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Claimed Proof of Riemann Hypothesis

An anonymous reader writes "Xian-Jin Li claims to have proven the Riemann hypothesis in this preprint on the arXiv." We've mentioned recent advances in the search for a proof but if true, I'm told this is important stuff. Me, I use math to write dirty words on my calculator.

345 comments

  1. Dirty Words by Rik+Sweeney · · Score: 5, Funny

    Me, I use math to write dirty words on my calculator.

    Such as 80085?

    1. Re:Dirty Words by Anonymous Coward · · Score: 5, Funny

      5318008

    2. Re:Dirty Words by G-forze · · Score: 1, Offtopic

      That would be "58008".

      --
      "There's someone in my head but it's not me." - Pink Floyd, Dark Side of the Moon
    3. Re:Dirty Words by bigstrat2003 · · Score: 1, Offtopic

      No, it'd be "5318008".

      --
      "16MB (fuck off, MiB fascists)" - The Mighty Buzzard
    4. Re:Dirty Words by UnknowingFool · · Score: 5, Funny

      No, you mean 5318008 or for the slashdot crowd, 55378008

      --
      Well, there's spam egg sausage and spam, that's not got much spam in it.
    5. Re:Dirty Words by Directrix1 · · Score: 4, Funny

      No for the slashdot crowd it would be: 58008uÉÉ . Because obviously we all have calculators that support unicode text entry.

      --
      Occam's razor is the blind faith in the natural selection of least resistance and in universal oversimplification. -- EF
    6. Re:Dirty Words by Directrix1 · · Score: 5, Funny

      That would've been a lot cooler if Slashdot supported Unicode.

      --
      Occam's razor is the blind faith in the natural selection of least resistance and in universal oversimplification. -- EF
    7. Re:Dirty Words by Archangel+Michael · · Score: 4, Funny

      On linux, wouldn't it be ...

      host:>man 80085

      ???

      --
      Agent K: A *person* is smart. People are dumb, stupid, panicky animals, and you know it.
    8. Re:Dirty Words by Trails · · Score: 0, Offtopic

      You fail at boobies.

    9. Re:Dirty Words by Firehed · · Score: 4, Funny

      At that point, isn't it safe to assume that our calculators can just draw a pair of boobs in 2-bit greyscale?

      And that we've written apps that simulate what we assume bouncing would look like given our collective lack of experience outside of the pornographic realm?

      --
      How are sites slashdotted when nobody reads TFAs?
    10. Re:Dirty Words by 8ball629 · · Score: 0, Offtopic

      No, he said he uses math to do it so I'm sure it's something more like...

      80084 + 1 = 80085

    11. Re:Dirty Words by JayJay.br · · Score: 2, Funny

      Newbie...

      correct spelling is "5318008" and you have to look at the calculator "umop apisdn"

      Mod me down, I dare you!!!

    12. Re:Dirty Words by rubah · · Score: 1

      Luckily the numerals 0, 8 and 5 are three of five that look exactly the same even upside down in liquid crystal notation.

      You can continue to turn your calculator 180 degrees, but why bother when you can be reaching into your pants. . . Or wherever mathnerds reach :O
      (inside of gabriel's horn moarlike)

    13. Re:Dirty Words by 0100010001010011 · · Score: 1, Funny

      I had proof of concept Porn on my TI-89 in 2000.

    14. Re:Dirty Words by StikyPad · · Score: 4, Funny

      You haven't grafted a color TFT screen to your calculator yet?

      Who let these guys in?

    15. Re:Dirty Words by ultranova · · Score: 1

      And that we've written apps that simulate what we assume bouncing would look like given our collective lack of experience outside of the pornographic realm?

      Why assume, when you can just calculate it using soft-body kinetics ?

      --

      Forget magic. Any technology distinguishable from divine power is insufficiently advanced.

    16. Re:Dirty Words by andy19 · · Score: 5, Funny

      Coming from a Slashdotter, are you surprised?

    17. Re:Dirty Words by Anonymous Coward · · Score: 2, Informative

      Hold the calculator upside down, mod-who-didn't-get-the-joke...

    18. Re:Dirty Words by JrOldPhart · · Score: 1

      Maybe (.)(.)

      or even (o)(o)

      --
      Nothing is foolproof, fools are too ingenious. - Murphy
    19. Re:Dirty Words by madsenj37 · · Score: 1

      What is an SBOOB?

      --
      Choosing the lesser of two evils is a choice for evil.
    20. Re:Dirty Words by droopycom · · Score: 5, Funny

      You just gave me the best idea for an iPhone app:

      Boobies that bounce according to how the phone is bouncing....

    21. Re:Dirty Words by hyperion454 · · Score: 3, Funny

      One of those guys must have been Gene Simmons.

    22. Re:Dirty Words by DFENS619 · · Score: 5, Funny

      Your ideas are intriguing to me and I wish to subscribe to your newsletter.

    23. Re:Dirty Words by Anonymous Coward · · Score: 0

      Slashdot would prefer 904753.

    24. Re:Dirty Words by acklenx · · Score: 1
      ...Apparently they did. I don't think the moderators noticed Cmdr Taco's comment

      Me, I use math to write dirty words on my calculator.

      Nothing but flamebait and offtopic points

      --
      Never let a mediocre career stand in the way of a good time
    25. Re:Dirty Words by Andor666 · · Score: 3, Funny

      äOEæ--¥é..."ããï¼ï¼

    26. Re:Dirty Words by david.given · · Score: 2, Funny

      Nah, if you really want a dirty word, try 71077345...

    27. Re:Dirty Words by DMUTPeregrine · · Score: 1

      TI-92 kama sutra I remember a TI-89 version, with 7-level greyscale as well.

      --
      Not a sentence!
    28. Re:Dirty Words by Firehed · · Score: 1

      Damn shame that Jobs-o doesn't want porn in the app store. Make it a jailbreak app and I'll hold off my upgrade.

      --
      How are sites slashdotted when nobody reads TFAs?
    29. Re:Dirty Words by CDMA_Demo · · Score: 0

      all she needs is chuck norris.

    30. Re:Dirty Words by h2k1 · · Score: 3, Interesting

      in portuguese, 50135.50738 (nice breasts).

    31. Re:Dirty Words by drinkypoo · · Score: 1

      Your calculator isn't a dual-core (or better) laptop that already has color TFT?

      What year is this?

      --
      "You're right," Fisheye says. "I should have set it on 'whip' or 'chop.'"
    32. Re:Dirty Words by Anonymous Coward · · Score: 0

      Yeah, but what good is the answer without the problem?

      Dolly Parton weighed 69 pounds.
      That was 2 2 2 much.
      She wanted to weigh 51.
      So she went to doctor X and took 8 pills.
      She ended up....

    33. Re:Dirty Words by Anonymous Coward · · Score: 0

      Dan Vasser, is that you??

    34. Re:Dirty Words by Anonymous Coward · · Score: 0

      ( o Y o )

    35. Re:Dirty Words by PachmanP · · Score: 4, Funny

      Link?

      Does your project have donation page?

      --
      You're thinking small. Why miniaturize the laser, when we could instead enlarge the sharks? -John Searle
    36. Re:Dirty Words by Anonymous Coward · · Score: 0

      This guy beat you to the punch: http://linearlabs.net/jigglesfortheiphone/

    37. Re:Dirty Words by DaFallus · · Score: 1

      Something like this?

      --
      No one cares what your captcha was

      Houston TX, USA
    38. Re:Dirty Words by Fred_A · · Score: 1

      On linux, wouldn't it be ...

      host:>man 80085

      ???

      And on 8 bit machines it was "POKE 80085"...

      Hours of fun to be had by all. (sigh)

      --

      May contain traces of nut.
      Made from the freshest electrons.
    39. Re:Dirty Words by regular_gonzalez · · Score: 1

      Did you seriously think this hadn't already been done?

      --
      Due to circumstances beyond my control, I am master of my fate and captain of my soul.
    40. Re:Dirty Words by JayJay.br · · Score: 1

      You know, I can get over the "offtopic" moderation, since it is offtopic. But flamebait??? Flamewars about the spelling of "boobies" in a calculator? How exciting!!

    41. Re:Dirty Words by tzot · · Score: 1

      That's not Unicode, that's ISO8859-1. And, for some strange reason, with your "OE" there, I think you wanted to have the "Latin capital ligature OE" character, which does not belong to ISO8859-1.

      --
      I speak England very best
    42. Re:Dirty Words by Directrix1 · · Score: 1

      Shit I had it in my TI-85 in '96.

      --
      Occam's razor is the blind faith in the natural selection of least resistance and in universal oversimplification. -- EF
    43. Re:Dirty Words by Directrix1 · · Score: 1

      Dude that is fucking awesome. Haha.

      --
      Occam's razor is the blind faith in the natural selection of least resistance and in universal oversimplification. -- EF
    44. Re:Dirty Words by Andor666 · · Score: 1

      I've written the Unicode characters relative to the japanese word "futsukayoi" (meaning "hangover"). In any moment it changed that way :P ;)

    45. Re:Dirty Words by yaDad · · Score: 1

      or 55378008. thats the one my dad showed me when i was about 8 yrs old.

    46. Re:Dirty Words by aliquis · · Score: 1

      I wanted to reply with this earlier but wasn't logged in and couldn't be bothered:

      6502.

      Hands of the Tac-2!

  2. I like to describe my workplace with my calculator by InvisblePinkUnicorn · · Score: 2, Informative

    37047734

  3. Yeah but did they point this out? by i_want_you_to_throw_ · · Score: 5, Funny

    By using Fourier analysis on number fields, we prove in this paper E. Bombieri's refinement of A. Weil's positivity condition, which implies the Riemann hypothesis for the Riemann zeta function in the spirit of A. Connes' approach to the Riemann hypothesis. Weather permitting of course. (Just looking on the positivity side)

    1. Re:Yeah but did they point this out? by rdwald · · Score: 5, Funny

      By using Fourier analysis on number fields, we prove in this paper E. Bombieri's refinement of A. Weil's positivity condition, which implies the Riemann hypothesis for the Riemann zeta function in the spirit of A. Connes' approach to the Riemann hypothesis.

      Weather permitting of course. (Just looking on the positivity side)

      I thought you were randomly babbling, but then I RTFA and realized you were just quoting it...

    2. Re:Yeah but did they point this out? by colonslashslash · · Score: 5, Funny

      Wait... both of you RTFA?

      We have a new /. record!

      --
      She's built like a steak house, but she handles like a bistro....
    3. Re:Yeah but did they point this out? by paazin · · Score: 1

      There's no 'article' as far as I see, only the paper: http://arxiv.org/PS_cache/arxiv/pdf/0807/0807.0090v2.pdf

    4. Re:Yeah but did they point this out? by StikyPad · · Score: 4, Funny

      Not so fast. I read it -2 times.

    5. Re:Yeah but did they point this out? by KC7GR · · Score: 1

      Or, to put it another way -- Mice got loose in the laundry room.

      --

      Bruce Lane, KC7GR,

      Blue Feather Technologies

    6. Re:Yeah but did they point this out? by jd · · Score: 4, Funny

      I imagined I read it, so that's +i.

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    7. Re:Yeah but did they point this out? by Anonymous Coward · · Score: 2, Funny

      I read half of TFA...so that's 1/2 + i, which just happens to be on the critical line.

    8. Re:Yeah but did they point this out? by StikyPad · · Score: 4, Funny

      Come on, be real.

    9. Re:Yeah but did they point this out? by LrdDimwit · · Score: 1

      You need to lay off the thiotimoline, man.

    10. Re:Yeah but did they point this out? by kramulous · · Score: 1

      But if your child read it your family contribution is -1

      --
      .
    11. Re:Yeah but did they point this out? by Tatarize · · Score: 1

      And here I read it e^((pi)*i) + 1 times.

      --

      It is no longer uncommon to be uncommon.
    12. Re:Yeah but did they point this out? by knutert · · Score: 1

      The fact that the author uses "we" gives me a warm and fuzzy feeling of being included in the work...

    13. Re:Yeah but did they point this out? by TheVelvetFlamebait · · Score: 1

      Wait, wait, wait. We don't exactly have proof that the OP RTFA...

      --
      You know, there is a difference between trolling and pointing out the flaws in your reasoning. Just saying.
  4. Tried to RTFA by multipartmixed · · Score: 5, Funny

    Man, where's Charles Eppes when you need something explained to you in layman's terms?

    --

    Do daemons dream of electric sleep()?
    1. Re:Tried to RTFA by Notquitecajun · · Score: 4, Funny

      Ummm...I think that WAS layman's terms. For you math geeks, try being a history major and looking at all that. It just looks like a cat walked on the keyboard to me...

