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Three Largest Stars Identified

mOoZik writes "BBC News is reporting that astronomers have identified the three biggest stars known to science, having diameters of more than 1.5 billion km. If they were located in the same place as our own Sun - at the centre of the Solar System - the stars would stretch out further than the orbit of Jupiter!"

47 of 354 comments (clear)

  1. The three widest stars? by gbulmash · · Score: 3, Funny
    The three largest stars with huge diameters? That's easy... Louie Anderson, Bruce Bruce, and Roseanne.

    Thanks folks, I'll be here all week. Try the veal.

    - Greg

    1. Re:The three widest stars? by tuxter · · Score: 2, Funny

      Don't forget john holmes... he was a HUGE star.

  2. just wondering by adamruck · · Score: 3, Interesting

    Why wouldn't these huge starts turn into black holes?

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    1. Re:just wondering by roseblood · · Score: 3, Informative

      Large dosen't mean heavy. LARGE RED stars are going to be very thin, not much density. All of their material will be spread out over quite a large area. A LARGE BLUE star on the other hand, would be quite dense (and short lived...they burn their fuel much faster and die in billiant novas, or if they are TOO heavy, as blackholes.)

      --
      There are lies, damned lies, and statistics.
    2. Re:just wondering by Anonymous Coward · · Score: 2, Insightful

      And the Green and Yellow stars have the best chance of finding inhabitable planets. Unless of course you are the Silicoids, in which case you can colonize anywhere.

    3. Re:just wondering by albn · · Score: 3, Informative

      Why wouldn't these huge starts turn into black holes? This URL may help you

      According to the web site: A star of 15 solar masses exhausts its hydrogen in about one-thousandth the lifetime of our sun. It proceeds through the red giant phase, but when it reaches the triple-alpha process of nuclear fusion , it continues to burn for a time and expands to an even larger volume. The much brighter, but still reddened star is called a red supergiant. Betelgeuse , at the shoulder of Orion, is the best-known example. Absolute luminosities may reach -10 magnitude compared to +5 for our sun.

      Some of these supergiants are unstable and form the very important Cepheid variables. In their final stages, supergiants may explode into supernovae . The collapse of these massive stars may produce a neutron star or a black hole .

      --
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    4. Re:just wondering by Phil+Urich · · Score: 2, Interesting

      ah, apparently you beat me to it. That's pretty much the point; speaking of, that's why our sun won't be going supernova, right? My knowledge is a bit far in the past, now, but I remember learning at some point that the eventual fate that our Sun will endure, ie. swelling out into a red giant or something of that like, then shrinking down and simmering out its final cold years as a white dwarf, is entirely related to exactly that: it's a medium density star, thus it will last a rather average time, and end "not with a bang, but a whimper".

      Ah, Sol, bastion of mediocrity. Without which, of course, conditions wouldn't've let us live so comfortably on this rock!

      --
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    5. Re:just wondering by Nogami_Saeko · · Score: 4, Informative

      And for some more black-hole info:

      Black Hole FAQ

      And on a side note, it's been a long time since I've watched my DVD of "The Black Hole", so I may have to do that now :). The last time I watched it, I was surprised how dark it was (no pun intended) for a "Disney Movie". May also have explained why I liked it so much as a kid...

      N.

      --
      "Nothing strengthens authority so much as silence." - Charles de Gaulle
    6. Re:just wondering by Sterling+Christensen · · Score: 2, Interesting

      Can a star really be that thin? Doesn't its own gravity dictate a minimum density to maintain that volume?

    7. Re:just wondering by tm2b · · Score: 2, Informative

      Light pressure and the heat of fusion.

      Stars don't become black holes until they burn up their fuel, collapsing (and perhaps exploding, perhaps even multiple times) in on themselves until they are much more dense than any visible stars. Then, assuming they they haven't blown off so much of their mass that they no longer have enough mass and will instead become a dwarf or a neutron star, they can collapse to become a black hole.

      Link: HOW BLACK HOLES ARE FORMED

      --
      "It is our blasphemy which has made us great, and will sustain us, and which the gods secretly admire in us." - Zelazny
    8. Re:just wondering by roseblood · · Score: 5, Informative

      YES, they can be that thin.

