottom of the maps! I feel upside down just thinking of it. And on which side of the road are they driving already? North or south? See: you cannot trust those guys!

    Second, the issue with "the" current "reference" in Paris (there are three cylinders in fact) is that is loses atoms sometimes, so its mass diminishes. I mean it is still The Kilogramme but the kilogramme is not what it was some years ago when the grass was greener and the boys were nice and, hum! Anyway, how would that be different with yet another physical object? Wouldn't it lose some random atoms from time to time?

    Third, it is well known that international standards are defined in Paris: the internationnal skirts lenght association, the general contest of retreat speed and the cheese-smelling index are all defined in my city and everybody agrees with that. M. Sarkozy has just battled staunchly with M. Puttin to assert our rights on those essential fields.

    Finally, I suspect that the kilogramme may be re-defined in October 2007 in Paris (http://fr.wikipedia.org/wiki/Kilogramme): a meeting of the Bureau Internationnal des Poids et Mesures (BIPM, Internationnal Weights and Measures Bureau in French) is scheduled this year.

    Best kisses from Earth.

    --
    I am not Remy Mouton, unfortunately: http://remy.mouton.free.fr/art/
  40. Re:"perfect" sphere by CensorshipDonkey · · Score: 2, Informative

    As if a billion devices around the world couldn't do the same thing.
    If this was true, there would be no reason for a standard in the first place, would there? Why don't you read a little about the ideas behind the work.
  41. Re:"perfect" sphere by hal2814 · · Score: 2, Funny

    A friend with a boob job? This is Slashdot so you're obviously not talking about a female (I'll ignore the "her" and assume it's a typo.). Who got the boob job? Is his name Robert Paulson?

  42. Too complicated! by Muad'Dave · · Score: 2, Interesting
    We've got a precise definition of the second:

    the duration of 9,192,631,770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium-133 atom.
    and the meter:

    the distance traveled by light in absolute vacuum in 1/299,792,458 of a second
    Why not tie the kg to the second and meter via the Newton? 1 Newton is defined as 1 kg * m * s^-2. Using centripetal force in a plane normal to the earth's gravitational field eliminates gravity from the equation.
    --
    Tiller's Rule: Never use a word in written form that you've only heard and never read. You will end up looking foolish.
  43. Re: Using the Sphere of One-ness by Migraineman · · Score: 4, Interesting

    Worse - you can't touch the Sphere of One-ness with anything.

    Q: May I put my greasy paws on it?
    A: No. Fingerprints will alter the mass in a measureable way.

    Q: White gloves?
    A: Abrasive.

    Q: Use a special cradle that's machined to exactly the same radius profile such that you won't scratch or deform the Sphere of One-ness?
    A: Nope. That'll result in a molecular interference fit. You'll never get the two pieces apart.

    So ultimately, they're building a very precise bauble that no one will ever be allowed to touch. I suspect that bouncing photons off the surface may displace an atom or two, so they'll keep it in a dark room ... in a vacuum chamber ... at the bottom of a flight of stairs, in a disused lavatory with a sign on the door reading "prendre garde du léopard."

  44. But the real question is... by SixArmedJesus · · Score: 2, Funny

    Does it look and feel like the real thing? /Sili-what? oh.

    --

    *slight crashing sound*
  45. The Perfect Sphere by egyptiankarim · · Score: 2, Funny

    They should be careful with this thing. I heard that if you go inside it, it will give you the ability to manifest your thoughts into reality! Usually situations like that just end up with giant squids attacking your underwater science labs.

    --
    Eek!
  46. Repercussions by Tabernaque86 · · Score: 2, Insightful

    If they redefine the kilogram, what happens to coefficients that rely on kilograms? For example, for the equation for Universal Gravitational Energy [G=(coefficient)(m1xm2)/d^2)], is the coefficient going to change?

  47. Re: Using the Sphere of One-ness by gardyloo · · Score: 2, Insightful

    Haha. Love the Douglas Adams reference. Such a lead-in, too!

        Seriously, though, photons of anywhere near visible frequencies won't displace the atoms; light bouncing is almost always a purely electronic transition thing. And if this thing is ultrapure silicon, atoms are NOT going to want to displace. No worries there.

  48. Re:isotopes by Tom+Womack · · Score: 2, Interesting

    The 'special crystal which took three years to grow in Russia' that the article writes about is made of pure silicon-28 precisely to get around this objection.

    I think the concern is that samples of silicon from different sources (consider, for example, 'depleted silicon' from the scrapyard of the Russian isotope-enrichment facility) might have different isotope distributions at the 10^-7 level, whilst good laser enrichment can ensure a really very constant isotope distribution.

  49. Re:don't need to create it to define it by AlecC · · Score: 2, Insightful

    And you are you going to determine if you have x atoms? It will take a long time to count them out. That is the point of this project: to create an object, the sphere, whose number of atoms is known as precisely as possible. If it is a perfect sphere, its volume is precisely known. And if the crystal spacing of silicon is known (which it is, very well), then you have a very precisely known number of silicon atoms. This means that you have a macro-scale object, suitable for use in a balance or equivalent, whose mass is known in terms of unique natural substance rather than an arbitrary lump.

    --
    Consciousness is an illusion caused by an excess of self consciousness.
  50. Where's the photographer? by TropicalCoder · · Score: 4, Interesting

    The picture shows a beautiful shot of the perfect silicon sphere. Out of curiosity, I looked very closly at the scene reflected by it's surface, thinking perhaps I might get a glimpse of the photographer. However, he was nowhere to be seen.

    Then I got to thinking - it should be easy to reconstruct the scene that is portrayed in the reflection from the surface of the sphere. All that is needed is to cut out the image of the silicon sphere and paste onto the surface of a three dimensional sphere. Then we could rotate it this way and that and look around the scientist's lab. So I did this - using a software simulation. I cut out the silicon sphere from the article's photo, and used it as a texture on a spherical 3D mesh, and added a little code to rotate it back and forth so that I could look around the scientist's lab. Guess what - there is no sign of the photographer! What we see is a very messy lab, with a closed door on the right. There are florescent fixtures on the ceiling that are currently turned off. There is a large window at the end of the room. I do believe that the ceiling, though it meets the left wall at the usual 90 degree angle, curves down to the wall at the right - a very unusual space, as if it was crammed into to an attic. At the extreme right of the room I believe we see a curtain hastily thrown over whatever would have been on the right side of the view. If the photographer is in the room, as he must be, I think he must be kneeling to the left of the window about three-quarters of the way back, and using a telephoto lens.

    I have made available the exe that I created on my web site so that you may take a look for yourself. The code is a hasty adaptation of Microsoft's DX3D mesh tutorial "Tut_06Meshes" from the DxSDK 9.0, which is also included. You can get the zip package here. Perhaps you could modify the code to produce an even better view, but unfortunately, the resolution of the original image is really too low to get much out of it. It was a lot of fun doing this, and if you come up with a better result than me I would like to hear from you.