    2. Re:Tried to RTFA by PlatyPaul · · Score: 5, Informative

      The Riemann zeta function is \zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^{s}} [written for LaTeX], or "the sum of 1/(n^s) as n goes from 0 to infinity (increasing by 1 repeatedly)" [in more human-readable form].

      Riemann was interested in the zeros to this function, where s is a complex number. He conjectured that all zeros (aside from those of the form s = -2c, where c is a positive integer) would have to be of the form (1/2) + ki, where k is a constant and i is the square root of -1.

      This paper is saying that they've found a way to verify this intuition by patching a hole in a previous attempt.

      Assuming that everything is correct (a big assumption), this would finally solve a long-standing problem (dating back to 1859).


      Details of the actual solution are a bit heavy. Those actually interested in this sort of number theory might want to start here.

      --
      Misery loves company. Online misery loves unsuspecting random strangers.
    3. Re:Tried to RTFA by stranger_to_himself · · Score: 5, Funny

      Ummm...I think that WAS layman's terms. For you math geeks, try being a history major and looking at all that. It just looks like a cat walked on the keyboard to me...

      Are you reading slashdot as some kind of anthropological study?

    4. Re:Tried to RTFA by Frankie70 · · Score: 2, Funny

      It's like 50 football fields laid in line from here to Riemann.
      Rieman sounds like a place in Germany.

    5. Re:Tried to RTFA by Frankie70 · · Score: 1

      Ok - can you now explain it in layman's terms?

    6. Re:Tried to RTFA by Notquitecajun · · Score: 1

      Heck, no. Do you KNOW how anal retentive anthropologists can get (particularly archaeologists?)? Ugh.

      No, I get half the geek jokes and enjoy the political discussions here - the balance here on politics is a bit more educated than most other places. I like Star Wars, too. Han shot first and all that. Huzzah!

    7. Re:Tried to RTFA by Notquitecajun · · Score: 2, Funny

      Okay...I would ask WHY this is important, but someone is ponying up a million bucks for the solution. THAT tells me this is important. I'm not sure if I care why...

    8. Re:Tried to RTFA by jd · · Score: 1

      I wanna LaTeX renderer for Firefox! Aaaaaargh!

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    9. Re:Tried to RTFA by geekoid · · Score: 1

      Look, what the laymen wants to know is "What does it Do" or "What does it mean"

      I piroved 2 + 2 = 4.
      What does that mean? it means when you ahve two of something, you can take another two, and then you will ahve four.

      They don't want to see:

      4/2 = 2

      For the case in hand:
      It's important because it has been believed to be true for years, and mathematicians have used it for other stuff..
      It also helps understand the distribution of primes.
      And the number one reason for it's importance is:
      Whomever proves it, gets a million bucks.

      I am no a professional mathematician, so maybe I'm wrong about it's meaning.

      --
      The Kruger Dunning explains most post on /. http://en.wikipedia.org/wiki/Dunning%E2%80%93Kruger_effect
    10. Re:Tried to RTFA by JohnsonJohnson · · Score: 5, Informative

      It's important because the zeros of the zeta function tell you how the prime numbers are distributed and prime numbers are to number theory as elements are to chemistry, everything you could care about is built out of them. The RH is also related to host of other more esoteric, but no less important conjectures; the truth of a large part of modern mathematics relies on knowing if the RH is true or false.

      Although it's unlikely to impact the storage capacity of a flash drive any time soon the zeta function shows up in high energy physics and thus does have real world consequences.

    11. Re:Tried to RTFA by PlatyPaul · · Score: 2, Interesting

      Here's another easy-to-grasp one: public key encryption (think: credit card purchases online) is dependent upon the use of large primes. Large primes are currently not the easiest/fastest to find - what if you knew better where to look for them?

      --
      Misery loves company. Online misery loves unsuspecting random strangers.
    12. Re:Tried to RTFA by the+phantom · · Score: 1

      Hey! I resemble that remark!

      Anyway, I stopped using toothpicks years ago while excavating. Now I use a toothbrush! And you have the audacity to call me anal retentive. :(

    13. Re:Tried to RTFA by Notquitecajun · · Score: 1

      Is it a clean toothbrush for every new artifact? Sorry, I did some archaeological technician work (aka Digging) for a few months, and the desire for the perfect 1mx1mx1m square hole was....interesting. WAY TOO INTERESTING.

    14. Re:Tried to RTFA by ConceptJunkie · · Score: 1

      I have the Andrews book listed on the "Buy these two for cheaper" link, but I got totally hung up on the Chinese Remainder Theorem about 8 years ago. Time to give it another go I think.

      If I didn't already believe in God, Number Theory would convince me. It's that cool. ;-)

      --
      You are in a maze of twisty little passages, all alike.
    15. Re:Tried to RTFA by the+phantom · · Score: 1

      Honestly, excavation never exited me that much. I prefer survey. However, in terms of excavation, provenience is everything -- if you don't know where something came from, it has less meaning. Thus, archaeologists are as anal about their 1 meter units (or even smaller units) as chemists are about their titrations (or whatever chemists do).

    16. Re:Tried to RTFA by Anonymous Coward · · Score: 0

      This article, and the book you've linked to, have finally put my interest in this sort of thing over the hump to really feeling like researching into it.

      Several of the reviewers on the book on Amazon suggest they enjoyed/learned from the book having come out of undergraduate mathmatics classes, a background I do not have. Do you have other suggestions on entry level books or communities/forums where I could start to self/group-teach in this area?

    17. Re:Tried to RTFA by Anonymous Coward · · Score: 1, Insightful

      Th thing is - how does the riemann hypothesis help with that? You could just _assume_ it before it was proved ?!

      I've never worked out how to make breaking crypto easier with a proved riemann hypothesis. That's not to say it isn't relevant. But does the riemann hypothesis speed up factorisation? Certainly not directly, though techniques used in its proofs and attempted proofs have been relevant (number fields, duh).

    18. Re:Tried to RTFA by Anonymous Coward · · Score: 0

      Riemann was interested in the zeros to this function, where s is a complex number. He conjectured that all zeros (aside from those of the form s = -2c, where c is a positive integer) would have to be of the form (1/2) + ki, where k is a constant and i is the square root of -1.

      I think it might be good to point out that "the zeroes to this function" means, the values of s (such as s=-2c) for which the the Z function = 0.

    19. Re:Tried to RTFA by Anonymous Coward · · Score: 0

      I am no a professional mathematician, so maybe I'm wrong about it's meaning.

      You are no a professional writer either.

      Also, your sig is wonderful.~

    20. Re:Tried to RTFA by obliv!on · · Score: 1

      I think there is some 'Charlie Vision' about Riemann in this episode:
      Numb3rs Season 1 Episode 105 - "Prime Suspect"

    21. Re:Tried to RTFA by drinkypoo · · Score: 4, Funny

      Thus, archaeologists are as anal about their 1 meter units (or even smaller units) as chemists are about their titrations (or whatever chemists do).

      Last time I tried to get anal with my 1 meter unit, I damned near killed someone.

      --
      "You're right," Fisheye says. "I should have set it on 'whip' or 'chop.'"
    22. Re:Tried to RTFA by soliptic · · Score: 1

      Joking I know, but FWIW I'm another "history major" (as you'd have it over that side of the pond). I've been reading Slashdot since about 98. At the time I was doing a-levels in history, English and computer science - trying to write a sci-fi RTS in Pascal instead of the dry database normalisation coursework, etc. Hence the geek link.

      I ended up following history to university, not computer science, but on graduation got into web development (a longstanding hobby), since the job market is rather more flush than "historian". So nowadays CSS/ASP/PHP/SQL/JS/RSS/IIS/TLA/ETC are a regular part of my job. And while I don't generally do all the real hardcore functional-OOP-XP-git-jvm-type programming stuff, I can keep up with it in the same sort of way I keep up with Hawking's popular science books. "Right, I suppose I can't claim to understand it, truly; but I don't not understand it..."

      I think there's a slashdot tendency to assume/generalise everyone here is geeky/techy/IT so has a maths/science background. So I thought I'd pop up and add a little visibility to the "nope, history major here" poster. My maths education stopped at 16 ("high school"). But I've still soley opened this Riemann story above any other on Slashdot tonight, because even if I don't really grasp the 1% of it, I still read XKCD and Stephenson, damnit, and this sort of thing is way cooler and more interesting than the next [RI|MP]AA story with a bunch of tedious hypocrites re-explain why it's OK to pirate entertainment because it sucks so much they don't even want to pirate its sucky ass, for the fifty trillionth time ;-)

      Worse, there's a definite tendency to mock and disparage degrees from the "arts" side of things. Personally, I think my history studies were one of the most enormously valuable things I've experienced. In terms of teaching you to apply critical scepticism to the words and actions of politicians, media, corporations, etc via means such as deconstructing language, considering the medium, separating fact from agenda, objectivity from subjectivity, evaluating the source provenance, weighing bias, etc, and having a broadly cross-disciplinary approach incorporating economics, sociology, psychology, politics, linguistics, philosophy, etc... I'd say it's practically an invaluable life skill for existence in this crazy information-overloaded, media-rich and doublespeak-rich 21st century.

      But I guess that's another whole (increasingly offtopic) post in itself.

    23. Re:Tried to RTFA by Hotawa+Hawk-eye · · Score: 1

      One reason that knowing whether or not the Riemann Hypothesis is true is that there are a large number of other theorems that have been proven with the assumption that the Riemann Hypothesis is true. If RH was proven false, then we'd need to come up with other proofs for those theorems, or consider that perhaps those theorems that we'd thought to be true were in fact not.

    24. Re:Tried to RTFA by Garridan · · Score: 2, Informative

      JSMath.

    25. Re:Tried to RTFA by Walkingshark · · Score: 2, Funny

      Great. Here comes the "intelligent arithmetic" movement.

      --
      The world you experience is only a close approximation of reality.
    26. Re:Tried to RTFA by knutert · · Score: 1

      Rieman sounds like a place in Germany.

      Maybe because Riemann was from Germany?

    27. Re:Tried to RTFA by stranger_to_himself · · Score: 1

      Thanks for posting, that was interesting. I have a lot of respect for humanities and classics, and I regret not studying them at school. It's also a shame that our commercially motivated government doesn't seem to value any education that doesn't contribute directly to your value in the jobs market.

      ..and this sort of thing is way cooler and more interesting than the next [RI|MP]AA story with a bunch of tedious hypocrites re-explain why it's OK to pirate entertainment because it sucks so much they don't even want to pirate its sucky ass, for the fifty trillionth time ;-)

      That was quite nicely put.

    28. Re:Tried to RTFA by assert(0) · · Score: 0

      Nope, sorry. k is not a constant. If you're going to explain really obscure maths to a lay audience at least get your facts straight. The hypothesis is that the nontrivial zeros are located on the critical line sigma = Re[s] = 1/2.

      --
      (founded 95,000,000 yrs ago, very space opera)
    29. Re:Tried to RTFA by soliptic · · Score: 1

      Thanks for posting, that was interesting. I have a lot of respect for humanities and classics, and I regret not studying them at school.

      Yeah I suppose it would have been nice of me to note I wasn't aiming any of that at you personally in any way - just your post struck some note and made me hang that ramble off it, not putting you in that "mock liberal arts degrees" boat, that's just a general thing I've noticed over the years here.

    30. Re:Tried to RTFA by Notquitecajun · · Score: 1

      I mock 'em too. I'm in a financial field (interestingly enough, an analyst), and for some reason my big-picture methodology helps with what I do. I didn't go further in history partially because of burnout, partially because of desire, and partially because I didn't want to have to move every 2-3 years because I was hunting for tenure in a place I didn't want to live.

      I got into /. because my wife is the computer geek, into coding and all that. I just happen to like sci-fi and politics.

    31. Re:Tried to RTFA by ConceptJunkie · · Score: 1

      Hey, just you wait until we find a message hidden in pi, like in "Contact" (the book, wasn't in the movie), then you'll change you're tune!

      --
      You are in a maze of twisty little passages, all alike.
    32. Re:Tried to RTFA by ConceptJunkie · · Score: 1

      As soon as I pushed "Submit" I saw "You're tune"

      I, er, uh, was going to say, um, "You're too nice!" Yeah, that's the ticket!

      p.s. Dear Slashdot: 15 seconds and 1 minute for the "Slow Down, Cowboy!" timers would eliminate 98% of the times I get that infuriating message. C'mon, howzabout it? Some of us can type fast; stop penalizing us!
      --
      You are in a maze of twisty little passages, all alike.
    33. Re:Tried to RTFA by show+me+altoids · · Score: 1

      Since Pi has an infinite number of digits, any message you want will have to be in there somewhere. That is, unless I am getting my Alephs confused.