      If I may be lazy and just give you a URL:
      http://www.astronomynotes.com/evolutn/s5.htm

      --
      There are lies, damned lies, and statistics.
    9. Re:just wondering by techno-vampire · · Score: 3, Interesting

      Alas, there are no green stars. Even if their temperature is such that their radiation peaks there, green has such a narrow band of frequencies that either yellow or blue will always predominate.

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    10. Re:just wondering by LuxFX · · Score: 2, Interesting

      ditto! I have always been curious and dissappointed about the lack of pretty emerald stars.

      fortunately, since moving to the midwest (Kansas City) and seeing the sun set over flat land instead of the mountains where I used to live, I have now seen sunsets with discernable green bands in them. That was my other hope for green.

      Now, if I can just witness a green flash sometime....

      --
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    11. Re:just wondering by physicsphairy · · Score: 4, Insightful
      This is a bit reverse logic, but the reason they don't collapse is because they're still burning.

      You can think of the fusion reaction in a sun as it's 'defense' against collapse. The force driving the future collapse, gravity, is what's sustaining the fusion reaction, which creates internal photonic pressure, which in turn pushes the mass of the star outward, counteracting the force of gravity.

      The reason these stars are so large is in fact directly related to the photonic pressure produced by this reaction. If the gases are very hot it prevents the gas from codensing, i.e., you need a lot of it (a big star) to combat gravity. Once these go supernovae and leave clouds of elements that burn at a lower temperature, smaller stars will be able to form.

    12. Re:just wondering by SandmanWAIX · · Score: 5, Funny

      supernovae . The collapse of these massive stars may produce a neutron star or a black hole .

      For a detailed example of supernovae -> black hole, click here.

    13. Re:just wondering by Eccles · · Score: 2, Funny

      Can a star really be that thin?

      Yes, but only if it gets lots of sleep.

      --
      Ooh, a sarcasm detector. Oh, that's a real useful invention.
    14. Re:just wondering by coyote-san · · Score: 3, Informative
      Stars don't become black holes until they burn up their fuel, collapsing (and perhaps exploding, perhaps even multiple times) in on themselves until they are much more dense than any visible stars.

      You might want to check university pages, not just some guy's geocities page.

      Stars collapse once the core has exhausted its available fuel. This is only a minute fraction of the star's total mass, but it's critical. When the core goes dark the rest of the star falls on it.

      According to an article in Discover magazine a few years ago, parts of the star will fall towards the center with a speed as high as a third of the speed of light! This causes enormous pressure, during the "big crunch" the density of the star may be 5-6 higher than the density of a neutron star. IIRC the massive neutrino flux is produced at this time. BTW this "core" is substantially far larger than the core mentioned earlier.

      Matter can't be compressed this hard for long and the core "bounces" back. That is what flings the outer layers of the star into space. But force goes both ways - what throws stellar masses into space also increases the pressure on the remaining core. If the density gets too high a black hole is created and it quickly consumes the core, but the outer layers have already been ejected. Otherwise the core eventually bounces back entirely and you have a neutron star. A neutron star is a core of degenerate matter covered by a layer of normal matter.

      You do not get cycles of explosions.

      (I seem to recall hearing about flares on neutron stars after enough normal mass has fallen to trigger fusion, but those flares are fall smaller than supernovas.)

      --
      For every complex problem there is an answer that is clear, simple, and wrong. -- H L Mencken
    15. Re:just wondering by jnik · · Score: 2, Informative

      > certainly more massive
      Correct.

      > probably just as dense (if not denser
      Incorrect, both in the sense of mean density and in the sense of the density of most of the star.

      > they are much, much hotter
      Incorrect.

      > the bigger a star is, the hotter it must be to
      > equilibriate
      The more massive a star is. Not bigger. The discussion is big in terms in volume. And it's only hotter while it's on the main sequence/during the hydrogen burning phase.

      > contrary to what you might expect, the bigger a
      > star is, the shorter its lifetime is, since it
      > has to consume its fuel so much faster.
      True for values of bigger==more massive.

      See e.g. Carrol and Ostlie, chapters 10 and 13.

      > So to answer your question, the reason these
      > stars don't become black holes is the same as
      > the reason that any supermassive stars don't.
      There is no "reason these stars don't become black holes." They likely are becoming black holes. The reason they aren't black holes is because they haven't gotten there yet. In the global sense, the black hole is a much, much lower energy state than a cloud of hydrogen, so it takes a long time to blow off all that energy.

      > The only difference with these is that they burn
      > their fuel much faster than other stars,
      > and correspondingly, can be expected to snuff it
      > much sooner.
      Correct.

      > I might be wrong about some of this, but I'm
      > pretty sure most of what I said is true, at
      > least to a first approximation.
      Um, better luck next time? :) You also lose points for not mentioning the Eddington limit, which is just so damn cool it should be mentioned in any discussion of stellar dynamics, even if it's not actually explained. (Eta Carinae, you're the one...)

      Qualification: I'm a PhD candidate in astronomy. So, although astrophysics isn't my field, I at least know my stuff well enough to pass my comps.

  3. Visible black holes? by Dancin_Santa · · Score: 2

    The mass of these stars must be outrageous. Could it be possible that they are already black holes that we are able to see only because we are already within the event horizon of the stars' gravitational pulls?

    1. Re:Visible black holes? by roseblood · · Score: 2, Insightful

      You know, large dosen't mean heavy. A Peacock feather is alot larger than my wedding ring. My wedding ring is (slightly) heavier though.

      --
      There are lies, damned lies, and statistics.
    2. Re:Visible black holes? by mOoZik · · Score: 2, Informative

      It seems they were able to measure temperature and luminance, thus making them red [super]giants.

    3. Re:Visible black holes? by cavetroll · · Score: 3, Insightful

      no. The mass of the stars is big, but they are very far away.

      Consider:

      density of sun = ~1400 kg/m^3

      let us assume these stars have the same density (they don't, it will be lower, but that is ok for our purposes here)
      diameter 1.5 billion km = 1.5E12 m

      volume (assume a perfect sphere) = 4/3 pi r^3 ~ 1.8E36 cubic metres
      giving a mass of 2.5E39Kg (about 1 billion times that of the sun)

      the gravitational field strength on an object obeys an inverse square relationship
      F=GM/r^2
      The nearest of these stars is 5200 light years away, or 5E19 metres
      G is the universal gravitational constant, about 7E-11

      so
      F=7E-11 * 2.5E39 / (5E19*5E19)
      F~ 1E-10 N/kg

      for comparison, the gravitational field strength on earth is about 10 N/kg, ie 100 billion times larger. /me waits for someone to point out an error in my arithmatic

  4. I'd like to announce the official... by The+Ultimate+Fartkno · · Score: 4, Funny

    ..."Name Three Fat Women In Entertainment" thread right here. Skill points will be deducted for all mentions of Delta Burke, Oprah, and Anna Nicole Smith. You have thirty seconds from the time you read the headline and pounced on the "reply" button.

    Go.

  5. My only wish by nihilogos · · Score: 2, Funny

    Is that at least one giant goes supernova in my lifetime. I don't think that's too much to ask

    --
    :wq
    1. Re:My only wish by sTalking_Goat · · Score: 2, Funny

      You might be in luck. I hear the Vogons have got a contract for another Interstellar Overpass...

      --

      My days of not taking you seriously are certainly coming to a middle...

    2. Re:My only wish by daeg · · Score: 3, Funny

      Dear nihilogos: We're sorry, but all intelligent designers are currently assisting other beings. Your request will be tended to in the the order that was receieved. The current wait time is: /pause/ 3 billion years. Please hold.

    3. Re:My only wish by NormalVisual · · Score: 2, Informative

      Already happened, back in March of 1987 in the Large Magellanic Cloud in the Southern Hemisphere. Sure, it was 100K light years away, but it's still pretty substantial.

      --
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  6. Solist! by IcEMaN252 · · Score: 4, Funny

    Don't be so ethnocentric. There are such things as trinary systems.

    --
    CitrusTV (http://www.citrustv.net): the Nation's Oldest & Largest Entirely Student-Run Television Station
  7. Betelguese! Betelguese! Betelguese! by Ralph+Spoilsport · · Score: 2, Interesting
    they had a picture of Betelguese! there, but only the vaguest idea as to when it's supposed to blow.