      --
      I feel sorry for people that don't drink, because when they get up in the morning, that's as good as they're gonna feel
    34. Re:Tried to RTFA by Guignol · · Score: 1

      you are getting your Alephs confused.
      divide 1 by 3

  5. Dolly parton bought a size 69 bra by larry+bagina · · Score: 1, Funny

    but it was 222 small. So she took 51 pills, 8 times a day, and ended up...

    --
    Do you even lift?

    These aren't the 'roids you're looking for.

    1. Re:Dolly parton bought a size 69 bra by u38cg · · Score: 1

      The version I learnt as a kid: There was a girl of 13, who had a bust of 84. She wanted to make it 45, so she went to the doctor. 0, he said. Take these pills 2 times a day - instead she took them four. Of course, she ended up...

      --
      [FUCK BETA]
    2. Re:Dolly parton bought a size 69 bra by Anonymous+Cowpat · · Score: 1

      Does that make me the only person who remembered how "boobless" is spelt and just typed 55318008 into the calculator when they wanted something to snigger at?

      --
      FGD 135
    3. Re:Dolly parton bought a size 69 bra by bigstrat2003 · · Score: 1

      Pardon me for asking, but what the heck are you two talking about? I can't figure it out.

      --
      "16MB (fuck off, MiB fascists)" - The Mighty Buzzard
    4. Re:Dolly parton bought a size 69 bra by somersault · · Score: 1

      It's about making rude words on an upside down calculator. I'm not sure what numbers and operators they're pressing either.

      --
      which is totally what she said
    5. Re:Dolly parton bought a size 69 bra by cyriene · · Score: 1

      I learned the story "There is 1 girl who is 16 years old and has done it 69 times with 3 guys. How does she feel?" so it looks like: 11669*3= now turn the calculator upside down to see how she feels...

  6. $1,000,000 prize to be collected then if true by deft · · Score: 4, Informative

    Was reading wikipedia because I have no idea why this is important, but need to know enough to impress my friends (and by that I mean, alienate).

    But I noticed this is such a big deal, theres a cool million waiting for the person that proves it. John Nash in "beautiful Mind" tries to prove this one too. Sorry gladiator... not today!

    So yeah, Check it out, notice the offer at the end, after all the completely unintelligible mathematicrap:

    Riemann hypothesis

    The Riemann hypothesis (also called the Riemann zeta-hypothesis), first formulated by Bernhard Riemann in 1859, is one of the most famous and important unsolved problems in mathematics. It has been an open question for almost 150 years, despite attracting concentrated efforts from many outstanding mathematicians. Unlike some other celebrated problems, it is more attractive to professionals in the field than to amateurs.

    The Riemann hypothesis (RH) is a conjecture about the distribution of the zeros of the Riemann zeta-function (s). The Riemann zeta-function is defined for all complex numbers s 1. It has zeros at the negative even integers (i.e. at s = 2, s = 4, s = 6, ...). These are called the trivial zeros. The Riemann hypothesis is concerned with the non-trivial zeros, and states that:

    The real part of any non-trivial zero of the Riemann zeta function is ½.
    Thus the non-trivial zeros should lie on the so-called critical line, ½ + it, where t is a real number and i is the imaginary unit. The Riemann zeta-function along the critical line is sometimes studied in terms of the Z-function, whose real zeros correspond to the zeros of the zeta-function on the critical line.

    The Riemann hypothesis is one of the most important open problems of contemporary mathematics, mainly because a large number of deep and important other results have been proven under the condition that it holds. Most mathematicians believe the Riemann hypothesis to be true.[1] A $1,000,000 prize has been offered by the Clay Mathematics Institute for the first correct proof.[2]

    --

    There's nothing Intelligent about Intelligent Design.
    1. Re:$1,000,000 prize to be collected then if true by rufty_tufty · · Score: 5, Informative

      Good explanation here too:
      http://www.irregularwebcomic.net/1960.html

      --
      "The weirdest thing about a mind, is that every answer that you find, is the basis of a brand new cliche" -
    2. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 4, Insightful

      The Riemann hypothesis is considered the most important unsolved problem in math. But, considering the source here (random paper on ArXiv by complete unknown), there's no real reason to believe this paper is correct. The number of incorrect proofs to major mathematics problems every year is staggering.

    3. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Oh, and this summary of the Riemann hypothesis somewhat obscures its true importance: it is equivalent to a very strong statement about the distribution of prime numbers. For example, the CS paper from a few years ago that gave a deterministic algorithm to check if a number was prime depended on the Riemann hypothesis for some of its results.

    4. Re:$1,000,000 prize to be collected then if true by Mr.+Sketch · · Score: 1, Informative

      I briefly looked through the proof, and it only claims to be a proof in the rational number field, not for all real numbers. It's still a step in the right direction, but not a full proof.

    5. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Basically the hypothesis tries to explain where all prime numbers lie along the number line, all the way to infinity. So it would be pretty important if there is a proof for it.

    6. Re:$1,000,000 prize to be collected then if true by olyar · · Score: 1

      John Nash in "Beautiful Mind" tries to prove this one too.

      One of the things I remember from the book is that he and his wife had a running joke that all babies know the solution to this problem and then forget it when they learn to talk. Maybe Xian-Jin Li had a flashback.

      --
      Custom, hands-free Linux installs. Instalinux
    7. Re:$1,000,000 prize to be collected then if true by nwf · · Score: 1

      That is probably the best explanation I've seen, thanks! And it makes use of LEGO, another plus!

      --
      I don't know, but it works for me.
    8. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      My GOD, that is a good explaination... now that I've read it I suddenly get the Riemann Hypothesis.

      Hmmm... This is the start of a very bad trend for me as a /. user.

    9. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Why is the Riemann hypothesis important?

      The Riemann hypothesis has a deep connection with prime numbers and proving it will help prove other theorems related to the distribution of prime numbers. This will help make finding the prime factors of large numbers practical and make many widely used cryptographic techniques almost trivial to break. So if the theorem has been proved (unlikely) we could be in for a bit of trouble...

    10. Re:$1,000,000 prize to be collected then if true by olyar · · Score: 1
      Ahh - here's where it came from:

      Paul Erdos once said all babies (he used to call them epsilons, because babies are really small!) remember the solution for Riemann Hypothesis. The only problem though is that they tend to forget everything once they reach the age of six month.

      Found that here

      --
      Custom, hands-free Linux installs. Instalinux
    11. Re:$1,000,000 prize to be collected then if true by UnknowingFool · · Score: 4, Funny

      I looked at the proof and have absolutely no idea what it said. But in the finest slashdot tradition, I WILL have opinions here shortly. Abrasive, loud, and irrefutable ones

      --
      Well, there's spam egg sausage and spam, that's not got much spam in it.
    12. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 5, Informative

      No. Every number field has its own zeta function. The standard Riemann hypothesis concerns that of the rationals.

    13. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      The Riemann Zeta function is the zeta function corresponding to the rational number field, thus it would really prove RH. Do you even know, what a number field is?

    14. Re:$1,000,000 prize to be collected then if true by Lundse · · Score: 1

      Was reading wikipedia because I have no idea why this is important, but need to know enough to impress my friends (and by that I mean, alienate).

      Story of my life...

      --
      IAIFARSIJDPOOTV - I Am In Fact A Reality Star; I Just Don't Play One On TV
    15. Re:$1,000,000 prize to be collected then if true by camperdave · · Score: 1

      http://www.irregularwebcomic.net/1960.html

      Great! Now how am I supposed to get any work done.

      --
      When our name is on the back of your car, we're behind you all the way!
    16. Re:$1,000,000 prize to be collected then if true by A+beautiful+mind · · Score: 2, Funny

      John Nash in "beautiful Mind" tries to prove this one too.

      And I would have succeeded if it weren't for these meddling kids! What do you mean you can't see them?!

      --
      It takes a man to suffer ignorance and smile
      Be yourself no matter what they say
    17. Re:$1,000,000 prize to be collected then if true by afidel · · Score: 1

      Flashbacks to babyhood, that reminds me of another outstanding film, the directors cut to The Butterfly Effect. If you haven't seen it I highly recommend it though it's definitely not for people who cry easily or women who have lost a child!

      --
      There are 4 boxes to use in the defense of liberty: soap, ballot, jury, ammo. Use in that order. Starting now.
    18. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      You mean a polynomial time algorithm for primality, since deterministic algorithms for it are trivial but slow (given n, check that n%k != 0 for all k, 1<k<n). The algorithm you're thinking of in "PRIMES is in P" was unconditionally polynomial time, and all the Riemann hypothesis did was give a better bound on when the algorithm would terminate so that they could prove it was something like O(n^6) instead of O(n^12).

    19. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0
    20. Re:$1,000,000 prize to be collected then if true by somersault · · Score: 2, Funny

      Do you even know, what a number field is

      It's where they grow new numbers, right?

      PS: Do you, even, know: how to use correct punctuation?1!?!?!?

      --
      which is totally what she said
    21. Re:$1,000,000 prize to be collected then if true by Cowculator · · Score: 2, Informative

      No, you're wrong because you have no idea what you're talking about. Every number field has its own zeta function which roughly describes the distribution of prime ideals in that field, and the Riemann zeta function is the one corresponding to the rational field. The Riemann hypothesis states that the Riemann zeta function (that is, the one for the field of rational numbers) has no zeros whatsover, rational or otherwise, on the critical strip 0 < Re(s) < 1 except along the line Re(s) = 1/2, and this is exactly the statement he's claiming to have proved.

    22. Re:$1,000,000 prize to be collected then if true by elguillelmo · · Score: 1

      John Nash in "beautiful Mind" tries to prove this one too. Sorry gladiator... not today!

      Amazingly enough the actual (and deranged) Nash claimed he had. It'd have been the greatest among his great achievements.

      --
      Dawkins Revisited: A person is shit's way of making more shit -- Steve Barnett, anthropologist.
    23. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      No, he's only working with the rational number field but indeed claims to prove the conjecture. The comment about other number fields is related to a generalization of zeta functions.

    24. Re:$1,000,000 prize to be collected then if true by IllForgetMyNickSoonA · · Score: 1

      I second that recommendation, a truly good movie! However don't watch the director's cut, for it's a rather un-convincing and generally considered worse than the "regular" version. Besides, it's a rip-off of the Donnie Darko.

    25. Re:$1,000,000 prize to be collected then if true by rrohbeck · · Score: 1

      Too heavy for me.
      I stopped at "We can also split apples (and dollars) into smaller pieces, like half an apple, or a hundredth of a dollar."

    26. Re:$1,000,000 prize to be collected then if true by MiniMike · · Score: 4, Funny

      Step 1: Find 5-month old baby.
      Step 2: Interrogate baby from step 1, asking questions relevant to the Riemann Hypothesis.
      Step 3: Profit!

      Progress so far:
      Step 1: Complete.
      Step 2: Complete. Reply to question consisted of: "Blah gurgle <splursh> gah hwooo naaae".
      Step 3: Incomplete, but I have reduced the problem from one of Mathematics to one of Linguistics. I expect results soon.

    27. Re:$1,000,000 prize to be collected then if true by LeafOnTheWind · · Score: 1

      Fuck a $1,000,000? That's NOTHING compared to the implications. Let's see if I can simplify this. For context let me just state that some of the most brilliant mathematicians in the world spend their entire lives studying this hypothesis.

      However, as a cryptographer I am interested in an especially important part - if the Riemann hypothesis can be extrapolated, it can possibly be used to factor very very large numbers by tracing the primes in the Riemann zeta function. If you look it up, you'll find that the Riemann zeta function is interesting in how it predicts the distribution of primes in the reals. The implications for factoring are very simple.

      RSA is based on factoring.

      The most commonly used public-key encryption algorithm is highly dependent on factoring. If the solution can be extrapolated, RSA could be broken. This is earth-shattering. I can't even express the kinds of ramifications that could take place if someone managed to reduce factoring to a polynomial time solution.

      Now, even if the hypothesis has been solved, there is no guarantee that it can be used for factoring or that a polynomial time algorithm could be created. Still... it's getting a little too close for comfort for me.

    28. Re:$1,000,000 prize to be collected then if true by TheDreadSlashdotterD · · Score: 1

      Why not waterboard the baby? That'll teach it to speak in gobbly-gook!

      --
      I have nothing to say.
    29. Re:$1,000,000 prize to be collected then if true by Daffy+Duck · · Score: 1

      I'm going to have to call "bullshit" on this one. For a very long time now, mathematicians have been banging away at plenty of problems using the assumption that the Riemann hypothesis is true. Suddenly justifying this assumption doesn't really affect anything practical.

    30. Re:$1,000,000 prize to be collected then if true by halsver · · Score: 1

      If you skip down in the article past the really long discussion of number theory (imaginary numbers, which if you made it past umm the 10th grade is probably doable) and to the discussion about the Rieman function, the author sums it up very well. Probably helps if you know basic Calculus ideas like summations and limits, but he may have explained that too...

      Good article.

      --
      Roughly half my comments are never submitted. You may be reading the better half...
    31. Re:$1,000,000 prize to be collected then if true by LandDolphin · · Score: 1

      I liked the darker ending on the DVD versus the happier ending released to theatres.

      --
      Spelling and Grammar errors have been added to this post for your enjoyment
    32. Re:$1,000,000 prize to be collected then if true by LandDolphin · · Score: 1

      It justifies the work that they've based off the Riemann hypothesis

      --
      Spelling and Grammar errors have been added to this post for your enjoyment
    33. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 2, Informative

      Ahem, Xian-Jin Li has a mathematical criterion named after him: http://en.wikipedia.org/wiki/Li%27s_criterion

    34. Re:$1,000,000 prize to be collected then if true by obliv!on · · Score: 1

      Well Arxiv isn't the wikipedia not everyone can post to it at their leisure. Based on this list just from Arxiv: http://arxiv.org/find/math/1/au:+Li_X/0/1/0/all/0/1
      I'd say he has to be reasonably legitimate, even if he's wrong he's breaking new ground with what is apparently at the very least a solid attempt.

    35. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Umm... Li isn't a complete unknown. He's written 21 papers in the field, and invented "Li's Criterion", which is known to be equivalent to the Riemann Hypothesis. Moreover, he's working on one of the more promising recent ideas about how to approach the RH. (That said, if I were a Vegas oddsmaker, I wouldn't rate his chances of being correct too highly.)

      Moral: Next time RTFA before you speak up. Dipshit.

    36. Re:$1,000,000 prize to be collected then if true by pdovy · · Score: 1

      While you're right to be wary of the correctness of this proof, this guy at least has some credibility. He's got a PhD in math and works at a university (can't seem to figure out if he's actually a professor), and he seems to have published frequently in the past. Hopefully even if it is incorrect it will add something to our understanding of the problem.

    37. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      The RH is the rational number field case. He's saying that the technique works for generalized RH.

    38. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      complete unknown

      Not true.

    39. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      This guy is not a complete unknown. In 1997, he presented an interesting condition that is completely equivalent to the Riemann Hypothesis. Look up Li's Criterion on Wikipedia. His work has been cited in papers by mathematicians working at the Institute for Advanced Study at Princeton.

    40. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      The Riemann hypothesis is considered the most important unsolved problem in math.

      What about P = NP? Well, actually, that's more of a computer science-ish (or applied mathematics if you prefer) problem. Then again, given the average /. user, it's more relevant for us anyways...

      Hmm... CAPTCHA's astute?

    41. Re:$1,000,000 prize to be collected then if true by Torvaun · · Score: 1

      Sure it does. Like looking at blueprints to a car, and deciding that it would work. Now someone actually builds a car, and, aside from proving that it works, he can now road trip, and see all the attractions. For Riemann, these attractions are primes that would take a long time to get to otherwise.

      --
      I see your informative link, and raise you a pithy comment.
    42. Re:$1,000,000 prize to be collected then if true by coolsnowmen · · Score: 1

      yeah, cause that movie needed to get darker...
      How many scenes where a dog in a bag is tortured do I really need to see? (don't answer)

    43. Re:$1,000,000 prize to be collected then if true by FLAGGR · · Score: 1

      Computer Science C Math
      That C is an inclusion sign.

    44. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0
    45. Re:$1,000,000 prize to be collected then if true by LandDolphin · · Score: 1

      HahA...

      That made me laugh out loud. But yeah, it was a dark movie, but that's why I felt it needed a dark ending. A happy ending to a dark movie just feels "hollywood" or make believe.

      --
      Spelling and Grammar errors have been added to this post for your enjoyment
    46. Re:$1,000,000 prize to be collected then if true by Garridan · · Score: 1
      No, you're wrong because you have no idea what you're talking about.
      1. The only prime ideal in a field is {0}. [wiki]
      2. The field of rational numbers is purely real. So the "line Re(s) = 1/2" is really a point.

      So what are you talking about? Q(i)? That's a field over which zeta has nontrivial roots, yes. There are plenty of prime ideals in Z , is that what you meant?

    47. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Don't for get their dog, and the meddling policemen.

    48. Re:$1,000,000 prize to be collected then if true by SimonGhent · · Score: 1

      but need to know enough to impress my friends (and by that I mean, alienate)

      Cool. I thought it was just me who did that.

      Finally, I'm not alone. Want to start a newsletter?

      --
      simon
    49. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      What? Actually, ArXiv is *precisely* like Wikipedia, and anyone *can* post to it at their leisure. This is why it's so fishy that this paper is first appearing discretely on ArXiv with no serious publicity.

    50. Re:$1,000,000 prize to be collected then if true by Anonymous Coward · · Score: 0

      Not exactly a "complete unknown." Wikipedia states that he's responsible for Li's criterion and is a student of Louis de Branges de Bourcia.

    51. Re:$1,000,000 prize to be collected then if true by Cowculator · · Score: 1

      Reading some articles on Wikipedia doesn't make you an expert.

      1. The "prime ideals in that field" refers to the prime ideals in the *ring of integers* in a number field, but people who actually know what they're talking about (not you) don't waste each other's time with those extra few words.

      2. The line Re(s)=1/2 is a line in the complex plane, which is where the Riemann zeta function (you know, the zeta function for the field of rational numbers) is defined. The fact that it relates to the rationals and encodes some information about them doesn't change the fact that it's a function from the complex numbers to itself.

  7. Reimann? by areusche · · Score: 5, Funny

    Reimann? Like the Noodles right?

    1. Re:Reimann? by Anonymous+Monkey · · Score: 4, Funny

      It's not just noodles. Its a way of life.

      --
      We are the Borg...
    2. Re:Reimann? by PlatyPaul · · Score: 0, Flamebait

      ::groan::

      That joke is nearly a year old online, and about 1000 if you've spent any time in a university math department.

      --
      Misery loves company. Online misery loves unsuspecting random strangers.
    3. Re:Reimann? by areusche · · Score: 0

      Honestly any time spent in a university math department can be best described as: âz

    4. Re:Reimann? by Anonymous Coward · · Score: 0

      Sure is.

      Damn you, OPEC!

    5. Re:Reimann? by Born2bwire · · Score: 1

      ... and about 1000 if you've spent any time in a university math department.

      Personally Paul, I try to avoid that as much as possible.

    6. Re:Reimann? by areusche · · Score: 0

      That was the infinite symbol that couldn't quite go through :(

    7. Re:Reimann? by PlatyPaul · · Score: 1

      Well, holy cow. Didn't expect you here.

      Although, on second thought, I guess I'm not surprised. heh.

      --
      Misery loves company. Online misery loves unsuspecting random strangers.
    8. Re:Reimann? by rpj1288 · · Score: 1

      I see you have been Touched.

      --
      Marvin knew: "Think of a number, any number..."
    9. Re:Reimann? by Anonymous Coward · · Score: 0

      No, like Tom Cruise and Dustin Hoffman. ;-)

    10. Re:Reimann? by Anonymous Coward · · Score: 0

      I believe it's spelled Raman. but that's a whole other(my) field.

    11. Re:Reimann? by Anonymous Coward · · Score: 0

      No, like Dustin Hoffman, you dolt.

  8. Hmmm.... by Otter · · Score: 5, Funny
    The only part of it I understood was:

    The author is grateful to J.-P. Gabardo, L. de Branges, J. Vaaler, B. Conrey, and D. Cardon who have obtained academic positions in that order for him during his difficult times of finding a job.

    Sounds about par for the course for academic hiring, and it sounds like he's still pretty traumatized from it. I hope this works out for him and he can go around flipping off all the hiring committees who turned him down.

    1. Re:Hmmm.... by Anonymous Coward · · Score: 2, Informative

      It's brutal trying to try to get into academia in a field that doesn't produce money. The sad thing is that departments want to hire more people but there is never any money or open positions and tenured professors hang onto their positions until they die. Things are a little better in physics than math, but not much (I am an experimental physicist).

      I had an undergraduate professor tell us endlessly to NOT go into physics, as it would make us miserable careerwise. I'm still in physics, but most of my friends are not, and I totally understand his point now. I had a history professor tell me that if he knew how hard it would be to get to where he was, he never would have been a history major.

    2. Re:Hmmm.... by Henry+V+.009 · · Score: 1

      And with all the competition, my school still can't hire any decent humanities professors. What's up with that?

    3. Re:Hmmm.... by Anonymous Coward · · Score: 5, Funny

      I had a history professor tell me that if he knew how hard it would be to get to where he was, he never would have been a history major.

      Well, that's all in the past now.

    4. Re:Hmmm.... by homesnatch · · Score: 1

      OH THE HUMANITIES!

    5. Re:Hmmm.... by Anonymous Coward · · Score: 0
  9. Math = $$ by RabidMoose · · Score: 5, Funny

    According to the http://en.wikipedia.org/wiki/Riemann_hypothesis wikipedia article, this means $1,000,000 if the proof turns out to be valid. Unfortunately, I didn't understand anything else in that article.

    1. Re:Math = $$ by JasterBobaMereel · · Score: 1

      He gets a million because a lot of modern mathematics assumes it is true but no-one can (so far) prove it ....

      It he is correct a lot of mathematicians breathe a huge sigh of relief

      If someone proves it is false then mathematics collectively panics and a lot of proofs will have to be re-written ...

      --
      Puteulanus fenestra mortis
    2. Re:Math = $$ by Kjella · · Score: 1

      Unfortunately, I didn't understand anything else in that article.

      The Riemann zeta-function is a function on the complex plane - the easiest explaination for that would be to say it takes a (x,y) value in and returns a (x,y) value as say on a graph. Basic things like addition and subtraction work like on a graph, multiplication is wierd like (0,1)*(0,1) = -1, or as they like to call the (0,1) unit i, that i^2 = -1. Now it's a function and we're looking for the values that give out zero. That is, zeta(x,y) = (0,0). There's a few trivial cases, but all the other cases have been for zeta(0.5,y) = (0,0) for various values of y. The proof is to show that all zeros must have x = 0.5, which is where it gets difficult. But if you've stayed with me so far, you've understood the problem.

      I'm not going to try to begin to describe the solution, not that I understand it myself. I don't think you could, even if you understood the whole paper. The main proof in the final sentence points to theorem 3.2, and that theorem isn't described by a formula only a sentence and says "Proof. It follows from theorem 3.1, (3.3) and the proof of Theorem 1 in Bombieri[2]." Ultimately most of these big proofs build on so many smaller proofs it'd take a book to get down to trivial concepts. Often you have one side coming "from" the conjencture like "If x, y and z holds the conjenture is true" and on the other side "In previous papers x and y have been proven, we now prove z and complete the proof". But if you just read the proof for z (like this piece), you start in nowhere and end up in nowhere because you just see the "missing link" in a chain of proofs.

      --
      Live today, because you never know what tomorrow brings
    3. Re:Math = $$ by Anonymous Coward · · Score: 0

      I think it is related with raving rabbits

  10. So what? by feijai · · Score: 3, Insightful

    arXiv has become the repository for junk that couldn't pass peer review. Wake me up when we see a published journal article.

    1. Re:So what? by 192939495969798999 · · Score: 1

      Also, the proof of something that complicated is likely so complicated that only the very best minds would even be able to prove that the proof was wrong.

      --
      stuff |
    2. Re:So what? by JambisJubilee · · Score: 5, Informative

      I think you misunderstand the scope and purpose of arXiv. arXiv is a repository for *preprints*.

      By uploading the file to arXiv before submitting it, not only do you ensure that those that can't afford $10,000+ subscription fees can access the article, but you open up your findings to a much wider international audience.