    Anyone heard ahything that way?

    I've heard anything from tomorrow afternoon to 2 milion years. I've heard it's been getting increasingly variable since 1940.

    If it goes supernova (and it's WAY big enough) what would be the results here? Genetic disorders? Extinction? Has anyone done the math on this?

    RS

    --
    Shoes for Industry. Shoes for the Dead.
  8. Non Red Giants by bobobobo · · Score: 2, Interesting

    It would be interesting to find the largest non-red giant stars. As once our own sun turns into a red giant, it's radius is supposed to extend out past Jupiter as well.

    1. Re:Non Red Giants by mOoZik · · Score: 3, Informative

      Actually, it will engulf the first three planets, but not extend to Jupiter.

    2. Re:Non Red Giants by helioquake · · Score: 2, Informative

      Well, that may not be true, either, according to the article I read about a decade ago:

      ApJ article (1993): Our Sun III

      Oh gosh, I referenced ApJ in /. What have I done?

    3. Re:Non Red Giants by Feztaa · · Score: 2, Funny

      Actually, it will engulf the first three planets

      Pfffft, good riddance I say.

  9. Saturn too... by tigersaw · · Score: 2, Informative

    This puppy would actually eclipse Saturn, whose mean orbit is about 1.43 billion km.

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    In Soviet Russia, all our base are belong to you!
  10. No worry -- the world will not end by helioquake · · Score: 5, Informative

    Don't worry about it. These giants are big, but not necessarily massive enough to go supernova at the end of their lives.

    Besides, hypothetically, even if it were to explode like a supernova, it won't affect us much. Here is the number:

    d = distance to the closest giant (5200light-yr)
    E = total energy arising from supernova (1e51erg or something like that)

    The energy receied at the Earth is

    E / (4 *pi *d*d).

    Now compare this number with the energy we receive every second from the Sun:

    E_sun / (4 * pi * r*r)

    where r is the distance between the Earth and the Sun (1.5e13 cm). You do the math, then the ratio of these two quantities comes out to be:

    [E/(4*pi*d*d)] / [E_sun/(4*pi*r*r)] ~ 2.4

    So all we get from this supernova is about 2 seconds worth of energy received from the Sun. And I'll tell you that the actual energy received from the supernova is much, much smaller.

  11. Imagine a cluster of stars... by Anonymous Coward · · Score: 2, Funny

    ... and the astronomers name it the Beowulf Cluster.

  12. Largest? by marevan · · Score: 3, Interesting

    Correct me if I'm wrong, but isn't red giants dencity pretty low? So when a star transforms into a red giant, it's bound to get much larger. So wouldn't it be cooler to find actually non-dying star of this magnitude?

    (Well definetly not cooler)

  13. If they were located in the same place by frovingslosh · · Score: 4, Funny
    If they were located in the same place as our own Sun - at the centre of the Solar System - the stars would stretch out further than the orbit of Jupiter!"

    Shows what little they know. If they were located in the same place as our own Sun, Jupiter would burn up and not have an orbit!

    --
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  14. More info for the non-physics folk... by TiggertheMad · · Score: 5, Informative

    Several other posts have danced around the question a little bit, without answering it directly. It's a good question.

    While these stars are big, filling a large volume of space, the article doesn't mention their mass. This is the ultimate determinant of what becomes a black hole and what doesn't.

    Stars have gravity trying to pull everything into the center off it's mass. In physics pressure is basically equal to temapture, so as all the mass is squezed together, it heats up and begins nuclear fission. This creates a lot of heat, and the star's mass tries to expand. Gravity and pressure find a happy meidum and that is how the star ends up a particular size.

    As the star burns it's fuel, it has to get hotter or it will stop 'burning', due to the way nuclear fusion works. Eventually it will burn up its fuel and prssure will not balance gravity, and the whole star will collapse. If it is really heavy, say several times the mass of the sun, it will probably collapse into a black hole. If it is slightly heavier than our sun, it might end up as a very dense neutron star. Otherwise, it will end up as a white dwarf, a small star that is somewhat like a ember left over after a campfire. If a star is really massive it can also explode in a supernova to lose some weight and avoid becomming a black whole.