      The lack of peer review is not necessarily a liability in this situation

    3. Re:So what? by Anonymous Coward · · Score: 1, Interesting

      I would hardly consider Perelman's preprints to be "junk that couldn't pass peer review"

    4. Re:So what? by ceoyoyo · · Score: 1

      Yes, it certainly is. Lack of peer review means this proof could very easily be wrong. The grandparent quite rightly points out that "publication" in arXiv means nothing as far as the paper's credibility.

      arXiv is a great idea, but any paper you find there has to be taken with the same grain of salt as an un-reviewed paper published on someone's personal web site.

    5. Re:So what? by Anonymous Coward · · Score: 0

      No. arXiv is matematics for "first post".

    6. Re:So what? by khallow · · Score: 1

      Of course it has. It also has become the repository for good stuff that will take another six months to pass peer review and then another six months to couple of years to get published. OTOH, you make a very good point. Having as your only link this arxiv article seems a setup for another vapid slashdot puff piece. If it's newsworthy, there'd be real articles to link to.

    7. Re:So what? by twistedcubic · · Score: 1

      Not exactly. At least in math, almost everybody posts to the ArXiv now. Some journals allow you to submit papers for publication directly from the ArXiv. Grigori Perelman posted his papers (Poincare conjecture) on the ArXiv years ago. It's true that anything that reasonably looks like a research paper will get accepted into the ArXiv, but anything incorrect that draws attention is usually refuted. Moreover, you can't remove submissions from the ArXiv (but you can revise/retract), which provides an incentive to do careful research. There are a few other proofs of the Riemann hypothesis on the ArXiv (I recall one of only a few pages that was a fun read years ago). I wonder why people are so drawn to it, since it seems to be the hardest of the millenium problems.

    8. Re:So what? by twistedcubic · · Score: 1

      Peer-reviewed papers do commonly have errors. The cool thing about the ArXiv is you can make revisions anytime you want. The best thing about the ArXiv, from a researchers perspective, is that you don't have to wait 2-3 years to see publications on the state of the art.

      Even though anybody can put a paper on the ArXiv, there is an incentive to get things right. Take a look at this retraction of a proof of the Riemann hypothesis.

      http://arxiv.org/abs/math/0109072

      Notice that a link to the original article is given at the bottom. You can't remove submissions from the ArXiv, so whenever you submit an article, you risk having your errors online forever, which may be a good or bad thing, but it certainly makes people more careful.

    9. Re:So what? by ceoyoyo · · Score: 1

      They may have errors, yes, but peer reviewed papers have at least been vetted by experts in the field. As noted several times in these comments, proofs of the Riemann hypothesis show up frequently in ArXiv, but they don't make it through peer review. There may be incentive to make high quality submissions for most people, but particularly in this case, a guy who isn't very established (he's having trouble getting a job) could very well be a little overly enthusiastic.

      ArXiv is cool, no question, and a great tool for quickly advancing fields, but any given submission is much less likely to be correct in its essential details than a peer reviewed one. That's fine if you have the expertise to critically review the papers yourself but if you don't you have to keep in mind that nobody else has done so for you.

    10. Re:So what? by twistedcubic · · Score: 1


      That's fine if you have the expertise to critically review the papers yourself but if you don't you have to keep in mind that nobody else has done so for you.

      Why would anyone read a research paper uncritically? I think it's understood that when you reach the level of expertise required to read research articles, you always read them critically. You criticize the ArXiv as if it were a replacement for peer-reviewed journals. I've never met anyone who thinks this, and it was never meant to be. That is not a bad thing. The problems you mention are not problems at all.

    11. Re:So what? by obliv!on · · Score: 1

      Yeah, because no mathematician EVER reads arXiv!

      I mean it isn't like someone recently posted a paper there never published it and turned out to be correct. Oh wait that's exactly where Perelman posted his proofs and never got them published, yet they are probably one of the most reviewed documents on the site! Certainly more reviewed than they would have been if he had submitted it to ANY journal.

      I'm not saying this proof is correct, but it isn't fair to assume that because it isn't in a journal that it isn't. If you know it is incorrect then post a proof accordingly. Otherwise all we can do is wait and see.

    12. Re:So what? by ceoyoyo · · Score: 1

      Well, let's see. This story is posted on Slashdot. Slashdot has over a million registered accounts. How many of those users do you suppose have the expertise to read this paper critically?

      The poster to whom you replied suggested that a paper claiming a proof posted on an unreviewed preprint server probably wasn't a good reason to get excited. He's absolutely correct.

    13. Re:So what? by twistedcubic · · Score: 1

      So what's your point? Do you want to make the ArXiv a peer-review journal (which kills its uniqueness)? Do you think it should be eliminated? Or are you just complaining for the hell of it?

    14. Re:So what? by TheLink · · Score: 2, Insightful

      I doubt most have even got around to reading the paper. They're too busy thinking of ways to display boobies on their calculators.

      Just look at the above threads.

      --
    15. Re:So what? by PDAllen · · Score: 1

      Depends what field you work in. It certainly gets all the junk (there was someone claiming a poly-time algorithm for SAT recently...) but it also gets a lot of first-rate stuff that the author wants to get published right now, which he'll send to a journal later. If this guy (who at least seems to have got some help from some fairly big names, so presumably isn't a complete nut) is worried that maybe someone else might be working on the problem and getting results, then the natural thing to do is get it out ASAP.

      Assuming it's all right (not my field...) then it will go in a journal (assuming this guy is more normal than the last guy to solve one of these big conjectures: Perelman did just drop his paper on the ArXiV, and refused to publish in a journal or accept prizes). But it will not appear for a year or two, so it needs to be put up somewhere anyway.

  11. not so fast by Anonymous Coward · · Score: 5, Informative

    there are "proofs" of the Riemann hypothesis on the arXiv every few weeks. Don't believe it 'til it's vetted.

    1. Re:not so fast by Anonymous Coward · · Score: 5, Funny

      Yeah. arXiv once published my paper that shows cases where P = NP; I proved it conclusively for the cases where P = 0 and/or N = 1, but so far I haven't gotten my $1,000,000.00 check from the Clay Math Institute.

    2. Re:not so fast by Sheafification · · Score: 2, Interesting

      Indeed. Among some mathematicians it is a pleasant diversion to take bets on which of the major unsolved (or unprovable) problems has the most solutions appear on the arXiv this week.

    3. Re:not so fast by Anonymous Coward · · Score: 0

      That could be the funniest thing I've read here in a long time. It just clicked the right humor circuits in the ol gray matter.

      If I bothered to have an account (why sign up when you can lurk for 7 years?) I would give you points.

      Congrats to you, fellow AC.

    4. Re:not so fast by Kingrames · · Score: 3, Funny

      They sent you your checks for cases where you are equal to 0.

      Someone beat you to the "1" part.

      --
      If you can read this, I forgot to post anonymously.
    5. Re:not so fast by binpajama · · Score: 0

      Yeah. arXiv once published my paper that shows cases where P = NP; I proved it conclusively for the cases where P = 0 and/or N = 1, but so far I haven't gotten my $1,000,000.00 check from the Clay Math Institute.

      That's probably because you didn't put in the appropriate citations.

    6. Re:not so fast by xsadar · · Score: 1

      Ah, but what about when P approaches 0 and N approaches infinity? I didn't see that in your article. No million dollar prize for you.

      --
      The only thing I know is that I don't know anything; and I'm not even sure about that.
    7. Re:not so fast by Spy+der+Mann · · Score: 1

      Indeed. Among some mathematicians it is a pleasant diversion to take bets on which of the major unsolved (or unprovable) problems has the most solutions appear on the arXiv this week.

      I'd bet, but my equation to win big money at it requires the Riemann Hypothesis to be true.

    8. Re:not so fast by Neil+Strickland · · Score: 3, Interesting

      That's true, but most of them are obvious drivel. I have looked through this one, and it is clearly a real attempt by a genuine mathematician who understands the relevant background. I'd still bet on it being wrong, but not stupidly wrong.

    9. Re:not so fast by Anonymous Coward · · Score: 0

      How about pointing out what is wrong with the proof then?

    10. Re:not so fast by bugeaterr · · Score: 2, Funny

      there are "proofs" of the Riemann hypothesis on the arXiv every few weeks. Don't believe it 'til it's vetted.

      Who needs proof!

      Do like Al Gore and declare,

      "The debate on the Riemann Hypothesis is OVER!"

    11. Re:not so fast by water-vole · · Score: 1

      Most of the "proofs" that you talk about are by crackpots who have published almost nothing before. This guy has 21 publications according to mathscinet, some of which are in relatively prestigious journals. So we should take this a bit more serious than the RH proof spam on the arXiv that the parent talks about. That said, it has happened before that a well respected mathematician has announced a proof for the RH that has turned out to be false (de Brange comes to mind). So the jury is still out on this one.

    12. Re:not so fast by shanen · · Score: 1

      Why does Al Gore continue to grate so hard on you right-wing lunatics?

      Is it the Nobel Prize? Dubya's miserable failures? Or maybe just that the big dick Cheney told you to?

      If you want to drag Al Gore into it in a relative way, you need to show some creativity. Perhaps you can somehow link his Congressional support of scientific research to the direction of research so that the American researchers were busy developing email rather than working on the Riemann Hypothesis. Yeah, that's it. You need to blame Al Gore for the spam.

      --
      Freedom = (Meaningful - Coerced) Choice != (Speech | Beer^2), and sad sock puppets' bad mods avail them naught.
  12. Dolly Parton by jav1231 · · Score: 1

    Dolly Parton was 69 lbs over weight. The doctor said that's 222 much! You need to lose 51 x 8 days. That left her:

    6922251x8=55378008

  13. The continuum hypothesis will be next... by JuanCarlosII · · Score: 1

    First Fermat, now this. Is nothing sacred?!

    This is seriously disappointing news though. I've always appreciated the romance of such "theories", and now there's one less in the world. That and my planned deal with the devil to save my soul has now hit the rocks.

    1. Re:The continuum hypothesis will be next... by sm62704 · · Score: 3, Insightful

      First Fermat, now this. Is nothing sacred?!

      Money. Not much else these days.

      --
      mcgrew's razor: Never attribute to stupidity that which can be explained by greedy self-interest
    2. Re:The continuum hypothesis will be next... by hansraj · · Score: 5, Insightful

      The Continuum Hypothesis is known to be neither provable nor disprovable in the standard axiomatic set theory ZF, enriched with the axiom of choice (ZFC). So I wouldn't really count on someone settling that one either way any time soon. Of course one could come up with a new set of axioms for the set theory and *then* prove or disprove CH but you would be hardpressed to find anyone showing interest in that result. After all, I could just add CH or not(CH) to ZFC and trivially prove or disprove it. So anything in that line first needs to even define what a sensible problem is.

      For those who have no clue what I said above:

      Continuum hypothesis: There is no set strictly larger than the set of natural numbers and at the same time strictly smaller than the set of real numbers. The size of a set in relation to other is defined in terms of mapping. Positive integers are the same number as even numbers because you can define a bijection between the two. Reals are strictly more than naturals.

      ZF: Set theory made axiomatic. Few axioms (like empty set exists, supersets are larger than original sets etc) that you need to believe and most of the set theory believed to follow.

      Axiom of Choice: Given a set of sets, one can make a set containing one element from each set. Looks obviously true but in some equivalent but different sounding formulations looks obviously false. Known to be independent to ZF.

      Y Independent to axioms X: Believing that Y is true does not yield contradiction together with X unless X itself yield contradictions. Same holds for believing that Y is false.

      PS: Apologies for not including links. I am feeling lazy. Wikipedia has nice articles about all of the above. Articles on ZF, CH or Axiom of Choice are the place to start for a fun reading.

    3. Re:The continuum hypothesis will be next... by Anonymous Coward · · Score: 0

      Axiom of Choice: Given a set of sets, one can make a set containing one element from each set. Looks obviously true but in some equivalent but different sounding formulations looks obviously false. Known to be independent to ZF.

      Cannot be true. Try from {{A}, {}}.

    4. Re:The continuum hypothesis will be next... by Anonymous Coward · · Score: 0

      Of course one could come up with a new set of axioms for the set theory and *then* prove or disprove CH but you would be hardpressed to find anyone showing interest in that result.

      From my understanding, this is in fact what current research in CH tries to do. Something like: CH is generally believed to be true, and ideally we can add another independent axiom that is more obvious than CH, from which CH can then be proven.

    5. Re:The continuum hypothesis will be next... by Anonymous Coward · · Score: 0

      From here:

      Informally put, the axiom of choice says that given any collection of bins, each containing at least one object, it is possible to make a selection of exactly one object from each bin, even if there are infinitely many bins and there is no "rule" for which object to pick from each. The axiom of choice is not required if the number of bins is finite or if such a selection "rule" is available.