    As I mentioned, the article doesn't say what the mass of the star is, but it's probably a safe bet that is above the black hole limit. When it finishes burining its fuel, it will likely go supernova and/or become a black hole.

    --

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    1. Re:More info for the non-physics folk... by Kugelfang · · Score: 3, Informative

      You're wrong in two points:
      a) Turning into a black hole is determined by
      mass/radius ratio. You could even turn out sun
      into a black hole by "somehow" ( :-) ) pushing
      its radius below the Schwarzschild radius.
      b) "it heats up and begins nuclear fission."
      -> You mean "fusion", as fusion needs heated-up
      gas (plasma) to start. Fission is what happens
      in nuclear power plants ;-)

    2. Re:More info for the non-physics folk... by DeusExLibris · · Score: 2, Informative

      Excellent post!

      A couple of clarifications and references to excellent books on black holes:

      First, not all stars reach equilibrium. Cepheid variables oscillate between small and dense states and large and diffuse states. This happens because the star cannot reach a steady state balance between pressure and temperature.

      Second, it is interesting to note that sun like stars below the Chandrasekhar limit (about 1.4 solar masses) will turn into white dwarfs. The pressure in these stellar remnants is provided not by heat from fusion, but from electron degeneracy pressure (as another poster pointed out). Neutron stars (1.4-3 solar masses) are supported by neutron degeneracy pressure. Beyond this (>3 solar masses) there is no force that can keep the star from collapsing on itself, leading to a black hole.


      Two excellent books on black holes are:

      Black Holes by J-P Luminet
      Black Holes and Time Warps by Kip Thorne

  15. Wrong Units by willpall · · Score: 4, Funny

    "1.5 billion km across" means nothing to me. How many Libraries of Congress could the star hold?

    --
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  16. Thanks for the tip! by po8 · · Score: 2, Funny

    If they were located in the same place as our own Sun - at the centre of the Solar System...

    So that's where I left it!

  17. Re:Big planets... by gardyloo · · Score: 2, Informative

    I'm sure that someone who keeps up on the latest astronomical findings could give a better answer than I, but: No.

    I doubt that there's much of a correlation between larger stars and larger planets orbiting them. The tricky thing about extrasolar astronomy is that we simply can't detect "normal" (i.e. non-gas-giant, although their prevalence might say that gas giants are actually normal, and rocky planets like the earth are maybe unusual) planets around other stars right now.
    As far as I know, extrasolar planets are really only detected (or detectable, right now) in two ways: 1) find a star's wobble which can't be explained by visible objects. From the wobble and the mass of the star (extrapolated from its color, generally), calculate that there must be a planet of some size orbiting it. But to wobble a typical star takes a pretty big planet: an uber-Jupiter, especially if you want this wobble detectable from earth; 2) find that once in a while, several pixels on a CCD's image of the star get occluded by something transiting the star. Again, this takes something of considerable size.

    There is a wikipedia article (at http://en.wikipedia.org/wiki/Extrasolar_planet with many more details, and disproving my guess that there are only two currently-used methods which have produced reasonably-confirmed planet detections -- pulsar timing methods have also seemed to work) which is relatively concise and nice.

  18. Re:Farther than the orbit of Jupiter by ine8181 · · Score: 2, Informative
    I'm sorry to post completely off-topic, but just to answer the comment, an excerpt from Chambers dictionary;

    • Use either farther or further when there is an actual physical distance involved I can't walk any farther / further.
    • Use further when the meaning is 'additional' or 'beyond this point' I would like to make one further point.
  19. Not very dense by hpa · · Score: 2, Insightful

    Red supergiants may be large, but their density have been described by e.g. Larry Niven as "red-hot vacuum." At least their outer layers are very tenuous at best. Given that the masses are typically only a few orders of magnitude more than the Sun, at most, but that their volumes are enormously much bigger, there can't be that

    This means (surface) gravity is low and they can get by with less hydrostatic pressure to maintain their bulk.

    The *core* is typically very dense, much denser than the Sun. Higher pressures are needed to support fusion of higher-order elements. Makes the surface layers even less dense, since a lot of the mass is still in the core.

  20. No ! by Professeur+Shadoko · · Score: 2, Funny

    The right unit is: (pick one)
    1/Furlongs
    2/Light-Fortnight