      As for the other links:

        Continuum Hypothesis

        ZFC

    6. Re:The continuum hypothesis will be next... by Anonymous Coward · · Score: 0

      The Aximon of Choice leads to some very tasty paradoxes like the Banach-Tarski Paradox.

    7. Re:The continuum hypothesis will be next... by Muhahahahaz · · Score: 1

      I love how I understood what you're talking about. :D I'm double majoring in Computer Science and Math right now, and Set Theory and Number Theory are two of my favorite things. Too bad the proof is probably still a little too complicated for me to understand. I'm definitely going to print it out thought. I'll see if I can read up on anything I don't know yet...

  14. Tough problems by dj245 · · Score: 3, Interesting

    Part of the reason these problems are so tough because to solve them, you have to understand what the problem is first. I studied the Riemann hypothesis in college for a good week and I'm still not sure where you might begin solving it. Like the Navier-Stokes equations (another big problem with a big prize) solving it will probably require the invention of some new mathematics. Its not simply a matter of dividing by 3 and carrying the 2. I don't know about you but I haven't the slightest idea about how to go about inventing new math. That's the realm of Newton and Einstein, and few others.

    New math is the only way to go about solving some of these problems.

    --
    Even those who arrange and design shrubberies are under considerable economic stress at this period in history.
    1. Re:Tough problems by aproposofwhat · · Score: 2

      New math is the only way to go about solving some of these problems.

      You mean like this?

      --
      One swallow does not a fellatrix make
    2. Re:Tough problems by afabbro · · Score: 4, Funny

      ...solving it will probably require the invention of some new mathematics. Its not simply a matter of dividing by 3 and carrying the 2.

      If you're carrying numbers when dividing, I guess you are inventing new math :-)

      --
      Advice: on VPS providers
    3. Re:Tough problems by naasking · · Score: 1

      I don't know about you but I haven't the slightest idea about how to go about inventing new math.

      Creating new math isn't that hard. It's just a bunch of made up rules (the axioms), that should be consistent with one another (lead to no contradictions). Creating a useful math is indeed hard, and creating a useful math to solve a particular problem you're interested in is even tougher. Discovering new mathematical techniques in existing math is also just as hard.

    4. Re:Tough problems by jd · · Score: 2, Funny

      It's easier to have just one heavy maths function and one trivial maths function than two heavy maths functions, so division is easiest implemented as multiplication with the inverse of one of the two numbers, inverses being relatively trivial in exponential notation. As only computers operate this way, the grandparent poster is obviously an artificial intelligence.

      --
      It's a small world and it smells funny; I'd buy another if it wasn't for the money; Take back what I paid (SoM)
    5. Re:Tough problems by fahrbot-bot · · Score: 1
      I studied the Riemann hypothesis in college for a good week and I'm still not sure where you might begin solving it.

      A whole week! Saturday *and* Sunday too? :-)

      --
      It must have been something you assimilated. . . .
    6. Re:Tough problems by AshtangiMan · · Score: 2, Informative

      Thank god (or Goedle) that they don't have to be both consistent and complete.

    7. Re:Tough problems by Anonymous Coward · · Score: 1, Funny

      I carry something else to avoid reproducing.

    8. Re:Tough problems by mav[LAG] · · Score: 2, Funny

      I carry something else to avoid reproducing.

      A clipboard?

      --
      --- Hot Shot City is particularly good.
    9. Re:Tough problems by Sharkeys-Day · · Score: 1

      If you're carrying numbers when dividing, I guess you are inventing new math :-)

      Either that or merely practicing new new math.

    10. Re:Tough problems by Anonymous Coward · · Score: 0

      If you're dividing by 3 or carrying a 2 you're not doing math. You are doing arithmetic.

    11. Re:Tough problems by Anonymous Coward · · Score: 0

      It's called long division.
      If he was dividing by 3 and carrying the 4, then that would be new maths.

  15. Oblig. by JuanCarlosII · · Score: 5, Funny
    1. Re:Oblig. by Boomerang+Fish · · Score: 1

      Great... this explains why I can't get my xkcd fix for the day!

  16. Re:I like to describe my workplace with my calcula by theskipper · · Score: 0, Offtopic

    5318008

    The true king of beghilos, and one that I think about at least 50 times a day.

  17. Apology for the Re by hackus · · Score: 1

    Ok, so many have tried, all have failed.

    It may take a decade to test the assertions that this so called proof attempts to demonstrate.

    Perhaps we could give the guy a consolation prize, wait for the work to be "proven" wrong and then off course, issue an Apology:

    http://www.math.purdue.edu/~branges/apology.pdf :-)

    -Hack

    PS: Does anyone find it STRANGE that the guy who can solve this problem has issues finding a job?

    WTF?

    --
    Got Geometrodynamics? Awe, too hard to figure out? Too bad.
    1. Re:Apology for the Re by JuanCarlosII · · Score: 2, Interesting

      Not really, the kind of person who would solve a problem of this nature is probably going to be the Andrew Wiles reclusive genius type - a lot like the Russian gent whose name escapes me who solved the Poincare Conjecture. Thus he's not necessarily going to be too keen to teach/lecture/supervise and so would possibly not be too attractive to prospective employers.

      I doubt too many Maths faculties in the world have people working full-time on the Riemann Hypotheses.

      Of course I echo your sentiments that his proof is almost certainly flawed though.

    2. Re:Apology for the Re by 1729 · · Score: 1

      Interestingly, DeBranges was Xian-Jin Li's advisor:

      http://www.genealogy.math.ndsu.nodak.edu/id.php?id=16641

    3. Re:Apology for the Re by colinrichardday · · Score: 1

      If the author expects me to read a 40-page PDF, he better not state that Descartes influenced the Renaissance, which happened before he was born.

  18. Re:Coulda told us more... by Anonymous Coward · · Score: 0

    i wouldn't touch this article with an imaginary 11 ft pole.

  19. Re:Try this. by chaboud · · Score: 0, Offtopic

    There was 1 girl, who was 16, she 69'ed 3 times.

    What was she?

  20. Numb3rs by Anonymous Coward · · Score: 0

    "Man, where's Charles Eppes when you need something explained to you in layman's terms?"


    Riemann's was featured prominently in the 5th episode of the first season.

    1. Re:Numb3rs by multipartmixed · · Score: 4, Funny

      Dude, you owe me a monitor.

      Note to self: Do not drink coke while reading /.

      --

      Do daemons dream of electric sleep()?
  21. 1134 by vingilot · · Score: 1

    hEll

  22. Re:Congratulations! by Anonymous Coward · · Score: 3, Funny

    Solving the energy crisis is easy.

    Use less energy.

    Kthxbye.

  23. 53188008? by ya+really · · Score: 1

    That reminds me.

  24. Re:Congratulations! by StarReaver · · Score: 1

    Actually, if he really did successfully prove this, not only does this make him a rich man, but it has huge effects on prime number distribution (if I recall correctly) and related cryptography. I'm not an expert on the subject (Very far from it. I'm a CS major, not a Math major.) but this is what I remember hearing about it. If I'm wrong, please correct me.

  25. typo by Ungrounded+Lightning · · Score: 4, Informative

    The Riemann zeta function is \zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^{s}} [written for LaTeX], or "the sum of 1/(n^s) as n goes from 0 to infinity (increasing by 1 repeatedly)" [in more human-readable form].

    You have a slight typo. Should be: "... as n goes from 1 to infinity ..."

    --
    Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
    1. Re:typo by PlatyPaul · · Score: 1

      Whoops. Thanks for catching that - missed it in preview.

      --
      Misery loves company. Online misery loves unsuspecting random strangers.
    2. Re:typo by mcrbids · · Score: 5, Funny

      The Riemann zeta function is \zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^{s}} [written for LaTeX], or "the sum of 1/(n^s) as n goes from 0 to infinity (increasing by 1 repeatedly)" [in more human-readable form].

      You have a slight typo. Should be: "... as n goes from 1 to infinity ..."

      You have a slight typo. It should be: "You have a slight typo. It should be: ..."

      --
      I have no problem with your religion until you decide it's reason to deprive others of the truth.
    3. Re:typo by Anonymous Coward · · Score: 0

      Not a "slight typo" unless you believe in "nullity" (division by zero)

    4. Re:typo by Gazzonyx · · Score: 1

      The Riemann zeta function is \zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^{s}} [written for LaTeX], or "the sum of 1/(n^s) as n goes from 0 to infinity (increasing by 1 repeatedly)" [in more human-readable form].

      You have a slight typo. Should be: "... as n goes from 1 to infinity ..."

      You have a slight typo. It should be: "You have a slight typo. It should be: ..."

      You have a slight typo. It should be: "You have an off by one error."

      --

      If I mod you up, it doesn't necessarily mean I agree with what you've said, sorry.

    5. Re:typo by Ungrounded+Lightning · · Score: 1

      Not a "slight typo" unless you believe in "nullity" (division by zero)

      It's 1 / (something ^ n). For n = 0: (anything ^ n) = 1. 1/1 = 1 and does not divide by zero.

      Going with the typo would redefine the function to be the actual zeta function plus one.

      --
      Bantam Dominique roosters crow a four-note song. Once you've heard it as "Happy BIRTHday" you can't NOT hear it that way
  26. Numb3rs by netsavior · · Score: 5, Funny

    Charles Eppes: Imagine you have an infinite number of plot holes, and you want to test how they compare to imaginary numbers. The Riemann Hypothesis states that I can use the zeros in this formula to predict how bullets will bounce off of concrete to a degree of statistical accuracy that it will actually give me the social security number of the guilty shooter.

  27. Re:Try this. by Anonymous Coward · · Score: 5, Funny

    your mother?

  28. Re:Coulda told us more... by Weaselmancer · · Score: 2, Insightful

    If you tried, you'd miss by 1/2.

    --
    Weaselmancer
    rediculous.
  29. Re:Coulda told us more... by Vectronic · · Score: 1

    Thats ok, the article doesnt say anything either...

    In its entirety:

    A proof of the Riemann hypothesis
    Xian-Jin Li
    (Submitted on 1 Jul 2008 (v1), last revised 2 Jul 2008 (this version, v2))
    By using Fourier analysis on number fields, we prove in this paper E. Bombieri's refinement of A. Weil's positivity condition, which implies the Riemann hypothesis for the Riemann zeta function in the spirit of A. Connes' approach to the Riemann hypothesis. Subjects: Number Theory (math.NT)
    MSC classes: 11M26
    Cite as: arXiv:0807.0090v2 [math.NT]

    Submission history
    From: Xian-Jin Li [view email]
    [v1] Tue, 1 Jul 2008 19:43:13 GMT (20kb)
    [v2] Wed, 2 Jul 2008 11:05:52 GMT (20kb)

    So Unless you are some encyclopedia of theorems and proofs, you will have to look it all up anyways.

  30. In English? by Codex_of_Wisdom · · Score: 1

    So... could someone explain this theorem in simple(r) terms, please?

    1. Re:In English? by Notquitecajun · · Score: 1

      Nope. Not happening.

    2. Re:In English? by Lunar_Lamp · · Score: 1

      http://www.irregularwebcomic.net/1960.html
      I haven't studied maths in years, nor at a high level, but I was able to understand that very easily.

  31. Re:Coulda told us more... by Anonymous Coward · · Score: 0

    But that's what /. editors are for...

  32. His Advisor Also Claimed Proof by Sirius00 · · Score: 2, Interesting

    This guys advisor, according to the Math Genealogy Project, is Louis deBranges. DeBranges also claimed to have proven this a few years back, but his proof was not accepted (for reasons unknown to me). The $1M might still be safe.

    1. Re:His Advisor Also Claimed Proof by the_povinator · · Score: 1
      This page (previously mentioned) on proposed proofs mentions that de Branges has had more than one failed attempt to prove it: http://secamlocal.ex.ac.uk/people/staff/mrwatkin/zeta/RHproofs.htm

      The wikipedia page on de Branges http://en.wikipedia.org/wiki/Louis_de_Branges_de_Bourcia is very informative

      --
      The .sig is dead, and I believe I had a hand in killing it.
  33. Re:Congratulations! by danzona · · Score: 2, Interesting

    it has huge effects on prime number distribution

    Prime numbers are distributed in pretty much the same way as they were before the proof.

    The proof is mathematics for the sake of mathematics. The Riemann Hypothesis has been accepted as true true for over a hundred years, so practical applications that derive from it already exist.

  34. You mean that... by misterhypno · · Score: 1

    Simple Simon actually met a Riemann, after all?!

    I thought that was just a hypothesis!

  35. The REAL importance is Primes by Anonymous Coward · · Score: 5, Interesting

    Section two of the wiki article (http://en.wikipedia.org/wiki/Riemann_hypothesis) is the great importance here. If indeed there is a proof of Riemann's Hypothesis, then there is a similar proof of the Generalized Riemann Hypothesis, which is in turn a big step in finding the exact distribution of prime numbers.

    Finding the distribution of prime numbers has epic consequences, like breaking most encryption, for starters.

    1. Re:The REAL importance is Primes by Notquitecajun · · Score: 1

      MOD UP. You've answered what I was about to ask - why the near-indecipherable answer to a confusing problem was so stinking important.

    2. Re:The REAL importance is Primes by Anonymous Coward · · Score: 0

      Not only that, but he even finished with a one-sentence paragraph --
      "Finding the distribution of prime numbers has epic consequences, like breaking most encryption, for starters."
      -- for the Digg crowd: It's short and you can understand it without straining your brain, but alludes to so much more("for starters") and even includes the word "epic"! You know it's true, that **** would get +423 diggs.

    3. Re:The REAL importance is Primes by payola · · Score: 5, Informative

      The Riemann Hypothesis and RSA encryption both have to do with prime numbers, but the relationship between the two pretty much ends there. To break RSA you need to know how to factor large numbers quickly. RH, on the other hand, pretains to the distribution of prime numbers. It's pretty unlikely that a proof would make computers any faster at factorizing.

      So this begs the question that a lot of people have been asking on this thread: why should you care? There tongue-in-cheek answer is that a solution is worth $1,000,000. While that response may suffice for non-mathematicians, mathematicians would have another, more important reason to celebrate. RH and its generalization, the Grand Riemann Hypothesis, have an absolutely enormous number of profound impliations in number theory, and it is difficult to overstate how critical a proof of either would be. (The implications are too technical to write about here, but you can read about them in most good survey books on analytic number theory; for example, see section 5.8 of Iwaniec & Kowalski). A successful proof probably won't affect your life in any meaningful way (unless you work with analytic number theory for a living), but it would be monumental in the world of math - indeed, this is precisely why there's a reward for solving it. If that's not enough for you, just remember that many mathematicians are motivated not by fame or money but by the beauty and elegance of mathematics, and any proof of RH would establish a truly beautiful and amazing result.

      Of course, there's also the question: is Li's proof correct? I certainily don't know, and I doubt anyone will for quite some time, but there's an interesting story. Li's Ph.D. adviser was Louis de Branges who, as noted on this very website, claimed to prove RH in 2004. His proof has not been accepted by the mathematical community and is widely considered to be incorrect, in large part because the method he wclaims to use was shown, in a 2000 paper co-authored by none other than Xian-Jin Li, to have holes in it.

  36. Music of the primes by elguillelmo · · Score: 1

    The Music of the Primes, by Marcus du Sautoy is, as far as I know, the best account not only of the great intricacies of the Theorem but also of the amazing quest for an explanation of the hidden structure of numbers.
    You may also find interesting the book's website (warning: cool web design)

    --
    Dawkins Revisited: A person is shit's way of making more shit -- Steve Barnett, anthropologist.
    1. Re:Music of the primes by williegeorgie · · Score: 1

      The book Prime Obsession by John Derbyshire is another book accessible by the vaguely mathematically inclined as well.

  37. DOOOOOMED!!!!!!! by Anonymous Coward · · Score: 2, Funny

    I can't believe they are brazenly going forward with research into this subject without knowing if it could possibly lead to the creation of a black hole that will swallow the earth.

    1. Re:DOOOOOMED!!!!!!! by Anonymous Coward · · Score: 0

      Actually, they are trying to vaporize a black hole that has been swallowing mathematicians' time and effort for the last 150 years.

  38. Re:Try this. by Anonymous Coward · · Score: 2, Funny

    Tired?

  39. You know a paper is hard when.. by antiseptic_poetry · · Score: 1

    even the Abstract is completely indecipherable.

  40. Re:I like to describe my workplace with my calcula by Anonymous Coward · · Score: 0

    hellhole - nice.

  41. Re:Coulda told us more... by 68030 · · Score: 1

    You mean this?
    http://arxiv.org/PS_cache/arxiv/pdf/0807/0807.0090v2.pdf

    The links are right on the side for downloading in various formats.

  42. Re: Doogie Howser by truz24 · · Score: 1

    Doogie tried solving this in Numb3rs as well.

  43. OMG Typo! by Doomedsnowball · · Score: 1

    Did anyone else see the typo in his paper? So close...

    --
    7h3$3 4r3n'7 7h3 Ðr01Ð$ ¥0 4r3 £00|{1n9 f0r. M0v3 4£0n9. --OB1
  44. TeX by Anonymous Coward · · Score: 0

    The article is actually written in TeX, not LaTeX.

  45. It's not complicated, that's the beauty by Nicolas+MONNET · · Score: 1

    It's quite simple (the hypothesis) with basic college-level mathematics. You just need to understand complex numbers and sums of series.
    That's why it's a nice puzzle.
    Compare with Fermat's last theorem, even simpler, yet the proof is only 10 year old and very complicated.
    The only one that's relatively simpler and yet unproven is 3x+1, AKA Collatz' conjecture, read it up, it's fascinating.

    1. Re:It's not complicated, that's the beauty by HuguesT · · Score: 1

      The puzzle isn't as simple as this. For a start one needs to understand analytic continuation as the usual formula for Zeta does not hold for arbitrary complex numbers.

  46. Wrong by InvisblePinkUnicorn · · Score: 5, Funny

    "hellhole - nice."

    No, it's elohlleh, pronounced "elO'-heh-luh", which in the Primitive Quendian proto-language used by the early Elves after their awakening by Eru Ilúvatar, roughly translates to "a dreary, oppressive, or unpleasant place".

    Totally different.

    1. Re:Wrong by Two9A · · Score: 1

      Absolute classic. (To be fair, it looks more Sindarin. The primitive Elves hadn't encountered the inhabitants of Wales, and thus wouldn't have such torturous constructions as "ll".)

      --
      xkcdsw: the unofficial archive of Making xkcd Slightly Worse
  47. Re:Congratulations! by jcgf · · Score: 1

    America's lack of knowledge in the sciences?

    If the fucktards won't pick up a book, what can this guy do about it? For that matter what are YOU doing about it? Nothing? That's what I thought.

  48. That's a really interesting document by Anonymous Coward · · Score: 0

    Not much else to say about it, but it sure is interesting. Score: +1, Interesting. Thanks for the link!

  49. Riemann ... by Dragged+Down+by+the · · Score: 1

    I thought it was just German noodles.

  50. His "proof" by Anonymous Coward · · Score: 0

    From the article:
    "Proof. It follows from Theorem 3.1, (3.3), and the proof of Theorem 1 in Bombieri
    [2].
    This completes the proof of the theorem."

    Yea nice proof there buddy...

  51. Dedeking? by Anonymous Coward · · Score: 0

    Who is this Dedeking they speak of?

  52. More unsolved problems solved by azaris · · Score: 1

    For those who get excited about Millennium problem "solutions" on arXiv.org, there's also what I interpret as an attempt to solve Navier-Stokes posted recently: http://arxiv.org/abs/0806.4902 Have fun finding the first error!

  53. Or, in layman's terms... by CarpetShark · · Score: 4, Informative

    I just finally found a simple explanation of complex numbers, and just heard of this Riemann Hypothesis, so I may be way off, but let me try to put what (I think) I've figured out so far in layman's terms for the rest of the lost souls:

    Riemann was interested in the zeros to this function, where s is a complex number. He conjectured that all zeros (aside from those of the form s = -2c, where c is a positive integer) would have to be of the form (1/2) + ki, where k is a constant and i is the square root of -1.

    Basically, 10 trillian calculations have been done involving certain complex numbers, which all show a clear pattern: if you get an answer of 0, the real part of the number given to the function always seems to be 0.5. As yet, no one has proven this, and so, presumably, no one truly understands why that's the case yet. Also, presumably, when we do understand it, we'll have forward (either in a a step or a leap) in our ability to use complex numbers (and the multi-dimensional calculations they represent.

  54. Picking nits perhaps, but... by BigGar' · · Score: 1

    This paper is only for the "rational number field" thus does not encompass all possible number fields and the technique, while believed to be generalizable, may not be. So even if this proof pans out, the way I read it, for the time being it is a partial proof and would need to be generalized, before the hypothesis could be considered proven.
    Second should he really be using language such as "I feel" to describe his thoughts on the possibility on this generalization.

    To avoid the complication of writings, I only considered the rational number
    field in this paper. But, I feel that techniques of this paper can be adopted to
    any algebraic number field without much difficulty to give a proof of the Riemann
    hypothesis for Dedeking zeta functions.

    --


    Shop smart, Shop S-Mart.
    1. Re:Picking nits perhaps, but... by payola · · Score: 1

      There are generalizations of the Riemann hypothesis which are known as Dedekind zeta functions; the Riemann zeta function is one of these, corresponding to the field of rational numbers. It is also believed that the Dedekind zeta functions have all their zeros lying on the line Re(s) = 1/2. Viewed in this way, the Riemann hypothesis can be considered as a special case of a larger conjecture.

      The first sentence that you quote indicates that Li is claiming to have "only" proven the Riemann hypothesis for the regular Riemann zeta function, but that he believes his techniques could be generalized to prove the related conjectures for other Dedekind zeta functions.

    2. Re:Picking nits perhaps, but... by BigGar' · · Score: 1

      Ok, thank you.

      It's been a while since I've even looked at this and I've forgotten some of the details. I was thinking that the Riemann hypothesis was the larger conjecture.
      I preferred the way you stated the techniques could be generalized. While I certainly understood what he meant, I just thought that using the term "feel" was a tad unscholarly, but perhaps I'm just getting old.

      --


      Shop smart, Shop S-Mart.
  55. Reimann hypothesis by LocalFire · · Score: 1

    Is there no gossip among mathematicians whether this proof is worth careful review? I can't see any comments from anyone who is versed in this subject.

    1. Re:Reimann hypothesis by Anonymous Coward · · Score: 0

      Yeah I'm a little disappointed by Slashdotters, especially since the first 20 posts were about spelling 'boobies' on a calculator..

    2. Re:Reimann hypothesis by Anonymous Coward · · Score: 0

      One of the Mathematics professors at my university said that it looked serious on first sight. I'm not going to give names to protect the innocent though. ;-)

    3. Re:Reimann hypothesis by tobiah · · Score: 2, Interesting
      page 4 for equations 3.2-3.4 he assumes g0 can be bounded because it has compact support on (0, Inf). This is false, a function that is continuous on all of (0, Inf) also has compact support on (0, Inf). That sort of thing is why functions with compact support are only interesting on a bounded domain.

      If you let g0(x)=1/x, then the integral at the bottom of page 38 blows up to Inf.

      I don't see a way to fix that, Theorem 8.6 is pretty important to this proof, and probably false. Those bits represent Li's major contribution to the problem, the rest of it is restating previous results.

      --
      "The ability to delude yourself may be an important survival tool" - Jane Wagner -
    4. Re:Reimann hypothesis by payola · · Score: 2, Informative

      Extremely highly-regarded mathematician Terence Tao has said, in response to a comment left on his blog, that the proof is probably incorrect.

  56. I have a simpler proof by Harl_Delos · · Score: 1

    Unfortunately, there isn't room here in the margin to post it....

    1. Re:I have a simpler proof by Anonymous Coward · · Score: 0

      Hilarious. See Fermat's Last Theorem, if you don't get the joke.

    2. Re:I have a simpler proof by laddiebuck · · Score: 1

      Yes, it's only every mathematics article ever posted on Slashdot that gets 2-3 comments like the GP. We must be up to a few thousand by now.

  57. And there's money involved... by AmigaMMC · · Score: 1

    A $1,000,000 prize has been offered by the Clay Mathematics Institute for the first correct proof. http://en.wikipedia.org/wiki/Riemann_hypothesis

  58. Weird idea maths you have here by Nicolas+MONNET · · Score: 1

    1. It's not been accepted as true.
    2. "Maths for the sake of maths" is called mathematics. Otherwise it's, I don't know, creationism or something.

    1. Re:Weird idea maths you have here by Muhahahahaz · · Score: 1

      I will clarify the point he is trying to get across.

      I'm not sure whether the results of RH actually help you break cryptography, but let's assume that it does somehow. Well then, in practice, you don't actually need a proof of RH to make use of it! Sure, you won't be 100% certain that it will work, but that can't stop you from trying! RH was already very strongly thought to be true, so if assuming RH helps you break cryptography somehow, then just assume it without proof and see if you can do so.

      Hopefully that was clearer? That's why it's more like "Math for the sake of Math", because there's no direct application of the proof, aside from more Math. Of course, within Number Theory, RH is huge. There's already a large body of work that assumes RH, and so all that work would be rendered useless if RH turned out to be false.

  59. Not quite right? by Jane+Q.+Public · · Score: 1
    I don't think that is quite correct. If

    k

    is a constant, then

    (1/2) + ki

    is also a constant.

    1. Re:Not quite right? by Markspark · · Score: 1

      k is an arbitrary constant, to clarify that. but yes your statement is correct. :)

      --
      i find your lack of faith in science disturbing!
    2. Re:Not quite right? by JuanCarlosII · · Score: 3, Funny

      k is an arbitrary constant

      Or a 'variable' as it is also known.

  60. The most important? by Woundweavr · · Score: 1

    The Riemann hypothesis is considered the most important unsolved problem in math.


    Thats a pretty strong statement. P vs NP might have something to say about that (especially if a functional P=NP solution emerged)

  61. Lame calculator joke by NJVil · · Score: 1

    It's the only one I know.

    Dolly Parton went to her doctor. She complained that her breasts were too large and she wanted breast reduction surgery. The doctor measured her chest. "69 inches!" (enter 69) "that's too too too big!" (enter 222) "Five times a day take one of these pills" (enter 51) and after eight days (multiply by 8) you will be (result 55378008)... and turn the calculator over.

    Great fun when you're 9 years old...

  62. Riemman was wrong? by alexborges · · Score: 0, Flamebait

    Well... if its so hard to prove (and such a little and simple hipothesys), perhaps is just plain not true and thats that.

    Of course, now we need to get into proving THAT.

    --
    NO SIG
    1. Re:Riemman was wrong? by Rebel_Jedi · · Score: 1

      It's not a question of simplicity. It takes several pages of symbolic logic just to prove 1 + 1 = 2. Mathematicians have been trying to prove RH for about 150 years. Fermat's Last Theorem took twice that to prove, despite being MUCH simpler, and the proof required mathematical tools which didn't even exist in Fermat's day. Plus if RH isn't true, virtually the whole of mathematics comes crashing down about our ears, because there are several critical parts of it which can't be true if RH isn't! Someone mentioned encryption and factorisation of prime numbers, but I think they misunderstood what they've read about RH. The problem with trying to crack encryption lies in trying to determine which prime numbers were used to encrypt the message; prime numbers are hard to generate and verify because as yet there does not exist any method other than brute force to determine if a given number even IS prime, i.e. you have to divide it by all prime numbers smaller than its square root. When you're talking about 60-digit primes, the number of possibilities for public and private key pairs is...well, I don't know what it is offhand, but it's bloody large! But proving RH would indirectly give mathematicians a method of deriving primes WITHOUT checking for possible factors - if RH is true and the given number lies on the critical line, then it's prime. Generating primes would then be a simple matter of plugging the right values into the Riemann zeta function. So untold trillions of years of work with a supercomputer are reduced to maybe a few hours with a PC. Which means public key encryption will be rendered useless once RH is proved. Not that the mathematicians will care about that! :)

    2. Re:Riemman was wrong? by cartermb · · Score: 1

      Actually, proving the negative is always quite easy - you just have to state a case under which the hypothesis is not true. Since no one has been able to do that so far, the broad-based assumption is that it must be true. Proving the positive - that it is true and why it is true - is, as always, the hard part.

  63. From the PDF by colinrichardday · · Score: 1

    The Renaissance was stimulated by the Cartesian Philosophy . . .

    Interesting, as Descartes was born in 1596, and the Renaissance started much earlier. Yes, that's nitpicking, but if you want me to read a 40-page PDF, you should get such things correct.

    1. Re:From the PDF by Anonymous Coward · · Score: 0

      But he didn't actually state that he's relying on the assumption of causality, did he?

  64. A mathematician's response. by Anonymous Coward · · Score: 0

    Here is a bit more information about Li's claimed proof of RH on the ArXiv: Li is certainly *not* a crackpot, and the attempt should *not* be dismissed automatically (like other completely bogus proofs found occasionally on the ArXiv). Li is a serious research mathematician.

    One mathematician I know, who is familiar with Li's work, doubts that RH has been proven. He has not thoroughly gone through the paper, but doubts that Li has proven RH. Although I am also a number theorist, I do not consider myself qualified, nor do I have time, to go through Li's paper thoroughly.

    My advice -- be skeptical but not dismissive of Li's preprint on the ArXiv.

  65. Finally I can downlad from Rapidshare! by Plantain · · Score: 1

    At last, I'll know what to put in the captcha on rapidshare :o

    --
    No, but I did throw granola at a deaf person once
  66. John Nash and Riemann hypothesis by BamBamboo · · Score: 0

    In Ron Howard's 2001 film A Beautiful Mind, John Nash (played by Russell Crowe) is hindered in his attempts to solve the Riemann hypothesis by the medication he is taking to treat his schizophrenia.

  67. Disproof by tobiah · · Score: 2, Interesting

    Ah well, not quite right. But let g0(x)=x works, because there's no integrability condition. Thm 8.6 then falls apart because h0 is no longer in L^2(C), or V(h) is not an operator, take your pick.

    --
    "The ability to delude yourself may be an important survival tool" - Jane Wagner -
    1. Re:Disproof by Anonymous Coward · · Score: 0

      Sorry, but your "disproof" is nonsense. g0(x)=x does NOT have compact support, its support is all of (0,Inf) (or |R or even (C if you consider a larger definition domain), which (either way) is definitely not compact. The support of g0(x) is the closure of the set for which g0(x) is nonzero. g0(x)=x is only zero at one point (x=0), which is not in the definition domain (0,Inf) (and would get filled by the closure when using a definition domain like |R or (C anyway), so the support is the entire definition domain. A compact set in |R or (C is bounded and closed, so "compact support" means "bounded support". And a continuous function from a compact set (ANY compact set, even a set of non-number objects) to |R or (C always has values in a compact set (actually a continuous map always maps a compact set to a compact set, even if the values are not numbers), and as such is always bounded (this last part of course only makes sense for sets where the Heine-Borel theorem holds, but that's definitely the case for |R and (C).

    2. Re:Disproof by Anonymous Coward · · Score: 0

      (same AC, correcting myself)
      Actually, for (0,Inf), "compact support" not only means bounded support, but also that the function becomes zero before it reaches x=0, as the closure is a closure relative to the definition domain, so for example the closure of (0,1) in (0,Inf) is (0,1], which is not compact (because it's not closed in |R). But this does not invalidate anything else in my post.

    3. Re:Disproof by tobiah · · Score: 1

      What are you talking about? [0,Inf) isn't compact, but any contiguous open set like (0, Inf) is. So a function which is non-zero everywhere on (0,Inf) has compact support.
      See http://mathworld.wolfram.com/CompactSupport.html

      --
      "The ability to delude yourself may be an important survival tool" - Jane Wagner -
    4. Re:Disproof by tobiah · · Score: 1

      I see what you'e saying here, but I still think the definition of g0 is problematic. It's either not strict enough and will mess up later results(ex. blowing up the integral on page 38), or it's too strict and fails to address cases that are relevant.

      --
      "The ability to delude yourself may be an important survival tool" - Jane Wagner -
  68. There's good news about this paper by jim.shilliday · · Score: 1

    You'd have to be crazy to bet that this proof is correct. That said (I'm not a mathematician, but): First, Li's proof at least claims to build on approaches that are, for number theory, reasonably mainstream. He cites the big guns. Second, he's not a delusional crank -- he's had number theory papers published in peer-reviewed journals. The math community will probably take him seriously. Finally, the best news - his paper is only forty pages long, so the few people who are capable of evaluating the proof won't feel that they have to devote the rest of their careers to it. Chances are that we will hear fairly soon whether or not the proof is valid. There's been a raft of comments here about the significance of a proof -- one short answer is that there are hundreds, maybe thousands, of mathematical theorems that start "Assuming the Riemann Hypothesis...."

    --
    Jim Shilliday
  69. That's not the right problem by Nicolas+MONNET · · Score: 1

    Unless I missed something, this conjecture does not have the sweeping consequences you allude to; unlike P=NP.

    1. Re:That's not the right problem by Muhahahahaz · · Score: 1

      That's why I said I'm not sure. I just heard some other people claiming something, so I simply explained a line of reasoning that assumes their claim. I haven't studied any of the consequences of RH yet, so perhaps their claim was false.

  70. Einstein by Anonymous Coward · · Score: 0

    PS: Does anyone find it STRANGE that the guy who can solve this problem has issues finding a job?

    Nice comment, Einstein.
    Following graduation, Einstein could not find a teaching post. After almost two years of searching, a former classmate's father helped him get a job in Berne, at the Federal Office for Intellectual Property,[14] the patent office, as an assistant examiner. :-)

  71. Let me help you understand his point by p3d0 · · Score: 1

    Don't be dense. Here's his point:

    The poster to whom you replied suggested that a paper claiming a proof posted on an unreviewed preprint server probably wasn't a good reason to get excited. He's absolutely correct.

    --
    Patrick Doyle
    I mod down every jackass who puts his moderation policy in his sig. Oh, wait a sec....
    1. Re:Let me help you understand his point by twistedcubic · · Score: 1

      No need to be rude with the dense comment.

  72. Retraction by tobiah · · Score: 1

    Nevermind, I'm quite off there.

    --
    "The ability to delude yourself may be an important survival tool" - Jane Wagner -
  73. Wikiaccurate by E.T.123 · · Score: 1

    Wikipedia is accurate (citation needed)

  74. respected expert (Alain Connes) spots problem by Anonymous Coward · · Score: 1, Informative

    Fields medal winner, and expert in the field,
    Alain Connes sees a problem with the attempted
      proof.

    http://noncommutativegeometry.blogspot.com/2008/06/fun-day-two.html?showComment=1215071400000#c8876982000013974667

  75. Calculating Primes by stock · · Score: 1
    The Riemann Hypothesis is that the locations and density of possible prime numbers can be predicted through the Riemann zeta-function. Well thats just fine.

    What is also interesting to know is that one can generate and calculate primes in a simple and straighforward manner using previous obtained results and primes through a prime number generating function :

    "Calculate Primes"
    by Prof James M. McCanney
    , (c)2006,2007
    http://www.calculateprimes.com/

  76. A leading mathematician finds the proof flawed. by jim.shilliday · · Score: 1

    Alain Connes, a leading French mathematician whose work forms part of the foundation of Li's claimed proof, believes that the proof is flawed -- so much so that he stopped reading it. Here's his comment (on his blog): http://noncommutativegeometry.blogspot.com/2008/06/fun-day-two.html?showComment=1215071400000#c8876982000013974667 Li will have to respond to this. Expect fireworks.

    --
    Jim Shilliday
  77. And Li responds to Connes and Tao by jim.shilliday · · Score: 1

    Prof. Li has posted a fourth version of his proof on arxiv: http://arxiv.org/abs/0807.0090v4. According to this comment on Connes's blog http://noncommutativegeometry.blogspot.com/2008/06/fun-day-two.html?showComment=1215144000000#c3090911722072092520, Li has made changes to the equations that Tao and Connes identified as problematic. The saga continues.

    --
    Jim Shilliday
  78. errors found by experts by purplelocust · · Score: 1
    It looks like a problem with the proof has been found. Fields Medalist Terry Tao comments on his blog:

    It unfortunately seems that the decomposition claimed in equation (6.9) on page 20 of that paper is, in fact, impossible; it would endow the function h (which is holding the arithmetical information about the primes) with an extremely strong dilation symmetry which it does not actually obey. It seems that the author was relying on this symmetry to make the adelic Fourier transform far more powerful than it really ought to be for this problem.

  79. Re:How do you get to this level? by Anonymous Coward · · Score: 0

    Can somebody please tell me, how do you get to the level of mathematics by self study? I know there are books on this, but where do you begin? I am a graduate student, I have taken discrete mathematics, calculus, differential equations, linear algebra, fourier analysis, complex analysis, and I have attempted to teach myself number theory, abstract algebra, and yet this claimed proof of RZH is practically incomprehensible to me. In fact, it practically makes me feel retarded. Cam somebody point me in the direction I need to go if I wanted to teach myself? Such as the graduate textbooks I would need.